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# Recent problems solved by 'stanbon'

Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 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56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179 , 57180..57209 , 57210..57239 , 57240..57269 , 57270..57299 , 57300..57329, >>Next

 Probability-and-statistics/198959: It is asserted that 80 percent of the cars approaching an individual toll booth in New Jersey are equipped with an EZ Pass transponder. Find the probability that in a sample of six cars: a) all six will have the transponder b) at least three will have the transponder c) none will have a transponder. 1 solutions Answer 149445 by stanbon(57377)   on 2009-06-04 14:52:46 (Show Source): You can put this solution on YOUR website!It is asserted that 80 percent of the cars approaching an individual toll booth in New Jersey are equipped with an EZ Pass transponder. Find the probability that in a sample of six cars: --------------- Since every car either has or does not have an EZ Pass, the problem is binomial. --------------- a) all six will have the transponder Ans: (0.8)^6 = 0.262 ---------------------------------- b) at least three will have the transponder Ans: 1 - binomcdf(6, 0.8, 2) = 0.983.. ---------------------------------- c) none will have a transponder. Ans: 0.2^6 = 0.000064 ================================== Cheers, Stan H.
 Probability-and-statistics/198782: The average number of days school is closed due to snow during the winter in a certain city in the eastern part of United States is 4.What is the probability that the school in this city will close for 2 or more days during winter1 solutions Answer 149384 by stanbon(57377)   on 2009-06-03 21:11:50 (Show Source): You can put this solution on YOUR website!The average number of days school is closed due to snow during the winter in a certain city in the eastern part of United States is 4.What is the probability that the school in this city will close for 2 or more days during winter ------------------------------------- You cannot answer this unless you know the probability of snow on a day in the winter. It's a binomial problem with np = 4. If you assume the "winter" means 365/4 = 91 days then p = 4/91. In that case P(x >= 2) = 1 - binomcdf(91,(4/91),1) = 0.9133 ------------------------------------------------------------------- Cheers, Stan H.
 Expressions-with-variables/198899: 5r-6s=21 6r+5s=74 Please help solve Answer: Solve for r and substitute 5r-6s=21 r=21-5s/5 substitute 5(21-5s/5)-6s=21 105-25s/5-6s=21 -5s-6s=21-105 -11s=-84 s=84/11 1 solutions Answer 149382 by stanbon(57377)   on 2009-06-03 20:59:38 (Show Source): You can put this solution on YOUR website!5r-6s=21 6r+5s=74 --------------- Multiply thru the 1st by 5 and the 2nd by 6 to get: 25r - 30s = 105 36r + 30s = 444 --------------------- Add to get: 61r = 549 r = 9 -------------- Substitute to solve for "s": 5*9 -6s = 21 45 -6s = 21 -6s = -24 s = 6 =================== Cheers, Stan H.
 Probability-and-statistics/198813: 1. Find the probability of x = 14 successes in n = 22 trials with the probability of success p = 0.6 on each trial. (2 points) About [?] % A bicycle-rental store has ten bicycles available for rent. On an average day, 60% of the bicycles are rented out. Answer the following questions. Round your answers to the nearest whole percent. 2. Find the probability that on one day, only four of the ten bicycles are rented out.[%]? 3. Find the probability that on one day, all ten of the bicycles are rented out.[%]? 1 solutions Answer 149372 by stanbon(57377)   on 2009-06-03 20:44:30 (Show Source): You can put this solution on YOUR website!1. Find the probability of x = 14 successes in n = 22 trials with the probability of success p = 0.6 on each trial. (2 points) About [?] % --- binompdf(22,0.6,14) = 0.164 or approx. 16% ---------------------------------------------- A bicycle-rental store has ten bicycles available for rent. On an average day, 60% of the bicycles are rented out. Answer the following questions. Round your answers to the nearest whole percent. 2. Find the probability that on one day, only four of the ten bicycles are rented out.[%]? binompdf(10,0.6,4) = 0.111 --------------------- 3. Find the probability that on one day, all ten of the bicycles are rented out.[%]? 0.6^10 = .006 -========================= Cheers, Stan H.
