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Recent problems solved by 'stanbon'

stanbon answered: 57911 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 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real-numbers/209612: write all the classifications that apply to each real number square root of 2 1 solutions Answer 158483 by stanbon(57984)   on 2009-08-30 14:14:04 (Show Source): You can put this solution on YOUR website! write all the classifications that apply to each real number square root of 2 ------------------ The Real Numbers comprise the rational and the irrational. sqrt(2) is irrational because it cannot be written as a ratio of two integers. ============================== Cheers, Stan H.

Miscellaneous_Word_Problems/209610: I had a procedure, it cost $625.00 the insurance company only reimbursed me for 82.00 what percentage did they pay I figured 76% round off to 80 am I right. I did 625.00 divided by 82, am I right? This site sounds good to help people with everyday math problems we encountered. We tend to forget basic math at times, and we do need it in our everyday lives. 1 solutions Answer 158481 by stanbon(57984)   on 2009-08-30 14:11:13 (Show Source): You can put this solution on YOUR website! I had a procedure, it cost $625.00 the insurance company only reimbursed me for 82.00 what percentage did they pay I figured 76% round off to 80 am I right. I did 625.00 divided by 82, am I right? ------------------ 82/625 = 0.1312 = 13.12% ----- That means you paid 86.88% of the cost of your procedure. -------------------------------------------------------------- Cheers, Stan H. Reply to stanbon@comcast.net

Functions/209594: Part a.solve 5x^2=35 Part b. find the x intercepts of f(x) = 5x^2-35 1 solutions Answer 158479 by stanbon(57984)   on 2009-08-30 13:56:13 (Show Source): You can put this solution on YOUR website! Part a. solve 5x^2=35 x^2=7 x = +sqrt(7) or x = -sqrt(7) ================================== Part b. find the x intercepts of f(x) = 5x^2-35 Let y = 0 and solve for x Answers are the same as in part a ======================================= Cheers, Stan H. Reply to stanbon@comcast.net

Triangles/209608: the largest angle of a triangle is 3 times the smallest angle. the middle angle is 30 degrees more than the smallest angle. find the number of degrees in each triangle 1 solutions Answer 158478 by stanbon(57984)   on 2009-08-30 13:48:25 (Show Source): You can put this solution on YOUR website! the largest angle of a triangle is 3 times the smallest angle. the middle angle is 30 degrees more than the smallest angle. find the number of degrees in each triangle --------------------------- Let the smallest angle be "x". Then middle is "x+30" And largest is "3x" ------------------------ Equation: x + (x+30) + 3x = 180 Solve for x and evaluate each angle. ======================================== Cheers, Stan H. Reply to stanbon@comcast.net

Miscellaneous_Word_Problems/209604: Melanie can paint a certain barn by herself in "x" days. Melissa can paint the same barn by herself in 2x days. Write a rational expression for the fration of the barn that they complete in one day by working together. Evaluate the expression for x=5. 1 solutions Answer 158475 by stanbon(57984)   on 2009-08-30 13:41:59 (Show Source): You can put this solution on YOUR website! Melanie can paint a certain barn by herself in "x" days. Melissa can paint the same barn by herself in 2x days. Write a rational expression for the fraction of the barn that they complete in one day by working together. Evaluate the expression for x=5. -------------------------- Melanie DATA: time = x day/job ; rate = 1/x job/day -------------------------- Melissa DATA: time = 2x day/job ; rate = 1/2x job/day ============================================== Together DATA: rate + rate = together rate 1/x + 1/2x = (2x+x)/2x^2 = 3x/2x^2 = 3/2x job/day ======================================================= Cheers, Stan H. Reply to comcast.net

Numbers_Word_Problems/209550: three consecutive even integers are such that the sum of the smallest and 3 times the second is 38 more than twice the third. what are the integers? 1 solutions Answer 158447 by stanbon(57984)   on 2009-08-30 09:53:25 (Show Source): You can put this solution on YOUR website! three consecutive even integers are such that the sum of the smallest and 3 times the second is 38 more than twice the third. what are the integers? ---------------------- 1st: 2x-2 2nd: 2x 3rd: 2x+2 -------------------- Equation: 2x-2 +3(2x)= 2x+2+38 2x-2 + 6x = 2x +40 6x = 42 x = 7 ------------- 1st: 14-2 = 12 2nd: 14 3rd: 14+2 = 16 ======================== Cheers, Stan H. Reply to stanbon@comcast.net

