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# Recent problems solved by 'stanbon'

Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 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 Sequences-and-series/80963: This question is from textbook Mary's annual salaries form an aritnmetic sequence. She earned \$17,400 during her third year and \$21,000 during her sixth year. a. Find her starting salary. b. Find her annual salary increases.1 solutions Answer 58095 by stanbon(57357)   on 2007-05-06 22:52:58 (Show Source): You can put this solution on YOUR website!Mary's annual salaries form an aritnmetic sequence. She earned \$17,400 during her third year and \$21,000 during her sixth year. a. Find her starting salary. Since it is an aritmetic sequence the nth term = 1st term + (n-1)d a(n)=a(1)+(n-2)d The 3rd term is a(3)=a(1)+2d=17,400 The 6th term is a(6)=a(1)+5d=21000 You need to find a(1): Subtract the 3rd term form from the 6th term form to get: 3d=3600 d=1200 ---- Substitute in the form a(1)+2d=17400 to find a(1) a(1)+2(1200)=17400 a(1) = \$15,000 (This is Mary's salary the 1st year.) ----------------- b. Find her annual salary increases. "d" tells you the annual salary increase. d= \$1,200 ================= Cheers, Stan H.
 Circles/80986: if the radius of circle A is twice the length of the radius of Circle B, does that mean that circle A has twice the area of circle B? Explain whiy or why not.1 solutions Answer 58094 by stanbon(57357)   on 2007-05-06 22:36:20 (Show Source): You can put this solution on YOUR website!if the radius of circle A is twice the length of the radius of Circle B, does that mean that circle A has twice the area of circle B? Explain whiy or why not. ------------- Let the 1st circle have radius = x ; its area is (pi)x^2 Then the 2nd circle will have radius = 2x ; its are will be (pi)(2x)^2 =(pi)4x^2 = 4[(pi)x^2] ---------- Conclusion: The 2nd circle will have 4 times the area of the 1st circle. ========= Cheers, Stan H.
 Percentage-and-ratio-word-problems/80989: Please help! When the ratio of a number and 4 is decreased by 2 the result is 6. Find the number. I would appreciate any help you can give me. makennedy01 1 solutions Answer 58093 by stanbon(57357)   on 2007-05-06 22:30:38 (Show Source): You can put this solution on YOUR website!When the ratio of a number and 4 is decreased by 2 the result is 6. Find the number. ----------- Let the "number" be x. EQUATION: (x/4)-2 = 6 x/4 = 8 x=32 --------------- Cheers, Stan H.
 logarithm/80987: for what values of x is : 2 ln (x-1) > e^(x-4) - 2 1 solutions Answer 58092 by stanbon(57357)   on 2007-05-06 22:25:33 (Show Source): You can put this solution on YOUR website!2 ln (x-1) > e^(x-4) - 2 This is one equation you cannot solve analytically. Graph the left side and the right side separately and determine over what x-interval the left side is greater than the right side: I get 1.3815 < x < 5.622 Comment: This site graphs the left side properly but does not do a good job with the right side. Hopefully you have a graphing calculator. ========== Cheers, Stan H.
 Radicals/80985: Please help!! I have tried working this problem out but don't know if I did it right. This is a homework assignment that is due Tuesday. Please bare with me because I am not certain how to type this one. Problem: Multiply (Show all work): (sqrt6 + 3*sqrt2)(4*sqrt6 - 5*sqrt2) Here is what I did: (sqrt6 + 3*sqrt2)(4*sqrt6 - 5*sqrt2) = (sqrt6*4*sqrt6) - (5*sqrt2*sqrt6) + (3*sqrt2*4*sqrt6)- (5*sqrt2*3*sqrt2) = (4*sqrt6*sqrt6) - (5*sqrt2*sqrt6) + (12*sqrt2*sqrt6) - (15*sqrt2*sqrt2) =(4*sqrt36) - (5*sqrt12) + (12*sqrt12) - (15*sqrt4) = (4*6) - (7*sqrt12) - (15*2) = 24 - (7*sqrt12) - 30 = -6 - (7*sqrt12) Any help would be appreciated very much! Thanks!!!1 solutions Answer 58090 by stanbon(57357)   on 2007-05-06 22:13:18 (Show Source): You can put this solution on YOUR website!(sqrt6 + 3*sqrt2)(4*sqrt6 - 5*sqrt2) --------------------- = 4*6 -5sqrt12 + 12sqrt12 - 15*2 = -6 + 7sqrt12 = -6 +14sqrt3 ============== Cheers, Stan H.
