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Recent problems solved by 'stanbon'
stanbon answered: 57288 problems
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56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179 , 57180..57209 , 57210..57239 , 57240..57269 , 57270..57299, >>NextProbability-and-statistics/75610: Thirty percent of the population in a southwestern community are Spanish-speaking Americans. A Spanish-speaking person is accused of killing a non-Spanish-speaking American. Of the first 12 potential jurors, only 2 are Spanish-speaking Americans, and 10 are not. The defendant’s lawyer challenges the jury selection, claiming bias against her client. The government lawyer disagrees, saying that the probability of this particular jury composition is common. What do you think?
Thank You
1 solutions
Answer 54280 by stanbon(57361)   on 2007-03-23 16:10:32 (Show Source):
You can put this solution on YOUR website!Thirty percent of the population in a southwestern community are Spanish-speaking Americans. A Spanish-speaking person is accused of killing a non-Spanish-speaking American. Of the first 12 potential jurors, only 2 are Spanish-speaking Americans, and 10 are not. The defendant’s lawyer challenges the jury selection, claiming bias against her client. The government lawyer disagrees, saying that the probability of this particular jury composition is common. What do you think?
---------------
P(person speaks Spanish)= 0.30
P(2 speak Spanish of 12) = 12C2(0.3)^2*(0.7)^10 = 66*0.09*0282475...
=0.167790....
It can happen about 17% of the time.
=======================
Cheers,
Stan H>
|
Polynomials-and-rational-expressions/75611: while using ac test determine if the following trinomial can be factored. if so how do you find the value of m and n
3x^2+11x-4
1 solutions
Answer 54273 by stanbon(57361) on 2007-03-23 14:57:48 (Show Source):
You can put this solution on YOUR website!while using ac test determine if the following trinomial can be factored. if so how do you find the value of m and n
3x^2+11x-4
a=3 ; b=11; c=-4
ac=-12
b=11
--------------
Find two numbers whose product is -12 and whose sum is 11
The numbers are -12 and 1.
Rewrite the problem as:
3x^2-12x+x-4
Factor the 1st two and then the last two terms separately to get:
=3x(x-4)+(x-4)
Factor again:
=(x-4)(3x+1)
==============
Cheers,
Stan H.
|
Radicals/75612: This question is from textbook Beginning Algebra
Please help!!! I am having an extremely difficult time solving these square root problems. Whatever assistance anyone can provide will be greatly appreciated. Thank you in advance.
PG. 530 Combine, if possible.
(6.) √5 - √6 + 3√5 - 2√6
(8.) √7 - √63
PG. 535 Multiply. Be sure to simplify any radicals in your answer.
(26.) (3√5 + √3) (√5 + √3)
(36.) (3√2 + 5)^2
PG. 542 Simplify. Be sure to rationalize all denominators.
(6.) √5 / √80
(14.) 6 / √17
1 solutions
Answer 54272 by stanbon(57361) on 2007-03-23 14:53:10 (Show Source):
You can put this solution on YOUR website!Combine, if possible.
(6.) √5 - √6 + 3√5 - 2√6
=4sqrt5 - 3sqrt6
-----------
(8.) √7 - √63
=sqrt7 - sqrt(9*7)
=sqrt7 - 3sqrt7
=-2sqrt7
--------------
PG. 535 Multiply. Be sure to simplify any radicals in your answer.
(26.) (3√5 + √3) (√5 + √3)
=3*5 +3sqrt15+sqrt15+3
=18 +4sqrt15
---------------
(36.) (3√2 + 5)^2
=(3sqrt2 + 5)(3sqrt2 + 5)
=9*2 +15sqrt2 + 15sqrt2 + 25
=43+30sqrt2
-----------------
PG. 542 Simplify. Be sure to rationalize all denominators.
