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Recent problems solved by 'stanbon'
stanbon answered: 57894 problems
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2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 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56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179 , 57180..57209 , 57210..57239 , 57240..57269 , 57270..57299 , 57300..57329 , 57330..57359 , 57360..57389 , 57390..57419 , 57420..57449 , 57450..57479 , 57480..57509 , 57510..57539 , 57540..57569 , 57570..57599 , 57600..57629 , 57630..57659 , 57660..57689 , 57690..57719 , 57720..57749 , 57750..57779 , 57780..57809 , 57810..57839 , 57840..57869 , 57870..57899, >>NextFinance/287057: a horse thief riding at 8mph has a 32 mile head start. the Posse in pursuit is riding at 10 mph. In how many hours will the thief be over taken?
1 solutions
Answer 208137 by stanbon(57967)   on 2010-03-30 19:50:16 (Show Source):
You can put this solution on YOUR website!a horse thief riding at 8mph has a 32 mile head start. the Posse in pursuit is riding at 10 mph. In how many hours will the thief be over taken?
----
Each hour the posse gains 2 miles on the horse thief.
---
Time to catch the thief = 32/2 = 16 hrs.
==========================================
Cheers,
Stan H.
|
percentage/287054: what is the percent decrease from 21 to 17.43
1 solutions
Answer 208135 by stanbon(57967) on 2010-03-30 19:41:48 (Show Source):
You can put this solution on YOUR website!what is the percent decrease from 21 to 17.43
-------------
Quantity decrease = 21-17.43 = 3.57
Percent decrease:: 3.57/21 = 0.17 = 17%
==========================================
Cheerd,
Stan H.
|
Graphs/287050: I hope I can explain this right! I will post the problem, then what I need to do with it.
-12x+y=28
I need to find the ordered pair of the y-intercept and the x-intercept.
I just do not get how to figure these out!!!
Thanks in advance!!
1 solutions
Answer 208134 by stanbon(57967) on 2010-03-30 19:38:51 (Show Source):
You can put this solution on YOUR website!-12x+y=28
I need to find the ordered pair of the y-intercept and the x-intercept
-----------------
To find the x-intercept, let y = zero; then solve for x:
-12x + 0 = 28
-12x = 28
x = -7/3
-----------
To find the y-intercept, let x = zero; then solve for y
0+y = 28
y = 28
--------------------------------
Cheers,
Stan H.
|
Money_Word_Problems/287049: susan is paid $3.00 per hour for a regular week of 40 hours.calculate her wages for a regular work week
1 solutions
Answer 208132 by stanbon(57967) on 2010-03-30 19:32:31 (Show Source):
You can put this solution on YOUR website!
susan is paid $3.00 per hour for a regular week of 40 hours.calculate her wages for a regular work week
----
wages for a week = 3*40 = $120
-----------------------------------
Cheers,
Stan H.
|
Square-cubic-other-roots/287046: Is this equation true or false? 28 – 4*sqrt(2) = 24*sqrt(2). Explain why.
1 solutions
Answer 208131 by stanbon(57967) on 2010-03-30 19:27:22 (Show Source):
You can put this solution on YOUR website!Is this equation true or false? 28 – 4*sqrt(2) = 24*sqrt(2). Explain why.
-------------------------
28 -4sqrt(2) ? 24sqrt(2)
28-4sqrt(2) is approximately:: 22.3431
24*sqrt(2) is approximately: 33.9411
-----------------------------------
Cheers,
Stan.
|
Probability-and-statistics/286919: 1000 tickets are sold @ $1. One prize is awarded $1,000. What is the fair price of the ticket?
1 solutions
Answer 208130 by stanbon(57967) on 2010-03-30 19:20:09 (Show Source):
You can put this solution on YOUR website!1000 tickets are sold @ $1. One prize is awarded $1,000. What is the fair price of the ticket?
----------------------------
Random Numbers winning values: $999, -$1
Corresponding Probabilities::: (1/1000), (999/1000)
--------------------------------------------------------
Expected Winnings = 999(1/1000)+(999/1000)(-1)
---
E(x) = (999/1000)-(999/1000)
E(x) = 0
-----------------
$1 is a fair price.
