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# Recent problems solved by 'stanbon'

Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 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 Expressions-with-variables/201581: this may be an expression to simplify the expression but here it goes: Marriage Penalty eliminated The value of the expression 4220+0.25(x - 30,650) is the 2006 federal income tax for a single taxpayer with taxable income of x dollars, where x is over \$30,650 but not over \$74,200. a) Simplify the expression. b) Find the amount of tax for a single taxpayer with taxable income of \$40,000. c) Who pays more, a married couple with a joint taxable income of \$80,000 or two single taxpayers with taxable incomes of \$40,000 each? 1 solutions Answer 151913 by stanbon(57214)   on 2009-06-30 22:33:55 (Show Source): You can put this solution on YOUR website!Marriage Penalty eliminated The value of the expression 4220+0.25(x - 30,650) is the 2006 federal income tax for a single taxpayer with taxable income of x dollars, where x is over \$30,650 but not over \$74,200. a) Simplify the expression. 4220 + (1/4)x - 7662.50 ------------------------------------ b) Find the amount of tax for a single taxpayer with taxable income of \$40,000. ------------------------------------ 4220 + (1/4)(40,000) - 7662.50 = \$6557.50 ------------------------------------ c) Who pays more, a married couple with a joint taxable income of \$80,000 or two single taxpayers with taxable incomes of \$40,000 each? --- If x = 80000 you get 4220 + 20,000-7662.50 = 16,557.5 If x = 40,000 you get tax of 6557.50 twice = 13,115 So it's cheaper for the couple to not be married. ====================================================== Cheers, Stan H
 Permutations/201594: In how many ways can letter of the word BALLOON be arranged so that the two Ls do not come together.1 solutions Answer 151910 by stanbon(57214)   on 2009-06-30 22:18:18 (Show Source): You can put this solution on YOUR website!In how many ways can letter of the word BALLOON be arranged so that the two Ls do not come together --------------------------- Total # of arrangements: 7!/[2!*2*] ------------------- Total # of arrangements with the LL together: Note: this means the LL is like one letter. # = 6!/2! --------------------------------------- Therefore, total number with the LL NOT together: 7!/(2!*2!) - 6!/2! = 1260 - 360 = 900 ======================================================== Cheers, Stan H.
 Geometry_proofs/201650: Given:B is the midpoint of AC Prove:AC =2AB1 solutions Answer 151908 by stanbon(57214)   on 2009-06-30 22:05:39 (Show Source): You can put this solution on YOUR website!Given:B is the midpoint of AC Prove:AC =2AB -------------------------- AC = AB + BC ------------definition of midpoint BC = AB------------------definition of midpoint AC = AB + AB-------------substitution AC = 2AB-----------------rule of addition QED ================================================= Cheers, Stan H.
 Travel_Word_Problems/201658: This question is from textbook Filling a tank. A water tank has an inlet pipe and a drain pipe. A full tank can be emptied in 30 minutes if the drain is opened and an empty tank can be filled in 45 minutes with the inlet pipe opened. If both pipes are accidentally opened when the tank is full, then how long will it take to empty the tank?1 solutions Answer 151906 by stanbon(57214)   on 2009-06-30 22:00:14 (Show Source): You can put this solution on YOUR website!Filling a tank. A water tank has an inlet pipe and a drain pipe. A full tank can be emptied in 30 minutes if the drain is opened and an empty tank can be filled in 45 minutes with the inlet pipe opened. If both pipes are accidentally opened when the tank is full, then how long will it take to empty the tank? -------------------- Drain Pipe DATA: time = 30 min/job ; rate = 1/30 job/min ----------------------- Fill Pipe DATA: time = 45 min/job ; rate = 1/45 job/min ------------------------- Together DATA: time = x min/job ; rate = 1/x job/min -------------------------------------------- Equation: fill rate - drain rate = together rate 1/30 - 1/45 = 1/x 45x - 30x = 30*45 15x = 30*45 x = 2*45 x = 90 minutes (time for both pipes together to fill the tank) =========================================== Cheers, Stan H.
