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Recent problems solved by 'stanbon'
stanbon answered: 57259 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 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53010..53039 , 53040..53069 , 53070..53099 , 53100..53129 , 53130..53159 , 53160..53189 , 53190..53219 , 53220..53249 , 53250..53279 , 53280..53309 , 53310..53339 , 53340..53369 , 53370..53399 , 53400..53429 , 53430..53459 , 53460..53489 , 53490..53519 , 53520..53549 , 53550..53579 , 53580..53609 , 53610..53639 , 53640..53669 , 53670..53699 , 53700..53729 , 53730..53759 , 53760..53789 , 53790..53819 , 53820..53849 , 53850..53879 , 53880..53909 , 53910..53939 , 53940..53969 , 53970..53999 , 54000..54029 , 54030..54059 , 54060..54089 , 54090..54119 , 54120..54149 , 54150..54179 , 54180..54209 , 54210..54239 , 54240..54269 , 54270..54299 , 54300..54329 , 54330..54359 , 54360..54389 , 54390..54419 , 54420..54449 , 54450..54479 , 54480..54509 , 54510..54539 , 54540..54569 , 54570..54599 , 54600..54629 , 54630..54659 , 54660..54689 , 54690..54719 , 54720..54749 , 54750..54779 , 54780..54809 , 54810..54839 , 54840..54869 , 54870..54899 , 54900..54929 , 54930..54959 , 54960..54989 , 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56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179 , 57180..57209 , 57210..57239 , 57240..57269, >>NextProbability-and-statistics/696925: 1. Conduct an ANOVA comparing the anxiety levels (at posttest only) of participants across all three treatment conditions: CBT, psychodynamic, and supportive therapy.
2. Conduct post hoc tests, if needed.
3. Report your analyses in the APA format and one to two sentences interpreting each of your results.
CBT: 8, 11, 4
PSY: 15, 15, 14
SUPP: 24, 17, 24
1 solutions
Answer 429478 by stanbon(57332) on 2012-12-26 14:45:46 (Show Source):
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Probability-and-statistics/696922: May you please help me with these five problems.
1. An official with Bartram paint believe that a new additive for the company’s deluxe paint has reduced the average drying time of the paint. She provides the following evidence. For a sample of 50 applications of the old formula, a mean drying time of 100 minutes was obtained. The sample standard deviation was 25 minutes. For a sample 50 applications of the new formula, the mean drying time was 93 minutes, with a standard deviation of 24 minutes. Do these results support her belief, or is the difference that she has noted merely due to random chance? Let alpha=.05.
2. A researcher wants to estimates, for a large population of employees, the proportion of those who have ever, sought professional help for an emotional or mental problem. Another researcher found the proportion in a similar population to be 0.25. if the present researcher wants to be within 0.04 of the true proportion with 99% confidence, how large of a sample needs to be to drawn?
3. A random sample of 300 blue-collar workers in a certain city reveals that 75% are planning to vote for a particular candidate for mayor. Of a random sample of 200 white-collar workers, 70% state that they are planning to vote for the candidate. Can we conclude that the two groups differ in their preference for mayor (assume alpha=.05)?
4. The mean weight of a sample of 100 persons from the Honolulu Heart Study is 64 kg. If the ideal weight is known to be 60kg, is the group significantly overweight? Assume the standard deviation is 12kg.
5. A radio station conducts a survey to determine what local citizens perceive to be the most pressing national problem. Of 300 adults contacted, 120 say that they consider declining moral standards to be the most serious problem. Construct the 95% confidence interval for the population that holds his opinion.
1 solutions
Answer 429477 by stanbon(57332) on 2012-12-26 14:44:16 (Show Source):
You can put this solution on YOUR website!1. An official with Bartram paint believe that a new additive for the company’s deluxe paint has reduced the average drying time of the paint. She provides the following evidence.
For a sample of 50 applications of the old formula, a mean drying time of 100 minutes was obtained. The sample standard deviation was 25 minutes.
For a sample 50 applications of the new formula, the mean drying time was 93 minutes, with a standard deviation of 24 minutes.
