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stanbon answered: 57135 problems
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53010..53039 , 53040..53069 , 53070..53099 , 53100..53129 , 53130..53159 , 53160..53189 , 53190..53219 , 53220..53249 , 53250..53279 , 53280..53309 , 53310..53339 , 53340..53369 , 53370..53399 , 53400..53429 , 53430..53459 , 53460..53489 , 53490..53519 , 53520..53549 , 53550..53579 , 53580..53609 , 53610..53639 , 53640..53669 , 53670..53699 , 53700..53729 , 53730..53759 , 53760..53789 , 53790..53819 , 53820..53849 , 53850..53879 , 53880..53909 , 53910..53939 , 53940..53969 , 53970..53999 , 54000..54029 , 54030..54059 , 54060..54089 , 54090..54119 , 54120..54149 , 54150..54179 , 54180..54209 , 54210..54239 , 54240..54269 , 54270..54299 , 54300..54329 , 54330..54359 , 54360..54389 , 54390..54419 , 54420..54449 , 54450..54479 , 54480..54509 , 54510..54539 , 54540..54569 , 54570..54599 , 54600..54629 , 54630..54659 , 54660..54689 , 54690..54719 , 54720..54749 , 54750..54779 , 54780..54809 , 54810..54839 , 54840..54869 , 54870..54899 , 54900..54929 , 54930..54959 , 54960..54989 , 54990..55019 , 55020..55049 , 55050..55079 , 55080..55109 , 55110..55139 , 55140..55169 , 55170..55199 , 55200..55229 , 55230..55259 , 55260..55289 , 55290..55319 , 55320..55349 , 55350..55379 , 55380..55409 , 55410..55439 , 55440..55469 , 55470..55499 , 55500..55529 , 55530..55559 , 55560..55589 , 55590..55619 , 55620..55649 , 55650..55679 , 55680..55709 , 55710..55739 , 55740..55769 , 55770..55799 , 55800..55829 , 55830..55859 , 55860..55889 , 55890..55919 , 55920..55949 , 55950..55979 , 55980..56009 , 56010..56039 , 56040..56069 , 56070..56099 , 56100..56129 , 56130..56159 , 56160..56189 , 56190..56219 , 56220..56249 , 56250..56279 , 56280..56309 , 56310..56339 , 56340..56369 , 56370..56399 , 56400..56429 , 56430..56459 , 56460..56489 , 56490..56519 , 56520..56549 , 56550..56579 , 56580..56609 , 56610..56639 , 56640..56669 , 56670..56699 , 56700..56729 , 56730..56759 , 56760..56789 , 56790..56819 , 56820..56849 , 56850..56879 , 56880..56909 , 56910..56939 , 56940..56969 , 56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149, >>Next

Functions/103625: Find the domain of the function: f(x)= square root of (2x-8)
...then write your solution in interval notation
1 solutions

Answer 75346 by stanbon(57203) About Me  on 2007-10-11 11:56:57 (Show Source):
You can put this solution on YOUR website!
Find the domain of the function: f(x)= square root of (2x-8)
--------------
2x-8 must be >= zero
--------
2x-8 >=0
2x >=8
x >= 4
--------
Domain is all Real Numbers greater than or equal to four.
[4,inf)
================
Cheers,
Stan H.


Travel_Word_Problems/103623: It takes 175 seconds for Sarah to walk from her house to the store and back. Going there she walks at 3 ft/sec and on the way back at 4 ft/sec. How long did it take her to walk to the store?
1 solutions

Answer 75340 by stanbon(57203) About Me  on 2007-10-11 11:22:26 (Show Source):
You can put this solution on YOUR website!
It takes 175 seconds for Sarah to walk from her house to the store and back. Going there she walks at 3 ft/sec and on the way back at 4 ft/sec. How long did it take her to walk to the store?
--------------------
Sara to store DATA:
Rate = 3 ft/sec ; distance = x ft ; time = x/3 seconds
----------------------
Sara from store DATA:
Rate = 4 ft/sec ; distance = x ft ; time = x/4 seconds
-------------------------
EQUATION:
time to + time from = 175
x/3 + x/4 = 175
Multiply thru by 12 to get rid of the denominators:
4x + 3x = 12*175
7x = 12*175
x = 300 ft (distance to the store)
-------------------------
x/3 = 100 seconds (time to get to the store)
=================
Cheers,
Stan H.


