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Recent problems solved by 'stanbon'

stanbon answered: 57158 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 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56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179, >>Next

Angles/323083: Two angles form a linear pair. The measure of one angle is seven less than twice the measure of the other angle. what are the measures of both the angles? 1 solutions Answer 231295 by stanbon(57226)   on 2010-07-16 22:13:30 (Show Source): You can put this solution on YOUR website! Two angles form a linear pair. x + y = 180 --------------------- The measure of one angle is seven less than twice the measure of the other angle. x = 2y-7 --------------------- what are the measures of both the angles? --- Substitute for "x" and solve for "y": 2y-7 + y = 180 3y = 187 y = 62 1/3 ------------- Since x+y = 180, x = 180-62 1/3 = 117 2/3 ======================= Cheers, Stan H.

Square-cubic-other-roots/323082: (-3√5)^2 1 solutions Answer 231290 by stanbon(57226)   on 2010-07-16 22:04:07 (Show Source): You can put this solution on YOUR website! (-3√5)^2 --- = (-3sqrt(5))(-3sqrt(5)) --- = 9*5 --- = 45 ========= Cheers, Stan H.

Probability-and-statistics/323068: find the indicated area under the standard normal curve. can someone check me and see if these are correct? Between z=0 and 1.28= .40 To the right ofz=2.40= .0081 between z=1.23 and z=1.90= .0806 between z=0 and z=-2.12= -.4829 to the left of z=-0.46=.3227 between z=-1.45 and z=1.87=.8957 1 solutions Answer 231287 by stanbon(57226)   on 2010-07-16 21:47:00 (Show Source): You can put this solution on YOUR website! They all look good. Cheers, Stan H.

Linear-equations/323010: 3r-5s=21 5r+3s=33 solve by elimination method 1 solutions Answer 231241 by stanbon(57226)   on 2010-07-16 16:38:00 (Show Source): You can put this solution on YOUR website! 3r-5s=21 5r+3s=33 solve by elimination method ------------------- Multiply 1st by 5 Multiply 2nd by 3 ----------- 15r - 25s = 105 15r + 9s = 99 ----- Subtract 1st from 2nd to get: 34s = -6 s = -3/17 ================== Substitute into 3r-5s = 21 to solve for r: 3r -5(-3/17) = 21 3r = 21 -15/17 r = 7 - 5/17 r = 114/17 =================== Cheers, Stan H.

Geometric_formulas/323017: which type of dilation is determined by a scale factor of 1/3? 1 solutions Answer 231234 by stanbon(57226)   on 2010-07-16 16:27:05 (Show Source): You can put this solution on YOUR website! which type of dilation is determined by a scale factor of 1/3? ------------------------ The y-values will only be (1/3) as high as they would be if the (1/3) factor was not there. So the curve will be flattened because of the 1/3 factor. Not sure what that is called, but that is what happens. ======================== Cheers, Stan H. ==================

Linear-equations/323014: find the domain 8(x)=5/1-3x 1 solutions Answer 231231 by stanbon(57226)   on 2010-07-16 16:22:01 (Show Source): You can put this solution on YOUR website! find the domain 8(x)=5/1-3x ----- Your notation is confusing. ---- But it looks like 1-3x cannot be zero Solve: 1-3x = 0 x = 1/3 ---------------- Domain: All Real numbers except x = 1/3 ======================== Cheers, Stan H. ========================

Equations/323015: 5(2x - 7) = 33 - 3(6x + 4) 1 solutions Answer 231228 by stanbon(57226)   on 2010-07-16 16:17:39 (Show Source): You can put this solution on YOUR website! 5(2x - 7) = 33 - 3(6x + 4) --- 10x - 35 = 33 - 18x -12 --- 10x - 35 = 21 - 18x --- 28x = 56 --- x = 2 ========= Cheers, Stan H.

