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Recent problems solved by 'stanbon'
stanbon answered: 57314 problems
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2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 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53010..53039 , 53040..53069 , 53070..53099 , 53100..53129 , 53130..53159 , 53160..53189 , 53190..53219 , 53220..53249 , 53250..53279 , 53280..53309 , 53310..53339 , 53340..53369 , 53370..53399 , 53400..53429 , 53430..53459 , 53460..53489 , 53490..53519 , 53520..53549 , 53550..53579 , 53580..53609 , 53610..53639 , 53640..53669 , 53670..53699 , 53700..53729 , 53730..53759 , 53760..53789 , 53790..53819 , 53820..53849 , 53850..53879 , 53880..53909 , 53910..53939 , 53940..53969 , 53970..53999 , 54000..54029 , 54030..54059 , 54060..54089 , 54090..54119 , 54120..54149 , 54150..54179 , 54180..54209 , 54210..54239 , 54240..54269 , 54270..54299 , 54300..54329 , 54330..54359 , 54360..54389 , 54390..54419 , 54420..54449 , 54450..54479 , 54480..54509 , 54510..54539 , 54540..54569 , 54570..54599 , 54600..54629 , 54630..54659 , 54660..54689 , 54690..54719 , 54720..54749 , 54750..54779 , 54780..54809 , 54810..54839 , 54840..54869 , 54870..54899 , 54900..54929 , 54930..54959 , 54960..54989 , 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56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179 , 57180..57209 , 57210..57239 , 57240..57269 , 57270..57299 , 57300..57329, >>NextLength-and-distance/184276: This question is from textbook Geometry
How can you describe a transformation just looking at a graph? 1 solutions
Answer 138289 by stanbon(57387) on 2009-02-28 19:50:09 (Show Source):
You can put this solution on YOUR website!How can you describe a transformation just looking at a graph?
------------
increasing, decreasing, symmetric, continuous, discontinuous,
a line, a parabola, a hyperbola, a cubic, etc.
Cheers,
Stan H.
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Miscellaneous_Word_Problems/184273: Talia's Tallitot. Talia plans to make tallitot (prayer shawls) and matching kipot (prayer hats) from a bolt of material. The fabric she plans to use is 250 yards long. She will need 2 yards of material for each tallit (prayer shawl) and (1/6) of a yard for each kipah (prayer hat). She also plans to put tzitzit (fringes) on the tallit and will need 1 yard of cord for each tallit. The kipot will not have any fringes. She has 100 yards of cord to use for the tzitzit.
1-1. Write two equations to use to solve for how many kipot and tallitot she can make from the supplies on hand. Let t equal the number of tallitot made and k equal the number of kipot made.
1 solutions
Answer 138288 by stanbon(57387) on 2009-02-28 19:45:35 (Show Source):
You can put this solution on YOUR website!Talia's Tallitot. Talia plans to make tallitot (prayer shawls) and matching kipot (prayer hats) from a bolt of material.
The fabric she plans to use is 250 yards long.
She will need 2 yards of material for each tallit (prayer shawl) and (1/6) of a yard for each kipah (prayer hat).
---
2t + (1/6)k <= 250
------------------------
She also plans to put tzitzit (fringes) on the tallit and will need 1 yard of cord for each tallit. The kipot will not have any fringes. She has 100 yards of cord to use for the tzitzit.
t <= 100
-----------------
Cheers,
Stan H.
============================
1-1. Write two equations to use to solve for how many kipot and tallitot she can make from the supplies on hand. Let t equal the number of tallitot made and k equal the number of kipot made.
|
Pythagorean-theorem/184271: This question is from textbook College Algebra
A lot is in the shape of a right triangle. The shorter leg measures 120 m. The hypotenuse is 40 m longer than the length of the longer leg. How long is the longer leg?
