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Recent problems solved by 'stanbon'
stanbon answered: 57314 problems
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2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 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43110..43139 , 43140..43169 , 43170..43199 , 43200..43229 , 43230..43259 , 43260..43289 , 43290..43319 , 43320..43349 , 43350..43379 , 43380..43409 , 43410..43439 , 43440..43469 , 43470..43499 , 43500..43529 , 43530..43559 , 43560..43589 , 43590..43619 , 43620..43649 , 43650..43679 , 43680..43709 , 43710..43739 , 43740..43769 , 43770..43799 , 43800..43829 , 43830..43859 , 43860..43889 , 43890..43919 , 43920..43949 , 43950..43979 , 43980..44009 , 44010..44039 , 44040..44069 , 44070..44099 , 44100..44129 , 44130..44159 , 44160..44189 , 44190..44219 , 44220..44249 , 44250..44279 , 44280..44309 , 44310..44339 , 44340..44369 , 44370..44399 , 44400..44429 , 44430..44459 , 44460..44489 , 44490..44519 , 44520..44549 , 44550..44579 , 44580..44609 , 44610..44639 , 44640..44669 , 44670..44699 , 44700..44729 , 44730..44759 , 44760..44789 , 44790..44819 , 44820..44849 , 44850..44879 , 44880..44909 , 44910..44939 , 44940..44969 , 44970..44999 , 45000..45029 , 45030..45059 , 45060..45089 , 45090..45119 , 45120..45149 , 45150..45179 , 45180..45209 , 45210..45239 , 45240..45269 , 45270..45299 , 45300..45329 , 45330..45359 , 45360..45389 , 45390..45419 , 45420..45449 , 45450..45479 , 45480..45509 , 45510..45539 , 45540..45569 , 45570..45599 , 45600..45629 , 45630..45659 , 45660..45689 , 45690..45719 , 45720..45749 , 45750..45779 , 45780..45809 , 45810..45839 , 45840..45869 , 45870..45899 , 45900..45929 , 45930..45959 , 45960..45989 , 45990..46019 , 46020..46049 , 46050..46079 , 46080..46109 , 46110..46139 , 46140..46169 , 46170..46199 , 46200..46229 , 46230..46259 , 46260..46289 , 46290..46319 , 46320..46349 , 46350..46379 , 46380..46409 , 46410..46439 , 46440..46469 , 46470..46499 , 46500..46529 , 46530..46559 , 46560..46589 , 46590..46619 , 46620..46649 , 46650..46679 , 46680..46709 , 46710..46739 , 46740..46769 , 46770..46799 , 46800..46829 , 46830..46859 , 46860..46889 , 46890..46919 , 46920..46949 , 46950..46979 , 46980..47009 , 47010..47039 , 47040..47069 , 47070..47099 , 47100..47129 , 47130..47159 , 47160..47189 , 47190..47219 , 47220..47249 , 47250..47279 , 47280..47309 , 47310..47339 , 47340..47369 , 47370..47399 , 47400..47429 , 47430..47459 , 47460..47489 , 47490..47519 , 47520..47549 , 47550..47579 , 47580..47609 , 47610..47639 , 47640..47669 , 47670..47699 , 47700..47729 , 47730..47759 , 47760..47789 , 47790..47819 , 47820..47849 , 47850..47879 , 47880..47909 , 47910..47939 , 47940..47969 , 47970..47999 , 48000..48029 , 48030..48059 , 48060..48089 , 48090..48119 , 48120..48149 , 48150..48179 , 48180..48209 , 48210..48239 , 48240..48269 , 48270..48299 , 48300..48329 , 48330..48359 , 48360..48389 , 48390..48419 , 48420..48449 , 48450..48479 , 48480..48509 , 48510..48539 , 48540..48569 , 48570..48599 , 48600..48629 , 48630..48659 , 48660..48689 , 48690..48719 , 48720..48749 , 48750..48779 , 48780..48809 , 48810..48839 , 48840..48869 , 48870..48899 , 48900..48929 , 48930..48959 , 48960..48989 , 48990..49019 , 49020..49049 , 49050..49079 , 49080..49109 , 49110..49139 , 49140..49169 , 49170..49199 , 49200..49229 , 49230..49259 , 49260..49289 , 49290..49319 , 49320..49349 , 49350..49379 , 49380..49409 , 49410..49439 , 49440..49469 , 49470..49499 , 49500..49529 , 49530..49559 , 49560..49589 , 49590..49619 , 49620..49649 , 49650..49679 , 49680..49709 , 49710..49739 , 49740..49769 , 49770..49799 , 49800..49829 , 49830..49859 , 49860..49889 , 49890..49919 , 49920..49949 , 49950..49979 , 49980..50009 , 50010..50039 , 50040..50069 , 50070..50099 , 50100..50129 , 50130..50159 , 50160..50189 , 50190..50219 , 50220..50249 , 50250..50279 , 50280..50309 , 50310..50339 , 50340..50369 , 50370..50399 , 50400..50429 , 50430..50459 , 50460..50489 , 50490..50519 , 50520..50549 , 50550..50579 , 50580..50609 , 50610..50639 , 50640..50669 , 50670..50699 , 50700..50729 , 50730..50759 , 50760..50789 , 50790..50819 , 50820..50849 , 50850..50879 , 50880..50909 , 50910..50939 , 50940..50969 , 50970..50999 , 51000..51029 , 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53010..53039 , 53040..53069 , 53070..53099 , 53100..53129 , 53130..53159 , 53160..53189 , 53190..53219 , 53220..53249 , 53250..53279 , 53280..53309 , 53310..53339 , 53340..53369 , 53370..53399 , 53400..53429 , 53430..53459 , 53460..53489 , 53490..53519 , 53520..53549 , 53550..53579 , 53580..53609 , 53610..53639 , 53640..53669 , 53670..53699 , 53700..53729 , 53730..53759 , 53760..53789 , 53790..53819 , 53820..53849 , 53850..53879 , 53880..53909 , 53910..53939 , 53940..53969 , 53970..53999 , 54000..54029 , 54030..54059 , 54060..54089 , 54090..54119 , 54120..54149 , 54150..54179 , 54180..54209 , 54210..54239 , 54240..54269 , 54270..54299 , 54300..54329 , 54330..54359 , 54360..54389 , 54390..54419 , 54420..54449 , 54450..54479 , 54480..54509 , 54510..54539 , 54540..54569 , 54570..54599 , 54600..54629 , 54630..54659 , 54660..54689 , 54690..54719 , 54720..54749 , 54750..54779 , 54780..54809 , 54810..54839 , 54840..54869 , 54870..54899 , 54900..54929 , 54930..54959 , 54960..54989 , 54990..55019 , 55020..55049 , 55050..55079 , 55080..55109 , 55110..55139 , 55140..55169 , 55170..55199 , 55200..55229 , 55230..55259 , 55260..55289 , 55290..55319 , 55320..55349 , 55350..55379 , 55380..55409 , 55410..55439 , 55440..55469 , 55470..55499 , 55500..55529 , 55530..55559 , 55560..55589 , 55590..55619 , 55620..55649 , 55650..55679 , 55680..55709 , 55710..55739 , 55740..55769 , 55770..55799 , 55800..55829 , 55830..55859 , 55860..55889 , 55890..55919 , 55920..55949 , 55950..55979 , 55980..56009 , 56010..56039 , 56040..56069 , 56070..56099 , 56100..56129 , 56130..56159 , 56160..56189 , 56190..56219 , 56220..56249 , 56250..56279 , 56280..56309 , 56310..56339 , 56340..56369 , 56370..56399 , 56400..56429 , 56430..56459 , 56460..56489 , 56490..56519 , 56520..56549 , 56550..56579 , 56580..56609 , 56610..56639 , 56640..56669 , 56670..56699 , 56700..56729 , 56730..56759 , 56760..56789 , 56790..56819 , 56820..56849 , 56850..56879 , 56880..56909 , 56910..56939 , 56940..56969 , 56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179 , 57180..57209 , 57210..57239 , 57240..57269 , 57270..57299 , 57300..57329, >>NextProbability-and-statistics/201533: A bag of marbles contains 6 red marbles and 4 blue marbles. If two are selected
simultaneously, what is the probability that at least 1 blue marble is drawn? 1 solutions
Answer 151779 by stanbon(57387) on 2009-06-29 20:36:07 (Show Source):
You can put this solution on YOUR website!A bag of marbles contains 6 red marbles and 4 blue marbles. If two are selected
simultaneously, what is the probability that at least 1 blue marble is drawn?