========================
Cheers,
Stan H.
|
Graphs/286887: When you get the vertex of a parabola, How do you get the other two points to graph it?
1 solutions
Answer 208038 by stanbon(57967) on 2010-03-30 13:09:05 (Show Source):
You can put this solution on YOUR website!When you get the vertex of a parabola, How do you get the other two points to graph it?
----------------
one additional point is all you need IF you can see
from the form that the parabola opens up, or down, or
to the right, or to the left.
----------------
Cheers,
Stan H.
|
Sequences-and-series/286880: what are the last three terms of the expansion (a-b)7
1 solutions
Answer 208036 by stanbon(57967) on 2010-03-30 13:06:47 (Show Source):
You can put this solution on YOUR website!what are the last three terms of the expansion (a-b)7
--------
6th term: 7C2(a)^2(-b)^5 = -21a^2b^5
---
7th term: 7C1(a)^1(-b)^6 = 7ab^6
---
8th term: 7C0(a)^0(-b)^7 = -b^7
===================================
Cheers,
Stan H.
|
Probability-and-statistics/286871: 10.60
interpret it.
Heart Rate Before and After Class Break
Person Before After
1 60 62
2 70 76
3 77 78
4 80 83
5 82 82
6 82 83
7 41 66
8 65 63
9 58 60
10 50 54
11 82 93
12 56 55
13 71 67
14 67 68
15 66 75
16 70 64
17 69 66
18 64 69
19 70 73
20 59 58
21 62 65
22 66 68
23 81 77
24 56 57
25 64 62
26 78 79
27 75 74
28 66 67
29 59 63
30 98 82
What is the correct tool to use in excel through tools>data analysis
1 solutions
Answer 208034 by stanbon(57967) on 2010-03-30 13:01:45 (Show Source):
You can put this solution on YOUR website!You might try a box plot on each of the data sets.
-
You could run a t-test on the (before-after) data.
using Ho: u(difference) = 0
Ha: u(difference) is not zero.
--------------------------------
These data pairs are dependent because each
pair is a before/after measure for a person.
So, do not use a 2-sample t-test; do not ues
a 2-sample z-test.
--------------------------------
Cheers,
Stan H.
|
Miscellaneous_Word_Problems/286864: Use a(t) = -32 ft/sec2 as the acceleration due to gravity. (Neglect air resistance.)
A ball is thrown vertically upward from a height of 5 feet with an initial velocity of 46 feet per second. How high will the ball go? (Round your answer to two decimal places.)
1 solutions
Answer 208019 by stanbon(57967) on 2010-03-30 11:59:27 (Show Source):
You can put this solution on YOUR website!Use a(t) = -32 ft/sec2 as the acceleration due to gravity. (Neglect air resistance.)
A ball is thrown vertically upward from a height of 5 feet with an initial velocity of 46 feet per second. How high will the ball go? (Round your answer to two decimal places.)
------------------
h(t) = -16t^2 + 46t + 5
---
Top of the arc is the vertex.
Vertex occurs when x = -b/2a = -46/(-32) = 23/16 seconds.
----
Height at the vertex = h(23/16) = -16(23/16)^2+46(23/16)+5 = 38.06 ft.
=======================
Cheers,
Stan H.
|
Probability-and-statistics/286822: There are 10 cars and 5 trucks in a dealer's showroom. 1 of the cars is black and 2 of the trucks are black. If a vehicle is chosen at random, what is the probability that it is black, given that it is a car?
1 solutions
Answer 208018 by stanbon(57967) on 2010-03-30 11:51:30 (Show Source):
You can put this solution on YOUR website!There are 10 cars and 5 trucks in a dealer's showroom. 1 of the cars is black and 2 of the trucks are black. If a vehicle is chosen at random, what is the probability that it is black, given that it is a car?
