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# Recent problems solved by 'stanbon'

Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 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 Functions/752971: f(x) = 5x and g(x) = x-4 Find: f[g(2)]1 solutions Answer 458154 by stanbon(57967)   on 2013-05-27 16:58:00 (Show Source): You can put this solution on YOUR website!f(x) = 5x and g(x) = x-4 Find: f[g(2)]= f[2-4] = f(-2) = 5(-2) = -10 ==================== Cheers, Stan H. -----
 t e s t/752972: Solve: y+2/2 = 2y/3 or y+2 2y --- = -- 2 3 or y+2 over 2 is equal to 2y over 31 solutions Answer 458153 by stanbon(57967)   on 2013-05-27 16:55:26 (Show Source): You can put this solution on YOUR website!Solve: (y+2)/2 = (2y)/3 ------------------ Cross-multiply to get: 3y+6 = 4y ------------------- y = 6 -------------- Cheers, Stan H. =====================
 Quadratic-relations-and-conic-sections/752970: Write an equation for each parabola described below. Then draw the graph. vertex (1,3) directrix x =7/8 Could you show me the steps and process to get the answer?1 solutions Answer 458151 by stanbon(57967)   on 2013-05-27 16:51:54 (Show Source): You can put this solution on YOUR website!Write an equation for each parabola described below. Then draw the graph. vertex (1,3) directrix x =7/8 Could you show me the steps and process to get the answer? ------- Note: The vertex is to the right of the directrix so the parabola is opening to the right. ---- Form: (y-k)^2 = 4p(x-h) ---- p is the distance from the directrix to the vertex. ---- p = 1-(7/8) = 1/8 ---- h = 1 and k = 3 ----------------------- Equation: (y-3)^2 = 4(1/8)(x-1) ---- (y-3)^2 = (1/2)(x-1) ------------------------- The graph is not a function so it cannot be shown on this site. ---- Sketch the vertical line x = 7/8 Plot the vertex at (1,3) Sketch a parabola opening to the right. =================== Cheers, Stan H. ===================
 �t�e�s�t/752967: I am thinking of a number I mutiply it by 10 and subtract by 89 I get the same answer if I multiply it by 5 and subtract by 14 What is my number?1 solutions Answer 458149 by stanbon(57967)   on 2013-05-27 16:44:48 (Show Source): You can put this solution on YOUR website! I am thinking of a number I mutiply it by 10 and subtract by 89 I get the same answer if I multiply it by 5 and subtract by 14 What is my number? ------- Let the number be "x". Equation: 10x-89 = 5x-14 5x = 75 x = 15 ============== Cheers, Stan H. ==============
 t e s t/752966: Solve the equation. Check for extraneous solutions! Problem 1. (k)/(k+4) +(4)/(k-4) = (4k+12)/(k+4)(k-4) 1 solutions Answer 458148 by stanbon(57967)   on 2013-05-27 16:42:37 (Show Source): You can put this solution on YOUR website!(k)/(k+4) +(4)/(k-4) = (4k+12)/(k+4)(k-4) ------ Multiply thru by (k+4)(k-4) to get: k(k-4) + 4(k+4) = 4k+12 ----- k^2 +16 = 4k+12 k^2 - 4k + 4 = 0 --- (k-2)^2 = 0 --- k = 2 with multiplicity 2 =============================== Cheers, Stan H. ================
 Probability-and-statistics/752964: I have zero idea what this question is even asking me and really need some help.Thank you Three experiments investigating the relation between need for cognitive closure and persuasion were performed. Part of the study involved administering a "need for closure scale" to a group of students enrolled in an introductory psychology course. The "need for closure scale" has scores ranging from 101 to 201. For the 73 students in the highest quartile of the distribution, the mean score was x = 178.70. Assume a population standard deviation of σ = 7.81. These students were all classified as high on their need for closure. Assume that the 73 students represent a random sample of all students who are classified as high on their need for closure. How large a sample is needed if we wish to be 95% confident that the sample mean score is within 2 points of the population mean score for students who are high on the need for closure? 