-------------------
P(at least one is blue) = 1 - P(none are blue)
= 1 - [6C2/10C2]
= 1 - 15/45
= 1 - (1/3)
= 2/3
=================
Cheers,
Stan H.
|
Probability-and-statistics/201518: If a tire has a mean mileage of 60,000 miles and a standard deviation of 2,000, and the company doesn't want to have a replacement expense of more than 4%, what is the minimum guaranteed mileage for the tire? 1 solutions
Answer 151778 by stanbon(57387) on 2009-06-29 20:32:29 (Show Source):
You can put this solution on YOUR website!If a tire has a mean mileage of 60,000 miles and a standard deviation of 2,000, and the company doesn't want to have a replacement expense of more than 4%, what is the minimum guaranteed mileage for the tire?
---------------
Draw the normal curve with center at 60,000.
Note that sigma = 2000
-----
Mark a point in the left tail that has 4$ of the miles driven to the left.
-------------------
Find the z-value of that point using your z-chart or calculator.
I get InvNorm(0.04) = -1.7507
------------------------------------
Now find the "raw score" corresponding to that z-score using
x = z*sigma + mu
x = -1.7507*2000 + 60000
x = 56498.63 miles
That is the number of miles for which they should warrant the tires.
========================================
Cheers,
Stan H.
|
Probability-and-statistics/201542: Card figure: 1 A, 2 B's, 3 C's
Referring to the figure in Question #26, think about first picking a card and
then rolling the die. Give the probability in simplest form.
P(C,even number) 1 solutions
Answer 151777 by stanbon(57387) on 2009-06-29 20:24:50 (Show Source):
You can put this solution on YOUR website!Card figure: 1 A, 2 B's, 3 C's
Referring to the figure in Question #26, think about first picking a card and
then rolling the die. Give the probability in simplest form.
P(C,even number)
--------------------------
P(C and even number) = (3/6)(1/2) = 1/4
--------------------------------------------
Cheers,
Stan H.
|
Probability-and-statistics/201543: Card figure: 1 A, 2 B's, 3 C's
Referring to the figure in Question #26, think about first picking a card and
then rolling the die. Give the probability in simplest form.
P(not A,6) 1 solutions
Answer 151776 by stanbon(57387) on 2009-06-29 20:22:34 (Show Source):
You can put this solution on YOUR website!Card figure: 1 A, 2 B's, 3 C's
Referring to the figure in Question #26, think about first picking a card and
then rolling the die. Give the probability in simplest form.
P(not A,6)
---------------------
P(not A) = 5/6
P(6 on the die) = 1/6
-----------
The events are independent so,
P(notA and 6) = (5/6)*(1/6) = 5/36
========================================
Cheers,
Stan H.
|
Probability-and-statistics/201545: On any given night, Becky has a 60% chance of seeing a shooting star in any given hour. If Becky watches the sky for two hours, find the following probabilities
a. What is the probability that Becky sees a shooting star in both hours?
b. What is the probability that Becky sees a shooting star in exactly one hour?
c. What is the probability that Becky does not see a shooting star at all?
d. Given that Becky did not see a shooting star in the first hour, what is the probability that she will see one in the second hour?
1 solutions
Answer 151775 by stanbon(57387) on 2009-06-29 20:17:02 (Show Source):
You can put this solution on YOUR website!On any given night, Becky has a 60% chance of seeing a shooting star in any given hour. If Becky watches the sky for two hours, find the following probabilities
These are Binomial problems.
p = 0.6 ; q = 0.4
a. What is the probability that Becky sees a shooting star in both hours?
n = 2 ; = 0.6 ; x = 2
P(x=2) = 0.6^2 = 0.36
---------------------------------------
b. What is the probability that Becky sees a shooting star in exactly one hour?