Do these results support her belief, or is the difference that she has noted merely due to random chance? Let alpha=.05.
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I ran a 2-Sample Z-Test on Ho: u1-u2, and got the following:
test stat: z = 1.980
p-value = 0.0477
Conclusion: Since the p-value is less than 5%, reject Ho.
=============================================================
2. A researcher wants to estimates, for a large population of employees, the proportion of those who have ever sought professional help for an emotional or mental problem. Another researcher found the proportion in a similar population to be 0.25. if the present researcher wants to be within 0.04 of the true proportion with 99% confidence, how large of a sample needs to be to drawn?
---
n = [z/E]^2*pq
n = [2.5758/0.04]^2 * 0.25*0.75 = 778 when rounded up
=============================================================
3. A random sample of 300 blue-collar workers in a certain city reveals that 75% are planning to vote for a particular candidate for mayor. Of a random sample of 200 white-collar workers, 70% state that they are planning to vote for the candidate. Can we conclude that the two groups differ in their preference for mayor (assume alpha=.05)?
----
Ho: p1-p2 = 0
Ha: p1-p2 # 0 (claim)
-----
If ran a 2-Prop Z-Test and got the following:
stat test: z = 1.2337
p-value = 0.2173
---
Since the p-value is greater than 5%, fail to reject Ho.
The test results support the claim.
==============
4. The mean weight of a sample of 100 persons from the Honolulu Heart Study is 64 kg. If the ideal weight is known to be 60kg, is the group significantly overweight? Assume the standard deviation is 12kg.
---
z(64) = (64-60)/[12/sqrt(100)] = 4/(1.2) = 3.3333
The mean weight of the group is 3 1/3 std's over the mean.
The group is significantly overweight as the z value is greater
than 2 .
=====================
5. A radio station conducts a survey to determine what local citizens perceive to be the most pressing national problem. Of 300 adults contacted, 120 say that they consider declining moral standards to be the most serious problem. Construct the 95% confidence interval for the population that holds his opinion.
---
p-hat = 120/300 = 0.4
ME = 1.96*sqrt(0.4*0.6/300) = 0.0554
===========
95% CI: 0.4-0.0554 < P < 0.4+0.0554
=====================================
Cheers,
Stan H.
============
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Probability-and-statistics/696923: 1.Conduct an ANOVA comparing the anxiety levels (at posttest only) of participants across all three treatment conditions: CBT, psychodynamic, and supportive therapy.
2. Conduct post hoc tests, if needed.
3. Report your analyses in the APA format and one to two sentences interpreting each of your results.
CBT: 8, 11, 4
PSY: 15, 15, 14
SUPP: 24, 17, 24
1 solutions
Answer 429475 by stanbon(57332) on 2012-12-26 14:21:57 (Show Source):
You can put this solution on YOUR website!1.Conduct an ANOVA comparing the anxiety levels (at posttest only) of participants across all three treatment conditions: CBT, psychodynamic, and supportive therapy.
---
Ho: The means are equal
Ha: at least one of the means is different
----------
Using a TI-84 I conducted ANOVA on the three lists and
got the following:
test stat: F = 15.21
p-value = 0.0045
Conclusion: Since the p-value is less than 5%
reject Ho at the 5% significance level.
------------------------------
2. Conduct post hoc tests, if needed.
3. Report your analyses in the APA format and one to two sentences interpreting each of your results.
----
I'll leave # 2 and 3 to you.
Cheers,
Stan H.
==============
CBT: 8, 11, 4
PSY: 15, 15, 14
SUPP: 24, 17, 24
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Probability-and-statistics/696919: An oil burner in a housing development burns 76 gallons of fuel oil per hour. At 9am on a very cold day,the superintendent asks the housing manager to put in an emergency order for more fuel oil. At that. Time, he report that he has on hand 266 gallons. At noon, he. Again comes to the manager, notifying him that no oil has been delivered the. Maximum amount of time that he can continue to furnish heat without receiving more oil is 1 solutions
Answer 429470 by stanbon(57332) on 2012-12-26 14:03:04 (Show Source):
You can put this solution on YOUR website!An oil burner in a housing development burns 76 gallons of fuel oil per hour. At 9am on a very cold day,the superintendent asks the housing manager to put in an emergency order for more fuel oil. At that. Time, he report that he has on hand 266 gallons. At noon, he. Again comes to the manager, notifying him that no oil has been delivered the. Maximum amount of time that he can continue to furnish heat without receiving more oil is
----
266/76 = 3.5 hrs of full left at 9:00am.
