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Recent problems solved by 'stanbon'
stanbon answered: 57227 problems
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56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179 , 57180..57209 , 57210..57239, >>NextGraphs/350841: find the x-intercept and the y-intercept for the graph of the equation.
x+2y=10
1 solutions
Answer 250785 by stanbon(57295)   on 2010-10-02 09:09:45 (Show Source):
You can put this solution on YOUR website!find the x-intercept and the y-intercept for the graph of the equation.
x+2y=10
----
x-intercept = ?
Let y = 0 and solve for "x":
x + 2*0 = 10
x = 10
---
x-intercept: (10,0)
=============================
y-intercept = ?
Let x = 0 and solve for "y":
0 + 2y = 10
y = 5
---
y-intercept: (0,5)
=======================
Cheers,
Stan H.
|
Rate-of-work-word-problems/350831: Four men and three women can do a job in 6 days. When five men and six women work on the same job, the work gets completed in 4 days. How long will a woman take to do the job, if she works alone on it?
1 solutions
Answer 250784 by stanbon(57295) on 2010-10-02 09:06:40 (Show Source):
You can put this solution on YOUR website!Fact: rate + rate = together rate
-----------------------------------------
Let "m" be the men's rate and "w" be the woman's rate.
-------------------
Four men and three women can do a job in 6 days.
---
4m+3w = 1/6
-------------------------------
When five men and six women work on the same job, the work gets completed in 4 days.
---
5m+6w= 1/4
=================
Multiply thru 1st equation by 2 to get:
8m + 6w = 1/3
----
Subtract 2nd from latter to get:
3m = (1/3)-(1/4)
3m = 1/12
m = 1/36
---
Solve for "w" using 4m+3w = 1/6
---
4(1/36) + 3w = 6/36
3w = 2/36
w = 1/54
=================
How long will a woman take to do the job, if she works alone on it?
Answer: 54 days
====================
Cheers,
Stan H.
|
Age_Word_Problems/350766: THE AGES OF THREE BROTHERS ARE CONSECUTIVE *EVEN* INTEGERS. THE SUM OF THEIR AGES IS 54. HOW OLD IS EACH OF THE BROTHERS?
1 solutions
Answer 250743 by stanbon(57295) on 2010-10-01 22:41:20 (Show Source):
You can put this solution on YOUR website! THE AGES OF THREE BROTHERS ARE CONSECUTIVE *EVEN* INTEGERS. THE SUM OF THEIR AGES IS 54. HOW OLD IS EACH OF THE BROTHERS?
----------------------
1st: 2x-2
2nd: 2x
3rd: 2x+2
----
Equation:
sum = 54
6x = 54
---
x = 9
-----
1st: 2x-2 = 16
2nd: 2x = 18
3rd: 2x+2 = 20
==================
Cheers,
Stan H.
|
Numbers_Word_Problems/350763: The lowest temperature ever recorded in the state of Oregon was
54°F (in Seneca, on February 10, 1933). The state’s record high temperature
occurred in Pendleton on August 10, 1898, when it reached 119°F. What is the
historical temperature range in the state of Oregon?
1 solutions
Answer 250742 by stanbon(57295) on 2010-10-01 22:37:09 (Show Source):
You can put this solution on YOUR website!The lowest temperature ever recorded in the state of Oregon was
54°F (in Seneca, on February 10, 1933). The state’s record high temperature
occurred in Pendleton on August 10, 1898, when it reached 119°F. What is the
historical temperature range in the state of Oregon?
---
range = highest - lowest
---
range = 119 - 54 = 65 degrees
===================
Cheers,
Stan H.
|
Rectangles/350758: The length of a rectangle is five times its width.
If the area of the rectangle is 405ft, find its perimeter.
1 solutions
Answer 250733 by stanbon(57295) on 2010-10-01 22:26:51 (Show Source):
You can put this solution on YOUR website!The length of a rectangle is five times its width.
If the area of the rectangle is 405ft, find its perimeter.
