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Recent problems solved by 'stanbon'
stanbon answered: 57151 problems
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49050..49079 , 49080..49109 , 49110..49139 , 49140..49169 , 49170..49199 , 49200..49229 , 49230..49259 , 49260..49289 , 49290..49319 , 49320..49349 , 49350..49379 , 49380..49409 , 49410..49439 , 49440..49469 , 49470..49499 , 49500..49529 , 49530..49559 , 49560..49589 , 49590..49619 , 49620..49649 , 49650..49679 , 49680..49709 , 49710..49739 , 49740..49769 , 49770..49799 , 49800..49829 , 49830..49859 , 49860..49889 , 49890..49919 , 49920..49949 , 49950..49979 , 49980..50009 , 50010..50039 , 50040..50069 , 50070..50099 , 50100..50129 , 50130..50159 , 50160..50189 , 50190..50219 , 50220..50249 , 50250..50279 , 50280..50309 , 50310..50339 , 50340..50369 , 50370..50399 , 50400..50429 , 50430..50459 , 50460..50489 , 50490..50519 , 50520..50549 , 50550..50579 , 50580..50609 , 50610..50639 , 50640..50669 , 50670..50699 , 50700..50729 , 50730..50759 , 50760..50789 , 50790..50819 , 50820..50849 , 50850..50879 , 50880..50909 , 50910..50939 , 50940..50969 , 50970..50999 , 51000..51029 , 51030..51059 , 51060..51089 , 51090..51119 , 51120..51149 , 51150..51179 , 51180..51209 , 51210..51239 , 51240..51269 , 51270..51299 , 51300..51329 , 51330..51359 , 51360..51389 , 51390..51419 , 51420..51449 , 51450..51479 , 51480..51509 , 51510..51539 , 51540..51569 , 51570..51599 , 51600..51629 , 51630..51659 , 51660..51689 , 51690..51719 , 51720..51749 , 51750..51779 , 51780..51809 , 51810..51839 , 51840..51869 , 51870..51899 , 51900..51929 , 51930..51959 , 51960..51989 , 51990..52019 , 52020..52049 , 52050..52079 , 52080..52109 , 52110..52139 , 52140..52169 , 52170..52199 , 52200..52229 , 52230..52259 , 52260..52289 , 52290..52319 , 52320..52349 , 52350..52379 , 52380..52409 , 52410..52439 , 52440..52469 , 52470..52499 , 52500..52529 , 52530..52559 , 52560..52589 , 52590..52619 , 52620..52649 , 52650..52679 , 52680..52709 , 52710..52739 , 52740..52769 , 52770..52799 , 52800..52829 , 52830..52859 , 52860..52889 , 52890..52919 , 52920..52949 , 52950..52979 , 52980..53009 , 53010..53039 , 53040..53069 , 53070..53099 , 53100..53129 , 53130..53159 , 53160..53189 , 53190..53219 , 53220..53249 , 53250..53279 , 53280..53309 , 53310..53339 , 53340..53369 , 53370..53399 , 53400..53429 , 53430..53459 , 53460..53489 , 53490..53519 , 53520..53549 , 53550..53579 , 53580..53609 , 53610..53639 , 53640..53669 , 53670..53699 , 53700..53729 , 53730..53759 , 53760..53789 , 53790..53819 , 53820..53849 , 53850..53879 , 53880..53909 , 53910..53939 , 53940..53969 , 53970..53999 , 54000..54029 , 54030..54059 , 54060..54089 , 54090..54119 , 54120..54149 , 54150..54179 , 54180..54209 , 54210..54239 , 54240..54269 , 54270..54299 , 54300..54329 , 54330..54359 , 54360..54389 , 54390..54419 , 54420..54449 , 54450..54479 , 54480..54509 , 54510..54539 , 54540..54569 , 54570..54599 , 54600..54629 , 54630..54659 , 54660..54689 , 54690..54719 , 54720..54749 , 54750..54779 , 54780..54809 , 54810..54839 , 54840..54869 , 54870..54899 , 54900..54929 , 54930..54959 , 54960..54989 , 54990..55019 , 55020..55049 , 55050..55079 , 55080..55109 , 55110..55139 , 55140..55169 , 55170..55199 , 55200..55229 , 55230..55259 , 55260..55289 , 55290..55319 , 55320..55349 , 55350..55379 , 55380..55409 , 55410..55439 , 55440..55469 , 55470..55499 , 55500..55529 , 55530..55559 , 55560..55589 , 55590..55619 , 55620..55649 , 55650..55679 , 55680..55709 , 55710..55739 , 55740..55769 , 55770..55799 , 55800..55829 , 55830..55859 , 55860..55889 , 55890..55919 , 55920..55949 , 55950..55979 , 55980..56009 , 56010..56039 , 56040..56069 , 56070..56099 , 56100..56129 , 56130..56159 , 56160..56189 , 56190..56219 , 56220..56249 , 56250..56279 , 56280..56309 , 56310..56339 , 56340..56369 , 56370..56399 , 56400..56429 , 56430..56459 , 56460..56489 , 56490..56519 , 56520..56549 , 56550..56579 , 56580..56609 , 56610..56639 , 56640..56669 , 56670..56699 , 56700..56729 , 56730..56759 , 56760..56789 , 56790..56819 , 56820..56849 , 56850..56879 , 56880..56909 , 56910..56939 , 56940..56969 , 56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179, >>NextPolynomials-and-rational-expressions/182298: Determine the number of factors of ^256-1 and list them. Support your answer
by showing logical algebraic steps and explain how you arrived at your answer.