---
!/2 hr of full left at noon.
=================================
Cheers,
Stan H.
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Numbers_Word_Problems/696884: an call for volunteers to act in a community play brings out ten men and eight women. if there are nine parts in the play, four for males and five for females, how many different casts are possible? 1 solutions
Answer 429448 by stanbon(57332) on 2012-12-26 10:26:04 (Show Source):
You can put this solution on YOUR website!a call for volunteers to act in a community play brings out ten men and eight women. if there are nine parts in the play, four for males and five for females, how many different casts are possible?
------------------
Ans: 10C4 * 8C5 = 210 * 56 = 11,760
===========
Cheers,
Stan H.
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Numbers_Word_Problems/696896: find two consecative odd number such that one fifth of the smaller exceeds one ninth of the greater by 2 1 solutions
Answer 429447 by stanbon(57332) on 2012-12-26 10:21:06 (Show Source):
You can put this solution on YOUR website!find two consecutive odd numbers such that one fifth of the smaller exceeds one ninth of the greater by 2
-----
1st: 2x-1
2nd: 2x+1
-----
Equation:
(1/5)(2x-1) = (1/9)(2x+1) + 2
--------
Multiply thru by 45 to get:
9(2x-1) = 5(2x+1) + 90
-----
18x - 9 = 10x + 95
----
8x = 104
---
x = 13
----
1st: 2x-1 = 25
2nd: 2x+1 = 27
====================
Cheers,
Stan H.
============
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Word_Problems_With_Coins/696897: three pretzels and one cup of soda costs $2.75. two pretzels and one cup of soda costs $2.00. find the cost of a pretzel and the cost of a cup of soda. 1 solutions
Answer 429446 by stanbon(57332) on 2012-12-26 10:15:37 (Show Source):
You can put this solution on YOUR website!three pretzels and one cup of soda costs $2.75. two pretzels and one cup of soda costs $2.00. find the cost of a pretzel and the cost of a cup of soda.
-----
Equations:
3p + s = 275 cents
2p + s = 200 cents
-------------------
Subtract and solve for "p":
p = 75 cents (cost of one pretzel)
---------
Solve for "s":
2p + s = 200
2*75+s = 200
s = 50 cents (cost of one soda)
================================
Cheers,
Stan H.
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Expressions-with-variables/696849: I need help with these problems. My book says to multiply and put in simplest form.
1.) (b+4)/(2)^2 times (3)/(b+4)^3
2.) (b+4)/(b-2) times (b^2)-(4)/(b^2)-(16)
1 solutions
Answer 429404 by stanbon(57332) on 2012-12-25 22:10:23 (Show Source):
You can put this solution on YOUR website!multiply and put in simplest form.
1.) (b+4)/(2)^2 times (3)/(b+4)^3
----
[(b+4)/4] * [3/[(b+4)(b^2-4b+16)]]
----
Cancel any factor(s) common to a numerator and a denominator:
[1/4] * [3/[(b^2-4b+16)]]
------
= 3/[4(b^2-4b+16)]
========================
2.) (b+4)/(b-2) times (b^2)-(4)/(b^2)-(16)
----
[(b+4)/(b-2)] * [[(b-2)(b+2)/(b-4)(b+4)]
----
Cancel where you can:
----
[1/1] * [[(b+2)/(b-4)]
==============
= (b+2)/(b-4)
=================
Cheers,
Stan H.
