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Recent problems solved by 'stanbon'
stanbon answered: 57314 problems
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2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 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56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179 , 57180..57209 , 57210..57239 , 57240..57269 , 57270..57299 , 57300..57329, >>NextMiscellaneous_Word_Problems/198587: The half-life of tritium is 12.4 years. How long will it take for 15% of a sample of tritium to decompose?
An isotope of thorium, , has a half-life of 18.4 days. How long will it take for 77% of the sample to decompose?
1 solutions
Answer 149115 by stanbon(57387)   on 2009-06-01 18:32:36 (Show Source):
You can put this solution on YOUR website!The half-life of tritium is 12.4 years. How long will it take for 15% of a sample of tritium to decompose?
If 15% decomposes, 85% remains.
-----------------
A(t) = Ao*e^(-ln(2t)/12.4)
0.85 = e^(-ln(2t)/12.4)
0.85 = 2t/12.4
2t = 10.54
t = 5.27 years
An isotope of thorium, , has a half-life of 18.4 days. How long will it take for 77% of the sample to decompose?
---
0.23 = e^(-ln(2t)/18.4)
0.23 = 2t/18.4
2t = 4.232
t = 2.116 days
=======================
Cheers,
Stan H.
|
Probability-and-statistics/198560: The United States Postal Service reports 95% of first class mail within the same city is delivered within two days of the time of the mailing. Six letters are randomly sent to different locations
a) What is the probability all six arrive within two days?
b) What is the probability that exactly five arrive within two days?
c) Find the mean number of letters that will arrive within two days
d) Compute the variance and Standard Deviation of the number that will arrive within two days.
1 solutions
Answer 149113 by stanbon(57387) on 2009-06-01 18:08:04 (Show Source):
You can put this solution on YOUR website!The United States Postal Service reports 95% of first class mail within the same city is delivered within two days of the time of the mailing. Six letters are randomly sent to different locations
--------------------------------------------------------------------
a) What is the probability all six arrive within two days?
Ans: (0.95)^6 = 0.735
----------------------------------------------
b) What is the probability that exactly five arrive within two days?
Ans: 6C5(0.95)^5(0.05)^1 = 0.2321
----------------------------------------------
c) Find the mean number of letters that will arrive within two days
Ans: u = np = 6*0.95 = 5.7
----------------------------------------------
d) Compute the variance and Standard Deviation of the number that will arrive within two days.
Ans: variance = npq = 6*0.95*0.05 = 0.285
stdev = sqrt(0.285) = 0.5339
========================================
Cheers,
Stan H.
|
Probability-and-statistics/198562: Backyard Retreats, Inc, sells an exclusive line of pools, hot tubs, and spas. It is located just off the Bee Line Expressway in Orlando, Florida. The owner reports 20% of the customers entering the store will make a purchase of at least $50. Suppose 15 customers enter the store before 10am on a particular Saturday
a) How many of these customers would you expect to make a purchase of at least $50?
b) What is the probability exactly five of these customers make a purchase of at least $50?
c) What is the probability at least five of these customers make a purchase of at least $50?
d) What is the probability at least one customers make a purchase of at least $50?
1 solutions
Answer 149112 by stanbon(57387) on 2009-06-01 17:54:07 (Show Source):
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Probability-and-statistics/198561: A telemarketer makes six phone calls per hour and is able to make a sale on 30% of these contacts. During the next two hours. Find:
a) The probability of exactly making four sales.
b) The probability of making no sales.
c) The probability of exactly making two sales.
d) The mean number of sales within the two-hour period.
1 solutions
Answer 149111 by stanbon(57387) on 2009-06-01 17:49:59 (Show Source):
You can put this solution on YOUR website!The owner reports 20% of the customers entering the store will make a purchase of at least $50. Suppose 15 customers enter the store before 10am on a particular Saturday
a) How many of these customers would you expect to make a purchase of at least $50?
Ans: 0.20*15 = 3
----------------------------
b) What is the probability exactly five of these customers make a purchase of at least $50?
Ans: 15C5(0.2)^5(0.8)^10 = 0.1032
---------------------------------------------------
c) What is the probability at least five of these customers make a purchase of at least $50?
Ans 1 - binomcdf(15,0.2,4) = 0.16423....
---------------------------------------------------
d) What is the probability at least one customers make a purchase of at least $50?