 Exponential-and-logarithmic-functions/201627: why am I having trouble figuring out concave up and down determine where the graph of the function is concave up and concave down f(x)=x^3-6x^2+9x+3 thanks 1 solutions Answer 151850 by stanbon(57214)   on 2009-06-30 14:36:43 (Show Source): You can put this solution on YOUR website!determine where the graph of the function is concave up and concave down f(x)=x^3-6x^2+9x+3 ---- I'll assume you are taking a calculus course. -------- 1st derivative = 3x^2-12x+9 2nd derivative = 6x-12 ----------------------------------- The roots of the 1st derivative: 3x^2-12x+9 = 0 x^2-4x+3 = 0 (x-3)(x-1)= 0 x = 1 or x = 3 --------------- Evaluate the 2nd derivative at x = 1 and at x = 3 f''(1) = 6*1-12<0 so f(x) is concave down at x = 1 f''(3) = 6*3-12>0 so f(x) is concave upward at x = 3 ----------------- The graph confirms those results: ----------------- Cheers, Stan H.
 Expressions-with-variables/201617: Solve the system by substitution -x-6y=5 x+6y=7 1 solutions Answer 151826 by stanbon(57214)   on 2009-06-30 12:51:47 (Show Source): You can put this solution on YOUR website!Solve the system by substitution -x-6y=5 x+6y=7 ---------------- Solve the 1st equation for "x": x = -6y-5 ---- Substitute into the 2nd equation to solve for "y": -6y-5 + 6y = 7 -5 = 7 ---- This is a contradiction. It means there is no consistency between the x/y values of the two equations. It means the graphs of the two equations are parallel. The system is said to be inconsistent. The system has no solution. ================================================== Cheers, Stan H.
 logarithm/201623: This question is from textbook write 5log(3x-11)-7log(x)as a single logarithm1 solutions Answer 151823 by stanbon(57214)   on 2009-06-30 12:45:43 (Show Source): You can put this solution on YOUR website!write 5log(3x-11)-7log(x)as a single logarithm --- = log(3x-11)^5 - log(x)^7 --- = log[(3x-11)^5/(x)^7] ============================== Cheers, Stan H.
 Functions/201624: find the domain 2x-401 solutions Answer 151822 by stanbon(57214)   on 2009-06-30 12:41:21 (Show Source): You can put this solution on YOUR website!find the domain 2x-40 --------------- Nothing about the expression restricts the values of "x"\ so the domain is "All Real Numbers". Cheers, Stan H.
 Probability-and-statistics/201607: Card Figure: 1 A , 2 B's, & 3 C's. Die 1/6 Referring to the figure, think about first picking a card and then rolling the die. Give the probability in simplest form.P(not B,not even)1 solutions Answer 151820 by stanbon(57214)   on 2009-06-30 12:36:00 (Show Source): You can put this solution on YOUR website!1 A , 2 B's, & 3 C's. Die 1/6 Referring to the figure, think about first picking a card and then rolling the die. Give the probability in simplest form. P(not B,not even) ----------------- P(not B) = 4/6 P(not even) = 3/6 ---- Since the events are independent, P(x AND y) = P(x)*P(y) P(not B and not even) = P(not B)*P(not even) = (4/6)*(3/6) = 12/36 = 1/3 =========================================================================== Cheers, Stan H.