=================
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test/696848: hello. i have a problem that i do not understand,can you help me. It says:
In Tess'store, four pounds of pears cost $6. In Dorothy's store, 10 pounds of pears are sold for $15. Bubble in 1 if it costs more, 2 if it costs less, and 3 if it is the same to buy pears in Dorothy's store. 1 solutions
Answer 429386 by stanbon(57332) on 2012-12-25 18:30:12 (Show Source):
You can put this solution on YOUR website!In Tess'store, four pounds of pears cost $6. In Dorothy's store, 10 pounds of pears are sold for $15. Bubble in 1 if it costs more, 2 if it costs less, and 3 if it is the same to buy pears in Dorothy's store.
------------
Tess's store charges 6/4 = 3/2 dollars per pound
---
Dorothy's store charges 15/10 = 3/2 dollars per pound
-----
So, Bubble in "3".
Cheers,
Stan H.
===========
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Miscellaneous_Word_Problems/696834: A tortoise travelled 4096 m in week one. Each week, it travelled half as far as the previous week. In what week will the tortoise travel 4 m? Please show me using a formula or equation. I know the answer because I used the calculator but I still want to know how to find the answer using a formula or equation.I'm in grade 7 can you explain, because the previous time i didnt understand. Help! 1 solutions
Answer 429382 by stanbon(57332) on 2012-12-25 18:24:55 (Show Source):
You can put this solution on YOUR website!A tortoise travelled 4096 m in week one. Each week, it travelled half as far as the previous week. In what week will the tortoise travel 4 m? Please show me using a formula or equation. I know the answer because I used the calculator but I still want to know how to find the answer using a formula or equation.
----
Look at the pattern:
#1 term: 4096
---
#2 term: 4096(1/2) = 2048
---
#3 term: 4096(1/2)^2 = 1024
----
....
....
----
nth term: 4096(1/2)^(n-1)
------
You want to find "n" when you are told the term is 4
----
Solve: 4096(1/2)^(n-1) = 4
-------
Note: 4096 = 2*2*2*2*2...*2*2*2 = 2^12
----
So: (2^(12))(1/2)^(n-2) = 4
----
Then: (2^12))(2)^(2-n) = 4
---
2^(14-n) = 2^2
---
14-n = 2
---
n = 12
----
4 is the 12th term of the sequence.
================
Cheers,
Stan H.
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Money_Word_Problems/696837: an investor invest 2800 dollars into two mutual funds one has a profit of 5% the other has 2%, the total profit is 80, how much was invested in each fund.
let x=5%
lety=2%
x+y=2800
0.05x+0.02y=80
I know how to write the problem but I forgot how to get to the answer could you please show me the equation step by step
1 solutions
Answer 429379 by stanbon(57332) on 2012-12-25 18:11:29 (Show Source):
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Numeric_Fractions/696844: what is the quotient of 22 divided by 8 and put the mixed number in simplest form.
Thank you 1 solutions
Answer 429378 by stanbon(57332) on 2012-12-25 18:09:51 (Show Source):
You can put this solution on YOUR website!what is the quotient of 22 divided by 8
and put the mixed number in simplest form.
----------------
22/8 = 16/8 + 6/8
= 2 + 3/4
= 2 3/4
======================================
Cheers,
Stan H.
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Graphs/696845: What is the x coordinate of the point at which the line intersects the x axis on a graph with a line going through pint (7,2) and point (8,-1) 1 solutions
Answer 429377 by stanbon(57332) on 2012-12-25 18:04:03 (Show Source):
You can put this solution on YOUR website!What is the x coordinate of the point at which the line intersects the x axis on a graph with a line going through point (7,2) and point (8,-1)
--------
slope = (2--1)/(7-8) = -3
----
Form: y = mx + b
You have m = -3 and y = -1 when x = 8 ; solve for "b":
-1 = -3*8 + b
b = 22
--------
Equation:
f(x) = -3x + 22
Ans:
Solve -3x+22 = 0
-3x = -22
x = 22/3
---------------
Cheers,
Stan H.
----------------
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Money_Word_Problems/696839: an investor invest 2800 dollars into two mutual funds one has a profit of 5% the other has 2%, the total profit is 80, how much was invested in each fund.