Ans: 1 - binomcdf(15,0.2,0) = 0.96482...
============================================
Cheers,
Stan H.
|
Probability-and-statistics/198596: Which sneakers are prefered?
female- running 12 cross training 28
Male- running 42 cross training 14
3. P(female | running)
4. P(female | cross training)
5. P(male | running)
6. P(male | cross training)
For questions 7 and 8, find the mean, median, and mode of each data set.
8.) 5 7 10 10 7 9 5 6 7 7 4
10.) 12 13 14 9 7 8 15 10 11 6
1 solutions
Answer 149108 by stanbon(57387) on 2009-06-01 17:33:34 (Show Source):
You can put this solution on YOUR website!Which sneakers are prefered?
female- running 12 cross training 28
Male- running 42 cross training 14
---------------------------------------------------
3. P(female | running) = 12/54
4. P(female | cross training) = 28/42
5. P(male | running) = 42/54
6. P(male | cross training) = 14/42
==========================================
Cheers,
Stan H.
|
Finance/198571: This question is from textbook beginning algebra
How do i set up an equation for this problem? There are a total of 500 douglas fir and hemlock trees in a section of the forest purchased by the hoodoo logging co. the company paid an average of $205 for each douglas fir and $300 for each hemlock. If the company paid a total of $132,000 for the trees how many of each kind did the company buy?
1 solutions
Answer 149101 by stanbon(57387) on 2009-06-01 15:31:41 (Show Source):
You can put this solution on YOUR website!How do i set up an equation for this problem? There are a total of 500 douglas fir and hemlock trees in a section of the forest purchased by the hoodoo logging co. the company paid an average of $205 for each douglas fir and $300 for each hemlock. If the company paid a total of $132,000 for the trees how many of each kind did the company buy?
----------------------------------
Quantity Eq. : f + h = 500
Value Eq.... :205f+300h = 132,000
---------------------------------------
Modify the 1st equation:
205f + 205h = 205*500
205f + 300h = 132000
--------------------------------
Subtract 1st from 2nd to get:
95h = 29500
h = 310.52 (# of hemlock trees bought)
f = 500-h = 189.47 # of fir trees bought)
===============================================
Cheers,
Stan H.
|
Finance/198579: A charity group which feeds homeless children, receives a donation of $3780 for food. They plan to use $180 each day. At the end of what day will they have $1260 left?
1 solutions
Answer 149097 by stanbon(57387) on 2009-06-01 15:16:23 (Show Source):
You can put this solution on YOUR website!A charity group which feeds homeless children, receives a donation of $3780 for food. They plan to use $180 each day. At the end of what day will they have $1260 left?
----------------
3780 - 1260 = $2520 (amt. they have spent)
--------------
2520/180 = 14 days (# of days to spend the @2520)
==============================================
Cheers,
Stan H.
|
Probability-and-statistics/198568: Blockbuster is testing a new policy of waiving all late fees on DVD rentals using a sample of 10 randomly chosen customers. (a) At a-.10, does the data show that the man number of monthly rentals has increased? (b) Is the decision close? (c) Are you convinced?
Customer No Late Fee Late Fee
1 14 10
2 12 7
3 14 10
4 13 13
5 10 9
6 13 14
7 12 12
8 10 7
9 13 13
10 13 9
I can figure out the mean which is 12.4 of no late fee but cannot figure out the rest, can someone please help. Thanks
1 solutions
Answer 149096 by stanbon(57387) on 2009-06-01 15:11:46 (Show Source):
You can put this solution on YOUR website!Blockbuster is testing a new policy of waiving all late fees on DVD rentals using a sample of 10 randomly chosen customers. (a) At a-.10, does the data show that the man number of monthly rentals has increased? (b) Is the decision close? (c) Are you convinced?
Customer No Late Fee Late Fee
1 14 10
2 12 7
3 14 10
4 13 13
5 10 9
6 13 14
7 12 12
8 10 7
9 13 13
10 13 9
-----------------
These data are dependent pairs because each pair measures a "before"
and "after" for the same person.
---------------------
Make a list for each data set.
Make a list of the difference (no late fee)-(late fee)
------------
------------------
Run a t-test on the difference of the 10 pairs.
mean of the difference = 2
--------------------------------------
Ho: u(difference) = 0
H1: u(difference) > 0
Decision Rule: Reject Ho if the test statistic is greater than 1.383..
test statistic: t = 2.8604
p-value: 0.0094
-----------
Conclusion: Since the p-value is less than 10%, reject Ho.
