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Recent problems solved by 'stanbon'
stanbon answered: 57222 problems
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56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179 , 57180..57209 , 57210..57239, >>Next
Probability-and-statistics/663125: From a large shipment of transistors from a supplier, 1% of the items are known to be defective. If a sample of 200 transistors are selected at random, what is the probability that 4 or more transistors will be defective?
The method I tried:
X-B(200,0.01), find P(X>=4)
n=200 np=200(0.01)=2<5
Therefore X-P(2)
P(X>=4)=1-P(X=3)
Then ???
1 solutions
Answer 412628 by stanbon(57290)   on 2012-10-08 07:08:49 (Show Source):
You can put this solution on YOUR website!From a large shipment of transistors from a supplier, 1% of the items are known to be defective. If a sample of 200 transistors are selected at random, what is the probability that 4 or more transistors will be defective?
----
Binomial Problem with n = 200 ; p(defect) = 0.01
----
P(x>=4) = 1 - P(0<= x <=3) = 1 - binomcdf(200,0.01,3) = 0.1420
====================
Cheers,
Stan H.
|
Probability-and-statistics/662996: Please help.
picking an ace or a ten from a standard deck of 52 cards
and
picking a red marble from a bag containg 20 white marbles, 8 blue, and 2 red.
My homework is based on questions like these, so if someone helps answer them i may be able to figure out the rest. i looked on the note sheet i have to help explain but i still don't understand, it's very hard for my to understand algerbra.
one example i wrote down is:
what are the odds against drawing a diamond from a standard 52 card deck.
so it's 52/4 = 13 diamonds in a deck, number of unfavorable outcomes/number of favorable outcomes = 39/13=3/1.
i can understand the begining but where did the 39 come from?
please help.
1 solutions
Answer 412580 by stanbon(57290) on 2012-10-07 20:56:39 (Show Source):
You can put this solution on YOUR website!what are the odds against drawing a diamond from a standard 52 card deck.
so it's 52/4 = 13 diamonds in a deck and 39 cards that are not diamonds.
-------------------
odds against = number of unfavorable outcomes/number of favorable outcomes
= 39/13 = 3:1
-----
Cheers,
Stan H.
================
|
Numeric_Fractions/662999: I have $1 in coins. One-fifth of the coins are dimes, two-fifteenths are nickels, and two-thirds are pennies. How many of each coin do I have?
I know that I have 30 coins with 6 dimes, 4 nickels and 20 pennies. I can't seem to figure out an equation to show how I arrived at my answer.
1 solutions
Answer 412579 by stanbon(57290) on 2012-10-07 20:49:21 (Show Source):
You can put this solution on YOUR website!I have $1 in coins. One-fifth of the coins are dimes, two-fifteenths are nickels, and two-thirds are pennies. How many of each coin do I have?
-------
Note: (1/5) + (2/15) + (2/3) = (3/15) + (2/15) + (10/15) = 15/15 = 1
Equations:
Value Equation: p + 5n + 10d = 100 cents
-----
Let "x" be the number of coins.
p = (2/3)x
n = (2/15)x
d = (1/5)x
----
Substitute and solve for "x"
(2/3)x + 5(2/15)x + 10(1/5)x = 100
-----
Multiply thru by 15:
10x + 10x + 30x = 1500
50x = 1500
x = 30 (total # of coins)
===========
Cheers,
Stan H.
|
test/662992: A student missed 3 problems on a test and received a grade of 77%. If all problems were equal value, how many problems were on the test!
1 solutions
Answer 412570 by stanbon(57290) on 2012-10-07 20:26:10 (Show Source):
You can put this solution on YOUR website!A student missed 3 problems on a test and received a grade of 77%. If all problems were equal value, how many problems were on the test!
--------------------------
Let "x" be the # of problems on the test.
---
23% of x = 3
x = 3/0.23
x = 13 when rounded down
===================
Cheers,
Stan H.
|
Mixture_Word_Problems/662980: A sugar solution was made by mixing 8 qt of a 2% sugar solution and 6 qt of a 51% sugar solution. find the concentration of the new mixture
1 solutions
Answer 412567 by stanbon(57290) on 2012-10-07 20:18:39 (Show Source):
You can put this solution on YOUR website!A sugar solution was made by mixing 8 qt of a 2% sugar solution and 6 qt of a 51% sugar solution. find the concentration of the new mixture
-------
Equation:
sugar + sugar = sugar
0.02*8 + 0.51*6 = x(8+6)
-----
Multiply thru by 100 to get:
-----
2*8 + 51*6 = 1400x
-----
16 + 306 = 1400x
322 = 1400x
x = 322/1400
x = 0.23 = 23% (That is the concentration of the mixture)
==================
Cheers,
Stan H.