Linear_Equations_And_Systems_Word_Problems/209562: a canned juice drink is 15% ans anouther juice is 5% How many liters of each would it take to make it 10L that is 13% juice? 1 solutions Answer 158444 by stanbon(57984)   on 2009-08-30 09:49:50 (Show Source): You can put this solution on YOUR website! a canned juice drink is 15% ans another juice is 5% How many liters of each would it take to make it 10L that is 13% juice? ---------------------- Equations: Quantity Eq: canned + other = 10L Juice Eq::: 0.15c + 0.05t = 0.13*10 ----------------------------- Substitute for c (or for t) to solve: 0.15c + (0.05)(10-c) = 0.13*10 Multiply thru by 100 to get: 15c + 5(10-c) = 13*10 15c + 50 - 5c = 130 10c = 80 c = 8L (amt. of canned juice drink needed in the mixture) Then "other" = 10-8 = 2L (amt. of 5% juice needed in the mix) ============================================= Cheers, Stan H. Reply to stanbon@comcast.net =============================================

Linear_Equations_And_Systems_Word_Problems/209551: I need to translate this problem into an equation. Since the beginning of the month, a local reservoir has been losing water at a constant rate. On the 13th of the month the reservoir held 454 million gallons of water, and on the 21st it held only 191 million gallons. How much water was in the reservoir on the 10th of the month? 1 solutions Answer 158443 by stanbon(57984)   on 2009-08-30 09:41:50 (Show Source): You can put this solution on YOUR website! translate this problem into an equation. Since the beginning of the month, a local reservoir has been losing water at a constant rate. On the 13th of the month the reservoir held 454 million gallons of water, and on the 21st it held only 191 million gallons. How much water was in the reservoir on the 10th of the month? ----------------------- You have two points relating day and amount of water: (13,454)and(21,191) --- Equation form is amt = (slope)(day)+ b slope = (191-454)/(21-13) = -263/8 ----------- to get the intercept: 191 = (-263/8)21 + b b = 499.375 ------------- Equation: Amt(day) = (-263/8)(day) + 499.375 --- How much water was in the reservoir on the 10th of the month? A(10) = (-263/8)(10) + 499.375 A(10) = 170.625 gallons =================================== Cheers, Stan H. Reply to stanbon@comcast.net

Polynomials-and-rational-expressions/209552: Rewrite the equation y = (x+2)(4-2x) in intercept form. Then state the coordinates of the vertex. (A) y = -2(x+2)(x-2);(0,-2) (B) y = -2(x+2)(x-2);(0,0) (C) y = -2(x+2)(x+2);(-4,-8) (D) y = -2(x-2)(x-2);(4,-8) 1 solutions Answer 158442 by stanbon(57984)   on 2009-08-30 09:32:52 (Show Source): You can put this solution on YOUR website! Rewrite the equation y = (x+2)(4-2x) in intercept form. Then state the coordinates of the vertex. -------------------- y = (x+2)(-2(x-2)) y = -2(x^2-4) y = -2x^2 + 8 -- Vertex occurs at x = -b/2a = 0/-4 = 0 f(0) = 8 --- So, vertex at (0,8) ------------------------------ ------ Cheers, Stan H. Reply to stanbon@comcast.net ======================================== (A) y = -2(x+2)(x-2);(0,-2) (B) y = -2(x+2)(x-2);(0,0) (C) y = -2(x+2)(x+2);(-4,-8) (D) y = -2(x-2)(x-2);(4,-8)

Polynomials-and-rational-expressions/209557: factor: 2x^5 + x^4 - 8x^3 - 4x^2 1 solutions Answer 158440 by stanbon(57984)   on 2009-08-30 09:24:22 (Show Source): You can put this solution on YOUR website! factor: 2x^5 + x^4 - 8x^3 - 4x^2 ---- x^2(2x^3 + x^2 - 8x - 4) --- I graphed the cubic and found a zero at x = 2 Then using synthetic division I got: 2)....2.....1.....-8.....-4 .......2.....5......2....|..0 Quotient: 2x^2+5x+2 = (2x+1)(x+2) = x^2(2x+1)(x-2)(x+2) ============================== Cheers, Stan H. Reply to stanbon@comcast.net

Travel_Word_Problems/209560: The area of Rhode Island is 1,545 square miles. What is this area ROUNDED to the nearest square mile? 1 solutions Answer 158438 by stanbon(57984)   on 2009-08-30 09:11:28 (Show Source): You can put this solution on YOUR website! The area of Rhode Island is 1,545 square miles. What is this area ROUNDED to the nearest square mile? --------------- It is already rounded to the nearest square mile. If it were rounded to the nearest tenth of a mile it might look like 1545.3 -------------------- Cheers, Stan H. Reply to stanbon@comcast.net

