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Recent problems solved by 'stanbon'
stanbon answered: 57151 problems
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43110..43139 , 43140..43169 , 43170..43199 , 43200..43229 , 43230..43259 , 43260..43289 , 43290..43319 , 43320..43349 , 43350..43379 , 43380..43409 , 43410..43439 , 43440..43469 , 43470..43499 , 43500..43529 , 43530..43559 , 43560..43589 , 43590..43619 , 43620..43649 , 43650..43679 , 43680..43709 , 43710..43739 , 43740..43769 , 43770..43799 , 43800..43829 , 43830..43859 , 43860..43889 , 43890..43919 , 43920..43949 , 43950..43979 , 43980..44009 , 44010..44039 , 44040..44069 , 44070..44099 , 44100..44129 , 44130..44159 , 44160..44189 , 44190..44219 , 44220..44249 , 44250..44279 , 44280..44309 , 44310..44339 , 44340..44369 , 44370..44399 , 44400..44429 , 44430..44459 , 44460..44489 , 44490..44519 , 44520..44549 , 44550..44579 , 44580..44609 , 44610..44639 , 44640..44669 , 44670..44699 , 44700..44729 , 44730..44759 , 44760..44789 , 44790..44819 , 44820..44849 , 44850..44879 , 44880..44909 , 44910..44939 , 44940..44969 , 44970..44999 , 45000..45029 , 45030..45059 , 45060..45089 , 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56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179, >>NextProbability-and-statistics/575154: 4. The amounts of money requested small business loan applications at GetBuckets Fantake Commercial Savings Bank follows the normal distribution, with a mean of $70,000 and a standard deviation of $20,000. What is the probability that the amount requested is $80,000 or more?
a. .3500
b. .3085
c. .2902
d. .5987
5. Using Problem #4, what is the probability the amount requested is between $65,000 and $80,000?
a. .4500
b. .2902
c. .5987
d. None of the above
1 solutions
Answer 369400 by stanbon(57219) on 2012-02-20 07:26:35 (Show Source):
You can put this solution on YOUR website!4. The amounts of money requested small business loan applications at GetBuckets Fantake Commercial Savings Bank follows the normal distribution, with a mean of $70,000 and a standard deviation of $20,000. What is the probability that the amount requested is $80,000 or more?
a. .3500
b. .3085
c. .2902
d. .5987
---
normalcdf(80000,10^10,70000,20000) = 0.3085
=====================================================
5. Using Problem #4, what is the probability the amount requested is between $65,000 and $80,000?
a. .4500
b. .2902
c. .5987
d. None of the above
normalcdf(65000,80000,70000,20000) = 0.2902
==========
Cheers,
Stan H.
==========
|
Probability-and-statistics/575152: A normal distribution has a mean of 80 and a standard deviation of 14. Compute the probability of a value between 75.0 and 90.0.
a. .2022
b. .3595
c. .4017
d. None of the above
1 solutions
Answer 369399 by stanbon(57219) on 2012-02-20 07:21:01 (Show Source):
You can put this solution on YOUR website!A normal distribution has a mean of 80 and a standard deviation of 14. Compute the probability of a value between 75.0 and 90.0.
a. .2022
b. .3595
c. .4017
d. None of the above
---
Using a TI-84 you get:
normalcdf(75,90,80,14) = 0.4020
=============
Cheers,
Stan H.
==============
|
Probability-and-statistics/575155: 10. The Ho and Ha for a given problem are as follows:
Ho: Mean or u = 999
Ha: Mean or u NE 999
This is a two-tailed test.
a. True
b. False
c. Not enough information to make a decision on the direction of the tail.
d. The direction of the tail is decided after the significance level is settled between the researcher and the sponsor of the research.
1 solutions
Answer 369398 by stanbon(57219) on 2012-02-20 07:18:06 (Show Source):
You can put this solution on YOUR website!The Ho and Ha for a given problem are as follows:
Ho: Mean or u = 999
Ha: Mean or u NE 999
This is a two-tailed test.
a. True
b. False
c. Not enough information to make a decision on the direction of the tail.
d. The direction of the tail is decided after the significance level is settled between the researcher and the sponsor of the research.