 Quadratic-relations-and-conic-sections/198646: x[squared]=9-y[squared]1 solutions Answer 149172 by stanbon(57377)   on 2009-06-02 07:09:19 (Show Source): You can put this solution on YOUR website!x[squared]=9-y[squared] -------- x^2 = 9 - y^2 So, x^2 + y^2 = 9 The graph is a circle with its center at (0,0) having a radius of 3. ---- Cheers, Stan H.
 Numeric_Fractions/198628: Can someone please help me with this? Given P(A) = .40, P(B) = .50. If A and B are independent, find P(A∩B). 1 solutions Answer 149171 by stanbon(57377)   on 2009-06-02 07:06:11 (Show Source): You can put this solution on YOUR website!Given P(A) = .40, P(B) = .50. If A and B are independent, find P(A∩B). --------------------------------- P(A and B) = P(A|B)*P(B) --- If you assume that A and B are independent you get: P(A and B) = P(A)*P(B) = 0.4*0.5 = 0.2 ------------ If you cannot assume that A and B are independent you don't have enough information to determine P(A and B). ================ Cheers, Stan H.
 Miscellaneous_Word_Problems/198649: suppose that four times a number is added to 16 and the result if positive. what are the possible numbers? A. any number less than -3 B. any number greater than -4 C. any number greater than 7 D. any number less than -41 solutions Answer 149170 by stanbon(57377)   on 2009-06-02 07:00:39 (Show Source): You can put this solution on YOUR website!suppose that four times a number is added to 16 and the result if positive. what are the possible numbers? --- 4x + 16 > 0 4x > - 16 x > -4 ---------------- Ans: B Cheers, Stan H. A. any number less than -3 B. any number greater than -4 C. any number greater than 7 D. any number less than -4
 Miscellaneous_Word_Problems/198652: With summer approaching, the number of air conditioners sold is expected to be doubled that of stoves and refrigerators combined. Stoves sell for \$200, refrigerators for \$300, and air conditioners for \$350, and sales are expected to be \$76000. If stoves and refrigerators sell in equal numbers, how many of each appliance should be stocked? 1 solutions Answer 149153 by stanbon(57377)   on 2009-06-01 22:44:08 (Show Source): You can put this solution on YOUR website!With summer approaching, the number of air conditioners sold is expected to be doubled that of stoves and refrigerators combined. a = 2(s + r) -------------------- Stoves sell for \$200, refrigerators for \$300, and air conditioners for \$350, and sales are expected to be \$76000. 200s + 300r + 350a = 76000 -------------------- If stoves and refrigerators sell in equal numbers, s = r ------------------- System: s - r + 0 = 0 2s + 2r - a = 0 200s + 300r + 350a = 76000 ------------------------------- Solve the system by any method you know to get: s = 40 (# of stoves to be stocked) r = 40 (# of refrigerators to be stocked) a = 160 (# of air conditioners to be stocked) ============================================================ Cheers, Stan H. how many of each appliance should be stocked? 0 solutions
 Travel_Word_Problems/198643: A cruise boat travels 72 miles down stream in two hours and returns upstream in 6 hours. Find the rate of the stream. D=RT so R=D/T 72/2=36 72/6=12 36-12=24 (speed of boat on still water?) I get lost here. 1 solutions Answer 149150 by stanbon(57377)   on 2009-06-01 22:22:46 (Show Source): You can put this solution on YOUR website!A cruise boat travels 72 miles down stream in two hours and returns upstream in 6 hours. Find the rate of the stream. ----------------------- Down stream DATA: distance = 72 miles ; time = 2 hrs: rate = d/t = 72/2 = 36 mph --------------------------- Up stream DATA: distance = 72 miles ; time = 6 hrs. rate = 72/6 = 12 mph ------------------------ Equations Down stream rate: b + c = 36 mph Upstream rate...: b - c = 12 ------------------------------------- Add to get 2b = 48 b = 24 mph (rate of the boat in still water) --- Substitute to find "c": b+c = 24 + c = 36 c = 36-24 = 12 mph (speed of the current) =============================================== Cheers, Stan H.
 Miscellaneous_Word_Problems/198650: what is the correct classification of the following polynomial? A. Trinomial B. Monomial C. Binomial D. None of the above1 solutions Answer 149148 by stanbon(57377)   on 2009-06-01 22:16:48 (Show Source): You can put this solution on YOUR website!The polynomial did not get posted. Cheers, Stan H.