 Quadratic_Equations/80984: how do you find the axis of symmetry and the vertex?1 solutions Answer 58089 by stanbon(57357)   on 2007-05-06 22:03:36 (Show Source): You can put this solution on YOUR website!Post a couple of the problems that you need to do. Cheers, Stan H.
 Probability-and-statistics/80944: from a group of 8 boys two students are selected to shake hands. how many hand shakes are possible?1 solutions Answer 58088 by stanbon(57357)   on 2007-05-06 21:59:50 (Show Source): You can put this solution on YOUR website!It takes two to shake hands. Answer 8C2 = 8*7/1*2 = 28 ============= Cheers, Stan H.
 Probability-and-statistics/80902: given: 2,3,4,5,6,8 how many 3-digit numerals are possible selecting three at a time?1 solutions Answer 58073 by stanbon(57357)   on 2007-05-06 18:07:18 (Show Source): You can put this solution on YOUR website!given: 2,3,4,5,6,8 how many 3-digit numerals are possible selecting three at a time? ---------- 6 ways to pick the hundreds digit 6 ways to pick the tens digit 6 ways to pick the units digit -------------- 6^3 = 216 3-digit numerals are possible. ==================== Cheers, Stan H.
 Probability-and-statistics/80914: This question is from textbook A survey of mathematics with applications An artist entered two paintings(lighthouse, and Old catherdral) in the show. He feels that the probablities are 0.15, 0.18, 0.11, respectively, that he will sell the lighthouse, the old catherdral, or both. What is the probability that he will sell either of the two paintings? 1 solutions Answer 58072 by stanbon(57357)   on 2007-05-06 18:02:25 (Show Source): You can put this solution on YOUR website!An artist entered two paintings(lighthouse, and Old catherdral) in the show. He feels that the probablities are 0.15, 0.18, 0.11, respectively, that he will sell the lighthouse, the old catherdral, or both. What is the probability that he will sell either of the two paintings? ----------- Formula: P(A or B) = P(A) + P(B) - P(A and B) ----------------- Your Problem: P(lighthouse Or cathedral) = 0.15 + 0.18 - 0.11) = 0.22 Cheers, Stan H.
 Problems-with-consecutive-odd-even-integers/80894: a landscape worker can lay sod in a yard in 6 hours. a helper would take 8 hours to do the same job. how long would sodding the yard take if both people worked together?1 solutions Answer 58033 by stanbon(57357)   on 2007-05-06 11:37:21 (Show Source): You can put this solution on YOUR website!a landscape worker can lay sod in a yard in 6 hours. a helper would take 8 hours to do the same job. how long would sodding the yard take if both people worked together? ---------- Worker DATA: Time = 6 hr/job ; Rate = 1/6 job/hr ----------- helper DATA: Time = 8 hr/job ; Rate = 1/8 job/hr --------------- Together DATA: Time = x hr/job ; Rate = 1/x job/hr ---------------------------- EQUATION: worker rate + helper rate = together rate 1/6 + 1/8 = 1/x 4x + 3x = 24 7x=24 x=24/7 hrs x= 3 3/7 hr (3/7)60min = 25.7 minutes x= 3 hr 25.7 min ===================== Cheers, Stan H.