---
Ha ALWAYS determines the type of test.
"not equal to" implies a 2-tail test.
Cheers,
Stan H.
|
Age_Word_Problems/575153: a 48 year old man is two times as old as his son. How old was the father when he was three times as old as his son? 1 solutions
Answer 369397 by stanbon(57219) on 2012-02-20 07:16:09 (Show Source):
You can put this solution on YOUR website!a 48 year old man is two times as old as his son. How old was the father when he was three times as old as his son?
--------------
father = 48
son = 24
-------------------------------
Equation:
(48+x) = 3(24+x)
48 + x = 72 + 3x
2x = -24
x = -12
----
Father was 48-12 = 36
Son was 24-12 = 12
=============================
Cheers,
Stan H.
|
Angles/575148: Let p, q, and r be the following statements:
p: Jamie is on the train.
q: Sylvia is at the park.
r: Nigel is in the car.
Translate the following statement into English: (~q ^ p) arrow ~r
(Points : 4)
1 solutions
Answer 369396 by stanbon(57219) on 2012-02-20 07:12:28 (Show Source):
You can put this solution on YOUR website!Let p, q, and r be the following statements:
p: Jamie is on the train.
q: Sylvia is at the park.
r: Nigel is in the car.
Translate the following statement into English: (~q ^ p) arrow ~r
-----
If Sylvia is not at the park and Jamie is on the train then
Nigel is not in the car.
---------
Cheers,
Stan H.
|
Travel_Word_Problems/575063: I rowed 20 km up a river that had a steady current in 5 hours and returned downstream in 2.5 hours. How fast would I have rowed the boat in still water, and what is the speed of the current?
Let x be the speed of the boat in still water and y the speed of the current (km/h). The speed of the boat going upstream is (x –y) km/h and the speed of the boat going downstream is (x+y) km/h,.
1 solutions
Answer 369365 by stanbon(57219) on 2012-02-19 22:19:19 (Show Source):
You can put this solution on YOUR website!I rowed 20 km up a river that had a steady current in 5 hours and returned downstream in 2.5 hours. How fast would I have rowed the boat in still water, and what is the speed of the current?
Let x be the speed of the boat in still water and y the speed of the current (km/h). The speed of the boat going upstream is (x –y) km/h and the speed of the boat going downstream is (x+y) km/h,.
---
Upstream DATA:
distance = 20 km ; rate = (x-y)km/h ; time = 20/(x-y) hr
------------------
Downstream DATA:
distance = 20 km ; rate = (x+y)km/h ; time = 20/(x+y) hr
----
Equation:
20/(x-y) = 5 hrs
20/(x+y) = 2.5 hrs
---------------------------
x-y = 4
x+y = 8
____
Add and solve for "x":
2x = 12
x = 6 km/h (boat speed in calm water)
-----
Solve for "y":
x+y = 8
y = 2 km/h (current speed)
================================
Cheers,
Stan H.
===========================
|
Polynomials-and-rational-expressions/574911: Can someone please help me sovle this problem...Thanks,
find all numbers for which the rational expression is undefined
x^2+17 over x^2-2x-3 1 solutions
Answer 369326 by stanbon(57219) on 2012-02-19 16:12:15 (Show Source):
You can put this solution on YOUR website!find all numbers for which the rational expression is undefined
x^2+17 over x^2-2x-3
----
Undefined when that denominator is zero.
----
Solve x^2-2x-3 = 0
Factor:
(x-3)(x+1) = 0
Undefined when x = 3 or x = -1
=================================
Cheers,
Stan H.
|
Rate-of-work-word-problems/574909: If 5 girls and 2 boys work together they can paint a house in a day. Three girls and 6 boys working together can also paint the house in a day. How long would it take one boy to paint the house by himself? 1 solutions
Answer 369325 by stanbon(57219) on 2012-02-19 16:07:59 (Show Source):
You can put this solution on YOUR website!If 5 girls and 2 boys work together they can paint a house in a day. Three girls and 6 boys working together can also paint the house in a day. How long would it take one boy to paint the house by himself?
