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Recent problems solved by 'stanbon'
stanbon answered: 57178 problems
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41130..41159 , 41160..41189 , 41190..41219 , 41220..41249 , 41250..41279 , 41280..41309 , 41310..41339 , 41340..41369 , 41370..41399 , 41400..41429 , 41430..41459 , 41460..41489 , 41490..41519 , 41520..41549 , 41550..41579 , 41580..41609 , 41610..41639 , 41640..41669 , 41670..41699 , 41700..41729 , 41730..41759 , 41760..41789 , 41790..41819 , 41820..41849 , 41850..41879 , 41880..41909 , 41910..41939 , 41940..41969 , 41970..41999 , 42000..42029 , 42030..42059 , 42060..42089 , 42090..42119 , 42120..42149 , 42150..42179 , 42180..42209 , 42210..42239 , 42240..42269 , 42270..42299 , 42300..42329 , 42330..42359 , 42360..42389 , 42390..42419 , 42420..42449 , 42450..42479 , 42480..42509 , 42510..42539 , 42540..42569 , 42570..42599 , 42600..42629 , 42630..42659 , 42660..42689 , 42690..42719 , 42720..42749 , 42750..42779 , 42780..42809 , 42810..42839 , 42840..42869 , 42870..42899 , 42900..42929 , 42930..42959 , 42960..42989 , 42990..43019 , 43020..43049 , 43050..43079 , 43080..43109 , 43110..43139 , 43140..43169 , 43170..43199 , 43200..43229 , 43230..43259 , 43260..43289 , 43290..43319 , 43320..43349 , 43350..43379 , 43380..43409 , 43410..43439 , 43440..43469 , 43470..43499 , 43500..43529 , 43530..43559 , 43560..43589 , 43590..43619 , 43620..43649 , 43650..43679 , 43680..43709 , 43710..43739 , 43740..43769 , 43770..43799 , 43800..43829 , 43830..43859 , 43860..43889 , 43890..43919 , 43920..43949 , 43950..43979 , 43980..44009 , 44010..44039 , 44040..44069 , 44070..44099 , 44100..44129 , 44130..44159 , 44160..44189 , 44190..44219 , 44220..44249 , 44250..44279 , 44280..44309 , 44310..44339 , 44340..44369 , 44370..44399 , 44400..44429 , 44430..44459 , 44460..44489 , 44490..44519 , 44520..44549 , 44550..44579 , 44580..44609 , 44610..44639 , 44640..44669 , 44670..44699 , 44700..44729 , 44730..44759 , 44760..44789 , 44790..44819 , 44820..44849 , 44850..44879 , 44880..44909 , 44910..44939 , 44940..44969 , 44970..44999 , 45000..45029 , 45030..45059 , 45060..45089 , 45090..45119 , 45120..45149 , 45150..45179 , 45180..45209 , 45210..45239 , 45240..45269 , 45270..45299 , 45300..45329 , 45330..45359 , 45360..45389 , 45390..45419 , 45420..45449 , 45450..45479 , 45480..45509 , 45510..45539 , 45540..45569 , 45570..45599 , 45600..45629 , 45630..45659 , 45660..45689 , 45690..45719 , 45720..45749 , 45750..45779 , 45780..45809 , 45810..45839 , 45840..45869 , 45870..45899 , 45900..45929 , 45930..45959 , 45960..45989 , 45990..46019 , 46020..46049 , 46050..46079 , 46080..46109 , 46110..46139 , 46140..46169 , 46170..46199 , 46200..46229 , 46230..46259 , 46260..46289 , 46290..46319 , 46320..46349 , 46350..46379 , 46380..46409 , 46410..46439 , 46440..46469 , 46470..46499 , 46500..46529 , 46530..46559 , 46560..46589 , 46590..46619 , 46620..46649 , 46650..46679 , 46680..46709 , 46710..46739 , 46740..46769 , 46770..46799 , 46800..46829 , 46830..46859 , 46860..46889 , 46890..46919 , 46920..46949 , 46950..46979 , 46980..47009 , 47010..47039 , 47040..47069 , 47070..47099 , 47100..47129 , 47130..47159 , 47160..47189 , 47190..47219 , 47220..47249 , 47250..47279 , 47280..47309 , 47310..47339 , 47340..47369 , 47370..47399 , 47400..47429 , 47430..47459 , 47460..47489 , 47490..47519 , 47520..47549 , 47550..47579 , 47580..47609 , 47610..47639 , 47640..47669 , 47670..47699 , 47700..47729 , 47730..47759 , 47760..47789 , 47790..47819 , 47820..47849 , 47850..47879 , 47880..47909 , 47910..47939 , 47940..47969 , 47970..47999 , 48000..48029 , 48030..48059 , 48060..48089 , 48090..48119 , 48120..48149 , 48150..48179 , 48180..48209 , 48210..48239 , 48240..48269 , 48270..48299 , 48300..48329 , 48330..48359 , 48360..48389 , 48390..48419 , 48420..48449 , 48450..48479 , 48480..48509 , 48510..48539 , 48540..48569 , 48570..48599 , 48600..48629 , 48630..48659 , 48660..48689 , 48690..48719 , 48720..48749 , 48750..48779 , 48780..48809 , 48810..48839 , 48840..48869 , 48870..48899 , 48900..48929 , 48930..48959 , 48960..48989 , 48990..49019 , 49020..49049 , 49050..49079 , 49080..49109 , 