You can
put this solution on YOUR website!Always solve a quadratic inequality in 4 steps.
Step 1. Bring it to standard form: f(x) = 2x^2 + 3x - 9 < 0.
Step 2. Solve f(x) = 0. You can use any method you prefer. I use the new Diagonal Sum method. Roots have opposite signs. There are 3 probable root-pairs:
(-1/2, 9/1),(-3/1, 3/2),(-3/2, 3/1). The diagonal sum of the second set is -3 = -b. The 2 real roots are -3 and 3/2.
Or, you can solve it by the factoring ac method (You Tube). Find 2 number that their product is ac = -18, and their sum is b = 3. Proceed: [(-1, 18)(1, -18)(-2, 9)(2, -9)(-3, 6), OK]. Replace in the equation f(x) = 0 the quantity 3x by two quantities -3x and 6x.
2x^2 + 3x - 9 = 2x^2 - 3x + 6x - 9 = 0.
= 2x(x + 3)- 3(x +3) = (x + 3)(2x - 3). Solve the 2 binomials:
x + 3 = 0 ---> x = -3
2x - 3 = 0 ---> x = 3/2
Step 3. Solve the inequality f(x) < 0. Use the number line and test point method. Plot the 2 real roots -3 and 3/2 on the number line. Use the origin O as test point. Substitute x = 0 into the inequality. You get -9 < 0. It is true, then the origin O is on the true segment (-3, 3/2).
Step 4. Express the answer (solution set) of the inequality in the form of an open interval (-3, 3/2). The 2 end points -3 and 3/2 are not included in the solution set.
If in the inequality, there is an additional (=) sign (lesser or equal to), then the solution set is a closed interval [-3, 3/2]. The 2 end points -3 and 3/2 are included in the solution set.