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# Recent problems solved by 'stanbon'

Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 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56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179 , 57180..57209 , 57210..57239 , 57240..57269 , 57270..57299 , 57300..57329 , 57330..57359 , 57360..57389 , 57390..57419 , 57420..57449 , 57450..57479 , 57480..57509 , 57510..57539 , 57540..57569 , 57570..57599 , 57600..57629 , 57630..57659 , 57660..57689 , 57690..57719 , 57720..57749 , 57750..57779 , 57780..57809 , 57810..57839 , 57840..57869 , 57870..57899, >>Next

 Linear_Algebra/98609: How would i graph y=2x+-2 if my paper says to make a table with any 5 numbers for the domain so if i chose -1,2,0,-2 for my x-values what do i put for my y values1 solutions Answer 71736 by stanbon(57967)   on 2007-09-16 20:14:44 (Show Source): You can put this solution on YOUR website!How would i graph y=2x+-2 if my paper says to make a table with any 5 numbers for the domain so if i chose -1,2,0,-2 for my x-values what do i put for my y values. -------------- That is what the equation tells you: y = 2x -2 So if x=-1, y=2*-1-2 = -2-2 = -4 And if x=2, y=2*2-2 = 4-2 = 2 etc. Cheers, Stan H.
 Money_Word_Problems/98602: This question is from textbook intro alg blitzer here's the question... I invested \$10,000 bonus in a CD that paid 6% simple interest and the rest in a mutual fund that paid @ 11%. If total interest earned that year was \$700.00. how much did I invest in the mutual fund? 0.06x + 0.11(10,000-x)=\$700 0.06x+1100-0.11x=\$700 -0.11x -0.05x +1100-1100=700-1000 -0.05x = -300 divided and came up with \$6000.00 \$10,000-6000= \$4000 @ 11% is this correct?1 solutions Answer 71733 by stanbon(57967)   on 2007-09-16 20:10:46 (Show Source): You can put this solution on YOUR website!I invested \$10,000 bonus in a CD that paid 6% simple interest and the rest in a mutual fund that paid @ 11%. If total interest earned that year was \$700.00. how much did I invest in the mutual fund? 0.06x + 0.11(10,000-x)=\$700 0.06x+1100-0.11x=\$700 -0.11x -0.05x +1100-1100=700-11000 -0.05x = -400 divided and came up with \$8000.00 (amount invested at 6%) \$10,000-8000= \$2000 (amount invested at 11%) ========== Note: You can always check your own answers. You could have checked 0.06*6000 + 0.11*4000 and found you did not get 700. That would tell you to look over your work again. ============================ Cheers Stan H.
 Graphs/98529: Graph the function using its vertex, axis of symmetry, and intercepts. f(x) = x2 - 6x 1 solutions Answer 71730 by stanbon(57967)   on 2007-09-16 19:59:56 (Show Source): You can put this solution on YOUR website!Graph the function using its vertex, axis of symmetry, and intercepts. f(x) = x^2 - 6x Complete the square on the x-terms: x^2-6x+9 = y+9 (x-3)^2 = y+9 ---------------- Vertex: (3,-9) Axis of symmetry: x=3 ------------ Intercepts: y-intercept: Let x=0, then y=0 ------ x=intercepts: Let x=0, then y = 0 or 6 ========================== Cheers, Stan H.