--------------
L = 5W
---
Equation:
Area = LW
405 = (5W)W
81= W^2
W = 9
---------------------
L = 5W = 45
======================
Perimeter = 2(L+W)
P = 2(45+9)
P = 2(54)
P = 108
=============
Cheers,
Stan H.
|
Triangles/350753: The Perimeter of a triangle is 57 centimeters. The longest side is 3 centimeters less than the sum of the other two sides. Twice the shortest side is 17 centimeters less than the longest side. Find the lengths of each side of the triangle
1 solutions
Answer 250732 by stanbon(57295) on 2010-10-01 22:22:10 (Show Source):
You can put this solution on YOUR website!The Perimeter of a triangle is 57 centimeters. The longest side is 3 centimeters less than the sum of the other two sides. Twice the shortest side is 17 centimeters less than the longest side. Find the lengths of each side of the triangle.
-------------------------
L = M+S-3
2S = L-17
L + M + S = 57
---
Rearrange:
L - M - S = -3
L + 0 -2S = 17
L + M + S = 57
--------------------
Use any method you know to solve.
I got the following:
L = 27
M = 35
S = 5
==============
Cheers,
Stan H.
============
|
Probability-and-statistics/350602: When the car park at Brinsons empties at the end of the day, the probability that a car turns left at the first junction is 3/4 and that a car turns left at its NEXT junction is 2/5. A car leaves the car park. What is the probability that
a) It turns right and then right again
b) It makes one left turn and one right turn at the first two junctions it encounters.
1 solutions
Answer 250598 by stanbon(57295) on 2010-10-01 10:21:33 (Show Source):
You can put this solution on YOUR website!When the car park at Brinsons empties at the end of the day, the probability that a car turns left at the first junction is 3/4 and that a car turns left at its NEXT junction is 2/5. A car leaves the car park. What is the probability that
a) It turns right and then right again: (1/4)(3/5) = 3/20
-----------------------
b) It makes one left turn and one right turn at the first two junctions it encounters.
(3/4)(3/5) + (1/4)(3/5) = 9/20 + 3/20 = 12/20 = 3/5
==================
Cheers,
Stan H.
==================
|
Probability-and-statistics/350543: Is the mean height for all adult American males between the ages of 18 and 21 now over 6 feet? If the population of all adult American males between the ages of 18 and 21 has mean height of μ feet and standard deviation σ feet, to answer this question one would test which of the following null and alternative hypotheses?
1 solutions
Answer 250595 by stanbon(57295) on 2010-10-01 10:15:22 (Show Source):
|
Probability-and-statistics/350592: In an article in the Journal of Management, Joseph Martocchio studied and estimated the costs of employee absences. Based on a sample of 176 blue‐collar workers, Martocchio estimated that the mean amount of paid time lost during a three‐month period was 1.4 days per employee with a standard deviation of 1.3 days. Martocchio also estimated that the mean amount of unpaid time lost during a three‐month period was 1.0 day per employee with a standard deviation of 1.8 days. Suppose we randomly select a sample of 100 blue‐collar workers. Based on Martocchio's estimates, find:
a. What is the probability that the average amount of paid time lost during a three‐month period for the 100 blue‐collar workers will exceed 1.5 days?
b. What is the probability that the average amount of unpaid time lost during a threemonth period for the I00 blue‐collar workers will exceed 1.5 days?
c. For the amount of paid time lost, the probability is 60% that the sample mean will be between what two values, symmetrically distributed around the population mean?
1 solutions
Answer 250593 by stanbon(57295) on 2010-10-01 09:55:07 (Show Source):
|
Equations/350508: Sandy uses a 1/2-ton pickup (a truck that can carry 1000 pounds) to transport ingredients for mortar. Sand comes in 50-pound bags and cement comes in 40-pound bags. Mortar is made from five bags of sand for every bag of cement. How many bags of each should Sandy load to make the most mortar possible? I need to use the four problem-solving steps (algebraic solution). Symbolic Representation.
Thank you,
Lorna
1 solutions
Answer 250546 by stanbon(57295) on 2010-09-30 23:50:13 (Show Source):
You can put this solution on YOUR website!Sandy uses a 1/2-ton pickup (a truck that can carry 1000 pounds) to transport ingredients for mortar.
Sand comes in 50-pound bags and
cement comes in 40-pound bags.
Mortar is made from five bags of sand for every bag of cement.
Equations:
50s + 40c = 1000
s = 5c
--------------
Substitute for "s" and solve for "c":
50(5c) + 40c = 1000
290c = 1000
c = 3.448
---
Max number of cement bags is 3
Since s = 5c, s = 15 (# of bags of sand needed with 3 bags of cement.
