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Recent problems solved by 'stanbon'
stanbon answered: 57894 problems
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2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 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54990..55019 , 55020..55049 , 55050..55079 , 55080..55109 , 55110..55139 , 55140..55169 , 55170..55199 , 55200..55229 , 55230..55259 , 55260..55289 , 55290..55319 , 55320..55349 , 55350..55379 , 55380..55409 , 55410..55439 , 55440..55469 , 55470..55499 , 55500..55529 , 55530..55559 , 55560..55589 , 55590..55619 , 55620..55649 , 55650..55679 , 55680..55709 , 55710..55739 , 55740..55769 , 55770..55799 , 55800..55829 , 55830..55859 , 55860..55889 , 55890..55919 , 55920..55949 , 55950..55979 , 55980..56009 , 56010..56039 , 56040..56069 , 56070..56099 , 56100..56129 , 56130..56159 , 56160..56189 , 56190..56219 , 56220..56249 , 56250..56279 , 56280..56309 , 56310..56339 , 56340..56369 , 56370..56399 , 56400..56429 , 56430..56459 , 56460..56489 , 56490..56519 , 56520..56549 , 56550..56579 , 56580..56609 , 56610..56639 , 56640..56669 , 56670..56699 , 56700..56729 , 56730..56759 , 56760..56789 , 56790..56819 , 56820..56849 , 56850..56879 , 56880..56909 , 56910..56939 , 56940..56969 , 56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179 , 57180..57209 , 57210..57239 , 57240..57269 , 57270..57299 , 57300..57329 , 57330..57359 , 57360..57389 , 57390..57419 , 57420..57449 , 57450..57479 , 57480..57509 , 57510..57539 , 57540..57569 , 57570..57599 , 57600..57629 , 57630..57659 , 57660..57689 , 57690..57719 , 57720..57749 , 57750..57779 , 57780..57809 , 57810..57839 , 57840..57869 , 57870..57899, >>NextMiscellaneous_Word_Problems/177997: This question is from textbook
Set K contains 30 elements, set J contains 46 elements, and 11 elements are common to both sets. Find n ( K U J). 1 solutions
Answer 132965 by stanbon(57967) on 2009-01-22 18:02:16 (Show Source):
You can put this solution on YOUR website!Set K contains 30 elements, set J contains 46 elements, and 11 elements are common to both sets. Find n ( K U J).
---------------------------------------
n(K U J) = n(K) + n(J) - n(K and J)
n(K U J) = 30 + 46 - 11 = 65
================================
Cheers,
Stan H.
|
Miscellaneous_Word_Problems/177994: This question is from textbook
For sets A and B, determine whether A = B, A is a subset of B, or B is a subset of A
A = { x| x є N and 13 < x < 18}
B = { 12, 13, 14, 15, 16, 17, 18}
Help me please!!!! 1 solutions
Answer 132962 by stanbon(57967) on 2009-01-22 17:57:55 (Show Source):
You can put this solution on YOUR website!For sets A and B, determine whether A = B, A is a subset of B, or B is a subset of A
A = { x| x є N and 13 < x < 18} = [14,15,16,17}
B = { 12, 13, 14, 15, 16, 17, 18}
----------------
A is a subset of B
========================
Cheers,
Stan H.
|
Graphs/177988: can someone help me with this problem, by completing each order of pair of the given equation
y =2x + 5: (8, ), (-1, ), ( , -1)
1 solutions
Answer 132961 by stanbon(57967) on 2009-01-22 17:53:18 (Show Source):
You can put this solution on YOUR website! can someone help me with this problem, by completing each order of pair of the given equation
y =2x + 5:
(8, ), : y = 2*8+5 = 21
(-1, ),: y = 2*-1+5 = 3
------------------------------
x = (y - 5)/2
( , -1): x = (-1 - 5)/2 = -3
================================
Cheers,
Stan H.
|
Linear_Equations_And_Systems_Word_Problems/177981: Find a value for k that will make 4x^2 + 6.4 x + k a perfect square. Describe the procedure that you used which requires algebra [that is, not trial and error].
been on this 1 for awhile just can't find the appropiate equation to make it work. 1 solutions
Answer 132958 by stanbon(57967) on 2009-01-22 17:46:13 (Show Source):
You can put this solution on YOUR website!Find a value for k that will make 4x^2 + 6.4 x + k a perfect square.
