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Recent problems solved by 'stanbon'

stanbon answered: 57274 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 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56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179 , 57180..57209 , 57210..57239 , 57240..57269 , 57270..57299, >>Next

Trigonometry-basics/153272: This is what my paper says... Find each angle measure to the nearest degree. 1) tan A=2.0503 1 solutions Answer 112804 by stanbon(57347)   on 2008-08-24 21:57:34 (Show Source): You can put this solution on YOUR website! Find each angle measure to the nearest degree. 1) tan A=2.0503 ----------------------- Take the inverse-tangent of both sides to get: A = 63.999958.. degrees ============================ Cheers, Stan H.

Graphs/153256: three fourths the number b is 96. 1 solutions Answer 112793 by stanbon(57347)   on 2008-08-24 20:19:58 (Show Source): You can put this solution on YOUR website! three fourths the number b is 96 ------------------------------ (3/4)b = 96 Multiply both sides by (4/3) to get: b = (4/3)96 b = 4*32 b = 128 ============== Cheers, Stan H.

Linear-equations/153231: I need help understanding how to determine this equation. I am trying to help my daughter with her worksheet, of course the school has not assigned text books yet (I asked for that also). Month Average numbe of nightly visitors Jan 32 Feb 25 Mar 12 Apr 17 May 10 Use the scatter plot that you made to find an equation that models the average number of nightly visitors as a function of the number of months since January. 1 solutions Answer 112790 by stanbon(57347)   on 2008-08-24 20:14:48 (Show Source): You can put this solution on YOUR website! Month/ Months after January/Average number of nightly visitors Jan............ 0.......................32 Feb.............1...................... 25 Mar.............2...................... 12 Apr.............3...................... 17 May.............4...................... 10 Use the scatter plot that you made to find an equation that models the average number of nightly visitors as a function of the number of months since January. ------------------------ I entered the pairs of numbers into a TI-83 calculator; graphed a scatter plot; then ran several Regression programs on the data to find the best fit. ------------------------ The best fit was the quartic equation y = -2.25x^4+175x^3-39.75x^2+17.5x+32- Its r-value is 1; the r-values for linearReg, quadreg, cubreg are all less than 1. ====================== Cheers, Stan H.

Rational-functions/153251: 4x^2/3-27x^1/3-7=0 1 solutions Answer 112788 by stanbon(57347)   on 2008-08-24 19:37:20 (Show Source): You can put this solution on YOUR website! 4x^2/3-27x^1/3-7=0 ------------------------------------ Let x^(1/3) = w --------------------- Substitute to get: 4w^2 - 27w - 7 = 0 Factor: 4w^2-28w+w-7 = 0 4w(w-7)+(w-7) = 0 (w-7)(4w+1) = 0 w = 7 or w = -1/4 ------------- Substitute to get: x^(1/3) = 7 or x^(1/3) = -1/4 x = 7^3 = 343 or x = -1/64 ============================= Cheers, Stan H.

Exponential-and-logarithmic-functions/153247: (12xy)^0(x^2y^4)^5 1 solutions Answer 112786 by stanbon(57347)   on 2008-08-24 19:21:16 (Show Source): You can put this solution on YOUR website! (12xy)^0(x^2y^4)^5 = 1 * x^10 y^20 = x^10 y^20 ========================== Cheers, Stan H.

Reduction-of-unit-multipliers/153248: I need some help on unit multipliers.... the question is 30cm ( )( )= kilo use two unit multipliers to convert to kilometers 1 solutions Answer 112784 by stanbon(57347)   on 2008-08-24 19:16:31 (Show Source): You can put this solution on YOUR website! 30cm (1m /100cm)(1km/1000m) = (30/10^5) = (3/10^4) = 0.0003 km ===================== Cheers, Stan H.

Exponential-and-logarithmic-functions/153249: 4x^8/6X^-5 1 solutions Answer 112781 by stanbon(57347)   on 2008-08-24 19:03:40 (Show Source): You can put this solution on YOUR website! 4x^8/6X^-5 = (2/3)x^13 ==================== Cheers, Stan H.

