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Recent problems solved by 'stanbon'
stanbon answered: 57911 problems
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56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179 , 57180..57209 , 57210..57239 , 57240..57269 , 57270..57299 , 57300..57329 , 57330..57359 , 57360..57389 , 57390..57419 , 57420..57449 , 57450..57479 , 57480..57509 , 57510..57539 , 57540..57569 , 57570..57599 , 57600..57629 , 57630..57659 , 57660..57689 , 57690..57719 , 57720..57749 , 57750..57779 , 57780..57809 , 57810..57839 , 57840..57869 , 57870..57899 , 57900..57929, >>NextFinance/190419: If Sally can paint a house in 4 hours, and John can paint the same house in 6 hour, how long will it take for both of them to paint the house together?
1 solutions
Answer 142911 by stanbon(57984)   on 2009-04-09 19:49:33 (Show Source):
You can put this solution on YOUR website!If Sally can paint a house in 4 hours, and John can paint the same house in 6 hour, how long will it take for both of them to paint the house together?
--------------------------------
Sally DATA:
time = 4 hrs/job ; rate = 1/4 job/hr
--------------------------------------
John DATA:
time = 6 hrs/job ; rate = 1/6 job/hr
-------------------------------------
Together DATA:
time = x hrs/job ; rate = 1/x job/hr
=========================================
Equation:
rate + rate = together rate
1/4 + 1/6 = 1/x
3x + 2x = 12
x = 12/5 = 2.4 hrs (time for them to do the job together)
=========================================================
Cheers,
Stan H.
---------------------
|
Exponential-and-logarithmic-functions/190411: Can you please help me with this problem:
simplify:
3(5x^2)^(1/3)
I tried to to distribute the (1/3) first and got 3(5^(1/3)*x^(2/3)) then I tried to distribute in the 3 and got 15^(1/3)*x^(2/3) but then I do not know what to do
1 solutions
Answer 142905 by stanbon(57984) on 2009-04-09 19:22:43 (Show Source):
|
Miscellaneous_Word_Problems/190229: Worker efficiency. In a study of worker efficiency at Wong
Laboratories it was found that the number of components
assembled per hour by the average worker t hours after
starting work could be modeled by the formula
N(t)=3t^3+ 23^t2 + 8t.
a) Rewrite the formula by factoring the right-hand side
completely.
b) Use the factored version of the formula to find N(3).
1 solutions
Answer 142904 by stanbon(57984) on 2009-04-09 19:09:18 (Show Source):
You can put this solution on YOUR website!N(t)=3t^3 + 23^t2 - 8t.
N(t) = t(3t^2 + 23t - 8)
N(t) = t(3t^2 +24t-t-8)
N(t) = t(3t(t+8) - (t+8))
N(t) = t(t+8)(3t-1)
================================
a) Rewrite the formula by factoring the right-hand side
completely.
b) Use the factored version of the formula to find N(3).
N(3) = 3*11*8 = 264
=========================
Cheers,
Stan H.
|
Probability-and-statistics/190337: stanbon 21772
having trouble to figure out how you solved the question about the baseball player hits a homerun on the average of once every 12 times at bat= would you mind letting me what to due
thanks
1 solutions
Answer 142893 by stanbon(57984) on 2009-04-09 17:52:48 (Show Source):
You can put this solution on YOUR website!Hope the additional explanation is helpful.
Let me know if there are statements you do
not understand.
---------------------------
A baseball player hits a homerun on the average of once every 12 times at bat. Use the idea of independent trials to answer the following questions.
---
If he bats 5 times in a game, what is the probability he will hit exactly one home run?
It's binomial with n=5, p = 1/12, x = 1
If you use a TI calculator you get binompdf(5,12^-1,1) = 0.2942
--------
If you do not have a TI: P(x=1) = 5C1(1/12)^1(11/12)^4
= 5*(1/12)(0.70607) = 0.2942
------------------------------------------
If he comes to bat 5 times, what is the probability he will hit at least one home run?