Linear-systems/208972: Aneku has 21 coins whose total value is Sh. 72, there are twice as many five shillings coins as there are 10 shilling coins. The rest are one shilling coins. Find the number of ten shilling coins that Aneku has 1 solutions Answer 158421 by stanbon(57984)   on 2009-08-29 23:19:44 (Show Source): You can put this solution on YOUR website! Aneku has 21 coins whose total value is Sh. 72, there are twice as many five shillings coins as there are 10 shilling coins. The rest are one shilling coins. Find the number of ten shilling coins that Aneku has --------------------- Quantity Eq.: f + t + n = 21 Value Eq:::::5f +10t +n = 72 Quantity Eq.: f = 2t --------------------------------- Rearrange: f + t + n = 21 5f +10t +n = 72 f - 2t +0 = 0 ---------------------- I used a matrix method to get: # of 5 schilling = 6 # of 10 schilling= 3 # of 1 schilling = 12 ============================== Cheers, Stan H. Reply to stanbon@comcast.net

Linear-equations/209043: find the equation of the slant asymptote for the graph of y= x^3 - 4x^2 + 2x -5 / x^2 +2 A)y=x-4 B)y=x+1 C)y=x D)y=1 1 solutions Answer 158420 by stanbon(57984)   on 2009-08-29 23:10:29 (Show Source): You can put this solution on YOUR website! find the equation of the slant asymptote for the graph of y= x^3 - 4x^2 + 2x -5 / x^2 +2 ------------------ Divide, using long division to get: Quotient: x-4 Remainder: 3 ---- The slant asymptote is y = x-4 ---------------------------------------- ---------------------------- Cheers, Stan H. Reply to stanbon@comcast.net ========================================= A)y=x-4 B)y=x+1 C)y=x D)y=1

Square-cubic-other-roots/209048: Please help me solve this problem: (5thrt5x^2y)^9 It is the 5th root of 5x squared time y; all to the 9th power 1 solutions Answer 158412 by stanbon(57984)   on 2009-08-29 22:18:18 (Show Source): You can put this solution on YOUR website! (5thrt5x^2y)^9 -------------------- = (5x^2y)^(9/5) --- = (5x^2y)(5x^2y)^(4/5) ============================= Cheers, Stan H. Reply to stanbon@comcast.net

Polynomials-and-rational-expressions/209054: How do I solve 45a^4b^2-75a^3b+30ab^4 1 solutions Answer 158411 by stanbon(57984)   on 2009-08-29 22:14:10 (Show Source): You can put this solution on YOUR website! How do I solve 45a^4b^2-75a^3b+30ab^4 ------------------------------------------ = 5ab[9a^3b - 15a^2 + 6b^3] =================================== Cheers, Stan H. Reply to stanbon@comcast.net

Pythagorean-theorem/209525: The question says: Use Pathagorean Theorem to find the distance between each pair of points, C(-10,2), D(-7,6). I have been looking over my notes and working very hard on this problem, but I just don't seem to get it. 1 solutions Answer 158410 by stanbon(57984)   on 2009-08-29 22:09:40 (Show Source): You can put this solution on YOUR website! Use Pathagorean Theorem to find the distance between each pair of points, C(-10,2), D(-7,6) ------------------------- d = sqrt[(6-2)^2 + (-7-10)] --- d = sqrt[4^2 + 17^2] --- d = 17.464... =============================== Cheers, Stan H.

Evaluation_Word_Problems/209214: This question is from textbook Pre-Algebra Jess has 3 more nickels than dimes for a total of $1.50. How many of each coin did he have? 1 solutions Answer 158391 by stanbon(57984)   on 2009-08-29 18:08:00 (Show Source): You can put this solution on YOUR website! Jess has 3 more nickels than dimes for a total of $1.50. How many of each coin did he have? ----------------------- Quantity Eq: n = d + 3 Value Eq: 5n + 10d = 150 cents ------------------------------------------- Substitute to solve for "d": 5(d+3)+10d = 150 15d + 15 = 150 15d = 135 d = 9 (# of dimes) n = d+3 = 9+3 = 12 (# of nickels) ====================================== Cheers, Stan H. Reply to stanbon@comcast.net