 Mixture_Word_Problems/98496: This question is from textbook College Algebra and Trigonometry A radiator contains 6 liters of 25% antifreeze solution. How much should be drained and replaced with pure antifreeze to produce a 33% antifreeze solution? So far, I know that the first solution contains 6 liters and I need to multiply that by 25%. Then since we are "replacing" pure antifreeze to the mixture that is 100% that I need to multiply to the unknown mixture of x+6 (which is my second solution) so that I can produce a 33% solution. Does this make any sense? I'm not sure how to do this. Thank You1 solutions Answer 71728 by stanbon(57967)   on 2007-09-16 19:54:26 (Show Source): You can put this solution on YOUR website!A radiator contains 6 liters of 25% antifreeze solution. How much should be drained and replaced with pure antifreeze to produce a 33% antifreeze solution? ----------------- Note: Keep track of the active ingredient. -------------- Start: 25%*6 liters = (3/2)liters of active --------------- You subtract x liters but it is still 25% active: You now have: (3/2)-(x/4) active; You add x amount of 100% active: You now have (3/2)-(x/4)+x active ---------------- That amount of active is 33% of the 6 liters you now have: EQUATION: (3/2)-(x/4)+x = 33%*6 (3/2) + (3/4)x = 2 (3/4)x = 1/2 x = (1/2)(4/3) x = 2/3 liters --------------- That is the amount of 100% alcohol you should add. ===================== Cheers, Stan H.
 Expressions-with-variables/98566: This problem does not come from a book, but I would appreciate it very much if you can solve it as I have a deadline tonight! Thanks so much~ Rewrite the equation below in general form Ax + By = C where A, B and C are the smallest integers possible and A > 0. Enter the variable expression Ax + By separately from the constant term C. y = 4/7(x) + 2/17 1 solutions Answer 71723 by stanbon(57967)   on 2007-09-16 19:32:14 (Show Source): You can put this solution on YOUR website!y = (4/7)(x) + 2/17 ----------- Multiply thru by 7*17 = 119 to get: 119y = 4*17x + 2*7 119y = 68x + 14 68x+(-119)y = -14 --------- This is usually written: 68x - 119y = -14 ================ Cheers, Stan H.
 Radicals/98586: Simplify the radical expressions. Assume that all variables represent positive real numbers. /(8/25)1 solutions Answer 71721 by stanbon(57967)   on 2007-09-16 19:22:55 (Show Source): You can put this solution on YOUR website!sqrt(8/25) = [sqrt(8)]/[sqrt(25)] = [2sqrt(2)]/5 =(2/5)sqrt(2) ============= Cheers, stan H.
 Radicals/98588: Simplify the radical expressions. Assume that all variables represent positive real numbers. /961 solutions Answer 71717 by stanbon(57967)   on 2007-09-16 19:09:02 (Show Source): You can put this solution on YOUR website!sqrt(96) = sqrt(16*6) = 4sqrt(6) ------------- Cheers, Stan H.
 Graphs/98572: if y varies directly with x, and y=44 when x=4 find the constant of variation k1 solutions Answer 71715 by stanbon(57967)   on 2007-09-16 19:07:05 (Show Source): You can put this solution on YOUR website!if y varies directly with x, and y=44 when x=4 find the constant of variation k -------------- y = kx 44 = k*4 k= 11 =========== Cheers, Stan H.
 Miscellaneous_Word_Problems/98560: This question is from textbook Beginning Algebra Please help! Can you give me a step by step solution? "A community theater sold 900 tickets to a play. Floor seats cost 12\$ each, and balcony seats cost 10\$. The total receipts were 9780\$. How many of each type of ticket were sold?" Thank you very much!1 solutions Answer 71704 by stanbon(57967)   on 2007-09-16 18:16:03 (Show Source): You can put this solution on YOUR website!A community theater sold 900 tickets to a play. Floor seats cost 12\$ each, and balcony seats cost 10\$. The total receipts were 9780\$. How many of each type of ticket were sold ---------- Let # of \$12 tickets be "x" ; Value of these is 12x dollars ------------------ # of \$10 tickets is "900-x" ; Value of these is 10(900-x)=9000-10x dollars ------------------- EQUATION: value + value = \$9780 12x + 9000-10x = 9780 2x = 780 x = 390 (# of \$12 tickets) 900-x = 510 (# of \$10 tickets) ============== Cheers, Stan H.