 Functions/198635: f(t)=4.5e^t I don't know how to explain how to get the answer1 solutions Answer 149141 by stanbon(57377)   on 2009-06-01 21:17:47 (Show Source): You can put this solution on YOUR website!f(t)=4.5e^t --- You did not say what you wanted to do with with equation. ---------------- Cheers, Stan H.
 Exponential-and-logarithmic-functions/198636: Simplify log2 2^51 solutions Answer 149140 by stanbon(57377)   on 2009-06-01 21:14:36 (Show Source): You can put this solution on YOUR website!Simplify log2 2^5 ------------------------- Let y = log2 2^5 Then 2^y = 2^5 Then y = 5 =================== Cheers, Stan H.
 Expressions-with-variables/198642: 3x^3-27x^2+60x=01 solutions Answer 149139 by stanbon(57377)   on 2009-06-01 21:11:59 (Show Source): You can put this solution on YOUR website!3x^3-27x^2+60x=0 2x is a common factor: --- 3x(x^2 - 9x + 20) = 0 --- 3x(x-5)(x-4)= 0 x = 0 or x = 5 or x = 4 ============================== Cheers, Stan H.
 Expressions-with-variables/198640: 4x^2+32x-80=0 my answer is (2x-1)(x+10)^21 solutions Answer 149138 by stanbon(57377)   on 2009-06-01 21:09:01 (Show Source): You can put this solution on YOUR website!4x^2+32x-80=0 4 is a common factor: ---- 4(x^2 + 8x - 20) = 0 4(x + 10)(x-2) = 0 x = -10 or x = 2 ========================== Cheers, Stan H.
 Exponential-and-logarithmic-functions/198621: What is the inverse of the function y=2ln(x-5) My answer choices are: A) y= (x/ln2)+5 B) x= (y/ln2)+5 C) y= 2e^(x-5) D) y= e^(2x)+5 E) y= e^(0.5x)+5 I think it's A but I'm not sure. Please help!1 solutions Answer 149137 by stanbon(57377)   on 2009-06-01 20:55:16 (Show Source): You can put this solution on YOUR website!What is the inverse of the function y=2ln(x-5) My answer choices are: --- To find the inverse, interchange x and y to get: x = 2ln(y-5) Solve for "y": ln(y-5) = x/2 y-5 = e^(x/2) y = e^(x/2)+5 y = e^(0.5x) + 5 --- The answer is E. Cheers, Stan H. ------------------- A) y= (x/ln2)+5 B) x= (y/ln2)+5 C) y= 2e^(x-5) D) y= e^(2x)+5 E) y= e^(0.5x)+5
 Probability-and-statistics/198605: (The solution to this problem was from another question) Could I get help on this one? A telemarketer makes six phone calls per hour and is able to make a sale on 30% of these contacts. During the next two hours. Find: a) The probability of exactly making four sales. b) The probability of making no sales. c) The probability of exactly making two sales. d) The mean number of sales within the two-hour period. 1 solutions Answer 149136 by stanbon(57377)   on 2009-06-01 20:47:42 (Show Source): You can put this solution on YOUR website!A telemarketer makes six phone calls per hour and is able to make a sale on 30% of these contacts. During the next two hours. Find: a) The probability of exactly making four sales. Ans: 6C4(0.3)^4(0.7)^2) = 0.0595 -------------------------------------------- b) The probability of making no sales. Ans: (0.7)^4 = 0.2401 -------------------------------------------- c) The probability of exactly making two sales. Ans: 6C2(0.3)^2(0.7)^4 = 324135... --------------------------------------------- d) The mean number of sales within the two-hour period. mean = np = 6*0.3 = 1.8 sales ===================================== Cheers, Stan H.