1 solutions
Answer 429374 by stanbon(57332) on 2012-12-25 17:55:57 (Show Source):
You can put this solution on YOUR website! an investor invest 2800 dollars into two mutual funds one has a profit of 5% the other has 2%, the total profit is 80, how much was invested in each fund.
-----
Equations:
Quantity: a + b = 2800 dollars
Interest:5a + 2b = 8000
-------------------------
Multiply thru the Quantity Equation by 2:
2a + 2b = 2*2800
5a + 2b = 8000
---------------------
Subtract and solve for "a":
3a = 2400
------
s = 800 (amt. invested at 5%)
----
Solve for "a":
a+b = 2800
a + 800 = 2800
a = 2000 (amt. invested at 2%)
===============
Cheers,
Stan H.
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Graphs/696841: Line a is perpendicular to line b. Line a has an equation y=-3x-4. What is the equation of line b if line b passes through the point (-3,4) 1 solutions
Answer 429373 by stanbon(57332) on 2012-12-25 17:48:02 (Show Source):
You can put this solution on YOUR website!Line a is perpendicular to line b. Line a has an equation y=-3x-4. What is the equation of line b if line b passes through the point (-3,4)
----
The given line has slope = -3.
---
Any perpendicular must have slope = 1/3
-----
Your Equation ??
Form: y = mx + b
----
slope = 1/3 and y = 4 when x = -3; solve for "b":
4 = (1/3)(-3) + b
---
4 = -1 + b
b = 5
-----
Equation: y = (1/3)x + 5
=========================
Cheers,
Stan H.
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Graphs/696842: what is the slope of a line perpendicular to a line with an equation 4x-2y=6 1 solutions
Answer 429372 by stanbon(57332) on 2012-12-25 17:43:11 (Show Source):
You can put this solution on YOUR website!what is the slope of a line perpendicular to a line with an equation 4x-2y=6
----------------
Given Equation:
4x-2y = 6
2y = 4x - 6
---
y = 2x -3
----
Its slope: m = 2
-----
Any line perpendicular to it must have
------------------
Cheers,
Stan H.
==================
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Problems-with-consecutive-odd-even-integers/696798: The time taken by Arushi to cover 150 km was 2hrs and 30 min more than the time taken in return journey. If she returned at a speed of 10km/hr more than the speed of going,find her speed in each direction. 1 solutions
Answer 429354 by stanbon(57332) on 2012-12-25 13:44:38 (Show Source):
You can put this solution on YOUR website!The time taken by Arushi to cover 150 km was 2hrs and 30 min more than the time taken in return journey. If she returned at a speed of 10km/hr more than the speed of going,find her speed in each direction.
--------
Going DATA:
dist = 150 km ; rate = r km/hr ; time = 150/r hrs
------------------
Return DATA:
dist = 150 km ; rate = r+10 km/hr ; time = 150/(r+10) hrs
-------
Equation:
time - time = 2.5 hrs
150/r - 150/(r+10) = 2.5 hrs
--------
150r + 150+10 - 150r = 2.5r(r+10)
--------
2.5r^2 + 25r - 1500 = 0
r^2 + 10r - 600 = 0
---
Factor:
(r+30)(r-20) = 0
----
Positive solution:
rate = 20 km/hr (going speed)
r + 10 = 30 km/hr (return speed)
====================================
Cheers,
Stan H.
==============
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Problems-with-consecutive-odd-even-integers/696792: Meeta can row her boat at 5km per hour in sill water.If she takes 1hr more to row the boat 5.25km upstream than to return downstream,find the speed of the stream. 1 solutions
Answer 429353 by stanbon(57332) on 2012-12-25 13:36:03 (Show Source):
You can put this solution on YOUR website!Meeta can row her boat at 5km per hour in still water. If she takes 1hr more to row the boat 5.25km upstream than to return downstream, find the speed of the stream.
--------
Upstream DATA:
rate = 5 - s ; distance = 5.25 km ; time = d/r = 5.25/(5-s) hrs.