-----------
4x^2 + 6.4x + k
-------
Factor out the "4" to get:
4(x^2 = 1.6x + ?
----
Add the square of half the coefficient of "x"
4(x^2 + 1.6x + (1.6/2)^2)
k = (1.6/2)^2 = 0.8^2 = 0.64
=================================
Cheers,
Stan H.
|
Probability-and-statistics/177958: Suppose that a researcher is interested in estimating the mean systolic blood pressure, , of executives of major corporations. He plans to use the blood pressures of a random sample of executives of major corporations to estimate . Assuming that the standard deviation of the population of systolic blood pressures of executives of major corporations is 26 mm Hg, what is the minimum sample size needed for the researcher to be 95% confident that his estimate is within 5 mm Hg of ?
1 solutions
Answer 132941 by stanbon(57967) on 2009-01-22 16:00:24 (Show Source):
You can put this solution on YOUR website!Assuming that the standard deviation of the population of systolic blood pressures of executives of major corporations is 26 mm Hg, what is the minimum sample size needed for the researcher to be 95% confident that his estimate is within 5 mm Hg of ?
-----------------------
n = unknown
z* = 1.96
sigma = 26
E = 5
---------------
Form: m = [z*sigma/E]^2
n = [1.96*26/5]^2 = 103.87..
Rounding up: n = 104
========================
Cheers,
Stan H.
|
Functions/177896: If a bacteria population starts with 100 bacteria and doubles every three hours, then the number of bacteria after t hours is n=f(t)=100(2 to the t/3 power). When will the population reach 50,000? 1 solutions
Answer 132887 by stanbon(57967) on 2009-01-22 09:06:43 (Show Source):
You can put this solution on YOUR website!If a bacteria population starts with 100 bacteria and doubles every three hours, then the number of bacteria after t hours is n=f(t)=100(2 to the t/3 power). When will the population reach 50,000?
---------------------
50,000 = 100(2)^(t/3)
2^(t/3) = 500
Take the log of both sides to get:
(t/3)log2 = log500
t/3 = log(500)/log(2)
t/3 = 8.9657..
t = 26.9 hours
===================
Cheers,
Stan H.
|
Functions/177893: The graph of the function f(x)= x-squared - 3. Find the slope of each of the tangent lines when x=0, x=1, and x=2. 1 solutions
Answer 132885 by stanbon(57967) on 2009-01-22 08:58:28 (Show Source):
You can put this solution on YOUR website!The graph of the function f(x)= x-squared - 3. Find the slope of each of the tangent lines when x=0, x=1, and x=2.
-------------

-------------------------------------------
The slope at every value of x is f(x) = 2x
Therefore, slope at x = 0 = 2*0 = 0
slope at x = 1 = 2*1 = 2
slope at x = 2 = 2*2 = 4
=========================
Cheers,
Stan H.
|
Linear_Algebra/177847: please grahph these
[>] means equal or greater than..
() means ablsoule value.. thanks for helping
y>x-5
3x+y[<]-2
y[<]x+2
y>(x-3)+1 1 solutions
Answer 132884 by stanbon(57967) on 2009-01-22 08:54:47 (Show Source):
You can put this solution on YOUR website!please graph these
[>] means equal or greater than..
() means absolute value.. thanks for helping
-------------------
Note: You cannot DIRECTLY graph an inequality. You need to
first graph the EQUALITY that forms its boundary.
-------------------
y>= x-5
1st: Graph the line y = x-5 as a dashed line
2nd: Shade the halfplane Above the line because you want the "greater than".

---------------------------------------
3x+y[<]-2
3x + y <= -2
y <= -3x -2
1st: Graph the line y = -3x -2 as a solid line
2nd: Shade the halfplane below the boundary line because you want "less than".

