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Recent problems solved by 'stanbon'
stanbon answered: 57178 problems
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47070..47099 , 47100..47129 , 47130..47159 , 47160..47189 , 47190..47219 , 47220..47249 , 47250..47279 , 47280..47309 , 47310..47339 , 47340..47369 , 47370..47399 , 47400..47429 , 47430..47459 , 47460..47489 , 47490..47519 , 47520..47549 , 47550..47579 , 47580..47609 , 47610..47639 , 47640..47669 , 47670..47699 , 47700..47729 , 47730..47759 , 47760..47789 , 47790..47819 , 47820..47849 , 47850..47879 , 47880..47909 , 47910..47939 , 47940..47969 , 47970..47999 , 48000..48029 , 48030..48059 , 48060..48089 , 48090..48119 , 48120..48149 , 48150..48179 , 48180..48209 , 48210..48239 , 48240..48269 , 48270..48299 , 48300..48329 , 48330..48359 , 48360..48389 , 48390..48419 , 48420..48449 , 48450..48479 , 48480..48509 , 48510..48539 , 48540..48569 , 48570..48599 , 48600..48629 , 48630..48659 , 48660..48689 , 48690..48719 , 48720..48749 , 48750..48779 , 48780..48809 , 48810..48839 , 48840..48869 , 48870..48899 , 48900..48929 , 48930..48959 , 48960..48989 , 48990..49019 , 49020..49049 , 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53010..53039 , 53040..53069 , 53070..53099 , 53100..53129 , 53130..53159 , 53160..53189 , 53190..53219 , 53220..53249 , 53250..53279 , 53280..53309 , 53310..53339 , 53340..53369 , 53370..53399 , 53400..53429 , 53430..53459 , 53460..53489 , 53490..53519 , 53520..53549 , 53550..53579 , 53580..53609 , 53610..53639 , 53640..53669 , 53670..53699 , 53700..53729 , 53730..53759 , 53760..53789 , 53790..53819 , 53820..53849 , 53850..53879 , 53880..53909 , 53910..53939 , 53940..53969 , 53970..53999 , 54000..54029 , 54030..54059 , 54060..54089 , 54090..54119 , 54120..54149 , 54150..54179 , 54180..54209 , 54210..54239 , 54240..54269 , 54270..54299 , 54300..54329 , 54330..54359 , 54360..54389 , 54390..54419 , 54420..54449 , 54450..54479 , 54480..54509 , 54510..54539 , 54540..54569 , 54570..54599 , 54600..54629 , 54630..54659 , 54660..54689 , 54690..54719 , 54720..54749 , 54750..54779 , 54780..54809 , 54810..54839 , 54840..54869 , 54870..54899 , 54900..54929 , 54930..54959 , 54960..54989 , 54990..55019 , 55020..55049 , 55050..55079 , 55080..55109 , 55110..55139 , 55140..55169 , 55170..55199 , 55200..55229 , 55230..55259 , 55260..55289 , 55290..55319 , 55320..55349 , 55350..55379 , 55380..55409 , 55410..55439 , 55440..55469 , 55470..55499 , 55500..55529 , 55530..55559 , 55560..55589 , 55590..55619 , 55620..55649 , 55650..55679 , 55680..55709 , 55710..55739 , 55740..55769 , 55770..55799 , 55800..55829 , 55830..55859 , 55860..55889 , 55890..55919 , 55920..55949 , 55950..55979 , 55980..56009 , 56010..56039 , 56040..56069 , 56070..56099 , 56100..56129 , 56130..56159 , 56160..56189 , 56190..56219 , 56220..56249 , 56250..56279 , 56280..56309 , 56310..56339 , 56340..56369 , 56370..56399 , 56400..56429 , 56430..56459 , 56460..56489 , 56490..56519 , 56520..56549 , 56550..56579 , 56580..56609 , 56610..56639 , 56640..56669 , 56670..56699 , 56700..56729 , 56730..56759 , 56760..56789 , 56790..56819 , 56820..56849 , 56850..56879 , 56880..56909 , 56910..56939 , 56940..56969 , 56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179, >>NextProbability-and-statistics/579018: There are four people playing a game with a standard die. In the game, the person who rolls the lowest number wins. Ties are broken by continuing to roll until the tie is broken. One of the four people rolls a three. What is the probability that they will win?