 Quadratic_Equations/80881: Factor 5xSQUARED-13x+6 could u show me how u got this please1 solutions Answer 58032 by stanbon(57357)   on 2007-05-06 11:32:01 (Show Source): You can put this solution on YOUR website!5xSQUARED-13x+6 ------- Think of two number whose product is 5*6=30 and whose sum is -13. The numbers are -3 and -10 Replace -13x with the terms -3x and -10x to get: 5x^2-3x-10x+6=0 Factor the 1st two and the last two terms separately to get: x(5x-3)-2(5x-3)=0 (5x-3)(x-2)=0 x=3/5 or x=2 ============ Cheers, Stan H.
 Miscellaneous_Word_Problems/80890: Hi, this isn't from a book, but it is for a resume, so any help would be appreciated! If a company starts out at \$250,000, and 4 1/2 years later it is making \$850,000, what is the growth of the company? Thanks a bunch!1 solutions Answer 58031 by stanbon(57357)   on 2007-05-06 11:25:18 (Show Source): You can put this solution on YOUR website!If a company starts out at \$250,000, and 4 1/2 years later it is making \$850,000, what is the growth of the company? -------- (85000-250,000)/(4.5) = \$13,333.33/yr. =========== Cheers, Stan H.
 Quadratic_Equations/80891: This question is from textbook CALCULUS For the general cubic polynomial f(x)= ax^3 + bx^2 + cx + d (a different from 0). Find conditions on a, b, c, and d to ensure that f is always increasing or always decreasing on (-00, +00).1 solutions Answer 58030 by stanbon(57357)   on 2007-05-06 11:22:05 (Show Source): You can put this solution on YOUR website!For the general cubic polynomial f(x)= ax^3 + bx^2 + cx + d (a different from 0). Find conditions on a, b, c, and d to ensure that f is always increasing or always decreasing on (-00, +00). ---------- To assure Increasing: The slope would have to be postive for all values of x. Take the derivative: 3ax^2+2bx+c>0 As long as c>0 and a>0 you would get a graph (parabola) that is always above the x axis. That should meet the asked-for condition. -------- To assure decreasing: The slope would have to be negative for all values of x. Use the same drivative but make it <0 Let c<0 and a<0 then you would get a graph (parabola) that is always below the x-axis. That should meet the asked-for condition. =========== Cheers, Stan H. ============ Cheers, Stan H.
 Probability-and-statistics/80840: Assume the following data set for points scored in a basketball game by a player. Data Set: (12, 15, 20, 23, 29, 30) Find the standard deviation of the data set. A. 6.7 B. 7.3 C. 53.1 D. 265.51 solutions Answer 58029 by stanbon(57357)   on 2007-05-06 11:10:51 (Show Source): You can put this solution on YOUR website!The answer is 6.7. Write down your data elements Find the mean value= 21.5. Subtract the mean from each of the data values Square each of the results. Add those squared values. Take the square root of the sum. Divide by (n-1)=5 to get the standard deviation. =========== Cheers, Stan H.
 Probability-and-statistics/80837: Assume there are 10 people taking this class. 3 recieve a grade of "A", 4 recieve a grade of "B" and 3 recieve a grade of "C". What is the empirical probability the next person to enter the class will recieve a grade of "A"? A. 2/5 B. 3/11 C. 3:10 D. 3/101 solutions Answer 58026 by stanbon(57357)   on 2007-05-06 11:03:38 (Show Source): You can put this solution on YOUR website!C. 3 out of 10 or 3/10 ========= Cheers, Stan H.
 Probability-and-statistics/80844: Looking for some help. this question is a smoker. Among 100 people randomly chosen in a survey, 10 stated that they believed that the elected representatives are honest most of the time. The approximate 95% confidence interval for the percentage of the population who believe that such people are honest most of the time is thank you for your time and help.1 solutions Answer 58020 by stanbon(57357)   on 2007-05-06 07:50:03 (Show Source): You can put this solution on YOUR website!Among 100 people randomly chosen in a survey, 10 stated that they believed that the elected representatives are honest most of the time. The approximate 95% confidence interval for the percentage of the population who believe that such people are honest most of the time is ---------- p-hat = 10/100=0.1 E=z*sqrt(pq/n) E=1.96sqrt(0.1*0.9/100) E=1.96*0.0009 E=0.0018 CI: (p-hat-E,p-hat+E) CI: (0.1-0.0018, 0.1+0.0018) CI: (0.0982,0.1018) ============ Cheers, Stan H.