----------------------------------------
y[<]x+2
y <= x + 2
1st: Graph the line y = x + 2 as a solid line.
2nd: Shade the halfplane below the boundary line.

----------------------------------------
y>(x-3)+1
y > |x-3| + 1
1st: Graph the |x-3|+1 as a dashed line.
2nd: Graph the sector above the boundary.

==================================================
Note: This site cannot accept the shading I described.
==================================================
Cheers,
Stan H.
|
Miscellaneous_Word_Problems/177871: Lolo has 16,65$ and some coins of 1 cent.From this lolo gave 10$ to his friend.He equaly gave the remaining money to his brother and sister.If his brother got 2.50$,how many coins of 1 cent did he have at the behining? PLEASEEEEEEEEEEEEEE HELPPPPPPPPPPPPPPPPPPPPPPP !!!!!!!!!! 1 solutions
Answer 132883 by stanbon(57967) on 2009-01-22 08:42:23 (Show Source):
|
Linear_Algebra/177852: Solve each quadratic equation.
23. x2 - 16 = 0
24. 2x2 - 3x - 11 = 0
25. x2 + 3x - 10 = 0
26. 3x2 + 48 = 0
27. x2 - 5x + 4 = 0
28. 2x2 - x + 1 = 0 1 solutions
Answer 132881 by stanbon(57967) on 2009-01-22 08:38:49 (Show Source):
You can put this solution on YOUR website!Solve each quadratic equation.
23. x^2 - 16 = 0
(x-4)(x+4) = 0
x = 4 or x = -4
-------------------------
24. 2x^2 - 3x - 11 = 0
x = [3 +- sqrt(9 -4*2*-11)]/4
x = [3 +- sqrt(97)]/4
-------------------------
25. x^2 + 3x - 10 = 0
(x+5)(x-2) = 0
x = -5 or x = 2
-------------------------
26. 3x^2 + 48 = 0
3(x^2 + 16) = 0
Factorable if you are familiar with complex numbers.
3(x+4i)(x-4i) = 0
x = -4i or x = 4i
-------------------------
27. x^2 - 5x + 4 = 0
(x-4)(x-1) = 0
x = 4 or x = 1
-------------------------
28. 2x^2 - x + 1 = 0
(2x+1)(x-1) = 0
x = -1/2 or x = 1
=========================
Cheers,
Stan H.
|
Linear_Algebra/177856: Write each function in vertex form. Sketch the graph of the function and
label its vertex.
33. y = x2 + 4x - 7
34. y = -x2 + 4x - 1
35. y = 3x2 + 18x
36.y = 1/2x2 - 5x + 12 1 solutions
Answer 132877 by stanbon(57967) on 2009-01-22 08:00:43 (Show Source):
You can put this solution on YOUR website!Write each function in vertex form. Sketch the graph of the function and
label its vertex.
33. y = x^2 + 4x - 7
x^2 + 4x + ? = y+7+?
x^2 + 4x + 4 = y+7+4
(x+2)^2 = y + 11
-----------------
Vertex: (-2,-11)

==================================================
34. y = -x^2 + 4x - 1
35. y = 3x^2 + 18x
-------------------------
36.y = 1/2x^2 - 5x + 12
(1/2)x^2 - 5x + ? = y-12 + ?
(1/2)[x^2 - 10x + ? = y-12 + ?
(1/2)[x^2 - 10x + 25] = y - 12 + (1/2)*25
(1/2)[x-5]^2 = y + (1/2)
----
Vertex: (5,-1/2))

============================
Cheers,
Stan H.
|
Graphs/177860: 41. Anthony has 10 ft of framing and wants to use it to make the largest
rectangular picture frame possible. Find the maximum area that can
be enclosed by his frame.
42. A ball is thrown upward from ground level. Its height h, in feet, above
the ground after t seconds is h = 48t - 16t2. Find the maximum height
of the ball.