-------------
P(b|c) = P(b and c)/P(c) = [1/15][10/15] = 1/10
--------------------------------------------------
Cheers,
Stan H.
|
Rational-functions/286758: Let f(x)= 2x^3-6x^2+2x+11 / x^2-4x+5. This is a function of x
A) Find the natural domain of f
B)Find the standard form of f
C) Find any straight line asymptotes of the graph y=f(x)
Please show working..
Thanks!
1 solutions
Answer 207960 by stanbon(57967) on 2010-03-30 08:18:21 (Show Source):
You can put this solution on YOUR website!Let f(x)= 2x^3-6x^2+2x+11 / x^2-4x+5. This is a function of x
Rewrite in factored form: y = 2x^3-6x^2+2x+11/[(x-5)(x+1)]
-----------------------------
A) Find the natural domain of f
Domain: All Real Numbers except x = 5 and x = -1
--------------------------------------
B) Find the standard form of f
Not sure what you mean by that. Maybe they want you to
divide the numerator by the denominator so you can see
a slant asymptote.
-----------------------------
C) Find any straight line asymptotes of the graph y=f(x)
Vertical at x = 5 and at x = -1
Horizontal: none because degree of num > degree of denom.
Slant: possibly
================
Cheers,
Stan H.
|
Quadratic-relations-and-conic-sections/286789: can you help me and thankn you in advanced I just can't ge t it
find x-andy- intercept of f(x)=(x+4)(2x-1)(x-1)and last can you
write the equation of the line with a slope slope of 2/3 and y-intercept of 1( write in intercept form. thank you again
1 solutions
Answer 207958 by stanbon(57967) on 2010-03-30 08:08:39 (Show Source):
You can put this solution on YOUR website!find x-and y- intercept of f(x)=(x+4)(2x-1)(x-1)
-----------
x-intercept:
Let y = 0 and solve for "x":
(x+4)(2x-1)(x-1) = 0
x = 4 or 1/2 or 1
Those are the x-intercepts.
------------------------------------
y-intercept:
Let x = 0 and solve for "y":
y = (0+4)(0-1)(0-1) = 4
that is the y-intercept
--------------------------------------
and last can you
write the equation of the line with a slope slope of 2/3 and y-intercept of 1( write in intercept form.
---
Slope = 2/3
intercept = 1
Equation:
y = (2/3)x + 1
=======================
Cheers,
Stan H.
|
Quadratic-relations-and-conic-sections/286788: If (x) =4x+3,Which of the following is true and why:
1.f(x+h)=4x+3+h
2.f(x+h)=4x+4h+3
3.f(x+h)4x+4h+6
can you tell me I'll appreciate thank you for this question and the previous one
1 solutions
Answer 207956 by stanbon(57967) on 2010-03-30 08:00:46 (Show Source):
You can put this solution on YOUR website!If (x) =4x+3,Which of the following is true and why:
Substitute "x+h" in place of "x" to get:
f(x+h) = 4(x+h)+3 = 4x+4h+3
----------------------------------
1.f(x+h)=4x+3+h
2.f(x+h)=4x+4h+3
3.f(x+h)4x+4h+6
---------------------
Ans: 2
Cheers,
Stan H.
|
Money_Word_Problems/286782: if interest is compounded annually how much is $1000 worth in 8 years at 8%. indicate the formula also. please help im not sure which formula to use. thanks
1 solutions
Answer 207954 by stanbon(57967) on 2010-03-30 07:53:03 (Show Source):
You can put this solution on YOUR website!if interest is compounded annually how much is $1000 worth in 8 years at 8%. indicate the formula also. please help im not sure which formula to use. thanks
-------------------------------
A(t) = P(1+(r/n))^(nt)
----
A(8) = 1000(1+(0.08/1))^(1*8)
---
A(8) = 1000(1.08)^8
A(8) = 1000*1.85093
A(8) = $1850.93
====================
Cheers,
Stan H.
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Probability-and-statistics/286784: In a sample of 500 college students fifty percent of all college students attend schools within 50 miles of their homes. The probability that the population proportion will be between 0.45 and 0.55 is?