 Probability-and-statistics/80846: not sure how to type this but here goes Let a random sample be taken of size n = 100 from a population with known standard deviation of o = 20 . Suppose that the mean of the sample is X = 37 . The approximate 68% confidence interval for the mean, u , of the population from which the sample was drawn is n = n o = Population standard deviation X = Sample mean u = population mean I need some help on this question and my key board is short some keys. I hope that you can help thank you mirna.1 solutions Answer 58019 by stanbon(57357)   on 2007-05-06 07:38:50 (Show Source): You can put this solution on YOUR website!Let a random sample be taken of size n = 100 from a population with known standard deviation of o = 20 . Suppose that the mean of the sample is X = 37 . The approximate 68% confidence interval for the mean, u , of the population from which the sample was drawn is ------------- E=z*sgma/sqrt(n) E=0.994*20/sqrt(100) E=0.994*2 E=1.988 ------------- CI: (x-bar-E,x-bar+E) CI: (37-1.988, 37+1.988) CI: (35.012,38.988) ============= Let me know if this is too difficult to follow and I will add some connecting comments. ============= Cheers, Stan H.
 Graphs/80854: Here is the question as stated (this is not from a textbook, and I can't find an explanation for a problem like it in any textbooks I have): "Write an equation in standard form for the line parallel to x - 2y + 7 = 0 and contains the point (-4,0)." I am just unsure how to solve this problem. I have converted problems from slope intercept form to standard, and standard to slope intercept, but there hasn't been an extra component (like the +7 in this one.) I am also not sure how to do this when I only have one set of coordinates. I tried figuring out the value of x and the value of y by (if x=0 then y=?, and if y = 0 then x=?) but I have two problems. One is, the numbers I get (x= -7 and y= -7/2) don't make the problem true. And even if they did, I don't know how to use them to help me make the original equation a line parallel to another point. Help!1 solutions Answer 58010 by stanbon(57357)   on 2007-05-05 22:35:28 (Show Source): You can put this solution on YOUR website!Write an equation in standard form for the line parallel to x - 2y + 7 = 0 and contains the point (-4,0). ---------- The given equation can be written in the form y=(1/2)x+7/2 ------------ so the equation you want has the same slope=1/2 The form is y=mx+b where y=0,x=-4 and m=1/2; solve for "b" as follows: 0=(1/2)(-4)+b b=2 EQUATION: y=(1/2)x+2 Now put it in standard form which is ax+by=c. Multiply thru by 2 to get: 2y=x+4 x-2y=-4 is the equation in standard form. ============== Cheers, San H.
 Linear-equations/80855: This question is from textbook beginners algebra Determine which two equations represent parallel lines a)y=6x-2 b) y=-6x+2 c)y=6x+1 d)y=-1/6x-2 and Determine which two equations represent parallel lines. a)y=6x-4 b)y=1/6x+4 c)y=-1/6x+4 d)y=1/6x-4 I really appreciate the help, thanks so much. 1 solutions Answer 58009 by stanbon(57357)   on 2007-05-05 22:27:52 (Show Source): You can put this solution on YOUR website!Determine which two equations represent parallel lines a)y=6x-2 b) y=-6x+2 c)y=6x+1 d)y=-1/6x-2 Answer: a and c have the same slope=6 ------------------------------------- Determine which two equations represent parallel lines. a)y=6x-4 b)y=1/6x+4 c)y=-1/6x+4 d)y=1/6x-4 Answer: b and d which both have slopes of 1/6 ======================= Cheers, Stan H.
