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Recent problems solved by 'stanbon'

stanbon answered: 57867 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 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Linear-equations/178179: I replaced the numbers in this equation so I can solve my own numbers. Could someone please help me. The medium age of first marriage is 24.5 years in 1995 to 25.1 years in 2000. Let 1995 be year 5 and 2000 be year 10. a) Find the equation of the line through (5,24.5)and (10, 25.1). b) What do x and y represent in your equation? c) Interpret the slope of this line. d) In what year will the medium age be 30? I want to compare what I have in my problem so please show work. Thank you. 1 solutions Answer 133138 by stanbon(57940)   on 2009-01-23 18:04:38 (Show Source): You can put this solution on YOUR website! The medium age of first marriage is 24.5 years in 1995 to 25.1 years in 2000. Let 1995 be year 5 and 2000 be year 10. a) Find the equation of the line through (5,24.5)and (10, 25.1). slope = (24.5 - 24.1) / (5 - 10) = 0.4/(-5) = -0.08 -------------- intercept: 25.1 = (-0.08)*10 + b 25.1 = -0.8 + b b = 25.9 --- Equation: y = -0.08x + 25.9 ------------------------------------ b) What do x and y represent in your equation? x is # of years after 1990 y is median age of first marriage ------------------------------------ c) Interpret the slope of this line. As the number of years after 1990 increases by one the median age of 1st marriage decreases by 0.08 ------------------------------------ d) In what year will the medium age be 30? 30 = -0.08x + 25.9 -0.08x = 4.1 x = -51.25 ---- Year = 1990 -51.25 = 1938.75 or year 1939 ============================================== Cheers, Stan H.

real-numbers/178177: can someone please help me with this problem I tried to do it myself but keep getting it wrong. A repair bill on a yacht came to $1,603 including $532 for parts and the remainder for labor. If the cost of labor is $63 per hour, how many hours of labor did it take to repair the yacht? 1 solutions Answer 133136 by stanbon(57940)   on 2009-01-23 17:43:46 (Show Source): You can put this solution on YOUR website! A repair bill on a yacht came to $1,603 including $532 for parts and the remainder for labor. If the cost of labor is $63 per hour, how many hours of labor did it take to repair the yacht? -------------------------------- Repair = parts + labor 1603 = 532 + labor labor = 1071 -------------- labor hrs = 1071/63 = 17 hrs to carry out the repair ====================== Cheers, Stan H.

Numbers_Word_Problems/178176: 3/4(4-x)=3-x Can you explain this step by step for me. I know x=0 but I can't figure out why 1 solutions Answer 133135 by stanbon(57940)   on 2009-01-23 17:39:50 (Show Source): You can put this solution on YOUR website! (3/4)(4-x) = 3-x Multiply both sides by 4 to get: 3(4 - x) = 4(3 - x) 12 - 3x = 12 -4x x = 0 ------------------ Cheers, Stan H.

Radicals/178175: Simplify (√y+3)(√y-5) 1 solutions Answer 133134 by stanbon(57940)   on 2009-01-23 17:34:55 (Show Source): You can put this solution on YOUR website! Simplify (√y + 3)(√y - 5) Use FOIL: F: sqrt(y)*sqrt(y) = y O: -5*sqrt(y) = -5sqrt(y) I: +3*sqrt(y) = 3sqrt(y) L: (3)*(-5) = -15 ------------------------ Combine the results: = y - 2sqrt(y) - 15 ======================= Cheers, Stan H.

Linear_Algebra/178153: The graph of y=x is translated up 3 units and left 2 units. What is the equation of the new graph? please graph..[] means absoulte value y=[x-1]-3 y=[x+2] y=3x-1 1 solutions Answer 133133 by stanbon(57940)   on 2009-01-23 17:29:49 (Show Source): You can put this solution on YOUR website! The graph of y=x is translated up 3 units and left 2 units. What is the equation of the new graph? y = (x+2) + 3 ------------------------ please graph..[] means absolute value y=[x-1]-3 ----------------------------------------------------- y=[x+2] ----------------------------------------------------- y=3x-1 ====================================================== Cheers, Stanh.