1 solutions
Answer 370826 by stanbon(57246)   on 2012-02-27 17:58:04 (Show Source):
You can put this solution on YOUR website!There are four people playing a game with a standard die. In the game, the person who rolls the lowest number wins. Ties are broken by continuing to roll until the tie is broken. One of the four people rolls a three. What is the probability that they will win?
----
The only way they can lose is for someone to roll a 1 or a 2.
---
The way they will win is for others to roll 4,5, or 6.
---
P(they will win) = 3/6 = 1/2
===================================
Cheers,
Stan H.
|
Probability-and-statistics/578909: Assume drivers are independent.
a) If 5% of the drivers fail to stop at a red light, find the probability tahat at least 2 of the next 100 drivers fail to stop.
b) If on the average 3 drivers fail to stop at the red light during each rush hour, what is the probability that at least 2 drivers fail to stop at the red light during tonight’s rush hour?
1 solutions
Answer 370824 by stanbon(57246) on 2012-02-27 17:45:43 (Show Source):
You can put this solution on YOUR website!Assume drivers are independent.
a) If 5% of the drivers fail to stop at a red light, find the probability that at least 2 of the next 100 drivers fail to stop.
Binomial Problem with n = 100 and p(fail to stop) = 0.05
P(2<= x <=100) = 1- binomcdf(100,0.05,1) = 0.9629
===========================================================
b) If on the average 3 drivers fail to stop at the red light during each rush hour, what is the probability that at least 2 drivers fail to stop at the red light during tonight’s rush hour?
That is a Poisson problem.
Cheers,
Stan H.
|
Probability-and-statistics/578882: If a committee of 4 workers is to be chosen what is the probability that it must include at least 2 males?
*there are five males and 5 females
1 solutions
Answer 370823 by stanbon(57246) on 2012-02-27 17:35:06 (Show Source):
You can put this solution on YOUR website!If a committee of 4 workers is to be chosen what is the probability that it must include at least 2 males?
*there are five males and 5 females
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# of ways to succeed : 5C2+5C3+5C4 = 10+10+5 = 25
-----
# of random groups of 4: 10C4 = 210
===============
Ans: 25/210 = 5/42
======================
Cheers,
Stan H.
|
Probability-and-statistics/578942: The probability that a hockey game will go into overtime is .3; Of the next 12 hockey games, what is the probability that more than 3 (P(x >3)) will go into overtime?
I think this is Poisson, but am not 100 percent sure. Would appreciate some guidance. Thank you.
1 solutions
Answer 370818 by stanbon(57246) on 2012-02-27 16:53:44 (Show Source):
You can put this solution on YOUR website!The probability that a hockey game will go into overtime is .3; Of the next 12 hockey games, what is the probability that more than 3 (P(x >3)) will go into overtime?
-----------------------
Binomial Problem with n = 12 and p(overtime) = 0.3
----
P(4<= x <=12) = 1 - P(0<= x <=3) = 1 - binomcdf(12,0.3,3)
---
= 1 - 0.4925
----
= 0.5075
=============
Cheers,
Stan H.
=============
|
Age_Word_Problems/578962: Can you please help me solve the following problem.
Tomorrow,the number of candles on Claire's birthday cake will be one less than three times two-fifths of the number five years ago.How old is Claire today?
1 solutions
Answer 370816 by stanbon(57246) on 2012-02-27 16:45:07 (Show Source):
You can put this solution on YOUR website!Tomorrow,the number of candles on Claire's birthday cake will be one less than three times two-fifths of the number five years ago.