 Polynomials-and-rational-expressions/80849: Solve: (x/(x+1)) - (x/(x-1))=-16/63 I tried to multiply each side by the LCD 63(x+1)(x-1) but then everything cancels each other out and I end up with 0=-16. What am I doing wrong?1 solutions Answer 58008 by stanbon(57357)   on 2007-05-05 22:15:24 (Show Source): You can put this solution on YOUR website!(x/(x+1)) - (x/(x-1))=-16/63 Multiply thru -by 63(x+1)(x-1) to get: 63x(x-1) - 63x(x+1) = -16(x^2-1) -126x = -16x^2+16 16x^2-126x-16=0 8x^2-63x-8=0 x=[63+-sqrt(63^2-4*8*-8)]/16 x=[63+-sqrt4225]/16 x=8 or x=-1/8 ==================== Cheers, Stan H.
 Probability-and-statistics/80842: Assume the following data set for points scored in a basketball game by a player Data Set: (12, 15, 20, 23, 29, 30). Assuming a standard normal distribution what would be the percentage of basketball games where the player should score more than 25 points? A. 18.4% B. 50% C. 31.6% D. 68.4%1 solutions Answer 58007 by stanbon(57357)   on 2007-05-05 21:05:53 (Show Source): You can put this solution on YOUR website!Assume the following data set for points scored in a basketball game by a player Data Set: (12, 15, 20, 23, 29, 30). Assuming a standard normal distribution what would be the percentage of basketball games where the player should score more than 25 points? -------------- Find the mean and standeard deviation of the set of scores: mu=21.5; sigma=6.65 P(X>25)=0.299... Comments: Results from TI calculator normalcdf(25,100,21.5,6.65)=0.299 --------------- Cheers, Stan H.
 Quadratic-relations-and-conic-sections/80843: Find an equation of a parabola satisfying the given conditions. Focus(0-pie),directrix y=pie1 solutions Answer 58004 by stanbon(57357)   on 2007-05-05 19:58:26 (Show Source): You can put this solution on YOUR website!What do you mean by "Focus (0-pi)"? Cheers, Stan H.
 Quadratic_Equations/80825: Can someone please check this for me? solve by using the quadratic formula x^2=5x+8 x^2=25+8 =-5+-sqrt33/21 solutions Answer 57995 by stanbon(57357)   on 2007-05-05 17:52:18 (Show Source): You can put this solution on YOUR website!solve by using the quadratic formula x^2=5x+8 x^2-5x-8=0 x=[5+-sqrt(25-4*-8)]/2 x=[5+-sqrt47]/2 x=(5+sqrt47)/2 or x=[5-sqrt47]/2 ========================= x^2=25+8 x^2-25x-8=0 x=[25+-sqrt(625-4*-8)]/2 x=[25+-sqrt657]'2 x=[25+sqrt657]/2 or x=[25-sqrt657]/2 ============ Cheers, Stan H.
 Graphs/80826: This question is from textbook Collage Algebra I need help on how to graph a liner equation and how to determine it's slope. y=3/4x-4. Thanks!!1 solutions Answer 57994 by stanbon(57357)   on 2007-05-05 17:45:19 (Show Source): You can put this solution on YOUR website!graph a liner equation and how to determine it's slope. y=(3/4)x-4. ------------ You are given the equation in the form y=mx+b where m=3/4 m=3/4 is the slope ------------- To graph it you need two points: If x=0, y=-4 If x=4 y=(3/4)(4)-4 = -3 Plot those two points and draw a line thru them This is the graph you want. --------------- ============ Cheers, Stan H.
 Quadratic_Equations/80827: can someone please check this for me? (x-3)^2=9 =x=-3+-9 x=3+-sqrt91 solutions Answer 57991 by stanbon(57357)   on 2007-05-05 17:36:48 (Show Source): You can put this solution on YOUR website!(x-3)^2=9 Write it as follows: [(x-3)^2-9]=0 This is the difference of squares: Factor as follows: [x-3-3][x-3+3]=0 [x-6][x]=0 x=0 or x=6 -------------- Another way to do it: Expand it to get: x^2-6x+9-9=0 x^2-6x=0 x(x-6)=0 x=0 or x=6 ============= Cheers, Stan H.