Reduction-of-unit-multipliers/153242: perform the following conversions using unit factoring. 1. 500mL= L 2. 25cg= g 3. 400mg= kg 1 solutions Answer 112780 by stanbon(57347)   on 2008-08-24 18:58:53 (Show Source): You can put this solution on YOUR website! perform the following conversions using unit factoring. 1. 500mL(L/1000mL) = (1/2)L 2. 25cg(g/100cg) = (1/4)g 3. 400mg(g/1000mg)(kg/1000g)= [400/10^6] = (4/10000) = (1/2500)kg ================= Cheers, Stan H.

Equations/153243: HELP!!! Solve the equation algebraically by factoring or using quadratic formula; x squared - 2x -3 = 0 very confused!!!!! 1 solutions Answer 112777 by stanbon(57347)   on 2008-08-24 18:38:12 (Show Source): You can put this solution on YOUR website! Solve the equation algebraically by factoring or using quadratic formula; x squared - 2x -3 = 0 --------------- x^2-2x-3 = 0 (x-3)(x+1) = 0 x = 3 or x=-1 ================== Cheers, Stan H.

Quadratic_Equations/153236: The manager at Cream of the Crop bought a load of watermelons for $200. She priced the melons so that she would make $1.50 profit for each melon. When all but 30 had been sold, the manager had recovered her initial investment. How many did she buy originally? 1 solutions Answer 112776 by stanbon(57347)   on 2008-08-24 18:33:19 (Show Source): You can put this solution on YOUR website! The manager at Cream of the Crop bought a load of watermelons for $200. She priced the melons so that she would make $1.50 profit for each melon. When all but 30 had been sold, the manager had recovered her initial investment. How many did she buy originally? ------------------------------ Let the original number bought be "x". ---------------- Average cost of each melon was $(200/x) ---------------- She priced the melons so that she would make $1.50 profit for each melon. Let her price per melon be "p". EQUATION: p = (200/x) + 1.5 ----------------------- When all but 30 had been sold, the manager had recovered her initial investment. EQUATION: p(x-30) = 200 ------------------------ Rearrange the two equations: p = (200/x) + 1.5 p = 200/(x-30) --------------------- Substitute to solve for "x". 200/(x-30) = (200/x) + 1.5 Multiply thru by x(x-30) to get: 200x = 200(x-30) + 1.5x(x-30) 6000 = 1.5x^2 - 45x x^2 - 30x -4000 = 0 (x- 80)(x+50) = 0 Positive solution x = 80 (original number of melons) ===================== Cheers, Stan H.

Linear_Equations_And_Systems_Word_Problems/153219: At its Grand Opening, the Guthrie Market distributed tow different types of souveniers. One type cost 20cents each, andt he other type cost 25 cents each. One thousand souveniers were distributed in all. If the cost of these souveniers was $220. how many of each type were distributed? 1 solutions Answer 112752 by stanbon(57347)   on 2008-08-24 15:50:00 (Show Source): You can put this solution on YOUR website! At its Grand Opening, the Guthrie Market distributed two different types of souveniers. ---------------------------------------- One type cost 20cents each, and the other type cost 25 cents each. Value equation: 20x + 25y = 22000 ---------------------------------------- One thousand souveniers were distributed in all. If the cost of these souveniers was $220. how many of each type were distributed? ---------------------------- Quantity equation: x + y = 1000 ------------------------------------ System: 20x + 25y = 22000 x + y = 1000 ---------------------- Multiply the 2nd equation by 20 to get: 20x + 25y = 22000 20x + 20y = 20000 -------------------- Subtract 2nd from 1st to get: 5y = 2000 y = 400 (# of 25 cent souvenirs) -------------- Since x+y = 1000, x = 600 (# of 20 cent souvenirs) ======================== Cheers, Stan H.

Angles/153222: what angle is formed by two right angles 1 solutions Answer 112750 by stanbon(57347)   on 2008-08-24 15:41:00 (Show Source): You can put this solution on YOUR website! A straight angle of 180 degrees. Cheers, Stan H.