Radicals/323020: Please help me with this problem. 2(sqrt(128) - sqrt(18) + (4)sqrt(32). Thank you. 1 solutions Answer 231226 by stanbon(57226)   on 2010-07-16 16:14:20 (Show Source): You can put this solution on YOUR website! sqrt(128) - sqrt(18) + (4)sqrt(32) ------ sqrt(64*2) - sqrt(9*2) + 4*sqrt(16*2) ------ = 8sqrt(2) - 3sqrt(2) + 4*4sqrt(2) --- = [8-3+16]sqrt(2) --- = 21sqrt(2) ==================== Cheers, Stan H ====================

Probability-and-statistics/322995: Insurance companies have determined that US males between the ages of 16 and 24 drive an average of 10,718 miles each year with a standard deviation of 3763 miles. Assume the datea is normally distributed. For a randomly selected male in that age group, find the probability that he drives less than 12,000 miles per year...i have a formula that i used...i'm just confused because some questions say less than...and some say more than...just wanted to ensure i did this correctly: (12000-10718)/3763=.3407 1 solutions Answer 231208 by stanbon(57226)   on 2010-07-16 13:49:47 (Show Source): You can put this solution on YOUR website! Insurance companies have determined that US males between the ages of 16 and 24 drive an average of 10,718 miles each year with a standard deviation of 3763 miles. Assume the datea is normally distributed. For a randomly selected male in that age group, per year...i have a formula that i used...i'm just confused because some questions say less than...and some say more than...just wanted to ensure i did this correctly: (12000-10718)/3763=.3407 ---- Good. That is the z-value of 12000 --- "Find the probability that he drives less than 12,000 miles." ---- Then P(x < 12000) = P(z < 0.3407) = normalcdf(-1000,0.3407) = 0.6333 ======================= Cheers, Stan H.

Graphs/322997: Solve using elimination 7x + 3y = -4 6x + 7y = 32 1 solutions Answer 231207 by stanbon(57226)   on 2010-07-16 13:43:28 (Show Source): You can put this solution on YOUR website! Solve using elimination 7x + 3y = -4 6x + 7y = 32 ==================== multiply thru 1st by 7 multiply thru 2nd by 3 ------- 49x + 21y = -12 18x + 21y = 96 -------- Subtract 2nd from 1st and solve for "x": 31x = -108 x = -108/31 -------------------- Substitute into 6x + 7y = 32 to solve for "y": 6(108/31) + 7y = 32 7y = 32 - 6(-108/31) 7y = 52.9032 y = 1640/217 ======================= Cheers, Stan H.

Probability-and-statistics/322980: I was wondering if I could get a little help with this question. Which of these situations could be analyzed with a one-way analysis of variance? A) The relationship between gender (male or female) and opinion about the death penalty (favor, oppose, uncertain) B) A comparison of four different age groups with regard to mean hours of watching television per day C) The relationship between weight and height for 12-year old girls D) A comparison of four different age groups with regard to proportion that opposes legalization of marijuana Thanks, Dave 1 solutions Answer 231192 by stanbon(57226)   on 2010-07-16 12:13:57 (Show Source): You can put this solution on YOUR website! Which of these situations could be analyzed with a one-way analysis of variance? --- Comment: Although ANOVA sounds like a test of variances, it is not. It is a test of means. ---- Ans: B Cheers, Stan H. -------------------- A) The relationship between gender (male or female) and opinion about the death penalty (favor, oppose, uncertain) B) A comparison of four different age groups with regard to mean hours of watching television per day C) The relationship between weight and height for 12-year old girls D) A comparison of four different age groups with regard to proportion that opposes legalization of marijuana

Probability-and-statistics/322989: please help...i tried to work the problem with the formula given z=value-mean/standard deviation According to a survey conducted by television advertisers, the average adult American watches an average of 6.98 hours of television per day. The data is normally distributed with a standard devieation of 3.80 hours. Find the probability that a randomly selected person watches more than 8.00 hours of television a day. 8.00-6.98/3.80=6.163...is this correct? 1 solutions Answer 231191 by stanbon(57226)   on 2010-07-16 12:11:13 (Show Source): You can put this solution on YOUR website! work the problem with the formula given z=value-mean/standard deviation According to a survey conducted by television advertisers, the average adult American watches an average of 6.98 hours of television per day. The data is normally distributed with a standard devieation of 3.80 hours. Find the probability that a randomly selected person watches more than 8.00 hours of television a day. 8.00-6.98/3.80=6.163...is this correct? --------------------- Note: Your Formula is wrong; you always need parentheses in the numerator. It should be z-value = (value-mean)/standard deviation ----- z(8) = (8-6.93)/3.8 = 1.02/3.8 = 0.2684 ======================== Cheers, Stan H.