How old is Claire today?
------
Equation:
x = 3(2/5)(x-5)-1
---
x+1 = (6/5)(x-5)
----
5x+5 = 6x-30
x = 35 (Claire's age today)
================================
Cheers,
Stan H.
===============
|
Proportions/574059: solve each proportion
1. n/6= 25/30
2. 6.1/x= 2/3
3. 100/25= t/4
I need help ASAP!
Help!
1 solutions
Answer 370805 by stanbon(57246) on 2012-02-27 14:12:01 (Show Source):
You can put this solution on YOUR website!solve each proportion
1. n/6= 25/30
Multiply both sides by 6 to get:
n = 6(25/30)
n = (6/30)*25
n = (1/5)*25
n = 5
==============================
2. 6.1/x= 2/3
Invert both sides:
x/6.1 = 3/2
Multiply both sides by 6.1 to get:
x = 6.1(3/2)
x = 18.3/2
x = 9.15
=========================
3. 100/25= t/4
Multiply both sides by 4 to get:
t = 4(100/25)
t = 4*4
t = 16
================
cheers,
Stan H.
|
Proportions/578870: I'm doing proportions with fractions well at least that's what the lessons called and I need help understanding it
1 solutions
Answer 370804 by stanbon(57246) on 2012-02-27 14:05:49 (Show Source):
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Probability-and-statistics/578761: i would please like help with this question,
"if may of a particular year was picked at random, what is the probability that average high temperature for that may was exactly 70 degrees?"
thank you!
1 solutions
Answer 370788 by stanbon(57246) on 2012-02-27 12:41:03 (Show Source):
You can put this solution on YOUR website!i would please like help with this question,
"if may of a particular year was picked at random, what is the probability that average high temperature for that may was exactly 70 degrees?"
---
Answer: Temperature is a continuous variable (as opposed to a discrete variable).
---
In a continuous distribution the propability of any particular value is zero.
Your answer is zero.
=========================
cheers,
Stan H.
|
Probability-and-statistics/578817: Given: P(good)= 0.70 and P(defective)= 0.30
In a sample of five items, find P(exactly four are good)
1 solutions
Answer 370785 by stanbon(57246) on 2012-02-27 12:35:30 (Show Source):
You can put this solution on YOUR website!Given: P(good)= 0.70 and P(defective)= 0.30
In a sample of five items, find P(exactly four are good)
-----
P(x = 4) = 5C4*0.7^4*0.3 = binompdf(5,0.7,4) = 0.3601
==============
Cheers,
Stan H.
=============
|
Probability-and-statistics/578786: Assume that blood pressure readings are normally distributed with a mean of 117 and a standard deviation of 5. A researcher wishes to select people for a study but wants to exclude the top 10 percent. What would be the cutoff blood pressure to qualify for the study?
a)120.5
b)117.0
c)124.6
d)123.4
e)121.8
1 solutions
Answer 370784 by stanbon(57246) on 2012-02-27 12:32:42 (Show Source):
You can put this solution on YOUR website!Assume that blood pressure readings are normally distributed with a mean of 117 and a standard deviation of 5. A researcher wishes to select people for a study but wants to exclude the top 10 percent. What would be the cutoff blood pressure to qualify for the study?
Find the z-value with a left-tail of 0.90
invNorm(0.90) = 1.6449
---
Find the corresponding bp value:
bp = z*s + u
---
blood pressure = 1.6449*5+117 = 125.22
===============
Cheers,
Stan H.
===============
a)120.5
b)117.0
c)124.6
d)123.4
e)121.8
|
Probability-and-statistics/578804: 3 red and 4 blue balls are in a basket. A member of PPTeam is drawing balls from the basket. What is the probablity of getting the 3 red balls simultaneously?
