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Recent problems solved by 'stanbon'

stanbon answered: 57178 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 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56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179, >>Next

Probability-and-statistics/270600: Can someone please help me answer the following question? Thank you. Find the number of successes x suggested by the given statement. 5. Among 660 adults selected randomly from among the residents of one town, 30.2% said that they favor stronger gun-control laws. 6. Among 1400 randomly selected car drivers in one city, 8.29% said that they had been involved in an accident during the past year. 1 solutions Answer 198194 by stanbon(57246)   on 2010-02-16 22:25:06 (Show Source): You can put this solution on YOUR website! Find the number of successes x suggested by the given statement. 5. Among 660 adults selected randomly from among the residents of one town, 30.2% said that they favor stronger gun-control laws. --- # of "successes" = 0.302*660 = 199 6. Among 1400 randomly selected car drivers in one city, 8.29% said that they had been involved in an accident during the past year. ----- # of "successes" = 0.0829*1400 = 116 ============================================= Cheers, Stan H.

Linear-systems/270598: What are the domain and range of each relation? Is the relation a function? E= {(40,10),(-18,27),(38,10),(57,-15)} 1 solutions Answer 198193 by stanbon(57246)   on 2010-02-16 22:21:14 (Show Source): You can put this solution on YOUR website! What are the domain and range of each relation? Is the relation a function? E= {(40,10),(-18,27),(38,10),(57,-15)} ------------------------------ Each ordered pair has a 1st element and a 2nd element. --- Domain is the set of 1st elements: {40,-18, etc. Range is the set of 2nd elements: {10,27, etc. ------------------------------ It is a function because each 1st element has just one 2nd element. ------- Cheers, Stan H.

Linear-systems/270595: Write the ordered pair for f(-5) = 8 and identify the x- and y-values. 1 solutions Answer 198192 by stanbon(57246)   on 2010-02-16 22:15:46 (Show Source): You can put this solution on YOUR website! Write the ordered pair for f(-5) = 8 and identify the x- and y-values. --------- ordered pair: (-5,8) --- x = -5 y = 8 ------------------ Cheers, Stan H.

absolute-value/270588: Solve the inequality: absolute value of 3-5x + 5 greater than equal to 6 **(So, it is the absolute value of 3-5x, and then it is followed by + 5 greater than equal to 6) 1 solutions Answer 198191 by stanbon(57246)   on 2010-02-16 22:13:19 (Show Source): You can put this solution on YOUR website! Solve the inequality: absolute value of 3-5x + 5 greater than equal to 6 -------- |3-5x| + 5 >= 6 ---- |3-5x| >= 1 ---- 3-5x >1 or 3-5x < -1 -5x > -2 or -5x < -4 x < 2/5 or x > 4/5 ========================= Cheers, Stan H.

Exponents-negative-and-fractional/270585: 23-2[4+3(x-1)]+5[x-2(x+3)]=7 {x-2[5-(2x+3)] } this all looks like jumble to me, my I please get this problem broken down step by step; PLEASE 1 solutions Answer 198190 by stanbon(57246)   on 2010-02-16 22:07:42 (Show Source): You can put this solution on YOUR website! 23-2[4+3(x-1)]+5[x-2(x+3)] = 7 {x-2[5-(2x+3)] ------------ 23-2[4+3x-3]+5[x-2x-6] = 7 {x-2[5-2x-3] ---------------- 23-2[1+3x]+5[-x-6] = 7{x-2[2-2x] ---------------- 23-2-6x-5x-30 = 7{x-4+4x] --------------- -9-11x = 7{5x-4] ------------------ -9-11x = 35x-28 46x = 19 ------ x = 19/46 ============== Cheers, Stan H.

Circles/270582: What is the number Pi square units in the area of a circle the longest chord of which is 2 units? 1 solutions Answer 198188 by stanbon(57246)   on 2010-02-16 21:37:26 (Show Source): You can put this solution on YOUR website! What is the number Pi square units in the area of a circle the longest chord of which is 2 units? ---------- The longest chord of a circle is a diameter. Radius = 1 unit --- Area = (pi)r^2 = pi units ============================== Cheers, Stan H.

Triangles/270577: Explain whether or not a cylinder has to have a circular base. 1 solutions Answer 198187 by stanbon(57246)   on 2010-02-16 21:34:22 (Show Source): You can put this solution on YOUR website! No, it could be triangular, or a square, or any other plane figure. Cheers, Stan H.