The test provides evidence that the mean of the differences
is not zero.
======================
Cheers,
Stan H.
|
Geometry_proofs/198538: I need help!! Can someone please help me with this problem? Thank you!!!!
7. (4 pts) Use Euler Diagrams to determine whether the following
syllogism is valid or invalid.
All golfers have golf carts.
All members of the A club have golf carts.
--------------------------------------------------
All members of the A club are golfers
1 solutions
Answer 149057 by stanbon(57387) on 2009-06-01 07:42:51 (Show Source):
You can put this solution on YOUR website!Use Euler Diagrams to determine whether the following
syllogism is valid or invalid.
All golfers have golf carts.
Draw a circle for "have golf carts".
Put a circle inside that for "all golfers".
All members of the A club have golf carts.
Put a circle for "members of A club" inside
the "have golf carts circle"
--------------------------------------------------
All members of the A club are golfers
?Is the "members of A club" circle inside the
"all golfers" circle?
If it does not HAVE TO BE, the argument is invalid.
==========================================================
Note: It is an invalid argument.
==========================================================
Cheers,
Stan H.
|
Probability-and-statistics/198460: Here's another homework problem I am not sure how to do. The numbers don't seem to add up to one. Can someone please help and explain? Thanks for your help.
Find the mean and standard deviation of the following probability distribution:
x | 1 2 3
P(x) | 0.4 0.15 0.35
1 solutions
Answer 149056 by stanbon(57387) on 2009-06-01 07:35:04 (Show Source):
You can put this solution on YOUR website!Here's another homework problem I am not sure how to do. The numbers don't seem to add up to one. Can someone please help and explain? Thanks for your help.
Find the mean and standard deviation of the following probability distribution:
x | 1 2 3
P(x) | 0.4 0.15 0.35
---------------------------------
OK, so it's not a probability distribution.
If it was a probability distribution the following would apply.
---------
mean = Sum[x*P(x)] = 1*0.4 + 2*0.15 + 3*0.35 = 1.75
--------
Variance = Sum[(x-u)^2 * P(x)]
= (1-1.75)^2*0.4 + (2-1.75)^2*0.15 + (3-1.75)^2*0.35
= 0.78125
----------------
standard deviation = sqrt(variance) = 0.88388....
=============================================================
Cheers,
Stan H.
|
Complex_Numbers/198541: what kind of numbers are involved in complex numbers?????
1 solutions
Answer 149054 by stanbon(57387) on 2009-06-01 07:10:38 (Show Source):
You can put this solution on YOUR website!what kind of numbers are involved in complex numbers?????
--------------
Every complex number has the form a + bi where
a and b are Real Numbers and i is the sqrt of -1.
========================================================
Cheers,
Stan H.
|
Graphs/198515: Solve the following system of equations for the positive value of y:
x = 2y
x + y^2 = 15
1 solutions
Answer 149039 by stanbon(57387) on 2009-05-31 22:51:32 (Show Source):
You can put this solution on YOUR website!Solve the following system of equations for the positive value of y:
x = 2y
x + y^2 = 15
------------------
Substitue for "x" to get:
2y + y^2 = 15
y^2 + 2y - 15 = 0
(y+5)(y-3) = 0
y = -5 or y = 3
======================
Cheers,
Stan H.
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Permutations/198486: 1) In how many ways can 5 seats on a bench be assigned from amongst 12 people?
2)John and Harry Invited four other people to sit on their bench. In how many ways can these six people be seated on this bench if:
a)there are no restrictions
b)john is seated at the left end and Harry is seated at the right end
c)John and Harry must be seated together.
3)You bought five house numbers at your lumber supply store. The numbers are 1,2,3,4 and 5.How many three-digit house numbers a)are even? b)are possible?
1 solutions
Answer 149038 by stanbon(57387) on 2009-05-31 22:46:04 (Show Source):
You can put this solution on YOUR website!1) In how many ways can 5 seats on a bench be assigned from amongst 12 people?
If you count arrangements,
there are 12C5 = 792 ways
Each of these sets of people can be arranges in 5! = 30 ways
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Total # of arrangements = 792*30 = 23760 way
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2)John and Harry Invited four other people to sit on their bench. In how many ways can these six people be seated on this bench if:
a)there are no restrictions: 6! = 720 ways
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b)john is seated at the left end and Harry is seated at the right end
4! = 24 ways
--------------------------
c)John and Harry must be seated together.