1 solutions
Answer 370783 by stanbon(57246) on 2012-02-27 12:27:21 (Show Source):
You can put this solution on YOUR website!3 red and 4 blue balls are in a basket. A member of PPTeam is drawing balls from the basket. What is the probablity of getting the 3 red balls simultaneously?
----
# of ways to succeed: 3C3 = 1
---
# of random triples: 7C3 = 35
----
P(3 red) = 1/35
===================
Cheers,
Stan H.
===================
|
Probability-and-statistics/578529: There are 4 white marbles,6 red marbles, and 2 blue marbles. Once a marble is selected,it is not replaced.Find the probability of selecting 2 blue marbles.
1 solutions
Answer 370729 by stanbon(57246) on 2012-02-27 08:37:37 (Show Source):
You can put this solution on YOUR website!There are 4 white marbles,6 red marbles, and 2 blue marbles. Once a marble is selected,it is not replaced.Find the probability of selecting 2 blue marbles.
---
# of ways to succeed: 2C2 = 1
---
# of random pairs: 12C2 = 66
---
P(2 blue) = 1/66
====================
Cheers,
Stan H.
|
Probability-and-statistics/578703: 10 chemists and 15 biologists apply for a position in a company. If 5 people are hired at random, what is the probability that 2 are chemists and 3 are biologists?
1 solutions
Answer 370728 by stanbon(57246) on 2012-02-27 08:34:58 (Show Source):
You can put this solution on YOUR website!10 chemists and 15 biologists apply for a position in a company. If 5 people are hired at random, what is the probability that 2 are chemists and 3 are biologists?
-----
# of ways to succeed: 10C2*15C3 = 45*455
---
# of random sets of 5: 25C5 = 53130
----
Ans: (45*455)/53130 = 0.3854
==================
Cheers,
Stan H.
==================
|
Probability-and-statistics/578590: 2) According to a recent survey approximately 68% of students at this campus are women. A group of 20 students are randomly selected. What is the probability that 15 of them are women?
1 solutions
Answer 370724 by stanbon(57246) on 2012-02-27 07:39:45 (Show Source):
You can put this solution on YOUR website!According to a recent survey approximately 68% of students at this campus are women. A group of 20 students are randomly selected. What is the probability that 15 of them are women?
-----------------
Binomial Problem with n = 20 and p(woman) = 0.68
----
P(x = 15) = 20C15(0.68)^15*(0.32)^5 = binompdf(20,0.68,15) = 0.1699
====================
Cheers,
Stan H.
=====================
|
Probability-and-statistics/578613: What is the p-value when we test H0 : µ = 10 versus Ha: µ < 10 and have a calculated test statistic Z = -2.41
1 solutions
Answer 370723 by stanbon(57246) on 2012-02-27 07:36:35 (Show Source):
You can put this solution on YOUR website!What is the p-value when we test H0 : µ = 10 versus Ha: µ < 10 and have a calculated test statistic Z = -2.41
p-value = P(z< -2.41) = normalcdf(-100,-2.41) = 0.0080
=================
Cheers,
Stan H.
|
Probability-and-statistics/578618: A set of data is normally distributed with a mean of 500 and standard deviation of 100.
What would be the standard score for a score of 400?
What percentage of scores is between 500 and 400?
What would be the percentile rank for a score of 400?
1 solutions
Answer 370722 by stanbon(57246) on 2012-02-27 07:34:28 (Show Source):
You can put this solution on YOUR website!A set of data is normally distributed with a mean of 500 and standard deviation of 100.
What would be the standard score for a score of 400?
z(400) = (400-500)/100 = -1
----------------------------------------
What percentage of scores is between 500 and 400?
P(400< x <500) = P(-1< z < 0) = 0.3413
---------------------------------------------------------
What would be the percentile rank for a score of 400?
The left tail of z = -1 = normalcdf(-100,-1) = 0.1587 = 16%ile when rounded up.