P(at least one) = 1 - P(no home runs) = 1-binompdf(5,12^-1,0) = 0.3528
OR
P(at least one) = 1-P(no home runs) = 1 - 5C0(1/12)^0(11/12)^5
= 1 - 1*1* = 1-0.6472 = 0.3528
------------------------------------------
If he comes to bat 5 times in a game, what is the expected value for the number of home runs he will hit?
E(x) = np = 5(1/12) = 5/12
==============================================
Cheers,
Stan H.
|
Equations/190302: hi.
i need some help in performing this indicated operation and simplifying it:
a^2 - a - 20/a^2 - 16 divided by a-5
thanks!
1 solutions
Answer 142839 by stanbon(57984) on 2009-04-09 09:08:03 (Show Source):
You can put this solution on YOUR website!a^2 - a - 20/a^2 - 16 divided by a-5
-------------
Factor where you can to get:
= [(a-5)(a+4)]/[(a-4)(a+4)]/(a-5)
Invert the denominator and multiply to get:
= [(a-5)(a+4)]/[(a-4)(a+4)]
Cancel factors that are common to a numerator and a denominator
such as (a+4), (a-5)
= [1/(a-4)]
===============
Cheers,
Stan H.
|
Linear_Algebra/190317: This question is from textbook algebra and trigonometry structure and method book 2
The stretch on a wire under a given tension varies directly as the length of the wire and inversely as the square of its diameter. A wire having length 2m and diameter 1.5mm stretches 1.2 mm. If a second wire of the same material(and under the same tension) has length 3m and diameter 2.0mm, find the amount of stretch.
Please help as i keep on messing the decimals up and can't seem to get the right answer. Please explain also. thank you!
1 solutions
Answer 142837 by stanbon(57984) on 2009-04-09 08:58:17 (Show Source):
You can put this solution on YOUR website!The stretch on a wire under a given tension varies directly as the length of the wire and inversely as the square of its diameter.
stretch = k[L/d^2]
------------------------------
A wire having length 2m and diameter 1.5mm stretches 1.2 mm.
1.2 = k[2/1.5^2]
1.2 = k[8/9]
k = (9/8)1.2
k = 27/20
So the equation for your problem is stretch = (27/20)[L/d^2]
---------
If a second wire of the same material(and under the same tension) has length 3m and diameter 2.0mm, find the amount of stretch.
stretch = (27/20)[3/2^2] = 1.0125
=====================================
Cheers,
Stan H.
-----------------------
|
Radicals/190314: This question is from textbook Introductory and Intermediate Algebra
Hi, I just want to know if I did the right thing on my homework.Please help me.
1) Find the domain of each square root of function. Then use the domain to graph the radical function.The graphs are labeled (a) through (f) and are shown in [-10,10,1] by [-10,10,1] viewing rectangles.]
f(x)= square root of 8-2x
Solution:
8-2x <=(less than or equal to) 0
-2x <= -8
x<= 4
The domain of f is{x\x<=4) or (-infinity, 4}
2)Multiply & simplify. Assume that all variables in a radicand represent positive real numbers and no radicands involve negative quantities raised to even powers.
sqrt of 5xy multiply by sqrt of 10xy^2
Sol'n:
=sqrt of 5xy.10xy^2
=sqrt of 50x^2y^3
=sqrt of 25x^2y^2 x sqrt of 2y
=5xy sqrt of 2y
3)Add or subtract as indicated. You will need to simplify terms to identify the like radicals,
5 sqrt of 12 + sqrt of 75
Sol'n:
=5sqrt of 4x3 + sqrt of 25x3
=5 x 2 x sqrt of 3 + 5sqrt of 3
=10sqrt of 3 + 5 sqrt of 3
=(10+5)sqrt of 3
= 15sqrt of 3
Please let me know my mistakes...Thanks a lot in advance.
