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Recent problems solved by 'stanbon'
stanbon answered: 57151 problems
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56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179, >>Next
Mixture_Word_Problems/415490: Please help me solve this problem: A collection of 102 nickels, dimes, and quarters is worth $13.60. There are 14 more nickels than dimes. How many quarters are there? 1 solutions
Answer 291280 by stanbon(57219) on 2011-02-28 19:20:42 (Show Source):
You can put this solution on YOUR website!A collection of 102 nickels, dimes, and quarters is worth $13.60. There are 14 more nickels than dimes. How many quarters are there?
---------------
Equations:
Quantity: n + d + q = 102
Quantity: n = d+14
Value:: 5n +10d+25q = 1360 cents
-------------------------------------
Rearrange:
n + d + q = 102
n - d + 0 = 14
5n+10d+25q= 1360
-----------------
Use any method you know to get:
q = 36
==============
Cheers,
Stan H.
|
Probability-and-statistics/415488: You are dealt one card from a 52-card deck. Find the probability that you are dealt a numbered card or a club 1 solutions
Answer 291277 by stanbon(57219) on 2011-02-28 19:14:26 (Show Source):
You can put this solution on YOUR website!You are dealt one card from a 52-card deck. Find the probability that you are dealt a numbered card or a club
------
# of numbered cards: 4*9 (not counting ace as a numbered card)
# of clubs: 13
# of numbered clubs: 9
---
# of numbered cards or clubs: 36 + 13 - 9 = 40
---
P(numbered card or a club) = 40/52
========================================
Cheers,
Stan H.
===========
|
Coordinate-system/415489: Andrew walks to school every day. The distance between his home nad school is 1000m, and it takes Andrew 20 minutes to walk there. Which equation relates the distance d to time t if Andrew is walking at a constant speed?
1 solutions
Answer 291275 by stanbon(57219) on 2011-02-28 19:10:37 (Show Source):
You can put this solution on YOUR website!Andrew walks to school every day. The distance between his home and school is 1000m, and it takes Andrew 20 minutes to walk there. Which equation relates the distance d to time t if Andrew is walking at a constant speed?
==========================
d = r*t
1000 = r*(1/3)
---
r = 3000 meters/hour
=======================
Cheers,
Stan H.
|
Graphs/415486: Graph each Equation: solve for y. need to find 3 points on a line that intercept.
this is what i have tried.
4/3*4x/3=3y/3*3/1
x=9y/3
and im stuck. 1 solutions
Answer 291274 by stanbon(57219) on 2011-02-28 19:08:02 (Show Source):
You can put this solution on YOUR website!4x=3y
---
y = (4/3)x
If x=0, y = 0
If x = 3, y = 4
If x = 6, y = 8
----
You have three points: (0,0),(3,4),(6,8)
===========================================
Cheers,
Stan H.
===========
|
Trigonometry-basics/415480: How do i find the remaining five trigonometric function values for Sin delta = 1/5 and delta is in the second quadrant? Thank you! 1 solutions
Answer 291273 by stanbon(57219) on 2011-02-28 19:04:58 (Show Source):
You can put this solution on YOUR website!How do i find the remaining five trigonometric function values for Sin delta = 1/5 and delta is in the second quadrant?
----
sin = y/r = 1/5
So y = 1 and r = 5
------
Solve for "x" in the 2nd Quadrant:
x = sqrt[5^2-1^2] = sqrt[24]
x = -2sqrt(6) in the 2nd Quadrant:
-------
sin = y/r = 1/5
cos = x/r = -2sqrt(6)/5
tan = y/x = 1/-2sqrt(6)
-------
csc = r/y = 5
sec = r/x = -5/(2sqrt(6))
cot = x/y = -2sqrt(6)
===========================
Cheers,
Stan H.
===============
|
Polynomials-and-rational-expressions/415477: The formula A = 3Ts+Qz/3T+Q gives a student's average, A, after T tests and Quizzes, where each test counts as 3 quizzes, where s is the test average and Z the quiz average. Solve for Q. 1 solutions
Answer 291271 by stanbon(57219) on 2011-02-28 18:59:21 (Show Source):
You can put this solution on YOUR website! The formula A = (3Ts+Qz)/(3T+Q) gives a student's average, A, after T tests and Quizzes, where each test counts as 3 quizzes, where s is the test average and Z the quiz average. Solve for Q.