Travel_Word_Problems/322987: A car and a bus leave town at 1 P.M. and head for a town 300 mi away. The rate of the car is twice the rate of the bus. The car arrives 5 h ahead of the bus. Find the rate of the car. 1 solutions Answer 231189 by stanbon(57226)   on 2010-07-16 12:04:41 (Show Source): You can put this solution on YOUR website! A car and a bus leave town at 1 P.M. and head for a town 300 mi away. The rate of the car is twice the rate of the bus. The car arrives 5 h ahead of the bus. Find the rate of the car. --- Car DATA: distance = 300 mi ; rate = 2x mph ; time = d/r = 300/(2x) hrs ------------- Bus DATA: distance = 300 mi ; rate = x mph ; time = d/r = 300/x hrs -------------------------------------------------- Equation: Bus time - Car time = 5 hrs. 300/x - 300/(2x) = 5 600 - 300 = 10x 10x = 300 x = 30 mph 2x = 60 mph (rate of the car) ================================== Cheers, Stan H.

Quadratic_Equations/322982: Use the quadratic formula to solve the equation. 2x^2 - 5x = -9 Type a solution set using radicals as needed. Express complex terms in terms of i. Use integers of fractions for any numbers in the expression. Use comma to separate answers. Thank you so much!!! 1 solutions Answer 231187 by stanbon(57226)   on 2010-07-16 11:59:41 (Show Source): You can put this solution on YOUR website! 2x^2 - 5x = -9 --- 2x^2 - 5x + 9 = 0 --- x = [5 +- sqrt(25-4*2*9)]/4 --- x = [5 +- sqrt(-47)]/4 --- x = [5+isqrt(47)]4 or x = [5-isqrt(47)]/4 ============================================= Cheers, Stan H.

Probability-and-statistics/322948: The diameters of oranges in a certain orchard are normally distributed with a mean of 7.10 inches and a standard deviation of 0.50 inches. Show all work. (A) What percentage of the oranges in this orchard have diameters less than 6.8 inches? (B) What percentage of the oranges in this orchard are larger than 7.00 inches? (C) A random sample of 100 oranges is gathered and the mean diameter obtained was 7.00. If another sample of 100 is taken, what is the probability that its sample mean will be greater than 7.00 inches? (D) Why is the z-score used in answering (A), (B), and (C)? (E) Why is the formula for z used in (C) different from that used in (A) and (B)? (Points :10) 1 solutions Answer 231183 by stanbon(57226)   on 2010-07-16 11:55:26 (Show Source): You can put this solution on YOUR website! The diameters of oranges in a certain orchard are normally distributed with a mean of 7.10 inches and a standard deviation of 0.50 inches. Show all work. (A) What percentage of the oranges in this orchard have diameters less than 6.8 inches? --- z(6.8) = (6.8-7.1)/0.5 = -0.6 --- P(x < 6.8) = P(z < -0.6) = 27.43% ============================================= (B) What percentage of the oranges in this orchard are larger than 7.00 inches? z(7) = (7-7.1)/0.5 = -0.2 --- P(x > 7) = P(z > -0.2) = 57.93% ---------------------------------------- (C) A random sample of 100 oranges is gathered and the mean diameter obtained was 7.00. If another sample of 100 is taken, what is the probability that its sample mean will be greater than 7.00 inches? -- z(7) = (7-7.1)/[0.5/sqrt(100)] = -2 P(x-bar > 7) = P(z > -2) = 0.9772 --------------- (D) Why is the z-score used in answering (A), (B), and (C)? I'll leave that to you. Some texts would say you should use a t-score on problem C. ------------------- (E) Why is the formula for z used in (C) different from that used in (A) and (B)? The Central limit theorem say the standard deviation for a sample of size n = sigma/sqrt(n), where sigma is the standard deviation used in part A an ============================== Cheers, Stan H.

Polynomials-and-rational-expressions/322945: The instructions are to perform using scientic notation and the complete the operation leaving the answer in scientic notation. The problem is (100000)(12000)/(.006)(20). I got 1.2E9/1.2E-1 and simplified to 1E1 and it was incorrect. Can you help me see why this is incorrect? 1 solutions Answer 231173 by stanbon(57226)   on 2010-07-16 10:28:47 (Show Source): You can put this solution on YOUR website! I get 1E10 ================ Cheers, Stan H.