==================
|
Mixture_Word_Problems/662912: How would I set up the following problem to find the answer?
How many pounds of M&M's containing 50% red M&M's would we have to mix with 5 pounds of M&M's containing only 25% red M&M's to obtain a final mix that contains 40% red M&M's?
1 solutions
Answer 412552 by stanbon(57290) on 2012-10-07 18:20:36 (Show Source):
You can put this solution on YOUR website!How many pounds of M&M's containing 50% red M&M's would we have to mix with 5 pounds of M&M's containing only 25% red M&M's to obtain a final mix that contains 40% red M&M's?
-----
Equation:
red + red = red
----
0.50x + 0.25*5 = 0.40(x+5)
-----
50x + 25*5 = 40*x + 40*5
-----
10x = 15*5
x = 7.5 lbs (amt. of 50% M&M's needed)
----
Cheers,
Stan H.
|
Functions/662913: f(x)=2x+4 find the inverse function, domain and range of inverse function
1 solutions
Answer 412549 by stanbon(57290) on 2012-10-07 18:13:07 (Show Source):
You can put this solution on YOUR website! f(x)=2x+4 find the inverse function, domain and range of inverse function
----
1st: interchange x and y
x = 2y+4
-----
2nd: Solve for "y":
2y = x-4
----
Divide both sides by 2 to get:
y = (1/2)x -2
That is the inverse function:
Domain: All Real Numbers
Range: All Real Numbers
========================
Cheers,
Stan H.
|
Mixture_Word_Problems/662906: Copper that was 63% pure was melted together with copper that was 90% pure to make 18 kilograms of an alloy that was 75% pure. How many kilograms of each kind were used?
1 solutions
Answer 412548 by stanbon(57290) on 2012-10-07 18:09:45 (Show Source):
You can put this solution on YOUR website!Copper that was 63% pure was melted together with copper that was 90% pure to make 18 kilograms of an alloy that was 75% pure. How many kilograms of each kind were used?
------
Equation:
copper + copper = copper
---
0.63x + 0.90(18-x) = 0.75*18
----
63x + 90*18 - 90x = 75*18
-27x = -15*18
---
x = 10 kg (amt of 63% alloy needed)
---
18-x = 8 kg (amt of 90% alloy needed)
==============
Cheers,
Stan H.
|
Travel_Word_Problems/662901: Nancy drives in traffic for 2 and 1/2 hours. After traffic dies down she travels another 4 and 1/2 hrs. at 42 mph. If the entire trip was 371 miles, how fast was she driving in traffic?
1 solutions
Answer 412547 by stanbon(57290) on 2012-10-07 17:50:16 (Show Source):
You can put this solution on YOUR website!Nancy drives in traffic for 2 and 1/2 hours. After traffic dies down she travels another 4 and 1/2 hrs. at 42 mph. If the entire trip was 371 miles, how fast was she driving in traffic?
-------
1st leg DATA:
time = 5/2 hrs ; rate = x mph ; distance = (5/2)x miles
-------
2nd leg DATA:
time = 9/2 hrs ; rate = 42 mph ; distance = (9/2)*42 = 189 miles
-------
Equation:
distance + distance = 371
(5/2)x + 189 = 371
-----
(5/2)x = 182
----
x = (2/5)182
---
x = 72.8 mph(rate of the 1st leg)
=========================================
Cheers,
Stan H.
|
logarithm/662883: Express the function f(x) = 4^5log4(2x + 4) without using logarithms
I have tried to move the 5 to be an exponent to follow the log properties and I have tried to change to exponential. I'm really not sure what I am doing wrong.
1 solutions
Answer 412535 by stanbon(57290) on 2012-10-07 17:06:34 (Show Source):
You can put this solution on YOUR website!Express the function f(x) = 4^5log4(2x + 4) without using logarithms
------
y = 4^[log4(2x+4)^4]
-----
y = (2x+4)^4
=====================
You have to know that loga(a^x) = x
-----
Cheers,
Stan H.
|
Linear_Equations_And_Systems_Word_Problems/662880: i need help with findin the equation of a line ...
lava flows from a volcano at .35mph. It is flowing 6 miles north of a highway near the volcano ..
my guess is that the rise is irrelevant so i'm making that 1 .. so is the line y= 1/6 x + .35 ?
thank you...