------------------------
A = (3Ts+Qz)/(3T+Q)
---
A(3T+Q) = 3Ts+Qz
---
3AT + AQ = 3Ts + Qz
----
AQ-Qz = 3Ts-3AT
---
Q(A-z) = (3Ts-3AT)
---
Q = (3Ts-3AT)/(A-z)
=======================
Cheers,
Stan H.
===========
|
Geometric_formulas/415474: I am having trouble making the relationships of pii or 3.14..... for instance i know that piiR^2 (pie x radius squared) is how you find the area of a circle
I know also you can use pii x D^2 divided by 4 because r^2 = (D/2)^2 = (d^2)/4
recently i was given the formula for volume of a pipe .785 x diameter x length where .785 is pi/4 could you please explain how you simplify the formula to get .785 x diameter x length for volume of a pipe i understand .785 is 1/4 pii but i dont understand how you get from piiR^2 x length to .785 X dia. x length for the volume and ive worked both ways the only one close is .785 formula 1 solutions
Answer 291270 by stanbon(57219) on 2011-02-28 18:54:36 (Show Source):
You can put this solution on YOUR website!recently i was given the formula for volume of a pipe .785 x diameter x length where .785 is pi/4 could you please explain how you simplify the formula to get .785 x diameter x length for volume of a pipe i understand .785 is 1/4 pii but i dont understand how you get from piiR^2 x length to .785 X dia. x length for the volume and ive worked both ways the only one close is .785 formula
-------
Volume = Area of a cross section *length
---
But Surface = Circumference * length
S = pi*D*L
------
0.785*diameter*length looks like a surface formula to me.
-----
Cheers,
Stan H.
========
|
Linear-systems/415469: How would you do a linear system that has one equation with a fraction, using the elimination method? Such as the following: 3/2x + y= -5/2
4x + y= -5?
Your help is much appreciated. 1 solutions
Answer 291267 by stanbon(57219) on 2011-02-28 18:44:02 (Show Source):
You can put this solution on YOUR website!When you have an equation you NEVER have to
deal with fractions.
-----
3/2x + y= -5/2
4x + y= -5
---------
Multiply thru by 2 to get:
3x + 2y = -5
4x + y = -5
----
Multiply thru the 2nd Eq. by 2:
3x + 2y = -5
8x + 2y = -10
---
Subtract and solve for "x":
5x = -5
x = -1
----
Solve for "y":
4x+y = -5
4(-1) + y = -5
-4 + y = -5
y = -1
----
Solution: (-1,-1)
=======================
Cheers,
Stan H.
===========
|
Linear-systems/415423: I need help with figuring out how to work these types of problems. Step by step. For example, here are two examples of problems I need help understanding how to work.
Solve - -2(-1-3y)=7y
solve 7(6=w)=6(2+w)
I know the goal is to get the variable by itself but I am confused. Please advise. Thanks! 1 solutions
Answer 291258 by stanbon(57219) on 2011-02-28 17:42:53 (Show Source):
You can put this solution on YOUR website!Solve
-2(-1-3y) = 7y
2+6y = 7y
y = 2
-------
solve
7(6+w) = 6(2+w)
42+7w = 12+6w
w = -30
==============
Cheers,
Stan H.
==============
|
Linear-systems/415418: I need help on a question on homework. Here is the problem:
Write a system of inequalities whose solution is the set of all points in quadrant 1 not including the axes.
1 solutions
Answer 291251 by stanbon(57219) on 2011-02-28 17:29:16 (Show Source):
You can put this solution on YOUR website!Write a system of inequalities whose solution is the set of all points in quadrant 1 not including the axes.
System:
x > 0
y > 0
==========
Cheers,
Stan H.
===========
|
Functions/415108: Consider the function defined by f(x)=-2x^3-3x^2+5x-4.
Use the intermediate value theorum to show that f has a zero between 0 and -1. 1 solutions
Answer 291082 by stanbon(57219) on 2011-02-28 07:46:28 (Show Source):
You can put this solution on YOUR website!f(x)=-2x^3-3x^2+5x-4.
Use the intermediate value theorum to show that f has a zero between 0 and -1.