49110..49139 , 49140..49169 , 49170..49199 , 49200..49229 , 49230..49259 , 49260..49289 , 49290..49319 , 49320..49349 , 49350..49379 , 49380..49409 , 49410..49439 , 49440..49469 , 49470..49499 , 49500..49529 , 49530..49559 , 49560..49589 , 49590..49619 , 49620..49649 , 49650..49679 , 49680..49709 , 49710..49739 , 49740..49769 , 49770..49799 , 49800..49829 , 49830..49859 , 49860..49889 , 49890..49919 , 49920..49949 , 49950..49979 , 49980..50009 , 50010..50039 , 50040..50069 , 50070..50099 , 50100..50129 , 50130..50159 , 50160..50189 , 50190..50219 , 50220..50249 , 50250..50279 , 50280..50309 , 50310..50339 , 50340..50369 , 50370..50399 , 50400..50429 , 50430..50459 , 50460..50489 , 50490..50519 , 50520..50549 , 50550..50579 , 50580..50609 , 50610..50639 , 50640..50669 , 50670..50699 , 50700..50729 , 50730..50759 , 50760..50789 , 50790..50819 , 50820..50849 , 50850..50879 , 50880..50909 , 50910..50939 , 50940..50969 , 50970..50999 , 51000..51029 , 51030..51059 , 51060..51089 , 51090..51119 , 51120..51149 , 51150..51179 , 51180..51209 , 51210..51239 , 51240..51269 , 51270..51299 , 51300..51329 , 51330..51359 , 51360..51389 , 51390..51419 , 51420..51449 , 51450..51479 , 51480..51509 , 51510..51539 , 51540..51569 , 51570..51599 , 51600..51629 , 51630..51659 , 51660..51689 , 51690..51719 , 51720..51749 , 51750..51779 , 51780..51809 , 51810..51839 , 51840..51869 , 51870..51899 , 51900..51929 , 51930..51959 , 51960..51989 , 51990..52019 , 52020..52049 , 52050..52079 , 52080..52109 , 52110..52139 , 52140..52169 , 52170..52199 , 52200..52229 , 52230..52259 , 52260..52289 , 52290..52319 , 52320..52349 , 52350..52379 , 52380..52409 , 52410..52439 , 52440..52469 , 52470..52499 , 52500..52529 , 52530..52559 , 52560..52589 , 52590..52619 , 52620..52649 , 52650..52679 , 52680..52709 , 52710..52739 , 52740..52769 , 52770..52799 , 52800..52829 , 52830..52859 , 52860..52889 , 52890..52919 , 52920..52949 , 52950..52979 , 52980..53009 , 53010..53039 , 53040..53069 , 53070..53099 , 53100..53129 , 53130..53159 , 53160..53189 , 53190..53219 , 53220..53249 , 53250..53279 , 53280..53309 , 53310..53339 , 53340..53369 , 53370..53399 , 53400..53429 , 53430..53459 , 53460..53489 , 53490..53519 , 53520..53549 , 53550..53579 , 53580..53609 , 53610..53639 , 53640..53669 , 53670..53699 , 53700..53729 , 53730..53759 , 53760..53789 , 53790..53819 , 53820..53849 , 53850..53879 , 53880..53909 , 53910..53939 , 53940..53969 , 53970..53999 , 54000..54029 , 54030..54059 , 54060..54089 , 54090..54119 , 54120..54149 , 54150..54179 , 54180..54209 , 54210..54239 , 54240..54269 , 54270..54299 , 54300..54329 , 54330..54359 , 54360..54389 , 54390..54419 , 54420..54449 , 54450..54479 , 54480..54509 , 54510..54539 , 54540..54569 , 54570..54599 , 54600..54629 , 54630..54659 , 54660..54689 , 54690..54719 , 54720..54749 , 54750..54779 , 54780..54809 , 54810..54839 , 54840..54869 , 54870..54899 , 54900..54929 , 54930..54959 , 54960..54989 , 54990..55019 , 55020..55049 , 55050..55079 , 55080..55109 , 55110..55139 , 55140..55169 , 55170..55199 , 55200..55229 , 55230..55259 , 55260..55289 , 55290..55319 , 55320..55349 , 55350..55379 , 55380..55409 , 55410..55439 , 55440..55469 , 55470..55499 , 55500..55529 , 55530..55559 , 55560..55589 , 55590..55619 , 55620..55649 , 55650..55679 , 55680..55709 , 55710..55739 , 55740..55769 , 55770..55799 , 55800..55829 , 55830..55859 , 55860..55889 , 55890..55919 , 55920..55949 , 55950..55979 , 55980..56009 , 56010..56039 , 56040..56069 , 56070..56099 , 56100..56129 , 56130..56159 , 56160..56189 , 56190..56219 , 56220..56249 , 56250..56279 , 56280..56309 , 56310..56339 , 56340..56369 , 56370..56399 , 56400..56429 , 56430..56459 , 56460..56489 , 56490..56519 , 56520..56549 , 56550..56579 , 56580..56609 , 56610..56639 , 56640..56669 , 56670..56699 , 56700..56729 , 56730..56759 , 56760..56789 , 56790..56819 , 56820..56849 , 56850..56879 , 56880..56909 , 56910..56939 , 56940..56969 , 56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179, >>NextFinance/185924: the fuel efficiency of an average car is given by y= -0.0177x*2 + 1.48x + 3.39 where x is the speed im miles per hour and y is the fuel economy in miles per gallon.