Kattie
1 solutions
Answer 142835 by stanbon(57984) on 2009-04-09 08:46:42 (Show Source):
You can put this solution on YOUR website!1) Find the domain of each square root of function. Then use the domain to graph the radical function.The graphs are labeled (a) through (f) and are shown in [-10,10,1] by [-10,10,1] viewing rectangles.]
f(x)= square root of 8-2x
-----------------------------------------------------
Response:
f(x) = sqrt(8-2x)
8-2x must be greater than or equal to zero for x to be in the Domain
8-2x >= 0
Add 2x to both sides to get a positive "x-term".
2x <= 8
x <= 4
Domain: All Real Numbers less than or equal to 4 ; (-inf,4]
=================================================================
2)Multiply & simplify. Assume that all variables in a radicand represent positive real numbers and no radicands involve negative quantities raised to even powers.
sqrt of 5xy multiply by sqrt of 10xy^2
Sol'n:
=sqrt of 5xy.10xy^2
=sqrt of 50x^2y^3
=sqrt of 25x^2y^2 x sqrt of 2y
=5xy[sqrt of 2y]
-----------------------------
Your work is correct.
========================
3)Add or subtract as indicated. You will need to simplify terms to identify the like radicals,
5 sqrt of 12 + sqrt of 75
Sol'n:
=5sqrt of 4x3 + sqrt of 25x3
=5 x 2 x sqrt of 3 + 5sqrt of 3
=10sqrt of 3 + 5 sqrt of 3
=(10+5)sqrt of 3
= 15sqrt of 3
----------
Your work is correct
=============================
Cheers,
Stan H.
|
Probability-and-statistics/190311: A baseball player hits a homerun on the average of once every 12 times at bat. Use the idea of independent trials to answer the following questions.
If he bats 5 times in a game, what is the probability he will hit exactly one home run?
If he comes to bat 5 times, what is the probability he will hit at least one home run?
If he comes to bat 5 times in a game, what is the expected value for the number of home runs he will hit?
thanks for your help
1 solutions
Answer 142834 by stanbon(57984) on 2009-04-09 08:10:29 (Show Source):
You can put this solution on YOUR website!A baseball player hits a homerun on the average of once every 12 times at bat. Use the idea of independent trials to answer the following questions.
---
If he bats 5 times in a game, what is the probability he will hit exactly one home run?
It's binomial with n=5, p = 1/12, x = 1
If you use a TI calculator you get binompdf(5,12^-1,1) = 0.2942
--------
If you do not have a TI: P(x=1) = 5C1(1/12)^1(11/12)^4
= 5*(1/12)(0.70607) = 0.2942
------------------------------------------
If he comes to bat 5 times, what is the probability he will hit at least one home run?
P(at least one) = 1 - P(no home runs) = 1-binompdf(5,12^-1,0) = 0.3528
OR
P(at least one) = 1-P(no home runs) = 1 - 5C0(1/12)^0(11/12)^5
= 1 - 1*1* = 1-0.6472 = 0.3528
------------------------------------------
If he comes to bat 5 times in a game, what is the expected value for the number of home runs he will hit?
E(x) = np = 5(1/12) = 5/12
==============================================
Cheers,
Stan H.
|
Probability-and-statistics/190261: can someone please help..thanks
Suppose that two teams called the Bears and Wildcats are in a playoff series where the first team to win 3 games wins the series. Let's suppose that for each game they play, the probability that the Bears win is 0.54 and the probability the Wildcats win is 0.46.
What is the probability that the bears win the series in 3 games ? .1574
What is the probability that the wildcats win the series in 3 games? .0973
What is the probability that the bears win the series in 4 games? .216
What is the probability that the wildcats win the series in 4 games? .156
what is the probability that the bears win the series in 5 games?
what is the probability that the wildcats win the series in 5 games?
What is the probability that the bears win the series?
what is the probability that the wildcats win the series ?
1 solutions
Answer 142799 by stanbon(57984) on 2009-04-08 23:02:09 (Show Source):
You can put this solution on YOUR website!Suppose that two teams called the Bears and Wildcats are in a playoff series where the first team to win 3 games wins the series. Let's suppose that for each game they play, the probability that the Bears win is 0.54 and the probability the Wildcats win is 0.46.