 Equations/201547: Give the equation of the horizontal asymptote of the rational function. g(x) = (3)/(x+4) A) y = 3 B) y = 0 C) y = 3/4 D) x = -4 1 solutions Answer 151782 by stanbon(57214)   on 2009-06-29 21:05:37 (Show Source): You can put this solution on YOUR website!Give the equation of the horizontal asymptote of the rational function. g(x) = (3)/(x+4) Horizontal asymptote : y = 0*x/1*x = 0/1 = 0 --- Another method: Divide 0 by (x+4). You get a quotient of 0 and a remainder of 3/(x+4) y = the quotient is the horizontal asymptote Ans: y = 0 ======================================= Cheers, Stan H. ======================================= x = 0 A) y = 3 B) y = 0 C) y = 3/4 D) x = -4
 Expressions-with-variables/201574: use synthetic substitution to find the value of f(-2) for f(x)=x^3-3x^2-x-9 1 solutions Answer 151781 by stanbon(57214)   on 2009-06-29 20:59:03 (Show Source): You can put this solution on YOUR website!use synthetic substitution to find the value of f(-2) for f(x)=x^3-3x^2-x-9 ------------- -2)....1....-3....-1....-9 .........1......-5......9.....|..-27 ========= f(-2) = -27 ================================ Cheers, Stan H.
 Probability-and-statistics/201533: A bag of marbles contains 6 red marbles and 4 blue marbles. If two are selected simultaneously, what is the probability that at least 1 blue marble is drawn?1 solutions Answer 151779 by stanbon(57214)   on 2009-06-29 20:36:07 (Show Source): You can put this solution on YOUR website!A bag of marbles contains 6 red marbles and 4 blue marbles. If two are selected simultaneously, what is the probability that at least 1 blue marble is drawn? ------------------- P(at least one is blue) = 1 - P(none are blue) = 1 - [6C2/10C2] = 1 - 15/45 = 1 - (1/3) = 2/3 ================= Cheers, Stan H.
 Probability-and-statistics/201518: If a tire has a mean mileage of 60,000 miles and a standard deviation of 2,000, and the company doesn't want to have a replacement expense of more than 4%, what is the minimum guaranteed mileage for the tire?1 solutions Answer 151778 by stanbon(57214)   on 2009-06-29 20:32:29 (Show Source): You can put this solution on YOUR website!If a tire has a mean mileage of 60,000 miles and a standard deviation of 2,000, and the company doesn't want to have a replacement expense of more than 4%, what is the minimum guaranteed mileage for the tire? --------------- Draw the normal curve with center at 60,000. Note that sigma = 2000 ----- Mark a point in the left tail that has 4\$ of the miles driven to the left. ------------------- Find the z-value of that point using your z-chart or calculator. I get InvNorm(0.04) = -1.7507 ------------------------------------ Now find the "raw score" corresponding to that z-score using x = z*sigma + mu x = -1.7507*2000 + 60000 x = 56498.63 miles That is the number of miles for which they should warrant the tires. ======================================== Cheers, Stan H.
 Probability-and-statistics/201542: Card figure: 1 A, 2 B's, 3 C's Referring to the figure in Question #26, think about first picking a card and then rolling the die. Give the probability in simplest form. P(C,even number)1 solutions Answer 151777 by stanbon(57214)   on 2009-06-29 20:24:50 (Show Source): You can put this solution on YOUR website!Card figure: 1 A, 2 B's, 3 C's Referring to the figure in Question #26, think about first picking a card and then rolling the die. Give the probability in simplest form. P(C,even number) -------------------------- P(C and even number) = (3/6)(1/2) = 1/4 -------------------------------------------- Cheers, Stan H.
 Probability-and-statistics/201543: Card figure: 1 A, 2 B's, 3 C's Referring to the figure in Question #26, think about first picking a card and then rolling the die. Give the probability in simplest form. P(not A,6)1 solutions Answer 151776 by stanbon(57214)   on 2009-06-29 20:22:34 (Show Source): You can put this solution on YOUR website!Card figure: 1 A, 2 B's, 3 C's Referring to the figure in Question #26, think about first picking a card and then rolling the die. Give the probability in simplest form. P(not A,6) --------------------- P(not A) = 5/6 P(6 on the die) = 1/6 ----------- The events are independent so, P(notA and 6) = (5/6)*(1/6) = 5/36 ======================================== Cheers, Stan H.