=================================
Cheers,
Stan H.
-----------------
|
Probability-and-statistics/578629: Consider using p-value to test H0 versus Ha by setting α equal to .10. We reject H0 at level α of significance if and only if the p-value is:
1 solutions
Answer 370721 by stanbon(57246) on 2012-02-27 07:29:41 (Show Source):
You can put this solution on YOUR website!Consider using p-value to test H0 versus Ha by setting α equal to .10.
We reject H0 at level α of significance
if and only if the p-value is < 0.10
-----------------
Cheers,
Stan H.
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Probability-and-statistics/578667: There were 19 people at your latest Narcoleptics Anonymous meeting (there would have been more, but they wer asleep?. After the meeting everyone decides to pile into the five corporate minis and drive to the coffe shop for a CAFFEINE FIX. Unfortunately, there were 7 people who haven't been taking their medication. Find the probalilty that;
a) all five drivers have been taking medication?
b) none of the drivers are taking their medication?
c) at least one of them iss not taking medication?
1 solutions
Answer 370720 by stanbon(57246) on 2012-02-27 07:26:26 (Show Source):
You can put this solution on YOUR website!There were 19 people at your latest Narcoleptics Anonymous meeting (there would have been more, but they wer asleep?. After the meeting everyone decides to pile into the five corporate minis and drive to the coffe shop for a CAFFEINE FIX. Unfortunately, there were 7 people who haven't been taking their medication.
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Total number of people: 19
# not taking med: 7
# taking med: 12
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Find the probalilty that;
a) all five drivers have been taking medication?
Ans: 12C5/19C5 = 0.0681
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b) none of the drivers are taking their medication?
Ans: (7/19)^5 = 0.0068
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c) at least one of them is not taking medication?
Ans: 1 - 0.0068 = 0.9932
==========================
Cheers,
Stan H.
==========================
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Probability-and-statistics/578680: A GROUP OF STUDENTS WAS ASKED TO INDICATE THEIR PREFERENCE FOR REGULAR or diet soft drinks. of 14 males, 11 preferred regular softdrinks. of 11 females, 7 preferresd diet soft drinks . if a students is selected at random: given the students was a male, what would be the probabilitythat he preferred a regular softdrinks?
1 solutions
Answer 370719 by stanbon(57246) on 2012-02-27 07:20:56 (Show Source):
You can put this solution on YOUR website!A GROUP OF STUDENTS WAS ASKED TO INDICATE THEIR PREFERENCE FOR REGULAR or diet soft drinks. of 14 males, 11 preferred regular softdrinks. of 11 females, 7 preferresd diet soft drinks . if a students is selected at random: given the students was a male, what would be the probabilitythat he preferred a regular softdrinks?
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Note: When you have a "given" phrase, the given set becomes your Universe.
Ans: 11/14
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Cheers,
Stan H.
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Linear_Algebra/578689: How does one show that an operator is invertible?
1 solutions
Answer 370718 by stanbon(57246) on 2012-02-27 07:16:57 (Show Source):
You can put this solution on YOUR website!How does one show that an operator is invertible?
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Let's say "a" is your operator.
---
You want it to operate on "b"
---
It gives you "c" as a result.
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Now assume you have an operator "d"
---
You want it to operate on "c" and it gives you "a".
===============
Do you see that "d" has undone what "b" did?
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That means "b" and "d" are inverse operators.
It also shows that "b" is invertible: it can be undone.
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Dressing and undressing are invertible.
Eating is not invertible.
==============================
Cheers,
Stan H.
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Numbers_Word_Problems/578692: Four less than six times a certain number is equal to 40 more than one-half of the number. Find the number
1 solutions
Answer 370717 by stanbon(57246) on 2012-02-27 07:10:55 (Show Source):
You can put this solution on YOUR website!Four less than six times a certain number is equal to 40 more than one-half of the number. Find the number
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Equation:
6x-4 = (1/2)x + 40
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Multiply thru by 2 to get:
12x-8 = x + 80
11x = 88
x = 8
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Cheers,
Stan H.