5! = 120
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3)You bought five house numbers at your lumber supply store. The numbers are 1,2,3,4 and 5.
How many three-digit house numbers
a)are even?
pick the units digit: 2 ways
pick the 2nd digit: 4 ways
pick the 1st digit: 3 ways
Total # of ways: 2*3*4 = 24
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b)are possible? 5*4*3 = 60 ways
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Cheers,
Stan H.
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logarithm/198513: Describe the transformations on the following graph of f(x)=log(x). State the placement of the vertical asymptote and x-intercept after the transformation: a) g(x) = log (x -3) b) g(x) = log(-x)
1 solutions
Answer 149036 by stanbon(57387) on 2009-05-31 22:30:47 (Show Source):
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Linear-equations/198512: Find the equation of the line (in y = mx + b form) that passes through the points
(-8, 6.5) and (9, -11)
1 solutions
Answer 149035 by stanbon(57387) on 2009-05-31 22:19:49 (Show Source):
You can put this solution on YOUR website!Find the equation of the line (in y = mx + b form) that passes through the points
(-8, 6.5) and (9, -11)
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slope = (-11-6.5)/(9--8) = -17.5/17
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intercept: -11 = (-17.5/17)*9 + b
b = -11 + (9.2647..)
b= -1.7353...
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Equation:
y = (-17.5/17)x - 1.7353..
====================================
Cheers,
Stan H.
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Miscellaneous_Word_Problems/198507: please help I'm really having a hard time with this math problem
1.Given U = {21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31}, A = {21, 23, 25, 27, 29}, and
B = {22, 25, 28, 29}. Find A′ U B′.
1 solutions
Answer 149029 by stanbon(57387) on 2009-05-31 21:06:59 (Show Source):
You can put this solution on YOUR website!Given U = {21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31},
A = {21, 23, 25, 27, 29}, and
B = {22, 25, 28, 29}.
Find A′ U B′.
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A' = {22, 24, 26, 28, 30, 31}
B' = {21, 23, 24, 26, 27, 30, 31}
---------------
So A' U B' = {21, 22, 23, 24, 26, 27, 28, 30, 31}
=====================================================
Cheers,
Stan H.
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Mixture_Word_Problems/198480: please I need you help asap.
Express the following in set builder notation:
Z = {9, 10, 11, 12, 13, 14, 15, 16, 17}
thank you so much
1 solutions
Answer 149028 by stanbon(57387) on 2009-05-31 20:57:18 (Show Source):
You can put this solution on YOUR website!Express the following in set builder notation:
Z = {9, 10, 11, 12, 13, 14, 15, 16, 17}
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E = {x an element of N : 8 < x < 18}
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Cheers,
Stan H.
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logarithm/198508: Describe the transformations on the following graph of . State the placement of the vertical asymptote and x-intercept after the transformation
1 solutions
Answer 149027 by stanbon(57387) on 2009-05-31 20:54:06 (Show Source):
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Miscellaneous_Word_Problems/198503: please help My teacher saying that I'm not doing this correctly please show me thank you so much
1.In a survey of 100 consumers, 33 indicated that they were going to buy a new car, 18 said they were going to buy a new refrigerator, and 34 said they were going to buy a new washer. Of these, 7 were going to buy both a car and a refrigerator, 15 were going to buy a car and a washer, and 9 were going to buy a washer and a refrigerator. Three consumers indicated that they were going to buy all three items.
Construct a Venn diagram, label your diagram clearly.
Use your diagram to answer the following questions:
(a)How many were going to buy only a car?
(b)How many were going to buy only a washer?
(c)How many were going to buy only a refrigerator
(d)How many were going to buy a car and a washer but not a refrigerator?
(e)How many were going to buy none of these items?
1 solutions
Answer 149024 by stanbon(57387) on 2009-05-31 20:48:15 (Show Source):
You can put this solution on YOUR website!1.In a survey of 100 consumers,
33 indicated that they were going to buy a new car,
18 said they were going to buy a new refrigerator, and
34 said they were going to buy a new washer.
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Of these, 7 were going to buy both a car and a refrigerator,
15 were going to buy a car and a washer, and
9 were going to buy a washer and a refrigerator.