P(x = 1) = 1 - [P(x=0) + P(x=2)] = 1 - (0.4)^2 - 0.6)^2 = 1 -0.16 - 0.36 = 0.48
------------------------------------------
c. What is the probability that Becky does not see a shooting star at all?
P(x=0) = 0.4^2 = 0.16
------------------------------------------
d. Given that Becky did not see a shooting star in the first hour, what is the probability that she will see one in the second hour?
The events are independent:
P(x = 1 in the 2nd hour) = 0.6
------------------------------------------
Cheers,
Stan H.
|
Geometry_Word_Problems/201482: A disc jockey must play 16 commercial spots during 1 hour of a radio show. Each commercial is either 30 seconds long or 60 seconds long. If the total commercial time during 1 hour is 13 min, how many 30 second commercials were played that hour? How many 60 second commercials? 1 solutions
Answer 151704 by stanbon(57387) on 2009-06-29 06:10:16 (Show Source):
You can put this solution on YOUR website!A disc jockey must play 16 commercial spots during 1 hour of a radio show. Each commercial is either 30 seconds long or 60 seconds long. If the total commercial time during 1 hour is 13 min, how many 30 second commercials were played that hour? How many 60 second commercials?
--------------------------------------------------
Quantity Equation: s + t = 16
time Equation: 60s + 30t = 13*60
----------------------------
Simplify
s + t = 16
2s + t = 26
-------------------
Subtract 1st from 2nd to get:
s = 10 (# of sixty second commercials)
---
Substitute to solve for "t":
10 + t = 16
t = 6 (# of thirty second commercials)
=============================================
Cheers,
Stan H.
|
Expressions-with-variables/201421: Please help me solve this problem:
y=1/2x-3
y=1/3x+2
I tried this
y=1/3x+2
-1/3x+y=2
-y=-y
-1/3x =-y+2
3/1(-1/3x)=(-y+2)3/1
x=-3y+6
Then substitue x=-3y+6
y=1/x(-3y+6)-3
y=-3/xy+6/2-3
y=-3/2y+3-3
But now I am lost 1 solutions
Answer 151643 by stanbon(57387) on 2009-06-28 12:47:38 (Show Source):
You can put this solution on YOUR website!y=1/2x-3
y=1/3x+2
------------
Substitute to get:
(1/2)x - 3 = (1/3)x + 2
[(1/2)-(1/3)]x = 5
(1/6)x = 5
x = 30
-----------
y = (1/2)30 - 3
y = 12
======================
Cheers,
Stan H.
|
Expressions-with-variables/201422: Please help me solve this problem:
x=1/8y-1
y=1/4x+3 1 solutions
Answer 151642 by stanbon(57387) on 2009-06-28 12:36:36 (Show Source):
You can put this solution on YOUR website!Please help me solve this problem:
x=1/8y-1
y=1/4x+3
------------
Rewrite:
y = 8x + 8
y = (1/4)x + 3
-------------------
Substitute to get:
8x + 8 = (1/4)x + 3
(31/4)x = - 5
x = -20/31
----------------
Substitute to solve for "y":
y = (1/4)(-20/31) + 3
y = -5/31 + 93/31
y = 88/31
===============================
Cheers,
Stan H.
|
Equations/201318: Solve the inequality and graph the solution.
9|x-1| (>or=) 9 1 solutions
Answer 151604 by stanbon(57387) on 2009-06-27 21:31:13 (Show Source):
You can put this solution on YOUR website!Solve the inequality and graph the solution.
9|x-1| (>or=) 9
-------------------------------
9|x-1| > = 9
|x-1| >= 1
x-1 >= 1 or -(x-1) >=1
x >= 2 or x-1 <= -1
x >=2 or x <= 0
======================
Cheers,
Stan H.
|
Exponents/201355: This question is from textbook Mathematics For Technical trades
Here is another problem I have an cannot figure out.
Using the formula L=2C + 1.57(D+d)+ D+d find L for D = 8",d=5,and C=19.
_____
4C
1 solutions
Answer 151573 by stanbon(57387) on 2009-06-27 15:20:42 (Show Source):
You can put this solution on YOUR website!Using the formula L=2C + 1.57(D+d)+ (D+d)/(4C) find L for D = 8",d=5,and C=19.