What is the probability that the bears win the series in 3 games ? .1575
What is the probability that the wildcats win the series in 3 games? .0973
What is the probability that the bears win the series in 4 games? .216
Patterns are LWWW, WLWW, WWLW
Each has probability (0.54^3)(0.46)= 0.07243
But all three are mutually exclusive so the probability = 3(0.07243)
= 0.2173
----------------------------
What is the probability that the wildcats win the series in 4 games? .156
Prob = 3*0.46^3*0.54 = 0.1577
---------------------------------------------
what is the probability that the bears win the series in 5 games?
# of patterns: 5C2 - 1= 10-1 = 9
Probability of each pattern = (0.54)^3(0.46)^2 = 0.03332
Ans: 9*0.3332 = 0.2999
---------------------------------------------
what is the probability that the wildcats win the series in 5 games?
Ans: 9*(0.46)^3(0.54)^2 = 0.2747
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What is the probability that the bears win the series?
They could win it in 4, or 5, or 6, or 7 games.
Figure each probability and add them.
------------------------------------------
what is the probability that the wildcats win the series ?
Same process as with the bears winning.
===========================================================
Cheers,
Stan H.
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Probability-and-statistics/190275: I would like to verify that i have the answered the problem below correctly, Thanks in advance for the help.
During a certain week in the winter, the following minimum temperatures were recorded in an eastern city: 20, 28, 24, 28, 40, 39, and 31. Find the following:
A. Median
B. Standard Deviation
The answers that I came up with are the following:
A. Median = 28
B. Standard Deviation = 7.371114773221212
I greatly appreciate the help.
Sam
1 solutions
Answer 142797 by stanbon(57984) on 2009-04-08 22:25:09 (Show Source):
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Proportions/190276: To determine the number of bass in a lake, a conservationist catches 54 bass, tags them, and returns them to the lake. Later, 32 are observed and 8 are tagged. Estimate how many bass are in the lake.
1 solutions
Answer 142796 by stanbon(57984) on 2009-04-08 22:20:43 (Show Source):
You can put this solution on YOUR website!To determine the number of bass in a lake, a conservationist catches 54 bass, tags them, and returns them to the lake. Later, 32 are observed and 8 are tagged. Estimate how many bass are in the lake.
-----------------------------------------------
[pop #/caught & tagged] = [caught including tagged]/[# tagged that were caught]
----------------------------
pop count/54 = 32/8
---
population count = 54[32/8) = 54*4 = 216
----------------------------------------------
Cheers,
Stan H.
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Probability-and-statistics/190148: A class contains 3 fresh, 4 soph, 6 juniors and 2 seniors. four students are selected at random, find the probability that...
a. all four are juniors
b. no fresh are selected
c. 1 of each year is selected
d.. 2 fresh and 2 juniors
1 solutions
Answer 142794 by stanbon(57984) on 2009-04-08 22:08:03 (Show Source):
You can put this solution on YOUR website!A class contains 3 fresh, 4 soph, 6 juniors and 2 seniors. four students are selected at random, find the probability that...
a. P(all four are juniors) = 6C4/15C4 = 15/1365 = 0.01099..
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b. P(no fresh are selected) = 12C4/15C4 = 495/1365
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c. P(1 of each year is selected) = (3+4+6+2)/1365 = 15/1365
------------------------------------------------------------
d.. P(2 fresh and 2 juniors) = [3C2 + 6C2]/15C4 = (3 + 15)/1365 = 18/1365
-------------------------------------------------------------
Cheers,
Stan H.
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percentage/190267: If a product normally retails for $40.00 and we give you a $10 discount, what percentage discount do you receive?
1 solutions
Answer 142786 by stanbon(57984) on 2009-04-08 21:09:40 (Show Source):
You can put this solution on YOUR website!If a product normally retails for $40.00 and we give you a $10 discount, what percentage discount do you receive?