1 solutions
Answer 207953 by stanbon(57967) on 2010-03-30 07:48:48 (Show Source):
You can put this solution on YOUR website!In a sample of 500 college students fifty percent of all college students attend schools within 50 miles of their homes. The probability that the population proportion will be between 0.45 and 0.55 is?
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z(0.45) = (0.45-0.5)/sqrt(0.5*0.5/500) = -2.2361
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z(0.55) = 0.55-0.5)/sqrt(0.5*0.5/500) = 2.2361
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P(0.45 < p < 0.55) = P(-2.2361 < z < 2.2361) = 0.9747
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Cheers,
Stan H.
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Probability-and-statistics/286759: Suppose a student taking a multiple choice test has to guess on three answers. Assume there are five choices for each question (a, b, c, d, e) with only one being correct. Construct a probability distribution table for the possible outcomes.
1 solutions
Answer 207952 by stanbon(57967) on 2010-03-30 07:43:29 (Show Source):
You can put this solution on YOUR website!Suppose a student taking a multiple choice test has to guess on three answers. Assume there are five choices for each question (a, b, c, d, e) with only one being correct. Construct a probability distribution table for the possible outcomes.
Binomial Problem with n = 3 ; p = 1/5 ; q = 4/5
P(x=0)= 3C0(1/5)^0(4/5)^3 = 0.512
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P(x=1)=3C1(1/5)^1(4/5)2) = 0.384
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P(x=2)=3C2(1/5)^2(4/5) = 0.096
etc.
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Cheers,
Stan H.
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Probability-and-statistics/286569: Use normal approximation to estimate the probability of getting less than 48 girls in 100 births. Assume that boys and girls are equally likely.
1 solutions
Answer 207951 by stanbon(57967) on 2010-03-30 07:21:42 (Show Source):
You can put this solution on YOUR website!Use normal approximation to estimate the probability of getting less than 48 girls in 100 births. Assume that boys and girls are equally likely.
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binomial P(0<= x <=48)
normal appox = P(-0.5<= x <=48.5)
mean = np = 100(1/2) = 50
std = sqrt(npq) = sqrt(50(1/2)) = sqrt(25) = 5
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z(-0.5) = (-0.5-50)/5 = -10.1
z(48.5) = (48.5-50)/5 = -0.3
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P(-10.1<= z <=-.3) = 0.3821
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Cheers,
Stan H.
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Probability-and-statistics/286557: An airline company is considering a new policy of booking as many as 204 persons on an airplane that can seat only 190.5. (Past studies have revealed that only 86% of the booked passengers actually arrive for the flight.) Estimate the probability that if the company books 204 persons. not enough seats will be available.
1 solutions
Answer 207950 by stanbon(57967) on 2010-03-30 07:13:45 (Show Source):
You can put this solution on YOUR website! An airline company is considering a new policy of booking as many as 204 persons on an airplane that can seat only 190.5. (Past studies have revealed that only 86% of the booked passengers actually arrive for the flight.) Estimate the probability that if the company books 204 persons. not enough seats will be available.
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Binomial Problem with n = 204 ; p = 0.86
P(191 <= x <= 204) = 1 - binomcdf(204,0.86,190) = 0.0004664
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Cheers,
Stan H.
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Probability-and-statistics/286607: The probability of a table-tennis ball being defective is 1/10. About how many balls would be defective in a case of 725 table-tennis balls
1 solutions
Answer 207949 by stanbon(57967) on 2010-03-30 07:08:32 (Show Source):
You can put this solution on YOUR website!The probability of a table-tennis ball being defective is 1/10. About how many balls would be defective in a case of 725 table-tennis balls
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average # = np = 725(1/10) = 72.5
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Cheers,
Stan H.
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Probability-and-statistics/286647: When you draw a sample from a normal distribution, what can you conclude about the sample distribution?
1 solutions
Answer 207948 by stanbon(57967) on 2010-03-30 07:06:23 (Show Source):
You can put this solution on YOUR website!When you draw a sample from a normal distribution, what can you conclude about the sample distribution?
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According to the Central Limit Theorem:
1. The mean of the sample means = the mean of the population
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2. The std of the sample means = (std of pop)/sqrt(sample size)
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Cheers,
Stan H.