(6.) √5 / √80
= sqrt5/sqrt(16*5)
=sqrt5 / 4(sqrt5)
=1/4
-------------------
(14.) 6 / √17
Multiply numerator and denominator by sqrt17 to get:
=(6sqrt17)/17
=(6/17)sqrt17
==================
Cheers,
Stan H.
|
Probability-and-statistics/75597: A certain 18-hole golf course has par-3, par-4, and par-5 holes, and there are twice as many par-4 as par-5 holes. How many holes of each type are there if a golfer has a par on every hole for a score of 70?
1 solutions
Answer 54263 by stanbon(57361) on 2007-03-23 13:10:28 (Show Source):
You can put this solution on YOUR website!A certain 18-hole golf course has par-3, par-4, and par-5 holes, and there are twice as many par-4 as par-5 holes. How many holes of each type are there if a golfer has a par on every hole for a score of 70?
---------------
Let number of par-5 holes be "x"; par-strokes for these is 5x
Number of par-4 holes is "2x"; par-strokes for these is 4(2x)=8x
Number of par-3 holes is "18-x-2x"="18-3x"; par-strokes for these is 3(18-3x)
=54-9x
--------------
EQUATION:
5x+8x+54-9x=70
4x=16
x=4
# of par-5 holes is x=4
# of par-4 holes is 2x=8
# of par-3 holes is 18-3x=6
================
Cheers,
Stan H.
|
Probability-and-statistics/75072: 1 The hospital records show that the mean weight of newly born baby is 7 lbs, with the standard deviation of 0.75 lbs. A researcher takes a sample of 55 newly born babies and found to have a mean weight of 6.73 lbs. Test the claim at 0.05 level of significance.(use z-test)
2 To compare freshmen’s knowledge of mathematics in two departments of the College of Computer of the Manuel S. Enverga University Foundation, a certain professor in business mathematics got a sample of economics and accountancy students and gave them special examination. A sample of 25 economics major students had a mean score of 85.85 with standard deviation of 7.5. A sample of 29 accounting major students had a mean score of 90.5 with a standard deviation of 10.3. Is there a significant difference between the two sample means? Use 0.01 level of significance.(use t-test)
3 In the contest of Search for Most Outstanding Teacher, 3 candidates are teaching Mathematics, 2 are teaching English, 2 are teaching Science and 1 teaching Filipino. What is the probability that the winner is teaching:
a.Mathematics
b.Science
c.Filipino
d.Any subject except English
e.Any subject except Math
4) If the probabilities are 0.40, 0.55 and 0.3 that student will get a failing grade either in Accountancy or Marketing, or in both, what is the probability that he fail at least one of these subjects?
1 solutions
Answer 54256 by stanbon(57361) on 2007-03-23 11:48:10 (Show Source):
You can put this solution on YOUR website!1 The hospital records show that the mean weight of newly born baby is 7 lbs, with the standard deviation of 0.75 lbs. A researcher takes a sample of 55 newly born babies and found to have a mean weight of 6.73 lbs. Test the claim at 0.05 level of significance.(use z-test)
-------
Ho: u=7 lbs
Ha: u is not equal 7 lbs
------------
z(6.73)=(6.73-7)/0.75/sqrt55=-2.6698
The test is two tail so the p value
associated with z=-2.6698 is 0.00379*2=0.007589
The critical value of alpha = +/-1.96
Conclusion:
Reject Ho since p value<5%
Mean weight is not 7 lbs.
========
Cheers,
Stan H.
======================================
2 To compare freshmen’s knowledge of mathematics in two departments of the College of Computer of the Manuel S. Enverga University Foundation, a certain professor in business mathematics got a sample of economics and accountancy students and gave them special examination. A sample of 25 economics major students had a mean score of 85.85 with standard deviation of 7.5. A sample of 29 accounting major students had a mean score of 90.5 with a standard deviation of 10.3. Is there a significant difference between the two sample means? Use 0.01 level of significance.(use t-test)
---------
Ho: mu(econ) = mu(account)
Ha: mu(econ) not equal to mu(account)
z(85.85-90.5)=z(-4.65)=(-4.65-0)/2.4307 = -1.913
p value = 0.0557
But alpha = 1%
Conclusion: Reject Ho. because p value < alpha.