-------------
Amount of discount = $10
Percent of discount:10/40 = 1/4 = 25%
------------------------------------------
Cheers,
Stan H.
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Geometry_Word_Problems/190270: The rate, given that the distance is 200 ft and the time is x+3 seconds
1 solutions
Answer 142785 by stanbon(57984) on 2009-04-08 21:00:56 (Show Source):
You can put this solution on YOUR website!The rate, given that the distance is 200 ft and the time is x+3 seconds
-------------------
rate = distance/time
rate = 200/(x+3) ft per second
=====================================================
Cheers,
Stan H.
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expressions/190269: How do you write this mathematical expression using parentheses and brackets.
"Subtract 6 from 16. Divide this difference by 5. Multiply this quotient by 8."
1 solutions
Answer 142782 by stanbon(57984) on 2009-04-08 20:47:13 (Show Source):
You can put this solution on YOUR website!How do you write this mathematical expression using parentheses and brackets.
"Subtract 6 from 16. Divide this difference by 5. Multiply this quotient by 8."
-------------------------------------------
[(16-6)/5]*8
===========================
Cheers,
Stan H.
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Trigonometry-basics/190262: How do you solve the following trig equation and sketch a unit circle? Equation: cosx= /2
1 solutions
Answer 142779 by stanbon(57984) on 2009-04-08 20:34:44 (Show Source):
You can put this solution on YOUR website!How do you solve the following trig equation and sketch a unit circle? Equation: cosx= sqrt[(3)]/2.
Take the inverse cosine or arccos to get:
x = arccos[(sqrt(3))/2] = 60 degrees or pi/3
================================================
You sketch a unit circle by drawing a circle and letting the radius be "1".
-------------------------
Cheers,
Stan H.
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Probability-and-statistics/190151: at a local deli, 5 out of every 8 people order a turkey club. find the probability that exactly 2 of the next 5 people will order a turkey club.
1 solutions
Answer 142774 by stanbon(57984) on 2009-04-08 20:05:04 (Show Source):
You can put this solution on YOUR website!at a local deli, 5 out of every 8 people order a turkey club. find the probability that exactly 2 of the next 5 people will order a turkey club.
---
Binomial Problem with n = 5, p = 5/8, x = 2
---
P(x=2) = 5C2(5/8)^2(3/8)^3 = 0.2060
========================================
Cheers,
Stan H.
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Reduction-of-unit-multipliers/190169: directions: convert the following units to the indicated units
1) 20 liters/ hour to milliliters/minute.
2) 80 mAs to Amp Hours
1 solutions
Answer 142740 by stanbon(57984) on 2009-04-08 14:05:53 (Show Source):
You can put this solution on YOUR website!convert the following units to the indicated units
1) 20 liters/ hour to milliliters/minute.
---
(20 L/hr)(1000mL/L)(60 min/hr) = [(20*1000*60)]/[1*1*1] (mL/minute)
= 1,200,000 (mL/minute)
================================
2) 80 mAs to Amp Hours
(80 mA sec)(Amp/1000 mA)(hr/3600 sec)
= [80*1*1]/[1*1000*3600)(Amp hrs)
= 80/3600000 Amp hrs
= 0.00002222.. Amp hrs
============================
Cheers,
Stan H.
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Probability-and-statistics/190152: you are taking a test that contains 5 multiple choice questions with 4 possible answers. you guess at all questions. find the probability that you guess exactly 2 questions correctly.
1 solutions
Answer 142734 by stanbon(57984) on 2009-04-08 13:54:01 (Show Source):
You can put this solution on YOUR website!you are taking a test that contains 5 multiple choice questions with 4 possible answers. you guess at all questions. find the probability that you guess exactly 2 questions
------------------------------
Binomial problem with n=5, p = 1/4, x = 2
P(x=2) = 5C2(1/4)^2(3/4)^3 = 10*(27/4^5) = 0.2637
====================================
Cheers,
Stan H.