Three consumers indicated that they were going to buy all three items.
===============================================================
Construct a Venn diagram, label your diagram clearly.
=============================================================
Draw 3 intersecting circles all inside one rectangle.
Label the rectangle U = 100 (that is the universe)
Label each circle as C = 33, W=34, R=18
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Now start putting numbers in the circle.
Work from the inside to the outside.
Put a 3 in the intersection of all three circles.
---------------------------------------------
Then C intersect W = 15-3 = 12
And C intersect R = 7-3 = 4
And R intersect W = 9-3 = 6
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Then the rest of C has to be 33-(12+3+4) = 14
And the rest of R has to be 18-(4+3+6) = 5
And the rest of W has to be 34-(6+3+12) = 13
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And the inside of the rectangle, but outside the
3 circles is 100-(14+12+3+4+5+6+13) = 100 - 57 = 43
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Use your diagram to answer the following questions:
(a)How many were going to buy only a car? 14
(b)How many were going to buy only a washer? 13
(c)How many were going to buy only a refrigerator5
(d)How many were going to buy a car and a washer but not a refrigerator? 12
(e)How many were going to buy none of these items? 43
==========================================================
Cheers,
Stan H.
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Polynomials-and-rational-expressions/198498: lim 4x-1/8X^2+3X+1
->OO
what is the trick to this
1 solutions
Answer 149023 by stanbon(57387) on 2009-05-31 20:29:27 (Show Source):
You can put this solution on YOUR website!lim 4x-1/8X^2+3X+1
->OO
what is the trick to this
------------------------------
Since x is getting larger without bound,
it certainly is not zero.
---
So divide numerator and denominator by x^2 to get:
{[4x-1]/x^2}/{[8x^2+3x+1]/x^2
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Expand that to get:
{(4/x - 1/x^2)] / [8 + 3/x + 1/x^2]
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Take the limit of that as x goes to infinity.
Notice that the fractions with x in the denominator
approach zero as x approaches infinity.
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The limit is (0 - 0)/(8 + 0 + 0) = 0/8 = 0
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Hope that helps.
-------------------
what you are really finding is the horizontal asymptote.
=========================================================
Cheers,
Stan H.
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Graphs/198501: Find the equation of the axis of symmetry and the coordinates of the turning point for y=x^2+4x-3
1 solutions
Answer 149022 by stanbon(57387) on 2009-05-31 20:18:10 (Show Source):
You can put this solution on YOUR website!Find the equation of the axis of symmetry and the coordinates of the turning point for y=x^2+4x-3
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The vertex occurs when x = -b/2a = -4/2*1 = -2
The corresponding y-value is y = 2^2+(4*-2)-3 = -7
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Axis of symmetry is x = -2
---------------------------------
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Cheers,
Stan H.
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Quadratic_Equations/198502: Hello,
I would like to know how to find the equation of a quadratic graph when the x-intercepts and the vetex are not visible.
1 solutions
Answer 149021 by stanbon(57387) on 2009-05-31 20:11:26 (Show Source):
You can put this solution on YOUR website!how to find the equation of a quadratic graph when the x-intercepts and the vetex are not visible.
------------------------
That depends on what the graph DOES tell you,
like vertex, y,intercept, other????
Cheers,
Stan H.
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Subset/198483: I try to see if there were an example of this problem there was not please help.
A survey of residents in a small town showed the following:
25 ate beef 13 ate both beef and fish 9 ate all types
28 ate fish 14 ate both fish and poultry 7 ate none of them
30 ate poultry 15 ate both beef and poultry
12.
Draw a Venn diagram. Label your diagram clearly.
Use your diagram to answer the following questions:
(a) How many ate fish, but not poultry or beef?
(b) How many ate poultry and fish, but not beef?
(c) How many ate only beef?
(d) How many ate nothing or only poultry?
1 solutions
Answer 149008 by stanbon(57387) on 2009-05-31 16:36:49 (Show Source):
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Mixture_Word_Problems/198482: My head is spinning I really don't know this please show how thank you so much.
Set K contains 50 elements, set J contains 66 elements, and 14 elements are common to both sets. Find n (K U J).
1 solutions
Answer 149007 by stanbon(57387) on 2009-05-31 16:33:49 (Show Source):
You can put this solution on YOUR website!Set K contains 50 elements, set J contains 66 elements, and 14 elements are common to both sets. Find n (K U J).
