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Recent problems solved by 'stanbon'
stanbon answered: 57239 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 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53010..53039 , 53040..53069 , 53070..53099 , 53100..53129 , 53130..53159 , 53160..53189 , 53190..53219 , 53220..53249 , 53250..53279 , 53280..53309 , 53310..53339 , 53340..53369 , 53370..53399 , 53400..53429 , 53430..53459 , 53460..53489 , 53490..53519 , 53520..53549 , 53550..53579 , 53580..53609 , 53610..53639 , 53640..53669 , 53670..53699 , 53700..53729 , 53730..53759 , 53760..53789 , 53790..53819 , 53820..53849 , 53850..53879 , 53880..53909 , 53910..53939 , 53940..53969 , 53970..53999 , 54000..54029 , 54030..54059 , 54060..54089 , 54090..54119 , 54120..54149 , 54150..54179 , 54180..54209 , 54210..54239 , 54240..54269 , 54270..54299 , 54300..54329 , 54330..54359 , 54360..54389 , 54390..54419 , 54420..54449 , 54450..54479 , 54480..54509 , 54510..54539 , 54540..54569 , 54570..54599 , 54600..54629 , 54630..54659 , 54660..54689 , 54690..54719 , 54720..54749 , 54750..54779 , 54780..54809 , 54810..54839 , 54840..54869 , 54870..54899 , 54900..54929 , 54930..54959 , 54960..54989 , 54990..55019 , 55020..55049 , 55050..55079 , 55080..55109 , 55110..55139 , 55140..55169 , 55170..55199 , 55200..55229 , 55230..55259 , 55260..55289 , 55290..55319 , 55320..55349 , 55350..55379 , 55380..55409 , 55410..55439 , 55440..55469 , 55470..55499 , 55500..55529 , 55530..55559 , 55560..55589 , 55590..55619 , 55620..55649 , 55650..55679 , 55680..55709 , 55710..55739 , 55740..55769 , 55770..55799 , 55800..55829 , 55830..55859 , 55860..55889 , 55890..55919 , 55920..55949 , 55950..55979 , 55980..56009 , 56010..56039 , 56040..56069 , 56070..56099 , 56100..56129 , 56130..56159 , 56160..56189 , 56190..56219 , 56220..56249 , 56250..56279 , 56280..56309 , 56310..56339 , 56340..56369 , 56370..56399 , 56400..56429 , 56430..56459 , 56460..56489 , 56490..56519 , 56520..56549 , 56550..56579 , 56580..56609 , 56610..56639 , 56640..56669 , 56670..56699 , 56700..56729 , 56730..56759 , 56760..56789 , 56790..56819 , 56820..56849 , 56850..56879 , 56880..56909 , 56910..56939 , 56940..56969 , 56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179 , 57180..57209 , 57210..57239, >>NextRadicals/132133: I really need help with what I am doing. Here is an example : 3 square root 63 time square root 4
I am really confused. Help is need immediately! Thank you! 1 solutions
Answer 96518 by stanbon(57307) on 2008-03-14 21:16:56 (Show Source):
You can put this solution on YOUR website!3 square root 63 time square root 4
----------------------------
[3sqrt(63)] * [sqrt(4)]
= 3*sqrt(9*7)] * [2]
= 9sqrt(7) * 2
= 18sqrt(7)
===================
Cheers,
san H.
|
Linear-equations/132099: I am so clueless when it comes to Algebra. How could i solve this?
y = -2x – 9
x y
-2
-1
0
1
2
1 solutions
Answer 96484 by stanbon(57307) on 2008-03-14 18:49:30 (Show Source):
You can put this solution on YOUR website!y = -2x – 9
x ..... y=-2x-9
---------------------------
-2..... y=-2*-2-9 = -5
-1..... y=-2*-1-9 = -7
0 ..... y=-2*0-9 = -9
1 ..... y=-2*1-9 = -11
----------------------------
Cheers,
Stan H.
|
Linear-equations/132105: . Find the slope of the line that passes through the points (2, 3) and (5, 8).
1 solutions
Answer 96479 by stanbon(57307) on 2008-03-14 18:29:28 (Show Source):
You can put this solution on YOUR website!Find the slope of the line that passes through the points (2, 3) and (5, 8).
---------------
slope = [change in y] / [change in x] (8-3)/(5-2) = 5/3
===============================
Cheers,
Stan H.
|
Pythagorean-theorem/132114: I am trying to do my homework and do not understand the statement below.