Average/322907: IF THE AVERAGE OF THREE NUMBERS IS V IF ONE OF THE NUMBERS IS Z AND ANOTHER IS Y WHAT IS THE REMAINING NUMBER 1 solutions Answer 231172 by stanbon(57226)   on 2010-07-16 10:25:31 (Show Source): You can put this solution on YOUR website! IF THE AVERAGE OF THREE NUMBERS IS V IF ONE OF THE NUMBERS IS Z AND ANOTHER IS Y WHAT IS THE REMAINING NUMBER ------------------------- Let the remaining number be "x". ---- Equation: (x + Y + Z)/3 = V ---- x + Y + Z = 3V x = 3V-Y-Z ================ Cheers, Stan H.

Polynomials-and-rational-expressions/322849: If a vendor charges p dollars each for rugby shirts, then he expects to sell 2000-100p shirts at a tournament. a) Find the polynomial R(p) that represents the total revenue when the shirts are p dollars each. b)Find R(5), R(10), and R(20) 1 solutions Answer 231131 by stanbon(57226)   on 2010-07-15 21:21:26 (Show Source): You can put this solution on YOUR website! If a vendor charges p dollars each for rugby shirts, then he expects to sell 2000-100p shirts at a tournament. a) Find the polynomial R(p) that represents the total revenue when the shirts are p dollars each. R(p) = p(2000-100p) ---------------------------- b)Find R(5) = 5(2000-500) = 7500 R(10)= 10(2000-1000) = 10000 R(20)= 20(2000-2000) = 0 ============================== Cheers, Stan H.

real-numbers/322854: please help me solve for x by using the quadratic formula 2/3x^2+1/4x=3 Thank you! 1 solutions Answer 231130 by stanbon(57226)   on 2010-07-15 21:17:14 (Show Source): You can put this solution on YOUR website! solve for x by using the quadratic formula 2/3x^2+1/4x=3 ---- Multiply thru by 12 to get rid of the fractions: --- 8x^2 + 3x - 36 = 0 --- x = [-3 +- srt(9 -4*8*-36)]/16 --- x = [-3 +- sqrt(1161)/16 --- x = 1.9421 or x = -2.3171 =============================== Cheers, Stan H.

Probability-and-statistics/322825: Could you provide the steps to performing this problem...the formulas alone would help...thank you. A dietician investigated whether apples washed in hot water or in cold water turned brown at different rates when exposed to air. She took 13 random apples and cut each in half. She washed one half of each apple in hot water and the other half in cold water, and then put both halves out in a tray. Her results (in hours until turning a particular shade of brown) are in the table below. At = .01, did she see a difference between the two treatments? Hot Water Cold Water Sample mean 5.50 4.85 Sample variance 2.60 2.00 A) No, because the test value –1.09 is inside the range (-3.055, 3.055). B) No, because the test value –0.79 is inside the range (-3.055, 3.055). C) Yes, because the test value –0.79 is inside the range (-3.012, 3.012). D) Yes, because the test value –1.09 is outside the range (-3.012, 3.012). 1 solutions Answer 231127 by stanbon(57226)   on 2010-07-15 20:59:36 (Show Source): You can put this solution on YOUR website! At = .01, did she see a difference between the two treatments? Hot Water Cold Water Sample mean 5.50 4.85 Sample variance 2.60 2.00 ---- The critical values for a 2-tail t-test with df= 12 = +-3.055 The test statistic for your data is 1.09 ---------------- Answer: A ---------------- Cheers, Stan H. ========================== A) No, because the test value –1.09 is inside the range (-3.055, 3.055). B) No, because the test value –0.79 is inside the range (-3.055, 3.055). C) Yes, because the test value –0.79 is inside the range (-3.012, 3.012). D) Yes, because the test value –1.09 is outside the range (-3.012, 3.012).