--------------------
Downstream DATA:
rate = 5+s ; distance = 5.25 km ; time = d/r = 5.25/(5+s) hrs
--------------------
Equation:
time - time = 1 hr
5.25/(5-s) - 5.25/(5+s) = 1
-----
5.25*5 + 5.25s - 5.25*5 + 5.25s = 25-s^2
--------
10.5s = 25-s^2
--------
s^2 + 10.5s - 25 = 0
-----
Factor:
(s-2)(s+12.5) = 0
------
Positive solution:
s = 2 km/hr (speed of the stream)
=====================
Cheers,
Stan H.
=====================
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expressions/696781: What is the coefficient of x^2y^5 when (x-2y)^7 is expanded? 1 solutions
Answer 429352 by stanbon(57332) on 2012-12-25 13:24:28 (Show Source):
You can put this solution on YOUR website! What is the coefficient of x^2y^5 when (x-2y)^7 is expanded?
----------------------
Ans: 7C2*x^2*(-2y)^5 = 21*x^2*(-32y^5) = -672x^2y^5
==============================
Cheers,
Stan H.
==============================
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Problems-with-consecutive-odd-even-integers/696811: To cover 14 km distance , anubhav cycles at a certain average speed. If he reduces his average speed by1 km/hr , he takes 20 min more to cover the same distance. find the original speed. 1 solutions
Answer 429349 by stanbon(57332) on 2012-12-25 12:37:54 (Show Source):
You can put this solution on YOUR website!To cover 14 km distance , anubhav cycles at a certain average speed. If he reduces his average speed by1 km/hr , he takes 20 min more to cover the same distance. find the original speed.
-------------------
1st trip DATA:
distance = 14 km ; speed = x km/hr ; time = 14/x hrs
-------
2nd trip DATA:
distance = 14 km ; speed (x-1) km/hr ; time = 14/(x-1) hrs
-------
Equation:
time - time = 1/3 hr
----
14/(x-1) - 14/x = 1/3
----
3*14x - 3*14(x-1) = x(x-1)
42x - 42x - 42 = x^2 - x
---
x^2 -x + 42 = 0
Factor:
(x-7)(x+6) = 0
Positive solution:
x = 7 km/hr (original speed)
==================================
Cheers,
Stan H.
==================
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test/696717: How do i graph inequalities? 1 solutions
Answer 429276 by stanbon(57332) on 2012-12-24 13:06:28 (Show Source):
You can put this solution on YOUR website!You do not graph the inequality directly.
You graph the boundary of the inequality.
Then you shade the area that satisfies the condition
of the inequality.
---
Example:
Graph: y <= 2x + 5
---
1st: Graph the boundary y = 2x+5 as a normal line.

---
2nd: Shade the half-plane BELOW the boundary be cause
you wan y to be LESS than the boundary.

-------------
Cheers,
Stan H.
=============
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Rate-of-work-word-problems/696746: Three pipes can fill a pool in eight hours.A drain can empty the fill pool in twelve hours.How many hours will it take to fill a quarter of the fool if the three pipes and drain open? 1 solutions
Answer 429275 by stanbon(57332) on 2012-12-24 12:56:30 (Show Source):
You can put this solution on YOUR website!Three pipes can fill a pool in eight hours.A drain can empty the fill pool in twelve hours.How many hours will it take to fill a quarter of the fool if the three pipes and drain open?
-----
3-pipe rate: 1/8 job/hr
Drain rate: 1/1/12 job/hr
Together rate: 1/x job/hr
-----
rate - rate = together rate
1/8 - 1/12 = 1/x
12x - 8x = 8*12
4x = 8*12
x = 24 hrs (time to fill the pool together)
======================
Cheers,
Stan H.
================
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Travel_Word_Problems/696685: The number N of state and federal inmates in millions during year x, where x>2002
can be approximated by the following formula N=0.05x-98.55 determine the year in which there were 1.6 million inmates. show work 1 solutions
Answer 429238 by stanbon(57332) on 2012-12-23 20:39:15 (Show Source):
You can put this solution on YOUR website!The number N of state and federal inmates in millions during year x, where x>2002
can be approximated by the following formula N=0.05x-98.55 determine the year in which there were 1.6 million inmates. show work
-----------
Solve 0.05x - 98.55 mil = 1.6m
-----
0.05x = 96.95
x = 1939
===============
Cheers,
Stan H.