-----
Let girl rate = g
Let boy's rate = b
----
Equations:
5g + 2b = 1
3g + 6b = 1
-------
Multiply thru 1st equation by 3
Multiply thru 2nd equation by 5
--------------------------
15g + 6b = 3
15g + 30b = 5
----
Subtract and solve for "b":
24b = 2
b = 1/12 job/day
----
Time for a boy to do the job alone 12 days/job
===================================================
Cheers,
Stan H.
|
Volume/574908: A cube has a volume of 64-cubic inches. What’s the length of one side of the cube?
1 solutions
Answer 369324 by stanbon(57219) on 2012-02-19 16:01:13 (Show Source):
You can put this solution on YOUR website!A cube has a volume of 64-cubic inches. What’s the length of one side of the cube?
---
Vol = side^3
---
side = Vol^(1/3)
-----
Your problem:
side = 64^(1/3) = 4 inches
============================
Cheers,
Stan H.
|
logarithm/574902: 2^(2x)-12*2^(x)+32=0
1 solutions
Answer 369323 by stanbon(57219) on 2012-02-19 15:57:45 (Show Source):
You can put this solution on YOUR website!2^(2x)-12*2^(x)+32=0
---
That is a quadratic with variable = 2^x:
----
(2^x)^2 - 12(2^x) + 32 = 0
-----
Let w = 2^x
----
Substitute:
w^2 - 12w + 32 = 0
Factor:
(w-8)(w-4) = 0
w = 4 or w = 8
-----
Solve for "x":
2^x = 4 implies x = 2
2^x = 8 implies x = 3
============================
Cheers,
Stan H
===========
|
Polynomials-and-rational-expressions/574904: I am so stuck on this problem. I need help i need someone to show me the steps so i can understand. Subtract.
(-4x^2 + 2x) – (5x^2 +2x^6 +3)
1 solutions
Answer 369321 by stanbon(57219) on 2012-02-19 15:52:29 (Show Source):
You can put this solution on YOUR website!I am so stuck on this problem. I need help i need someone to show me the steps so i can understand. Subtract.
(-4x^2 + 2x) – (5x^2 +2x^6 +3)
------
-4x^2 + 2x -5x^2 -2x^6 - 3
----
= -2x^6 -9x^2 + 2x - 3
=================================================================
Cheers,
Stan H.
===========
|
Geometry_Word_Problems/574903: 1. Find 2 summplementary angles such that the measure of the 1st angle is 34 degrees less than 3 times the measure of the second.
I just need to double check on an answer if you could help me out.
Thank you! 1 solutions
Answer 369319 by stanbon(57219) on 2012-02-19 15:48:45 (Show Source):
You can put this solution on YOUR website!Find 2 summplementary angles such that the measure of the 1st angle is 34 degrees less than 3 times the measure of the second.
-----
Equations:
x = 180-y
x = 3y-34
-----
Substitute for "x" and solve for "y":
180-y = 3y -34
4y = 214
y = 53.5 degrees
----
x = 126.5 degrees
=====================
Cheers,
Stan H.
|
test/574818: I have a big test and cannot firqure this out please help
A cellular phone company offers a contract for which the cost C, in dollars, of T minutes of telephoning is given by C=0.25(t-600)+50.95, where it is assumed that t is greater then or equal to 600 minutes. What time keeps the cost between $97.95 and $123.45?
for the cost to be between 97.95 and 123.45 the time must be between and minutes 1 solutions
Answer 369301 by stanbon(57219) on 2012-02-19 11:55:51 (Show Source):
You can put this solution on YOUR website!C=0.25(t-600)+50.95, where it is assumed that t is greater then or equal to 600 minutes. What time keeps the cost between $97.95 and $123.45?