Linear_Equations_And_Systems_Word_Problems/322850: Basal energy requirement. The basal energy requirement B is the number of calories that a person needs to maintain the life process. For a 28-year-old female with a height of 160 centimeters and a weight of 45 kilograms (kg), B is 1300 calories. If her weight increases to 50 kg, then B is 1365 calories. There is a linear equation that expresses B in terms of her weight w. Find the equation and find the basal energy requirement if her weight is 53.2 kg. 1 solutions Answer 231119 by stanbon(57226)   on 2010-07-15 20:33:41 (Show Source): You can put this solution on YOUR website! For a 28-year-old female with a height of 160 centimeters and a weight of 45 kilograms (kg), B is 1300 calories. If her weight increases to 50 kg, then B is 1365 calories. There is a linear equation that expresses B in terms of her weight w. Points relating weight and basal energy: (45,1300) and (50,1365) --- slope = (1365-1300)/(50-45) = 65/5 = 13 ------- intercept: B = m*w + b 1300 = 13*45 + b b = 1300-13*45 = 715 --- Equation: Basal energy reqt = 13(weight) + 715 -------------------- Find the equation and find the basal energy reqt if her weight is 53.2 kg. -------- Basal = 13*53.2 + 715 = 1406 calories ======================================== Cheers, Stan H.

Quadratic_Equations/322848: Can somebody Please help me solve this problem? I have been working on it a long time and I still do not understand it. Simplify as much as possible x sqrt 6t^3-tsqrt24tx^2 Assume that all variables represent positive real numbers 1 solutions Answer 231117 by stanbon(57226)   on 2010-07-15 20:26:43 (Show Source): You can put this solution on YOUR website! Simplify as much as possible: (x sqrt(6t^3) - (tsqrt(24tx^2)) ------ = x*t*sqrt(6t) - t*2xsqrt(6t) --- = (xt*sqrt(6t)(1 - 2) --- = -xtsqrt(6t) ===================== Cheers, Stan H.

Probability-and-statistics/322846: Students who graduate from law schools must till pass a bar exam before coming layers. Suppose that in a particular jurisdiction the pass rate for first time test takers is 72%. Candidates who fail the first exam may take it again several months later of those who failed their first test ,88% pass their first attempt. Find the probability that a randomly selected law school graduate becomes a lawyer. Assume that candidates cannot take the exam more than twice. 1 solutions Answer 231115 by stanbon(57226)   on 2010-07-15 20:21:27 (Show Source): You can put this solution on YOUR website! Students who graduate from law schools must still pass a bar exam before becoming layers. Suppose that in a particular jurisdiction the pass rate for first time test takers is 72%. Candidates who fail the first exam may take it again several months later. Of those who failed their first test ,88% pass their first attempt. Find the probability that a randomly selected law school graduate becomes a lawyer. Assume that candidates cannot take the exam more than twice. ------- Not a lawyer if he/she fails twice; otherwise, becomes a lawyer ------- P(becomes lawyer) = 1 - P(does not become a lawyer) -------- P(does not become lawyer) = P(f and f) = P(f|f)P(f) = 0.12*0.28 = 0.0336 -------------------------------- Therefore: P(becomes lawyer) = 1 - 0.0336 = 0.9664 ==================================================== Cheers, Stan H.

Probability-and-statistics/322827: This problem tells me to use the variances unequal formula...could you provide it...thank you. Mauricio Cruz, a wine merchant for Cruz's Spirits Emporium, wants to determine if the average price of imported wine is less than the average price of domestic wine. The data obtained is shown in the table below. Imported Wine Domestic Wine X 7.03 9.78 s 2.31 3.62 n 15 16 40. What is the test value? Use a = 0.05. (Use the variances unequal formula) A) –4.53 B) –2.54 C) –2.50 D) –6.97 1 solutions Answer 231113 by stanbon(57226)   on 2010-07-15 20:06:59 (Show Source): You can put this solution on YOUR website! t = [(x1bar-x2bar)-(u1 - u2)]/[sqrt[s1^2/n1 + s2^2/n2] df = smaller of n1-1 and n2-1 =================================== Note: I ran a 2-SampleT test on my TI-84 calculator and got a test statistic of t = -2.5372 ========================================== Cheers, Stan H.

Probability-and-statistics/322845: A graduate statistics course has seven male and three female students. The professor wants to select two students at random to help her conduct a reseach project. What is the probability that the two students chosen a females? 1 solutions Answer 231111 by stanbon(57226)   on 2010-07-15 20:00:32 (Show Source): You can put this solution on YOUR website! A graduate statistics course has seven male and three female students. The professor wants to select two students at random to help her conduct a reseach project. What is the probability that the two students chosen a females? -------------- # of ways to select two females: 3C2 = 3 --- # of ways to select two students randomly: 10C2 = 45 ============================= P(select 2 females) = 3/45 = 1/15 ==================================== Cheers, Stan H.

