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Recent problems solved by 'stanbon'
stanbon answered: 57288 problems
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47070..47099 , 47100..47129 , 47130..47159 , 47160..47189 , 47190..47219 , 47220..47249 , 47250..47279 , 47280..47309 , 47310..47339 , 47340..47369 , 47370..47399 , 47400..47429 , 47430..47459 , 47460..47489 , 47490..47519 , 47520..47549 , 47550..47579 , 47580..47609 , 47610..47639 , 47640..47669 , 47670..47699 , 47700..47729 , 47730..47759 , 47760..47789 , 47790..47819 , 47820..47849 , 47850..47879 , 47880..47909 , 47910..47939 , 47940..47969 , 47970..47999 , 48000..48029 , 48030..48059 , 48060..48089 , 48090..48119 , 48120..48149 , 48150..48179 , 48180..48209 , 48210..48239 , 48240..48269 , 48270..48299 , 48300..48329 , 48330..48359 , 48360..48389 , 48390..48419 , 48420..48449 , 48450..48479 , 48480..48509 , 48510..48539 , 48540..48569 , 48570..48599 , 48600..48629 , 48630..48659 , 48660..48689 , 48690..48719 , 48720..48749 , 48750..48779 , 48780..48809 , 48810..48839 , 48840..48869 , 48870..48899 , 48900..48929 , 48930..48959 , 48960..48989 , 48990..49019 , 49020..49049 , 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51030..51059 , 51060..51089 , 51090..51119 , 51120..51149 , 51150..51179 , 51180..51209 , 51210..51239 , 51240..51269 , 51270..51299 , 51300..51329 , 51330..51359 , 51360..51389 , 51390..51419 , 51420..51449 , 51450..51479 , 51480..51509 , 51510..51539 , 51540..51569 , 51570..51599 , 51600..51629 , 51630..51659 , 51660..51689 , 51690..51719 , 51720..51749 , 51750..51779 , 51780..51809 , 51810..51839 , 51840..51869 , 51870..51899 , 51900..51929 , 51930..51959 , 51960..51989 , 51990..52019 , 52020..52049 , 52050..52079 , 52080..52109 , 52110..52139 , 52140..52169 , 52170..52199 , 52200..52229 , 52230..52259 , 52260..52289 , 52290..52319 , 52320..52349 , 52350..52379 , 52380..52409 , 52410..52439 , 52440..52469 , 52470..52499 , 52500..52529 , 52530..52559 , 52560..52589 , 52590..52619 , 52620..52649 , 52650..52679 , 52680..52709 , 52710..52739 , 52740..52769 , 52770..52799 , 52800..52829 , 52830..52859 , 52860..52889 , 52890..52919 , 52920..52949 , 52950..52979 , 52980..53009 , 53010..53039 , 53040..53069 , 53070..53099 , 53100..53129 , 53130..53159 , 53160..53189 , 53190..53219 , 53220..53249 , 53250..53279 , 53280..53309 , 53310..53339 , 53340..53369 , 53370..53399 , 53400..53429 , 53430..53459 , 53460..53489 , 53490..53519 , 53520..53549 , 53550..53579 , 53580..53609 , 53610..53639 , 53640..53669 , 53670..53699 , 53700..53729 , 53730..53759 , 53760..53789 , 53790..53819 , 53820..53849 , 53850..53879 , 53880..53909 , 53910..53939 , 53940..53969 , 53970..53999 , 54000..54029 , 54030..54059 , 54060..54089 , 54090..54119 , 54120..54149 , 54150..54179 , 54180..54209 , 54210..54239 , 54240..54269 , 54270..54299 , 54300..54329 , 54330..54359 , 54360..54389 , 54390..54419 , 54420..54449 , 54450..54479 , 54480..54509 , 54510..54539 , 54540..54569 , 54570..54599 , 54600..54629 , 54630..54659 , 54660..54689 , 54690..54719 , 54720..54749 , 54750..54779 , 54780..54809 , 54810..54839 , 54840..54869 , 54870..54899 , 54900..54929 , 54930..54959 , 54960..54989 , 54990..55019 , 55020..55049 , 55050..55079 , 55080..55109 , 55110..55139 , 55140..55169 , 55170..55199 , 55200..55229 , 55230..55259 , 55260..55289 , 55290..55319 , 55320..55349 , 55350..55379 , 55380..55409 , 55410..55439 , 55440..55469 , 55470..55499 , 55500..55529 , 55530..55559 , 55560..55589 , 55590..55619 , 55620..55649 , 55650..55679 , 55680..55709 , 55710..55739 , 55740..55769 , 55770..55799 , 55800..55829 , 55830..55859 , 55860..55889 , 55890..55919 , 55920..55949 , 55950..55979 , 55980..56009 , 56010..56039 , 56040..56069 , 56070..56099 , 56100..56129 , 56130..56159 , 56160..56189 , 56190..56219 , 56220..56249 , 56250..56279 , 56280..56309 , 56310..56339 , 56340..56369 , 56370..56399 , 56400..56429 , 56430..56459 , 56460..56489 , 56490..56519 , 56520..56549 , 56550..56579 , 56580..56609 , 56610..56639 , 56640..56669 , 56670..56699 , 56700..56729 , 56730..56759 , 56760..56789 , 56790..56819 , 56820..56849 , 56850..56879 , 56880..56909 , 56910..56939 , 56940..56969 , 56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179 , 57180..57209 , 57210..57239 , 57240..57269 , 57270..57299, >>Nexttest/556844: my problem: Where would you expect the vertex on the graph Y= (x-4)^2 +5 to be? Explain why?