43. Suppose a parabola has a vertex in Quadrant IV and a , 0 in the
equation y = ax2 + bx + c. How many real solutions will the equation
ax2 + bx + c = 0 have? 1 solutions
Answer 132876 by stanbon(57967) on 2009-01-22 07:50:36 (Show Source):
You can put this solution on YOUR website!41. Anthony has 10 ft of framing and wants to use it to make the largest
rectangular picture frame possible. Find the maximum area that can
be enclosed by his frame.
------
Perimeter = 2(L + W)
10 = 2(L + W)
L+W = 5
L = 5-W
------------
Area = LW
Area = (5-W)W
Area = 5W - W^2
------------------
This is a quadratic with a = -1, b=5
The maximum area occurs when W = -b/2a = -5(2*-1) = 5/2
---
If W + L = 5 and W = 5/2, then L = 5/2
---------
So the maximum area is: A = LW = (5/2)^2 = 25/4 sq ft
===============================================================
42. A ball is thrown upward from ground level. Its height h, in feet, above
the ground after t seconds is h = 48t - 16t2. Find the maximum height
of the ball.
---
h(t) = 48t - 16t^2
Max occurs when t = -48/(2*-16) = 48/32 = 3/2 seconds
--
Max height = h(3/2) = 48(3/2)-16(3/2)^2 = 72 - 36 = 36 ft.
===============================================================
43. Suppose a parabola has a vertex in Quadrant IV and a , 0 in the
equation y = ax2 + bx + c. How many real solutions will the equation
ax2 + bx + c = 0 have?
Comment: Somthing is missing in your statement.
====================================================
Cheers,
Stan H.
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Equations/177854: You are awesome...I have a few more!!! This also needs to be factored. THANK YOU
(x+3)^10(x-5)^7 + (x+3)^9(x-5)^8 = 1 solutions
Answer 132875 by stanbon(57967) on 2009-01-22 07:40:43 (Show Source):
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Expressions-with-variables/177889: Simplify or Perform operation :
113) (y2 – 16) / (-8 – 2y)
114) -2b^2 - 6b - 4
b^2 - 1
115) (3x – 6)/(x^2 – 4x + 4)
116) mx + 3x + my + 3y / m2 – 3m – 18
I'M SO COMPLETELY LOST!!! PLEASE HELP ME.....
1 solutions
Answer 132873 by stanbon(57967) on 2009-01-22 07:26:28 (Show Source):
You can put this solution on YOUR website!Simplify or Perform operation :
113) (y^2 – 16) / (-8 – 2y)
Factor where you can to get:
[(y-4)(y+4)] / [-2(4+y)]
Cancel the y+4 common factor to get:
(y-4)/(-2)
=========================
114) (-2b^2 - 6b - 4) / (b^2 - 1)
Factor where you can to get:
[-2(b^2 + 3b +2)] / [(b-1)(b+1)]
Factor again:
= [-2(b^2 + 3b +2)] / [(b-1)(b+1)]]
= [-2(b+1)(b+2)] / [(b-1)(b+1)]
Cancel the b+1 common factor to get:
= [-2(b+2)] / [(b-1)]
==============================
115) (3x – 6)/(x^2 – 4x + 4)
Factor to get:
(3(x-2)) / [(x-2)(x-2)]
Cancel the common x-2 factor:
= 3/(x-2)
========================
116) mx + 3x + my + 3y / m^2 – 3m – 18
Factor to get:
[m(x+y) + 3(x+y)] / [(m-6)(m+3)]
Factor again:
[(x+y)(m+3)] / [(m-6)(m+3)]
Cancel the common factor to get:
(x+y) / (m-6)
========================
Cheers,
Stan H.
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Quadratic_Equations/177880: Solve. s^2+3s-54+0
I think I use the quadratic equation to solve this. I did and got the answers of -3Plus or minus the square root of -207 all divided by 2. Is this right? Thank you for your help.