Angles/322805: how do I convert this problem degrees to pi 15 degrees 30 seconds?? 1 solutions Answer 231091 by stanbon(57226)   on 2010-07-15 18:47:32 (Show Source): You can put this solution on YOUR website! how do I convert this problem degrees to pi 15 degrees 30 seconds?? --------------------------- 15.5 degrees ------------- Converting to radians: 15.5(pi/180) = 0.0861pi ============================ Cheers, Stan H.

Age_Word_Problems/322804: PLEASE HELP ME WITH THIS PROBLEM !!!=[ timmy is 4 years old.Janet is 3 times as old as timmy.when timmy turns 12,how old will janet be ? 1 solutions Answer 231087 by stanbon(57226)   on 2010-07-15 18:40:29 (Show Source): You can put this solution on YOUR website! timmy is 4 years old. t = 4 ------------------ Janet is 3 times as old as timmy. J = 3t = 3*4 = 12 ------- when timmy turns 12,how old will janet be ? ================== Since J = 3t, If timmy is 12, Janet will be 3*12 = 36 ========================================= Cheers, Stan H.

Graphs/322797: hey trying to solve this: -0.5(0.3x-0.6)=-1.5 -0.5x0.3x=-1.5 then -0.5x-0.6=-3.0 then -1.5x(0.3)=-1.5 then I took -0.3 out from both sides was left with -1.5x=-1.8 need help am I even on the right track? 1 solutions Answer 231085 by stanbon(57226)   on 2010-07-15 18:31:20 (Show Source): You can put this solution on YOUR website! -0.5(0.3x-0.6) = -1.5 ----- I don't like decimal, so let's multiply both sides by 10 to get: --- -5(0.3x-0.6) = -15 --- Divide both sides by -5 to get: 0.3x-0.6 = 3 --- Multiply thru by 10 to get: 3x - 6 = 30 3x = 36 x = 12 ==================== Cheers, Stan H.

Quadratic_Equations/322777: The path of a toy rocket is defined by the relation y=-3x^2+11x+4, where x is the horizontal distance, in meters, traveled and y is the height, in metres, above the ground. Determine the zeros of the relation. How far has the rocket traveled horizontally when it lands on the ground? What is the maximum height of the rocket above the ground, to the nearest hundredth of a meter? 1 solutions Answer 231082 by stanbon(57226)   on 2010-07-15 18:14:15 (Show Source): You can put this solution on YOUR website! The path of a toy rocket is defined by the relation y=-3x^2+11x+4, where x is the horizontal distance, in meters, traveled and y is the height, in metres, above the ground. Determine the zeros of the relation. -3x^2 + 11x + 4 = 0 --- 3x^2 - 11x -4 = 0 Factor: 3x^2 - 12x + x - 4 = 0 --- 3x(x-4) + x-4 = 0 --- (x-4)(3x+1) = 0 --- x = 4 or x = -1/3 ============================ f(x) = -3x^2+11x+4 How far has the rocket traveled horizontally when it lands on the ground? 4 ft. ================== What is the maximum height of the rocket above the ground, to the nearest hundredth of a meter? --- max occurs when x = -b/2a = -11/(2*-3) = 11/6 height = f(11/6) = 14.083 ft =============================================== Cheers, Stan H.

Graphs/322780: Find the x intercept for the graph of the equation: y = x^2 + 2x - 8 Answer in an ordered pair. Thanks much!! 1 solutions Answer 231080 by stanbon(57226)   on 2010-07-15 18:02:04 (Show Source): You can put this solution on YOUR website! Find the x intercept for the graph of the equation: y = x^2 + 2x - 8 ------------ Let y = 0 and solve for "x": x^2 + 2x -8 = 0 Factor: (x+4)(x-2) = 0 x = -4 or x = 2 ========================= Answer in an ordered pair. (-4,0) and (2,0) ==================== Cheers, Stan H.

test/322792: Write the equation of the line with a slope of -5 and a y-intercept of (0,3). 1 solutions Answer 231079 by stanbon(57226)   on 2010-07-15 17:55:54 (Show Source): You can put this solution on YOUR website! Write the equation of the line with a slope of -5 and a y-intercept of (0,3). --- If you have the slope and the intercept you have it all. --- Form: y = mx +b m is the slope and b is the intercept: ---- So the equation is y = -5x + 3 ================================== Cheers, Stan H.