1 solutions
Answer 138287 by stanbon(57387) on 2009-02-28 19:40:11 (Show Source):
You can put this solution on YOUR website!A lot is in the shape of a right triangle. The shorter leg measures 120 m. The hypotenuse is 40 m longer than the length of the longer leg. How long is the longer leg?
-----------
Let the longer leg be "x" m in length.
Then the hypotenuse is "x+40" m
-------------
Equation:
(x+40)^2 = x^2 + 120^2
x^2 + 80x + 6400 = x^2 = 14400
x^2 + 79x - 8000 = 0
x = [-79 +- sqrt(79^2 - 4*-8000)]/2
Positive solution:
x = [-79 + sqrt(38241)]/2
x = 58.28 (longer leg)
=======================================
Cheers,
San H.
|
Money_Word_Problems/184260: I have a circular diagramme. I draw the first sector,then the second one which is 2 times bigger than the fist one ,and so on, to finally divide the whole diagramme. If we double the previos sector 6 times, find the value of the angle at the middle of the inital sector. PLEASEEEEEEEEEEEEEEE HELPPPPPPPPPPPPPPPP PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE HELPPPPPPPPPPPPPPPPPPP 1 solutions
Answer 138285 by stanbon(57387) on 2009-02-28 19:25:54 (Show Source):
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Probability-and-statistics/184266: Hi,
This is not from a book, can you please tell me if I am on the right track?:
The appropriate "null hypothesis" for a lower-tail test to determine if mean body weight of all the women who have joined a health club is less than 150 pounds would be
a. H0: (Mu)greater than or equal to 150 lb.
b. H0: (Mu) < 150 lb.
c. H0: (Mu) = 150 lb.
d. H0: (Mu)not equal to 150 lb.
*I was thinking (a.), is this the correct answer?
If not can you please explain why, and which one would be the best answer?
Thank you
1 solutions
Answer 138283 by stanbon(57387) on 2009-02-28 19:24:16 (Show Source):
You can put this solution on YOUR website!The appropriate "null hypothesis" for a lower-tail test to determine if mean body weight of all the women who have joined a health club is less than 150 pounds would be
a. H0: (Mu)greater than or equal to 150 lb.
b. H0: (Mu) < 150 lb.
c. H0: (Mu) = 150 lb.
d. H0: (Mu)not equal to 150 lb.
*I was thinking (a.), is this the correct answer?
-------------------
It depends on your textbook and/or you instructor.
Some books would say "a" is the answer ; some
would say "c" is the answer ; and still others
would say "a" or "c" is the answer.
----------------------
I have seen both choices used.
Cheers,
Stan H.
|
Finance/184256: The trajectory of a potato launched from a potato cannon on the ground at an angle of 45 degrees with an initial speed of 65 meters per second can be modeled by the parabola: f(x)= x - 0.0023x2, where the x-axis is the ground. Find the height of the highest point of the trajectory and the horizontal distance the potato travels before hitting the ground. 1 solutions
Answer 138280 by stanbon(57387) on 2009-02-28 19:16:31 (Show Source):
You can put this solution on YOUR website!The trajectory of a potato launched from a potato cannon on the ground at an angle of 45 degrees with an initial speed of 65 meters per second can be modeled by the parabola: f(x)= x - 0.0023x2, where the x-axis is the ground. Find the height of the highest point of the trajectory and the horizontal distance the potato travels before hitting the ground.
-------------------------------------------------------
f(x)= x - 0.0023x^2
The highest point occurs when x = -b/2a = -1/(2*-0.0023) = 217.39 seconds
The height at that time is f(217.39) = 217.39 - 0.0023(217.39)^2
= 108.7 ft.
============================
Distance when it hits the ground?;
Distance will 2(217.39) = 434.78 feet
-----------------
You can get this result by solving
x - 0.0023x^2 = 0 since zero is the hight of the potato when it hits the ground.