1 solutions Answer 458144 by stanbon(57967)   on 2013-05-27 16:39:15 (Show Source): You can put this solution on YOUR website!Three experiments investigating the relation between need for cognitive closure and persuasion were performed. Part of the study involved administering a "need for closure scale" to a group of students enrolled in an introductory psychology course. The "need for closure scale" has scores ranging from 101 to 201. For the 73 students in the highest quartile of the distribution, the mean score was x = 178.70. Assume a population standard deviation of σ = 7.81. These students were all classified as high on their need for closure. Assume that the 73 students represent a random sample of all students who are classified as high on their need for closure. How large a sample is needed if we wish to be 95% confident that the sample mean score is within 2 points of the population mean score for students who are high on the need for closure? ------ n = [z*s/E]^2 ---- n = [1.96*7.81/2]^2 = 59 when rounded up ================ Cheers, Stan H. ==================
 Probability-and-statistics/752808: A class has 10 boys and 5 girls. Three students are selected at random one after another. Find the probability that (i) first two are boys and third is girl (ii) first and third are of same sex and the second is of opposite sex.1 solutions Answer 458096 by stanbon(57967)   on 2013-05-27 11:18:03 (Show Source): You can put this solution on YOUR website!answered
 Probability-and-statistics/752817: (a) A class has 10 boys and 5 girls. Three students are selected at random one after another. Find the probability that (i) first two are boys and third is girl (ii) first and third are of same sex and the second is of opposite sex. 1 solutions Answer 458095 by stanbon(57967)   on 2013-05-27 11:16:50 (Show Source): You can put this solution on YOUR website! (a) A class has 10 boys and 5 girls. Three students are selected at random one after another. Find the probability that (i) first two are boys and third is girl P(bbg) = (10/15)(9/14)(5/13) ---------------------------------------- (ii) first and third are of same sex and the second is of opposite sex. P(bgb) + P(gbg) = (10/15)(5/14)(9/13) + (5/15)(10/14)(4/13) ======================== cheers, Stan H. ========================
 Probability-and-statistics/752848: A standard six-sided die is rolled. Find the odds in favor of rolling a 3?1 solutions Answer 458092 by stanbon(57967)   on 2013-05-27 11:01:46 (Show Source): You can put this solution on YOUR website!A standard six-sided die is rolled. Find the odds in favor of rolling a 3? ------ P(x = 3) = 1/6 P(x # 3) = 5/6 ----- odds in favor = P(x=3)/P(x#3) = 1:5 ----------------------------------- Cheers, Stan H. ========================
 Probability-and-statistics/752852: Please explain to me how to multiply 0.5 by 0.2. Thanks for your help!1 solutions Answer 458091 by stanbon(57967)   on 2013-05-27 10:58:30 (Show Source): You can put this solution on YOUR website!Please explain to me how to multiply 0.5 by 0.2. Thanks for your help! ---- (5/10)(2/10) = 10/100 = 1/10 ---- 0.5*0.2 = (1/2)(0.2) = 0.1 = 1/10 ---- 0.5*0.2 = 0.10 = 0.1 = 1/10 ================================== Cheers, Stan H. ===============
 Travel_Word_Problems/752825: A and b are athletes. A covers a distance of 1 km in 5 minutes and 50 seconds while b covers The same distance in 6 minutes and 4 seconds. If both them starts together and run at uniform speed by what approximate distance will A win a 5 km mini Marathon? 1 solutions Answer 458089 by stanbon(57967)   on 2013-05-27 10:56:10 (Show Source): You can put this solution on YOUR website!A and b are athletes. A covers a distance of 1 km in 5 minutes and 50 seconds while b covers the same distance in 6 minutes and 4 seconds. ----- A DATA: dist = 1 km ; time = 5 5/6 min = (35/6)/60 = 7/72 hr ; rate = d/t = 72/7 km/hr ------ B DATA: dist = 1 km ; time = 6 2/3 min = (20/3)/60=(1/9) hr ;rate = 9 km/hr ------------------------- If both of them starts together and run at uniform speed by what approximate distance will A win a 5 km mini Marathon? A-time = d/r = 5/(72/7) = 35/72 hr to run 5 km B-distance for 35/72 hr = (35/72)*9 km/hr = 4.375 km ========== A will win by 5-4.375 = 5/8 th of a kilometer ============== Cheers, Stan H. =======================