Expressions-with-variables/178173: 202) 2+3/(y-5)= 2y/(y-5) Perform the operations or solve if it is an equation (= sign) 1 solutions Answer 133132 by stanbon(57940)   on 2009-01-23 17:24:12 (Show Source): You can put this solution on YOUR website! 2+3/(y-5)= 2y/(y-5) ----------- Multiply thru by y-5 to get: 2(y-5) + 3 = 2y 2y - 5 + 3 = 2y -2 = 0 Contradiction: The equation has no solutions. ================= Cheers, Stan H.

Expressions-with-variables/178161: simplify or perform operation: 215) 2x – 5 / (x – 2)(x + 6) + x2 – 2x + 1 / (x – 2)(x + 6) 217.) 2/(x-3) + 3/(3-x) 1 solutions Answer 133130 by stanbon(57940)   on 2009-01-23 16:59:16 (Show Source): You can put this solution on YOUR website! 215) [(2x – 5) / (x – 2)(x + 6)] + [(x^2 – 2x + 1) / (x – 2)(x + 6)] [(2x – 5) / (x – 2)(x + 6)] + [(x^2 – 1)^2 / (x – 2)(x + 6)] The denominators are the same so combine the numerators to get: = [2x - 5 + x^2 -2x + 1] / [(x-2)(x+6)] = [x^2-4] / [(x-2)(x+6)] = (x+2)/(x+6) =================== 217.) 2/(x-3) + 3/(3-x) Modify to get: 2(x-3) - 3 (x-3) = (2-3)/(x-3 = -1/(x-3) ====================== Cheers, Stan H.

Radicals/178168: Solve √(2x+3) - √(2x)=1 1 solutions Answer 133126 by stanbon(57940)   on 2009-01-23 16:49:02 (Show Source): You can put this solution on YOUR website! Solve √(2x+3) - √(2x)=1 Square both sides to get: 2x+3 -2sqrt(2x(2x+3) - 2x = 1 Combine: -2sqrt(4x^2+6x) = -2 sqrt(4x^2+6x) = 1 Square both sides to get: 4x^2 + 6x = 1 Rearrange: 4x^2 + 6x -1 = 0 Use quadratic formula: x = [-6 +- sqrt(36 - 4*4*-1] / 8 x = [-6 +- sqrt(52)/8 x = [-6 +- 2sqrt(13)]/8 x = [3 +- sqrt(13)]/4 ============================ Check the answers to see if any are extraneous. =============================================== Cheers, Stan H.

Polynomials-and-rational-expressions/178166: Would someone help me to understand this....Thanks 4 sqrt[50]+sqrt[32]-sqrt[18] I got 4[5]+[4]-[6] not sure if that's right or not. 1 solutions Answer 133124 by stanbon(57940)   on 2009-01-23 16:38:47 (Show Source): You can put this solution on YOUR website! 4 sqrt[50]+sqrt[32]-sqrt[18] = 4*sqrt(25*2)+sqrt(16*2)-sqrt(9*2) = 4*5sqrt(2)+4sqrt(2)-3sqrt(2) = (20+4-3)sqrt(2) = 21sqrt(2) ========================== Cheers, Stan H.

Graphs/178149: Solve each system of inequalities by graphing [] means absloute value.also can you tell me what the > is it dotted of not?? y>1 y[x]+1 2x-3<9 x+y>-2 1 solutions Answer 133092 by stanbon(57940)   on 2009-01-23 13:31:03 (Show Source): You can put this solution on YOUR website! Solve each system of inequalities by graphing [] means absloute value.also can you tell me what the > is it dotted of not?? --------- If there is no equality sign the boundary is dotted. If there is an equality sign the boundary is a solid line or curve. If there is an inequality there is an area that is shaded or hatched. ------------------------------------------------------------------------ y>1 Draw a dotted horizontal line at z = 1 Shade the halfplane ABOVE because you want "greater than". --------------- y=[x]+1 Draw a solid v-shape opening up with vertex at (0,1) ------------ The system solution is the intersection of the two graphs --------------- 2x-3<9 Draw the dotted line x = 6 Shade the halfplane to the LEFT of the line because you want "less than" --- x+y>-2 Draw the dotted line y = -x-2 Shade the halfplane ABOVE the line because you want "greater than" ============== The system solution is the intersection of the two graphs. Note: This site cannot graph x = 6 because it is not a function. ===================================================== Cheers, Stan H.