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Probability-and-statistics/286770: A stats practitioner wishes to test the following hypothesis H0:μ = 600 against H1:μ<600. A sample of 50 observations yielded the statistics: mean = 585 and standard deviation = 45. The test statistic of a test to determine there is enough evidence at the 10% signigicance level to reject the null hypothesis is?
1 solutions
Answer 207947 by stanbon(57967) on 2010-03-30 07:02:50 (Show Source):
You can put this solution on YOUR website!A stats practitioner wishes to test the following hypothesis
H0:μ = 600 against
H1:μ<600.
A sample of 50 observations yielded the statistics: mean = 585 and standard deviation = 45. The test statistic of a test to determine there is enough evidence at the 10% signigicance level to reject the null hypothesis is?
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t(585) = (585-600)/[45/sqrt(50)] = -2.3570
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Cheers,
Stan H.
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Graphs/286774: Find the slope of the line that goes through the given points....
(3,-3), (3,8)
1 solutions
Answer 207946 by stanbon(57967) on 2010-03-30 06:59:27 (Show Source):
You can put this solution on YOUR website! Find the slope of the line that goes through the given points....
(3,-3), (3,8)
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Note: Since both x-coordinates are the same
the slope will be "undefined".
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slope = (8--3)/(3-3) = 11/0 which is undefined.
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Cheers,
Stan H.
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Probability-and-statistics/286771: A stats practitioner formulated the following hypothesis: H0:μ = 200 against H1:<200 and learned that the mean = 190 n = 9 and σ = 50. The p-value of the test is?
1 solutions
Answer 207945 by stanbon(57967) on 2010-03-30 06:57:11 (Show Source):
You can put this solution on YOUR website!A stats practitioner formulated the following hypothesis:
H0: μ = 200 against
H1: u <200
and learned that the mean = 190 n = 9 and σ = 50. The p-value of the test is?
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Determine the test statistic:
t(190) = (190-200)/[50/sqrt(9)] = -0.6
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p-value = P(t<-0.6 when df = 8) = 0.2826
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I used a TI calculator command: tcdf(-100,-0.6,8) = 0.2826
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Cheers,
Stan H.
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Probability-and-statistics/286772: Consider an infinite population with a mean of 160 and a standard deviation of 25. A random sample of size 64 is taken from this population. The standard deviation of the sample mean equals?
1 solutions
Answer 207943 by stanbon(57967) on 2010-03-30 06:50:08 (Show Source):
You can put this solution on YOUR website!Consider an infinite population with a mean of 160 and a standard deviation of 25. A random sample of size 64 is taken from this population. The standard deviation of the sample mean equals?
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s = 25/sqrt(64) = 25/8 = 3.125
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Cheers,
Stan H.
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Probability-and-statistics/286773: A random sample of 30 women drank an average of 15 cups of coffee per week, with the sample standard deviation equals to 3 cups. A upper limit of an approximate confidence interval with 95% of the population avg cup drunk is?
1 solutions
Answer 207942 by stanbon(57967) on 2010-03-30 06:47:51 (Show Source):
You can put this solution on YOUR website!A random sample of 30 women drank an average of 15 cups of coffee per week, with the sample standard deviation equals to 3 cups. A upper limit of an approximate confidence interval with 95% of the population avg cup drunk is?
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sample mean = 15
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standard error = E = t*s/sqrt(n)
E = invT(97.5 with df = 29)(3/sqrt(30)] = 2.0452*3/sqrt(30) = 1.1202
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95% CI: 15-1.1202 < u < 15+1.1202
95% CI: 13.880 < u < 16.120
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Cheers,
Stan H.
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Probability-and-statistics/286710: 2. A department store manager claims that at least 45% of persons who visited this store make a purchase. In a sample of 400 persons who visited the store 150 made a purchase. Test the manager’s claim at the 3% significance level.
a. State the null and alternate hypothesis.
b. Determine the rejection region for the decision rule.
c. Which equation listed below would you use?
d. Using the statistical calculator or manual calculation what is the observed statistic and what is your decision regarding the null hypothesis. Provide a one sentence answer.