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Probability-and-statistics/190153: a computer password contains 4 digits followed by 2 letters. Find the number of password possibilities if the first digit cannot be 0 and repetition is permitted.
1 solutions
Answer 142731 by stanbon(57984) on 2009-04-08 13:49:30 (Show Source):
You can put this solution on YOUR website!a computer password contains 4 digits followed by 2 letters. Find the number of password possibilities if the first digit cannot be 0 and repetition is permitted.
--------
1st digit....9 ways
2nd digit....10 ways
3rd digit....10 ways
4th digit....10 ways
1st letter...26 ways
2nd letter...26 ways
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Total # of ways: 9*10^3*26^2 = 6,084,000 ways
==================================================
Cheers,
Stan H.
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Miscellaneous_Word_Problems/190167: Hello, the question below has me stumped. It is from a homework handout so I do not have a textbook ISBN--sorry. Thanks in advance for your help.
Two pipes can be used to fill a tank. The smaller diameter pipe takes 4 hours longer to fill the tank than the larger diameter pipe. If both pipes are used together, it takes 10 hours to fill the tank. How long would it take each pipe working alone to fill the tank? Round to the nearest tenth of an hour.
1 solutions
Answer 142726 by stanbon(57984) on 2009-04-08 13:42:27 (Show Source):
You can put this solution on YOUR website!Two pipes can be used to fill a tank.
The smaller diameter pipe takes 4 hours longer to fill the tank than the larger diameter pipe. If both pipes are used together, it takes 10 hours to fill the tank. How long would it take each pipe working alone to fill the tank? Round to the nearest tenth of an hour.
-----------------------------------
Smaller pipe DATA:
time = x+4 hrs/job ; rate = 1/(x+4) job/hr
-----------------------
Larger pipe DATA:
time = x hrs/job ; rate = 1/4x job/hr
-----------------------
Together DATA:
time = 10 hrs/job ; rate = 1/10 job/hr
-------------------------
Equation:
rate + rate = together rate
1/(x+4) + 1/x = 1/10
Multiply thru by 10x*(x+4) to get:
10x + 10(x+4) = x(x+4)
20x + 40 = x^2 + 4x
x^2 - 16x - 40 = 0
x = [16 +- sqrt(16^2-4*1*-40)]/2
Positive answer:
x = [16 + sqrt(416)]/2
x = 18.2 hrs. (time for the larger pipe to do the job)
x+4 = 22.2 hrs. (time for the smaller pipe to do the job.)
======================================
Cheers,
Stan H.
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Pythagorean-theorem/190170: Hi, I really need help with the question below. It is from a homework handout so I do not have an ISBN. Thanks for your help.
A ladder 15 feet long leans against a wall. The top of the ladder reaches a height that is 3 feet more than twice the distance from the base of the ladder to the wall. Draw and label a diagram. How high up the wall does this ladder reach?
1 solutions
Answer 142724 by stanbon(57984) on 2009-04-08 13:35:53 (Show Source):
You can put this solution on YOUR website!A ladder 15 feet long leans against a wall. The top of the ladder reaches a height that is 3 feet more than twice the distance from the base of the ladder to the wall. Draw and label a diagram. How high up the wall does this ladder reach?
----------------
Draw the picture.
---
The ladder is the hypotenuse of a right triangle.
Let the base of the right triangle be "x".
Then the height on the wall is "2x+3".
---------------
Using Pythagoras you get:
x^2 + (2x+3)^2 = 15^2
x^2 + 4x^2 + 12x + 9 = 225
5x^2 + 12x - 216 = 0
Use the quadratic formula to get:
x = [-12 +- sqrt(12^2-4*5*-216)]/10
Positive solution:
x = [-12 + sqrt(4464)]/10
x = 5.38 ft
2x+3 = 13.96 ft. (height on the wall)
========================================
Cheers,
Stan H.