Probability-and-statistics/177713: 8.46 A random sample of 10 miniature Tootsie Rolls was taken from a bag. Each piece was weighed on a very accurate scale. The results in grams were: 3.087 3.131 3.241 3.241 3.270 3.353 3.400 3.411 3.437 3.477 (a)Construct a 90 percent confidence interval for the true mean weight. (b) What sample size would be necessary to estimate the true weight with an error (+ or -) 0.03 grams with 90 percent confidence? (c) Discuss the factors which might cause variation in the weight of Tootsie Rolls during manufacture. 1 solutions Answer 133091 by stanbon(57940)   on 2009-01-23 13:21:04 (Show Source): You can put this solution on YOUR website! done today Cheers, Stan H.

Probability-and-statistics/177902: A random sample of 10 miniature Tootsie Rolls was taken from a bag. Each piece was weighed on a very accurate scale. The results in grams were: 3.087 3.131 3.241 3.241 3.270 3.353 3.400 3.411 3.437 3.477 (a) Construct a 90 percent confidence interval for the true mean weight. (b) What sample size would be necessary to estimate the true weight with an error (+ or -) 0.03 grams with 90 percent confidence? (c) Discuss the factors which might cause variation in the weight of Tootsie Rolls during manufacture. 1 solutions Answer 133090 by stanbon(57940)   on 2009-01-23 13:19:07 (Show Source): You can put this solution on YOUR website! A random sample of 10 miniature Tootsie Rolls was taken from a bag. Each piece was weighed on a very accurate scale. The results in grams were: 3.087 3.131 3.241 3.241 3.270 3.353 3.400 3.411 3.437 3.477 (a) Construct a 90 percent confidence interval for the true mean weight. x-bar = (sum of the number)/10 = 3.308 E = z = 1.645*0.1399/sqrt(10) = 0.0728 ------- 90% CI; 3.308-0.0728-0.0728 < u < 3.308+0.0728 ---------------------------------------------------------------- (b) What sample size would be necessary to estimate the true weight with an error (+ or -) 0.03 grams with 90 percent confidence? n = [z*s/E]^2 n = [1.645*0.1399/0.03]^2 = 7.67^2 is appox 50 ----------------------------- (c) Discuss the factors which might cause variation in the weight of Tootsie Rolls during manufacture. I'll leave that to your imagination. ======================================== Cheers, Stan H.

Probability-and-statistics/177903: In 1992, the FAA conducted 86,991 pre-employment drug tests on job applicants who were to be engaged in safety and security related jobs, and found that 1,143 were positive. (a) Construct a 95 percent confidence interval for the population proportion of positive drug tests. (b) Why is the normality assumption not a problem, despite the very mall value of p? 1 solutions Answer 133074 by stanbon(57940)   on 2009-01-23 12:09:51 (Show Source): You can put this solution on YOUR website! In 1992, the FAA conducted 86,991 pre-employment drug tests on job applicants who were to be engaged in safety and security related jobs, and found that 1,143 were positive. (a) Construct a 95 percent confidence interval for the population proportion of positive drug tests. p-hat = 1143/86991 = 0.01314 E = z = 1.96[sqrt(0.01314*0.98686)/86991] = 0.0254 95% CI: 0.01314-0.0254 < p < 0.01314 +0.0254 ------------------------------- (b) Why is the normality assumption not a problem, despite the very mall value of p? The sample is large so np > 5 and nq > 5 . ===================== Cheers, Stan H.

Percentage-and-ratio-word-problems/178127: the mean of a set of numbers is 120. if one number is increased by 300, the mean increases to 135. how many numbers are in the set? 1 solutions Answer 133058 by stanbon(57940)   on 2009-01-23 10:55:23 (Show Source): You can put this solution on YOUR website! the mean of a set of numbers is 120. if one number is increased by 300, the mean increases to 135. how many numbers are in the set? --------- Let the number of numbers be "n". Then (sum of numbers)/n = 120 or old sum = 120n ------------------- If one of the numbers is increased by 300 the new sum = (old sum + 300) Then (new sum)/n = 135 or new sum = 135n = old sum + 300 = 120n + 300 --------------------------- Equation: 135n = 120n + 300 15n = 300 n = 20 =========== Cheers, Stan H.