 Graphs/752826: -x^2=3x-21 solutions Answer 458083 by stanbon(57967)   on 2013-05-27 10:13:33 (Show Source): You can put this solution on YOUR website!-x^2=3x-2 ------ Add x^2 to both sides to get: x^2 + 3x -2 = 0 ------ Quadratic Formula: x = [-3 +-sqrt(9-4*1*-2)]/2 ---- x = [-3 +- sqrt(17)]/2 ============================ Cheers, Stan H. =========================
 Probability-and-statistics/752839: Please help me solve this problem. If a sample has 20 observations and a 95% confidence estimate for u is needed, the appropriate value of the t-multiple required is? I came up with 2.086.1 solutions Answer 458082 by stanbon(57967)   on 2013-05-27 10:09:31 (Show Source): You can put this solution on YOUR website!If a sample has 20 observations and a 95% confidence estimate for u is needed, the appropriate value, the t-multiplier is? --------------------- I get invT(0.025 with df = 19 ) is 2.0930 Cheers, Stan H.
 test/752842: What is a 3,4,5 triangle?1 solutions Answer 458081 by stanbon(57967)   on 2013-05-27 10:07:20 (Show Source): You can put this solution on YOUR website!What is a 3,4,5 triangle? ---- It is a right triangle where the sides are in a ratio of 3:4:5 =============== Cheers, Stan H. ===============
 Probability-and-statistics/752670: Use the following table which contains data from a study of three airlines which fly to Small Town, USA. Number of flights ON TIME | Number of LATE FLIGHTS Podunk Airlines | 33 | 6 Upstate Airlines | 43 | 5 Sargasso Airlines | 26 | 10 - One of the flights is randomly selected, find the probability that the flight sleeted arrived late. - One of the flights is randomly selected; find the probability that the flight selected is not a upstate airline flight. - One of the flights is randomly selected; find the probability that the flight selected arrived on time or is a Podunk airlines flight. - One of the flights is randomly selected, find the probability that the flight selected arrived late and is a Sargasso airlines flight. - One of the flights is randomly selected, find the probability that the flight selected arrived on time given that it was an upstate airlines flight. 1 solutions Answer 458026 by stanbon(57967)   on 2013-05-26 22:00:27 (Show Source): You can put this solution on YOUR website!Use the following table which contains data from a study of three airlines which fly to Small Town, USA. Number of flights ON TIME | Number of LATE FLIGHTS Podunk Airlines | 33 | 6 Upstate Airlines | 43 | 5 Sargasso Airlines | 26 | 10 - One of the flights is randomly selected, find the probability that the flight selected arrived late. Ans: (6+5+10)/123 = 21/123 --------------------------------- - One of the flights is randomly selected; find the probability that the flight selected is not an upstate airline flight. Ans: (33+26+6+10)/121 = 75/123 --------------------------------- - One of the flights is randomly selected; find the probability that the flight selected arrived on time or is a Podunk airlines flight. Ans: (102+39-33)/121 = 108/123 --------------------------------- - One of the flights is randomly selected, find the probability that the flight selected arrived late and is a Sargasso airlines flight. Ans: 10/123 --------------------------------- - One of the flights is randomly selected, find the probability that the flight selected arrived on time given that it was an upstate airlines flight. Ans 43/48 ================= Cheers, Stan H.