1. find the speed at which an average car will get 20 mi/gal
2. what speed yields the best fuel economy?
3. determine the range of speeds that yield 32 mi/gal or better
please answer
tHaNk yOU 1 solutions
Answer 139415 by stanbon(57246) on 2009-03-09 20:15:18 (Show Source):
You can put this solution on YOUR website!the fuel efficiency of an average car is given by y= -0.0177x*2 + 1.48x + 3.39 where x is the speed im miles per hour and y is the fuel economy in miles per gallon.
1. find the speed at which an average car will get 20 mi/gal
solve -0.0177x*2 + 1.48x + 3.39 = 20
---
If that equation is really a quadratic there are two solutions:
x = 70.26 mph and x = 13.36 mph
--------------------------------------------
2. what speed yields the best fuel economy?
x = -b/2a = -1.48/(2*-0.0177) = 41.81 mph
---------------------------------
3. determine the range of speeds that yield 32 mi/gal or better
33.34 <= x <= 53.28
=============================
Cheers,
Stan H.
|
Polynomials-and-rational-expressions/185925: Please show me how to work this difference of 2 rational expressions, reduced to its lowest terms.
y / 7x - x-2 / 2y
or: Y divided by 7x minus x-2 divided by 2y.
Your help is greatly appreciated! 1 solutions
Answer 139413 by stanbon(57246) on 2009-03-09 19:54:48 (Show Source):
You can put this solution on YOUR website!Please show me how to work this difference of 2 rational expressions, reduced to its lowest terms.
[y / 7x] - [(x-2) / 2y]
If you are adding or subtracting fractions you need a least common denominator:
You lcd is 14xy
--------------------
Rewrite each fraction with the lcd as its denominator:
[2y^2/lcd] - [7x(x-2)/lcd]
Now you can subtract to get:
[2y^2 - 7x(x-2)]/lcd
Now simplify the numerator:
[2y^2 - 7x^2 + 14x]/[14xy]
--------------------------------
Cheers,
Stan H.
|
Probability-and-statistics/185819: This question is from textbook doane-Seward
Please I am new to statistic and i need help with the questions below can you please help me. the questions is
A 20- minute consumer survey mailed to 500 adults aged 25-34 included a $5 Starbucks gift certificate. The same survey was mailed to 500 adults aged 25-34 without the gift certificate. There were 65 responses from the first group and 45 from the second group. (a) Perform a two-tailed test comparing the responses rates (proportions) at a=.05. (b) from a confidence interval for the difference of proportions, without pooling the samples. Does it include zero?
Are woman’s feet getting bigger? Retailers in the last 20 years have had to increase their stock of larger sizes. Wal-Mart Stores, Inc., and Payless Shoe Source, Inc., have been aggressive in stocking larger sizes, and Nordstrom’s reports that its larger sizes typically sell out first, assuming equal variances, at a=.025, do these random shoe size samples of 12 randomly chosen women in each age group show that women’s shoe sizes have increase? (See The Wall Street Journal, July 17, 2004.) Shoe Size
Born in 1980: 8 7.5 8.5 8.5 8 7.5 9.5 7.5 8 8 8.5 9
Born in 1960: 8.5 7.5 8 8 7.5 7.5 7.5 8 7 8 7 8
Block buster is testing a new policy of waiving all late fees on DVD rentals using a sample of 10 randomly chosen customers. (a) At a= .10, does the data show that the mean number of monthly rentals has increased? (b) is the decision close? (C Are you convinced?
Customer
Customer No Late Fee Late Fee
1 14 10
2 12 7
3 14 10
4 13 13
5 10 9
6 13 14
7 12 12
8 10 7
9 13 13
10 13 9
1 solutions
Answer 139410 by stanbon(57246) on 2009-03-09 19:30:37 (Show Source):
You can put this solution on YOUR website!A 20- minute consumer survey mailed to 500 adults aged 25-34 included a $5 Starbucks gift certificate. The same survey was mailed to 500 adults aged 25-34 without the gift certificate. There were 65 responses from the first group and 45 from the second group.
--------
(a) Perform a two-tailed test comparing the responses rates (proportions) at a=.05.
-----------
Ho: p1-p2 = 0
Ha: p1-p2 is not 0
Using a 2=Proportion z-test on a TI-83 I get:
test statistic = 13.2116
p-value = 7.8x10^-40
Conclusion: since the p-value is less than 5%, reject Ho
The proportions are not equal
----------------------------------------------------
(b) from a confidence interval for the difference of proportions, without pooling the samples. Does it include zero?