1 solutions
Answer 132849 by stanbon(57967) on 2009-01-21 22:19:14 (Show Source):
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Geometry_Word_Problems/177879: This question is from textbook
Abby has 37 coins, consisting only of dimes and quarters, worth $7.45. How many dimes and how many quarters does she have? 1 solutions
Answer 132848 by stanbon(57967) on 2009-01-21 22:16:49 (Show Source):
You can put this solution on YOUR website!Abby has 37 coins, consisting only of dimes and quarters, worth $7.45. How many dimes and how many quarters does she have?
--------------------------------------
Quantity Equation: d + q = 37
Value Equation...:10d+25q= 745 cents
-------------------------------------------
Modify:
10d + 10q = 370
10d + 25q = 745
------------------------
Subtract 1st from 2nd to solve for "q":
15q = 375
q = 25 (# of quarters)
----------------
Since d+q = 37, d + 25 = 37; d = 12 (# of dimes)
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Cheers,
Stan H.
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Quadratic_Equations/177876: Here is one that I am struggling with the directions.
Find the polynomial for the perimeter and the area. Do not factor.
there is a rectangle with the length labeled z+5 and the width is labeled z.
I think the perimeter would be 2z+2(z+5) and the area may be z(z+5). Thanks 1 solutions
Answer 132847 by stanbon(57967) on 2009-01-21 22:11:54 (Show Source):
You can put this solution on YOUR website!Find the polynomial for the perimeter and the area. Do not factor.
there is a rectangle with the length labeled z+5 and the width is labeled z.
--------------------------
Perimeter = 2(length + width)
P = 2(z+5 + z) = 2(2z + 5) = 4z + 10
-----------------------------------------
Area = width * length
A = z(z+5) = z^2 + 5z
=============================
Cheers,
Stan H.
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Equations/177877: I know the answer to this problem is K=3, but I do not know how to figure out how to get it on my own. Can you show me the steps to figure this out?
5(K-4)+3K = 4
Thanks! Tony 1 solutions
Answer 132846 by stanbon(57967) on 2009-01-21 22:08:24 (Show Source):
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Geometry_Word_Problems/177873: If the complement of an angle is 5degrees less than one-sixth of its supplement. Find the measure of the angle. 1 solutions
Answer 132845 by stanbon(57967) on 2009-01-21 22:06:17 (Show Source):
You can put this solution on YOUR website!If the complement of an angle is 5degrees less than one-sixth of its supplement. Find the measure of the angle.
--------------------------------------
Let the angle be "x".
Its complement = "90-x"
Its supplement = "180-x"
----------------------------
Equation:
90-x = (1/6)(180-x)-5
90-x = 30 - x/6 - 5
90 - x = 25 - x/6
65 = (5/6)x
x = (6/5)*65
x = 6*13
x = 78 Degrees (measure of the angle)
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Cheers,
Stan H.
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Inequalities/177863: Y=2x-7
x+y=11
with all work and solve for x and y
i just dont get it 1 solutions
Answer 132843 by stanbon(57967) on 2009-01-21 21:59:22 (Show Source):
You can put this solution on YOUR website!Y=2x-7
x+y=11
------------
There are a number of ways to solve this system.
One way is called substitution:
Since y = 2x-7 substitute that into the 2nd equation and solve for "x":
---
x + (2x-7) = 11
x + 2x - 7 = 11
3x = 18
x = 6
----------------
Since y = 2x-7,y = 2*6-7 = 12-7 = 5
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Ans: y = 5 and x = 6
=========================
Cheers,
Stan H.
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Square-cubic-other-roots/177870: This question is from textbook Algebra 1
Can you please help me simplify this exponential equation?
(-3xy^2)^3(-2x^2y)^2
Here is how I tried:
(-3^3*x^3*y^6)(-2^2*x^4*y^2)
-3^3*x^3*y^6*-2^2*x*4*y^2
-3^3*x^7*y^8*-2^2 1 solutions
Answer 132842 by stanbon(57967) on 2009-01-21 21:51:04 (Show Source):
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Miscellaneous_Word_Problems/177869: in a farm, there are 150 more goats than ducks. there are 1800 animal legs altogether. how many goats and ducks are there in the farm? 1 solutions
Answer 132841 by stanbon(57967) on 2009-01-21 21:45:40 (Show Source):
You can put this solution on YOUR website!in a farm, there are 150 more goats than ducks. there are 1800 animal legs altogether. how many goats and ducks are there in the farm?