 Rational-functions/98556: Write the domain of the ration function in interval notation. F(x)= 1/x-10 I just dont understand how they want me to express it. 1 solutions Answer 71703 by stanbon(57967)   on 2007-09-16 18:08:39 (Show Source): You can put this solution on YOUR website!Write the domain of the ration function in interval notation. F(x)= 1/(x-10) ------------- The denominator must not be zero. So x-10 cannot be zero So x cannot be 10 ------- Domain is all Real Numbers except x=10. ============== Cheers, Stan H.
 Exponents-negative-and-fractional/98553: I am having trouble with a question on rules of exponants. I have 6 questions to do but don't know how to reduce or move exponents (positive and negative) from one side of the equation to the other. My first question in my home work is: open bracket n to the 5th closed bracket to the negative 6 equals 1 (n5)-6 = 1 I guess I should write it like (n^5)^-6 = 1 When I move an exponent across the equals sign does it become a root and does a negative become a positive. So that the -6 exponent would become a positive root 6?? This is on a hand out there is no text book (ISBN)1 solutions Answer 71702 by stanbon(57967)   on 2007-09-16 18:04:53 (Show Source): You can put this solution on YOUR website!Exponents change sign when you move them up and down not right and left ------------ 1/x^2 = x^-2/1 ----------- x^3 = 1/x^-3 --------------- (n^5)^-6 = 1 n^-30 = 1 1/[n^30] = 1 Cross-multiply to get: n^30 =x n = 1 or n = -1 ========================= Cheers, Stan H.
 expressions/98519: 13 less than two times S How do I write this in an algebraic equation?1 solutions Answer 71696 by stanbon(57967)   on 2007-09-16 17:05:30 (Show Source): You can put this solution on YOUR website!2S - 13 ============ Cheers, Stan H.
 logarithm/98545: This question is from textbook Calculus with Applications Brief Version I'm having trouble solving for 'x' in this equation . I have tried re-arranging it to make an exponential equation, but I end up confusing myself even more. Thank you for looking at this.1 solutions Answer 71695 by stanbon(57967)   on 2007-09-16 17:02:07 (Show Source): You can put this solution on YOUR website!log4(x-2)+ log4(x+6)=2 ----------- Note: Keep the "base 4" in mind ============ log(x-2)(x+6) = 2 (x-2)(x+6) = 4^2 x^2+4x-12 = 16 x^2+4x-28=0 x = [-4 +- sqrt(16-4*-28]/2 x = [-4 +- sqrt(128)]/2 ---------------- x = [-4 + 8sqrt(2)]/2 = -2+4sqrt2 OR x = [-4 - 8sqrt(2)]/2 = -2-4sqrt2 ==================== Cheers, Stan H.
 Complex_Numbers/98546: the two longest sides of a pentagon are each three times as long as the shortest side. the other sides are each 8 meters longer than the shortest side. find the length of each side if the perimeter is 79 meters.1 solutions Answer 71693 by stanbon(57967)   on 2007-09-16 16:53:12 (Show Source): You can put this solution on YOUR website!the two longest sides of a pentagon are each three times as long as the shortest side. the other sides are each 8 meters longer than the shortest side. find the length of each side if the perimeter is 79 meters. ------------ Let the shortest side be x meters long. Two longest sides are each 3x meters long. Each of the two remainding sides is x+8 meters long. --------------- EQUATION: x + 3x + 3x + x+8 + x+8 = 79 9x + 16 = 79 9x = 83 x = 83/9 meters 3x = 83/3 meters x+8 = 155/9 meters -------------------- Cheers, Stan H.
 Expressions-with-variables/98536: I am attepting to solve this equation, but am having difficulty. 2x + 15 = (-2x - 3) / x 1 solutions Answer 71689 by stanbon(57967)   on 2007-09-16 16:40:23 (Show Source): You can put this solution on YOUR website!2x + 15 = (-2x - 3) / x ---------------- Multiply both sides by "x" to get: 2x^2+15x = -2x-3 2x^2+17x+2=0 x = [-17 +- sqrt(17^2-4*2*2)]/4 x = [-17 +- sqrt(273)]/4 x = [-17 + 16.5227..]/4 = -0.11932... OR x = [-17 - 16.5227..]/4 = -8.380677.... ============ Cheers, Stan H.