Complex_Numbers/209218: 3 - 6i ------ > Divided By 6 + 4i 1 solutions Answer 158389 by stanbon(57984)   on 2009-08-29 18:01:44 (Show Source): You can put this solution on YOUR website! 3 - 6i ------ > Divided By 6 + 4i ============================ Multiply numerator and denominator by (6-4i) to get: [(3-6i)(6-4i)]/[6^2+4^2] --- [18-12i - 36i -24]/52 --- [-6 - 48i]/52 --- =[-3 - 24i]/26 ==================== Cheers, Stan H. Reply to stanbon@comcast.net

Functions/209241: if f(x) = x^2 + 3x +2 then [f(x+a)- f(x)]/a = a) 2x+a+3 b) (x+ a)^2 - x^2 c) a^2 + 2ax + 3a d) 2x + a e) 2x+3 1 solutions Answer 158388 by stanbon(57984)   on 2009-08-29 17:54:44 (Show Source): You can put this solution on YOUR website! if f(x) = x^2 + 3x +2 then [f(x+a)- f(x)]/a = --- f(x+a) = (x+a)^2 + 3(x+a) +2 f(x+a) = x^2 +2ax + a^2 + 3x + 3a + 2 ----------------------------------------------- Subtract f(x) from f(x+a) to get: 2ax + a^2 + 3a ----------------------- Divide by "a" to get the final answer: 2x + 3 + a ========================= Cheers, Stan H. Reply to stanbon@comcast.net ------------------------------------- a) 2x+a+3 b) (x+ a)^2 - x^2 c) a^2 + 2ax + 3a d) 2x + a e) 2x+3

Equations/209468: Suppose M is Between L and N. Use the Segment Addition Postulate to solve for the variable. Then find the lengths of LM MN and LN LM= 3x+5 MN = 2x-5 LN = 23 please show all work. thank you 1 solutions Answer 158387 by stanbon(57984)   on 2009-08-29 17:45:46 (Show Source): You can put this solution on YOUR website! Suppose M is Between L and N. Use the Segment Addition Postulate to solve for the variable. Then find the lengths of LM MN and LN LM= 3x+5 MN = 2x-5 LN = 23 --------------------- Equation: 3x+5 + 2x-5 = 23 5x = 23 x = (23/5) ------------------------ LM = 3x+5 = 3(23/5)+5 = (69/5)+(25/5) = 94/5 = 18 4/5 ----------------------- MN = 2x-5 = 2(23/5)-5 = (46/5)-(25/5) = 21/5 = 4 1/5 ============================================================= Cheers, Stan H.

Quadratic_Equations/209498: write a quadratic equation in the variable x having the given numbers as solutions. Type the equation in standard form, ax^2+bx+c=0. Solution:9, only solution 1 solutions Answer 158386 by stanbon(57984)   on 2009-08-29 17:38:51 (Show Source): You can put this solution on YOUR website! write a quadratic equation in the variable x having the given numbers as solutions. Type the equation in standard form, ax^2+bx+c=0. Solution:9, only solution ============================ The quadratic is y = (x-9)^2 y = x^2 - 18x + 81 ============================== Cheers, Stan H.

Equations/209438: i was assigned this word problem, can you help me solve it? please and thank you. july 4th 1876, was america's 100th birthday. all members of the family decided to get together for a great family picnic. when they started off for the picnic grounds, ever wagon they owned was pressed into service. each wagon carried the same number of people. halfway to the grounds 10 wagons broke down, so it was necessary for the remaining wagons to carry one more person. when they started for home it was discovered that 15 more wagons were out of commission. so in the return trip there were three persons more in each wagon that when they started out in the morning. the question is: how many people attended the great family picnic? the paper give you a hint, it says: here's how you might start: let x = number of people per wagon when they started. let y = number of wagons when they started write two equations with x and y, then solve the system. (you'll find that the "xy" terms cancel.) 1 solutions Answer 158377 by stanbon(57984)   on 2009-08-29 15:12:51 (Show Source): You can put this solution on YOUR website! every wagon they owned was pressed into service. each wagon carried the same number of people. ------------- Starting number of people is xy ----------------------- halfway to the grounds 10 wagons broke down, so it was necessary for the remaining wagons to carry one more person. xy = (x+1)(y-10) xy = xy+y-10x-10 y-10x-10 = 0 y - 10x = 10 --------------------------------- when they started for home it was discovered that 15 more wagons were out of commission. so in the return trip there were three persons more in each wagon that when they started out in the morning. xy = (x+3)(y-25) xy = xy+3y-25x-75 3y - 25x = 75 ---------------------------------- Solve this system of equations: y - 10x = 10 3y -25x = 75 ------------------ Substitute y = 10x+10 into 3y-25x = 75 to solve for "x": 3(10x+10) -25x = 75 30x + 30 -25x = 75 5x = 45 x = 9 (# of people per wagon) --- Substitute into y = 10x+10 to solve for "y": y = 10*9 + 10 = 100 (# of wagons at the start) ========================================================== the question is: how many people attended the great family picnic? # at the picnic = xy = 9*100 = 900 ========================================================== Cheers, Stan H. Reply to stanbon@comcast.net ------------------------------------- let x = number of people per wagon when they started. let y = number of wagons when they started