====================================
Cheers,
Stan H.
|
Probability-and-statistics/184261: Hi this is not from a book, can you please tell me if I am on the right track?:
An ice cream store manager thinks that the average bill paid by his customers is $10. To test his hypothesis, the next 20 tabs are tallied. All of them are over $10. Therefore, he can conclude immediately that the average bill paid by all of his customers
a. exceeds $10.
b. may be less than, equal to, or greater than $10.
c. is less than $10.
d. equals $10.
*I was thinking (a.), is this the correct answer?
If not can you please explain why, and which one would be the best answer?
Thank you
1 solutions
Answer 138271 by stanbon(57387) on 2009-02-28 18:52:02 (Show Source):
You can put this solution on YOUR website!An ice cream store manager thinks that the average bill paid by his customers is $10. To test his hypothesis, the next 20 tabs are tallied. All of them are over $10. Therefore, he can conclude immediately that the average bill paid by all of his customers
a. exceeds $10.
b. may be less than, equal to, or greater than $10.
c. is less than $10.
d. equals $10.
*I was thinking (a.), is this the correct answer?
If not can you please explain why, and which one would be the best answer?
-------------------------
"a" appears to be the reasonable answer but it is not the statistical
answer. "b" is the statistical answer. The fact that 20 or even 2000
bills are ore than $10 does not prove anything.
---------------------------
Cheers,
Stan H.
|
Probability-and-statistics/184258: Hi this is not from a book, I wanted to know if I am on the right track?:
A shoe store owner is interested in determining if the average weight of a package of shoes sold in the store weighs two pounds. An appropriate alternate hypothesis for this study is
a. H1: (Mu) = 2 lb
b. H1: (Mu) not equal to 2 lb
c. H1: (Mu) > 2 lb
d. H1: (Mu) < 2 lb
*I was thinking (d.), would that be the right answer?
If it isn't why not, and which one would be the most appropriate?
Thank you
1 solutions
Answer 138269 by stanbon(57387) on 2009-02-28 18:45:28 (Show Source):
You can put this solution on YOUR website!A shoe store owner is interested in determining if the average weight of a package of shoes sold in the store weighs two pounds. An appropriate alternate hypothesis for this study is
a. H1: (Mu) = 2 lb
b. H1: (Mu) not equal to 2 lb
c. H1: (Mu) > 2 lb
d. H1: (Mu) < 2 lb
*I was thinking (d.), would that be the right answer?
If it isn't why not, and which one would be the most appropriate?
---------
d would be the null hypothesis because that is what is commonly believed.
b would be the alternate hypothesis as it is the altenate to u = 2.
==============
Ho: u = 2
Ha: u is not equal to 2
===========================
Cheers
Stan H.
|
Age_Word_Problems/184257: Zoron is 10 years older than his sister.In 3 years,he will be twice as old as she will be then. How old are they now? 1 solutions
Answer 138266 by stanbon(57387) on 2009-02-28 18:38:32 (Show Source):
You can put this solution on YOUR website!Zoron is 10 years older than his sister.In 3 years,he will be twice as old as she will be then. How old are they now?
---------------------------------------------
NOW DATA
Let his sister's age be "x" yrs old
Then Zoron is "x+10" yrs old.
----------------------------------------
3 yrs from now DATA:
His sister will be "x+3" yrs old
Zoron will be "x+13" yrs old
------------------------------
Equations:
x+13 = 2(x+3)
x + 13 = 2x + 6
x = 7 (his sister is now 7 yrs old
Zonron is now x+10 = 17 yrs old
====================================
Cheers,
Stan H.
|
Linear-systems/184227: This question is from textbook
A student walks and jogs to college each day. She averages 5 km/h walking and 9km/h jogging. The distance from home to college is 8 km, and she makes the trip in 1 hr. How far does the student jog? 1 solutions
Answer 138259 by stanbon(57387) on 2009-02-28 16:18:47 (Show Source):
You can put this solution on YOUR website!A student walks and jogs to college each day. She averages 5 km/h walking and 9km/h jogging. The distance from home to college is 8 km, and she makes the trip in 1 hr. How far does the student jog?