Hint: Note that 256=2^8 . This problem requires understanding both, the prime factorization (section 5.1) and also factoring difference of two squares from the "special products" rules (section 5.2). After studying factoring, answering this DQ involves synthesis and some deep thinking in your part. Try to do your best.
1 solutions
Answer 136832 by stanbon(57219)   on 2009-02-17 08:26:47 (Show Source):
You can put this solution on YOUR website!256-1
= 2^8 - 1
= (2^4 -1)(2^4 + 1)
= (2^2 -1)(2^2 +1)(2^2+i)(2^2-i)
= (2-1)(2+1)(2+i)(2-i)(4+i)(4-i)
= 1*3*(2+i)(2-i)(4+i)(4-i)
----------------------------------
I'm not sure this is what you want and I don't know
what you mean when you put ^ in front of 256-1.
.
----------------------------------
Cheers,
Stan H.
|
Coordinate-system/182300: What are coordinate planes
1 solutions
Answer 136830 by stanbon(57219) on 2009-02-17 08:18:47 (Show Source):
You can put this solution on YOUR website!Use Google to get a thorough explanation with illustrations.
------------
Draw two perpendicular intersecing lines.
Label the horizontal line "x"
Label the vertical line "y"
-----------------------------
Those lines determine a plane which is called a coordinate plane.
===================================================
Cheers,
Stan H.
|
logarithm/182304: I need to know how to solve this problem please log7 49
1 solutions
Answer 136827 by stanbon(57219) on 2009-02-17 08:10:25 (Show Source):
You can put this solution on YOUR website!solve this problem please log7 49
---------
log means exponent or power.
---------------
You are asked "what is the power of 7 that gives you 49?"
----
The answer is "2".
So log7 49 = 2
====================
Cheers,
Stan H.
|
Functions/182287: 1. 0
----=0( that's 89 to the second power is it true or false)
89^2
2.(3x^4)^-3 3.(16)^3/4 4. x^1/2times x^3/2
--------
y ----------------
x^-1
1 solutions
Answer 136826 by stanbon(57219) on 2009-02-17 08:08:03 (Show Source):
You can put this solution on YOUR website! 0
----=0( that's 89 to the second power is it true or false)
89^2
yes, it's true. 0 divided by any number, other than 0, is zero.
-------------------------------------------------
2.(3x^4)^-3 3.(16)^3/4 4. x^1/2times x^3/2
--------
y ----------------
x^-1
----------------------------------------------------------------
#2. = 1/[(27x^12)y]
------------------
#3 = 2^3 = 8
--------------------
#4 = x^(1/2 + 3/2)/x^-1
= x^2*x = x^3
================
Cheers,
Stan H.
|
Polynomials-and-rational-expressions/182246: Pam has brown eyes and Bob has blue eyes. Brown genes B are dominant over blue eyes b. A person with genes BB or Bb has brown eyes. Someone with genes bb has blue eyes. Suppose Pam's genes for eye color are Bb.
a. Write an expression for the possible eye coloring of Pam and Bob's children.
b. What is the probability that a child of Pam and bob would have blue eyes?
Please help! I tried it, but I don't know if I am right. For A, I have no idea how to do that. For B, I have 3/4 b, but i'm not sure if i'm right.
1 solutions
Answer 136798 by stanbon(57219) on 2009-02-16 21:07:41 (Show Source):
You can put this solution on YOUR website!Pam has brown eyes and Bob has blue eyes. Brown genes B are dominant over blue eyes b. A person with genes BB or Bb has brown eyes. Someone with genes bb has blue eyes. Suppose Pam's genes for eye color are Bb.
------------
a. Write an expression for the possible eye coloring of Pam and Bob's children.
From Bob: b or b
From Pam: b or B
--------------
Expression for possible eye coloring: bb(blue),bb(blue),bB(brown),bB(brown)
-----------------------------------------------------------------
b. What is the probability that a child of Pam and bob would have blue eyes?
2/4 = 1/2
------------------------------
Chers,
Stan H.
|
Travel_Word_Problems/182256: five friends drove at an average rate of 50 miles per hour to a weekend retreat. On the way home, they took the same route but averaged 75 miles per hour. What was the distance between home and the retreat if the round trip took 10 hours?