Probability-and-statistics/270478: if a deck has 53 cards, it contains 4 cuits (hearts,dimonds,clubs, and spades) of 13 cards each, where 10 are numbers cards and 3 face cards (jack, queen, king) a)how many different 6-card hands are possible if order does not matter? b) how many different 6-card hands can be dealt with all face cards sif order does not matter? c)How many 7-card hands can be dealt with no faces if order does not matter? 1 solutions Answer 198180 by stanbon(57246)   on 2010-02-16 19:56:44 (Show Source): You can put this solution on YOUR website! if a deck has 52 cards, it contains 4 suits (hearts,dimonds,clubs, and spades) of 13 cards each, where 10 are numbers cards and 3 face cards (jack, queen, king) a)how many different 6-card hands are possible if order does not matter? Ans: 52C6 -------------------- b) how many different 6-card hands can be dealt with all face cards if order does not matter? Ans: 12C6 ----------------- c)How many 7-card hands can be dealt with no face cards if order does not matter? Ans: 40C7 ============================ Cheers, stan H.

Probability-and-statistics/270486: A class has 29 students, of which 5 are seniors. How many committees of size 5 can be selected if at least one member of each committee must be a senior? 1 solutions Answer 198174 by stanbon(57246)   on 2010-02-16 19:50:37 (Show Source): You can put this solution on YOUR website! A class has 29 students, of which 5 are seniors. How many committees of size 5 can be selected if at least one member of each committee must be a senior? ------------------------------------------------ P(no senior in group of 5) = 24C5/29C5 = 42504/118755 = 0.3579 ---- P(at least one senior) = 1 - P(no senior) = 1 - 0.3579 = 0.6421... Cheers, Stan H.

Polygons/270447: What is the measure of an interior angle of a regular 9-gon? 1 solutions Answer 198144 by stanbon(57246)   on 2010-02-16 18:39:45 (Show Source): You can put this solution on YOUR website! What is the measure of an interior angle of a regular 9-gon? ----------------------- Fact: The sum of the exterior angles is 360 degrees. In a 9-gon each exterior angle is 360/9 = 40 degrees Each corresponding interior angle is 180-40 = 140 degrees ====================================== Cheers, Stan H.

Probability-and-statistics/270404: A shipping department will deliver a product in one, two, three or four days. The probability of delivery in one day is 0.18. The probability of delivery in two days is 0.27. The probability of delivery in three days is 0.48. What is the expected number days of delivery? 1 solutions Answer 198141 by stanbon(57246)   on 2010-02-16 18:29:45 (Show Source): You can put this solution on YOUR website! A shipping department will deliver a product in one, two, three or four days. The probability of delivery in one day is 0.18. The probability of delivery in two days is 0.27. The probability of delivery in three days is 0.48. What is the expected number days of delivery? ---- Multiply each "day-number" by its probability. Then add the products to get the expected value. ---- Cheers, Stan H.

Probability-and-statistics/270406: Meredith has 20 shirts, 5 skirts, and 4 pair of shoes. How many different outfits (consisting of one shirt, one skirt and one pair of shoes) can she make? 1 solutions Answer 198137 by stanbon(57246)   on 2010-02-16 18:23:14 (Show Source): You can put this solution on YOUR website! Meredith has 20 shirts, 5 skirts, and 4 pair of shoes. How many different outfits (consisting of one shirt, one skirt and one pair of shoes) can she make? ---------------------- Ans: 20*5*4 = 400 outfits ============================== Cheers, Stan H.

Probability-and-statistics/270410: A class has 15 students. Four of these students will be chosen to complete a special group project. How many different groupings (order does not matter) of 4 students can be created from this class of 15? 1 solutions Answer 198133 by stanbon(57246)   on 2010-02-16 18:20:04 (Show Source): You can put this solution on YOUR website! A class has 15 students. Four of these students will be chosen to complete a special group project. How many different groupings (order does not matter) of 4 students can be created from this class of 15? ---------------- Ans: 15C4 = 15!/(15-4)!/4! = 1365 ---------------- Cheers, Stan H.