Thank You 1 solutions
Answer 362267 by stanbon(57361) on 2012-01-13 08:35:08 (Show Source):
You can put this solution on YOUR website!my problem: Where would you expect the vertex on the graph Y= (x-4)^2 +5 to be? Explain why?
The graph is a parabola opening upward.
It has a minimum point at its vertex.
--
The smallest value y can have occurs
when x = 4.
That y-value is 5
---
So the vertex is at (4,5)
===============================
Cheers,
Stan H.
============
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Travel_Word_Problems/556832: A bicycle leaves town at 16 mph at 8 AM. A car leaves at 11 AM traveling the same direction at 45 mph. How many minutes after 11 AM is it when the car overtakes the bicycle? 1 solutions
Answer 362266 by stanbon(57361) on 2012-01-13 08:32:34 (Show Source):
You can put this solution on YOUR website!A bicycle leaves town at 16 mph at 8 AM. A car leaves at 11 AM traveling the same direction at 45 mph. How many minutes after 11 AM is it when the car overtakes the bicycle?
-----
Bike DATA:
rate = 16 mph ; time = x hrs ; distance = 16x miles
---
Car DATA:
rate = 45 mph ; time = x-3 hrs ; distance = 45x-135 miles
-----
Equation:
distance = distance
16x = 45x -135
29x = 135
x = 4.66 hrs
x-3 = 1.66 hrs = 99.31 minutes
====================================
Cheers,
Stan H.
==================
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Quadratic_Equations/556843: Solve for x.
x^2+32=8x
I got (8+8i/2 , 8-8i/2)
Am I on the right track?
Thank you
1 solutions
Answer 362263 by stanbon(57361) on 2012-01-13 08:23:58 (Show Source):
You can put this solution on YOUR website!Solve for x.
x^2+32=8x
---
x^2-8x+32 = 0
---
x = [8 +- sqrt(64-128)]/2
---
x = [8 +- sqrt(-64)]/2
---
x = [8 +- 8i]/2
---
x = (4+4i) or x = (4-4i)
==========================
Cheers,
Stan H.
===============
|
Permutations/556831: A class consists of 40 girls and 60 boys.in how many ways can a president,treasurer and secretary be chosen if the treasurer must be a girl,the secretary must be a boy and a student may not hold more than one office? 1 solutions
Answer 362262 by stanbon(57361) on 2012-01-13 08:20:52 (Show Source):
You can put this solution on YOUR website!A class consists of 40 girls and 60 boys.in how many ways can a president,treasurer and secretary be chosen if the treasurer must be a girl,the secretary must be a boy and a student may not hold more than one office?
--------
40 ways to choose the treasurer
60 ways to choose the secretary
98 ways to choose the president
---
Total choices: 235,200
Cheers,
Stan H.
=============
|
Pythagorean-theorem/556837: beginning with a 3 dimentional rectangular box, how is the degree of the angle of turn determined where a line enters the box and then proceeds to the furthest corner within the box
1 solutions
Answer 362261 by stanbon(57361) on 2012-01-13 08:17:34 (Show Source):
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Surface-area/556840: A park has a circular goldfish pond. What is A, the apporximate are of the surface of the pond, if its radius, r, is 5 feet?