1 solutions
Answer 136792 by stanbon(57219) on 2009-02-16 20:51:11 (Show Source):
You can put this solution on YOUR website!five friends drove at an average rate of 50 miles per hour to a weekend retreat. On the way home, they took the same route but averaged 75 miles per hour. What was the distance between home and the retreat if the round trip took 10 hours?
------------------
To the retreat DATA:
rate = 50 mph ; distance = x miles : time = d/r = x/50 hrs
-----------------------------------------------------------
From the retreat DATA:
rate = 75 mph ; distance = x miles ; time = d/r = x/75 hrs
-------------------------------------------------------
Equation:
x/50 + x/75 = 10
75x + 50x = 50*75*10
125x = 50*75*10
x = 300 miles
------------------
Cheers,
Stan H.
|
Average/182255: the average of x,y, and z is 80. IF two of the numbers are 74 and 78, then what is the other number?
1 solutions
Answer 136783 by stanbon(57219) on 2009-02-16 20:06:52 (Show Source):
You can put this solution on YOUR website!the average of x,y, and z is 80. IF two of the numbers are 74 and 78, then what is the other number?
---------------------
(74 + 78 + z)/3 = 80
152 + z = 240
z = 88
=====================
Cheers,
Stan H
=====================
|
Equations/182253: 2x - 5 sqrt x +2 =0
1 solutions
Answer 136780 by stanbon(57219) on 2009-02-16 19:58:02 (Show Source):
You can put this solution on YOUR website!2x - 5 sqrt x + 2 =0
--------
2x - 4sqrt(x) - sqrt(x) + 2 = 0
2sqrt(x)[sqrt(x)-2] - [sqrt(x) -2] = 0
[sqrt(x)-2] [2sqrt(x) -1] = 0
sqrt(x) = 2 or 2sqrt(x) = 1
x = 4 or x = 1/4
------------------------------------------------
Cheers,
Stan H.
------------------------------------------------
|
Trigonometry-basics/182252: This question is from textbook saxon algebra 2
Point Q is located on the terminal side of angle 0 with a dash through it and has coordinates (-8,6). Find the exact value of the six trigonometric functions for 0 with a dash through it.
I have figured it out to be sin=6/10, cos=-8/10, tan=-6/8, csc=10/6, sec=-10/8, cot=-8/10. My questions are am I correct, and should they be in simplest form?
1 solutions
Answer 136778 by stanbon(57219) on 2009-02-16 19:52:01 (Show Source):
You can put this solution on YOUR website!Point Q is located on the terminal side of angle 0 with a dash through it and has coordinates (-8,6). Find the exact value of the six trigonometric functions for 0 with a dash through it.
I have figured it out to be sin=6/10, cos=-8/10, tan=-6/8, csc=10/6, sec=-10/8, cot=-8/10. My questions are am I correct, and should they be in simplest form?
-------------------------
Since x = -8 and y = 6, r = sqrt(64+36) = sqrt(100) = 10
---------------------
So:
sin(theta) = y/r = 6/10
etc.
You could put them in simplest form; they are correct.
=========================================================
Cheers,
Stan H.
|
Probability-and-statistics/181941: Regression analysis of free throws by 29 NBA teams during the 2002-2003 season revealed the fitted regression Y = 55.2 + .73X (R2 = .874, Syx = 53.2) where Y = total free throws made and X = total free throws attempted. The observed range of X was from 1, 620 (New York Knicks) to 2,383 (Golden State Warriors) (a.) Find the expected number of free throws made for a team that shoots 2,000 free throws. (b.) Do you think that the intercept is meaningful? Hint: Make a scatter plot and let Excel fit the line (c.) Use the quick rule to make a 95 percent predicition interval for Y when X = 2,000.
FGP FTP Points Fouls TrnOvr
FGP 1.000
FTP - 0.039 1.000
Points 0.475 0.242 1.000
Fouls - 0.014 0.211 0.054 1.000
TrnOvr 0.276 0.028 0.033 0.340 1.000
Rbnds 0.436 0.137 0.767 - 0.032 0.202
1 solutions
Answer 136774 by stanbon(57219) on 2009-02-16 19:36:27 (Show Source):
You can put this solution on YOUR website!Regression analysis of free throws by 29 NBA teams during the 2002-2003 season revealed the fitted regression Y = 55.2 + .73X
(R2 = .874, Syx = 53.2) where Y = total free throws made and X = total free throws attempted.
The observed range of X was from 1, 620 (New York Knicks) to 2,383 (Golden State Warriors)
--------------------------------------------
(a.) Find the expected number of free throws made for a team that shoots 2,000 free throws.