---
f(-1) = -2(-1)^3-3(-1)^2+5(-1)-4 = -2(-1)-3(1)-5-4 < 0
---
f(0) = -4
-------
Note: It doesn't have a zero between -1 and 0
-------------
Cheers,
Stan H.
|
Evaluation_Word_Problems/415125: Factor fully:
a) x^3-27
b) 2x^3+4x^2-13x-6 1 solutions
Answer 291081 by stanbon(57219) on 2011-02-28 07:35:10 (Show Source):
You can put this solution on YOUR website!Factor fully:
a) x^3-27 = (x-3)(x^2+3x+9)
----------------------------------
b) 2x^3+4x^2-13x-6
x = 2 is a root
Use synthetic division to find the other two roots:
2)....2....4....-13....-6
.......2....8.....3....|..0
--
Solve 2x^2+8x+3 = 0
x = [-8 +- sqrt(64-4*2*3)]/4
x = [-8 +- sqrt(40)]/4
x = [-8 +- 2sqrt(10)]/4
---
x = -2+(1/2)sqrt(10) or x = -2-(1/2)sqrt(10)
===========================
Cheers,
Stan H.
==================
|
expressions/415128: i=io e^(-Rt/L)
i=0.1
io=4
R=150
L=0.012
Solve for t 1 solutions
Answer 291079 by stanbon(57219) on 2011-02-28 07:25:55 (Show Source):
You can put this solution on YOUR website!i=io e^(-Rt/L)
i=0.1
io=4
R=150
L=0.012
Solve for t
-----
0.1 = 4*e^(-150t/0.012)
0.025 = e^(-12500t)
-12500t = ln(0.025)
---
-12500t = -3.688879
t = 2.951104x10^-4
==========================
Cheers,
Stan H.
=============
|
Coordinate-system/415130: give me the answer and its solution:
m=1/2 (one half)
PTa=(-2,-4)
PTb=(k,4)
Find:K=?
[hint: Y2-Y1/X2-X1 (Y2 minus Y1 over X2 minus X1)
Then graph it please.
Thats what my teacher told me.. 1 solutions
Answer 291078 by stanbon(57219) on 2011-02-28 07:20:54 (Show Source):
You can put this solution on YOUR website!m=1/2 (one half)
PTa=(-2,-4)
PTb=(k,4)
Find:K=?
------
slope = (-4-4)/(-2-k) = 1/2
---
-8/(-2-k) = 1/2
Cross-multiply:
-16 = -2-k
k = 14
===========
Cheers,
Stan H.
===========
|
Human-and-algebraic-language/415044: a.Suppose a market research company finds that at a price of p = $12, they would sell x = 54 tiles each month. If they lower the price to p = $6, then more people would purchase the tile, and they can expect to sell x = 60 tiles in a month’s time. Find the equation of the line for the demand equation. Write your answer in the form p = mx + b. Hint: Write an equation using two points in the form (x,p). Show how you arrived at your answer. 1 solutions
Answer 291016 by stanbon(57219) on 2011-02-27 22:22:33 (Show Source):
You can put this solution on YOUR website! a.Suppose a market research company finds that at a price of p = $12, they would sell x = 54 tiles each month. If they lower the price to p = $6, then more people would purchase the tile, and they can expect to sell x = 60 tiles in a month’s time. Find the equation of the line for the demand equation. Write your answer in the form p = mx + b. Hint: Write an equation using two points in the form (x,p).
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Two points: (12,54) and (6,60)
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slope = (60-54)/(6-12) = 6/-6 = -1
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Form p = mx + b
60 = -1(6) + b
b = 66
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Equation:
p(x) = -x + 66
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Cheers,
Stan H.
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Circles/415035: Question is: if the radius of a circle is 8ft and the central angle is 5pi/4 find the intercepted arc length.
I know that 5pi/4 equals 225 degrees and the diameter is 16ft but im not sure how to set this equation up to figure the intercepted arc length.
thank you 1 solutions
Answer 291013 by stanbon(57219) on 2011-02-27 22:10:32 (Show Source):
You can put this solution on YOUR website!Question is: if the radius of a circle is 8ft and the central angle is 5pi/4 find the intercepted arc length.
I know that 5pi/4 equals 225 degrees and the diameter is 16ft but im not sure how to set this equation up to figure the intercepted arc length.
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arc length/circumference = central angle/360
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arc length = (16pi)[225/360]
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arc length = (16pi)*0.625 = 10pi ft
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Cheers,
stan H.