The mean values are not the same.
===================
3 In the contest of Search for Most Outstanding Teacher, 3 candidates are teaching Mathematics, 2 are teaching English, 2 are teaching Science and 1 teaching Filipino. What is the probability that the winner is teaching:
a.P(Mathematics)=3/8
b.P(Science)=2/8
c.P(Filipino)=1/8
d.P(Any subject except English)= 1-(2/8)=6/8
e.P(Any subject except Math)= 1-3/8 = 5/8
4) If the probabilities are 0.40, 0.55 and 0.3 that student will get a failing grade either in Accountancy or Marketing, or in both, what is the probability that he fail at least one of these subjects?
P(fail at least one)= 1-P(fail none)
=1-[P(fail account)+P(fail marketing)-P(fail both)]
=1-[0.40+0.55-0.30]
=1-[0.65]
=0.35
==========
Cheers,
Stan H.
|
Graphs/75595: Solve the system by graphing.
4x + 4y = 4
x + y = 1
1 solutions
Answer 54252 by stanbon(57361) on 2007-03-23 11:11:59 (Show Source):
You can put this solution on YOUR website!The two equation are the same; one is 4 times the other.
They are dependent.
The solution is y=-x+1
If you were to graph the two you would end up with one line:
Cheers,
Stan H.
|
Probability-and-statistics/75159: There are 75 people present to vote new members into their organization. There are 12 candidates and only 6 candidates can be voted in to become members of the organization. In order to become part of the organization, you must receive 75% of the vote amongst the 75 people that are voting. These 75 people can vote for up to 6 candidates during each voting session. Is it possible for all 6 candidates to get 75% of the vote if voters are selecting anywhere between 1 to 6 candidates on each ballot? If so, how many times must the group vote in order to select 6 people to meet the 75% requirement?
1 solutions
Answer 54251 by stanbon(57361) on 2007-03-23 11:09:13 (Show Source):
You can put this solution on YOUR website!There are 75 people present to vote new members into their organization. There are 12 candidates and only 6 candidates can be voted in to become members of the organization. In order to become part of the organization, you must receive 75% of the vote amongst the 75 people that are voting. These 75 people can vote for up to 6 candidates during each voting session.
----------------
Is it possible for all 6 candidates to get 75% of the vote if voters are selecting anywhere between 1 to 6 candidates on each ballot?
6 votes each by 75 persons = 450 votes
75%(450)=337.5 votes
337.5/6 = 56.25
75%(75)=56.25
So it is possible for all 6 candidates to get 75% of the vote.
-----------------------
If so, how many times must the group vote in order to select 6 people to meet the 75% requirement?
N/A
--------------
Cheers,
Stan H.
|
Quadratic-relations-and-conic-sections/75528: I am graphing parabolas and I have a quick question...
How would I graph x=(1/24)(y^2)?
I know that the vertex is (0,0), the focus is (6,0) and the directrix is x=-6
Thank you
1 solutions
Answer 54245 by stanbon(57361) on 2007-03-23 09:31:25 (Show Source):
You can put this solution on YOUR website!I am graphing parabolas and I have a quick question...
How would I graph x=(1/24)(y^2)?
I know that the vertex is (0,0), the focus is (6,0) and the directrix is x=-6
---------------
That is really all you need to know.
Plot the vertex and focus point. Draw the directrix.
The parabola opens to the right
If you want more points give a value for y and find x:
If y=+/-1, x=1/24
If y=+/-10 x is approximately 4
etc.
Cheers,
Stan H.
|
Exponential-and-logarithmic-functions/75554: SMOKING AND COLLEGE EDUCATION
Q1. The tobacco industry closely monitors all surveys that involve smoking. One survey showed that among 785 randomly selected sunjects who completed four years of college, 18.3% smoke(based on data from American Medical Association).
a. Construct the 98% confidence interval for the true percentage of smokers among all people who completed four years of college.
b. Based on the result from part (a),does the smoking rate for those with four year of college appear to be substantially different than the 27% rate for the general population?