Ans: Y(2000) = 55.2 + 0.73*2000 = 1515
----------------------------------------------
(b.) Do you think that the intercept is meaningful? Hint: Make a scatter plot and let Excel fit the line
I'll leave that to you.
-----------------------------
(c.) Use the quick rule to make a 95 percent predicition interval for Y when X = 2,000.
I am not familiar with your Quick Rule.
-------------------------------------
Cheers,
Stan H.
================================
FGP FTP Points Fouls TrnOvr
FGP 1.000
FTP - 0.039 1.000
Points 0.475 0.242 1.000
Fouls - 0.014 0.211 0.054 1.000
TrnOvr 0.276 0.028 0.033 0.340 1.000
Rbnds 0.436 0.137 0.767 - 0.032 0.202
|
Probability-and-statistics/181962: Tutors, I am not understanding this problem please help:
in Business and Economics
14.16 (a) Plot the data on U.S. general aviation shipments. (b) Describe the pattern and discuss possible
causes. (c) Would a fitted trend be helpful? Explain. (d) Make a similar graph for 1992–2003 only.
Would a fitted trend be helpful in making a prediction for 2004? (e) Fit a trend model of your
choice to the 1992–2003 data. (f) Make a forecast for 2004, using either the fitted trend model or
a judgment forecast. Why is it best to ignore earlier years in this data set? Airplanes
U.S. Manufactured General Aviation Shipments, 1966–2003
Year Planes Year Planes Year Planes Year Planes
1966 15,587 1976 15,451 1986 1,495 1996 1,053
1967 13,484 1977 16,904 1987 1,085 1997 1,482
1968 13,556 1978 17,811 1988 1,143 1998 2,115
1969 12,407 1979 17,048 1989 1,535 1999 2,421
1970 7,277 1980 11,877 1990 1,134 2000 2,714
1971 7,346 1981 9,457 1991 1,021 2001 2,538
1972 9,774 1982 4,266 1992 856 2002 2,169
1973 13,646 1983 2,691 1993 870 2003 2,090
1974 14,166 1984 2,431 1994 881
1975 14,056 1985 2,029 1995 1,028
Source: U.S. Manufactured General Aviation Shipments, Statistical Databook 2003, General Aviation Manufacturers Association,
1 solutions
Answer 136773 by stanbon(57219) on 2009-02-16 18:51:11 (Show Source):
You can put this solution on YOUR website!(a) Plot the data on U.S. general aviation shipments.
Put the years on the horizontal axis and the # of Planes on the vertical.
---------------------------------------------------------
(b) Describe the pattern and discuss possible causes.
1966-1970 sales go down
1971-1979 sales go up
1980-1993 sales go down
1994-2000 sales go up
2001-2004 sales go down
------------------------------------------------
(c) Would a fitted trend be helpful? Explain.
Not sure what youmean by a fitted trend
---------------------------------------------
(d) Make a similar graph for 1992–2003 only.
You should be able to do that.
----------------
Would a fitted trend be helpful in making a prediction for 2004?
?
------------------------------------
(e) Fit a trend model of your
choice to the 1992–2003 data.
(f) Make a forecast for 2004, using either the fitted trend model or
a judgment forecast.
Why is it best to ignore earlier years in this data set?
Your opinion
------------------
Cheers,
Stan H.
============================================
Airplanes
U.S. Manufactured General Aviation Shipments, 1966–2003
Year Planes Year Planes Year Planes Year Planes
1966 15,587 1976 15,451 1986 1,495 1996 1,053
1967 13,484 1977 16,904 1987 1,085 1997 1,482
1968 13,556 1978 17,811 1988 1,143 1998 2,115
1969 12,407 1979 17,048 1989 1,535 1999 2,421
1970 7,277 1980 11,877 1990 1,134 2000 2,714
1971 7,346 1981 9,457 1991 1,021 2001 2,538
1972 9,774 1982 4,266 1992 856 2002 2,169
1973 13,646 1983 2,691 1993 870 2003 2,090
1974 14,166 1984 2,431 1994 881
1975 14,056 1985 2,029 1995 1,028
Source: U.S. Manufactured General Aviation Shipments, Statistical Databook 2003, General Aviation Manufacturers Association,
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Linear-systems/182242: How do you solve two problems at the same time and get a coordinationes
example 2c-d=-2 second problem is 4c+d=20
1 solutions
Answer 136769 by stanbon(57219) on 2009-02-16 18:38:18 (Show Source):
You can put this solution on YOUR website! 2c-d=-2
4c+d=20
--------
This is called a system of equations.
You are asked to find a solution that
satisfies both equations.
---------
Add the two equation to solve for "c":
6c = 18
c = 3
----------------
Substitute into 2c - d = -2 to solve for "d":
2*3 - d = -2
d = 8
-------------------
Check the answer in both equations:
2c-d=-2
2*3 - 8 = -2
6 - 8 = -2
-2 = -2
--------------------
4c+d=20
4*3 + 8 = 20
12 + 8 = 20
20 = 20
====================
Both check out so the solution is c=3, d=8
============================================
Cheers,
Stan H.