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Quadratic_Equations/190141: I need to find the equation that goes with a series of plotted points. The points form what appears to be part of a parabola. The coordinates given are:
x y
32 6
48 14
64 24
80 38
96 55
112 75
The scenario relates to the speed of a car (x) and the braking distance at that speed (y). So presumably another coordinate can also be 0,0.
Given the staring coordinate of 0,0 I have worked out that in the formula form y = ax^2 + bx + c that c = 0, but I cannot work out the procedure to use to solve for a and b and come up with the equation. I have tried simultaneous equations but think I am doing something wrong. My boyfriend talked about solving it by taking logs but we have not been taught that way at school.
Thanks
1 solutions
Answer 142714 by stanbon(57984) on 2009-04-08 10:26:30 (Show Source):
You can put this solution on YOUR website!I need to find the equation that goes with a series of plotted points. The points form what appears to be part of a parabola. The coordinates given are:
x y
32 6
48 14
64 24
80 38
96 55
112 75
------------
You are thinking right.
Use any three of the points to generate 3 equations in a,b,c
Then solve the system for a,b,c.
6 = a(6^2) + b(6) + c
14= a(48^2) + b(48) + c
24= a(64^2) + 64b + c
----------------------------
I used a matrix method to solve the system and found:
a = 0.00749
b = -0.21408
c = 7.01478
---------------
Equation:
y= 0.00749x^2 - 0.21408x + 7.01478
=======================================
I also ran a Quadratic Regression program against
the whose set of data and came up with:
y = 0.006x^2-0.2321x+0.6
------------------------------------
The fact that these answers are not the same means
that not all the points lie exactly on a parabola.
That may be what your instructor is trying to show.
===================================================
Cheers,
Stan H.
need to find the equation that goes with a series of plotted points. The points form what appears to be part of a parabola. The coordinates given are:
x y
32 6
48 14
64 24
80 38
96 55
112 75
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Probability-and-statistics/189502: A physician's health study of the effectiveness of aspirin in the reduction of heart attacks was begun in 1982 and completed in 1987 (see C. Hennekens et al., "Findings from the Aspirin Component of the Ongoing Physician's Health Study," The New England Journal of Medicine 318 (January 28, 1988): 262-264). Of 11,037 male medical doctors in the United States who took one 325 mg buffered aspirin tablet every other day, 104 suffered heart attacks during the five-year period of the study. Of 11,034 male medical doctors in the United States who took a placebo (i.e., a pill that, unknown to the participants in the study, contained no active ingredients), 189 suffered heart attacks during the five-year period of the study. Is there evidence that the proportion having heart attacks is significantly lower for the male medical doctors in the United States who received the buffered aspirin every other day than for those who received a placebo? Does this lead you to believe that taking one buffered aspirin every other day is effective in reducing the incidence of heart attacks? Explain.
1 solutions
Answer 142713 by stanbon(57984) on 2009-04-08 10:13:51 (Show Source):
You can put this solution on YOUR website!Of 11,037 male medical doctors in the United States who took one 325 mg buffered aspirin tablet every other day, 104 suffered heart attacks during the five-year period of the study.
p(aspirin) = 104/11037 = 0.00942
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Of 11,034 male medical doctors in the United States who took a placebo (i.e., a pill that, unknown to the participants in the study, contained no active ingredients), 189 suffered heart attacks during the five-year period of the study.
p(placebo) = 189/11034 = 0.01713
--------------------------------------
Is there evidence that the proportion having heart attacks is significantly lower for the male medical doctors in the United States who received the buffered aspirin every other day than for those who received a placebo?
Ha: p(aspirin)-p(placebo) < 0
Does this lead you to believe that taking one buffered aspirin every other day is effective in reducing the incidence of heart attacks?
--------
Ho: p(asprin) - p(placebo) = 0
----
I ran a 2-PropZTest to get:
test statistic = -5.00
p-value = 0.000000285
-------------------------
Conclusion:
Since the p-value is extremely small reject Ho.
The aspirin a day keeps the heart attack away.
=================================================
Cheers,
Stan H.
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