 Graphs/98528: Graph the function by starting with the graph of the basic function and then using the techniques of shifting, compressing, stretching, and/or reflecting. f(x) = (x - 1)2 - 3 1 solutions Answer 71686 by stanbon(57967)   on 2007-09-16 16:30:28 (Show Source): You can put this solution on YOUR website!f(x) = (x - 1)2 - 3 ------------------- Start with y=x^2 ---------- Shift all points one to the right to get: y = (x-1)^2 -------------- Move all point down three to get: y = (x-1)^2-3 ================= Cheers, Stan H.
 Travel_Word_Problems/98531: Two buses traveling in opposite directions. Bus one at 55mph, bus two at 45 mph. How long before they are 400 miles apart? So can I do it like this? t = time B1 times t plus B2 times t = 400 55T + 45T = 400 100T= 400 t= 4 4 hours and they will be 400 miles apart. Thank You, Laur1 solutions Answer 71685 by stanbon(57967)   on 2007-09-16 16:26:11 (Show Source): You can put this solution on YOUR website!Yes; that's good. Cheers, Stan H>
 Functions/98525: Find the domain of the function. h(x) = x-4/x3-64x note: x3 is x to 3rd degree and and it is a fraction thanks 1 solutions Answer 71680 by stanbon(57967)   on 2007-09-16 14:49:32 (Show Source): You can put this solution on YOUR website!Find the domain of the function. h(x) = x-4/[x^3-64x] ------------ h(x) = (x-4)/[x(x-8)(x+8)] ----------- Domain: All Real Numbers except x=0, x=8, x=-8 ============== Cheers, Stan H.
 Probability-and-statistics/98524: This question is from textbook Algebra 2 Find the combinations. 10C21 solutions Answer 71678 by stanbon(57967)   on 2007-09-16 14:44:36 (Show Source): You can put this solution on YOUR website!Find the combinations. 10C2 --------- Long Form: 10C2 = 10!/[(10-2)!*2!] = 45 ------- Short Form:10C2 = [10*9]/[1*2] = 45 ============ Cheers, Stan H.
 Exponential-and-logarithmic-functions/98517: i need help with this... Solve simultaneously: , what ive got so far is : , and 1 solutions Answer 71677 by stanbon(57967)   on 2007-09-16 14:39:51 (Show Source): You can put this solution on YOUR website!2log y = log 2 + log x , 2^y=4x ----------------------- log(y^2/x) = log(2) --------------------------------- 1st: y^2 = 2x ------------------ 2nd: 2^y = 4x -------------- Multiply 1st by 2 to get: 2y^2=4x ------------ Therefore 2y^2 = 2^y y^2 = 2^(y-1) -------------- Solution: y = 1 Substitute into 2logy=log2+logx 0 = log2 +logx 0=log(2x) 2x = 1 x = 1/2 ---------------- Check x=1/2 and y=1 in 2^y=4x 2^1 = 4(1/2) 2 = 2 =========== Cheers, Stan H. =============== Cheers, Stan H.
 percentage/98507: An herbicide loses one-half its toxic effect each week. After how many weeks will the herbicide have less than 10 percent of its original potency?1 solutions Answer 71674 by stanbon(57967)   on 2007-09-16 14:12:43 (Show Source): You can put this solution on YOUR website!An herbicide loses one-half its toxic effect each week. After how many weeks will the herbicide have less than 10 percent of its original potency? ---------------- let Po be the original potency. ------------------ If you figure the answer in days Po(1/2)^(t/7) < 0.10Po --------- Divide both sides by Po to get: (1/2)^(t/7) < 0.10 Take the log to get: (t/2)log(1/2) Since log(1/2) is negative you get: (t/7) > [log0.10]/[log(1/2) t/7 > 3.32 t > 23.25 days ---------------- Starting with the 24th day, the percentage will be < 10% of the original amount. ======================== Cheers, Stan H.