Polynomials-and-rational-expressions/103613: (((8/2m-4 + 3/5m-10=1/5)))
1 solutions

Answer 75335 by stanbon(57203) About Me  on 2007-10-11 11:05:02 (Show Source):
You can put this solution on YOUR website!
8/(2m-4) + 3/(5m-10) = 1/5
Factor the denominators:
8/[2(m-2)] + 3/[5(x-2)] = 1/5
----------------------------------
Least common multiple of the denominators is 10(x-2)
---------------------
Multiply thru by the lcm to get:
8*5 + 3*2 = 2(x-2)
13 + 6 = 2x-4
2x = 23
x = 23/2
===================
Cheers,
Stan H.


expressions/103620: John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. How fast does he need to go to make it to the meeting on time?
1 solutions

Answer 75334 by stanbon(57203) About Me  on 2007-10-11 10:59:29 (Show Source):
You can put this solution on YOUR website!
John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. How fast does he need to go to make it to the meeting on time?
--------------
distance = 28 miles ; time = (1/2) hour
EQUATION:
rate = distance/time = 28/(1/2) = 56 mph
He needs to average 56 mph
=======================
Cheers,
Stan H.


Distributive-associative-commutative-properties/103582: What property is m[t+(-t)]= mt+m(-t) , m[t+(-t)]=m(-t+t), and m[t+(-t)] = [t+(-t)]m
1 solutions

Answer 75332 by stanbon(57203) About Me  on 2007-10-11 10:56:55 (Show Source):
You can put this solution on YOUR website!
What property is m[t+(-t)]= mt+m(-t)
The distributive property
--------------------------------
m[t+(-t)]=m(-t+t)
The commutative property allows you to change t+(-t) to (-t+t)
------------------------
and m[t+(-t)] = [t+(-t)]m
The commutative property allows you to swithc the order of the factors.
-------------
Cheers,
Stan H.


absolute-value/103621: please i was hoping maybe you may help my with this equasion.


(6+2*8-4)
---------
2 i think i got it 8*4 32 =9
--- ---
2 2 thank you
1 solutions

Answer 75331 by stanbon(57203) About Me  on 2007-10-11 10:42:00 (Show Source):
You can put this solution on YOUR website!
(6+2*8-4)
---------
2
======================
= (6+16-4)/2
= (18)/2
= 9
==========
Cheers,
Stan H.


Graphs/103601: What does my teacher mean when she says "Tell how each of the following may be graphed by "shifting" the graph of y=/x/. Then sketch the graph for each."
y = /x + 2/ - 1
y = /x - 3/ - 2
y = /x - 1/ + 2
y = -/x + 2/ + 1
1 solutions

Answer 75325 by stanbon(57203) About Me  on 2007-10-11 09:09:16 (Show Source):
You can put this solution on YOUR website!
"Tell how each of the following may be graphed by "shifting" the graph of y=/x/. Then sketch the graph for each."
-----------------
Graph y = |x|
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2Cabs%28x%29%29
-------------------------------
y = /x + 2/ - 1
The "x+2" moves the graph 2 to the left;
The -1 moves the graph 1 down;
You get:
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2Cabs%28x%2B2%29-1%29
-----------------------
y = /x - 3/ - 2
The "x-3" moves the original graph 3 to the right:
The -2 moves it down 2
You get:
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2Cabs%28x-3%29-2%29
--------------------
y = /x - 1/ + 2
One to the right, then up 2.
-----------------
y = -/x + 2/ + 1
Two to the left, then flip it over the x-axis, then up 1.
=============
Cheers,
Stan H.