---------------
Walking DATA:
distance = x km ; rate = 5 km/h ; time = d/r = x/5 hr
--------------------
Jogging DATA:
distance = (8-x) km ; rate = 9 km/h ; time = (8-x)/9 hr
=============
Equation
time + time = 1 hr
x/5 + (8-x)/9 = 1
Multiply thru by 45 to get:
9x + 5(8-x) = 45
9x + 40 - 5x = 45
4x = 5
x = 5/4 km (walking distance
-----
8-x = 8 -5/4 = 27/4 km (jogging distance)
=================================================
Cheers
Stan H.
|
Probability-and-statistics/184191: This question is from textbook saxon algebra 2
The table shows the results of a survey that asked students from three grade levels to pick their favorite fruit from those listed. Find P(Banana\11).
10th 11th 12th
apple 23 35 21
orange 16 12 30
pear 8 7 12
banana 32 24 18
I worked it out thus far: banana/11: 74/24=3.08 or 31%. Am I correct? 1 solutions
Answer 138255 by stanbon(57387) on 2009-02-28 15:50:59 (Show Source):
You can put this solution on YOUR website!The table shows the results of a survey that asked students from three grade levels to pick their favorite fruit from those listed. Find P(Banana\11).
......10th 11th 12th
apple. 23.. 35.. 21
orange 16.. 12.. 30
pear... 8... 7.. 12
banana.32...24.. 18
-------------------------------------------------
P(banana | 11th grade) = 24/78 = 0.3077
Note: When you have a contingency table like this, if 11th is
the conditional, the total of the 11th column is the denominator
of the probability.
You want the Probability of banana in that 11th column. it
is 24/78
-----------------------------------------
Another way to do the problem:
P(banana | 11th) = P(banana and 11th)/P(11th) = (24/grand total)/(78/grand total)
The grand totals cancel and you end up with 24/78
===================================================
Cheers,
Stan H.
|
Graphs/184176: #5
what does THIS one look like when graphed and plotted?
3.8y=-4.2x+1.9
divide by 3.8
y=(-4.2x+1.9)/3.8
set x to zero to find the y intercept
y=1.9/3.8
set y=0 for x intercept
thanks. 1 solutions
Answer 138206 by stanbon(57387) on 2009-02-28 10:06:55 (Show Source):
You can put this solution on YOUR website!what does THIS one look like when graphed and plotted?
3.8y=-4.2x+1.9
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Multiply thru by 10 to get rid of those messy decimals.
38y = -42x + 19
y = (-42/38)x + 1/2
--------------------------------
Let x= 0, then y = 1/2 giving point (0,1/2)
Let x = 38, then y = -41.5 giving point (38,-41.5)
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Plot and draw a line thru them.
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cheers,
Stan H.
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Graphs/184177: I am having a terrible time trying to figure this out, any help will be greatly appreciated
Bill and Barbara collected the following data in a chemistry experiment when they were in lab. They were comparing two thermometers. The thermometers were under constant conditions except that the heat was changing under each thermometer as time passed. T is the time of the reading. X is the reading of the first thermometer. Y is the reading of the second thermometer. Bill and Barbara are assuming a linear relationship between the readings X and Y on the thermometers and are to find a linear equation relating this (x,y) relationship.
See data collection chart below.
Time starts at t = 0 min.
time
0
10 min.
20 min
30 min.
x
10
15
28
40
y
50
59
82.4
104
a. Create a graph locating these data points on an (x,y) coordinate plane.
b. Find the slope of this graph.
c. Create the linear equation based on the data info collected. 1 solutions
Answer 138205 by stanbon(57387) on 2009-02-28 10:01:01 (Show Source):
You can put this solution on YOUR website!Bill and Barbara collected the following data in a chemistry experiment when they were in lab. They were comparing two thermometers. The thermometers were under constant conditions except that the heat was changing under each thermometer as time passed. T is the time of the reading. X is the reading of the first thermometer. Y is the reading of the second thermometer. Bill and Barbara are assuming a linear relationship between the readings X and Y on the thermometers and are to find a linear equation relating this (x,y) relationship.