1 solutions
Answer 412533 by stanbon(57290) on 2012-10-07 17:00:46 (Show Source):
You can put this solution on YOUR website!i need help with findin the equation of a line ...
lava flows from a volcano at .35mph. It is flowing 6 miles north of a highway near the volcano ..
my guess is that the rise is irrelevant so i'm making that 1 .. so is the line y= 1/6 x + .35 ?
-----------------------
Confusing information.
What are x and y representing?
================================
Cheers,
Stan H.
|
Probability-and-statistics/662706: a committee must have 4 members or 5 members. How many different committees are possible if there are 12 people available?
1 solutions
Answer 412463 by stanbon(57290) on 2012-10-07 12:24:54 (Show Source):
You can put this solution on YOUR website! a committee must have 4 members or 5 members. How many different committees are possible if there are 12 people available?
------
If 4 members the # of committees possible = 12C4 = 495
---
If 5 members the # of committees possible = 12C5 = 792
==============================
Cheers,
Stan H.
|
Probability-and-statistics/662732: Given a level of confidence of 95% and a population standard deviation of 9, answer the following:
(A) What other information is necessary to find the sample size (n)?
(B) Find the Maxium Error of Estimate (E) if n=72. Show all work.
=============================================================================
Here is what I stated doing. Please correct if I am wrong.
a: n= sqrt=9=3
Please Help me!!
1 solutions
Answer 412461 by stanbon(57290) on 2012-10-07 12:18:18 (Show Source):
You can put this solution on YOUR website! Given a level of confidence of 95% and a population standard deviation of 9, answer the following:
(A) What other information is necessary to find the sample size (n)?
n = [z*s/E]^2
You need to know the maximum allowed error.
-----------------------------------
(B) Find the Maximum Error of Estimate (E) if n=72. Show all work.
ME = z*s/sqrt(n) = 1.96*9/sqrt(72) = 2.08
=====================
Cheers,
Stan H.
|
Probability-and-statistics/662733: A sample of 106 golfers showed that their average score on a particular golf course was 87.98 with a standard deviation of 5.39.
Answer each of the following (SHOW ALL WORK and state the FINAL answer to at least TWO Decimal places):
(A) Find the 90% confidence interval of the mean score for all 106 golfers.
(B) Find the 90% confidence interval of the mean score for all golfers if this is a sample of 130 golfers instead of a sample of 106.
(C) Which confidence interval is larger and why?
Thank you for your help!
1 solutions
Answer 412460 by stanbon(57290) on 2012-10-07 12:08:13 (Show Source):
You can put this solution on YOUR website!A sample of 106 golfers showed that their average score on a particular golf course was 87.98 with a standard deviation of 5.39.
Answer each of the following (SHOW ALL WORK and state the FINAL answer to at least TWO Decimal places):
(A) Find the 90% confidence interval of the mean score for all 106 golfers.
x-bar = 87.98
ME = 1.645*5.39/sqrt(106) = 0.8612
--------------------------------------
90% CI: 87.98-0.8612 < u < 87.98+0.8612
=================================================
(B) Find the 90% confidence interval of the mean score for all golfers if this is a sample of 130 golfers instead of a sample of 106.
new ME = 1.645*5.39/sqrt(130) = 0.7776
90% CI: 87.98-0.7776 < u < 87.98+0.7776
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(C) Which confidence interval is larger and why?
The 1st is larger because the sample size is smaller.
Note 2 things:
1st: The CI is ALWAYS 2*ME in width
2nd: Since ME and sqrt(n) are indirectly related, ME gets
smaller when n gets larger.
That makes sense because having a larger sample means you
have more information; so the confidence interval can be tighter.
Cheers,
Stan H.
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Probability-and-statistics/662741: Just haven't Grasped it yet!
Assume that the population of heights of male college students is approximately normally distributed with mean of 73.16 inches and standard deviation of 6.39 inches. A random sample of 70 heights is obtained. SHOW all Work.
(A) Find the mean and standard error of the - distribution.
x
(B) Find P ( - >74.50)
x
I hope you understand that the x has that line above it.