--------------------
Draw two intersecting circles.
Label them K and J.
---------------
Put "14" in the intersection because 14 elements are common to both sets.
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Then the rest of K must have 50-14 = 36 elements.
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And the rest of J must have 66-14 = 52 elements.
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So the total number of elements is 52 + 14 + 36 = 102
======================================================
Cheers,
Stan H.
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Mixture_Word_Problems/198481: please I need your assistant again i really don't understands this please help. asap.
For sets A and B, determine whether A = B, A is a subset of B, or B is a subset of A
A = {x| x є N and 13 < x < 20}
B = {14, 15, 16, 17, 18}
1 solutions
Answer 149006 by stanbon(57387) on 2009-05-31 16:29:12 (Show Source):
You can put this solution on YOUR website!For sets A and B, determine whether A = B, A is a subset of B, or B is a subset of A
A = {x| x є N and 13 < x < 20}
B = {14, 15, 16, 17, 18}
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A = {14,15,16,17,18,19}
B = {14,15,16,17,18}
----------------------
So B is a subset of A since every element in B is an element in A.
-----------
A is not a subset of B because 19 is in A and not in B.
---------------
A is not equal to B because they do not have exactly the
same elements.
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Cheers,
Stan H.
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Probability-and-statistics/198408: Is this sample of 25 exam scores inconsistent with the hypothesis that the true variance is 64 (i.e. σ = 8)? Use the 5 percent level of significance in a two-sided test. Show all steps, including the hypotheses and critical values from Appendix E. Exams
80 79 69 71 74
73 77 75 65 52
81 84 84 79 70
78 62 77 68 77
88 70 75 85 84
1 solutions
Answer 149002 by stanbon(57387) on 2009-05-31 16:23:25 (Show Source):
You can put this solution on YOUR website!A worked example of this problem (with different data) can be
found in your text on page 384, Section 9.6 "Tests for one
Variance".
Cheers,
Stan H.
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Inequalities/198473: Hi!
Solve the inequality and express the solution using the interval notation.
abs(2x+1)> 1
thanks!
1 solutions
Answer 148995 by stanbon(57387) on 2009-05-31 15:58:28 (Show Source):
You can put this solution on YOUR website!abs(2x+1)> 1
====================
Since x is a variable value,
2x+1 might be positive or it might be negative.
----------------
If it is positive you get:
(2x+1) > 1
2x > 0
x > 0
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If it is negative you get:
-(2x+1) > 1
2x+1 < -1
2x < -2
x < -1
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So your solution is x < -1 OR x > 0
---
Using interval notation:
(-inf,-1) U (0,+inf)
==============================
Cheers,
Stan H.
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Probability-and-statistics/198457: Please help! I haven't the foggiest idea how to do an example problem with this formula. I look at it and freeze. Can someone help me? (This is a homework assn.)
If there are “k” possible outcomes for a phenomenon and each is equally likely, then each individual outcome has a probability 1/k. The probability of any event A is:
P(A) = count of Outcomes in A / count of outcomes in S
= count of outcomes in / k
1 solutions
Answer 148992 by stanbon(57387) on 2009-05-31 15:52:04 (Show Source):
You can put this solution on YOUR website!Please help! I haven't the foggiest idea how to do an example problem with this formula. I look at it and freeze. Can someone help me? (This is a homework assn.)
If there are “k” possible outcomes for a phenomenon and each is equally likely, then each individual outcome has a probability 1/k. The probability of any event A is:
P(A) = count of Outcomes in A / count of outcomes in S
= count of outcomes in / k
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They are trying to defind the probability of an event.
Say you flip a coin.
# of heads is one
# of tails is one
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The are two possible outcomes.
P(head) = 1/2
P(tail) = 1/2
In this case k = 2
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Say you have a die with faces 1,2,3,4,5,6
Here k = 6
There is only one way to get each of the results.
P(1) = 1/6
P(2) = 1/6
P(3) = 1/6
etc.
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Say you have a family of three children.
The pattern could be bbb,bgg,gbg,ggb,bbg,bgb,gbb,ggg
So there are 8 possible results.
The probability of having 2 girls in a family of
three is 3/8
Here k = 8
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P(success) = [# of ways to succeed]/[# of possible outcomes]
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Hope this helps.
Cheers,
Stan H.
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