---
L = 2*19 + 1.57(8+5) + (8+5)/(4*19)
L = 38 + 1.57*13 + 13/76
L = 38 + 20.41 + 0.1710526..
L = 58.58...
Cheers,
Stan H.
|
Miscellaneous_Word_Problems/201347: Spencer makes 9 out of 13 shots in the first half of a basketball game.
How many consecutive shots must he make in the second half of the game to
raise his percentage to 96%? 1 solutions
Answer 151568 by stanbon(57387) on 2009-06-27 15:13:54 (Show Source):
You can put this solution on YOUR website!Spencer makes 9 out of 13 shots in the first half of a basketball game.
How many consecutive shots must he make in the second half of the game to
raise his percentage to 96%?
----------------------------------
Let "x" be the number of consecutive shots he need to make.
Equation:
(9+x)/(13+x) = 0.96
9+x = 0.96(13+x)
900 + 100x = 96(13+x)
900 + 100x = 1248 + 96x
4x = 348
x = 87 (# of consecutive shots he must make to get to 96%)
=============================================================
Cheers,
Stan H.
|
Exponential-and-logarithmic-functions/201313: not sure how to set up and do
an airport shuttle has an average of 1200 passengers per day and charges 15 per ride. Each 1 dollar increase in fare results in a loss of 50 riders. What should the fare be to maximize the revenue?
can someone help please
thanks
1 solutions
Answer 151541 by stanbon(57387) on 2009-06-27 07:31:03 (Show Source):
You can put this solution on YOUR website!an airport shuttle has an average of 1200 passengers per day and charges 15 per ride. Each 1 dollar increase in fare results in a loss of 50 riders. What should the fare be to maximize the revenue?
---------------------------------
Revenue = (# of passengers)(charge per passenger)
Let the dollar increase be x dollars.
Equation:
R(x) = (1200-50x)(15+x)
R(x) = 50(24-x)(15+x)
R(x) = 50(360 + 9x - x^2)
Maximum R occurs when x = -b/2a = -9/-2 = 4.5
---
Maximum Revenue occurs when the price is 15 + 4.5 = $19.50
=============================================================
Cheers,
Stan H.
|
Equations/201325: Use the given data points to construct a linear model, then use the model to find the appropriate Celsius or Fahrenheit temp.
Degrees Fahreheit 32 122 185
Degrees Celsius 0 50 85
Choose any two data points and use them to construct a linear equation that models the data, with x being Celsius and y Fahrenheit. Then use the equation to find the Fahrenheit temp corresponding to 40 Degrees Celsius 1 solutions
Answer 151540 by stanbon(57387) on 2009-06-27 07:14:00 (Show Source):
You can put this solution on YOUR website!Degrees Fahreheit 32 122 185
Degrees Celsius 0 50 85
Choose any two data points and use them to construct a linear equation that models the data, with x being Celsius and y Fahrenheit. Then use the equation to find the Fahrenheit temp corresponding to 40 Degrees Celsius
-----------------
Use (0,32) and (50,122)
slope = (122-32)/(50-0) = 9/5
-----
Form: F = mC + b
m = 9/5 and F = 32 when C = 0
32 = (9/5)*0 + b
b = 32
------------
Equation:
F = (9/5)C + 32
-----
Then use the equation to find the Fahrenheit temp corresponding to 40 Degrees Celsius
F(40) = (9/5)*40 + 32
F(40) = 72 + 32
F(40) = 104 degree
==============================
Cheers,
Stan H.
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Equations/201329: Write an equation in standard form for a line passing through the pair of points.
(-2,0) and (4,-5) 1 solutions
Answer 151539 by stanbon(57387) on 2009-06-27 07:06:48 (Show Source):
You can put this solution on YOUR website!Write an equation in standard form for a line passing through the pair of points.
(-2,0) and (4,-5)
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slope = (-5-0)/(4--2) = -5/6
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Form is y = mx + b
You know m= 5/6 and y = 0 when x = -2
Substitute to solve for "b":
0 = (-5/6)*-2 + b
0 = 5/3 + b
b = -5/3
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Equation:
y = (-5/6)x - 5/3
==========================
Cheers,
Stan H.