 Probability-and-statistics/198622: I need help with this problem. Stats is definitely not my thing. This contingency table shows average yield (rows) and average duration (columns) for 38 bond funds. Average Portfolio Duration Yield Short(D1) Intermediate(D2) Long(D3) Row Total Small(Y1) 8 2 0 10 Medium(Y2) 1 6 6 13 High(Y3) 2 4 9 15 Column Total 11 12 15 38 Required: For a randomly chosen bond fund, find the probability of the following: a. The bond fund is of long duration b. The bond fund has high yield c. The bond fund has high yield given that it is of short duration d. The bond fund is of short duration given that it has high yield 1 solutions Answer 149135 by stanbon(57377)   on 2009-06-01 20:41:42 (Show Source): You can put this solution on YOUR website!Please post the data in a rectangular array. Cheers, Stan H.
 Probability-and-statistics/198601: Sixty-four students in an introductory college economics class were asked how many credits they had earned in college, and how certain they were about their choice of major. Research question: At � = .01, is the degree of certainty independent of credits earned? Certainty Credits Earned Very Uncertain Somewhat Certain Very Certain Row Total 0 -9 12 8 3 23 10-59 8 4 10 22 60 or more 1 7 11 19 Col Total 21 19 24 64 Applied Statistics in Business and Economics (2007) by David P. Doane and Lori E. Seward 1 solutions Answer 149134 by stanbon(57377)   on 2009-06-01 20:38:19 (Show Source): You can put this solution on YOUR website!Sixty-four students in an introductory college economics class were asked how many credits they had earned in college, and how certain they were about their choice of major. Research question: At � = .01, is the degree of certainty independent of credits earned? Certainty Credits Earned Very Uncertain Somewhat Certain Very Certain Row Total 0 -9 12 8 3 23 10-59 8 4 10 22 60 or more 1 7 11 19 Col Total 21 19 24 64 ------------------------- Ho: degree of certainty is independent of credits earned H1: they are dependent -------------------- Run a Chi-Sq test on the 3 by 4 set of data to get: test statistic: Chi-Sq = 14.76 p-value = 0.0222 --- Decision: Since the p-value is greater than 1%, Fail to reject Ho. The row and column factors are independent. ============================================= Cheers, Stan H.
 Miscellaneous_Word_Problems/198587: The half-life of tritium is 12.4 years. How long will it take for 15% of a sample of tritium to decompose? An isotope of thorium, , has a half-life of 18.4 days. How long will it take for 77% of the sample to decompose? 1 solutions Answer 149115 by stanbon(57377)   on 2009-06-01 18:32:36 (Show Source): You can put this solution on YOUR website!The half-life of tritium is 12.4 years. How long will it take for 15% of a sample of tritium to decompose? If 15% decomposes, 85% remains. ----------------- A(t) = Ao*e^(-ln(2t)/12.4) 0.85 = e^(-ln(2t)/12.4) 0.85 = 2t/12.4 2t = 10.54 t = 5.27 years An isotope of thorium, , has a half-life of 18.4 days. How long will it take for 77% of the sample to decompose? --- 0.23 = e^(-ln(2t)/18.4) 0.23 = 2t/18.4 2t = 4.232 t = 2.116 days ======================= Cheers, Stan H.
 Probability-and-statistics/198560: The United States Postal Service reports 95% of first class mail within the same city is delivered within two days of the time of the mailing. Six letters are randomly sent to different locations a) What is the probability all six arrive within two days? b) What is the probability that exactly five arrive within two days? c) Find the mean number of letters that will arrive within two days d) Compute the variance and Standard Deviation of the number that will arrive within two days. 1 solutions Answer 149113 by stanbon(57377)   on 2009-06-01 18:08:04 (Show Source): You can put this solution on YOUR website!The United States Postal Service reports 95% of first class mail within the same city is delivered within two days of the time of the mailing. Six letters are randomly sent to different locations -------------------------------------------------------------------- a) What is the probability all six arrive within two days? Ans: (0.95)^6 = 0.735 ---------------------------------------------- b) What is the probability that exactly five arrive within two days? Ans: 6C5(0.95)^5(0.05)^1 = 0.2321 ---------------------------------------------- c) Find the mean number of letters that will arrive within two days Ans: u = np = 6*0.95 = 5.7 ---------------------------------------------- d) Compute the variance and Standard Deviation of the number that will arrive within two days. Ans: variance = npq = 6*0.95*0.05 = 0.285 stdev = sqrt(0.285) = 0.5339 ======================================== Cheers, Stan H.