Expressions-with-variables/178121: This question is from textbook algebra structure and method can you please help me express in simplest radical form:(((6square root sign3 multiplied by 3square root sign5))) 1 solutions Answer 133054 by stanbon(57940)   on 2009-01-23 10:27:31 (Show Source): You can put this solution on YOUR website! express in simplest radical form:(((6square root sign3 multiplied by 3square root sign5))) ----------- (6sqrt(3))*(3sqrt(5)) = 6*3*sqrt(3*5) = 18sqrt(15) =============== Cheers, Stan H.

Equations/178117: Please help me solve this problem. 4a+9b=8 8a+6c=-1 6b+6c=-1 thanks for your help!! 1 solutions Answer 133053 by stanbon(57940)   on 2009-01-23 10:25:06 (Show Source): You can put this solution on YOUR website! 4a + 9b + 0 = 8 8a + 0 + 6c= -1 0 + 6b + 6c= -1 ------------ Subtract twice the 1st equation from the 2nd to get: 4a + 9b + 0 = 8 0 - 18b + 6c= -17 0 + 6b + 6c= -1 --------------- Subtract the 3rd equation from the 2nd to get: 4a + 9b + 0 = 8 0 - 24b + 0= -16 0 + 6b + 6c= -1 ------------------------ Solve for "b" in the 2nd equation: b = 16/24 = 2/3 -------------------- Substitute into the 1st to solve for "a" and into the 3rd to solve for "x". 4a + 9(2/3) = 8 4a + 6 = 8 4a = 2 a = 1/2 ------------- 6b + 6c = -1 6(2/3) + 6c = -1 4 + 6c = -1 6c = -5 c = -5/6 =================== a = 1/2 b = 2/3 c = -5/6 =================== Cheers, Stan H

Linear-equations/178113: I am in desperate...I can do these problems until I get to the answer and I miss every time, so could someone please give me step by step. Find an equation of the line containing the given pair of points (-2, -3) and (-8, -4) THANKS! 1 solutions Answer 133052 by stanbon(57940)   on 2009-01-23 10:12:43 (Show Source): You can put this solution on YOUR website! Find an equation of the line containing the given pair of points (-2, -3) and (-8, -4) ----- slope : (-4--3) / (-8--2) = -1/-6 = 1/6 --------------- Intercept: Since the form is y = mx + b and you know y,x, and m, solve for "b". -3 = (1/6)*-2 + b -3 = -1/3 + b b = -9/3 + 1/3 = -8/3 --------------------------- Equation: y = (1/6)x - (8/3) ======================= Cheers, Stan H.

Probability-and-statistics/177905: A normally distributed population has a mean of 60 and a standard deviation of 6. Compute the probability of a value between 51 and 66. ________ Compute the probability of a value less than 51. ________ Compute the probability of a value greater than 72. ________ 1 solutions Answer 133049 by stanbon(57940)   on 2009-01-23 09:44:43 (Show Source): You can put this solution on YOUR website! A normally distributed population has a mean of 60 and a stand deviation of 6. ------------- You need to find the z-value on each of these: For example: Compute the probability of a value between 51 and 66. ________ z(66) = (66-60)/6 = 1 z(51) = (51-60)/6 = -1.5 P(51 < x < 66) = P(-1.5 < z < 1) = 0.77454.. ----------------------------------------------- Compute the probability of a value less than 51. ________ P(z < 51) = P(z< -1.5) = 0.06681.. ----------------------------------------------- Compute the probability of a value greater than 72. ________ z(72) = (72 - 60)/6 = 12/6 = 2 P(x > 72) = P(z > 2) = 0.02275... ------------------- Cheers, Stan H.

Quadratic_Equations/178100: 1. If tn=2n-3, for what value of 'n'is tn=5? Is it -1,1,4 OR 7??????? I think the answer is 4 or 7???????? 2. Which sequence represents an exponential function???? a) {1,6,11,16,21,...} b) {16,8,4,2,1,...} c) {2,8,18,32,50,...} d) {1,8,27,64,125,...} I think it is (b)??? 3. Which function represents a geometric sequence? a) {3*4,3*4^2, 3*4^3,3*4^4,...} b) {3+4,3+4+4,3+4+4+4,...} c) {3*4,3*5,3*6,3*7,...} d) {3+4,3+4^2,3+4^3,...} 1 solutions Answer 133045 by stanbon(57940)   on 2009-01-23 09:20:32 (Show Source): You can put this solution on YOUR website! 1. If tn=2n-3, for what value of 'n'is tn=5? Is it -1,1,4 OR 7??????? I think the answer is 4 or 7???????? Correct -------------------- 2. Which sequence represents an exponential function???? a) {1,6,11,16,21,...} b) {16,8,4,2,1,...} c) {2,8,18,32,50,...} d) {1,8,27,64,125,...} I think it is (b) d = 1^3,3^3,8^3,5^3 Correct ------ 3. Which function represents a geometric sequence? a) {3*4,3*4^2, 3*4^3,3*4^4,...} b) {3+4,3+4+4,3+4+4+4,...} c) {3*4,3*5,3*6,3*7,...} d) {3+4,3+4^2,3+4^3,...} a has a common ratio of 3 =============================== Cheers, Stan H.