Probability-and-statistics/209460: A coin is flipped 3 times and heads (H) or tails (T) are recorded. a. List all the elements in the sample space. b. List the elements in the event “at least two heads appear.” c. Find the probability that the event in part (b) occurs. 1 solutions Answer 158376 by stanbon(57984)   on 2009-08-29 14:56:17 (Show Source): You can put this solution on YOUR website! A coin is flipped 3 times and heads (H) or tails (T) are recorded. a. List all the elements in the sample space. hhh,hht,hth,thh,htt,tht,tth,ttt ------------------------------------------- b. List the elements in the event “at least two heads appear.” tth,tht,htt,hhh ---------------------------- c. Find the probability that the event in part (b) occurs. P(x >= 2) = 4/8 ------------------------- Cheers, Stan H. Reply to stanbon@comcast.net

Probability-and-statistics/209462: Five women live together in an apartment. Two have blue eyes. If two of the women are chosen at random, what is the probability that they both have blue eyes? 1 solutions Answer 158375 by stanbon(57984)   on 2009-08-29 14:53:07 (Show Source): You can put this solution on YOUR website! Five women live together in an apartment. Two have blue eyes. If two of the women are chosen at random, what is the probability that they both have blue eyes? -------------------- # of ways to pick two with blue eyes: 2C2 = 1 --- # of ways to pick any two from the five: 5C2 = 10 ---------------------- P(pick two with blue eyes) = 1/10 ======================================== Cheers, Stan H. Reply to stanbon@comcast.net

Quadratic_Equations/209463: I need help sovling this problem. I need steps in words as well as the math. Please help I nee to know how to do this. (81a^12 b^16)^-1/2 1 solutions Answer 158374 by stanbon(57984)   on 2009-08-29 14:49:37 (Show Source): You can put this solution on YOUR website! I need help sovling this problem. I need steps in words as well as the math. Please help I nee to know how to do this. (81a^12 b^16)^-1/2 ------------------------- The exponent has two instructions: #1: the negative means "invert" #2: the 1/2 means "take the square root" ----------------------------- You may do the instructions in any order and get the same answer: -------------------------------------- So, Take the square root and you get: (9*a^6*b^8)^-1 --- Now, Invert to get: 1/(9a^6 * b^8) ========================= Cheers, Stan H.

Quadratic_Equations/209451: Harry and Gary are traveling to Nashville to make their fortunes. Harry leaves on the train at 8:00 A.M. and Gary travels by car, starting at 9:00 A.M. To complete the 300-mile trip and arrive at the same time as Harry, Gary travels 10 miles per hour (mph) faster than the train. At what time will they both arrive in Nashville? I am supposed to use the quadratic equation, but this is all I have come up with. 300/8x=300/(9x+10) 1 solutions Answer 158373 by stanbon(57984)   on 2009-08-29 14:44:39 (Show Source): You can put this solution on YOUR website! Harry leaves on the train at 8:00 A.M. and Gary travels by car, starting at 9:00 A.M. To complete the 300-mile trip and arrive at the same time as Harry, Gary travels 10 miles per hour (mph) faster than the train. At what time will they both arrive in Nashville? -------------------------------------- Gary DATA: distance = 300 miles ; rate = x mph ; time = d/r = 300/x hrs ----------------------- Harry DATA: distance = 300 miles ; rate = (x+10) mph ; time = d/r = 300/(x+10) hrs ---------------------------------------- Equation: Harry time - Gary time = 1 hr 300/(x+10) - 300/x = 1 300x - 300(x+10) = x(x+10) -3000 = x^2+10x x^2 + 10x - 3000 = 0 Factor the Quadratic: (x+60)(x-50) = 0 Positive solution: x = 50 mph (Gary's rate) x+10 = 60 mph (Harry's rate) ---------------------- Cheers, Stan H. Reply to stanbon@comcast.net