=======================
Cheers,
Stan H.
How many bags of each should Sandy load to make the most mortar possible? I need to use the four problem-solving steps (algebraic solution). Symbolic Representation.
|
Miscellaneous_Word_Problems/350503: Find the cost per ounce of a sunscreen made from 70 oz of lotion that cost $3.44 per ounce and 50 oz of lotion that cost $10.88 per ounce.
A hospital staff mixed a 75% disinfectant solution with a 25% disinfectant solution. How many liters of each were used to make 25 L of a 45% disinfectant solution?
A butcher has some hamburger that is 22% fat and some that is 13% fat. How many pounds of each should be mixed to make 90 lb of hamburger that is 16% fat?
A ferry leaves a harbor and travels to a resort island at an average speed of 18 mph. On the return trip, the ferry travels at an average speed of 12 mph because of fog. The total time for the trip is 5 h. How far is the island from the harbor?
1 solutions
Answer 250532 by stanbon(57295) on 2010-09-30 22:37:32 (Show Source):
You can put this solution on YOUR website!Find the cost per ounce of a sunscreen made from 70 oz of lotion that cost $3.44 per ounce and 50 oz of lotion that cost $10.88 per ounce.
---
Value 70*3.44+50*10.88 = 784.80 for 120 ounces
---
Cost per ounce = Value/amount = 784.80/120 = $6.54 per ounce.
----------------------------------------------------------------------
A hospital staff mixed a 75% disinfectant solution with a 25% disinfectant solution. How many liters of each were used to make 25 L of a 45% disinfectant solution?
----
active + active = active
0.75x + 0.25(25-x) = 0.45*25
Multiply thru by 100 to get:
75x + 25*25-25x = 45*25
50x = 20*25
x = 10 L (amt of 75% solution needed in the mixture)
---
25-x = 15 L (amt of 25% solution needed in the mixture)
==========================================================
A butcher has some hamburger that is 22% fat and some that is 13% fat. How many pounds of each should be mixed to make 90 lb of hamburger that is 16% fat?
---
fat + fat = fat
0.22x + 0.13(90-x) = 0.16*90
Note: Same procedure as in the previous problem.
================================================
A ferry leaves a harbor and travels to a resort island at an average speed of 18 mph. On the return trip, the ferry travels at an average speed of 12 mph because of fog. The total time for the trip is 5 h. How far is the island from the harbor?
---
h to island DATA:
rate = 18 mph ; distance = x miles ; time = d/r = x/18 hrs.
---------------------
island to h DATA:
rate = 12 mph ; distance = x miles ; time = d/r = x/12 hrs
------
Equation:
time + time = 5 hrs.
x/18 + x/12 = 5
Multiply thru by 36:
2x + 3x = 5*36
5x = 5*36
x = 36 miles
===================
Cheers,
Stan H.
=================
|
Numeric_Fractions/350504: Can you help me solve this problem: 1/2n + 6 = 1/3n
I have subtracted the 1/2n from the left side to combine with the right side. I have 6 = 5/6n. I'm stuck now. Just to clarify the / indicates a fraction.
1 solutions
Answer 250526 by stanbon(57295) on 2010-09-30 22:24:13 (Show Source):
You can put this solution on YOUR website! (1/2)n + 6 = (1/3)n
-------
Multiply thru by 6 to get rid of the fractions:
3n + 36 = 2n
n = -36
----------------------
Cheers,
Stan H.
|
Travel_Word_Problems/350497: First off, thanks for volunteering your time and expertise to help students; you are so valuable to us!
Two brothers , Bob and Charlie , live 450 miles apart. Starting at the same time they plan to drive until they meet. Bob averages 10 mph faster than Charlie who averages 50 mph. How long will it take them to meet?
Let t = time (in hours)
60(t) + 50(t) = 450
t = 4.09 hours
I have a very bad history with converting a word problem into a math problem, so I am not too confident in my solution.
1 solutions
Answer 250523 by stanbon(57295) on 2010-09-30 22:22:00 (Show Source):
You can put this solution on YOUR website!Two brothers , Bob and Charlie , live 450 miles apart. Starting at the same time they plan to drive until they meet. Bob averages 10 mph faster than Charlie who averages 50 mph. How long will it take them to meet?