Surface-area/270439: a cube has a surface area of 364 cm squared.what is the edge lenth of the cube? 1 solutions Answer 198131 by stanbon(57246)   on 2010-02-16 18:14:51 (Show Source): You can put this solution on YOUR website! a cube has a surface area of 364 cm squared.what is the edge length of the cube? ---- Let each edge have length "x". ---- Equation: surface area = 6x^2 = 364 x^2 = 384/6 --- x = sqrt(384/6) = sqrt(64) = 8 cm ================= Cheers, Stan H.

Probability-and-statistics/270415: For a normal probability distribution with a mean of 240 and a standard deviation of 40, calculate the following: a. The probability that an observation will fall between 240 and 300. b. The probability that an observation will fall between 195 and 240. c. The probability that an observation will be less than 260. d. The probability that an observation will fall between 180 and 220. 1 solutions Answer 198129 by stanbon(57246)   on 2010-02-16 18:10:36 (Show Source): You can put this solution on YOUR website! For a normal probability distribution with a mean of 240 and a standard deviation of 40, calculate the following: ------- a. The probability that an observation will fall between 240 and 300. z(240) = (240-240)/40 = 0 z(300) = (300-240)/40 = 3/2 P(240< x <300) = P(0< z < 3/2) = 0.4332 ----- Fallow the same procedure for b,c, and d. Cheers, Stan H. b. The probability that an observation will fall between 195 and 240. c. The probability that an observation will be less than 260. d. The probability that an observation will fall between 180 and 220.

Probability-and-statistics/270422: Maggie is applying to college. There are only two outcomes for each application. It is either accepted or rejected. Each application she sends has a 0.70 probability of being accepted. If Maggie applies to 10 colleges, what is the probability that more than 8 of the applications will be accepted? What is the expected value for "number of acceptances?" 1 solutions Answer 198127 by stanbon(57246)   on 2010-02-16 18:04:42 (Show Source): You can put this solution on YOUR website! Maggie is applying to college. There are only two outcomes for each application. It is either accepted or rejected. ---------------------------------------------- Each application she sends has a 0.70 probability of being accepted. If Maggie applies to 10 colleges, what is the probability that more than 8 of the applications will be accepted? Binomial Problem with n= 10 ; p = 0.7 P(8 < x <=10) = 1 - binomcdf(10,0.7,8) = 0.1493 ----------------------------- What is the expected value for "number of acceptances?" E(x) = np = 10*0.7 = 7 ========================== Cheers, Stan H.

Probability-and-statistics/270418: Billy has 10 books, but he only has space for 6 on his bookshelf. How many different arrangements (order does not matter) of the books can Billy make? 1 solutions Answer 198126 by stanbon(57246)   on 2010-02-16 17:58:54 (Show Source): You can put this solution on YOUR website! Billy has 10 books, but he only has space for 6 on his bookshelf. How many different arrangements (order does not matter) of the books can Billy make? Ans: 10P6 = 10!/4! = 10*9*8*7 = 151,200 =============== Cheers, Stan H.

Probability-and-statistics/270412: Using the following probability distribution for "Numbers of Cars sold" determine the expected value and standard deviation. Number of cars sold Probability 5 .15 8 .3 11 .33 17 .22 1 solutions Answer 198116 by stanbon(57246)   on 2010-02-16 17:29:51 (Show Source): You can put this solution on YOUR website! Using the following probability distribution for "Numbers of Cars sold" determine the expected value and standard deviation. Number of cars sold Probability 5 .15 8 .3 11 .33 17 .22 ------- Multiply each car sale number by its probability. Then add the products to find the expected value. E(x) = 10.2 ------- Note: E(x) = u ---------------------- To find the standard deviation: 1st: Form (x-u)^2 for each "car sales 2nd: Add those numbers: 78.6 3rd: Divide by N = sum of all the car sales:78.6/41 = 1.92 4th: The standard deviation is the square root of the result of the 3rd step. s = 1.386 ==================================== Cheers, Stan H.