See data collection chart below.
Time starts at t = 0 min.
time
0
10 min.
20 min
30 min.
x
10
15
28
40
y
50
59
82.4
104
a. Create a graph locating these data points on an (x,y) coordinate plane.
b. Find the slope of this graph.
c. Create the linear equation based on the data info collected.
You have more than two points but only need two.
(10,50) (15,59)
-----
slope = (59-50)/(15-10) = 9/5
--------------
Form of you linear equation is y = mx + b
You know y = 50 when x = 10 and you know m = 9/5; solve for "b":
50 = (9/5)*10 + b
b = 50 - 18 = 32
------------------------
Equation:
Y = (9/5)X + 32
===================
Note: This happens to be the formula for converting temperature
in Celsius to temperature in Farenheit.
============================
Cheers,
Stan H.
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Graphs/184170: What does this look like on a graph after plotted out?
plot points:
(0; -7) and (-7/2; 0)
and draw a line passing both points
thanks for your help! 1 solutions
Answer 138199 by stanbon(57387) on 2009-02-28 07:22:59 (Show Source):
You can put this solution on YOUR website!What does this look like on a graph after plotted out?
plot points:
(0; -7) and (-7/2; 0)
and draw a line passing both points
-----------------------------------------
The y-intercept is (0,-7)
----------
slope = (0--7)/(-7/2 - 0) = 7/(-7/2) = -2
---------------
Equation: y = -2x -7
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Cheers,
Stan H.
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Travel_Word_Problems/184158: A man has a swimming pool in the form of a square. He constructs a cement walk 6 feet wide around the pool and finds that the area of the walk is exactly 1/2 the area of the pool. What is the length of the pool? 1 solutions
Answer 138198 by stanbon(57387) on 2009-02-28 07:19:10 (Show Source):
You can put this solution on YOUR website!A man has a swimming pool in the form of a square. He constructs a cement walk 6 feet wide around the pool and finds that the area of the walk is exactly 1/2 the area of the pool. What is the length of the pool?
--------------------------------------
Draw the picture of a rectangle inside a rectangle.
------------
Let dimensions of the inner rectangle be L and W
Area of the inner rectangle is then L*W
This is the area of the pool.
-----------------
The dimensions of the outer rectangle are L+12 and W+12
Area of the outer rectangle is (L+12)*(W+12)
-------------------------------------------------
Equation:
Area of the walk = outer area - inner area
= (LW+12L + 12W + 144) - LW = 12L + 12W + 144
------------------------------
Equation:
Area of walk = (1/2) area of pool
12L + 12W + 144 = (1/2)LW
24L + 24W + 288 = LW
LW - 24L = 24W + 288
L(W-24) = 24W + 288
Length = (24W+288)/(W-24)
=============================
Cheers,
Stan H.
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Finance/184161: A farmer has 120 yards of fencing to build around a rectangular orchard. Let w be the width of the orchard. Write an equation giving the area of the orchard. Find the dimensions of the orchard when the area is 900 square yards. 1 solutions
Answer 138197 by stanbon(57387) on 2009-02-28 07:06:57 (Show Source):
You can put this solution on YOUR website!A farmer has 120 yards of fencing to build around a rectangular orchard. Let w be the width of the orchard. Write an equation giving the area of the orchard. Find the dimensions of the orchard when the area is 900 square yards.