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Equations/201330: Sketch the graph of the equation.
y=x^2+2 1 solutions
Answer 151538 by stanbon(57387) on 2009-06-27 07:02:32 (Show Source):
You can put this solution on YOUR website!Sketch the graph of the equation.
y=x^2+2
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If x = -1, y = (-1)^2+2 = 3
If x = 0, y = 2
If x = 1, y = (1)^2+2 = 3
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Plote the three points (-1,3), (0,2), (1,3)
and draw a parabola contaiing the three points:

======
Cheers,
Stan H.
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Equations/201331: Find an equation of the line satisfying the given conditions.
Through the orgin with slope 7 1 solutions
Answer 151537 by stanbon(57387) on 2009-06-27 06:59:02 (Show Source):
You can put this solution on YOUR website!Find an equation of the line satisfying the given conditions.
Through the orgin with slope 7
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Form of the equation is y = mx + b
You are told that m=7 and y = 0 when x = 0
So solve for "b".
0 = 7*0 + b
0 = 0 + b
b = 0
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Equation:
y = 7x+0
y = 7x
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Cheers,
Stan H.
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Radicals/201271: ) Solve the following algebraically. Trial and error is not an appropriate method of solution.
x -2
a) 4-_____=_____
x-2 x-2
b) x^2/3=125
c)∛(x-4=2)
algebraically and check your potential solutions.d)√(x+20-x=0)
2)Show the steps that you would take to solve the following algebraically.
a)
x -2
4-_____=______
x-2 x-2
b)What potential solution did you obtain? Explain why this is this not a solution 1 solutions
Answer 151495 by stanbon(57387) on 2009-06-26 14:44:47 (Show Source):
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Linear_Equations_And_Systems_Word_Problems/201268: This question is from textbook Applied Statistics in Business and Economics
Chapter 11: Exercise 11.2 (ANOVA)
11.2 One particular morning, the length of time spent in the examination rooms is recorded for each patient seen by each physician at an orthopedic clinic. Does the data prove a significant difference in mean times? Physicians
Scrap Rate (Per Thousand Units)
FIGURE 11.12
MINITAB’s one-factor ANOVA
Physician 1 Physician 2 Physician 3 Physician 4
34 33 17 28
25 35 30 33
27 31 30 31
31 31 26 27
26 42 32 32
34 33 28 33
21 26 40
29
12.60 Below are revenue and profit (both in $ billions) for nine large entertainment companies.
(a) Make a scatter plot of profit as a function of revenue.
(b) Use Excel to fit the regression, with fitted equation and R2.
(c) In your own words, describe the fit. (Data are from Fortune 149, no. 7 [April 5, 2005], p. F-50.) Entertainment
Revenue and Profit of Nine Entertainment Companies
Company Revenue Profit
AMC Entertainment 1.792 −0.020
Clear Channel Communication 8.931 1.146
Liberty Media 2.446 −0.978
Metro-Goldwyn-Mayer 1.883 −0.162
Regal Entertainment Group 2.490 0.185
Time Warner 43.877 2.639
Univision Communications 1.311 0.155
Viacom 26.585 1.417
Walt Disney 27.061 1.267
Chapter 15: Exercise 15.6 (Chi-Square)
15.6 Advertisers need to know which age groups are likely to see their ads. Purchasers of 120 copies of Cosmopolitan are shown by age group.
(a) Make a bar chart and describe it.
(b) Calculate expected frequencies for each class.
(c) Perform the chi-square test for a uniform distribution. At α = .01, does this sample contradict the assumption that readership is uniformly distributed among these six age groups? (See J. Paul Peter and Jerry C. Olson, Consumer Behavior and Marketing Strategy, 9th ed. [McGraw-Hill, 2004], p. 300.) Cosmo
Purchaser Age Units Sold
18–24 38
25–34 28
35–44 19
45–54 16
55–64 10
65+ 9
Total 120
1 solutions
Answer 151493 by stanbon(57387) on 2009-06-26 14:41:59 (Show Source):
You can put this solution on YOUR website!One particular morning, the length of time spent in the examination rooms is recorded for each patient seen by each physician at an orthopedic clinic. Does the data prove a significant difference in mean times? Physicians
Scrap Rate (Per Thousand Units)
FIGURE 11.12
MINITAB’s one-factor ANOVA
Physician 1 Physician 2 Physician 3 Physician 4
34 33 17 28
25 35 30 33
27 31 30 31
31 31 26 27
26 42 32 32
34 33 28 33
21 26 40
29
---------------------
Ho: The means are all equal.