Probability-and-statistics/270362: The length of time a domestic flight must wait between gate departure and takeoff taxi at BWI International Airport is approximately normally distributed with a mean of 22 minutes and a standard deviation of 7 minutes. a. what is the probability that a plane must wait between 18 and 24 minutes before taxiing for takeoff after leaving the gate? b. what is the probability a plane must wait between 22 and 30 minutes before taxiing for takeoff after leaving the gate? c. what is the probability a plane waits more than 12 minutes between gate departure takeoff taxi? d. what is the length of time such that only 5% of planes wait this long or longer before gate departure and taxiing down the runway? 1 solutions Answer 198115 by stanbon(57246)   on 2010-02-16 17:25:44 (Show Source): You can put this solution on YOUR website! The length of time a domestic flight must wait between gate departure and takeoff taxi at BWI International Airport is approximately normally distributed with a mean of 22 minutes and a standard deviation of 7 minutes. ------------------------------------------------ a. what is the probability that a plane must wait between 18 and 24 minutes before taxiing for takeoff after leaving the gate? z(18) = (18-22)/7 = -4/7 z(24) = (24-22)/7 = 2/7 P(18< x <24) = P(-4/7 < z < 2/7) = 0.3286 --------------------------------------------------- b. what is the probability a plane must wait between 22 and 30 minutes before taxiing for takeoff after leaving the gate? Ans: Same procedure as above. ----- c. what is the probability a plane waits more than 12 minutes between gate departure takeoff taxi? z(12) = (12-22)/7 = -10/7 = -1.4286 P(x > 12) = P(z > -1.4286) Note: z = -1.4286 is a point 1.4286 standard deviations to the left of the mean. You want the area under the normal curve that is to the right of -1.4286. Use Your z-chart or calculator, if you have one. Using a TI calculator I get normalcdf(-1.4286,100) = 0.9234 --- Comment: If these calculations are a mystery I would strongly suggest you use a sketch of the normal curve as you work each problem. That is so you can see where your x-values, z-values, and areas under the curve really are. You will better understand what is going on when you get the answers. ------------ d. what is the length of time such that only 5% of planes wait this long or longer before gate departure and taxiing down the runway? Ans: Find the z-value that corresponds to a left-tail of 5%. invNorm(0.5) = -1.645 Find the corresponding x-value: x = zs + u x = -1.645*7 + 22 x = 10.485 minutes ======================= Cheers, Stan H.

Age_Word_Problems/270161: Mr. Tan has two daughters. If their total age is 95, and his elder daughter is 1/3 of his age while his younger daughter is 1/4 of his age, how old is Mr. Tan? 1 solutions Answer 197946 by stanbon(57246)   on 2010-02-16 07:24:14 (Show Source): You can put this solution on YOUR website! Mr. Tan has two daughters. If their total age is 95, and his elder daughter is 1/3 of his age while his younger daughter is 1/4 of his age, how old is Mr. Tan? ------------ Equations: d + D = 95 d = (1/3)F D = (1/4)F --- Substitute and solve for "F": (1/3)F + (1/4)F = 95 (7/12)F = 95 F = (12/7)95 F = 162.86 yrs (Wow!) ============================ Cheers, Stan H.

Rational-functions/270165: Test whether the function is even, off or neither even nor odd: f(x)=7x^3+4x-2 1 solutions Answer 197945 by stanbon(57246)   on 2010-02-16 07:19:46 (Show Source): You can put this solution on YOUR website! Test whether the function is even, off or neither even nor odd: f(x)=7x^3+4x-2 f(-x) = -7x^2 - 4x -2 -f(-x) = 7x^3 + 4x + 2 ------ f(x) not equal to f(-x) so not even -- f(x) not equal to -f(-x) so not odd --- Ans: neither even nor odd ================================= Cheers, Stan H.

Word_Problems_With_Coins/270162: Maria has $1-coins and 50-centavos coins. If she has 3,600 coins in all, and amounting to $2250, how many coins of each kind does she have? 1 solutions Answer 197944 by stanbon(57246)   on 2010-02-16 07:17:08 (Show Source): You can put this solution on YOUR website! Maria has $1-coins and 50-centavos coins. If she has 3,600 coins in all, and amounting to $2250, how many coins of each kind does she have? ------------ One-variable solution: Equation: value + value = value 100x + 50(3600-x) = 225000 centavos --- 100x + 180000 - 50x = 225000 150x = 45000 ---- x = 300 (# of $1 coins) 3600-300 = 3300 (# of 50 centavos coins) ======================= Cheers, Stan H.

Geometry_Word_Problems/270163: A grass lawn is 56 meters long and 42 meters wide. Near the end of each corner there is a flower plot 6 meters by 4 meters. How many square meters of the lawn are covered with grass? 1 solutions Answer 197943 by stanbon(57246)   on 2010-02-16 07:12:42 (Show Source): You can put this solution on YOUR website! A grass lawn is 56 meters long and 42 meters wide. Near the end of each corner there is a flower plot 6 meters by 4 meters. How many square meters of the lawn are covered with grass? ----------------------------- Each flower area = 24 sq meters Total flower are = 4*24 = 96 sq meters ------------- Total rectangular area = 56*42 = 2352 sq meters ------------------------- Total grass area = 2352-96 = 2256 sq meters ============================================== Cheers, Stan H.