 Linear-equations/98516: Write the equation of the line that passes through point (7, –13) with a slope of –3.1 solutions Answer 71673 by stanbon(57967)   on 2007-09-16 13:54:34 (Show Source): You can put this solution on YOUR website!Write the equation of the line that passes through point (7, –13) with a slope of –3. ---------- Form y=mx+b You are given x, y, and m; solve for b asfollows: -13 = -3*7 + b 8 = b EQUATION: y=-3x+8 ========== Cheers, Stan H.
 Miscellaneous_Word_Problems/98430: Please help me with this question. I've been trying to solve this question for days but I still couldn't figure this out. We will have to submit this one on September 11. Thanks........ A freight train makes a regular run of 1300 km according to its present schedule. The train dispatchers want to schedule this run for less than one hour, but the average speed will have to be increased by 2 km per hour. What average speed will be required to make the run on the new schedule?1 solutions Answer 71633 by stanbon(57967)   on 2007-09-15 23:12:06 (Show Source): You can put this solution on YOUR website!A freight train makes a regular run of 1300 km according to its present schedule. The train dispatchers want to schedule this run for less than one hour, but the average speed will have to be increased by 2 km per hour. What average speed will be required to make the run on the new schedule? ------------- Old schedule DATA; Distance = 1300 km; rate = x kpm ; time = d/r = 1300/x hrs ----------------- New schedule DATA: Disance = 1300 km; rate = x+2 kpm ; time = d/r = 1300/(x+2) hrs ----------------- EQUATION: New time < 1 hour 1300/(x+2) < 1 x+2 > 1300 x > 1300+2 kph x > 1303 kph ================= Comment: That would more than 800 mph. Are you sure you have stated the problem correctly? It would be more reasonable to REDUCE the time by one hour rather than to have the new time be LESS than one hour. Please check the statement of your problem. ======================= Cheers, Stan H.
 Radicals/98182: Simplify the radical expressions. Assume that all variables represent positive real numbers /48 + /1471 solutions Answer 71593 by stanbon(57967)   on 2007-09-15 18:18:11 (Show Source): You can put this solution on YOUR website!/48 + /147 ---------------- sqrt(48) + sqrt(147) = sqrt(16*3) + sqrt(49*3) = 4sqrt(3) + 7sqrt(3) = 11sqrt(3) ============== Cheers, Stan H.
 Miscellaneous_Word_Problems/98415: Another word problem Im having trouble with. Using R for revenue, C for cost, and P for profit, write an expression for selling x thousand items if the the following is true. Item price: \$8.00 Fixed Costs \$71,174 Varaible Costs \$3816x Thank you1 solutions Answer 71591 by stanbon(57967)   on 2007-09-15 17:57:45 (Show Source): You can put this solution on YOUR website!Using R for revenue, C for cost, and P for profit, write an expression for selling x thousand items if the the following is true. Item price: \$8.00 Fixed Costs \$71,174 Variable Costs \$3816x --------------- Comment: "Variable Costs" is not a standard finance item, especially when it contains a variable in its expression. ------------------------ Revenue = (price)*(number of items sold) = 8*x Profit = Revenue - Cost= 8x - 71,174-3816x ============================= Cheers, Stan H.
 Square-cubic-other-roots/98416: You have a round clock from 1-12. Draw two straight lines to get three equal sums. I drew a line from 1 to 11 and from 9 to 3. I'm not sure though because it sawy three equal sums when you're supposed to draw two lines.1 solutions Answer 71588 by stanbon(57967)   on 2007-09-15 17:45:13 (Show Source): You can put this solution on YOUR website!Two lines could separate the clock-face into 3 regions where the sum of the hour numbers was equal. Try doing that. Cheers, Stan H.