We can use the Pythagorean Theorem to solve problems that involve right triangles. Provide an example of a day-to-day situation that involves right triangles and the use of the theorem. 1 solutions
Answer 96477 by stanbon(57307) on 2008-03-14 18:05:27 (Show Source):
You can put this solution on YOUR website!We can use the Pythagorean Theorem to solve problems that involve right triangles. Provide an example of a day-to-day situation that involves right triangles and the use of the theorem.
----------------------------
If it is 90 ft. from home plate to 1st base
and 90 ft from 1st base to 2nd base how far
does the catcher have to throw a baseball
to stop a player trying to steal 2nd base?
-----------------
EQUATION:
(throw)^2 = 90^2 + 90^2
throw = sqrt(2*90^2)
throw = 90sqrt(2)
throw is approximately 127.28 ft.
==================
Cheers,
Stan H.
|
Quadratic_Equations/132115: I have no idea how to do the following please help!
Suppose that a market research company finds that a price of p=$20, they would sell x=42 tiles each month. If they lower the price to p=$10, then more people would purchase teh tile, and they can expect to sell x=52 tiles in a month's time. Find the equation of the line for the demand equation. Write your answer in the form p=mx+b.
(write the equation using two points in the form(x,p)
1 solutions
Answer 96476 by stanbon(57307) on 2008-03-14 17:54:08 (Show Source):
You can put this solution on YOUR website!Suppose that a market research company finds that a price of p=$20, they would sell x=42 tiles each month. If they lower the price to p=$10, then more people would purchase teh tile, and they can expect to sell x=52 tiles in a month's time. Find the equation of the line for the demand equation. Write your answer in the form p=mx+b.
(write the equation using two points in the form (x,p)
-----------------------------------------------------------
You have two points: (42,20), (52,10)
---------------
slope = -10/10 = -1
-------
Form: p = mx+b
You know p, m, and x; solve for "b".
10 = -1*52+b
b = 62
EQUATION:
p(x) = -x + 62
--------------------
Cheers,
Stan H.
|
Numbers_Word_Problems/132116: This question is from textbook elementary algebra
three times the largest of three consecutive odd integers is three less than twice the sum of the other two integers. find the integers. 1 solutions
Answer 96474 by stanbon(57307) on 2008-03-14 17:47:51 (Show Source):
You can put this solution on YOUR website!three times the largest of three consecutive odd integers is three less than twice the sum of the other two integers. find the integers.
---------------------
1st: 2x+1
2nd: 2x+3
3rd: 2x+5
---------------
EQUATION:
3(2x+5)= 2(2x+1+2x+3)-3
6x+15 = 2(4x+4)+3
6x+15 = 8x+11
2x= 4
x = 2
-----------
1st: 5
2nd: 7
3rd: 9
============
Cheers,
Stan H.
|
test/132107: Mark is 10 years younger then Larry.Larry's age in 8 years will exceed twice Mark's age 3 years ago by 4 years.How old is each now? 1 solutions
Answer 96463 by stanbon(57307) on 2008-03-14 15:50:15 (Show Source):
You can put this solution on YOUR website!Mark is 10 years younger then Larry.
Larry's age in 8 years will exceed
twice Mark's age 3 years ago by 4 years.
How old is each now?
--------------------------
NOW DATA:
Let Larry's age be "x": Mark's age is "x-10"
----------
In 8 years years Larry will be x+8
x-13 (Mark;s age three years ago)
--------------
EQUATION:
x+8 = 2(x-13)+4
x+8 = 2x-22
x = 30 (Larry's age now)
x-10 = 20 (Mark's age now)
================
Cheers,
Stan H.
|
Quadratic_Equations/132081: This is not from a textbook.
Write a quadratic equation in the variable x having the given numbers as solutions. Type the equation in standard form, ax^2 + bx + c = 0
solution: 7, only solution
Equation is 0 = ___________
I'm just starting to be able to understand how to compute these kind of equations so to do it backwards is confusing me totally. 1 solutions
Answer 96456 by stanbon(57307) on 2008-03-14 14:37:14 (Show Source):
You can put this solution on YOUR website!If 7 is the only solution, it has multiplicity two.
Therefore it has two factors that look like (x-7)
EQUATION:
y = (x-7)^2 = x^2-14x+49
=============
Cheers,
Stan H.
|
Equations/132086: A manufacturer of tennis rackets finds that the total cost C(x) (in dollars) of manufacturing x rackets/day is given by Each racket can be sold at a price of p dollars, where p is related to x by the demand equation If all rackets that are manufactured can be sold, find the daily level of production that will yield a maximum profit for the manufacturer.