 Points-lines-and-rays/80818: Find the coordinates of the image of a segment whose endpoints are: D(-2,3) and K(1,2) after each transformation. A translation of right 4 and down 2? A reflection over the x-axis? A rotation of 90 degrees about the orgin? 1 solutions Answer 57986 by stanbon(57357)   on 2007-05-05 16:05:28 (Show Source): You can put this solution on YOUR website!Find the coordinates of the image of a segment whose endpoints are: D(-2,3) and K(1,2) after each transformation. ---------------- Looking at D(2,-3) A translation of right 4 and down 2? You go to (2+4,-3-2) or (6,-5) -------------------------- A reflection over the x-axis? You go to (2,3) ---------------------------- A rotation of 90 degrees about the origin? That depends of which way you rotate. If +90 degrees (counter clockwise), go to (3,2) If -90 degrees (clockwise), go to (-2,-3) ============ You can work it out for K(1,2). Draw the coordinat system. Notice the x and y distances from the axes. Perform the translation and you will see what the new coordinates have to be> ----------------- Cheers, Stan H.
 Angles/80819: The perimeter of a triangle is 24cm. One side is 2cm. longer than the shortest side. The longest side is 2cm less than twice the length of the shorest side. Find the length of each side of the triangle.1 solutions Answer 57985 by stanbon(57357)   on 2007-05-05 15:52:43 (Show Source): You can put this solution on YOUR website!The perimeter of a triangle is 24cm. One side is 2cm. longer than the shortest side. The longest side is 2cm less than twice the length of the shorest side. Find the length of each side of the triangle. ----------- Let the shortest side be "x". A 2nd side is "x+2" The longest side is "2x-2" EQUATION: x + x+2 + 2x-2 = 24 4x=24 x=6 cm (shortest side) x+2 = 8 cm (2nd shde) 2x-2= 10 cm (longest side) =============== Cheers, Stan H.
 Polynomials-and-rational-expressions/80821: what is x^2-25 when factored? the question reads factor each polynomial completely. 1 solutions Answer 57984 by stanbon(57357)   on 2007-05-05 15:44:34 (Show Source): You can put this solution on YOUR website!what is x^2-25 when factored? -------------- The form is a^2-b^2 which factors into (a-b)(a+b) --------------- Your Problem: x^2-25 = (x-5)(x+5) ============== Cheers, Stan H.
 Equations/80822: 8r -(5r+4)> - 31 1 solutions Answer 57983 by stanbon(57357)   on 2007-05-05 15:42:26 (Show Source): You can put this solution on YOUR website!8r -(5r+4)> - 31 8r-5r-4 > -31 3x > -27 x > -9 =========== Cheers, Stan H.
 Quadratic_Equations/80824: can someone check this for me please!please check this for me 2x^2-6x+3=0 2^2+(-6)+3=0 1^2+(-3)+1.5=0 -3/4^2+x=1.5 x=1.5-(-3)/4^2=0.75 (-3/2)^2+(-0.75)=0 (13/2)=sqrt0.75 and (-3/2)=-sqrt0.751 solutions Answer 57982 by stanbon(57357)   on 2007-05-05 15:40:23 (Show Source): You can put this solution on YOUR website!I can't even imagine what you are trying to do. -------------- Your Problem: 2x^2-6x+3=0 Use the quadratic formula to get: x=[6+-sqrt(6^2-4*2(3)]/4 x=[6+-sqrt(12)]/4 x=[6+-2sqrt(3)]/4 x=(3+sqrt3)/2 or x=(3-sqrt3)/2 =============== Cheers, Stan H.
 Equations/80823: Solve 6(|n|-3)-4|n|+5+11 1 solutions Answer 57981 by stanbon(57357)   on 2007-05-05 15:34:40 (Show Source): You can put this solution on YOUR website!Solve 6(|n|-3)-4|n|+5+11 You cannot "solve" it because it is not an equation. You can only simplify it. -------------- 6|n|-18-4|n|+5+11 =2|n|-2 ---------- Cheers, Stan H.