1 solutions
Answer 54244 by stanbon(57361) on 2007-03-23 09:26:33 (Show Source):
You can put this solution on YOUR website!One survey showed that among 785 randomly selected sunjects who completed four years of college, 18.3% smoke(based on data from American Medical Association).
a. Construct the 98% confidence interval for the true percentage of smokers among all people who completed four years of college.
--------
E= z*sqrt(pq/n)
You don't have "p" so use p-hat=0.183
E= 2.326sqrt(0.183*0.817/785)
E= 0.032
Then CI is: (0.183-0.032,0.183+0.032) or (0.151,0.215)
==========================
b. Based on the result from part (a),does the smoking rate for those with four year of college appear to be substantially different than the 27% rate for the general population?
Yes, 27% is significantly outside the range of the 98% confidence interval
for the smoking percent of four year college students.
===========
Cheers,
Stan H.
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Probability-and-statistics/75557: FINDING SAMPLE SIZE.
Q1. margin of error:$125, confidence level:95%,standard deviation=$500
1 solutions
Answer 54241 by stanbon(57361) on 2007-03-23 09:04:09 (Show Source):
You can put this solution on YOUR website!FINDING SAMPLE SIZE.
Q1. margin of error:$125, confidence level:95%,standard deviation=$500
-----------
E=z*(sigma/sqrt(n))
sqrt(n) = z*(sigma)/E
sqrt(n) = 1.96(500)/125
sqrt(n) = 7.84
n=61 (rounded to whole number)
========
Cheers,
Stan H.
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logarithm/75575: Please explain how the graph of y=log base 2 of x/7 can be obtained from the graph of y=log base 2 of x. Thank you.
1 solutions
Answer 54240 by stanbon(57361) on 2007-03-23 08:58:00 (Show Source):
You can put this solution on YOUR website!Please explain how the graph of y=log base 2 of x/7 can be obtained from the graph of y=log base 2 of x.
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log(base 2)(x/7)= log(base 2)x - log(base 2)7
So if you have the graph of log(base 2)x
you can obtain the graph of log(base 2)(x/7) by lowering the graph log(base 2)7,
that is by subtracting that amount from each of the y values.
============
Cheers,
Stan H.
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logarithm/75577: Between what two integers does the solution of log base 7 of x= 4.98 lie? Please explain. Thank you.
1 solutions
Answer 54239 by stanbon(57361) on 2007-03-23 08:53:08 (Show Source):
You can put this solution on YOUR website!Between what two integers does the solution of log base 7 of x= 4.98 lie?
log(base 7)x=4.98
x=7^4.98
x=16165.4664
x lies between 16165 and 16166
Cheers,
Stan H.
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logarithm/75578: Please explain why log base a of 5 = 5. Thank you.
1 solutions
Answer 54238 by stanbon(57361) on 2007-03-23 08:49:55 (Show Source):
You can put this solution on YOUR website!Please explain why log base a of 5 = 5.
------------
log(base a) of 5 could be any number.
Your problem says it is "5"
-------
Keep in mind that "log" means "exponent".
So you have a^5=5 as the exponential form of log(base a)5=5.
Take the 5th root of both sides to find "a".
a=5^(1/5)=1.3797...
=========
Hope this helps you understand logs.
Cheers,
Stan H.
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Linear-equations/75559: This question is from textbook
Find four solutions for the following and write the solutions as ordered pairs:
y=1/3x
1 solutions
Answer 54204 by stanbon(57361) on 2007-03-22 22:54:35 (Show Source):
You can put this solution on YOUR website!Find four solutions for the following and write the solutions as ordered pairs:
y=1/3x
---------
(0,0)
(3,1)
(6,2)
(9,3)
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Cheers,
Stan H.