Can you help please please please please : ) THANK YOU! ! ! ! 1 solutions
Answer 96455 by stanbon(57307) on 2008-03-14 14:34:42 (Show Source):
|
Probability-and-statistics/132069: There are 20 questions in a multiple-choice test. Each question has five choices and one correct answer out of these five choices. A student did not study. He/she answers the questions at random What are the probabilities that he/she makes (i) more than 10-answers right? (ii) exatly eight right? And (iii) at most 7 right? 1 solutions
Answer 96450 by stanbon(57307) on 2008-03-14 12:23:47 (Show Source):
You can put this solution on YOUR website!There are 20 questions in a multiple-choice test. Each question has five choices and one correct answer out of these five choices. A student did not study. He/she answers the questions at random What are the probabilities that he/she makes
(i) P(more than 10-answers right) = 1-binomcdf(20,(1/5),10) = 0.0005634
(ii) P(exactly eight right) = binompdf(20,5^-1,8) = 0.0222...
(iii) P(at most 7 right) = binomcdf(20,5^-1,7) = 0.9679..
Cheers,
Stan H.
|
Polynomials-and-rational-expressions/132040: Okay, second time asking for help with this particular question.
2x+1/x^2-16 [+] x^2-6x-7/x^2-11x+28
I placed the + in [] just so you could tell the two fraction apart, it does not mean anything. 1 solutions
Answer 96414 by stanbon(57307) on 2008-03-13 22:17:56 (Show Source):
You can put this solution on YOUR website!2x+1/x^2-16 [+] x^2-6x-7/x^2-11x+28
-------------------------------------
Factor where you can:
[(2x+1)/(x-4)(x+4)] + [(x-7)(x+1)/(x-4)(x-7)]
----------------------------
Least common denominator: (x-4)(x+4)(x-7)
--------------------------
Rewrite each fraction with the lcm as its denominator.
[(2x+1)(x-7)/lcm] + [(x-7)(x+1)(x+4)]/lcm
------------------------------
Simplify:
[2x^2-13x-7+(x-7)(x^2+5x+4)]/lcm
---------
[2x^2-13x-7+x^3+5x^2-7x^2+4x-35x-28]/lcm
[x^3-44x-35]/lcm
==================
Cheers,
Stan H.
|
Length-and-distance/132035: Segment AD has a midpoint B, BD has a midpoint C. If A has coordinates (-5, 4) and C has coordinates (10, 11), what are the coordinates of B and D? 1 solutions
Answer 96411 by stanbon(57307) on 2008-03-13 22:04:43 (Show Source):
You can put this solution on YOUR website!Segment AD has a midpoint B, BD has a midpoint C. If A has coordinates (-5, 4) and C has coordinates (10, 11), what are the coordinates of B and D?
---------------------------
That's a pretty messy problem, but doable.
----------------------------------------------
Draw the picture so you can follow what is happening.
----------------
Label point D as (a,b)
Label point B as (x,y)
-------------------------
EQUATIONS:
Since C is the midpoint of BD
x+a = 2*10
y+b = 2*11
-----------------
Since B is the midpoint of AD
a-5=2x
b+4=2y
-------------------
Look at these two equations:
x+a = 20
2x-a = -5
Add them to solve for x:
3x = 15
x = 5
Substitute to solve for "a":
5+a=20
a= 15
---------------------
Look at these two equations:
y+b = 22
2y-b=4
Add to solve for y:
3y = 26
y = 26/3
Substitute to solve for "b":
(26/3)+b = (66/3)
b = 40/3
------------------------
Coordinates:
(a,b) = (15,40/3)
(x,y) = (5,26/3)
===============================
Cheers,
Stan H.
|
Linear-systems/132032: This question is from textbook
Comparing Methods:
Solve the linear system using all three methods on page 418.
3x - y = 3
-x + y = 3
I have the answer (3,6)
But I don't understand how to graph it.
Which is the first method to use, graphing. 1 solutions
Answer 96409 by stanbon(57307) on 2008-03-13 21:49:05 (Show Source):
You can put this solution on YOUR website!3x - y = 3
-x + y = 3
-----------
Solve each equation for "y":
y = 3x-3
y = x+3
--------------
Graph y=3x-3
Let x=0,then y=-3, giving you point (0,-3)
Let x=1, then y= 0, giving you point (1,0)
Plot those two points and draw a line thru them.