Ha: At least one of the means is different
---------------------
I ran the ANOVA function on a TI calculator and got:
F = 1.228...
p-value = 0.3212
---
Conclusion: Since the p-value is greater than 5%,
Fail to reject Ho.
The means are statistically the same for the four
doctors.
====================================================
12.60 Below are revenue and profit (both in $ billions) for nine large entertainment companies.
(a) Make a scatter plot of profit as a function of revenue.
Comment: That cannot be shown on this site.
Just plot the ordered pairs listed below.
------------
(b) Use Excel to fit the regression, with fitted equation and R2.
I ran a linear regression program against the listed ordered pairs and got
Profit = 0.06269(revenue) - 0.18299...
R^2 = 0.8206
---------------------------------
(c) In your own words, describe the fit.
The linear fit is fairly good. R^2 = 0.82 indicates that
82% of the variability between profit and revenue is
described by the regression equation.
---------------------------------------
(Data are from Fortune 149, no. 7 [April 5, 2005], p. F-50.) Entertainment
Revenue and Profit of Nine Entertainment Companies
Company Revenue Profit
AMC Entertainment 1.792 −0.020
Clear Channel Communication 8.931 1.146
Liberty Media 2.446 −0.978
Metro-Goldwyn-Mayer 1.883 −0.162
Regal Entertainment Group 2.490 0.185
Time Warner 43.877 2.639
Univision Communications 1.311 0.155
Viacom 26.585 1.417
Walt Disney 27.061 1.267
===========================================
Chapter 15: Exercise 15.6 (Chi-Square)
15.6 Advertisers need to know which age groups are likely to see their ads. Purchasers of 120 copies of Cosmopolitan are shown by age group.
(a) Make a bar chart and describe it.
Comment: A bar chart cannot be illustrated on this site.
---
(b) Calculate expected frequencies for each class.
There are 120 data items in 6 classes. The expected
number for each class is 120/6 = 20
-----------------
(c) Perform the chi-square test for a uniform distribution. At α = .01, does this sample contradict the assumption that readership is uniformly distributed among these six age groups?
I ran a Chi Sq Goodness of Fit test against the six (observed,expected) data
pairs and got the following results:
Ho: The observed frequency values are uniformly distributed.
Ha: The frequency values are not uniformly distributed.
---
Chi-Sq = 31.3
p-value = 0.0000081725
Conclusion: Since the p-value is less than 1% Reject Ho.
The observed values are not uniformly distributed.
===============================================================
(See J. Paul Peter and Jerry C. Olson, Consumer Behavior and Marketing Strategy, 9th ed. [McGraw-Hill, 2004], p. 300.) Cosmo
Purchaser Age Units Sold
18–24 38
25–34 28
35–44 19
45–54 16
55–64 10
65+ 9
Total 120
This question is from textbook Applied Statistics in Business and Economics
: Chapter 11: Exercise 11.2 (ANOVA)
-----------------------------------------------------------
11.2 One particular morning, the length of time spent in the examination rooms is recorded for each patient seen by each physician at an orthopedic clinic. Does the data prove a significant difference in mean times? Physicians
Scrap Rate (Per Thousand Units)
FIGURE 11.12
MINITAB’s one-factor ANOVA
Physician 1 Physician 2 Physician 3 Physician 4
34 33 17 28
25 35 30 33
27 31 30 31
31 31 26 27
26 42 32 32
34 33 28 33
21 26 40
29
12.60 Below are revenue and profit (both in $ billions) for nine large entertainment companies.
(a) Make a scatter plot of profit as a function of revenue.
(b) Use Excel to fit the regression, with fitted equation and R2.