Rational-functions/270164: Find (fog)(x)and(gof)(x) and the domain of each: f(x)=sqrt(x), g(x)=sqrt(x) 1 solutions Answer 197942 by stanbon(57246)   on 2010-02-16 07:08:49 (Show Source): You can put this solution on YOUR website! Find (fog)(x)and(gof)(x) and the domain of each: f(x)=sqrt(x), g(x)=sqrt(x) ----------- (fog)(x) = f[g(x)] = f[sqrt(x)] = sqrt[sqrt(x)] = x^(1/4) ----- (gof)(x) follows the same pattern. ---------- Cheers, Stan H.

Probability-and-statistics/270107: In a random sample of 26 computers, the mean repair cost was $130 with a sample standard deviation of $36. Assume that the population is normally distributed. a. Find the margin of error for a 95% confidence interval. Round your answer to the nearest hundredths. b. Find a 95% confidence interval for the population mean . 1 solutions Answer 197941 by stanbon(57246)   on 2010-02-16 07:02:47 (Show Source): You can put this solution on YOUR website! In a random sample of 26 computers, the mean repair cost was $130 with a sample standard deviation of $36. Assume that the population is normally distributed. a. Find the margin of error for a 95% confidence interval. Round your answer to the nearest hundredths. E = 1.96 = 13.84 ---------------------- b. Find a 95% confidence interval for the population mean CI: 130-13.84 < u < 130+13.84 CI: 116.16 < u < 143.84 ========================== Cheers, Stan H.

Volume/270156: WOULD YOU PLEASE CHECK IF I HAVE THE CORRECT ANSWER TO MY QUESTION? I MAKE THE ANSWER TO BE 3,139,500 CUBIC METRES. The question? there are 3 Tunnels and they are each 50 kilometers long. 2 of the tunnels have a 7.6 metre diameter and the 3rd tunnel which is smaller has a 4.8 metre diameter, the tunnels are to be treated as a tube and I need to find the volume of rubble removed from this circular cross section tunnel. Also what is a circular cross section. Any help would be much appreciated. 1 solutions Answer 197940 by stanbon(57246)   on 2010-02-16 06:23:35 (Show Source): You can put this solution on YOUR website! The question? there are 3 Tunnels and they are each 50 kilometers long. 2 of the tunnels have a 7.6 metre diameter and the 3rd tunnel which is smaller has a 4.8 metre diameter, the tunnels are to be treated as a tube and I need to find the volume of rubble removed from this circular cross section tunnel. ---- The circular cross section does not have a volume; it has an area. The area = (pi)r^2 = (pi)(7.6/2)^2 = 45.36 sq meters for each of two tunnels. The volume of each of these tunnel would be 45.36*50,000 = 2268000 cu meters ================================= The area = (pi)(4.8/2)^2 = 18.10 sq meters for the other tunnel. The volume of the smaller tunnel would be 18.10*50,000 = 904778.68 cu meters ================================= ----------------------------------------------------- Also what is a circular cross section. Take a wooden telephone pole. Use a saw to cut it in half. The flat top of the bottom half of the pole is a circular cross section of the pole. The section has area but no volume. Only the pole has volume. -------------------------------------------------------- Cheers, Stan H.

Probability-and-statistics/270108: 1. Find the critical value zc necessary to form a confidence interval at 97% level of confidence 1 solutions Answer 197939 by stanbon(57246)   on 2010-02-16 06:10:17 (Show Source): You can put this solution on YOUR website! Ans: Each tail is (1/2)3% = 0.015 Using a TI-84 I get invNorm(0.985) = 2.1770 =========== Cheers, Stan H.

logarithm/270032: Change the following base 2 numbers to their decimal (base 10) equivalents. 1010 ______ 1 _____ 1011101 ________ 1010111 _______ 1 solutions Answer 197901 by stanbon(57246)   on 2010-02-15 22:17:12 (Show Source): You can put this solution on YOUR website! Change the following base 2 numbers to their decimal (base 10) equivalents. 1010 = 2+8=10 1011101 = 1+4+8+16+64 = 93 1010111 = 1+2+4+16+64 = 87_____ =============== Cheers, Stan H.