Linear-equations/153220: Find the solution of the system; type and ordered pair. 9x-2y=-47 8x+48=y Please talk me through this. I have quite a few examples of how to solve it, it's just that instead of an addition sign theres a subtraction sign and it's confusing my dumb little mind. 1 solutions Answer 112749 by stanbon(57347)   on 2008-08-24 15:39:16 (Show Source): You can put this solution on YOUR website! 9x-2y=-47 8x+48=y ------------ Rearrange to use elimination: 9x - 2y = -47 8x - y = -48 ----------------- Now the objective is to have the same number of x's or y's in both equations. So, multiply the 2nd equation by 2 and rewrite the system. ----------------- 9x - 2y = -47 16x -2y = -96 ============== Subtract the 1st equation from the 2nd to get: 7x = -49 x = -7 ----------------- Substitute into 8x+48=y to solve for "y": y = 8*-7 + 48 y = -56 + 48 y = -7 ------------- Final solution: (-7,-7) =============== Cheers, Stan H.

Angles/153211: Find the surface area and volume of a sphere with a radius of 14cm. Thanks, Pat 1 solutions Answer 112740 by stanbon(57347)   on 2008-08-24 14:19:38 (Show Source): You can put this solution on YOUR website! Find the surface area and volume of a sphere with a radius of 14cm. -------------------- Surface area = 4(pi)r^2 Your surface area = 4(pi)(14cm)^2 = 2463.00864...cm^2 ------------------- Volume= (4/3) (pi)r^3 Your Volume = (4/3) (pi) (14cm)^3 = 11494.04032... cm^3 ================= Cheers, Stan H.

Polynomials-and-rational-expressions/153195: simplify: a^4 times a^6 divided by -a^3 thanks 1 solutions Answer 112737 by stanbon(57347)   on 2008-08-24 14:14:09 (Show Source): You can put this solution on YOUR website! simplify: a^4 times a^6 divided by -a^3 ---------------------------------- [a^4 * a^6] / -a^3 = [a^10] / -a^3 = -a^7 =========== Cheers, Stan H.

Polynomials-and-rational-expressions/153197: simpify: -4[5x-6(-5+x)] 1 solutions Answer 112735 by stanbon(57347)   on 2008-08-24 14:12:05 (Show Source): You can put this solution on YOUR website! simpify: -4[5x-6(-5+x)] ------------- Comment: simplify from the inner parentheses to the outer: = -4[5x + 30 -6x] = -4[30 - x] = 4x -120 ==================== Cheers, Stan H.

Functions/153210: This question is from textbook Is Y a function of d? Is d a function of y? y 1993 94 95 96 97 98 d $2 $4 $3 $-2 $5 $2 1 solutions Answer 112732 by stanbon(57347)   on 2008-08-24 14:08:35 (Show Source): You can put this solution on YOUR website! Is Y a function of d? Ans: No, because d=2 has two corresponding y values: 1993 and 98 ------------------------ Is d a function of y? Ans: Yes, because each year has one corresponding d value. ------------------------ y 1993 94 95 96 97 98 d $2 $4 $3 $-2 $5 $2 ============================ Cheers, Stan H.