----
Using a 2-Sample Z Interval on a TI-83 I get:
(0.4632 , 6568) which does not include zero
Conclusion: the proportions are not equal.
---------------------------
----------
Are woman’s feet getting bigger? Retailers in the last 20 years have had to increase their stock of larger sizes. Wal-Mart Stores, Inc., and Payless Shoe Source, Inc., have been aggressive in stocking larger sizes, and Nordstrom’s reports that its larger sizes typically sell out first, assuming equal variances, at a=.025, do these random shoe size samples of 12 randomly chosen women in each age group show that women’s shoe sizes have increase? (See The Wall Street Journal, July 17, 2004.) Shoe Size
Born in 1980: 8 7.5 8.5 8.5 8 7.5 9.5 7.5 8 8 8.5 9
Born in 1960: 8.5 7.5 8 8 7.5 7.5 7.5 8 7 8 7 8
-------------------
Sample mean for 1980: 8.2 ; Sample s = 0.6201
Sample mean for 1960: 7.7 ; sample s = 0.4502
---------
Ho: u(80)-u(60) = 0
Ha: u(80)-u(60) > 0
--------------------
Using a 2-Sample T Test on a TI-83 I get:
test statistic = 2.2605
p-value = 0.0175
-----------------
Conclusion: Since the p-value is less than 5%, reject Ho.
1980 sizes are larger than 1969 sizes
---------------------------------------------------
Block buster is testing a new policy of waiving all late fees on DVD rentals using a sample of 10 randomly chosen customers. (a) At a= .10, does the data show that the mean number of monthly rentals has increased? (b) is the decision close? (C Are you convinced?
Customer
Customer No Late Fee Late Fee
1 14 10
2 12 7
3 14 10
4 13 13
5 10 9
6 13 14
7 12 12
8 10 7
9 13 13
10 13 9
--------------
This problem is done the same way as the previous
Find the "no late fee" sample mean
Find the "late fee" sample mean
Ho: u(late)-u(not late) = 0
Ha: u(late)-u(not late) > 0
--------
Perform a 2-Sample T test to find:
the p-value
If it is less than 10% reject Ho.
=====================================
Cheers,
Stan H.
|
Probability-and-statistics/185905: The length of a certain Caribbean fish at adulthood is normally distributed with mean 10.5 cm and standard deviation 2.1 cm. About what percent of these fish are longer than 11.1 cm? 1 solutions
Answer 139407 by stanbon(57246) on 2009-03-09 18:50:19 (Show Source):
You can put this solution on YOUR website!The length of a certain Caribbean fish at adulthood is normally distributed with mean 10.5 cm and standard deviation 2.1 cm. About what percent of these fish are longer than 11.1 cm?
------------------------------
Using TI-83 I get normalcdf(11.1,100,10.5,2.1) = 0.3875
------------------
Cheers,
Stan H.
|
Probability-and-statistics/185842: This question is from textbook
Can you please help thank you
1 If a court acquits every defendant, they will never commit a Type I error.
A)
True
B)
False
2 The probability of rejecting a true null hypothesis increases as the sample size increases.
A)
True
B)
False
3 For a given level of significance, the critical value of Student's t increases as n increases.
A)
True
B)
False
4 In a two-tailed hypothesis test with α = .05, a test statistic of t = 1.813 with d.f. = 15 leads one to reject the null hypothesis of a statistical test.
A)
True
B)
False
5 The power of a test is the probability that the test will reject a false null hypothesis.
A)
True
B)
False
6 The height of the power curve shows the probability of accepting a true null hypothesis
A)
True
B)
False
7 Which is not true of p-values?
A)
When they are small, we want to reject Ho.
B)
They must be specified before the sample is taken.
C)
They show the chance of Type I error if we reject Ho.
D)
They do not require α to be specified a priori.
Use the following scenario to answer questions 8 to 10.
Dullco Manufacturing claims that its alkaline batteries last forty hours on average in a certain type of portable CD player. Tests on a random sample of 18 batteries showed a mean battery life of 37.8 hours with a standard deviation of 5.4 hours.
8 The test statistic is
A)
-1.980
B)
-1.728
C)
-2.101
D)
-1.960
9 In determining the p-value for reporting the study's findings, which of the following is true?
A)
The p-value is less than .05.
B)
The p-value is equal to .05.
C)
The p-value is greater than .05.
D)
The p-value cannot be determined without specifying α.
10 In a left-tailed test at α = .05 we would
A)
comfortably reject the claim.
B)
comfortably accept the claim.
C)
feel uncomfortable with either decision (too close).
D)
switch to alpha of 0.01 for a more powerful test.
1 solutions
Answer 139406 by stanbon(57246) on 2009-03-09 18:45:07 (Show Source):
You can put this solution on YOUR website!1 If a court acquits every defendant, they will never commit a Type I error.
Type I is the probability you reject Ho when it is true.