Let t = time (in hours)
60(t) + 50(t) = 450
t = 4.09 hours
-----------------------
That is correct.
=======================
Cheers,
Stan H.
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Equations/350499: How do you know if a value is a solution for an inequality?
1 solutions
Answer 250519 by stanbon(57295) on 2010-09-30 22:16:54 (Show Source):
You can put this solution on YOUR website!How do you know if a value is a solution for an inequality?
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Replace the variable by the "solution".
If you get a true statement, the "solution" is truly a solution.
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Cheers,
Stan H.
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test/350500: If 6 more than x is two less than y, what is the value of y in terms of x? How do u solve this?
1 solutions
Answer 250518 by stanbon(57295) on 2010-09-30 22:13:50 (Show Source):
You can put this solution on YOUR website!If 6 more than x is two less than y, what is the value of y in terms of x? How do u solve this?
----
x+6 = y-2
----
y = x+6+2
y = x+8
=========
Cheers,
Stan H.
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Expressions-with-variables/350495: Find three consecutive odd numbers such that the sum of four times the smallest is the same as one more than three times the largest.
1 solutions
Answer 250516 by stanbon(57295) on 2010-09-30 22:11:36 (Show Source):
You can put this solution on YOUR website!Find three consecutive odd numbers such that the sum of four times the smallest is the same as one more than three times the largest.
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Odd numbers are always one more or one less than an even number.
----
1st: 2x-1
2nd: 2x+1
3rd: 2x+3
----------------------------
Equation:
4(2x-1) = 3(2x+3)+1
8x-4 = 6x+9+1
2x = 14
x = 7
-------
1st: 2x-1 = 13
2nd: 15
3rd: 17
=========================
Cheers,
Stan H.
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Probability-and-statistics/350015: A bakery shop sells loaves of fresh French bread. Any unsold loaves at the end of the day are either discarded or sold elsewhere at a loss. The demand for this bread has followed a normal distribution with a mean = 35 loaves and variance/sigma = 8 loaves.
a) If 40 loaves are to be made each day, what is the probability of not meeting demand?
b) How many loaves should the bakery make each day so that they can meet the demand 90% of the time?
c) What is the probability of exceeding 38 loaves, given that the demand exceeds 35?
1 solutions
Answer 250514 by stanbon(57295) on 2010-09-30 22:03:13 (Show Source):
You can put this solution on YOUR website!A bakery shop sells loaves of fresh French bread. Any unsold loaves at the end of the day are either discarded or sold elsewhere at a loss.
--------------------------------
The demand for this bread has followed a normal distribution with a mean = 35 loaves and variance/sigma = 8 loaves.
a) If 40 loaves are to be made each day, what is the probability of not meeting demand?
---
Find the z-value of 40.
z(40) = (40-35)/8 = 1/2
P(x > 40) = P(z> 1/2) = normalcdf(0.5,100) = 0.3085
The probability the demand is more than 40 loves is 30.85%
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b) How many loaves should the bakery make each day so that they can meet the demand 90% of the time?
---
Find the z-value with a left tail of 90%: invNorm(0.90) = 1.2816
---
Find the corresponding x value:
x = 1.2816*8+35 = 45.25
------------------------------------
c) What is the probability of exceeding 38 loaves, given that the demand exceeds 35?
----
Cheers,
Stan H.
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Probability-and-statistics/350359: I need someone to fully explain how to get this answer ns easy terms. Please include step by step instructions to figure this out. I am struggling with this class and have other questions to answer. Thank you for your help!
A clinical trial is conducted to compare an experimental medication to placebo to reduce the symptoms of asthma. Two hundred participants enrolled in the study and randomized to receive either the experimental medication or placebo. The primary outcome is a self-reported reduction of symptoms. Among 100 participants who received the experimental medication, 38 reported a reduction of symptoms as compared to 21 participants of 100 assigned to the placebo.
a. Generate a 95% CI for the difference in proportions of participants reporting a reduction of symptoms between the experimental and the placebo groups?
b. Estimate the RR for reduction in symptoms between groups?
c. Estimate the OR for reduction in symptoms between groups?
d. Generate a 95% CI for the RR?
1 solutions
Answer 250509 by stanbon(57295) on 2010-09-30 21:47:18 (Show Source):
You can put this solution on YOUR website!A clinical trial is conducted to compare an experimental medication to placebo to reduce the symptoms of asthma.