Exponential-and-logarithmic-functions/153207: This question is from textbook elementary and intermediate algebra A) Write the sentence (-x)2 is not equal to -x2 in words. In your own words explain why (-x)2 and -x2 are not equivalent. Provide an example to support your explanation. B) Evaluate (a) 3x0 and (b) (3x)0 when x is not 0. Are the results different? If so, explain in your own words why they are different. If not, then state so. A student writes down the following as part of her response: a ) 3(to the 2nd power) times 3(to the 3rd power) = 729. and b) 3(to the negative 2nd power) = -9. Are her answers correct? If not, explain why you think her answers are incorrect. Include in your explanation what she did wrong, if any. What would you advise her to do instead? i hope this makes sense to you...the way i typed it. please let me know if you need additional info. It is the chapter on Laws/Types of Exponents. Thank you thank you thank you Jennifer 1 solutions Answer 112728 by stanbon(57347)   on 2008-08-24 14:03:51 (Show Source): You can put this solution on YOUR website! A) Write the sentence (-x)^2 is not equal to -x^2 in words. The square of negative x is not equal to the negative of x squared. ----------- In your own words explain why (-x)2 and -x2 are not equivalent. Provide an example to support your explanation. In the 1st you are squaring -x. In the 2nd you are forming the negative of the square of x. Ex: (-5)^2 is not equal to -5^2 25 is not equal to -25 --------------------------------- B) Evaluate (a) 3x0 and (b) (3x)0 when x is not 0. Are the results different? 3x^0 = 3*1 = 3 (3x)^0 = 1 Ans: Yes, they are different. --------------- If so, explain in your own words why they are different. If not, then state so. In the 1st you are multiply x^0 by 3 to get 3*1 = 3 In the 2st you are raising (3x) to the zero power to get 1 --------------------------------- A student writes down the following as part of her response: a ) 3(to the 2nd power) times 3(to the 3rd power) = 729. Ans: 3^2 * 3*3 = 3^5 = 243 The student is wrong. ------------------------------- and b) 3(to the negative 2nd power) = -9. Are her answers correct? Ans: 3^(-2)= (3^2)^-1 = 9^-1 = 1/9 The student is wrong. ---------------------------- If not, explain why you think her answers are incorrect. Include in your explanation what she did wrong, if any. What would you advise her to do instead? ================= Cheers, Stan H.

Linear_Equations_And_Systems_Word_Problems/153180: Joe plans to make ropes and matching hats from a bolt of material. The fabric he plans to use is 250 yards long. She will need 2 yards of material for each rope and 1/6 of a yard for each hat She also plans to put decorations on the rope and will need 1 yard of cord for each rope . The hats will not have any fingers . She has 100 yards of cord to use for the decorations. 1. Write two equations to use to solve for how many hats and ropes she can make from the supplies on hand. Let r equal the number of ropes and made and h equal the number of hats made 2. Try to solve this system of equations If you get a solution state what it is. If not describe what the result mean. 1 solutions Answer 112725 by stanbon(57347)   on 2008-08-24 13:48:39 (Show Source): You can put this solution on YOUR website! Joe plans to make ropes and matching hats from a bolt of material. The fabric he plans to use is 250 yards long. He will need 2 yards of material for each rope and 1/6 of a yard for each hat He also plans to put decorations on the rope and will need 1 yard of cord for each rope . The hats will not have any fingers . He has 100 yards of cord to use for the decorations. ----------------------- 1. Write two equations to use to solve for how many hats and ropes he can make from the supplies on hand. Let r equal the number of ropes and made and h equal the number of hats made. Fabric inequality: 2r + (1/6)h <= 250 Cord inequality: r <= 100 ------------------------- 2. Try to solve this system of equations If you get a solution state what it is. If not describe what the result mean. Solve the EQUALITY; 2*100 + (1/6)h = 250 (1/6)h = 50 h = 300 So, when # of ropes is 100, # of hats is 300. ----------- Cheers, Stan H.

Geometry_Word_Problems/153189: Hello, How would I solve the following: The level of thorium in a sample decreases by a factor of one-half every 4.2 million years. A meteorite is discovered to have only 7.6% of its original thorium remaining. How old is the meteorite? I think this has been answered but I can not find the answer. Please help me I have tried several time to solve this without any help but I just can seen to solve it. Thank you, Jimmy 1 solutions Answer 112718 by stanbon(57347)   on 2008-08-24 13:27:43 (Show Source): You can put this solution on YOUR website! The level of thorium in a sample decreases by a factor of one-half every 4.2 million years. A meteorite is discovered to have only 7.6% of its original thorium remaining. How old is the meteorite? ------------------------- A(t) = Ao(1/2)^(t/4.2 mil) This says "the amount at time t A(t) is the amount you start with (Ao) multiplied by (1/2) (t/4.2 mil) times. ------------- 0.076Ao = Ao*(1/2)^(t/4.2 mil) 0.076 = (1/2)^(t/4.2 mil) Take the log of both sides to get: log 0.076 = (t/4.2 mil)*log(1/2) t/4.2 mil = log0.076/log0.5 t = 4.2 mil * 3.717857... t = 15.614998.. million years old. ================ Cheers, Stan H.