---------------------------
Perimeter = 2(L + W)
120 yds = 2(L + W)
L+W = 60
L = 60-W
-------------
Area = L*W
Area = (60-W)W
Area = 60W-W^2
--------------------
900 = 60W-W^2
W^2 - 60W + 900 = 0
(W-30)(W-30) = 0
W = 30 yds (Width)
----
L = 30yds (length)
========================
Cheers,
Stan H.
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Complex_Numbers/184166: please help me solve the equation: also could you explain how to solve it 1 solutions
Answer 138195 by stanbon(57387) on 2009-02-28 06:56:17 (Show Source):
You can put this solution on YOUR website!please help me solve the equation:
-------------------
If you are studying DeMoivre's Theorem in a trig class,
i = (cos(90+360n) + i sin(90+360n) where n = 1,2,3....
So: i^(1/3) = cos[(1/3)(90+360n)] + isin[(1/3)(90+360n)]
-------------
Letting n = 1,then 2,then3 will give you three cube roots of "i".
--------------
If n=1 you get: i^(1/3) = cos(150) + isin(150)
If n=2 you get: i^(1/3) = cos(270) + isin(270)
If n=3 you get: i^(1/3) = cos(30) + isin(30)
================================================
Cheers,
Stan H.
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Miscellaneous_Word_Problems/184153: Pictorally with explanations, illustrate the necessity of using common denominators when adding fractions with different denominators. (I am in school for being a teacher and this concept seems hard to teach) 1 solutions
Answer 138190 by stanbon(57387) on 2009-02-27 23:35:41 (Show Source):
You can put this solution on YOUR website!Pictorally with explanations, illustrate the necessity of using common denominators when adding fractions with different denominators
-----------------------------------------------------------------
Let say you want to add 1/2 and 1/3.
------------
Draw two pies.
Split the 1st pie into two parts.
Split the 2nd pie into three parts.
---------------------------
How would you add 1 part of the two to 1 part of the three?
----------------------------
Hmmmmmm???
----------------------------
Color 1 of the 2 parts; Color 1 part of the three
---------------------------------------------------
Split each part of the 1st pie into three parts; you now have 6 parts.
Split each part of the 2nd pie into two parts; you now have 6 parts
----------------------------------------------------
Now you can add the 3 colored parts of the 1st pie to 2 colored parts
of the 2nd pie to be 5 parts out of 6.
------------------------------------------
(1/2) + (1/3) = (3/6) + (2/6) = 5/6
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Cheers,
Stan H.
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Travel_Word_Problems/184160: The cost of a class picnic was $42. If 14 more students had come, the cost per student would have been 20 cents less. How much is the cost per student? 1 solutions
Answer 138186 by stanbon(57387) on 2009-02-27 23:19:11 (Show Source):
You can put this solution on YOUR website!The cost of a class picnic was $42. If 14 more students had come, the cost per student would have been 20 cents less. How much is the cost per student?
-------------------------------------------------
Let original number of students is "x".
---------
Original cost per student = 42/x dollars
---------------------------------------------
When 14 students are added the cost per student = 42/(x+14)
----------------------------------------------
Equation:
original cost per student - new cost per student = 1/5 dollar
42/x - 42/(x+14) = 1/5
----
Multiply thru by 5x(x+14) to get:
42*5(x+14) - 42*5x = x(x+14)
210x + 210*14 - 210x = x^2 + 14x
x^2 + 14x - 2940 = 0
-------
x = [-14 +- sqrt(14^2 - 4*1*-2940)]/2
x = 47.67
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Note: The number should be a positive whole number.
Check you data. Are you sure is was 14 students
and not 4 that were added?
Cheers,
Stan H.
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Probability-and-statistics/183351: According to the boss of the retail outlets, these are the figures of the daily sales for the month of November and December. The boss claims that the average daily sales exceed $250 000.