---------------------
Graph y = x+3
Let x=0, then y = 3 giving you point (0,3)
Let x=1, then y = 4 giving you point (1,4)
Plot those two points and draw a line thru them.
---------------------

========================
Cheers,
Stan H.
|
Linear_Equations_And_Systems_Word_Problems/132027: This question is from textbook Holt Algebra 1
I am working out of the Holt Algebra 1 text book. This problem is from a work- sheet that our teacher handed out.
Find the two digit number whose tens digit is 3 less than the unit digit. The orginal number is 6 more than 4 times the sum of the digits.
Thanks 1 solutions
Answer 96407 by stanbon(57307) on 2008-03-13 21:42:43 (Show Source):
You can put this solution on YOUR website!Find the two digit number whose tens digit is 3 less than the unit digit. The orginal number is 6 more than 4 times the sum of the digits
-----------------------
Every 2-digit number can be written as 10t+u where t is the tens and u is
the units digit.
----------------
EQUATIONS:
t = u-3
10t+u = 4(t+u)+6
---------------------
Rearranging the equations:
t = u-3
6t-3u=6
----------
Simplifying:
t = u-3
2t-u = 2
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Substitute to solve for "u":
2(u-3)-u = 2
u-6 = 2
u = 8
------------
Substitute to solve for "t":
t = 8-3 = 5
--------------------
Original Number: 58
==========================
Cheers,
Stan H.
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Inverses/132013: Will you please help me with this??
The amount of candy shared by the class varies inversely with the number of students in the class. If there are 120 pieces of candy, how much would each student receive in a class of 30? 1 solutions
Answer 96397 by stanbon(57307) on 2008-03-13 21:03:13 (Show Source):
You can put this solution on YOUR website!The amount of candy shared by the class varies inversely with the number of students in the class. If there are 120 pieces of candy, how much would each student receive in a class of 30?
-------------------------
Comment: Your posted problem is incomplete
The general equation is c = k/n. But you need
to be given a value fo c and for n so you can
find k, which is the constant of proportionality.
-------------
Look again at the problem in your book.
Cheers,
Stan H.
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Linear-systems/132010: This question is from textbook Algebra 1
Your math teacher tells you that next week's test is worth 100 points and contains 38 problems. Each problem is worh either 5 points or 2 points. Because you are studying systems of linear equations, your teacher says that for extra credit you can figure out how many problems of each value are on the test. How many of each value are there? 1 solutions
Answer 96395 by stanbon(57307) on 2008-03-13 20:58:27 (Show Source):
You can put this solution on YOUR website!Your math teacher tells you that next week's test is worth 100 points and contains 38 problems. Each problem is worth either 5 points or 2 points. Because you are studying systems of linear equations, your teacher says that for extra credit you can figure out how many problems of each value are on the test. How many of each value are there?
--------------
Let # of 5 point questions be "x" ; # of points available is 5x
-----------
# of 2 point questions is "38-x" ; # of points available is 2(38-x)=76-2x
--------------
EQUATION:
5x + 76 -2x = 100
3x = 24
x = 8 (# of 5-point questions)
38-x = 30 (# of 2-point questions)
===============
Cheers,
Stan H.
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Volume/132009: If you are asked to give the volume of a rectangular prism. But you are only given the height and length. How do you find the width? 1 solutions
Answer 96384 by stanbon(57307) on 2008-03-13 20:26:14 (Show Source):
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Quadratic_Equations/131997: Find the standard form of the equation for the parabola having a vertex (-3,6) that contains the origin 1 solutions
Answer 96382 by stanbon(57307) on 2008-03-13 20:23:31 (Show Source):
You can put this solution on YOUR website!Find the standard form of the equation for the parabola having a vertex (-3,6) that contains the origin.
------------
Form: y = ax^2+bx+c
Using (0,0) you find 0 = a*0+b*0+c
So c = 0
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Foem y = ax^2+bx
Using (-3,6) you find 6 = a(-3)^2+b(-3)
6 = 9a -3b
2 = 3a-b
b = 3a-2
Let a=1, then b = 3*1-2 = 1
------------------------------
So a=1,b=1,c=0
EQUATION:
y = x^2+x
==================
Cheers,
Stan H.
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Rational-functions/131993: Can you help me solve this problem?
(2/5w-10)-(3/2w-4)
I factored, found the LCD and arrived at the answer -11/10(w-2)
Is this correct?