expressions/153179: I would want to know step by step of how to simplfy ecuation and to reduce the expresion? 1 4(2x-1)-6(x+3) 2 6a-2a+5=17 3 4(8-3w)=32-8(w+2) 1 solutions Answer 112706 by stanbon(57347)   on 2008-08-24 10:58:16 (Show Source): You can put this solution on YOUR website! 1 4(2x-1)-6(x+3) 8x-4 -6x-18 2x-22 ------------------ 2 6a-2a+5=17 4a = 12 a = 3 --------------- 3 4(8-3w)=32-8(w+2) 32-12w = 32 -8w -16 -12w = -8w - 16 Add 12w to both sides; Add 16 to both sides to get: 4w = 16 w = 4 ============ Cheers, Stan H.

Polynomials-and-rational-expressions/153178: solve for x: 7^x=200 please show workings 1 solutions Answer 112696 by stanbon(57347)   on 2008-08-24 09:06:25 (Show Source): You can put this solution on YOUR website! solve for x: 7^x=200 Take the log of both sides to get: x*log7 = log200 x = log200/log7 x = 2.301030.../0.845098... x = 2.722797... ----------- Cheers, Stan H.

Exponential-and-logarithmic-functions/153160: Hi How would I solve the following: Exponent and logarithm as function of power True or false: The function "f(x) = 3x" grows three times faster than the function "g(x) = x". Explain. I got two different answer when I tried to solve this logarithm. Can you please help me. Answer: False. If x = 3 it would make f(3)=3 * 3 =9 and g(3)=3 If x = 4 then f(4)=12 and g(4)=4 if x=5 then f(5)=15 and g(5)=5 although f(x) is 3 times greater than g(x) the growth of f(x) is not 3 times faster than g(x) because from 9 the change of f(x) is only 3 and from 12 it only changed by 3 again. wherein it should have incurred a change of 9. If f(x) grows three times faster than g(x) the equation should be f(x)=x raise to the 3rd power and g(x)=x. Answer is True The question is on rate of growth, ie slope. slope of g(x) is 1. slope of f(x) is 3. 1 solutions Answer 112695 by stanbon(57347)   on 2008-08-24 09:03:25 (Show Source): You can put this solution on YOUR website! 1st: This is not a logarithm problem 2nd: When you say " it should have grown by 9 " you are pointing to the fact that when x increased from 0 to 3 f(x) increased from 0 to 9. That is true. But, if x had increased from 0 to 1 f(x) would have increased by only 3. Similarly for x increasing from 1 to 2, then from 2, to 3. So for each increase in x by one f(x) increases by 3. That is a description of the slope; and the slope is the rate of growth for a linear function. ================ Cheers, Stan H.

Permutations/153166: I HAVE BEEN GIVEN A TABLE WHICH SHOWS THE MEDIAN "B.M.I" (BODY MASS INDEX) FOR FEMALES OF DIFFERENT AGES IN THE U.S IN THE YEAR 2000 . THE QUESTION IS USE TECHNOLOGY TO PLOT THE DATA POINTS ON A GRAPH?? . DEFINE ALL VARIABLES USED AND STATE ANY PARAMETERS CLEARLY??what type of function ,models the behavior of the graph? explain why one chose this function? ( very imporant!! - reason for using this function , parametres and variables ) AGE B.M.I 2 16.40 3 15.70 4 15.30 5 15.20 6 15.21 7 15.40 8 15.80 9 16.30 10 16.80 11 17.50 12 18.18 13 18.70 14 19.36 15 19.88 16 20.40 17 20.85 18 21.22 19 21.60 20 21.65 1 solutions Answer 112694 by stanbon(57347)   on 2008-08-24 08:46:54 (Show Source): You can put this solution on YOUR website! I entered the data in a TI-83. I ran the LinReg, QuadReg, CubReg, QuartReg programs against the data. Best fit is with the cubic and quartic regressions. With both the R^2 values are 0.999... indicating a close fit. Visually both track the data very well. The cubic is y = -0.004075x^3+0.153565x^2-1.275736x+18.272879 The quartic is y = 9.7x10^-5x^4 - 0.008354x^3 + 0.21674x^2 -1.63x+18.863421 ------------- Cheers, Stan H.