=================
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Linear-equations/696683: Hi. My teacher makes us use www.assistments.org and the problems on there are really hard because I dont understand them. If you get a certain amount wrong, you get locked out and you have to try again another day. I dont understand the linear equations because my teacher does the notes too fast for me to keep up with the lesson. How can I? Write a linear equation in the form "y = ______________" using the following information about the equation:
X-intercept of the equation: -10
Y-intercept of the equation: 3
1 solutions
Answer 429237 by stanbon(57332) on 2012-12-23 20:32:35 (Show Source):
You can put this solution on YOUR website!Write a linear equation in the form "y = ______________" using the following information about the equation:
X-intercept of the equation: (-10,0)
Y-intercept of the equation: (0,3)
================
slope = (3-0)/(0--10) = 3/10
-----
Equation:
y = mx + b
y = (3/10)x + 3
===================
Cheers,
Stan H.
===================
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Linear-equations/696684: Hi. My teacher makes us use www.assistments.org and the problems on there are really hard because I dont understand them. If you get a certain amount wrong, you get locked out and you have to try again another day. I don't understand the Evaluating Functions. I dont even remember us learning about it. Use the equation 7m - 11m = n to find m when n = 4.
1 solutions
Answer 429236 by stanbon(57332) on 2012-12-23 20:26:09 (Show Source):
You can put this solution on YOUR website!Use the equation 7m - 11m = n to find m when n = 4
----
Substitute for "n" and solve for "m":
----
7m - 11m = n
-4m = n
-----
-4m = 4
----
Divide both isdes by -4 to get:
---------
m = -1
===========
Cheers,
Stan H.
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Functions/696667: f(x)= y+6/y^2-6y what is the domain and range of this? 1 solutions
Answer 429235 by stanbon(57332) on 2012-12-23 20:15:28 (Show Source):
You can put this solution on YOUR website! f(x)= y+6/y^2-6y what is the domain and range of this?
-----
Factor:
f(x) = (y+6)/(y(y-6))
-----
The denominator cannot be zero.
Domain: All Real Numbers except y = 0 and x = 6.
----
The horizontal asymptote is f(x) = 0/1 = 0
Vertical asymptotes at y = 0 and y = 6
-----
Range: All Real Numbers except 0.
-----
Cheers,
Stan H.
=================
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Money_Word_Problems/696677: Can anyone help me solve this problem ? I have no idea how to do it. An investor invested a total of $1,900 in two mutual funds, one fund earned a 7% profit, while the other earned a 4% profit. If the investor's total profit was $97, how much was invested into each mutual fund?
Amount invested into mutual fund that earned 7% -
Amount invested into mutual fund that earned 4%- 1 solutions
Answer 429233 by stanbon(57332) on 2012-12-23 20:02:58 (Show Source):
You can put this solution on YOUR website!Can anyone help me solve this problem ? I have no idea how to do it. An investor invested a total of $1,900 in two mutual funds, one fund earned a 7% profit, while the other earned a 4% profit. If the investor's total profit was $97, how much was invested into each mutual fund?
Principal Equation: a + b = 1900
Interest Equation: 7a + 4b = 9700
--------------------------------------
Multiply thru 1st by 4
----------------------------
4a + 4b = 4*1900
7a + 4b = 9700
---
Subtract and solve for "a":
3a = 2100
a = 700 (amt. invested at 7%
-----
Solve for "b":
a + b = 1900
700 + b = 1900
b = 1200 (amt. invested at 4%
====================================
Cheers,
Stan H.