 Probability-and-statistics/201545: On any given night, Becky has a 60% chance of seeing a shooting star in any given hour. If Becky watches the sky for two hours, find the following probabilities a. What is the probability that Becky sees a shooting star in both hours? b. What is the probability that Becky sees a shooting star in exactly one hour? c. What is the probability that Becky does not see a shooting star at all? d. Given that Becky did not see a shooting star in the first hour, what is the probability that she will see one in the second hour? 1 solutions Answer 151775 by stanbon(57214)   on 2009-06-29 20:17:02 (Show Source): You can put this solution on YOUR website!On any given night, Becky has a 60% chance of seeing a shooting star in any given hour. If Becky watches the sky for two hours, find the following probabilities These are Binomial problems. p = 0.6 ; q = 0.4 a. What is the probability that Becky sees a shooting star in both hours? n = 2 ; = 0.6 ; x = 2 P(x=2) = 0.6^2 = 0.36 --------------------------------------- b. What is the probability that Becky sees a shooting star in exactly one hour? P(x = 1) = 1 - [P(x=0) + P(x=2)] = 1 - (0.4)^2 - 0.6)^2 = 1 -0.16 - 0.36 = 0.48 ------------------------------------------ c. What is the probability that Becky does not see a shooting star at all? P(x=0) = 0.4^2 = 0.16 ------------------------------------------ d. Given that Becky did not see a shooting star in the first hour, what is the probability that she will see one in the second hour? The events are independent: P(x = 1 in the 2nd hour) = 0.6 ------------------------------------------ Cheers, Stan H.
 Geometry_Word_Problems/201482: A disc jockey must play 16 commercial spots during 1 hour of a radio show. Each commercial is either 30 seconds long or 60 seconds long. If the total commercial time during 1 hour is 13 min, how many 30 second commercials were played that hour? How many 60 second commercials?1 solutions Answer 151704 by stanbon(57214)   on 2009-06-29 06:10:16 (Show Source): You can put this solution on YOUR website!A disc jockey must play 16 commercial spots during 1 hour of a radio show. Each commercial is either 30 seconds long or 60 seconds long. If the total commercial time during 1 hour is 13 min, how many 30 second commercials were played that hour? How many 60 second commercials? -------------------------------------------------- Quantity Equation: s + t = 16 time Equation: 60s + 30t = 13*60 ---------------------------- Simplify s + t = 16 2s + t = 26 ------------------- Subtract 1st from 2nd to get: s = 10 (# of sixty second commercials) --- Substitute to solve for "t": 10 + t = 16 t = 6 (# of thirty second commercials) ============================================= Cheers, Stan H.
 Square-cubic-other-roots/201429: This question is from textbook Algebra for college students I really can't figure out how the answer is 16. Can you help, please? 8+2 √5² - 3² That is 5 squared - 3 squared. 5 squared = 25 3 squared = 9 so 25 - 9 = 16 but what is to be done with the 8 + 2 in the beginning? Thanks for your help - Jamie1 solutions Answer 151644 by stanbon(57214)   on 2009-06-28 13:21:27 (Show Source): You can put this solution on YOUR website!8+2 √(9² - 3²) ------------- = 8 + 2*Sqrt(16) = 8 + 2*4 = 8 + 8 = 16 =============== Cheers, Stan H.
 Expressions-with-variables/201421: Please help me solve this problem: y=1/2x-3 y=1/3x+2 I tried this y=1/3x+2 -1/3x+y=2 -y=-y -1/3x =-y+2 3/1(-1/3x)=(-y+2)3/1 x=-3y+6 Then substitue x=-3y+6 y=1/x(-3y+6)-3 y=-3/xy+6/2-3 y=-3/2y+3-3 But now I am lost1 solutions Answer 151643 by stanbon(57214)   on 2009-06-28 12:47:38 (Show Source): You can put this solution on YOUR website!y=1/2x-3 y=1/3x+2 ------------ Substitute to get: (1/2)x - 3 = (1/3)x + 2 [(1/2)-(1/3)]x = 5 (1/6)x = 5 x = 30 ----------- y = (1/2)30 - 3 y = 12 ====================== Cheers, Stan H.