Unit_Conversion_Word_Problems/103561: leah travels 22 feet per second on her bicycle. how many miles per hour does she travel.



1 solutions

Answer 75287 by stanbon(57203) About Me  on 2007-10-10 21:29:07 (Show Source):
You can put this solution on YOUR website!
(22 ft/sec)*(3600 sec/1 hr)(1 mile/5280 ft)
-------------
the ft cancel ; the sec cancel; you are left with
= [22*3600*1]/[1*1*5280](miles/hr)
= 15 mph
=================
Cheers,
Stan H.


Linear-equations/103560: Graph the following equation, using the intercept method.
2x+3y=6
1 solutions

Answer 75285 by stanbon(57203) About Me  on 2007-10-10 21:25:05 (Show Source):
You can put this solution on YOUR website!
Graph the following equation, using the intercept method.
2x+3y=6
---------------------
If x=0, y = 2
If y=0, x = 3
-----------------
Plot the two points (0,2), (3,0)
Draw a line thru them.
Graph:
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C%28-2%2F3%29x%2B2%29
====================
Cheers,
Stan H.


Quadratic_Equations/103518: Please help me with this problem.
Your parents are planning to retire in 18 years. They currently have $250,,000, and they would like to have $1,000,000 when they retire. What annual rate of interest would they have to earn on their $250,000 in order to reach their goal, assuming they save no more money?
Someone please help me out, I am confused on this question.
Thanks
Steve
1 solutions

Answer 75283 by stanbon(57203) About Me  on 2007-10-10 21:20:56 (Show Source):
You can put this solution on YOUR website!
Your parents are planning to retire in 18 years. They currently have $250,,000, and they would like to have $1,000,000 when they retire. What annual rate of interest would they have to earn on their $250,000 in order to reach their goal, assuming they save no more money?
---------
That depends on whether they invest the money in a compound interest account
or in a simple interest account.
-----------------------
Formulas:
simple interest: Value = P(1+rt)
compound interest: Value = P(1+r/n)^(nt)
===================
Cheers,
Stan H.


Polynomials-and-rational-expressions/103526: Can you please help me to factor this Polynomial expression.12ax^3+20bx^2+32cx

1 solutions

Answer 75281 by stanbon(57203) About Me  on 2007-10-10 21:16:34 (Show Source):
You can put this solution on YOUR website!
factor this Polynomial expression.12ax^3+20bx^2+32cx
---------=
= 4x(3ax^2 + 5bx +8c)
==========================
Cheers,
Stan H.


Quadratic_Equations/103555: 0.478
using scientific notation
1 solutions

Answer 75280 by stanbon(57203) About Me  on 2007-10-10 21:12:37 (Show Source):
You can put this solution on YOUR website!
0.478
using scientific notation
-------------------------
= 4.78x10^-1
================
Cheers,
Stan H.


Exponents-negative-and-fractional/103534: HELLO,HOW DO YOU CHANGE FROM EXPONENTIAL TO RADICAL FORM AND FROM RADICAL TO EXPONENTIAL. CAN YOU GIVE SOME EXAMPLES? THANKS!!!!
1 solutions

Answer 75279 by stanbon(57203) About Me  on 2007-10-10 21:11:11 (Show Source):
You can put this solution on YOUR website!
5^(2/3) = cube root of 5^2
-------------
7^(1/2) = sqrt(7)
-------------------
10^(-5/2) = 1/[sqrt(10^5)]
==================
Cheers,
Stan H.