1 solutions
Answer 412459 by stanbon(57290) on 2012-10-07 11:55:48 (Show Source):
You can put this solution on YOUR website!Assume that the population of heights of male college students is approximately normally distributed with mean of 73.16 inches and standard deviation of 6.39 inches.
A random sample of 70 heights is obtained. SHOW all Work.
(A) Find the mean and standard error of the x-bar distribution.
mean of sample means if n = 70: 73.16
std of sample means if n = 70: 6.39/sqrt(70)
--------------------------
(B) Find P (x-bar > 74.50)
z(74.5) = (74.5-73.16)/[6.39/sqrt(70)] = 1.7545
P(x-bar > 74.50) = P(z > 1.7545) = 0.0397
=================
Cheers,
Stan H.
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Probability-and-statistics/662745: The diameters of apples in a certain orchard are normally distributed with a mean of 4.77 inches and a standard deviation of 0.43 inches. Show all work.
(A) What percentage of apples in this orchard is larger than 4.71 inches?
(B) A random sample of 100 apples is gathers and the mean diameter is calculated. What is the probability that the samply that the sample mean is greater than 4.71 inches?
Please, I need help!
1 solutions
Answer 412457 by stanbon(57290) on 2012-10-07 11:47:15 (Show Source):
You can put this solution on YOUR website!The diameters of apples in a certain orchard are normally distributed with a mean of 4.77 inches and a standard deviation of 0.43 inches. Show all work.
(A) What percentage of apples in this orchard is larger than 4.71 inches?
----
z(4.71) = (4.71-4.77)/0.43 = -0.06/0.43 = -0.1395
P(x > 4.71) = P(z > -0.1395) = normalcdf(-0.1395,100) = 0.5555
====================================================================
(B) A random sample of 100 apples is gathered and the mean diameter is calculated. What is the probability that the sample mean is greater than 4.71 inches?
x-bar = 4.71
std for the distribution of sample means when n = 100 = 0.43/sqrt(100)
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z(4.71) = (4.71-4.77)/(0.43/sqrt(100)) = -1.3953
----
P(x-bar > 4.71) = P(z > -1.3953) = normalcdf(-1.3953,100) = 0.9185
===========================
Cheers,
Stan H.
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Probability-and-statistics/662752: A researcher is interested in estimating the noise levels in decibels at area urban hospitals. She wants to be 98% confident that her estimate is correct. If the standard deviation is 5.17, how large a sample is needed to get the desired information to be accurate within 0.62 decibels?
Im off to try and work my other problems..Thanks for your help!
1 solutions
Answer 412455 by stanbon(57290) on 2012-10-07 11:19:19 (Show Source):
You can put this solution on YOUR website!A researcher is interested in estimating the noise levels in decibels at area urban hospitals. She wants to be 98% confident that her estimate is correct. If the standard deviation is 5.17, how large a sample is needed to get the desired information to be accurate within 0.62 decibels?
-----
Since E = zs/sqrt(n)
---
n = [zs/E]^2
---
Your Problem:
n = [2.326*5.17/0.62]^2 = 377 when rounded up
=================
cheers,
Stan H.
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Geometry_proofs/662751: I don't quite understand proofs. I need serious help because I have a geometry test coming up and I have a horrible grade in Geometry could you please help me?
1 solutions
Answer 412454 by stanbon(57290) on 2012-10-07 11:15:11 (Show Source):
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Rate-of-work-word-problems/662754: Pipe A can fill a tank in 14 hours. Pipe B can empty a tank in 10 hours. Miscommunication between Emilio and Stephen causes Emilio to release water into Pipe A at the same time as Stephen opens Pipe B to empty the tank. With both pipes open to the tank, how long does it take to empty the tank?
1 solutions
Answer 412453 by stanbon(57290) on 2012-10-07 11:13:01 (Show Source):
You can put this solution on YOUR website! Pipe A can fill a tank in 14 hours. Pipe B can empty a tank in 10 hours. Miscommunication between Emilio and Stephen causes Emilio to release water into Pipe A at the same time as Stephen opens Pipe B to empty the tank. With both pipes open to the tank, how long does it take to empty the tank?
----
Pipe A rate = 1/14 job/hr
Pipe B rate = 1/10 job/hr
------
Together rate = 1/x job/hr
=================================
Note: The job is to empty the tank, so Pipe A has a negative rate.