1 solutions
Answer 362260 by stanbon(57361) on 2012-01-13 08:15:15 (Show Source):
You can put this solution on YOUR website!A park has a circular goldfish pond. What is A, the apporximate are of the surface of the pond, if its radius, r, is 5 feet?
---
Area = (pi)r^2
---
Area = 25pi sq ft
======================
Cheers,
Stan H.
|
Angles/556839: Bruce is 36 years old. His son is 8 years old. In how many years will Bruce be three times as old as his son? 1 solutions
Answer 362259 by stanbon(57361) on 2012-01-13 08:13:12 (Show Source):
You can put this solution on YOUR website!Bruce is 36 years old. His son is 8 years old. In how many years will Bruce be three times as old as his son?
----
Let the "number of years" be "x":
---
Equation:
36+x = 3(8+x)
36+x = 24+3x
2x = 12
x = 6 years
---
Bruce will be 36+6 = 42
His son will be 8+6 = 14
--
And 42 = 3*14
===================
Cheers,
Stan H.
===================
|
Probability-and-statistics/556683: A disc jockey has 11 songs to play. Eight are slow songs, and three are fast songs. Each song is to be played only once. In how many ways can the disc jockey play the 11 songs if
The songs can be played in any order.
The first song must be a slow song and the last song must be a slow song.
The first two songs must be fast songs. 1 solutions
Answer 362209 by stanbon(57361) on 2012-01-12 21:25:43 (Show Source):
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Probability-and-statistics/556660: Show all work. A disc jockey has 11 songs to play. Eight are slow songs, and three are fast songs. Each song is to be played only once. In how many ways can the disc jockey play the 11 songs if
The songs can be played in any order.
The first song must be a slow song and the last song must be a slow song.
The first two songs must be fast songs. 1 solutions
Answer 362208 by stanbon(57361) on 2012-01-12 21:24:49 (Show Source):
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Probability-and-statistics/556676: If we want to be 99% confident that our estimate of the population percentage (p) of green M&M candies is within 4% of the actual population percentage, how many M&M's must be in our sample?
1 solutions
Answer 362206 by stanbon(57361) on 2012-01-12 21:21:41 (Show Source):
You can put this solution on YOUR website! If we want to be 99% confident that our estimate of the population percentage (p) of green M&M candies is within 4% of the actual population percentage, how many M&M's must be in our sample?
------
n = [z/E]pq
-----
n = [2.5758/0.04]^2*(1/2)(1/2)
------
n = 1037 when rounded up
==============================
Cheers,
Stan H.
=============
|
Polynomials-and-rational-expressions/556220: 10cm^3 of a normal specimen of human blood contains 1.2 g of hemoglobin. How
many grams does 31 cm^3 of the same blood cantain?
31 cm^3 of the blood cantain _____ grams of hemoglobin
1 solutions
Answer 362083 by stanbon(57361) on 2012-01-12 09:05:40 (Show Source):
You can put this solution on YOUR website!10cm^3 of a normal specimen of human blood contains 1.2 g of hemoglobin.
How many grams does 31 cm^3 of the same blood cantain?
-----
Use a proportion:
-----
x/31 = 1.2/10
---
x = 3.1*1.2 = 3.72 g's
-----
Cheers,
Stan H.
============
31 cm^3 of the blood cantain 3.72 grams of hemoglobin
|
Matrices-and-determiminant/556199: integral 9x+4
----- dx
x2-7x+15 1 solutions
Answer 362081 by stanbon(57361) on 2012-01-12 09:02:00 (Show Source):
You can put this solution on YOUR website!integral [(9x+4)/(x^2-7x+15)] dx
---
Use partial fraction decompostion to get::
------------
= [(A/(x-5))+(B/(x-3)] = (9x/4)/(x^2-7x+15)
-----
A(x-3)+B(x-5) = 9x+4
----
A+B = 9
-3A-5B = 4
-----
3A+3B = 27
-3A-5B = 4
--------
-2B = 31
B = -31/2
---
A = 49/2
---------------
integra[((49/2)/(x-5) - (31/2)/(x-3)]
----
= (49/2)ln(x-5) - (31/2)ln(x-3)
----
Check the following site to see how this all works.
===============
http://www.math.ucdavis.edu/~kouba/CalcTwoDIRECTORY/
partialfracsoldirectory/PartialFracSol.html#SOLUTION 1
=====================
Cheers,
Stan H.