1 solutions
Answer 207934 by stanbon(57967) on 2010-03-29 22:54:20 (Show Source):
You can put this solution on YOUR website!A department store manager claims that at least 45% of persons who visited this store make a purchase. In a sample of 400 persons who visited the store 150 made a purchase. Test the manager’s claim at the 3% significance level.
a. State the null and alternate hypothesis.
Ho: p >= 0.45
Ha: p < 0.45
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b. Determine the rejection region for the decision rule.
invNorm(0.97) = -1.8808
Reject region is all z < -1.8808
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c. Which equation listed below would you use?
Equations were not listed.
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d. Using the statistical calculator or manual calculation what is the observed statistic and what is your decision regarding the null hypothesis.
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stat test: z(150/400) = (0.375-0.45)/sqrt[0.45*0.55/400] = -3.0151
Provide a one sentence answer.
Since the test stat is in the rejection region, reject Ho.
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Cheers,
Stan H.
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Radicals/286715: h=-16t+vt+s A ball is tossed into the air from a height of 10 feet with an initial velocity of 12 feet /sec. Find the time t(in seconds) for the object to reach the ground.
#2 a baseball player releases a baseball at a height of 6 feet with an initial velocity of 46 feet/sec. find the time(in seconds) for the ball to reach the ground.
1 solutions
Answer 207925 by stanbon(57967) on 2010-03-29 22:09:12 (Show Source):
You can put this solution on YOUR website!h=-16t+vt+s A ball is tossed into the air from a height of 10 feet with an initial velocity of 12 feet /sec. Find the time t(in seconds) for the object to reach the ground.
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h(t) = -16t^2 + 12t + 10
Solve: -16t^2 + 12t + 10 = 0
Modify: -8t^2 + 6t + 5 = 0
-8t^2 + 10t - 4t + 5 = 0
-2t(4t-5)-(4t-5) = 0
(4t-5)(-2t-1) = 0
Positive solution:
t = 5/4 second
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#2 a baseball player releases a baseball at a height of 6 feet with an initial velocity of 46 feet/sec. find the time(in seconds) for the ball to reach the ground.
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Solve:: -16t^2 + 46t + 6 = 0
8t^2 - 23t -3 = 0
8t^2 - 24t + t - 3 = 0
8t(t-3) + t-3 = 0
(t-3)(8t+1) = 0
Positive solution:
t = 3 seconds
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Cheers,
Stan H.
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Probability-and-statistics/286706: 1. The manager of a driving school claims that the mean time taken to learn how to drive a car is 8 hours or less for all new drivers. A sample of 16 new drivers showed that the mean time taken by them to learn how to drive the car is 9.5 hours with a standard deviation of 1.5 hours. Test the manager’s claim at the 1% significance level.
a. Select the null and alternate hypothesis.
b. Determine the critical values of the test statistic.
c. What equation/formula would you use?
d. Using the statistical calculator or manual calculation what is the observed statistic and what is your decision regarding the null hypothesis. Provide a one sentence answer.
1 solutions
Answer 207923 by stanbon(57967) on 2010-03-29 21:57:17 (Show Source):
You can put this solution on YOUR website!1. The manager of a driving school claims that the mean time taken to learn how to drive a car is 8 hours or less for all new drivers. A sample of 16 new drivers showed that the mean time taken by them to learn how to drive the car is 9.5 hours with a standard deviation of 1.5 hours. Test the manager’s claim at the 1% significance level.
a. Select the null and alternate hypothesis.
Ho: u <= 8 hrs
Ha: u >= 8 hrs
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b. Determine the critical values of the test statistic.
invT(0.99 with df = 15) = 2.6042
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c. What equation/formula would you use?
t(9.5) = (9.5-8)/[1.5/sqrt(16)] = 4
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d. Using the statistical calculator or manual calculation what is the observed statistic and what is your decision regarding the null hypothesis. Provide a one sentence answer.
Conclusion: Since the test statistic is in the reject interval,
reject Ho.
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Cheers,
Stan H.
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