Angles/103554: This question is from textbook
the measure of the supplement of an angle is 30 degrees less than 5 times the measure of the compliment find 2/5 the measure of the compliment
1 solutions

Answer 75277 by stanbon(57203) About Me  on 2007-10-10 21:04:13 (Show Source):
You can put this solution on YOUR website!
the measure of the supplement of an angle is 30 degrees less than 5 times the measure of the compliment find 2/5 the measure of the compliment
---------------
Let the angle be "x"; supplement is "180-x"; complement is "90-x"
------------------------
EQUATION:
180-x = 5(90-x)-30
180-x = 450-5x-30
4x = 240
x = 60 degrees
complement = 90-x = 30 degrees
--------------------------
(2/5)30 = 12 degrees
================
Cheers,
Stan H.


Equations/103553: This question is from textbook Texas Algebra 1
3-4q=10q+10
1 solutions

Answer 75274 by stanbon(57203) About Me  on 2007-10-10 20:59:37 (Show Source):
You can put this solution on YOUR website!
3-4q=10q+10
Add 4q to both sides to get:
14q = -13
Divide both sides by 14 to get:
q = -13/14
============
Cheers,
Stan H.


Travel_Word_Problems/103550: A cyclist rides D km at a rate of X km/hr and returns D km at a rate of Y km/hr. Write an expression representing the average rate in terms of X,Y and D. Simplify this expression if you can.
rate=distance/time
Total distance = 2D
rate=Total Distance/Total Time
I can't figure out how to get the total time in terms of X and Y. Can you help?
Thanks!
1 solutions

Answer 75273 by stanbon(57203) About Me  on 2007-10-10 20:57:46 (Show Source):
You can put this solution on YOUR website!
A cyclist rides D km at a rate of X km/hr and returns D km at a rate of Y km/hr. Write an expression representing the average rate in terms of X,Y and D. Simplify this expression if you can.
---------------------
1st ride DATA;
Rate = X km/h ; Distance = D miles ; Time = D/R = D/X hrs
----------------
Return ride DATA:
Rate = Y km/h ; Distance = D miles ; Time = D/R = D/Y hrs
------------------
Average Rate = (total distance) / (total time) = 2D/[D/X + D/Y]
= 2D/[D(Y+X)/XY]
= 2XY/(X+Y)
=================
Cheers,
Stan H.


Equations/103509: 2x^2+6x+9=0 (finding the value of the discriminant) How many real solutions are there of this equation? I have no idea how to do this question. Please help me
1 solutions

Answer 75251 by stanbon(57203) About Me  on 2007-10-10 19:48:05 (Show Source):
You can put this solution on YOUR website!
2x^2+6x+9=0 (finding the value of the discriminant) How many real solutions are there of this equation?
-------------
You have a quadratic equation with a=2, b=6, c=9
-----------
The discriminant is b^2-4ac.
-------------------------
Your Problem:
b^2-4ac = 36-4*2*9 = -36
---------------
Since the result is negative, there are no Real Number
solutions to your problem.
========================
Cheers,
Stan H.


Linear-equations/103507: Find the equation that defines the relations below:
(-3,0) (-2,4) (-1,2) (0,0) (1,4) (2,20)
1 solutions

Answer 75248 by stanbon(57203) About Me  on 2007-10-10 19:44:06 (Show Source):
You can put this solution on YOUR website!
Find the equation that defines the relations below:
(-3,0) (-2,4) (-1,2) (0,0) (1,4) (2,20)
------------------------------
I used the TI calculator Cubic Regression function to find
f(x) = x^3 + 3x^2 as a function that generates these ordered pairs.
==========================
Cheers,
Stan H.


Quadratic_Equations/103489: Can someone offer some assistance to a 49 year old algebra student?
([2a^2b]/[3x^2y])^3 times ([-6xy^2]/[a^3b])^2
1 solutions

Answer 75243 by stanbon(57203) About Me  on 2007-10-10 19:24:55 (Show Source):
You can put this solution on YOUR website!
([2a^2b]/[3x^2y])^3 times ([-6xy^2]/[a^3b])^2
----------------------
=([8a^6b^3] / [27x^6y^3]) * ([36x^2y^4] / [a^6b^2])
Get the ab's together and the xy's together:
=([8a^6b^3] / [a^6b^2]) * ([36x^2y^4] / [27x^6y^3])
Cancel where you can to get:
= (8b)*(4y/3x^4)
= [32by/3x^4]
========================
Cheers,
Stan H.