 Probability-and-statistics/752675: A pair of dice are rolled. What is the probability that the number rolled will be less then 71 solutions Answer 458023 by stanbon(57967)   on 2013-05-26 21:47:46 (Show Source): You can put this solution on YOUR website!A pair of dice are rolled. What is the probability that the number rolled will be less then 7 ---- # of ways to get 2: 1 # of ways to get 3: 2 # of ways to get 4: 3 # of ways to get 5: 4 # of ways to get 6: 5 ------ Total number of ways to get less than 7: 1+2+3+4+5=2*6+3 = 15 P(sum less than 7) = 15/36 =============================== Cheers, Stan H. ===============================
 Probability-and-statistics/752709: X/1 2 3 4 5 6 F/4 6 a 10 b 8 The mean of 50 observations for a grouped data is 3.72 the two frequencies are missing in the frequency table.find the missing frequencies.. 1 solutions Answer 458020 by stanbon(57967)   on 2013-05-26 21:38:21 (Show Source): You can put this solution on YOUR website!X/1 2 3 4 5 6 F/4 6 a 10 b 8 The mean of 50 observations for a grouped data is 3.72 the two frequencies are missing in the frequency table.find the missing frequencies.. ------ mean = [1*4+2*6+3a+4*10+5b+6*8]/50 [4+12+3a+40+5b+48]/50 = 3.72 ----- [3a+5b+104] = 186 3a+5b = 82 ================================ Sum of the frequencies = 50 a+b + 28 = 50 ================================== Using the 2 equations, solve for "a" and for "b": 3a+5b = 82 a + b = 22 -------- Modify for elimination: 3a + 5b = 82 3a + 3b = 66 ---- Subtract and solve for "b": 2b = 16 b = 8 ----- Solve for "a": a + 8 = 22 a = 14 ========================== Cheers, Stan H. ==========================
 Probability-and-statistics/752722: 1. Suppose that 20% of the M&M's are red a) what is the probability that in a sample of 20 randomly selected M&M's,exactly 5 are red? I assume that there are 100 M&M's because the question says 20% of the M&M's are red. I know that it is dependent because getting one red will affect the chances of getting another red, because there's no replacement. So the probability would be (20/100)(19/99)(18/98)(17/97)(16/96), but that's for the population and not for the sample. 1 solutions Answer 458012 by stanbon(57967)   on 2013-05-26 20:23:19 (Show Source): You can put this solution on YOUR website!Suppose that 20% of the M&M's are red a) what is the probability that in a sample of 20 randomly selected M&M's,exactly 5 are red? ----- Binomial Problem with n = 20 and p(red) = 0.20 ----- P(x = 5) = binompdf(20,0.2,5) = 0.1746 ========================================= Cheers, Stan H.