==============
|
Age_Word_Problems/556012: bill is 4 times as old as john.five year ago the sum of their ages was 50 how old are they now 1 solutions
Answer 362016 by stanbon(57361) on 2012-01-11 20:25:09 (Show Source):
You can put this solution on YOUR website!bill is 4 times as old as john.five year ago the sum of their ages was 50 how old are they now
---
Equations:
b = 4*j
(b-5)+(j-5) = 50
-----
Substitute for "b" and solve for "j":
4j-5+j-5 = 50
5j = 60
j = 12 yrs. (john's age now)
----
Solve for "b":
b = 4*j
b = 4*12 = 48 yrs (Bill's age now)
=======================================
|
Travel_Word_Problems/556002: I am unsure as to how to begin to solve this word problem. The OfficeJet printer can copy Maria's dissertation in 8 minutes. The LaserJet printer can copy the same document in 12 minutes. If the two machines worked together, how long would they take to copy the dissertation? Thank you for any help you can provide on this one. 1 solutions
Answer 362012 by stanbon(57361) on 2012-01-11 20:21:01 (Show Source):
You can put this solution on YOUR website!The OfficeJet printer can copy Maria's dissertation in 8 minutes. The LaserJet printer can copy the same document in 12 minutes. If the two machines worked together, how long would they take to copy the dissertation?
-----
Office Jet time = 8 min/job ; rate = 1/8 job/min
-----
Laser Jet time = 12 min/job ; rate = 1/12 job/min
-----
Together time = x min/job ; rate = 1/x job/min
---------------------------------
Equation:
rate + rate = together rate
1/8 + 1/12 = 1/x
----
Multiply thru by 24x to get:
3x + 2x = 24
5x = 24
x = 4.8 minutes/job (time to do the job together)
=====================================================
Cheers,
Stan H.
=================
|
Travel_Word_Problems/555998: I am in an online college class for algebra 2 and get stuck on word problems quite easily. This is the problem: Elena bicycles 6 km/h faster than Javier. In the same time it takes Javier to bicycle 57 km, Elena can bicycle 75 km. How fast is both bicyclist traveling? 1 solutions
Answer 362006 by stanbon(57361) on 2012-01-11 20:09:46 (Show Source):
You can put this solution on YOUR website!Elena bicycles 6 km/h faster than Javier. In the same time it takes Javier to bicycle 57 km, Elena can bicycle 75 km. How fast is both bicyclist traveling?
--------------
Javier DATA:
rate = x km/h ; distance = 57 km ; time = d/r = 57/x hrs.
-----
Elena DATA:
rate = (x+6) km/h ; distance = 75 km ; time = d/r = 75/(x+6) hrs
======================
Equation:
time = time
57/x = 75/(x+6)
75x = 57(x+6)
75x-57x = 6*57
18x = 6*57
x = (1/3)57
x = 19 km/h (Javier's rate)
x+6 = 25 km/h (Elena's rate)
================================
Cheers,
Stan H.
=================
|
Percentage-and-ratio-word-problems/555994: 12 items cost $120.00 wHAT IS THE LOSS PERCENT IF THEY ARE SOLD FOR $9.00 EACH 1 solutions
Answer 362002 by stanbon(57361) on 2012-01-11 20:03:32 (Show Source):
You can put this solution on YOUR website!12 items cost $120.00 wHAT IS THE LOSS PERCENT IF THEY ARE SOLD FOR $9.00 EACH
------
Original cost per item 120/12 = $10
-----
Selling price per item $9
-----
Quantity loss per item: $1
---
Percentage loss peritme: 1/10 = 10%
=======================================
Cheers,
Stan H.
|
Probability-and-statistics/555592: I am really confused. I am in MM207 and do not understand how to solve this problem. Could someone please take me step by step through it so that I understand what I am doing?
Assume you want to estimate with the proportion of students who commute less than 5 miles to work within 2%, what sample size would you need?
This question relates to a survey that was done at the done at the beginning of the term.
1 solutions
Answer 361955 by stanbon(57361) on 2012-01-11 16:47:14 (Show Source):
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Probability-and-statistics/555613: i am in MM207 and have a question that I cannot answer. This question comes from a survey that was done. Assume you want to estimate with the proportion of students who commute less than 5 miles to work within 2%, what sample size would you need? 1 solutions
Answer 361954 by stanbon(57361) on 2012-01-11 16:46:07 (Show Source):
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Probability-and-statistics/555694: A single die is rolled. What is the probability of rolling the following: (a) P(4) (b) P(a number greater than 4) (c) P(a number greater than 6) (d) P(a number less than 7)? 1 solutions
Answer 361951 by stanbon(57361) on 2012-01-11 16:44:40 (Show Source):
You can put this solution on YOUR website!A single die is rolled. What is the probability of rolling the following:
(a) P(4) = 1/6
(b) P(a number greater than 4):: = 2/6 = 1/3
(c) P(a number greater than 6):: 0/6 = 0
(d) P(a number less than 7)?:: 6/6 = 1
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Cheers,
Stan H.