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Probability-and-statistics/181991: Hi Tutors! This is one of the questions I'm stuck on. Please show me how to do it.
A traffic officer has a concealed radar unit that she uses to measure the speed of traffic crossing a bridge. She finds that the mean speed is 84km/h and the standard deviation is 5km/h.
a) What probability distribution is most likely to model the speed of the traffic crossing the bridge? Give reasons for your choice that are related to the problem and give any parameters for the distribution.
b) If the speed limit on the bridge is 90km/h, find out how many out of 200 cars she would expect to find to be breaking the limit.
Thank you very very much for your help tutors!!
1 solutions
Answer 136767 by stanbon(57219) on 2009-02-16 18:18:12 (Show Source):
You can put this solution on YOUR website!A traffic officer has a concealed radar unit that she uses to measure the speed of traffic crossing a bridge. She finds that the mean speed is 84km/h and the standard deviation is 5km/h.
-------------------------------------------
a) What probability distribution is most likely to model the speed of the traffic crossing the bridge? Give reasons for your choice that are related to the problem and give any parameters for the distribution.
Ans: Normal Distribution because the data is continuous, numerical, and tends
to cluster around an average speed.
----------------------------
b) If the speed limit on the bridge is 90km/h, find out how many out of 200 cars she would expect to find to be breaking the limit.
If the mean is at 84 km/h, 90km/h is (90-84)/5 = 6/5 = 1.2 standard deviations
above the mean.
The percent of the population that is more than 1.2 standard deviations above the mean is 11.5%.
11.5% of 200 is 23 persons.
=====================================
Cheers,
Stan H.
=====================================
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Probability-and-statistics/181994: This question is from textbook Elementary Statistics
Review Exercises
#16.
The average cost of a certain type of seed per acre is $42. The standard deviation is $3. Using Chebyshev's theorem, find the range in which at least 88.89% of the dte values will fall.
Please help me with this problem I understand that 1-1/k2 but i don't know who to apply it... please help me.
1 solutions
Answer 136764 by stanbon(57219) on 2009-02-16 18:01:17 (Show Source):
You can put this solution on YOUR website!The average cost of a certain type of seed per acre is $42. The standard deviation is $3. Using Chebyshev's theorem, find the range in which at least 88.89% of the the values will fall.
Please help me with this problem I understand that 1-1/k2 but i don't know who to apply it... please help me.
------------------------------------
Equation:
1 - (1/k^2) = 0.8889
1/k^2 = 0.1111111
k^2 = 9
k = 3
----------------
You want the range of values within 3 standard deviations of the mean.
42-3*(standard dev.) <= cost <= 42+3(standard deviation)
42-9 <= cost <= 42+9
$33 <= cost <= $51
============================
Cheers,
Stan H.
====================
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Travel_Word_Problems/182233: This question is from textbook Algebra 1
Catherine is camping along a river. It takes her 1.5 hours to paddle her canoe 6 miles upstream from her campsite. Catherine turns her canoe around and returns 6 miles downstream to her campsite in exactly 1 hour. What is the rate of the rivers current and the rate of Catherines paddeling in still water?
1 solutions
Answer 136762 by stanbon(57219) on 2009-02-16 17:17:07 (Show Source):
You can put this solution on YOUR website!Catherine is camping along a river. It takes her 1.5 hours to paddle her canoe 6 miles upstream from her campsite. Catherine turns her canoe around and returns 6 miles downstream to her campsite in exactly 1 hour. What is the rate of the rivers current and the rate of Catherines paddeling in still water?
-----------
Upstream DATA:
distance = 6 miles: time = 1.5 hours: rate = 6/(3/2) = 4 mph
---------------------
Downstream DATA:
distance + 6 miles ; time = 1 hr ; rate = 6/1 = 6 mph
----------------------
Equations:
b - c = 4 mph
b + c = 6 mph
--------------
2b = 10
b = 5 mph (speed of the boat in still water)
---
Substitute to solve for "c":
5 - c = 4
c = 1 mph (speed of the currect)
====================================
Cheers,
Stan H.
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Probability-and-statistics/182047: Hi can you please help me solve for this problem from this book: Doane−Seward: Applied Statistics in Business and Economics,chapter 10:
A new drug is being tested to see if it reduces the number of migraine headaches. Assuming equal variances, at α = .025, do these samples of number of monthly migraines from eight volunteers who are taking the drug and eight who are not show a significant reduction in the mean number of monthly migraine headaches? (See Science News 165, no. 9 [February 28, 2004].)