 Probability-and-statistics/752733: 1. At the St. Catharine's hospital, 30% of its patients seek care for a health-related problem. a) what is the probability that the first patient seeking heart-related care is the fifth patient seen? 1 solutions Answer 458011 by stanbon(57967)   on 2013-05-26 20:12:25 (Show Source): You can put this solution on YOUR website!At the St. Catharine's hospital, 30% of its patients seek care for a health-related problem. a) what is the probability that the first patient seeking heart-related care is the fifth patient seen? ------- Let "n" be not seeking Let "s" be seeking ----- P(nnnns) = (0.7)^4*0.3 = 0.0720 =================================== Cheers, Stan H. =================
 Probability-and-statistics/752740: A variable X has a mean of 185.5 and a standard deviation of 21.4. A random sample of size 67 is selected. Assuming X is normally distributed, what is the probability, to two decimal places, that the sample mean exceeds 200?1 solutions Answer 458007 by stanbon(57967)   on 2013-05-26 19:55:14 (Show Source): You can put this solution on YOUR website!A variable X has a mean of 185.5 and a standard deviation of 21.4. A random sample of size 67 is selected. Assuming X is normally distributed, what is the probability, to two decimal places, that the sample mean exceeds 200? ----------- z(200) = (200-185.5)/[21.4/sqrt(67)] = 5.5462 P(x-bar > 200) = P(z > 5.5462) = normalcdf(5.5462,100) = 0.0000000146 ======================================== Cheers, Stan H. ==============================
 Probability-and-statistics/752732: Can you please help assist me with problem I am having a hard time. 8) A marketing research company is estimating which of two soft drinks college students prefer. A random sample of n college students produced the following 90% confidence interval for the proportion of college students who prefer drink A: (. 406, . 586). Identify the point estimate for estimating the true proportion of college students who prefer that drink. A) .0 9 B) . 406 C) . 586 D) . 496 1 solutions Answer 458005 by stanbon(57967)   on 2013-05-26 19:49:56 (Show Source): You can put this solution on YOUR website!A marketing research company is estimating which of two soft drinks college students prefer. A random sample of n college students produced the following 90% confidence interval for the proportion of college students who prefer drink A: (. 406, . 586). Identify the point estimate for estimating the true proportion of college students who prefer that drink. ------ The width of every conficence interval is twice the margin of error. ---- P-hat is the average of the upper and lower bounds of the CI p-hat = (0.586+0.406)/2 = 0.496 =================================== Cheers, Stan H. ==================== A) .0 9 B) . 406 C) . 586 D) . 496
 Exponents-negative-and-fractional/752656: How do I solve an equation where the base is a fraction and the exponent is a negative fraction?1 solutions Answer 457936 by stanbon(57967)   on 2013-05-26 09:44:53 (Show Source): You can put this solution on YOUR website! How do I solve an equation where the base is a fraction and the exponent is a negative fraction? ----- Not exactly sure what you mean, but this might be an example: (27/64)^(-2/3) = ? ---- The 3 in the exponent means "take the cube root" The 2 in the exponent means "square" The negativ sign in the exponent means "invert" ------ Inverting you get: (64/27)^(2/3) Taking the cube root you get: = (4/3)^2 ----- Squaring you get: = 16/9 ======================= Cheers, Stan H.
 Functions/752638: If f(x)+{(x^3)-(3x^2)+ax-15} is divided by (x-3) and remainder is (-9), find 'a'.1 solutions Answer 457926 by stanbon(57967)   on 2013-05-26 08:44:01 (Show Source): You can put this solution on YOUR website!If f(x) = {(x^3)-(3x^2)+ax-15} is divided by (x-3) and remainder is (-9), find 'a'. ---------- f(3) = -9 ---- 3^3 -3*3^2 + 3a - 15 = -9 3a-15 = -9 3a = 6 a = 2 ============= Cheers, Stan H. =================
 logarithm/752634: Log(base2) x^2/3 - 5x^1/3 + 6= 0, 1 solutions Answer 457925 by stanbon(57967)   on 2013-05-26 08:40:01 (Show Source): You can put this solution on YOUR website!x^2/3 - 5x^1/3 + 6= 0 --------- That is a quadratic equation with variable x^(1/3) =========================== Factor: (x^(1/3)-6)(x^(1/3)+1) = 0 ----- x^(1/3) = 6 or x^(1/3) = -1 --- x = cbrt(6) or x = -1 ========================== Cheers, Stan H. ==================