Exponents-negative-and-fractional/103490: -34 = r/-3

-34 x -3 = r/-3 x -3
102 = r is this correct...Thanks
1 solutions

Answer 75237 by stanbon(57203) About Me  on 2007-10-10 19:10:28 (Show Source):
You can put this solution on YOUR website!
The answer is correct.
Cheers,
Stan H>


Polynomials-and-rational-expressions/103491: A parsec is approximately 3.1x10%5E16 meters. How many meters are there in 8+x+10%5E13 parsecs
1 solutions

Answer 75236 by stanbon(57203) About Me  on 2007-10-10 19:08:00 (Show Source):
You can put this solution on YOUR website!
A parsec is approx 3.1x10^16 meters.How many meters are there in 8x10^13 parsecs
----------------------
(8x10^13 p)*(3.1x10^16 m/p) = (8*3.1x10^29) = 24.8x10^29 = 2.48x10^30 meters
========================
Cheers,
Stan H.


Radicals/103454: express as a mixed radical
a) square root 98
b) -5 square root 32
how do i solve these types of questions
thanks
1 solutions

Answer 75235 by stanbon(57203) About Me  on 2007-10-10 19:01:54 (Show Source):
You can put this solution on YOUR website!
express as a mixed radical
a) square root 98 = sqrt(49*2) = 7sqrt(2)
----------------------------------------------
b) -5 square root 32 = -5sqrt(16*2) = -5*4sqrt(2) = -20sqrt(2)
======================
Cheers,
Stan H.


Rate-of-work-word-problems/103421: Jim can fill a pool carring buckets of water in 30 minutes. Sue can do the same job in 45 minutes, and Tony can do the same job in 1 1/2 hours. How quickly can the three fill the pool together?

I have tried soo many ways, and even my toutor could not remember how to do these problems. Please if any way possible, give a solution and a reasoning of how you got your answer. Thank you.
1 solutions

Answer 75213 by stanbon(57203) About Me  on 2007-10-10 16:03:06 (Show Source):
You can put this solution on YOUR website!
Jim can fill a pool carring buckets of water in 30 minutes. Sue can do the same job in 45 minutes, and Tony can do the same job in 1 1/2 hours. How quickly can the three fill the pool together?
---------------------------------
Jim Rate = 1/30 job/min
Sue Rate = 1/45 job/min
Tony Rate= 1/90 job/min
Together Rate = 1/x job min
--------------------------------
EQUATION:
1/30 + 1/45 + 1/90 = 1/x
3x + 2x + x = = 90
6x = 90
x = 15 min (Time for them to do the job together)
======================================
Cheers,
Stan H.


Graphs/103413: This question is from textbook Algebra and Trigonometry
I have the following problem. I will be honest, it is for homework, so the answer is not in the back of the book. I am just trying to understand how to properly solve it.
y = (x^2 - 4)/2x^4
I tried to simplify this on the website and it gave me y - (x^2 - 4)/2x^4 = 0
I am suppose to state what the intercept is and what it is symmetric to (y-axis, x-axis and/or origin)
Here is what I did.
y = (x^2 - 4)/2x^4
y = (x^2 - 4)/(x^2)(2x^2) - I broke apart the 2x^4
y = -4/2x^2 - I thought the x^2 on the bottom of the fraction cancelled out the top.
After that, I did not know what else to do. I could multiply both sides by 2x^2, but that did not seem to get me anywhere, so I started by making a list of the possible values of x and y.
Here is what I came up with.
x = 2, y = -1/2
x = -2, y = -1/2
x = 1, y = -2
I plotted these and my answer was the following:
1. I could not find an intercept. I don't see where either can equal 0, unless they both equal 0.
2. They would be symmetric to the y-axis.
Am I correct? My main goal is to find out what else to do with the equation. I'm lost.
Thanks for your help in advance.
1 solutions