Ho for court proceedings is "the defendent is innocent"
----
Acquittal means the court accepts Ho. So the answer is True
A)
True
B)
False
---------------------------------------------
2 The probability of rejecting a true null hypothesis increases as the sample size increases.
---
As n increases the test statistic value [z*(s/sqrt(n)] will decrease
increasing the p-value and decreasing the chance of rejecting Ho.
Ans: False
A)
True
B)
False
------------------------------------
3 For a given level of significance, the critical value of Student's t increases as n increases.
--------
The critical value does not depend on the size of "n".
Ans: False
A)
True
B)
False
----------------------------------------
4 In a two-tailed hypothesis test with α = .05, a test statistic of t = 1.813 with d.f. = 15 leads one to reject the null hypothesis of a statistical test.
Ans: False
A)
True
B)
False
------------------------------
5 The power of a test is the probability that the test will reject a false null hypothesis.
Ans: True
A)
True
B)
False
------------------------------------------------
6 The height of the power curve shows the probability of accepting a true null hypothesis
Ans: False
A)
True
B)
False
-----------------------------------
7 Which is not true of p-values?
A)
When they are small, we want to reject Ho.
True
--------------
B)
They must be specified before the sample is taken.
False
---------------------------
C)
They show the chance of Type I error if we reject Ho.
False
D)
They do not require α to be specified a priori.
True
--------------------------------------------
Use the following scenario to answer questions 8 to 10.
Dullco Manufacturing claims that its alkaline batteries last forty hours on average in a certain type of portable CD player. Tests on a random sample of 18 batteries showed a mean battery life of 37.8 hours with a standard deviation of 5.4 hours.
8 The test statistic is
t(37.8) = (37.8-40)/[5.4/sqrt(18)] = -1.7285
A)
-1.980
B)
-1.728
C)
-2.101
D)
-1.960
----------------------------------
9 In determining the p-value for reporting the study's findings, which of the following is true?
Ans: The p-value cannot be determined unless you know whether the
test is two-tail, left, or right. Similarly the rest of the questions
under 9 cannot be answered.
---------------------------------------
A)
The p-value is less than .05.
B)
The p-value is equal to .05.
C)
The p-value is greater than .05.
D)
The p-value cannot be determined without specifying α.
10 In a left-tailed test at α = .05 we would
A)
comfortably reject the claim.
B)
comfortably accept the claim.
C)
feel uncomfortable with either decision (too close).
D)
switch to alpha of 0.01 for a more powerful test.
------------------
Cheers,
Stan H.
|
Probability-and-statistics/185890: find the area under the normal curve that has mean 100 and standard deviation 500 that lies between the values x=-150 and x=1,200. 1 solutions
Answer 139399 by stanbon(57246) on 2009-03-09 17:59:54 (Show Source):
You can put this solution on YOUR website!find the area under the normal curve that has mean 100 and standard deviation 500 that lies between the values x=-150 and x=1,200.
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Do you need to know how to work this problem or just what the answer is?
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Using a TI-83 you would get: normalcdf(-150,1200,100,500) = 0.6776
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Cheers,
Stan H.
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Matrices-and-determiminant/185849: A total of twelve thousand passengers normally ride the green line of the MBTA during te morning rush hour. The token prices for a ride are .25 for childern under 12, $1 for adults and .50 for senior citizens. The revenue from these riders is $10,700. If he token prices were raised to .35 for childern under 12 and $1.50 for adults, and the senior ctizens price was unchanged, the expected revenue from these riders would be $15,820. How many riders in each category normally ride the green line during the morning rush hour?
I know how to do matrices, however, I can not figure out how to set this one up and could use some help. 1 solutions
Answer 139368 by stanbon(57246) on 2009-03-09 15:25:51 (Show Source):
You can put this solution on YOUR website!A total of twelve thousand passengers normally ride the green line of the MBTA during te morning rush hour.
a + s + c = 12000
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The token prices for a ride are .25 for childern under 12, $1 for adults and .50 for senior citizens. The revenue from these riders is $10,700.
100a + 50s + 35c = 1070000 cents
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If the token prices were raised to .35 for childern under 12 and $1.50 for adults, and the senior ctizens price was unchanged, the expected revenue from these riders would be $15,820.
150a + 50s + 35c = 1582000 cents
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System to solve:
a + s + c = 12000
100a + 50s + 35c = 1070000
150a + 50s + 35c = 1582000
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Use what you know about matrices to solve for a,s, and c.
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How many riders in each category normally ride the green line during the morning rush hour?
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Cheers,
Stan H.
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Linear-equations/185799: This question is from textbook Introductory & Intermediate algebra
Hi,I'm trying to work out on my assignments and i want to find out if i did it right..CAn u please help me solve these two problems?WOuld appreciate your help very much.
1)Solve each system by the substitution method.If there is no solution or an infinite number of solutions, so state, and use set of notation to express solution set: x/4-y/4 = -1
x+4y = -9
2)Solve each system or state that the system is inconsistent or dependent.
x/2 = (y+8)/4
(x+3)/2= (y+5)/4
Thanks again in advance.