 Probability-and-statistics/198562: Backyard Retreats, Inc, sells an exclusive line of pools, hot tubs, and spas. It is located just off the Bee Line Expressway in Orlando, Florida. The owner reports 20% of the customers entering the store will make a purchase of at least \$50. Suppose 15 customers enter the store before 10am on a particular Saturday a) How many of these customers would you expect to make a purchase of at least \$50? b) What is the probability exactly five of these customers make a purchase of at least \$50? c) What is the probability at least five of these customers make a purchase of at least \$50? d) What is the probability at least one customers make a purchase of at least \$50? 1 solutions Answer 149112 by stanbon(57377)   on 2009-06-01 17:54:07 (Show Source): You can put this solution on YOUR website!done Cheers, Stan H.
 Probability-and-statistics/198561: A telemarketer makes six phone calls per hour and is able to make a sale on 30% of these contacts. During the next two hours. Find: a) The probability of exactly making four sales. b) The probability of making no sales. c) The probability of exactly making two sales. d) The mean number of sales within the two-hour period. 1 solutions Answer 149111 by stanbon(57377)   on 2009-06-01 17:49:59 (Show Source): You can put this solution on YOUR website!The owner reports 20% of the customers entering the store will make a purchase of at least \$50. Suppose 15 customers enter the store before 10am on a particular Saturday a) How many of these customers would you expect to make a purchase of at least \$50? Ans: 0.20*15 = 3 ---------------------------- b) What is the probability exactly five of these customers make a purchase of at least \$50? Ans: 15C5(0.2)^5(0.8)^10 = 0.1032 --------------------------------------------------- c) What is the probability at least five of these customers make a purchase of at least \$50? Ans 1 - binomcdf(15,0.2,4) = 0.16423.... --------------------------------------------------- d) What is the probability at least one customers make a purchase of at least \$50? Ans: 1 - binomcdf(15,0.2,0) = 0.96482... ============================================ Cheers, Stan H.
 Probability-and-statistics/198596: Which sneakers are prefered? female- running 12 cross training 28 Male- running 42 cross training 14 3. P(female | running) 4. P(female | cross training) 5. P(male | running) 6. P(male | cross training) For questions 7 and 8, find the mean, median, and mode of each data set. 8.) 5 7 10 10 7 9 5 6 7 7 4 10.) 12 13 14 9 7 8 15 10 11 6 1 solutions Answer 149108 by stanbon(57377)   on 2009-06-01 17:33:34 (Show Source): You can put this solution on YOUR website!Which sneakers are prefered? female- running 12 cross training 28 Male- running 42 cross training 14 --------------------------------------------------- 3. P(female | running) = 12/54 4. P(female | cross training) = 28/42 5. P(male | running) = 42/54 6. P(male | cross training) = 14/42 ========================================== Cheers, Stan H.
 Finance/198571: This question is from textbook beginning algebra How do i set up an equation for this problem? There are a total of 500 douglas fir and hemlock trees in a section of the forest purchased by the hoodoo logging co. the company paid an average of \$205 for each douglas fir and \$300 for each hemlock. If the company paid a total of \$132,000 for the trees how many of each kind did the company buy?1 solutions Answer 149101 by stanbon(57377)   on 2009-06-01 15:31:41 (Show Source): You can put this solution on YOUR website!How do i set up an equation for this problem? There are a total of 500 douglas fir and hemlock trees in a section of the forest purchased by the hoodoo logging co. the company paid an average of \$205 for each douglas fir and \$300 for each hemlock. If the company paid a total of \$132,000 for the trees how many of each kind did the company buy? ---------------------------------- Quantity Eq. : f + h = 500 Value Eq.... :205f+300h = 132,000 --------------------------------------- Modify the 1st equation: 205f + 205h = 205*500 205f + 300h = 132000 -------------------------------- Subtract 1st from 2nd to get: 95h = 29500 h = 310.52 (# of hemlock trees bought) f = 500-h = 189.47 # of fir trees bought) =============================================== Cheers, Stan H.