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Probability-and-statistics/75537: In a recent study 90 percent of the homes in the United States were found to have color TVs. In a sample of nine homes, what is the probability that:
a. All nine have color TVs?
b. Less than five have color TVs?
c. More than five have color TVs?
d. At least seven homes have color TVs?
Thank You
1 solutions
Answer 54201 by stanbon(57361) on 2007-03-22 22:32:39 (Show Source):
You can put this solution on YOUR website!In a recent study 90 percent of the homes in the United States were found to have color TVs. In a sample of nine homes, what is the probability that:
p(have color TV)=0.9
--------------------------
a. All nine have color TVs?
0.9^9=0.3874
-----------------------
b. Less than five have color TVs?
binomcdf(9,0.9,4)=0.0008909
----------------------
c. More than five have color TVs?
1-binomcdf(9,0.9,5)=0.99166
--------------------
d. At least seven homes have color TVs?
1-binomcdf(9.0,9,6)=0.94703
------------
Cheers,
Stan H.
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Probability-and-statistics/75539: The Director of Emergency Medicine at Big Mountain Medical Services is studying patient waiting time. Waiting time is defined as the time from when a patient enters the facility until seen by a physician. The study indicates the waiting time follows a normal distribution with a mean of 22 minutes and a standard deviation of 8 minutes.
a. What fraction of the patients is seen in between 15 and 22 minutes?
b. What fraction is seen in less than 15 minutes?
c. What fraction is seen in more than 15 minutes but less than 32 minutes?
d. What fraction is seen in more than 25 minutes but less than 32 minutes?
e. Five percent of the patients are seen in how many minutes or less? That is, how quickly are 5 percent of the patients seen?
Thank You
1 solutions
Answer 54192 by stanbon(57361) on 2007-03-22 21:36:52 (Show Source):
You can put this solution on YOUR website!The Director of Emergency Medicine at Big Mountain Medical Services is studying patient waiting time. Waiting time is defined as the time from when a patient enters the facility until seen by a physician. The study indicates the waiting time follows a normal distribution with a mean of 22 minutes and a standard deviation of 8 minutes.
a. What fraction of the patients is seen in between 15 and 22 minutes?
P(15<=x<=18)= normalcdf(15,18,22,8)=0.1178
Using TI calculator
-------------
b. What fraction is seen in less than 15 minutes?
= normalcdf(0,15,22,8)
=0.1878
------------------
c. What fraction is seen in more than 15 minutes but less than 32 minutes?
= normalcdf(15,32,22,8)= "can you get this?"
-----------------
d. What fraction is seen in more than 25 minutes but less than 32 minutes?
same procedure
-----------------
e. Five percent of the patients are seen in how many minutes or less? That is, how quickly are 5 percent of the patients seen?
InvNorm(0.05,22,8) = 8.84
Rounding down to whole patients you get 8 patients
=============
Cheers,
Stan H.
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Polynomials-and-rational-expressions/75538: could you help me factor completely? i tried where am i wrong?
x^2+2x-80
x^2+160-3x-80
(x^2+160x)-(3x+80)
x^2(x+160)-3(x+80)
1 solutions
Answer 54180 by stanbon(57361) on 2007-03-22 21:17:33 (Show Source):
You can put this solution on YOUR website!x^2+2x-80
Think of two numbers whose product is -80 and whose sum is +2.
They are +10 and -8
Rewrite the problem as:
x^2+10x-8x-80
Factor the 1st two terms and the last two terms separately:
=x(x+10)-8(x+10)
=(x+10)(x-8)
------------------
This is called the AC Method of factoring.
Cheers,
Stan H.
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Probability-and-statistics/75536: Help me please....
A manufacturer of window frames knows from long experience that 5 percent of the production will have some type of minor defect that will require an adjustment. What is the probability that in a sample of 20 window frames:
a. None will need adjustment.
b. At least one will need adjustment.
c. More than two will need adjustment.
Thank You!