Amount invested into mutual fund that earned 7% -
Amount invested into mutual fund that earned 4%-
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Probability-and-statistics/696632: A survey was conducted to measure the height of men. In the survey, respondents were grouped by age. In the 20-29 group the groups were normally distributed, with a mean of 68.4 inches and a standard deviation of 4 inches. A study participant is randomly selected. Complete parts a through c
a. Find the probability that his height is less than 66 inches
b. FInd the probability that the height is between 66 and 71 inches
c. Find the probability that the height is more than 71 inches 1 solutions
Answer 429185 by stanbon(57332) on 2012-12-23 15:01:43 (Show Source):
You can put this solution on YOUR website!A survey was conducted to measure the height of men. In the survey, respondents were grouped by age. In the 20-29 group the groups were normally distributed, with a mean of 68.4 inches and a standard deviation of 4 inches. A study participant is randomly selected. Complete parts a through c
a. Find the probability that his height is less than 66 inches
z(66) = (66-68.4)/4 = -0.6
P(x < 66) = P(z < -0.6) = normalcdf(-100,-0.6) = 0.2743
----------------------------------------------------------------
b. FInd the probability that the height is between 66 and 71 inches
z(71) = (71-68.4)/4 = 0.65
P(66< x <71) = P(-0.6< z <0.65) = normalcdf(-0.6,0.65) = 0.4675
------------------------------------
c. Find the probability that the height is more than 71 inches
P(x > 71) = P(z > 0.65) = normalcdf(0.65,100) = 0.2578
==========================
Cheers,
Stan H.
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Probability-and-statistics/696636: A bicycle safety organization claims that..........Can you reject that the distirbution is uniform? A bicycle safety organization claims that fatal bicycle accidents are uniformly disturbed throughout the week. The table shows the day of the week for which 779 randomly selected fatal bicycle accidents occurred. At ?=0.10, can you reject the claim that the distribution is uniform?
a) State your Hypothesis, and identify the claim
b) (DATA) Conduct the test and underline your decision
Sunday107
Monday113
Tuesday 106
Wednesday 111
Thursday 123
Friday 106
Saturday 113 T
determine the critical value adn the rejection region calculate teh test statistic and decide whether or not to reject the null hypothesis
please help!! 1 solutions
Answer 429184 by stanbon(57332) on 2012-12-23 14:39:00 (Show Source):
You can put this solution on YOUR website!A bicycle safety organization claims that..........Can you reject that the distirbution is uniform? A bicycle safety organization claims that fatal bicycle accidents are uniformly disturbed throughout the week. The table shows the day of the week for which 779 randomly selected fatal bicycle accidents occurred. At ?=0.10, can you reject the claim that the distribution is uniform?
a) State your Hypothesis, and identify the claim
b) (DATA) Conduct the test and underline your decision
Sunday107
Monday113
Tuesday 106
Wednesday 111
Thursday 123
Friday 106
Saturday 113 T
determine the critical value and the rejection region calculate teh test statistic and decide whether or not to reject the null hypothesis
-------------------------------------------------------
Ho: probabilities are all equal
Ha: at least one of the probabilities is not equal
-----------
I ran a Goodness-of-Fit Test on my TI84 and got the following:
Test statistic: Chi-Sq = 15.99..
p-value: 0.0011..
Conclusion: Since the p-value is less than 10% reject Ho.
================
Cheers,
Stan H.
===========
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Age_Word_Problems/696593: the sum of the ages of two men equals99.If the inverted age of the older is added to the age of the younger the sum is 108.However is the age of the younger is inverted and subtracted from the age of the older, the difference is 44. find the age of the older man 1 solutions
Answer 429158 by stanbon(57332) on 2012-12-23 09:12:36 (Show Source):
You can put this solution on YOUR website!the sum of the ages of two men equals99.If the inverted age of the older is added to the age of the younger the sum is 108.However is the age of the younger is inverted and subtracted from the age of the older, the difference is 44. find the age of the older man
-----
Equations:
x + y = 99
x + 1/y = 108
y - 1/x = 44
---------
Substitute for "x" and solve for "y" in x + (1/y) = 108
----
99-y + 1/y = 108
99y - y^2 + 1 = 108y
y^2 + 9y -1 = 0
---
y = [-9 +- sqrt(81-4*-1)]/2
Positive solution:
y = [-9 + sqrt(86)]/2
y = 0.1368 yrs
---
Comment:
I very much doubt that answer, but it is the answer
to the problem that you posted.
Cheers,
Stan H.
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