Answer 75211 by stanbon(57203) About Me  on 2007-10-10 15:59:24 (Show Source):
You can put this solution on YOUR website!
simplify this on the website and it gave me y - (x^2 - 4)/2x^4 = 0
I am suppose to state what the intercept is and what it is symmetric to (y-axis, x-axis and/or origin)
-------------------------------------
y - (x^2 - 4)/2x^4 = 0
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C%28x%5E2-4%29%2F2x%5E4%29%29
---------------
Intercepts:
Since x cannot be zero, no y-intercepts.
If y=0, x=+2 or x=-2 are the x-intercepts.
-----------------------
Symmetry:
f(x)=f(-x) so the function is even and therefore symmetric to the y-axis.
--------------------------
Cheers,
Stan H.


Quadratic_Equations/103417: This question is from textbook
I have these two quadratic equations that I have to solve.
+5x%5E2+%2B+x+%2B+2+=+0+
and
+2x%5E2+%2B+6x+%2B+12+=+0+
I know how to factor and I'm aware of the zero product property...but I'm not sure that regular factoring is the right way to solve this problem. Can you help me out, please?
1 solutions

Answer 75208 by stanbon(57203) About Me  on 2007-10-10 15:46:56 (Show Source):
You can put this solution on YOUR website!
5x^2 + x + 2 = 0
Use the quadratic formula to get:
x = [-1 +- sqrt(1-4*5*2)]/10
x = [-1 +- sqrt(-39)]/10
x = [-1 + isqrt(39)]/10 or x = [-1 - isqrt(39)]/10
----------------------------------
and
2x^2 + 6x + 12 = 0
x^2+3x+6=0
x = [-3 +- sqrt(9-4*1*6)]/2
x = [-3 + isqrt(15)]/2 or x = [-3 -isqrt(15)]/2
--------------------------------------
Cheers,
Stan H.


Polynomials-and-rational-expressions/103419: This question is from textbook Beginning Algebra
Hello. A square has sides of length 3x-2 cm. Express the area of the square as a polynomial.
I think it is supposed to be like this, can you check my work and let me know if it correct, or if not where I went wrong?
(3x-2)^2
=3x^2 - 2(3x)(2)+2^2
=9x-12x+4
Is this correct?
1 solutions

Answer 75206 by stanbon(57203) About Me  on 2007-10-10 15:41:24 (Show Source):
You can put this solution on YOUR website!
(3x-2)^2
=(3x)^2 - 2(3x)(2)+2^2
=9x^2-12x+4
-------------
Cheers,
Stan H.


Square-cubic-other-roots/103418: solve the following quadratic equations by factoring or by any other techniques
(x-1)^2=7
1 solutions

Answer 75205 by stanbon(57203) About Me  on 2007-10-10 15:39:30 (Show Source):
You can put this solution on YOUR website!
(x-1)^2=7
x-1 = sqrt7 or x-1=-sqrt7
x = 1+sqrt7 or x = 1-sqrt7
===================
Cheers,
Stan H.


Polynomials-and-rational-expressions/103378: This question is from textbook Beginning Algebra
Hello. I would like some help not only in finding the answer for this particular problem, but understanding the steps taken in solving the equation. I am not very good at understanding fractions.
(x/2 + 2/3)(2x/3 - 2/5)

Sorry, these are supposed to be fractions.

If you could let me know what your doing step by step, it would better help me
understand, so that I can work on my homework question using the same format.
1 solutions

Answer 75178 by stanbon(57203) About Me  on 2007-10-10 11:50:19 (Show Source):
You can put this solution on YOUR website!
(x/2 + 2/3)(2x/3 - 2/5)
Use FOIL:
F: (x/2)(2x/3) = 2x^2/6 = x^2/3
O: (x/2)(-2/5) = -(1/5)x
I: (2/3)(2x/3) = (4/9)x
L: (2/3)(-2/5) = -4/15
-------------------------
Combine to get:
(1/3)x^2 + [(-1/5)+(4/9)]x - 4/15
= (1/3)x^2 -(11/45)x -(4/15)
=================
Cheers,
Stan H.