Kattie 1 solutions
Answer 139337 by stanbon(57246) on 2009-03-09 08:07:02 (Show Source):
You can put this solution on YOUR website!1)Solve each system by the substitution method.If there is no solution or an infinite number of solutions, so state, and use set of notation to express solution set:
x/4-y/4 = -1
x+4y = -9
----------------
Modify the 1st equation.
x - y = -4
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Substitute x = -9-4y into that equation to solve for "y"
-9-4y-y= -4
-5y = 5
y = -1
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substitute that into x = -9-4y to solve for "x"
x = -9 -4*-1 = -5
============================
2)Solve each system or state that the system is inconsistent or dependent.
x/2 = (y+8)/4
(x+3)/2= (y+5)/4
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Modify both equations:
2x = y+8
2(x+3) = y+5
------------------
Simplify:
x = (y+8)/2
2x + 6 = y+5
----------------
Substitute into the 2nd equation to solve for "Y":
---
2[(y+8)/2] + 6 = y+5
y+8 + 6 = y = 5
14 = 5
Contradiction:
No solution
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Cheers,
Stan H.
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Probability-and-statistics/185795: This question is from textbook Elementary Statistics
16.) If 10% of the people who are given a certain drug experience dizziness, find these probabilities for a sample of 15 people who take the drug.
a. At least two people will become dizzy.
b. Exactly three people will become dizzy.
c. At most four people will become dizzy.
Thanks! 1 solutions
Answer 139336 by stanbon(57246) on 2009-03-09 07:58:28 (Show Source):
You can put this solution on YOUR website!If 10% of the people who are given a certain drug experience dizziness, find these probabilities for a sample of 15 people who take the drug.
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There are all binomial problems:
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a. At least two people will become dizzy.
Ans: 1 - binomcdf(15,0.1,1) = 0.4510
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b. Exactly three people will become dizzy.
Ans: binompdf(15,0.1,3)= 0.1285
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c. At most four people will become dizzy.
Ans: binomcdf(15,0.1,4) = 0.9873
-----------------------------------
Cheers,
Stan H.
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Probability-and-statistics/185796: This question is from textbook Elementary Statistics
22.) One out of four Americans over age 55 has eaten pizza for breakfast. If a sample of 10 Americans over age 55 is selected at random, find the probability that at most 3 have eaten pizza for breakfast.
Thanks! 1 solutions
Answer 139335 by stanbon(57246) on 2009-03-09 07:51:22 (Show Source):
You can put this solution on YOUR website!One out of four Americans over age 55 has eaten pizza for breakfast. If a sample of 10 Americans over age 55 is selected at random, find the probability that at most 3 have eaten pizza for breakfast.
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It's binomial because each person either has or has not eaten pizza.
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n = 10 ; p = 1/4 ; 0<=x<=3
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On a TI-83 use binomcdf(10,0.25,3) to get 0.7759
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Cheers,
Stan H.
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Probability-and-statistics/185745: can someone please help me solve this? thank you so much.
An insurance company is trying to determine, using the 95% confidence level, what proportion of teenagers have an accident. Using a sample of 582 accidents, the company discovers that teenagers were involved in 91 accidents. What is confidence interval for this proportion?
1 solutions
Answer 139315 by stanbon(57246) on 2009-03-08 22:27:49 (Show Source):
You can put this solution on YOUR website!An insurance company is trying to determine, using the 95% confidence level, what proportion of teenagers have an accident. Using a sample of 582 accidents, the company discovers that teenagers were involved in 91 accidents. What is confidence interval for this proportion?
---------------------------------------------
sample proportion = 91/582 = 0.1564
Standard error = E = z*sqrt[pq/n] = 1.96sqrt[0.1564*0.8436/582] = 0.0295
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95% CI: 0.1564 - 0.0295 < p < 0.1564 + 0.0295
95% CI: 0.1269 < p < 0.1859
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Do you understand this procedure for constructing confidence intervals?
===================================
Cheers,
Stan H.
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Linear_Equations_And_Systems_Word_Problems/185760: This question is from textbook beginning algebra
please help me solve this problem. The sum of three times a number and 7 more than the number is the same as the difference between -11 and twice the number. What is the number? 1 solutions
Answer 139310 by stanbon(57246) on 2009-03-08 21:45:48 (Show Source):
You can put this solution on YOUR website!The sum of three times a number and 7 more than the number is the same as the difference between -11 and twice the number. What is the number?
--------------------------
Equation:
3x+(x+7) = -11-2x
4x + 7 = -11-2x
6x = -18
x = -3
===============
Cheers,
Stan H.
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Probability-and-statistics/185747: can someone please help me solve this? thank you so much.
An insurance company is trying to determine, using the 95% confidence level, what proportion of teenagers have an accident. Using a sample of 582 accidents, the company discovers that teenagers were involved in 91 accidents. What is confidence interval for this proportion?
1 solutions
Answer 139306 by stanbon(57246) on 2009-03-08 21:37:56 (Show Source):
You can put this solution on YOUR website!An insurance company is trying to determine, using the 95% confidence level, what proportion of teenagers have an accident. Using a sample of 582 accidents, the company discovers that teenagers were involved in 91 accidents. What is confidence interval for this proportion?