Probability-and-statistics/177923: This question is from textbook Applied Statistics I am having the hardest time trying to solve both of the below questions. Can you please help guide me on the right track with this, perhaps get me started with the first step. Any help is greatly appreciated. Thanks! 1- You want to prove that a population mean is not 7. Data is ratio and a large sample size will be used (n = 225). When the sample is done the sample mean is computed to be 7.2 and the sample standard deviation is 1.5. Test the hypothesis using an alpha of 5%. Use formal hypothesis testing and compute the p-value. 2- An associate asks for your help in deciphering the following Anova table, indicating that a test of means was performed on the average age of people at three different locations. Unfortunately the person leaves before you can get any further explanation or detail, but you know the results must be presented before senior staff within twenty minutes! Use the formal 5-step hypothesis testing model to describe the test, the results and interpret the results in conversational English. ANOVA Source of Variation--- SS----- df----- MS----- F------ P-value F crit Between Groups------- 700.0--- 2------ 350.0-- 4.00--- 0.0288 3.32 Within Groups-------- 2625.0-- 30----- 87.5 Total------------------3325.0-- 32 **The above is suppose to be a table. 1 solutions Answer 133033 by stanbon(57940)   on 2009-01-22 23:05:28 (Show Source): You can put this solution on YOUR website! 1- You want to prove that a population mean is not 7. Data is ratio and a large sample size will be used (n = 225). When the sample is done the sample mean is computed to be 7.2 and the sample standard deviation is 1.5. Test the hypothesis using an alpha of 5%. Use formal hypothesis testing and compute the p-value. ----------- Ho: u = 7 Ha: u is not equal to 7 Critical value for 2-tail test and alpha = 5%: +/-1.96 Test Statistic: z(7.2) = (7.2-7)/[1.5/sqrt(225)] = 2 p-value = 2*P(z>2) = 2*0.02275.. = 0.0455.. ----- Conclusion: Sinde the p-value is less than 5%, reject Ho. ========================================================== P.S. I assume you were able to figure out #2. ========================================================== Cheers, Stan H. --------------- Comment on your #2: To see an analysis of EXCEL ANOVA output use Google with that search string. Or just go to: http://org.elon.edu/econ/sac/anova.htm =========================================== Cheers, Stan H.

Quadratic_Equations/178074: Analytic geometry 11) Determine the shortest distance from the origin to the line represented by y=1/2x-2. (PLEASE) Thank you very much 1 solutions Answer 133031 by stanbon(57940)   on 2009-01-22 22:48:24 (Show Source): You can put this solution on YOUR website! Determine the shortest distance from the origin to the line represented by y=1/2x-2. ------------------- Slope of the given line is (1/2). ------------------------------------- Slope of any line perpendicular to the given line is -2 ------------- Equation of a line with slope -2 and passing thru (0,0) is y = -2x ----------------- Intersection of the two lines = ? -2x = (1/2)x-2 (5/2)x = 2 x = 4/5 ------------ y = -2(4/5) = -8/5 ----------------------- Pt. of intersection is (4/5, - 8/5) ============================ Distance from origin to the point of intersection is ? d = sqrt[(4/5)^2 + (-8/5)^2] d = sqrt[(16 + 64)/25] = sqrt[80/25] d = (4/5)sqrt(5) ======================== Cheers, Stan H.