Functions/103358: This is coming from the University of Houston online textbook, section 3.6 #39, if that helps anyone else. I'm not sure how to get "fog" when there is a number to multiply by.
Given the functions f (x) = x2 + 2 and
g(x) = 5x − 8 , find:
(a) f (g(1)) (b) g(f (1))
(c) f (g(x)) (d) g(f (x))
(e) f ( f (1)) (f) g(g(1))
(g) f ( f (x)) (h) g(g(x))

1 solutions

Answer 75177 by stanbon(57203) About Me  on 2007-10-10 11:41:39 (Show Source):
You can put this solution on YOUR website!

Given the functions f (x) = x2 + 2 and
g(x) = 5x − 8 , find:
(a) f (g(1)) = f[5*1-8] = f[-3] = (-3)^2+2 = 11
(b) g(f (1)) = g[1+2] = g[3] = 5*3-8 = 7
(c) f (g(x)) = f[5x-8]= (5x-8)^2+2 = 25x^2-80x+66
--------
I'll leave the rest for you.
--------------------------
Cheers,
Stan H.
(d) g(f (x))
(e) f ( f (1))
(f) g(g(1))
(g) f ( f (x))
(h) g(g(x))


Linear-equations/103376: the postive y values of the graph y=-3-4x fall in which quadrant?
1 solutions

Answer 75176 by stanbon(57203) About Me  on 2007-10-10 11:34:46 (Show Source):
You can put this solution on YOUR website!
the postive y values of the graph y=-3-4x fall in which quadrant?
Plot a couple of points; Draw the graph of the line and see where
the y-values are positive.
-------------
Graph:
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C-4x-3%29
=================
Looks like the line has positive y-values in the 2nd quadrant.
=================
Cheers,
Stan H.


Money_Word_Problems/103368: Can someone please help me with the following two questions?
1. Mary just deposited $33,000 in an account paying 10% interest. She plans to leave the money in this account for seven years. How much will she have in the account at the end of the seventh year?
I got 64,307.66. Is this correct?
2. Mary and Joe would like to save up $10,000 by the end of three years from now to buy new furniture for their home. They currently have $2500 in a savings account set aside for the furniture. They would like to make equal year end deposits to this savings account to pay for the furniture when they purchase it three years from now. Assuming that this account pays 8% interest, how much should the year end payments be?
I cannot find a formula to solve this question. Can someone please help me? Greatly appreciated.
1 solutions

Answer 75175 by stanbon(57203) About Me  on 2007-10-10 11:31:33 (Show Source):
You can put this solution on YOUR website!
1. Mary just deposited $33,000 in an account paying 10% interest. She plans to leave the money in this account for seven years. How much will she have in the account at the end of the seventh year?
I got 64,307.66. Is this correct?
-----------------
Since did not specify compounding I guess the money is invested at 10%
simple interest!? Is that right?
A = P(1+rt) = 33000(1+0.01*7) = 33000*(1+0.21) = $39930.00
------------------------------------------
2. Mary and Joe would like to save up $10,000 by the end of three years from now to buy new furniture for their home. They currently have $2500 in a savings account set aside for the furniture. They would like to make equal year end deposits to this savings account to pay for the furniture when they purchase it three years from now. Assuming that this account pays 8% interest, how much should the year end payments be?
I cannot find a formula to solve this question. Can someone please help me?
-------------
Formula: Bn=A(1+i)^n - (P/i)[(1+i)^n - 1]
Bn is the desired balance = $10000
A is the current amount = 2500
i is the interest rate = 0.08
n is # of years = 3
---------
You need to solve for P = periodic payment
----------
Cheers,
stan H.