 Expressions-with-variables/201422: Please help me solve this problem: x=1/8y-1 y=1/4x+31 solutions Answer 151642 by stanbon(57214)   on 2009-06-28 12:36:36 (Show Source): You can put this solution on YOUR website!Please help me solve this problem: x=1/8y-1 y=1/4x+3 ------------ Rewrite: y = 8x + 8 y = (1/4)x + 3 ------------------- Substitute to get: 8x + 8 = (1/4)x + 3 (31/4)x = - 5 x = -20/31 ---------------- Substitute to solve for "y": y = (1/4)(-20/31) + 3 y = -5/31 + 93/31 y = 88/31 =============================== Cheers, Stan H.
 Radicals/201423: b=? AB+CB=D 1 solutions Answer 151641 by stanbon(57214)   on 2009-06-28 12:26:38 (Show Source): You can put this solution on YOUR website!Not enough information to solve. Cheers, Stan H.
 Equations/201318: Solve the inequality and graph the solution. 9|x-1| (>or=) 91 solutions Answer 151604 by stanbon(57214)   on 2009-06-27 21:31:13 (Show Source): You can put this solution on YOUR website!Solve the inequality and graph the solution. 9|x-1| (>or=) 9 ------------------------------- 9|x-1| > = 9 |x-1| >= 1 x-1 >= 1 or -(x-1) >=1 x >= 2 or x-1 <= -1 x >=2 or x <= 0 ====================== Cheers, Stan H.
 Equations/201327: Solve the inequality and graph the solution. |x|>61 solutions Answer 151603 by stanbon(57214)   on 2009-06-27 21:27:38 (Show Source): You can put this solution on YOUR website!Solve the inequality and graph the solution. |x|>6 ------ x >6 or -x > 6 x > 6 or x < -6 ========================= Cheers, Stan H.
 absolute-value/201373: |2x+3|=|x|1 solutions Answer 151602 by stanbon(57214)   on 2009-06-27 21:24:03 (Show Source): You can put this solution on YOUR website!|2x+3|=|x| 2x+3 = x or 2x+3 = -x x = -3 or 3x = -3 x = -3 or x = -1 ========================= Cheers, Stan H.
 Exponents/201355: This question is from textbook Mathematics For Technical trades Here is another problem I have an cannot figure out. Using the formula L=2C + 1.57(D+d)+ D+d find L for D = 8",d=5,and C=19. _____ 4C 1 solutions Answer 151573 by stanbon(57214)   on 2009-06-27 15:20:42 (Show Source): You can put this solution on YOUR website!Using the formula L=2C + 1.57(D+d)+ (D+d)/(4C) find L for D = 8",d=5,and C=19. --- L = 2*19 + 1.57(8+5) + (8+5)/(4*19) L = 38 + 1.57*13 + 13/76 L = 38 + 20.41 + 0.1710526.. L = 58.58... Cheers, Stan H.
 Divisibility_and_Prime_Numbers/201346: How many positive primes have a remainder of zero when divided by 13?1 solutions Answer 151572 by stanbon(57214)   on 2009-06-27 15:17:04 (Show Source): You can put this solution on YOUR website!How many positive primes have a remainder of zero when divided by 13? ------------- Ans: Only one; the number 13 is a positive prime which when divided by 13 has zero as its remainder. ==================================== Cheers, Stan H.
 Miscellaneous_Word_Problems/201347: Spencer makes 9 out of 13 shots in the first half of a basketball game. How many consecutive shots must he make in the second half of the game to raise his percentage to 96%?1 solutions Answer 151568 by stanbon(57214)   on 2009-06-27 15:13:54 (Show Source): You can put this solution on YOUR website!Spencer makes 9 out of 13 shots in the first half of a basketball game. How many consecutive shots must he make in the second half of the game to raise his percentage to 96%? ---------------------------------- Let "x" be the number of consecutive shots he need to make. Equation: (9+x)/(13+x) = 0.96 9+x = 0.96(13+x) 900 + 100x = 96(13+x) 900 + 100x = 1248 + 96x 4x = 348 x = 87 (# of consecutive shots he must make to get to 96%) ============================================================= Cheers, Stan H.