Equations/153171: I can find a way to simplify this expression. 5x**2 + 2x + 1 = 0 ** menas Squared. I canot find two factos that allow me to (5X+ )(X + ) solve this 1 solutions Answer 112692 by stanbon(57347)   on 2008-08-24 07:57:17 (Show Source): You can put this solution on YOUR website! 5x**2 + 2x + 1 = 0 ------------- Use the quadratic formula: x = [-2 +- sqrt(4 -4*5*1)]/10 x = [-2 +- sqrt(-16)]/10 x = [-2 +- 4i]/10 x = (-1/5) + (2/5)i or x = (-1/5) - (2/5)i ------------- Factors: (x + (1/5) -(2/5)i)(x + (1/5) + (2/5)i) = 0 ====================== Cheers, Stan H.

Numeric_Fractions/153175: x - 2 divided by x - x over x + 3 1 solutions Answer 112691 by stanbon(57347)   on 2008-08-24 07:51:50 (Show Source): You can put this solution on YOUR website! x - 2 divided by x - x over x + 3 ----------- [(x-2)/x] - [x/(x+3)] -------- lcm = x(x+3) -------- [(x-2)(x+3)]/lcm - [x^2]/lcm ---------- Add the numerators: [x^2+x-6-x^2]/lcm -------- Simplify: [x - 6]/[x(x+3)] ================= Cheers, Stan H.

Numeric_Fractions/153177: 9 - x square over y square divided by 3 - x over y 1 solutions Answer 112690 by stanbon(57347)   on 2008-08-24 07:47:16 (Show Source): You can put this solution on YOUR website! 9 - x square over y square divided by 3 - x over y ------------------------------------------------------ [(9-x^2)/y^2] / [(3-x)/y] ------- Invert the denominator and multiply: [(9-x^2)/y^2] * [y/(3-x)] ----------- Cancel factors common to numerator and denominator to get: (3+x)/y ============= Cheers, Stan H.

Quadratic-relations-and-conic-sections/153157: I'm not sure the answer I got for this is right. Find the vertex and axis of symmetry of the following parabola. f(x) = x^2 - 6x + 11 My work: (-3) ^2 y = (x-3)^2 + 11 - 9 y = (x-3)^2 +2 a = 1 h =3 k = 2 Vertex : (3,2) No asymptotes Can anyone tell me if this is correct and point me in the right direction if it isn't? Thanks! 1 solutions Answer 112663 by stanbon(57347)   on 2008-08-23 23:40:33 (Show Source): You can put this solution on YOUR website! Find the vertex and axis of symmetry of the following parabola. f(x) = x^2 - 6x + 11 x^2-6x+9 = y - 11 + 9 (x-3)^2 = y-2 --------------- Axis of symmetry at x = 3 Vertex: (3,2) =================== Cheers, Stan H.

Graphs/153158: Please help!!! A ball is thrown upward with an initial speed of 50ft/sec. It's height after t seconds is given by h=50t - 16t^2. A) What is the height of the ball after 1.3 seconds? B) When does the ball hit the ground? For A, the answer I worked out is 37.96 feet. For B, I worked out 25/8 seconds = t, which doesn't seem right. Can anyone help? Thank you!!!! 1 solutions Answer 112662 by stanbon(57347)   on 2008-08-23 23:37:57 (Show Source): You can put this solution on YOUR website! A ball is thrown upward with an initial speed of 50ft/sec. It's height after t seconds is given by h=50t - 16t^2. A) What is the height of the ball after 1.3 seconds? For A, the answer I worked out is 37.96 feet. That is correct. --------------------------- B) When does the ball hit the ground? Let h = 0. 0 = 50t -16t^2 Factor to get: 2t(25 - 8t) = 0 t = 0 or t = 25/8 sec. Comment: that tells you the ball is on the ground at the beginning and is back on the ground after 25/8 = 3 1/8 seconds. ------------------------ For B, I worked out 25/8 seconds = t, which doesn't seem right. Can anyone help? You are correct ========================== Cheers, Stan H.