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Probability-and-statistics/555809: At the play there is a raffle. Each student is given a number card. The seniors are given 592 cards numbered consecutively with the first number being 358. When the winners are announced, all numbers that are multiples of 50 win a free T-shirt. How many seniors won a free t-shirt? Show your work to explain your answer. 1 solutions
Answer 361949 by stanbon(57361) on 2012-01-11 16:41:28 (Show Source):
You can put this solution on YOUR website!At the play there is a raffle. Each student is given a number card. The seniors are given 592 cards numbered consecutively with the first number being 358. When the winners are announced, all numbers that are multiples of 50 win a free T-shirt. How many seniors won a free t-shirt? Show your work to explain your answer.
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Ans: Multiples of 50: 400,450,500,550
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4 Seniors won a t-shirt
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Cheers,
Stan H.
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Rational-functions/555584: what is the answer in the retional expression 6c raised to two minus 23c minus 4 all over c raised to two minus 6c plus 8? please show the solution. 1 solutions
Answer 361851 by stanbon(57361) on 2012-01-11 06:17:46 (Show Source):
You can put this solution on YOUR website!what is the answer in the retional expression 6c raised to two minus 23c minus 4 all over c raised to two minus 6c plus 8? please show the solution.
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(6c^2 - 23c - 4)/(c^2 -6c + 8)
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Factor:(6c^2-24c+c-4) / [(c-4)(c-2)]
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= [(6c)(c-4)+(c-4)] / [(c-4)(c-2)]
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= [(c-4)(6c+1)] / [(c-4)(c-2)]
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Cancel the common (c-4) factors:
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= (6c+1)/(c-2)
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Cheers,
Stan H.
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Probability-and-statistics/555436: a license plate is to consist of three digits followed by two uppercase letters. Determine the number of different license plates possible if the first digit cannot be zero, and repetition is not permitted 1 solutions
Answer 361850 by stanbon(57361) on 2012-01-11 06:10:50 (Show Source):
You can put this solution on YOUR website!a license plate is to consist of three digits followed by two uppercase letters. Determine the number of different license plates possible if the first digit cannot be zero, and repetition is not permitted
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1st digit: 9 ways (0 is excluded)
2nd digit: 9 ways (0 is now included)
3rd digit: 8 ways (0 and the 2nd digit are excluded)
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1st Letter: 26 ways
2nd Letter: 25 ways
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Total # of license plates: 9^2*8*26*25 == 421,200
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Cheers,
Stan H.
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Probability-and-statistics/555587: I am really confused. I am in MM207 and do not understand how to solve this problem. Could someone please take me step by step through it so that I understand what I am doing?
Assume you want to estimate with the proportion of students who commute less than 5 miles to work within 2%, what sample size would you need? 1 solutions
Answer 361849 by stanbon(57361) on 2012-01-11 06:06:29 (Show Source):
You can put this solution on YOUR website!Assume you want to estimate with the proportion of students who commute less than 5 miles to work within 2%, what sample size would you need?
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As I told you two days ago, you have to know the confidence level
for your problem because:
n = [z/E]^2*pq
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If the confidence level is 95%, then z = 1.96
Since you have no p-value you use p = 1/2 = q
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Then you would get:
n = [1.96/0.02]^2*(1/2)(1/2) = 2401
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Cheers,
Stan H.
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Graphs/555591: Good Morning,
Can someone show me how to solve and graph the following system of inequalities:
y<-1/2x +2
x-y <= 4
(the second line is x-4 is less than or equal to 4)
Hope to hear from someone soon.
Sincerely,
T.H.
1 solutions
Answer 361848 by stanbon(57361) on 2012-01-11 05:54:24 (Show Source):
You can put this solution on YOUR website!solve and graph the following system of inequalities:
y<-1/2x +2
Graph the line y = (-1/2)x+2 as a dashed line.
Shade the half-plane below that boundary line.
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x-y <= 4
Solve for "y":
y >= x-4
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Graph the line y = x-4
Shade the half-plane above that boundary line.
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The solution set is the intersection of those 2 graphs.

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cheers,
Stan H.
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