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Signed-numbers/578687: sketch this equation and find domain and range
f(x)= 2/x-3
1 solutions
Answer 370716 by stanbon(57246) on 2012-02-27 07:07:37 (Show Source):
You can put this solution on YOUR website!sketch this equation and find domain and range
f(x)= 2/(x-3)
The denominator cannot be zero.
So the Domain is "All Real Numbers except x = 3".
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The Horizontal asymptote is y = (0*x)/(1*x) = 0/1 = 0
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So the Range is "All Real Numbers except y = 0".
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===============
Cheers,
Stan H.
===============
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Probability-and-statistics/578390: assume that x has a normal distribution, and find the indicated probablility. The mean is 60.0 and the standard deviation is 4.0. Find the probability that x is less than 53.0
1 solutions
Answer 370693 by stanbon(57246) on 2012-02-26 22:07:56 (Show Source):
You can put this solution on YOUR website!assume that x has a normal distribution, and find the indicated probablility. The mean is 60.0 and the standard deviation is 4.0. Find the probability that x is less than 53.0
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z(53) = (53-60)/4.0 = -7/4
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P(x < 53) = P(z < -7/4) = normalcdf(-100,-7/4) = 0.0401
======================
Cheers,
Stan H.
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Probability-and-statistics/578576: Find the probability of getting 2 face cards (king, queen, jack) when 3 cards are drawn from a deck without replacement.
Please help!!
1 solutions
Answer 370692 by stanbon(57246) on 2012-02-26 21:59:23 (Show Source):
You can put this solution on YOUR website!Find the probability of getting 2 face cards (king, queen, jack) when 3 cards are drawn from a deck without replacement.
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There are 12 face cards.
# of ways to succeed: 12C2*40C1 = 66*40 = 2640
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# of random triples: 52C3 = 22100
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Probility = 2640/22100 = 0.1195
==================================
Cheers,
Stan H.
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Probability-and-statistics/578567: A survey conducted by USA today showed that 118 of 250 investors owned some real estate. In the past it showed that 45% of investors owned some real estate. Has the number of investors that own some real estate increased? Use alpha =.01
1 solutions
Answer 370690 by stanbon(57246) on 2012-02-26 21:51:17 (Show Source):
You can put this solution on YOUR website!A survey conducted by USA today showed that 118 of 250 investors owned some real estate. In the past it showed that 45% of investors owned some real estate. Has the number of investors that own some real estate increased? Use alpha =.01
--------------------------------
Ho: p <= 0.45
Ha: p > 0.45 (claim)
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sample proportion = 118/250 = 0.4720
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p(0.4720) = (0.4720-0.45)/sqrt[0.45*0.55/250] = 0.6356
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p-value = P(z > 0.6356) = normalcdf(0.6356,100) = 0.2625
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Since the p-value is greater than 5%, fail to reject Ho.
The test results do not support the claim.
==============
Cheers,
Stan H.
==============
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Probability-and-statistics/578570: to purchase a lottery ticket, you must select 4 numbers from 0 to 9. How many possible lottery tickets can be chosen?
I know the answer is 10,000, but how do you get to that answer?
1 solutions
Answer 370686 by stanbon(57246) on 2012-02-26 21:40:10 (Show Source):
You can put this solution on YOUR website!to purchase a lottery ticket, you must select 4 numbers from 0 to 9.
How many possible lottery tickets can be chosen?
I know the answer is 10,000, but how do you get to that answer?
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# of ways to pick the 1st number: 10
# of ways to pick the 2nd number: 10
# of ways to pick the 3rd:::::::: 10
# of ways to pick the 4th:::::::: 10
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Total # = 10*10*10*10 = 10,000
===================================
Cheers,
Stan H.
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