---------------------------------------------
sample proportion = 91/582 = 0.1564
Standard error = E = z*sqrt[pq/n] = 1.96sqrt[0.1564*0.8436/582] = 0.0295
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95% CI: 0.1564 - 0.0295 < p < 0.1564 + 0.0295
95% CI: 0.1269 < p < 0.1859
===================================
Do you understand this procedure for constructing confidence intervals?
===================================
Cheers,
Stan H.
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Linear-equations/185715: In the equation y-9= -2(x+1) I know the slope is -2 but my homework question is: "use the point-slope form of the equation to identify a point the line passes through." Could it be as simple as (1,-9)? And how can I identify the next point it passes through with a slope of -2? Just guessing but would the next point the line passes through be (2, -11), because the rise is -2 and the run is 1? Please help! 1 solutions
Answer 139293 by stanbon(57246) on 2009-03-08 19:41:04 (Show Source):
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Geometry_Word_Problems/185710: What does it mean to refer to a 20 inch Tv set or a 25 inch TV set? Such units refer to the diagonal of the screen. A 10 inch tv set also has a width of 8 inches. What is its height? 1 solutions
Answer 139292 by stanbon(57246) on 2009-03-08 18:46:54 (Show Source):
You can put this solution on YOUR website!What does it mean to refer to a 20 inch Tv set or a 25 inch TV set? Such units refer to the diagonal of the screen. A 10 inch tv set also has a width of 8 inches. What is its height?
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Use Pythagoras to findthe height:
height^2 + 8^2 = 10^2
h^2 = 100 - 64
h^2 = 36
h = 6 inches (height)
===========================
Cheers,
Stan H.
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Functions/185707: If an object is given an initial velocity of v0 feet per second from a height of S0 feet, then its height S after t seconds is given by the formula
S = -16t^2 +v0t + S0. A rock is thrown into the air at 26 feet per second from a height of 13 feet. How long does it take to reach the earth?
?
1 solutions
Answer 139291 by stanbon(57246) on 2009-03-08 18:42:07 (Show Source):
You can put this solution on YOUR website!If an object is given an initial velocity of v0 feet per second from a height of S0 feet, then its height S after t seconds is given by the formula
S = -16t^2 +v0t + S0. A rock is thrown into the air at 26 feet per second from a height of 13 feet. How long does it take to reach the earth?
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S(t) = -16t^2 +26t + 13
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When it reaches the earth its height is zero; solve for "t":
-16t^2 +26t + 13 = 0
t = [-26 +- sqrt(26^2 - 4*-16*13)/(-32)
t = [-26 +- sqrt(1508)]/(-32)
Positive solution:
t = [-26 - 38.83]/(-32)
t = 2.03 seconds
=========================
Cheers,
Stan H.
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Functions/185706: Find the perfect square trinomial whose first two terms are q^2 + 3q.
??? 1 solutions
Answer 139290 by stanbon(57246) on 2009-03-08 18:34:48 (Show Source):
You can put this solution on YOUR website!Find the perfect square trinomial whose first two terms are q^2 + 3q.
----------------
q^2 + 3q + (3/2)^2
= (q + (3/2))^2
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Cheers,
Stan H.
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Exponential-and-logarithmic-functions/185701: If you've got a minute, can you please help with this algebra problem?
4100 = 100*((1+X)^20 -1)/X
I can also take this down to
41X+1 = (1+X)^20
but that doesn't help me 1 solutions
Answer 139289 by stanbon(57246) on 2009-03-08 18:32:23 (Show Source):
You can put this solution on YOUR website!algebra problem?
4100 = 100*((1+X)^20 -1)/X
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Using Google and search string "present value equation"
I found the following:
i = [FV/PV]^(1/n) -1
i = [4100/100]^(1/20) -1
i = [41]^(1/20) -1
i = 1.20 -1
i = 0.20 or 20%
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Cheers,
Stan H.
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Functions/185700: Please help Find the axis of symmetry for....
y = x^2 – 9x + 3 1 solutions
Answer 139288 by stanbon(57246) on 2009-03-08 18:20:58 (Show Source):
You can put this solution on YOUR website!Find the axis of symmetry for....
y = x^2 – 9x + 3
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complete the square on the x-terms:
x^2 - 9x + ? = y-3+?
x^2 - 9x + (9/2)^2 = y - 3 + (9/2)^2
(x-(9/2))^2 = y -12/4 + 81/4
(x-(9/2))^2 = y+(69/4)
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Axis of symmetry: x = 9/2
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You could get the same answer as x = -b/2a = -(-9/2*1) = 9/2
============================================================
Cheers,
Stan H.
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Quadratic_Equations/185695: Solving Problems Using Linear Systems
1. Leanne works at a greenhouse. She needs to plant a total of 32 bulbs. Two types of bulbs are available. She is asked to plant three times as many crocus bulbs as tulip bulbs. How many of each should she plant?
(The answer is: 24 crocus bulbs and 8 tulip bulbs, but i dont know how to solve it?)