Equation:
rate - rate = together rate
-1/14 + 1/10 = 1/x
-10x + 14x = 14*10x
4x = 140x
x= 35 hrs (time to emptythe tank working together)
============
Cheers,
Stan H.
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Money_Word_Problems/662755: If your toral is 4.65 and you have to add 5%of tax .what is the toral including the tax?
1 solutions
Answer 412451 by stanbon(57290) on 2012-10-07 11:05:52 (Show Source):
You can put this solution on YOUR website!If your toral is 4.65 and you have to add 5%of tax .what is the toral including the tax?
Let price after tax be "x":
Equation:
x = 4.65 + 0.05*4.65
x = 4.65 + 0.2325
x = $4.88
===========
Cheers,
Stan H.
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Numbers_Word_Problems/662692: working together, Dan and Leah can mow a lawn in 1hour and 12 min. working alone , Leah can mow the lawn in 1hour less time than it would take Dan. Find the time it takes for each of them working alone?
1 solutions
Answer 412450 by stanbon(57290) on 2012-10-07 11:02:25 (Show Source):
You can put this solution on YOUR website!working together, Dan and Leah can mow a lawn in 1hour and 12 min. working alone , Leah can mow the lawn in 1hour less time than it would take Dan. Find the time it takes for each of them working alone?
-----
Note: 1 hr 12 min = 6/5 hours
------
Dan DATA: time = x hrs/job ; rate = 1/x job/hr
----
Leah DATA: time = x-1 hrs/job ; rate = 1/(x-1) job/hr
-----
Together DATA: time = 6/5 hrs/job ; rate = 5/6 job/hr
----------------
Equation:
rate + rate = together rate
1/x + 1/(x-1) = 5/6
-----
6(x-1) + 6x = 5x(x-1)
-----
6x-6 + 6x = 5x^2 - 5x
5x^2 -17x +6 = 0
x = 3 hrs (Dan's time to do the job alone)
x-1 = 2 hrs (Leah's time to do the job alone)
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Cheers,
Stan H.
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Linear-systems/662625: I need to setup linear equation for the following:A 7 mile cab ride cost $10.20, a 10 mile cab ride is $13.80. Find a linear equation that models a relationship bewtween the cost (c) and the distance (d).
1 solutions
Answer 412393 by stanbon(57290) on 2012-10-06 21:44:51 (Show Source):
You can put this solution on YOUR website!I need to setup linear equation for the following:A 7 mile cab ride cost $10.20, a 10 mile cab ride is $13.80. Find a linear equation that models a relationship bewtween the cost (c) and the distance (d).
----
You have 2 points (7,10,2) and (10,13.8)
0000
slope = (13.8-10.2)/(10-7) = 3.6/3 = 1.2
---
Form: y = mx + b
You know y = 10.2 when x = 7 and m = 1.2
-------
Solve for "b":
10.2 = 1.2*7 + b
b = 1.8
----
Equation:
y = 1.2x + 1.8
===================
Cheers,
Stan H.
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Mixture_Word_Problems/662621: In addition to oil-in-water and water-in-oil emulsions, there are also double emulsions called water-in-oil-in-water (w/o/w or WOW) and oil-in-water-in oil (o/w/o or OWO). WOW’s are more commonly used because food and supplements are usually composed of a continuous aqueous phase. WOW’s have recently been receiving enhanced news coverage due to their ability to potentially reduce the amount of fat in common foods. Based on what you already know about emulsion creation, hypothesize how you think a WOW emulsion is made. Make sure to back up your hypothesis with fact/reason.
1 solutions
Answer 412391 by stanbon(57290) on 2012-10-06 21:36:25 (Show Source):
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Exponents/662615: Raise the quantity in parenthesis to the indicated exponent and simplify the resulting expression. express answer with positive exponents.
[43x^-4y^4/86x^0y^-5]^3
1 solutions
Answer 412387 by stanbon(57290) on 2012-10-06 21:26:51 (Show Source):
You can put this solution on YOUR website!express answer with positive exponents.
[43x^-4y^4/86x^0y^-5]^3
-----
Better Procedure: Work INSIDE the parenthesis before cubing the result.
------------------------
= [(43/86)(1/x^4)(y^9)]^3
------
= [(1/2)(y^9/x^4)]^3
---
= (1/8)(y^27/x^12)
----------------------
cheers,
Stan H.
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