Geometric_formulas/178071: AT 930 AM ANDREW LEFT EXETER FOR PORTSMOUTH ,CYCLING AT 12 MPH AT 10 AM STACY LEFT PORTSMOUTH FOR EXETER,CYCLING AT 16 MPH.THE DISTANCE FROM EXETER TO PORTSMOUTH IS 20 MILES.FIND THE TIME THEY MEET. THIS IS WHAT I HAVE AM I ON THE RIGHT TRACK? 12T 16 (T-1/2)=20 MILES 12T 16T -8=20 18T-8=20 18T=28 T=1.555555556 THEY WILL MEET AT 11 35 AM?????? 1 solutions Answer 133030 by stanbon(57940)   on 2009-01-22 22:40:51 (Show Source): You can put this solution on YOUR website! AT 930 AM ANDREW LEFT EXETER FOR PORTSMOUTH ,CYCLING AT 12 MPH AT 10 AM STACY LEFT PORTSMOUTH FOR EXETER,CYCLING AT 16 MPH.THE DISTANCE FROM EXETER TO PORTSMOUTH IS 20 MILES.FIND THE TIME THEY MEET. THIS IS WHAT I HAVE AM I ON THE RIGHT TRACK? 12T + 16(T-1/2)=20 MILES 12T + 16T -8=20 28T = 28 T = 1 hr 9:30 + 1 hr = 10:30 AM ========================== Cheers, Stan H.

Graphs/178073: Graph y=5x-2 how do I even start this? 1 solutions Answer 133028 by stanbon(57940)   on 2009-01-22 22:30:23 (Show Source): You can put this solution on YOUR website! Graph y=5x-2 how do I even start this? ----You need two points to graph a line. If x = 0, y = 5*0-2 = -2, giving you point (0,-2) -------------- If x = 2, y = 5*2-2 = 8, giving you point (2,8) ----------------- Plot those two points and draw a line thru them to get: ======================================== Cheers, Stan H.

Length-and-distance/178069: TWO JETS LEAVE DENVER AT 9 AM ONE FLYING EAST AT A SPEED 50km/h GREATER THAN THE OTHER,WHICH IS TRAVELING WEST.AT 11 AM THE PLANES ARE 2500 km APART .FIND THERE SPEEDS. I HAVE TRIED SEVERAL WAYS IS THERE AN EASIER WAY TO REMEMBER THE FORMULAS FOR THIS 1 solutions Answer 133027 by stanbon(57940)   on 2009-01-22 22:26:03 (Show Source): You can put this solution on YOUR website! TWO JETS LEAVE DENVER AT 9 AM ONE FLYING EAST AT A SPEED 50km/h GREATER THAN THE OTHER,WHICH IS TRAVELING WEST.AT 11 AM THE PLANES ARE 2500 km APART .FIND THERE SPEEDS. --------------------- East jet DATA: rate = (x+50) km/h ; time = 2 hr ; distance = rt = 2(x+50) km ------------------------------- West jet DATA: rate = x km/h ; time = 2 hr ; distanc e= 2x km ----------------------------- Equation: distance + distance = 2500 2(x+50) + 2x = 2500 4x = 2400 x = 600 km/h (speed of the west jet) x+50 = 650 km/h (speed of the east jet) =========================================== Cheers, Stan H.

Miscellaneous_Word_Problems/178038: )PLEASEEEEEEEEEEE HELPPPPPPPPPPPPPP !!!!!!!! Lolo has 16,65$ and some coins of 1 cent.From this lolo gave 10$ to his friend.He equaly shared the remaining money amoung his brother and sister.If his brother got 2.50$,how many coins of 1 cent did he have at the behining? At first,he had 16,65$ and 0,01x. from this he gave 10$. IT gives me 6,65$ and 0,01x. I dont know after this.pleaseeeee helpppppppppp 1 solutions Answer 133004 by stanbon(57940)   on 2009-01-22 20:10:19 (Show Source): You can put this solution on YOUR website! Lolo has 16,65$ and some coins of 1 cent.From this lolo gave 10$ to his friend.He equaly shared the remaining money amoung his brother and sister.If his brother got 2.50$,how many coins of 1 cent did he have at the beginning? At first,he had 16,65$ and 0,01x. from this he gave 10$. IT gives me 6,65$ and 0,01x ---------------------------------- Now he gave equal shares to his brother and sister: Each received (6,65$ + 0.01x)/2 = (3,325$ + 0.005x) -------------------------------- Brother got 2.50$ so you have the following equation: 3,325$ + 0.005x = 2.50$ -------------------- If your money conversion is 1.00$ = 100 cents you have the following: Equation in cents: 332.5 + 0.005x = 250 ------ Comment: This doesn't make any sense as x would have to be negative. ============== Cheers, Stan H.