Topiramate: 3 3 2 4 3 4 3 5
Control: 3 3 5 5 7 5 5 4
Thank you
1 solutions
Answer 136752 by stanbon(57219) on 2009-02-16 16:32:54 (Show Source):
You can put this solution on YOUR website!A new drug is being tested to see if it reduces the number of migraine headaches. Assuming equal variances, at α = .025, do these samples of number of monthly migraines from eight volunteers who are taking the drug and eight who are not show a significant reduction in the mean number of monthly migraine headaches? (See Science News 165, no. 9 [February 28, 2004].)
-------------
Topiramate: 3 3 2 4 3 4 3 5
u1 bar = 3.375
s1 = 0.916
-------------
Control: 3 3 5 5 7 5 5 4
u2 bar = 4.625
s2 = 1.302
----------------
Ho: u1-u2 = 0
Ha: u1 - u2 < 0
Unknown variances; assumed equal:
test statistic
pooled estimate of common variance: sp^2 = [6*0.016^2 + 6*1.302^2]/[14]= 0.05
t statistic: t = (3.375-4.625)/sqrt[0.05(1/8 + 1/8)] = -11.18
p-value: P(-20< t<-11.18 with df = 8+8-2 = 14) = 0.00000001416
---
Conclusion: Since p-value is less than alpha, reject Ho.
The medicine is more effective than the control.
===================================================
Cheers,
Stan H.
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Probability-and-statistics/182048: Hi can you please help me solve for this problem from book: Doane−Seward: Applied Statistics in Business and Economics, chapter 10:
Blockbuster is testing a new policy of waiving all late fees on DVD rentals using a sample of 10 randomly chosen customers. (a) At α = .10, does the data show that the mean number of monthly rentals has increased? (b) Is the decision close? (c) Are you convinced?
Customer: 1,2,3,4,5,6,7,8,9,10
No Late Fee: 14,12,14,13,10,13,12,10,13,13
Late Fee: 10,7,10,13,9,14,12,7,13,9
Thank you
1 solutions
Answer 136745 by stanbon(57219) on 2009-02-16 15:58:05 (Show Source):
You can put this solution on YOUR website!book: Doane−Seward: Applied Statistics in Business and Economics, chapter 10:
Blockbuster is testing a new policy of waiving all late fees on DVD rentals using a sample of 10 randomly chosen customers.
(a) At α = .10, does the data show that the mean number of monthly rentals has increased?
Ho: u(d) = 0
Ha: u(d) > 0
---------------
The differences: 4,5,4,0,1,-1,0.3.0.4
mean of the sample: u(d) bar = 20/10 = 2
stand Dev of the sample; 2.211
Test statistic: t(2) = 2/[2.211/sqrt(10)] = 2.86
p-value: P(t > 2.86 with df = 9) = 0.009
--------------------
(b) Is the decision close?
No since alpha = 10% and p= 0.9%
---------------------------
(c) Are you convinced?
I'll leave that to you.
---
Customer: 1,2,3,4,5,6,7,8,9,10
No Late Fee: 14,12,14,13,10,13,12,10,13,13
Late Fee:... 10, 7,10,13, 9,14,12,7,13,9
---
----------------
Cheers,
Stan H.
t(2) = 2/
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Probability-and-statistics/182133: Ben rolls a 1-6 number cube. Find each probability.
1.) Ben rolls a prime number or an odd number.
Mr. Rodney's English class is made up of 28 students. He has 6 ESL students make up 1/5 of the remedial students and 3/5 of the advanced learners.
2.)What is the probability that a student is remedial and NOT ESL?
Please explain how do you know.
Please answer me as soon as you could.
Thank you for your help.
1 solutions
Answer 136740 by stanbon(57219) on 2009-02-16 15:06:58 (Show Source):
You can put this solution on YOUR website!Ben rolls a 1-6 number cube. Find each probability.
1.) Ben rolls a prime number or an odd number.
---
P(prime or odd) = P(prime) + P(odd) - P(prime AND odd)
P(prime or odd) = 3/6 + 3/6 -- 2/6 = 4/6 = 2/3
------------------------------------------------------
Mr. Rodney's English class is made up of 28 students. He has 6 ESL students make up 1/5 of the remedial students and 3/5 of the advanced learners.
2.)What is the probability that a student is remedial and NOT ESL?
---
Your data is contradictory. If 6 ESL students make up 1/5 of the remedial
students there must be 30 remedial students in the class. But you say
there are a total of 28 students in the class. That information is
contradictory.
---------------------
Cheers,
Stan H.
|
Probability-and-statistics/182131: This question is from textbook Compound Events
Could you explain everything that you do?
Numbers 1-10 are written on cards and placed in a bag. Find each probability.
7. choosing at lease one even number when selecting 2 cards from the bag
Five years after 650 high school senior graduated, 400 had a college degree and 310 were married. Half of the students with a college degree were married.
8. What is the probability that a student has a college degree or is married?
Please answer me as soon as you could.