Can you pleaseeeeeeeeeeeeee help me with this problem thank you very much!!!! 1 solutions
Answer 139285 by stanbon(57246) on 2009-03-08 18:04:40 (Show Source):
You can put this solution on YOUR website!1. Leanne works at a greenhouse. She needs to plant a total of 32 bulbs. Two types of bulbs are available. She is asked to plant three times as many crocus bulbs as tulip bulbs. How many of each should she plant?
-------------------
Equations:
Quantity: c + t = 32
Quantity: c = 3t
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Rearrange:
c + t = 32
c -3t = 0
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Subtract the 2nd equation from the 1st to solve for "t":
4t = 32
t = 8 (# of tulips)
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Since c = 3t, c = 24 (# of crocus)
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Cheers,
Stan H.
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logarithm/185694: Simply the expression
(256x^4 y)^1/4 divided by (625xy^3)^3/4
a) 4x^4/125y^2
b) 4x^1/4 divided by 125y^2
c) 4x^1/4 divided by 625y^2 1 solutions
Answer 139281 by stanbon(57246) on 2009-03-08 17:48:03 (Show Source):
You can put this solution on YOUR website!Simplify the expression
(256x^4 y)^1/4 divided by (625xy^3)^3/4
------------------
(4xy^(1/4)) / (5x^(3/4)y^(9/4))
= (4/5)(x^(1/4)/y^2)
= (4x^(1/4)/(5y^2)
=======================
Cheers,
Stan H.
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Probability-and-statistics/185672: Can someone please help me solve this? Thank you so much.
The owner of Britton’s Egg Farm wants to estimate the mean number of eggs laid per chicken. A sample of 25 chickens shows they laid an average of 19 eggs per month with a standard deviation of 2.25 eggs per month.
a. What is the best estimate of the population mean?
b. For a 99 percent confidence interval, what is the value of t?
c. Develop the 99 percent confidence interval for the population mean.
Please identify the lower and upper confidence boundaries.
1 solutions
Answer 139279 by stanbon(57246) on 2009-03-08 17:36:12 (Show Source):
You can put this solution on YOUR website!The owner of Britton’s Egg Farm wants to estimate the mean number of eggs laid per chicken. A sample of 25 chickens shows they laid an average of 19 eggs per month with a standard deviation of 2.25 eggs per month.
-------------------------------
a. What is the best estimate of the population mean?
The best estimate is the sample mean: 19 eggs per month
It is called "a point estimate".
----------------------------------------------------------------
b. For a 99 percent confidence interval, what is the value of t?
For df=24 and alpha = 99% the t-value is 2.797
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c. Develop the 99 percent confidence interval for the population mean.
E = 2.797[2.25/sqrt(25)] = 1.2587
99% CI: 19-1.2587 < u < 19+1.2587
---------------
Please identify the lower and upper confidence boundaries.
lower: 19-1.2587 = 17.7414
upper: 19+1.2587 = 2.5174
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Cheers,
Stan H.
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Miscellaneous_Word_Problems/185685: This question is from textbook saxon algebra 2
A manager gives a store evaluation form to each customer. Customers who mail in their complete forms receive a coupon. Identify the type of sample and determine whether it is biased. Explain your answer.
I'm thinking this is a Self-selected sample. Am I correct? I'm not sure if it is biased or not. Maybe it's biased because only those customers mailing in the completed forms get a coupon. Any thoughts on this? 1 solutions
Answer 139277 by stanbon(57246) on 2009-03-08 17:23:26 (Show Source):
You can put this solution on YOUR website!
Yes, it has self-selective bias.
The bias is that participants choose themselves
as participants. The coupons are simply a
motivator but are not the reason for the bias
since everyone who receives a survey has the
same motivation.
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Cheers,
Stan H.
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Sequences-and-series/185684: How do you solve a geomtric mean when the first term is 81, and the fifth term is 16? 1 solutions
Answer 139274 by stanbon(57246) on 2009-03-08 17:09:51 (Show Source):
You can put this solution on YOUR website!How do you solve a geomtric mean when the first term is 81, and the fifth term is 16?
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Form: a(n) = ar^(n-1)
----
a = 81
a(5) = ar^(5-1) = 16
a(5) = 81*r^4 = 16
r^4 = 16/81
r = 2/3
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Geometric sequence:
81, (2/3)81, (2/3)^2*81, (2/3)^3(81) ...
81, 54, 36, 24, 16
==========================
Cheers,
Stan H.
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Circles/185682: The directions state: For each problem, draw a picture to help solve the problem.
the question: A circle witht the radius x-2 produces an area of 169pi cm power 2. Find x.
I drew a circle deplicting radius x-2. I solved for x with
A= 169pi cm power 2
x= sq root 169 + 2
x = 13 + 2
x = 15
Did I do this correctly?
Thank for you time 1 solutions
Answer 139273 by stanbon(57246) on 2009-03-08 17:02:44 (Show Source):
You can put this solution on YOUR website!A circle witht the radius x-2 produces an area of 169pi cm^2 2. Find x.
----------------------
r = x-2 cm
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Area = (pi)(x-2)^2
169pi = pi(x-2)^2
(x-2)^2 = 169
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x-2 = 13 or x-2 = -13
Positive solution:
radius = 13 cm
====================
Cheers,
Stan H.
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