-----------
97.95 <= 0.25(t-600)+50.95 <= 123.45
----
Subtract 50.95 along the line:
----
45 <= 0.25(t-600) <=72.50
---
Divide through by 0.25 to get:
180 <= t-600 <= 290
----
Add 600 along the line:
780 <= t <=890
==================
Cheers,
Stan H.
==================
|
Travel_Word_Problems/574816: A boat can travel at a speed of 12km / h in still water. If it takes three hours to go 15km upstream and back, find the speed of the current. 1 solutions
Answer 369299 by stanbon(57219) on 2012-02-19 11:38:14 (Show Source):
You can put this solution on YOUR website!A boat can travel at a speed of 12km / h in still water. If it takes three hours to go 15km upstream and back, find the speed of the current.
-----------------------
Upstream DATA:
rate = 12-c km/h ; distance = 15 km ; time = 15/(12-c) hrs
------
Downstream DATA:
rate = 12+c km/h ; distance = 15 km ; time = 15/(12+c) hrs
--------
Equation:
time + time = 3 hrs.
15/(12-c) + 15/(12+c) = 3
-----
[15(12+c) + 15(12-c) = 3(144-c^2)
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360 = 3(144-c^2
120 = 144-c^2
c^2 = 24
c = 2sqrt(6) km/h (speed of the current)
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Cheers,
Stan H.
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Equations/574769: Determine if the following sets are closed under multiplication:
a. {0}
b. {1, 3, 5, 7, 9,...}
c. {0, 1, 2} 1 solutions
Answer 369274 by stanbon(57219) on 2012-02-19 09:06:59 (Show Source):
You can put this solution on YOUR website!Determine if the following sets are closed under multiplication:
a. {0}
0*0 = 0 ; closed under multiplication
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b. {1, 3, 5, 7, 9,...}
The product of any 2 odd numbers is an odd number: true
So closed under multiplication.
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c. {0, 1, 2}
0*0 or 1 or 2 is 0
1*0 = 0 ; 1*1 = 1 ; but 2*2 = 4
Not closed under multiplication.
Cheers,
Stan H.
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Age_Word_Problems/574770: one year ago, ram's age was 8 times his son's age.Now his age is equal to square of his son's age .find their present age. 1 solutions
Answer 369273 by stanbon(57219) on 2012-02-19 09:03:04 (Show Source):
You can put this solution on YOUR website!one year ago, ram's age was 8 times his son's age.Now his age is equal to square of his son's age .find their present age.
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Equations:
r-1 = 8(s-1)
r = s^2
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Substitute for "r" and solve for "s":
s^2-1 = 8s-8
s^2-8s+7 = 0
Factor:
(s-7)(s-1) = 0
Acceptable solution:
s = 7 yrs (son's age now)
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r = s^2 = 49 (father's age now)
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Cheers,
Stan H.
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Sequences-and-series/574584: Can someone plz help me. plz show me how to work this problem. adding the polynomials.
(1/8x^2 -1/4x -3/8) + (-1/2x^2 -1/4x -1/2) 1 solutions
Answer 369164 by stanbon(57219) on 2012-02-18 13:00:01 (Show Source):
You can put this solution on YOUR website!adding the polynomials.
(1/8x^2 -1/4x -3/8) + (-1/2x^2 -1/4x -1/2)
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= ((1/8)-(1/2))x^2 + ((-1/4)+(-1/4))x + ((-3/8)+(-1/2))
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= (-3/8)x^2 + (-1/2)x + (-7/8)
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Cheers,
Stan H.
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Linear-equations/574598: Please help me solve this problem.
A total of 508 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student tickets sold was three times the number of adult tickets sold. How many adult tickets were sold? 1 solutions
Answer 369160 by stanbon(57219) on 2012-02-18 12:47:58 (Show Source):
You can put this solution on YOUR website!Please help me solve this problem.