Divisibility_and_Prime_Numbers/178039: What is the answer -18.9 divide by 6.3 1 solutions Answer 132997 by stanbon(57940)   on 2009-01-22 19:56:49 (Show Source): You can put this solution on YOUR website! -18.9 divide by 6.3 ------- = -3 =========== Cheers, Stan H.

Geometry_Word_Problems/178014: Is it possible for a leg of a right triangle to be longer than its hypotenuse? If it is, when does this occur? IF it is not, why not? 1 solutions Answer 132990 by stanbon(57940)   on 2009-01-22 19:34:58 (Show Source): You can put this solution on YOUR website! Is it possible for a leg of a right triangle to be longer than its hypotenuse? If it is, when does this occur? IF it is not, why not? ------------------- Impossible. Assume leg b is greater than hypotenuse c. ------------------- Pythagoras says c^2 = a^2 + b^2 Therefore a^2 = c^2 - b^2 -------- But if b > c then b^2 > c^2, and a^2 would be negative. If a is a Real Number a^2 cannot be negative. Therefore both a < c and b < c ================================ Cheers, Stan H.

Quadratic_Equations/178029: Linear System Use the graphing to find the point of intersection of each pair of lines. b) y=1/2x-4 y=2x-1 f) x+y-4=0 5x-y-8=0 Can you pleaseeeeee do both of them because i have to do a, c, d, e, and g for that i need to understand b and f okay thank you sooo much 1 solutions Answer 132986 by stanbon(57940)   on 2009-01-22 19:29:02 (Show Source): You can put this solution on YOUR website! Use the graphing to find the point of intersection of each pair of lines. b) y=1/2x-4 y=2x-1 --- Ans: (-2,-5) ========================================================= f) x+y-4=0 5x-y-8=0 --- Rearrange: y = -x - 4 y = 5x -8 Ans: (2/3 , -14/3) ============================================= Cheers, Stan H.

Rational-functions/178026: Write the expression in the simplest form using the properties of radicals 3√81/5√729 IT SAYS (81) to the 1/3 power divided by (729) to the 1/5 power 1 solutions Answer 132982 by stanbon(57940)   on 2009-01-22 19:20:27 (Show Source): You can put this solution on YOUR website! (81) to the 1/3 power divided by (729) to the 1/5 power ------------ 81^(1/3) = 3*(3^(1/3)) 729^(1/5) = [3^(6)]^(1/5) = 3*(3^(1/5)) ------------------------------------ Dividing you get [3*(3^(1/3))] / [3*(3^(1/5))] The "3" factors cancel and you need to subtract the exponents to get: = 3^(1/3 - 1/5) = 3^(2/15) ================ Cheers, Stan H.

Rational-functions/178011: 14x^2/21x 1 solutions Answer 132978 by stanbon(57940)   on 2009-01-22 18:31:23 (Show Source): You can put this solution on YOUR website! (14x^2) / (21x) Cancel the common factors, such as 7 and x: = (2x) / (3) = (2/3)x ============== Cheers, Stan H.

Numeric_Fractions/177999: I'm in 9th grade. My math teacher said that there is another way to ADD/Subtract improper fractions without making them proper by adding/subtracting the whole numbers and then the fractions. But on my Tests, whenever I do this, I get the answer incorrect.I'm not sure if I'm using this method incorrectly, we never really took any notes on it. Can Anyone tell me how to do this? 1 solutions Answer 132977 by stanbon(57940)   on 2009-01-22 18:25:58 (Show Source): You can put this solution on YOUR website! My math teacher said that there is another way to ADD/Subtract improper fractions without making them proper by adding/subtracting the whole numbers and then the fractions. But on my Tests, whenever I do this, I get the answer incorrect.I'm not sure if I'm using this method incorrectly, we never really took any notes on it. Can Anyone tell me how to do this? ------------------------------ Write the problem vertically (one below the other): Here is a SUBTRACTION Example: .......... 2 3/5 -1 1/2 -------------- Rewrite the problem with the fractions having the same denominator: 2 (6/10) -1 (5/10) ---------------- 1 1/10 ========================= Cheers, Stan H.