 Exponential-and-logarithmic-functions/201313: not sure how to set up and do an airport shuttle has an average of 1200 passengers per day and charges 15 per ride. Each 1 dollar increase in fare results in a loss of 50 riders. What should the fare be to maximize the revenue? can someone help please thanks 1 solutions Answer 151541 by stanbon(57214)   on 2009-06-27 07:31:03 (Show Source): You can put this solution on YOUR website!an airport shuttle has an average of 1200 passengers per day and charges 15 per ride. Each 1 dollar increase in fare results in a loss of 50 riders. What should the fare be to maximize the revenue? --------------------------------- Revenue = (# of passengers)(charge per passenger) Let the dollar increase be x dollars. Equation: R(x) = (1200-50x)(15+x) R(x) = 50(24-x)(15+x) R(x) = 50(360 + 9x - x^2) Maximum R occurs when x = -b/2a = -9/-2 = 4.5 --- Maximum Revenue occurs when the price is 15 + 4.5 = \$19.50 ============================================================= Cheers, Stan H.
 Equations/201325: Use the given data points to construct a linear model, then use the model to find the appropriate Celsius or Fahrenheit temp. Degrees Fahreheit 32 122 185 Degrees Celsius 0 50 85 Choose any two data points and use them to construct a linear equation that models the data, with x being Celsius and y Fahrenheit. Then use the equation to find the Fahrenheit temp corresponding to 40 Degrees Celsius1 solutions Answer 151540 by stanbon(57214)   on 2009-06-27 07:14:00 (Show Source): You can put this solution on YOUR website!Degrees Fahreheit 32 122 185 Degrees Celsius 0 50 85 Choose any two data points and use them to construct a linear equation that models the data, with x being Celsius and y Fahrenheit. Then use the equation to find the Fahrenheit temp corresponding to 40 Degrees Celsius ----------------- Use (0,32) and (50,122) slope = (122-32)/(50-0) = 9/5 ----- Form: F = mC + b m = 9/5 and F = 32 when C = 0 32 = (9/5)*0 + b b = 32 ------------ Equation: F = (9/5)C + 32 ----- Then use the equation to find the Fahrenheit temp corresponding to 40 Degrees Celsius F(40) = (9/5)*40 + 32 F(40) = 72 + 32 F(40) = 104 degree ============================== Cheers, Stan H.
 Equations/201329: Write an equation in standard form for a line passing through the pair of points. (-2,0) and (4,-5)1 solutions Answer 151539 by stanbon(57214)   on 2009-06-27 07:06:48 (Show Source): You can put this solution on YOUR website!Write an equation in standard form for a line passing through the pair of points. (-2,0) and (4,-5) ----------- slope = (-5-0)/(4--2) = -5/6 ----------- Form is y = mx + b You know m= 5/6 and y = 0 when x = -2 Substitute to solve for "b": 0 = (-5/6)*-2 + b 0 = 5/3 + b b = -5/3 --------------- Equation: y = (-5/6)x - 5/3 ========================== Cheers, Stan H.
 Equations/201330: Sketch the graph of the equation. y=x^2+21 solutions Answer 151538 by stanbon(57214)   on 2009-06-27 07:02:32 (Show Source): You can put this solution on YOUR website!Sketch the graph of the equation. y=x^2+2 ---------- If x = -1, y = (-1)^2+2 = 3 If x = 0, y = 2 If x = 1, y = (1)^2+2 = 3 ----- Plote the three points (-1,3), (0,2), (1,3) and draw a parabola contaiing the three points: ====== Cheers, Stan H.