A total of 508 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student tickets sold was three times the number of adult tickets sold. How many adult tickets were sold?
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Quantity Eq: a + s = 508
Quantity Eq: s = 3a
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Substitute for "s" and solve for "a":
a + 3a = 508
4a = 508
a = 127 (# of adult tickets sold)
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Solve for "s":
s = 3a
s = 3*127
s = 381 (# of student tickets sold)
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Cheers,
Stan H.
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Probability-and-statistics/574592: Show all work. A disc jockey has 7 songs to play. 5 are slow songs, and 2 are fast songs. each song is to be played only once. In how many ways can the disc jockey play the 7 songs if:
a)the songs can be played in any order
b)the first song must be a slow song and the last song must be a slow song
c)the first two songs must be fast songs
1 solutions
Answer 369158 by stanbon(57219) on 2012-02-18 12:32:25 (Show Source):
You can put this solution on YOUR website!A disc jockey has 7 songs to play. 5 are slow songs, and 2 are fast songs. each song is to be played only once. In how many ways can the disc jockey play the 7 songs if:
a)the songs can be played in any order:: 7! = 5040
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b)the first song must be a slow song and the last song must be a slow song
1st song: 5
last song: 4
middle 5 songs: 5!
---
# = 5*4*5! = 20*120 = 2400
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c)the first two songs must be fast songs
1st 2 songs: 2
last 5 songs: 5!
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# = 2*120 = 240
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Cheers,
Stan H.
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Probability-and-statistics/574595: Sow all work. Mary purchased a package of 18 different plants, but she only needed 12 plants for planting. In how many ways can she select the 12 plants from the package to be planted? 1 solutions
Answer 369156 by stanbon(57219) on 2012-02-18 12:26:05 (Show Source):
You can put this solution on YOUR website!Mary purchased a package of 18 different plants, but she only needed 12 plants for planting. In how many ways can she select the 12 plants from the package to be planted?
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Ans: 18C12 = 18C6 = 18564
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Cheers,
Stan H.
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Probability-and-statistics/574574: I really need help!!! thanks Suppose we want to estimate the average number of purchases in a given hour in a local convenience store. Using this example, describe how you would go about determining this average through:
a. Drawing a random sample
b. Drawing a systematic sample
c. Drawing a convenience sample 1 solutions
Answer 369140 by stanbon(57219) on 2012-02-18 11:26:14 (Show Source):
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Probability-and-statistics/574576: A machine has 9 identical components which function independently. The probability that a component will fail is 0.2. The machine will stop working if more than three components fail. Find the probability that the machine will be working. 1 solutions
Answer 369138 by stanbon(57219) on 2012-02-18 11:24:52 (Show Source):
You can put this solution on YOUR website!A machine has 9 identical components which function independently. The probability that a component will fail is 0.2. The machine will stop working if more than three components fail. Find the probability that the machine will be working.
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Binomial Problem with n = 9 and p(fail) = 0.02
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P(0<= x <=3) = binomcdf(9,0.02,3) = 0.9993
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Cheers,
Stan H.
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Probability-and-statistics/574577: A company purchases shipments of machine components and uses this acceptance sampling plan: Randomly select and test 21 components and accept the whole batch if there are fewer than 3 defectives. If a particular shipment of thousands of components actually has a 6% rate of defects, what is the probability that this whole shipment will be accepted 1 solutions
Answer 369137 by stanbon(57219) on 2012-02-18 11:22:07 (Show Source):
You can put this solution on YOUR website!A company purchases shipments of machine components and uses this acceptance sampling plan: Randomly select and test 21 components and accept the whole batch if there are fewer than 3 defectives. If a particular shipment of thousands of components actually has a 6% rate of defects, what is the probability that this whole shipment will be accepted
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Binomial problem with n = 21 and p(defect) = 0.06
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P(0<= x <=2) = binomcdf(21,0.06,2) = 0.8716
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Cheers,
Stan H.
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