Thank you for your help.
1 solutions
Answer 136705 by stanbon(57219) on 2009-02-16 07:27:16 (Show Source):
You can put this solution on YOUR website!Numbers 1-10 are written on cards and placed in a bag. Find each probability.
7. choosing at lease one even number when selecting 2 cards from the bag
P(getting one even) = 1- P[getting 2 even or getting 0 even]
= 1 - P(getting 2 even) - P(getting 2 odd)
= 1 - 5C2/10C2 - 5C2/10C2
= 1 - 10/45 - 10/45
= 25/45
= 5/9
============
Five years after 650 high school senior graduated, 400 had a college degree and 310 were married. Half of the students with a college degree were married.
8. What is the probability that a student has a college degree or is married?
P(cd or married) = P(cd) + P(married) - P(cd and married)
= 400/650 + 310/650 - 200/650
= 510/650
= 51/65
===============
Cheers,
Stan H.
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Human-and-algebraic-language/182141: I appreciate any help on this problem:
Hannah has taken three exams and earned scores of 85,72, and 77 out of a possible 100 points. She needs an average of at least 80 to earn a B in the course. What range of scores on the fourth (and last) 100-point test will guarantee a B in the course?
This is the equation I set up for the problem: ((85+72=77+b)/4)=80
And I know the lowest possible grade is 86 but I'm not sure how to set up the answer for this problem and this teacher takes off points for any little mistake made in getting the answer.
Thanks!
1 solutions
Answer 136704 by stanbon(57219) on 2009-02-16 07:17:29 (Show Source):
You can put this solution on YOUR website!Hannah has taken three exams and earned scores of 85,72, and 77 out of a possible 100 points. She needs an average of at least 80 to earn a B in the course. What range of scores on the fourth (and last) 100-point test will guarantee a B in the course?
-----------------------------------------
This is the inequality I set up for the problem: ((85+72+77+b)/4) >=80
80 <= (234+b)/4
320 <= 234 + b
86 <= b
----
Range: 86 <= b <= 100
-----------------
Cheers,
Stan H.
|
Coordinate-system/182142: Appreciate any help on this problem:
Give the center and radius of the circle 
I think the center is (3,4) but I wasn't sure about the radius. I would appreciate any step by step help.
Thanks!
1 solutions
Answer 136703 by stanbon(57219) on 2009-02-16 07:07:25 (Show Source):
You can put this solution on YOUR website!Give the center and radius of the circle
I think the center is (3,4) but I wasn't sure about the radius. I would appreciate any step by step help.
--------------------------------------
x^2+y^2+6x-8y-56=0
Complete the square on the x and on the y terms to get:
x^2 + 6x + ? + y^2 - 8y + ? = 56 + ?
x^2 + 6x + 9 + y ^2 - 8y + 16 = 56 + 9 + 16
(x+3)^2 + (y-4)^2 = 81
--------------------------
Center is (-3,4); radius = sqrt(81) = 9
==========================================
Cheers,
Stan H.
|
Linear-systems/182143: Hello Tutors!I have a problem that I'm stuck with here.
1) The equations of three planes are:
3x + 2y + 7z = 25
2x + y + 4z = 14
5x + 3y + 11z = 39
Solve the above system of equations. State whether this system is consistent or inconsistent and how many solutions are there?
Thank you for your help!!
1 solutions
Answer 136702 by stanbon(57219) on 2009-02-16 07:03:21 (Show Source):
You can put this solution on YOUR website!The equations of three planes are:
3x + 2y + 7z = 25
2x + y + 4z = 14
5x + 3y + 11z = 39
--------------
The determinant of the coefficient matrix is zero,
so the system is inconsistent. There are no solutions.
=================
Cheers
Stan H.
|
Mixture_Word_Problems/182146: A chemist has prepared two acid solutions, one of which is 4% acid by volume, another 11% acid. HOw many cubic centimeters of each should the chemist mix together to obtain 50cm^3 of 6.24% solution?
1 solutions
Answer 136701 by stanbon(57219) on 2009-02-16 06:59:10 (Show Source):
You can put this solution on YOUR website!A chemist has prepared two acid solutions, one of which is 4% acid by volume, another 11% acid. HOw many cubic centimeters of each should the chemist mix together to obtain 50cm^3 of 6.24% solution?
---------------
Equation:
acid + acid = acid
0.04x + 0.11(50-x) = 0.0624*50
Multiply thru by 10000 to get:
400x + 1100(50-x) = 624*50
400x + 1100*50 - 1100x = 624*50
-700x = -476*50
x = 34 cm^3 (amt. of 4% solution in the mixture)
50-x = 50-34 = 16 cm^3 (amt. of 11^ solution in the mixture)
================================================================
Cheers,
Stan H.
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Polynomials-and-rational-expressions/182149: 1. can polynomials have coefficients which are not real numbers?