 Finance/752637: 1000 euros is invested at 3% per annum interest, compounded monthly. Calculate the minimum number of months required for the value to exceed 1300 euros. I know that this is a geometric series and the multiplier is 1.03 per year but it is compounded monthly which makes it difficult.1 solutions Answer 457924 by stanbon(57967)   on 2013-05-26 08:37:05 (Show Source): You can put this solution on YOUR website!1000 euros is invested at 3% per annum interest, compounded monthly. Calculate the minimum number of months required for the value to exceed 1300 euros. ------------- A(t) = P(1+(r/n))^(nt) ----- 1300 = 1000(1+(0.03/12))^(12*t) ----- 1.3 = (1.0025)^(12t) ---- 12t*log(1.0025) = log(1.2) ---- 12t = log(1.2)/log(1.0025) 12t = 73.02 # of months is 73.02 ========================= t would be the number of years ========================= Cheers, Stan H. ================
 Trigonometry-basics/752628: Hello,i need help with the following problems:If 5 sin a=3 and 0degrees1 solutions Answer 457923 by stanbon(57967)   on 2013-05-26 08:31:34 (Show Source): You can put this solution on YOUR website!If 5 sin a=3 ---------------- sin(a) = 3/5 ---- a = sin^-1(3/5) = 36.87 degrees or 180-36.87 = 143.13 degrees =============================== Cheers, Stan H. =================
 Probability-and-statistics/752432: my question is..how do you determine the limits/boundaries of the given percentage lets say 65% of the data provided?1 solutions Answer 457922 by stanbon(57967)   on 2013-05-26 08:27:45 (Show Source): You can put this solution on YOUR website!my question is..how do you determine the limits/boundaries of the given percentage lets say 65% of the data provided? ---- You need to provide a little more context to your problem. Cheers, Stan H. ============
 Probability-and-statistics/752595: Hi there. I'm running 9 trials with 5 possible results -- A,B,C,D, and E -- on each trial. How would I calculate the odds of Either A or B showing up at least 6 times? I tried .4^6 * 1^3 = ~ .4% which seems too low. Total number of combinations is 5^9 -- 1953125. Total combinations with at least 6 A or B seems to be 2^6 * 5^3 -- 8000. Again leads to .4% Is it really that low or am I missing something?1 solutions Answer 457921 by stanbon(57967)   on 2013-05-26 08:25:15 (Show Source): You can put this solution on YOUR website!I'm running 9 trials with 5 possible results -- A,B,C,D, and E -- on each trial. How would I calculate the odds of Either A or B showing up at least 6 times? ----------------- Binomial Problem with n = 9 and p(A or B) = 2/5 ----- P(6<= x <=9) = 1 - P(0<= x <=5) = 1 - binomcdf(9,2/5,5) = 0.0994 ================================================= Cheers, Stan H. ====================
 Probability-and-statistics/752596: End of Section Problem 9.11A A random sample of size 20 is taken, resulting in a sample mean of 15.46 and a sample standard deviation of 4.58. Assume x is normally distributed and use this information and α = .05 to test the following hypotheses. Round your answer to 2 decimal places, the tolerance is +/-0.01. The value of the test statistic is ______________ and we ______________. 1 solutions Answer 457919 by stanbon(57967)   on 2013-05-26 08:20:29 (Show Source): You can put this solution on YOUR website!A random sample of size 20 is taken, resulting in a sample mean of 15.46 and a sample standard deviation of 4.58. Assume x is normally distributed and use this information and α = .05 to test the following hypotheses. Round your answer to 2 decimal places, the tolerance is +/-0.01. The value of the test statistic is ______________ and we ______________. --------------- What hypothesis??? Cheers, Stan H. ================
 Probability-and-statistics/752618: The probability that a randomly selected male is color blind is 0.042. Find the probability that in a randomly selected group of 50 males, at least 2 are color blind.1 solutions Answer 457918 by stanbon(57967)   on 2013-05-26 08:18:39 (Show Source): You can put this solution on YOUR website!The probability that a randomly selected male is color blind is 0.042. Find the probability that in a randomly selected group of 50 males, at least 2 are color blind. ----- Binomial Problem with n = 50 and p(cb) = 0.042 ------ P(2<= x <=50) = 1 - P(0<= x <=1) = 1 - binomcdf(50,0.042,1) = 0.6265 ========================= Cheers, Stan H. =============