November 08 (in $000)
215
180
240
246
267
305
245
311
265
224
285
255
235
268
290
187
263
255
266
278
233
203
226
264
335
320
December 08 (in $000)
229
185
238
267
224
280
260
265
285
210
235
200
204
223
187
265
280
240
248
268
240
215
225
245
240
255
320
Determine if the mean daily sale in December is significantly lower than November 2008 with the following:
a) State the null and alternative hypothesis and explain how it is derived.
b) Which would be an appropriate test for this case?
c) State the assumptions made in performing this test and is it reasonable?
d) Perform an appropriate hypothesis test with alpha=0.05 using critical value approach.
1 solutions
Answer 138185 by stanbon(57387) on 2009-02-27 22:55:34 (Show Source):
You can put this solution on YOUR website!Determine if the mean daily sale in December is significantly lower than November 2008 with the following:
a) State the null and alternative hypothesis and explain how it is derived.
Ho: u(december)-u(november) = 0
Ha: u(december)-u(november) < 0
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b) Which would be an appropriate test for this case?
Two-Sample T test
----------------------------------
c) State the assumptions made in performing this test and is it reasonable?
d) Perform an appropriate hypothesis test with alpha=0.05 using critical value approach
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You need to determine the two sample means in order to conduct the test.
========================
Cheers
Stan H.
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Probability-and-statistics/184157: (a) Plot the data on U.S. general aviation shipments. (b) Describe the pattern and discuss possible causes. (c) Would a fitted trend be helpful? Explain. (d) Make a similar graph for 1992–2003 only. Would a fitted trend be helpful in making a prediction for 2004? (e) Fit a trend model of your choice to the 1992–2003 data. (f) Make a forecast for 2004, using either the fitted trend model or a judgment forecast. Why is it best to ignore earlier years in this data set? Airplanes
U.S. Manufactured General Aviation Shipments, 1966–2003
Year Planes Year Planes Year Planes Year Planes
1966 15,587 1976 15,451 1986 1,495 1996 1,053
1967 13,484 1977 16,904 1987 1,085 1997 1,482
1968 13,556 1978 17,811 1988 1,143 1998 2,115
1969 12,407 1979 17,048 1989 1,535 1999 2,421
1970 7,277 1980 11,877 1990 1,134 2000 2,714
1971 7,346 1981 9,457 1991 1,021 2001 2,538
1972 9,774 1982 4,266 1992 856 2002 2,169
1973 13,646 1983 2,691 1993 870 2003 2,090
1974 14,166 1984 2,431 1994 881
1975 14,056 1985 2,029 1995 1,028
1 solutions
Answer 138184 by stanbon(57387) on 2009-02-27 22:48:12 (Show Source):
You can put this solution on YOUR website!These are all judgement questions.
You should be able to sketch a dot-plot
of the numbers against the years and
describe increase intervals and decrease
intervals. "Fitted trend" is a descriptive
term for "do you see a pattern?".
--------
The rest of the problem is similarly
descriptive.
------------
Cheers,
Stan H.
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Probability-and-statistics/184106: Hi can someone please assist me with this problem from Doane−Seward: Applied
Statistics in Business and Economics, ch. 12:
For each sample, do a test for zero correlation. (a) Use Appendix D to find the critical value of tα. (b) State the hypotheses about ρ. (c) Perform the t test and report your decision. (d) Find the critical value of rα and use it to perform the same hypothesis test.
a. r = +.45, n = 20, α = .05, two-tailed test
b. r = −.35, n = 30, α = .10, two-tailed test
c. r = +.60, n = 7, α = .05, one-tailed test
d. r = −.30, n = 61, α = .01, one-tailed test
Thank you
1 solutions
Answer 138173 by stanbon(57387) on 2009-02-27 21:10:46 (Show Source):
You can put this solution on YOUR website!Doane−Seward: Applied Statistics in Business and Economics, ch. 12:
-------------------------------------------
For each sample, do a test for zero correlation.
(a) Use Appendix D to find the critical value of tα.
(b) State the hypotheses about ρ.
(c) Perform the t test and report your decision.