Thanks for your help! 1 solutions
Answer 96373 by stanbon(57307) on 2008-03-13 19:47:44 (Show Source):
You can put this solution on YOUR website!(2/5w-10)-(3/2w-4)
I factored, found the LCD and arrived at the answer -11/10(w-2)
Is this correct?
----------------------------------
= (2/5)w - (3/2)w -10 + 4
----------------------
[(4-15)/10]w -6
= -(11/10)w -6
=======================
Cheers,
Stan H.
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Miscellaneous_Word_Problems/131981: This question is from textbook Algebra Structure and Method
I have been struggling with this math problem for awhile now and I was wondering if anyone could help me? I would deeply appreciate it!! Please and Thank you!!
Multiplying Polynomials
Solve.
(2n-3)(n^2+3n-2)=(n-1)(2n^2+5n-4) 1 solutions
Answer 96367 by stanbon(57307) on 2008-03-13 19:26:54 (Show Source):
You can put this solution on YOUR website!(2n-3)(n^2+3n-2)=(n-1)(2n^2+5n-4)
2n^3+6n^2-2n-3n^2-9n+6 = 2n^3+5n^2-4n-2n^2-5n+4
2n^3 + 3n^2 - 11n + 6 = 2n^3 + 3n^2 -9n + 4
2n = 2
n = 1
==========
Cheers,
Stan H.
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Unit_Conversion_Word_Problems/131982: The mass of 1 cubic meter of a substance is 800 kilograms under certain
conditions. What is the volume, in cubic centimeters, of 1 gram of this
substance under these conditions? (1 kilogram=1000 grams and 1 cubic meter
= 1,000,000 cubic centimeters) 1 solutions
Answer 96363 by stanbon(57307) on 2008-03-13 19:01:25 (Show Source):
You can put this solution on YOUR website!): The mass of 1 cubic meter of a substance is 800 kilograms under certain
conditions. What is the volume, in cubic centimeters, of 1 gram of this
substance under these conditions? (1 kilogram=1000 grams and 1 cubic meter
= 1,000,000 cubic centimeters)
---------------
1 cubic meter of a substance is 800 kilograms
1 cu meter = 800 kg
1 cu meter = 800,000 grams
1 gram = 1 cu meter / 800,000
--------------
1 cu meter = (100cm)^3 = 1,000,000 cu cm
--------------
1 gram = 1,000,000 cu cm /800,000
1 gram = 1.25 cu cm
==========================
Cheers,
Stan H.
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Miscellaneous_Word_Problems/131969: I really need help with this word problem. I've been working on it for 2 hours and keep getting wrong answers.
Problem
A cellular phone co. offers a contract for which cost C in dollars, of t minutes of telephoning is given by C=0.25(t-400)+64.95, where it is assumed that t>400 minutes. What times will keep costs between $105.20 and $146.45, the telephoning times must be between ____ minutes and ______ minutes.
1 solutions
Answer 96360 by stanbon(57307) on 2008-03-13 18:08:13 (Show Source):
You can put this solution on YOUR website!A cellular phone co. offers a contract for which cost C in dollars, of t minutes of telephoning is given by C=0.25(t-400)+64.95, where it is assumed that t>400 minutes. What times will keep costs between $105.20 and $146.45, the telephoning times must be between 561 minutes and 726__ minutes.
---------------------------------
C(t) = 0.25(t-400)+64.95
-----------------------------
Solve the following :
105.20 < 0.25(t-400)+64.95 < 146.45
Subtract 64.95 along the line to get:
40.25 < 0.25(t-400) < 81.5
Divide thru by 0.25 to get:
161 < (t-400) <326
Add 400 along the line to get:
561 < t < 726
==================
Cheers,
Stan H.
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Expressions-with-variables/131768: Hello,
My 8th grader is stuck on problems involving systems of equations and inequality, or substition. Can you please explain the following problem?
How to find X and Y?
Y=x+3
Y=2x+4 1 solutions
Answer 96359 by stanbon(57307) on 2008-03-13 17:58:40 (Show Source):
You can put this solution on YOUR website!Y=x+3
Y=2x+4
------------------------
Substitute to solve for "x":
x+3 = 2x+4
Subtract x from both sides.
Subtract 4 from both sides.
x = -1
--------------
Substitute to solve for "y":
y = -1+3 = 2
----------------
Solution: (-1,2)
====================
Cheers,
Stan H.
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