1 solutions
Answer 54177 by stanbon(57361) on 2007-03-22 21:12:25 (Show Source):
You can put this solution on YOUR website!A manufacturer of window frames knows from long experience that 5 percent of the production will have some type of minor defect that will require an adjustment. What is the probability that in a sample of 20 window frames:
a. None will need adjustment.
P(none faulty) = 20C0(0.05)^0(0.95)^20 = 1*1*0.3585=0.3585
----------------
b. At least one will need adjustment.
= 1 - P (none faulty)
= 1 - 0.3585
= 0.6415
--------------
c. More than two will need adjustment.
= 1 - P(0<=x<=2)
= 1- binomcdf(20,0.05,2)
= 0.07548
==============
Cheers,
Stan H.
|
Probability-and-statistics/75535: This question is from textbook Precalculus with limits
Four letters and envelopes are addressed to four different people. If the letters are randomly inserted into the envelopes, what is the probability that(a) exactly one is inserted and (b) at least one is inserted in the correct envelope
1 solutions
Answer 54173 by stanbon(57361) on 2007-03-22 21:04:20 (Show Source):
You can put this solution on YOUR website!Four letters and envelopes are addressed to four different people. If the letters are randomly inserted into the envelopes, what is the probability that(a) exactly one is inserted in the correct envelope:
P(success)=1/4
P(one correct of four)= 4C1 (1/4)^1(3/4)^3 = 4(27/256)=0.421875
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(b) at least one is inserted in the correct envelope
P(at least one) = 1 - P(none correct)
= 1 - 4C0(1/4)^0(3/4)^4
= 1 - 1*1*81/256
= 1 - 0.316
= 0.6835
--------------
Cheers,
stan H.
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Probability-and-statistics/75493: Q1. if Z is a standard normal variable, find the probability. P(-0.73
Q2. express the confidence interval in the form of +/-E, -0.052
Q3. find the critical value Z(alpha/2) that corresponds to a degree of confidence of 91%
Q4. find the minimum sample size you should use to assure that your estimate of P will be within the required margin of error around the population P. Margin of error:0.04 confidence level:94% P and q unknown.
1 solutions
Answer 54169 by stanbon(57361) on 2007-03-22 20:56:24 (Show Source):
You can put this solution on YOUR website!Q1. if Z is a standard normal variable, find the probability. P(-0.73
Comment: Something must be missing in this posting.
-------------------------
Q2. express the confidence interval in the form of +/-E, -0.052
Comment: Something is missing here.
--------------
Q3. find the critical value Z(alpha/2) that corresponds to a degree of confidence of 91%
Half of 91% is 45.5%
The z-score that corresponds to 4.5% and to 95.5% is -1.6954 and +1.6954
-------------
Q4. find the minimum sample size you should use to assure that your estimate of P will be within the required margin of error around the population P. Margin of error:0.04 confidence level:94% P and q unknown.
E=z*sqrt(pq/n)
sqrt(n)=[z*sqrt(pq)]/E
sqrt(n) = [1.88079 sqrt(.5*.5)]/0.04
sqrt(n) = [0.9403968049]/0.04
sqrt(n) = 23.5099
Square both sides to get:
n=552 (rounded down to the whole number)
============
Cheers,
Stan H.
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Probability-and-statistics/75466: Q1. A final exam in math 160 has a mean of 73 with standard deviation 7.8. If 24 students are randomly selected, find the probability that the mean of their test score is greater than 78.
Q2.For the binomial distribution with the given values for n and p, state whether or not it is suitable to use the normal distribution as an approximation. n = 16 and p = 0.5
Q3. This is the same as question 1, but find the probability that the mean of their test scores is LESS than 70
Q4. Estimate the indicated probability by using the normal distribution as an approximation to the binomial distribution. With n = 20 and p = 0.06, estimate p (fewer than 8).
1 solutions
Answer 54160 by stanbon(57361) on 2007-03-22 17:39:53 (Show Source):
You can put this solution on YOUR website!Q1. A final exam in math 160 has a mean of 73 with standard deviation 7.8. If 24 students are randomly selected, find the probability that the mean of their test score is greater than 78.