2. can a linear polynomial ever have a zero or root which is not real?
3.what's the method to find zeroes of a cubic polynomial?
1 solutions
Answer 136700 by stanbon(57219) on 2009-02-16 06:52:11 (Show Source):
You can put this solution on YOUR website!1. can polynomials have coefficients which are not real numbers?
Ans: Sure, for example (sqrt(2))x^2 + (sqrt(5))x + 3
------------------------------------------------------------
2. can a linear polynomial ever have a zero or root which is not real?
Ans: For y = mx + b the root is always -b/m. If b or m are
not Real the root will not be Real.
Ex: y = sqrt(2)x + 3 has root -3/sqrt(2)
----------------------------------------------
3.what's the method to find zeroes of a cubic polynomial?
Ans: Google will find you the forms taht can be used but graphing
with a scietific calculator is the fastest way to find Real roots
of a cubic.
====================
Cheers,
Stan H.
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Quadratic_Equations/182092: How do I come up with a real life application for a quadratic function
1 solutions
Answer 136678 by stanbon(57219) on 2009-02-15 21:22:49 (Show Source):
You can put this solution on YOUR website!A ball is projected from ground level, climes to a height of h feet
and returns to the ground after 5 seconds. What is the equation of
the trajectory?
--
h(t) = x(x-5) = x^2-5x
===========================
Cheers,
Stan H.
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Rate-of-work-word-problems/182103: A water tank has an inlet pipe and a drain
pipe. A full tank can be emptied in 30 minutes if the drain
is opened and an empty tank can be filled in 45 minutes
with the inlet pipe opened. If both pipes are accidentally
opened when the tank is full, then how long will it take to
empty the tank?
1 solutions
Answer 136677 by stanbon(57219) on 2009-02-15 21:16:49 (Show Source):
You can put this solution on YOUR website!A water tank has an inlet pipe and a drain pipe.
------------
A full tank can be emptied in 30 minutes if the drain
is opened and an empty tank can be filled in 45 minutes
with the inlet pipe opened.
-----------------------------
If both pipes are accidentally opened when the tank is full,
then how long will it take to empty the tank?
------------------------------
Drain pipe DATA:
time = 30 min/job ; rate = (1/30) job/min
----------------------------------------
Fill pipe DATA:
time = 45 min/job ; rate = 1/45 job/min
----------------------------------------
Together DATA:
time = x min/job ; rate = 1/x job/min
---------------------------------------
Equations:
fill rate - drain rate = together emptying rate
1/30 - 1/45 = 1/x
45x-30x 30*45
15x = 30*45
x = 90 min (time to empty the tank when both pipes are open
================================================
Chers,
Stan H.
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Trigonometry-basics/182085: I am working with a non-right triangle with Angle A and Angle B unknown. Angle C measures 36.5 degrees. Side a=13, b=?, c=7.8. The question states that sin(36.5)=0.5948, and cos(36.5)=0.8039. I am having trouble figuring out how to calculate sin A. Can someone out there please help me??? I have tried using the law of cosines but I ran into a dead end quickly on that try. Thank you for any help that you can provide!!
1 solutions
Answer 136674 by stanbon(57219) on 2009-02-15 20:56:57 (Show Source):
You can put this solution on YOUR website!I am working with a non-right triangle with Angle A and Angle B unknown. Angle C measures 36.5 degrees. Side a=13, b=?, c=7.8. The question states that sin(36.5)=0.5948, and cos(36.5)=0.8039. I am having trouble figuring out how to calculate sin A.
------------------------
Use the Law of Sines:
SinA /a = sinC/c
---------------
Sin(A)/13 = sin(36.5)/7.8
sin(A) = 13[sin(36.5)/7.8]
sin(A) = 0.991
===================
Cheers,
Stan H.
|
Inequalities/182098: This question is from textbook pre-algebra
The Jaspers collect nickels,dimes,and quarters in a jar. When they count the change in the jar there are twice as many nickels as there are quarters. If there is $15.30 in dimes and $74.80 in all how many quarters are there?
1 solutions
Answer 136673 by stanbon(57219) on 2009-02-15 20:50:38 (Show Source):
You can put this solution on YOUR website!The Jaspers collect nickels,dimes,and quarters in a jar. When they count the change in the jar there are twice as many nickels as there are quarters. If there is $15.30 in dimes and $74.80 in all how many quarters are there?
------------------------
Equations:
Quantity Equation: n = 2q
Value Equation: 5n + 1530 + 25q = 7480 cents
-----------------------------------
Substitute to love for "q":
5*2q + 1530 + 25q = 7480
35q = 5950
q = 170 (# of quarters)
-------
Since n = 2q, n = 340 (# of nickels)
------------
Since # of dimes = 1530/10 = 153 (# of dimes)
=================================================
Cheers,
Stan H.
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