 Percentage-and-ratio-word-problems/98406: This question is from textbook beginning and intermediate algebra One roofer can put a neew roof on a house three times faster than another. Working together they can roof a house in 4 days. How long would it take the faster roofer working alone? I need to know how to set up the problem then i can work it from there1 solutions Answer 71567 by stanbon(57967)   on 2007-09-15 16:10:22 (Show Source): You can put this solution on YOUR website!One roofer can put a neew roof on a house three times faster than another. Working together they can roof a house in 4 days. How long would it take the faster roofer working alone? I need to know how to set up the problem then i can work it from there ------------------- 1st roofer DATA: Time = x days/job ; Rate = 1/x job/day ------------------- 2nd roofer DATA: Time = 3x days/job ; Rate = 1/3x job/day --------------- Working-together DATA: Time = 4 day/job ; Rate = 1/4 job/day ------------------ EQUATION: rate + rate = together rate ================ I'll let you solve it. ================= Cheers, Stan H.
 Angles/98407: please help me solve this asap ! thanks. five times the complement of an angle less twice the angle's supplement is 40 degrees. find the measure of the supplement. 1 solutions Answer 71565 by stanbon(57967)   on 2007-09-15 16:04:33 (Show Source): You can put this solution on YOUR website!five times the complement of an angle less twice the angle's supplement is 40 degrees. find the measure of the supplement. --------------- Let the angle be "x". Its complement is "90-x" Its supplement is "180-x" ------------------- EQUATION: 5(90-x)-2(180-x) = 40 Solve for x ================ cheers, Stan H.
 Inequalities/98352: Hello, I am to make a graph to depict the variables for the value of a house that is \$10,000 now and rises \$1500 every year. I am not sure how to do this, and how to show linear inequalities, I would appreciate some help if possible!1 solutions Answer 71563 by stanbon(57967)   on 2007-09-15 16:01:54 (Show Source): You can put this solution on YOUR website!You should not post the same problem many times; it jams up the list. Cheers, Stan H.
 Graphs/98391: I am not understanding this question. Write equations for the vertical and the horizontal lines passing through the point(2,7) in(x,y)coordinates. 1 solutions Answer 71562 by stanbon(57967)   on 2007-09-15 15:59:02 (Show Source): You can put this solution on YOUR website!Did you understand the answer? x=2; y=7 Those are the equations you are looking for x=2 is the vertical line thru the point (2,7) y=7 is the horizontal line thru the point (2,7) ============== Cheers, Stan H.
 Linear_Equations_And_Systems_Word_Problems/98397: This is for our Chapter 2 test and he never explained ive tried and tried to get the soultion and I've came up with \$2.26 and my husband came up with \$10.77 so Here goes. Recently, the Texas Junior College Teachers Association annual conferance was held in Austin. At That time a taxi ride in Austin was \$1.25 for the first 1/5 of a mile and \$0.25 for each addtional 1/5 of a mile. The distance from one of the convention hotels to the airport is 7.5 miles. If you were to tip the driver of the taxi 15%, how much would it cost to take the taxi from the hotel to the airport?1 solutions Answer 71561 by stanbon(57967)   on 2007-09-15 15:55:32 (Show Source): You can put this solution on YOUR website!a taxi ride in Austin was \$1.25 for the first 1/5 of a mile and \$0.25 for each addtional 1/5 of a mile. The distance from one of the convention hotels to the airport is 7.5 miles. If you were to tip the driver of the taxi 15%, how much would it cost to take the taxi --------------- 1st (1/5)th mile = 1.25 dollars --------------------------------- Remaining Distance = 7.5 - 0.2 miles = 7.3 miles ------------------------- 7.3/(0.2) =36.5 (this is the number of (1/5)th of a mile after the 1st (1/5)th ----------------------------- Each of these costs 0.25 dollars 36.5*0.25 = 9.125 dollars ------------------------------- Total cost before tip = 1.25+9.125 = 10.375 dollars --------------------------- 15% tip = 0.15*10.375 = 1.55625 dollars ==================== Total cost including tip = 10.375+1.55625 = \$11.93 ======================= Cheers, Stan H.