 Polynomials-and-rational-expressions/198578: complex rational expressions 1/5 - 1/y __________ 5-y/5 1 solutions Answer 149099 by stanbon(57377)   on 2009-06-01 15:22:28 (Show Source): You can put this solution on YOUR website!1/5 - 1/y __________ 5-y/5 ======================= [(y-5)/(5y)] / [(25-y)/5] ----- Invert the denominator and multiply to get: = [(y-5)/(5y)] * [5/(25-y)] ------ Cancel the "5" factor to get: = (y-5)/(y(25-y)) ====================== Cheers, Stan H.
 Finance/198579: A charity group which feeds homeless children, receives a donation of \$3780 for food. They plan to use \$180 each day. At the end of what day will they have \$1260 left? 1 solutions Answer 149097 by stanbon(57377)   on 2009-06-01 15:16:23 (Show Source): You can put this solution on YOUR website!A charity group which feeds homeless children, receives a donation of \$3780 for food. They plan to use \$180 each day. At the end of what day will they have \$1260 left? ---------------- 3780 - 1260 = \$2520 (amt. they have spent) -------------- 2520/180 = 14 days (# of days to spend the @2520) ============================================== Cheers, Stan H.
 Probability-and-statistics/198568: Blockbuster is testing a new policy of waiving all late fees on DVD rentals using a sample of 10 randomly chosen customers. (a) At a-.10, does the data show that the man number of monthly rentals has increased? (b) Is the decision close? (c) Are you convinced? Customer No Late Fee Late Fee 1 14 10 2 12 7 3 14 10 4 13 13 5 10 9 6 13 14 7 12 12 8 10 7 9 13 13 10 13 9 I can figure out the mean which is 12.4 of no late fee but cannot figure out the rest, can someone please help. Thanks 1 solutions Answer 149096 by stanbon(57377)   on 2009-06-01 15:11:46 (Show Source): You can put this solution on YOUR website!Blockbuster is testing a new policy of waiving all late fees on DVD rentals using a sample of 10 randomly chosen customers. (a) At a-.10, does the data show that the man number of monthly rentals has increased? (b) Is the decision close? (c) Are you convinced? Customer No Late Fee Late Fee 1 14 10 2 12 7 3 14 10 4 13 13 5 10 9 6 13 14 7 12 12 8 10 7 9 13 13 10 13 9 ----------------- These data are dependent pairs because each pair measures a "before" and "after" for the same person. --------------------- Make a list for each data set. Make a list of the difference (no late fee)-(late fee) ------------ ------------------ Run a t-test on the difference of the 10 pairs. mean of the difference = 2 -------------------------------------- Ho: u(difference) = 0 H1: u(difference) > 0 Decision Rule: Reject Ho if the test statistic is greater than 1.383.. test statistic: t = 2.8604 p-value: 0.0094 ----------- Conclusion: Since the p-value is less than 10%, reject Ho. The test provides evidence that the mean of the differences is not zero. ====================== Cheers, Stan H.
 Exponential-and-logarithmic-functions/198550: solve: log6(5-2a)-log6(3a)=11 solutions Answer 149062 by stanbon(57377)   on 2009-06-01 09:59:44 (Show Source): You can put this solution on YOUR website!solve: log6(5-2a)-log6(3a)=1 ------------ log6[(5-2a)/(3a)] = 1 (5-2a)/3a = 6^1 5-2a = 18a 20a = 5 a = 1/4 ----------------- Cheers, Stan H.
 Geometry_proofs/198538: I need help!! Can someone please help me with this problem? Thank you!!!! 7. (4 pts) Use Euler Diagrams to determine whether the following syllogism is valid or invalid. All golfers have golf carts. All members of the A club have golf carts. -------------------------------------------------- All members of the A club are golfers 1 solutions Answer 149057 by stanbon(57377)   on 2009-06-01 07:42:51 (Show Source): You can put this solution on YOUR website!Use Euler Diagrams to determine whether the following syllogism is valid or invalid. All golfers have golf carts. Draw a circle for "have golf carts". Put a circle inside that for "all golfers". All members of the A club have golf carts. Put a circle for "members of A club" inside the "have golf carts circle" -------------------------------------------------- All members of the A club are golfers ?Is the "members of A club" circle inside the "all golfers" circle? If it does not HAVE TO BE, the argument is invalid. ========================================================== Note: It is an invalid argument. ========================================================== Cheers, Stan H.