-----------------
Equations:
Quantity Equation: g = d + 150
Leg equation: 4g + 2d = 1800
---------------------------------
Rearrange:
g - d = 150
4g + 2d = 1800
--------------------
Modify:
2g - 2d = 300
4g + 2d = 1800
---------------------
Add to solve for "g":
6g = 2100
g = 350 (# of goats)
----
Solve for "d":
350 -d = 150
d = 200 (# of ducks)
========================
Cheers,
Stan H.
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Linear-equations/177867: This question is from textbook
How do you graph the equation 5x- 2y= -4 1 solutions
Answer 132840 by stanbon(57967) on 2009-01-21 21:28:20 (Show Source):
You can put this solution on YOUR website!How do you graph the equation 5x- 2y= -4
---------------
Find the x-intercept and the y-intercept:
---
x-intercept:
Let y = 0, then x = -4/5, giving you point (-4/5,0)
-------------
y-intercept:
Let x = 0,then y = 2, giving you point (0,2)
-------------
Plot the two points and draw a line thru them.

Cheers,
Stan H.
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Age_Word_Problems/177817: Rick is 5 times the age of Mike, who is half the age of Ed. Fred is double the ages of Mike and Ed combined. Daniel is 79 years younger than Rick. All thier ages equal 271. What is the age of Daniel. 1 solutions
Answer 132810 by stanbon(57967) on 2009-01-21 18:44:48 (Show Source):
You can put this solution on YOUR website!Rick is 5 times the age of Mike, who is half the age of Ed. Fred is double the ages of Mike and Ed combined. Daniel is 79 years younger than Rick. All thier ages equal 271. What is the age of Daniel.
-------------------
R = 5M
M = (1/2)E
F = 2(M + E)
D = R-79
R + M + F + E + D = 271
---------------------------
Rearrange:
R + M + F + E + D = 271
R - 5M + 0 + 0 + 0 = 0
0 + 2M + 0 - E + 0 = 0
0 + 2M - F +2E + 0 = 0
R + 0 + 0 + 0 - D = 79
----------------------------
Solve the system by any method you know to get:
R =
M =
F =
E =
D =
----------
Comment:
This set of equations does not yield whole number values for the variables.
The equations are based on the words used in the narrative.
Check the words; make sure they express the problem you are trying to solve.
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Cheers,
Stan H.
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Miscellaneous_Word_Problems/177811: zain and hina have 375 strawberries.Each time hina picks 3 strawberries zain has 2. how many strawbrries did each of them pick up? 1 solutions
Answer 132795 by stanbon(57967) on 2009-01-21 17:43:34 (Show Source):
You can put this solution on YOUR website!zain and hina have 375 strawberries.Each time hina picks 3 strawberries zain has 2. how many strawbrries did each of them pick up?
----------------------
Let number of berries picked by zain be 2x; then # of berries
piciked by hina will be 3x
Equation:
3x + 2x = 375
5x = 375
x = 75
2x = 150 (# of berries picked by zain)
3x = 225 (# of berries picked by hina)
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Cheers,
Stan H.
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Equations/177808: This question is from textbook Pre-Algebra
How can I find out the answer to -1/8??? So far I have tried doing one divided by eight. I ended up with 0.12. I really don't think that that is the right answer. I have a feeling I'm missing a step that has to do with the negative. Please help! Thank You. 1 solutions
Answer 132793 by stanbon(57967) on 2009-01-21 17:35:45 (Show Source):
You can put this solution on YOUR website!So far I have tried doing one divided by eight. I ended up with 0.12. I really don't think that that is the right answer. I have a feeling I'm missing a step that has to do with the negative.
----------------------------------------
I don't see the negative you are talking about.
------------
1/8 = 0.125000.....
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Cheers,
Stan H.
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