-------------------
z(78)=(78-73)/7.8/sqrt(24)=3.14
P(z>3.14)=0.0008448059....
-------------
Q2.For the binomial distribution with the given values for n and p, state whether or not it is suitable to use the normal distribution as an approximation. n = 16 and p = 0.5
The answer to this depends on the conditions listed in your text for using
a normal approximation on a binomial problem.
--------------------------
Q3. This is the same as question 1, but find the probability that the mean of their test scores is LESS than 70
z(70)=(70-73)/7.8/sqrt(24)=-1.88442228...
P(z<-1.88442228...)=0.02975...
---------------
Q4. Estimate the indicated probability by using the normal distribution as an approximation to the binomial distribution. With n = 20 and p = 0.06, estimate
P(fewer than 8).
Z(8)=(8-20*0.06)/sqrt(20*0.06*0.94)=6.8/1.06207=6.40257
P(z<6.40257)=0.9999
----------
Cheers,
Stan H.
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Probability-and-statistics/75427: Q. M&M candies:Are 10% blue?
According to a consumer affairs representative from Mars(the candy company, not the planet), 10% of all M&M plain candies are blue. Data set 19 in Appendix B shows that among 100 M&Ms chosen, 5 are blue. Estimate the probability of randomly selecting 100 M&Ms and getting 5 or fewer that are blue. Assume that the company's 10% blue rate is correct. Based on the result, is it unusual to get 5 or fewer blue M&Ms when 100 are randomly selected?
1 solutions
Answer 54130 by stanbon(57361) on 2007-03-22 09:49:20 (Show Source):
You can put this solution on YOUR website!According to a consumer affairs representative from Mars(the candy company, not the planet), 10% of all M&M plain candies are blue. Data set 19 in Appendix B shows that among 100 M&Ms chosen, 5 are blue. Estimate the probability of randomly selecting 100 M&Ms and getting 5 or fewer that are blue. Assume that the company's 10% blue rate is correct.
--------
P(X<=5)=binomcdf(100,0.10,5)= 0.057577...
I used a TI calculator.
------------
Based on the result, is it unusual to get 5 or fewer blue M&Ms when 100 are randomly selected?
Not too unusual; Seems to happen about 6% of the time.
That answer is a judgement call; not based on z-scores,
standard deviations, etc.
Cheers,
Stan H.
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Probability-and-statistics/75220: 1. In the contest of Serach for Most Outstanding Teacher, 3 candidates are teaching Mathematics, 2 are teaching English, 2 are teaching Science and 1 is teaching in Filipino. What is the probability that the winner is teaching:
a. Mathematibs
b. Science
c. Filipino
d. Any subject except English
e. any subject except math
2. If the probabilities are 0.40, 0.55 and 0.3 that student will get a failing grade either in Accountancy or Marketing, or in both, what is the probability that he fail at least one of these subjects?
1 solutions
Answer 54096 by stanbon(57361) on 2007-03-21 23:08:11 (Show Source):
You can put this solution on YOUR website!1. In the contest of Serach for Most Outstanding Teacher, 3 candidates are teaching Mathematics, 2 are teaching English, 2 are teaching Science and 1 is teaching in Filipino. What is the probability that the winner is teaching:
a. P(Mathematics)= 3/8
b. P(Science)=2/8
c. P(Filipino)=1/8
d. P(Any subject except English)=1-(2/8)=6/8
e. P(any subject except math)=1-(3/8)=5/8
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2. If the probabilities are 0.40, 0.55 and 0.3 that student will get a failing grade either in Accountancy or Marketing, or in both, what is the probability that he fail at least one of these subjects?
P(fail at least one)=?
P(fail Account OR Market)= P(fail Acc)+P(fail Mar)-P(fail both)=0.4+0.55-0.3=0.65
P(fail at least one)=0.65
============
Cheers,
Stan H.
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