(d) Find the critical value of rα and use it to perform the same hypothesis test.
a. r = +.45, n = 20, α = .05, two-tailed test
------------------
a.
critical value for df = n-2 = 18 is r = 2.101
----------------------------------
b.State the hypotheses about ρ.
Ho: rho = 0
Ha: no it isn't
---
c.Perform the t test and report your decision.
t = rsqrt[(n-2)/(1-r^2) = 0.45sqrt[18/(1-0.2025)] = 2.1379
Reject Ho because 2.1379 is greater than 2.101
--------------
d.Find the critical value of rα and use it to perform the same hypothesis test.
r(alpha) = t(alpha)/sqrt(t^2(alpha) + n -2)
r(alpha) = 2.101/sqrt(2.101^2+20-2) = 2.101/4.73436 = 0.44378
Since r(alpha) is less that alpha=5%, reject Ho.
============================================================
Note: I'll leave the others to you. Follow the example I have
given you. Your text has these two test procedures on pages
492 and 493
=============================================================
Cheers,
Stan H.
b. r = −.35, n = 30, α = .10, two-tailed test
c. r = +.60, n = 7, α = .05, one-tailed test
d. r = −.30, n = 61, α = .01, one-tailed test
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Linear-equations/184147: The height of Kegan Falls in Japan is 11/8ths the height of Radiar Falls in Wales. The sum of the heights of these two waterfalls is 570ft. Find the height of each. 1 solutions
Answer 138169 by stanbon(57387) on 2009-02-27 20:02:30 (Show Source):
You can put this solution on YOUR website!The height of Kegan Falls in Japan is 11/8ths the height of Radiar Falls in Wales. The sum of the heights of these two waterfalls is 570ft. Find the height of each.
-----------------------------
Let the height of Radiar Falls be "x" ft.
Then the height of Kegan Falls is (11/8)x ft.
-----------------------------
Equation:
R. Falls ht. + K. Falls = 570 ft
x + (11/8)x = 570 ft
(19/8)x = 570
x = (8/19)*570
x = 240 ft. (height of Radiar Falls)
570 - 240 = 330 ft. (height of Kegan Falls)
==============================
Cheers,
Stan H.
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absolute-value/184139: Need some help with absolute value equations. Thanks
[x+2]=[4-x] 1 solutions
Answer 138167 by stanbon(57387) on 2009-02-27 19:42:54 (Show Source):
You can put this solution on YOUR website!Need some help with absolute value equations. Thanks
[x+2]=[4-x]
---------------
It's a bit of a mess with a simple solution.
A) x+2 = |4-x| or B) x+2 = -|4-x|
------------------------------------
Working with A you get:
4-x = x+2 or 4-x = -(x+2)
2x = 2 or 4-x = -x - 2
x = 1 or contradiction
=============================
Working with B you get:
-(4-x) = x+2 or -(4-x) = -(x+2)
-4+x = x+2 or -4+x = -x-2
-4 = 2 or 2x = 2
contradiction or x =1
===============================
Conclusion: x = 1 is the only solution.
===============================
Note: I graphed it and that answer is true.
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Cheers,
Stan H.
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Graphs/184132: Please help with solving and graphing inequalities using interval notation. Thanks
4x>or=0 and -2x+4>or=2 1 solutions
Answer 138161 by stanbon(57387) on 2009-02-27 19:22:30 (Show Source):
You can put this solution on YOUR website!Please help with solving and graphing inequalities using interval notation. Thanks
4x>or=0 and -2x+4>or=2
---------------------------
4x >= 0 AND -2x+4 >= 2
x >= 0 AND -2x >- -2
x >= 0 AND x <= 1
------
0 <= x <= 1
---------
To graph it:
1st: Draw a number line and label a point x=0 and x = 1
2nd: Put solid circles at x = 0 and x = 1
3rd: Draw a line segment connect x = 0 and x = 1
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Cheers,
Stan H.
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