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Graphs/415031: Hello! My problem is
Solve the following inequality using a graphing approach.
I don't know the steps on my caculator on how to find it correctly.
the equations is |x-(square root)13| + (square root) 6 < -x-(square root) 10
???
1 solutions
Answer 291005 by stanbon(57219) on 2011-02-27 21:52:49 (Show Source):
You can put this solution on YOUR website! |x-(square root)13| + (square root) 6 < -x-(square root) 10
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Enter in your calculator:
Y1: abs(x-sqrt(13))+sqrt(6)
Y2: -x-sqrt(10)
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Graph them both on the same set of axes.
Then find the intervals on the x-axis where Y1 is below Y2
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Cheers,
Stan H.
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Probability-and-statistics/415024: Opposed Supported Neutral Total
Males 25 24 10 59
Females 18 15 14 47
Total 43 39 24 106
compute the following probabilities of randomly selecting:
A. A person who supported the policy.
B. A man who either supported or was neutral to the policy.
C. Two different females who opposed the policy.
D. A male, given that the selected person supported the policy.
E. A person who opposed the policy, given that the selected person is a female. 1 solutions
Answer 291002 by stanbon(57219) on 2011-02-27 21:39:49 (Show Source):
You can put this solution on YOUR website! Opposed Supported Neutral Total
Males 25 24 10 59
Females 18 15 14 47
Total 43 39 24 106
compute the following probabilities of randomly selecting:
A. A person who supported the policy.:::39/106
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B. A man who either supported or was neutral to the policy.::(39+24)/106
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C. Two different females who opposed the policy.::18C2/106
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D. A male, given that the selected person supported the policy.::24/39
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E. A person who opposed the policy, given that the selected person is a female.
:::18/47
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Cheers,
Stan H.
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Money_Word_Problems/415019: melissa wants a camera that is 28% off. the discount is $100.80. what is the original price? 1 solutions
Answer 290994 by stanbon(57219) on 2011-02-27 21:21:07 (Show Source):
You can put this solution on YOUR website! melissa wants a camera that is 28% off. the discount is $100.80. what is the original price?
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Let original price be "x":
0.28x = 100.80
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x = 100.80/0.28
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x = $360.00
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Cheers,
Stan H.
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Trigonometry-basics/414999: Please help me with my last problem::
On cloudy days, the sun intensity I (in calories per square centimeter) is given by I = I(max) sin‚‚^2 ( t / D) where I(max) is the largest sun intensity and D is the number of daylight hours. If D = 12, how many hours after sunrise is intensity exactly half of the maximum level? (Assume t is in between zero and D)
Thank you very much!!
1 solutions
Answer 290992 by stanbon(57219) on 2011-02-27 21:14:38 (Show Source):
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Trigonometry-basics/415011: graph and find the vertex, y-intercept and line of symmetry of the following equation: y=(x-3)^2+4. 1 solutions
Answer 290991 by stanbon(57219) on 2011-02-27 21:12:21 (Show Source):
You can put this solution on YOUR website!graph and find the vertex, y-intercept and line of symmetry of the following equation: y=(x-3)^2+4.
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Vertex: (3,4)
y-int: (0,13)
line of sym: x = 3
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Cheers,
Stan H.
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Trigonometry-basics/415003: Please help me with my last problem::
On cloudy days, the sun intensity I (in calories per square centimeter) is given by I = I(max) sin‚‚^2 (pi t / D) where I(max) is the largest sun intensity and D is the number of daylight hours. If D = 12, how many hours after sunrise is intensity exactly half of the maximum level? (Assume t is in between zero and D)
Thank you very much!!
1 solutions
Answer 290989 by stanbon(57219) on 2011-02-27 21:08:40 (Show Source):
You can put this solution on YOUR website!On cloudy days, the sun intensity I (in calories per square centimeter) is given by I = I(max) sin^2 (pi t / D) where I(max) is the largest sun intensity and D is the number of daylight hours. If D = 12, how many hours after sunrise is intensity exactly half of the maximum level? (Assume t is in between zero and D)
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Solve sin^2[(pi/12)t] = 1/2
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sin[(pi/12)t] = sqrt(2)/2
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(pi/12)t = pi/4
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(t/12) = 1/4
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t = 3 hrs.
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Cheers,
Stan H.
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