Probability-and-statistics/152891: Can you please help me with this problem? the cost of one serving of peanut butter (in cents) for a random sample of 19 jars of peanut butter was to be: 22 27 32 26 26 19 16 26 14 21 20 21 20 17 12 32 17 9 16 a) give the five-number summary ( low, Q1, median, Q3, high) b) calculate the IQR.. Thank you for your help in advance carol 1 solutions Answer 112661 by stanbon(57347)   on 2008-08-23 23:31:18 (Show Source): You can put this solution on YOUR website! the cost of one serving of peanut butter (in cents) for a random sample of 19 jars of peanut butter was to be: 22 27 32 26 26 19 16 26 14 21 20 21 20 17 12 32 17 9 16 a) give the five-number summary ( low, Q1, median, Q3, high) Ans: low = 9 Q1 = 16 median = 20 Q3 = 26 max = 32 --------------------------- b) calculate the IQR.. IQR = (Q3 - Q1) = 26 - 16 = 10 ================ Cheers, Stan H.

Probability-and-statistics/153080: can some one please help me with this i do not even know how to get started with this. consumer reports stated that the mean time for a chrysler concorde to go from 0 to 60 miles per hour was 8.7 seconds. a) if you want to set up a statistical test to challenge the claim of 8.7 seconds what would you use for the null hypothesis? AM I CORRECT WHEN THIS ANSWER Ho: u = 8.7? b) the town of leadville, colorado, has an elevation over 10,000 feet. Suppose you wanted to test the claim that the average time to accelerate from 0 to 60 miles per hour is longer in leadville ( because of less oxygen). What would you use for the alternate hypothesis? I HOPE THIS IS RIGHT TOO H1 : U> 10,000 C) Suppose you made an engine modification and you think that they average time to accelerate from 0 to 60 miles per hour has been reduced. What would you use for the alernate hypothesis? NOW THIS IS WHERE I GET CONFUSED. BUT I AM GOING TO TRY IT H1: U< 0 TO 60 d) For each of the tests in parts (b) and (c), would the P-value area be on the left, on the right, or on both sides of the mean> Explain your answer in each case? This part i do not understand at all? Julie 1 solutions Answer 112660 by stanbon(57347)   on 2008-08-23 22:53:38 (Show Source): You can put this solution on YOUR website! consumer reports stated that the mean time for a chrysler concorde to go from 0 to 60 miles per hour was 8.7 seconds. a) if you want to set up a statistical test to challenge the claim of 8.7 seconds what would you use for the null hypothesis? AM I CORRECT WHEN THIS ANSWER Ho: u = 8.7? Ans: You are correct -------------------------- b) the town of leadville, colorado, has an elevation over 10,000 feet. Suppose you wanted to test the claim that the average time to accelerate from 0 to 60 miles per hour is longer in leadville ( because of less oxygen). What would you use for the alternate hypothesis? I HOPE THIS IS RIGHT TOO H1 : U> 10,000 Ans: You should use u > 8.7 ------------------------------- C) Suppose you made an engine modification and you think that they average time to accelerate from 0 to 60 miles per hour has been reduced. What would you use for the alernate hypothesis? NOW THIS IS WHERE I GET CONFUSED. BUT I AM GOING TO TRY IT H1: U< 0 TO 60 Ans: You should use u < 8.7 -------------------------------- d) For each of the tests in parts (b) and (c), would the P-value area be on the left, on the right, or on both sides of the mean> Explain your answer in each case? b) Since the alternate is "greater than" the p-value is on the right. c) Since the alternate is "less than" the p-value is on the left. ======================== Cheers, Stan H.