-----------------------------
Two hundred participants enrolled in the study and randomized to receive either the experimental medication or placebo. The primary outcome is a self-reported reduction of symptoms.
--------------------------------
Among 100 participants who received the experimental medication, 38 reported a reduction of symptoms as compared to 21 participants of 100 assigned to the placebo.
--------------------------------
a. Generate a 95% CI for the difference in proportions of participants reporting a reduction of symptoms between the experimental and the placebo groups?
---
I ran a 2-Proportion Z Interval on my TI-84 and got the following:
0.0458 < p1-p2 < 0.2942
------------------------------------
b. Estimate the RR for reduction in symptoms between groups?
c. Estimate the OR for reduction in symptoms between groups?
d. Generate a 95% CI for the RR?
---
Comment: I am not sure what the RR is.
Cheers,
Stan H.
----------------
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Travel_Word_Problems/350283: Kesha drove from Buffalo to Syracuse at an average rate of 48 miles per hour. On the return trip along the same road she was able to travel at an average rate of 60 miles per hour. The trip from Buffalo to Syracuse took one-half hour longer than the return trip. How long did the return trip take?
1 solutions
Answer 250391 by stanbon(57295) on 2010-09-30 16:35:54 (Show Source):
You can put this solution on YOUR website!Kesha drove from Buffalo to Syracuse at an average rate of 48 miles per hour.
---
B to S DATA:
rate = 48 mph ; time = x hrs ; distance = 48x miles
-------------------------------------
On the return trip along the same road she was able to travel at an average rate of 60 miles per hour. The trip from Buffalo to Syracuse took one-half hour longer than the return trip.
-------------------------------------
S to B DATA:
rate = 60 mph ; time = x-(1/2) hrs ; distance = 60(x-(1/2)) = 60x-30 miles
---------------------------------
How long did the return trip take?
Equation:
distance = distance
48x = 60x-30
12x = 30
x = 5/2 hrs
x-(1/2) = 5 hrs (time for return trip)
========================================
Cheers,
Stan H.
=================
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Probability-and-statistics/350176: Us e the compound interest formula A=P(1+r)t and the given information to solve for. A=$9,000,000 P=$20,000 t=40
1 solutions
Answer 250370 by stanbon(57295) on 2010-09-30 16:01:28 (Show Source):
You can put this solution on YOUR website!Us e the compound interest formula A=P(1+r)t and the given information to solve for. A=$9,000,000 P=$20,000 t=40
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9000000 = 20,000(1+r)^t
450 = (1+r)^40
---
1+r = 1.1650
r = 0.1650
r = 16.5%
================
Cheers,
Stan H.
================
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Trigonometry-basics/350266: An insect population P in a certain area fluctuates with the seasons. It is estimated that P=17,000+4500sin pi(t)/52, where t is given in weeks. Determine the number of weeks it would take for the population to initially reach 20,000.
1 solutions
Answer 250365 by stanbon(57295) on 2010-09-30 15:55:01 (Show Source):
You can put this solution on YOUR website!An insect population P in a certain area fluctuates with the seasons.
It is estimated that P=17,000+4500sin pi(t)/52, where t is given in weeks. Determine the number of weeks it would take for the population to initially reach 20,000.
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20,000 = 17,000+4500sin pi(t)/52
---
3000 = 4500*sin(pi*t/52)
-----
1/15 = sin(pi*t/52)
---
(pi*t/52) = sin^-1(1/15)
---
(pi/52)t = 0.0667
pi*t = 3.4692
t = 1.1043 weeks
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Cheers,
Stan H.
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Probability-and-statistics/350252: What is the difference between a point estimate and a confidence interval estimate? Does the confidence interval always contain the true population parameter? Yes or No. I think it is yes.
Interpret what is meant by a 95% confidence interval.
1 solutions
Answer 250360 by stanbon(57295) on 2010-09-30 15:48:39 (Show Source):
You can put this solution on YOUR website!What is the difference between a point estimate and a confidence interval estimate?
---
A point estimate is some sample statistic such as sample mean, or
sample proportion.
A confidence interval estimate is a derived interval around a
sample mean or sample proportion that may or may not contain the
population mean or population proportion.