(c) In your own words, describe the fit. (Data are from Fortune 149, no. 7 [April 5, 2005], p. F-50.) Entertainment
Revenue and Profit of Nine Entertainment Companies
Company Revenue Profit
AMC Entertainment 1.792 −0.020
Clear Channel Communication 8.931 1.146
Liberty Media 2.446 −0.978
Metro-Goldwyn-Mayer 1.883 −0.162
Regal Entertainment Group 2.490 0.185
Time Warner 43.877 2.639
Univision Communications 1.311 0.155
Viacom 26.585 1.417
Walt Disney 27.061 1.267
Chapter 15: Exercise 15.6 (Chi-Square)
15.6 Advertisers need to know which age groups are likely to see their ads. Purchasers of 120 copies of Cosmopolitan are shown by age group.
(a) Make a bar chart and describe it.
(b) Calculate expected frequencies for each class.
(c) Perform the chi-square test for a uniform distribution. At α = .01, does this sample contradict the assumption that readership is uniformly distributed among these six age groups? (See J. Paul Peter and Jerry C. Olson, Consumer Behavior and Marketing Strategy, 9th ed. [McGraw-Hill, 2004], p. 300.) Cosmo
Purchaser Age Units Sold
18–24 38
25–34 28
35–44 19
45–54 16
55–64 10
65+ 9
Total 120
Cheers,
Stan H.
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Conjunction/201262: TWO PIPES FILL UP A TANK IN 9 3/8 HRS(75/8) . IF TWO PIPE RUN SEPARATELY THE LARGER DIA TAKES 10HRS LESS THAN THE SMALLER DIA PIPE TO FILL THE TANK INDIVIDUALLY . fIND THE NO OF HRS TAKE INDIVIDUAL TO FILL THE TANK ... 1 solutions
Answer 151468 by stanbon(57387) on 2009-06-26 11:18:58 (Show Source):
You can put this solution on YOUR website!TWO PIPES FILL UP A TANK IN 9 3/8 HRS(75/8) . IF TWO PIPES RUN SEPARATELY THE LARGER DIA TAKES 10HRS LESS THAN THE SMALLER DIA PIPE TO FILL THE TANK INDIVIDUALLY . fIND THE NO OF HRS TAKE INDIVIDUAL TO FILL THE TANK ...
----------------------------------------------------
Together DATA:
time = (75/8) hrs/job ; rate = (8/75) job/hr.
------------------------------------------
Larger Pipe DATA:
time = x-10 hrs/job ; rate = 1/(x-10) job/hr.
--------------------------------
Smaller Pipe DATA:
time = x hrs/job ; rate = 1/x job/hr.
---------------------------------------------
Equations:
rate + rate = together data
1/x + 1/(x-10) = 8/75
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75(x-10) + 75x = 8x(x-10)
75x - 750 + 75x = 8x^2 - 80x
8x^2 -230x + 750 = 0
4x^2 - 115x + 375 = 0
(x-25)(4x-15) = 0
Positive realistic solution.
x = 25 hrs. (time for the smaller pipe)
x-10 = 15 hrs. (time for the larger pipe)
==============================================
Cheers,
Stan H.
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Probability-and-statistics/201218: This question is from textbook statistics techniques in business and economics
a recent issue of bride magazine suggested that couples planning their wedding should expect two-thirds of those who are sent am invitation to respond that they will attend. rich and stacy are planning to be married later this year. They plan to send 197 invitations
Question: what is the probability exactly 140 will accept the invitation? 1 solutions
Answer 151465 by stanbon(57387) on 2009-06-26 10:48:04 (Show Source):
You can put this solution on YOUR website!a recent issue of bride magazine suggested that couples planning their wedding should expect two-thirds of those who are sent am invitation to respond that they will attend. rich and stacy are planning to be married later this year. They plan to send 197 invitations
Question: what is the probability exactly 140 will accept the invitation?
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It's a binomial problem with n = 197 ; p = 2/3 ;x = 140
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P(x=140) = 197C140 (2/3)^140*(1/3)^53 = 0.2599...
Cheers,
Stan H.
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Equations/201196: Simplify the expression. Write answer with positive exponents. Variables are positive real numbers.
(y(9/8))/(y(5/8)) 1 solutions
Answer 151444 by stanbon(57387) on 2009-06-25 21:51:15 (Show Source):
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