Expressions-with-variables/270066: Solve the equation. 6x^(-1/2) - 13x^(-1/4) +6 = 0 1 solutions Answer 197896 by stanbon(57246)   on 2010-02-15 22:08:30 (Show Source): You can put this solution on YOUR website! Solve the equation. 6x^(-1/2) - 13x^(-1/4) +6 = 0 ---- Let x^(-1/4) = w ------ You get the quadratic: 6w^2 - 13w + 6 = 0 --- 6w^2 -4w-9w + 6 = 0 ---- 2w(3w-2) -3(3w-2) = 0 Factor: (3w-2)(2w-3) = 0 ------- w= 2/3 or w = 3/2 ------------------------ Now solve for "x": If x = 2/3 x^(-1/4) = 2/3 x = (2/3)^(-4) x = 81/16 ------ If w = 3/2 x^(-1/4) = 3/2 x = (3/2)^-4 x = 16/81 ================ Cheers, Stan H.

Quadratic_Equations/270067: Combine like terms where possible. 8y^4 - 3y^4 1 solutions Answer 197885 by stanbon(57246)   on 2010-02-15 21:57:29 (Show Source): You can put this solution on YOUR website! Combine like terms where possible. 8y^4 - 3y^4 = 5y^4 ===================== cheers, Stan H.

Probability-and-statistics/270053: If we use values beyond our data set then a. the predicted value can be wrong b. the linear model may not fit the trend c. A & B 9. When we find a variable that is statically significant a. it allows us to build a model for estimating points b. it can referred to as a “driver” of the change c. A & B d. it is important based on Bohme’s theory of significance 10.A point estimate for 8 units is a. 8 b. 6.5 c. 7.36 11. A confidence interval for a sample average of 8 units a. 4.72 to 9.56 b. 4.03 to 8.97 c. -1.05 to 14.05 d. 1.15 to 14.05 12. A confidence interval for a individual point of 8 units a. 4.72 to 9.56 b. 4.03 to 8.97 c. -1.05 to 14.05 d. 1.15 to 14.05 1 solutions Answer 197880 by stanbon(57246)   on 2010-02-15 21:55:04 (Show Source): You can put this solution on YOUR website! The regression equation is Sales1 = - 0.86 + 0.920 Units Predictor Coef SE Coef T P Constant -0.864 3.265 -0.26 0.799 Units 0.9203 0.4219 2.18 0.066 S = 3.76362 R-Sq = 40.5% R-Sq(adj) = 32.0% Analysis of Variance Source DF SS MS F P Regression 1 67.40 67.40 4.76 0.066 Residual Error 7 99.15 14.16 Total 8 166.55 Unusual Observations Obs Units Sales1 Fit SE Fit Residual St Resid 1 12.4 17.10 10.55 2.55 6.55 2.37R 7 11.2 2.90 9.44 2.12 -6.54 -2.10R R denotes an observation with a large standardized residual. Predicted Values for New Observations New Obs Fit SE Fit 90% CI 90% PI 1 6.50 1.31 (4.03, 8.97) (-1.05, 14.05) Values of Predictors for New Observations New Obs Units 1 8.00 If we use values beyond our data set then a. the predicted value can be wrong b. the linear model may not fit the trend c. A & B Ans: c --------------------------------------------- 9. When we find a variable that is statically significant a. it allows us to build a model for estimating points b. it can referred to as a “driver” of the change c. A & B d. it is important based on Bohme’s theory of significance Ans: I would say "a" ---------------------------- 10.A point estimate for 8 units is a. 8 b. 6.5 c. 7.36 Ans: Sales(8)=-.86 = 0.92*8 = 6.5 ------------------------------------------------ 11. A confidence interval for a sample average of 8 units a. 4.72 to 9.56 b. 4.03 to 8.97 c. -1.05 to 14.05 d. 1.15 to 14.05 Ans: 4.03 to 8.97 is the answer for either question 11 or question 12 I would have to read some text material to pin it down. ------------------------------------ 12. A confidence interval for a individual point of 8 units a. 4.72 to 9.56 b. 4.03 to 8.97 c. -1.05 to 14.05 d. 1.15 to 14.05 Ans: See answer to question 11 Cheers, Stan H.