--------------------------------------
Does the confidence interval always contain the true population parameter? Yes or No. No is the correct answer.
--------
Interpret what is meant by a 95% confidence interval.
Using the method prescribed we can state with 95% confidence
that the interval does contain the population parameter.
==================
Cheers,
Stan H.
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Word_Problems_With_Coins/350257: Jamil always throws loose change into a pencil holder on his desk and takes it out every two weeks. This time it is all nickels and dimes.
There are 2 times as many dimes as nickels and the value of the dimes is $1.65 more than the value of nickles. How many nickels and dimes does Jamil have?
1 solutions
Answer 250359 by stanbon(57295) on 2010-09-30 15:35:04 (Show Source):
You can put this solution on YOUR website!There are 2 times as many dimes as nickels and the value of the dimes is $1.65 more than the value of nickles. How many nickels and dimes does Jamil have?
--------------------------------
Equations:
d = 2n
---
10d = 5n+165
---------------------
Substitute for "d" and solve for "n":
10(2n) = 5n+165
20n = 5n+165
15n = 165
n = 11 (# of nickels)
---
Since d = 2n, # of dimes = 22
===============================
Cheers,
Stan H.
=============
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Geometry_Word_Problems/350246: 1.a rectangular field 70m long and 50m wide has a path of uniform width around it . if the area of the path is 1024 sq.cm.find the width of the path
2.The base and height of a triangle are (x+3) and (2x-5)cm respectively if the area of the triangle is 20 sq.cm find x
3.The length of a rectangle is 5cm longer than its width and its area is 66 sq.cm find the perimeter of the rectangle
1 solutions
Answer 250356 by stanbon(57295) on 2010-09-30 15:29:22 (Show Source):
You can put this solution on YOUR website!1.a rectangular field 70m long and 50m wide has a path of uniform width around it . if the area of the path is 1024 sq.m.find the width of the path
---
Draw the picture of a rectangle inside a rectangle.
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The area of the inner rectangle is 70*50 = 3500 sq. meters
---
Area of the outer rectangle = (70+2x)(50+2x) = 4X^2 + 240x + 3500
----
Equation:
Outer area - Inner area = 4x^2+ 240x = 1024
x^2+60x-256 = 0
(x-4)(x+64) = 0
---
Positive Solution:
x = 4 meters.
====================
2.The base and height of a triangle are (x+3) and (2x-5)cm respectively if the area of the triangle is 20 sq.cm find x
------------------
Area = (1/2)(base)(height)
20 cm^2 = (1/2)(x+3)(2x-5)
40 = 2x^2+x-15
---
2x^2+x-55 = 0
(x-5)(2x+11) = 0
Positive solution:
x = 5
-----
base = x+3 = 9 cm
height = 2x-5 = 5 cm
=====================
3.The length of a rectangle is 5cm longer than its width and its area is 66 sq.cm find the perimeter of the rectangle.
---
Let width = x
The length = x+5
---
Equation:
x(x+5) = 66
x^2+5x-66 = 0
(x+11)(x-6) = 0
---
Positive Solution:
x = 6 cm
---
Perimeter = 2(width + length)
P = 2(6 + 11)
P = 2(17)
Perimeter = 34 cm
======================
Cheers,
Stan H.
==============
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Geometry_Word_Problems/350244: 1.a rectangular field 70m long and 50m wide has a path of uniform width around it . if the area of the path is 1024 sq.cm.find the width of the path
2.The base and height of a triangle are (x+3) and (2x-5)cm respectively if the area of the triangle is 20 sq.cm find x
3.The length of a rectangle is 5cm longer than its width and its area is 66 sq.cm find the perimeter of the rectangle
1 solutions
Answer 250349 by stanbon(57295) on 2010-09-30 15:12:29 (Show Source):
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Geometry_Word_Problems/350245: 1.a rectangular field 70m long and 50m wide has a path of uniform width around it . if the area of the path is 1024 sq.cm.find the width of the path
2.The base and height of a triangle are (x+3) and (2x-5)cm respectively if the area of the triangle is 20 sq.cm find x
3.The length of a rectangle is 5cm longer than its width and its area is 66 sq.cm find the perimeter of the rectangle
1 solutions
Answer 250348 by stanbon(57295) on 2010-09-30 15:11:21 (Show Source):
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