Linear-equations/209426: Could you please assist me with this? I am having difficulty. Your help is very much appreciated. Media services charges $20 for a phone and $30/month for its economy plan.The equation c=30t+20 describes the total cost, c, of operating a Media Services phone for 1 month. The total cost for 4 months of service is $__________ If a customer has only $90 available, how many months of servie can she receive? 3___, 2 1/3 ____, 2 1/2___, 2____. Then, graph the equation c+30t+20 = total cost 1 solutions Answer 158353 by stanbon(57984)   on 2009-08-29 12:46:27 (Show Source): You can put this solution on YOUR website! Media services charges $20 for a phone and $30/month for its economy plan.The equation c=30t+20 describes the total cost, c, of operating a Media Services phone for 1 month. The total cost for 4 months of service is $30*4 + 20 = 120+20 = $140__________ If a customer has only $90 available, how many months of servie can she receive? 90 = 30t + 20 70 = 30t t = 7/3 t = 2 1/3 3___, 2 1/3 ____, 2 1/2___, 2____. Then, graph the equation c+30t+20 = total cost ------------------------------- ================================================= Cheers, Stan H. Reply to stanbon@comcast.net

Square-cubic-other-roots/209434: Evaluate sqrt((-10-6)**2+(4-7)**2) 1 solutions Answer 158351 by stanbon(57984)   on 2009-08-29 12:37:21 (Show Source): You can put this solution on YOUR website! Evaluate sqrt((-10-6)**2+(4-7)**2) --- sqrt[(-16)^2 + (-3)^2] --- sqrt[256 + 9] sqrt[265] = 16.2788... Cheers, Stan H. Reply to stanbon@comcast.net

Polynomials-and-rational-expressions/209408: how is this problem factored. 3xy^2+11xy-20x 1 solutions Answer 158341 by stanbon(57984)   on 2009-08-29 11:28:23 (Show Source): You can put this solution on YOUR website! how is this problem factored. 3xy^2+11xy-20x --- Think of two numbers whose product is 3*-120 = -60 and whose sum or difference is 11 ---------------- The numbers are 15 and 4 ------------------------------- Rewrite the problem: x(3y^2 + 11y - 20) x(3y^2 + 15y - 4y - 20) x(3y(y+5)-4(y+5)) x(y+5)(3y-4) ====================== Cheers, Stan H. Reply to stanbon@comcast.net

Exponents/209233: if 3^a-b = 1/9 and 3^a+b = 9 then a = A) -2 b) 0 c) 1 d) 2 e) 3 1 solutions Answer 158327 by stanbon(57984)   on 2009-08-29 08:01:54 (Show Source): You can put this solution on YOUR website! 3^(a-b) = 1/9 3^(a+b) = 9 then a = ? -------------------- 3^(a-b) = 3^-2 3^(a+b) = 3^2 ------------------- a-b = -2 a+b = 2 --------- Adding you get: 2a = 0 a = 0 =================== Cheers, Stan H. Reply to stanbon@comcast.net A) -2 b) 0 c) 1 d) 2 e) 3

Expressions-with-variables/209399: I need help with the following quetion : A firefighter spraying water on a fire stood on the middle of the ladder. When the smoke became less thick the firefighter moved up 4 rungs. However it got too hot, so the firefighter backed down 6 rungs. Later the firefighter went up 7 rungs and stayed until the fire was out. Then the firefighter climbed the remaining 4 rungs and entered the building. How many rungs did the ladder have ? I did try to work out this problem using a diagram, but im not sure if the answer is right. 1 solutions Answer 158326 by stanbon(57984)   on 2009-08-29 07:53:16 (Show Source): You can put this solution on YOUR website! I need help with the following quetion : A firefighter spraying water on a fire stood on the middle of the ladder. When the smoke became less thick the firefighter moved up 4 rungs. However it got too hot, so the firefighter backed down 6 rungs. Later the firefighter went up 7 rungs and stayed until the fire was out. Then the firefighter climbed the remaining 4 rungs and entered the building. How many rungs did the ladder have ? --------------- start at rung "h" which is half way up the ladder Then Add 4; then subtract 6, so he is at h-2 Then Add 7 ; then add 4, so he is at h-2+11 = h+9. If that is the top of the ladder(?), the bottom of the ladder is at h-9 so there are 18 + 1 = 19 rungs --------- Cheers, Stan H. Reply to stanbon@comcast.net