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Recent problems solved by 'stanbon'

stanbon answered: 57894 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 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Probability-and-statistics/444408: The library is given 3 books as a gift. The books will be selected from a list of 16 titles. if each book selected must have a differtn title how many selections are there? 1 solutions Answer 306383 by stanbon(57967)   on 2011-05-03 17:09:03 (Show Source): You can put this solution on YOUR website! The library is given 3 books as a gift. The books will be selected from a list of 16 titles. If each book selected must have a different title. How many selections are there? --------------------- Ans: 16C3 = (16*15*14)/(1*2*3) = 560 ======================================== Cheers, Stan H. ==========

Probability-and-statistics/444432: random sample of 42 graduates revealed worked 5.5 yrs the sample standard deviation was 1.1 yrs Using 99% degree of confidence what is the confidence interval for the population mean 1 solutions Answer 306379 by stanbon(57967)   on 2011-05-03 17:04:50 (Show Source): You can put this solution on YOUR website! A random sample of 42 graduates revealed worked 5.5 yrs the sample standard deviation was 1.1 yrs Using 99% degree of confidence, what is the confidence interval for the population mean. ------------------------------ x-bar = 5.5 --- ME = zs/sqrt(n) = 2.5758*1.1/sqrt(42) = 0.4372 ----------------- 99% CI: 5.5-0.4372 < u < 5.5+0.4372 ===================================== Cheers, Stan H. ===========

Probability-and-statistics/444475: If you roll a standard number cube twice. Find each probability. P(1, then 2), P(3, then even), P(less than 4, then 1), P(odd, then even), P(divisible by 2, then 5), and P(greater than 2, then odd) 1 solutions Answer 306375 by stanbon(57967)   on 2011-05-03 16:55:36 (Show Source): You can put this solution on YOUR website! If you roll a standard number cube twice. Comment: These roll results are all independent. ----------------------------------------------------- Find each probability. P(1, then 2) = (1/6)(1/6) = 1/36 ----------------- P(3, then even) = (1/6)(1/2) = 1/12 ----------------- P(less than 4, then 1) = (3/6)(1/6) = 1/12 ----------------- P(odd, then even) = (3/6)(3/6) = 1/4 ----------------- P(divisible by 2, then 5) = (3/6)(1/6) = 1/12 ----------------- P(greater than 2, then odd) = (4/6)(1/6) = 1/9 ---- Cheers, Stan H. ========

Linear-equations/444242: I am not sure how to resolved this math problem: Find points of intersection for 2x-4y>6 3x+2y<6 (Solve by graphing and state 1 solution and 1 non-solution) Thank you very much for your help Elik 1 solutions Answer 306299 by stanbon(57967)   on 2011-05-03 10:00:04 (Show Source): You can put this solution on YOUR website! I am not sure how to resolved this math problem: Find points of intersection for 2x-4y>6 3x+2y<6 (Solve by graphing and state 1 solution and 1 non-solution) -------------- 1st: Graph the boundary line of the 1st inequality: y = 2x/4-6/4 y = (1/2)x-(3/2) 2nd: Sketch that boundary as a dashed line. 3rd: Since you want y < (1/2)x-(3/2), shade the half-plane BELOW the boundary. ----------------------------- 1st: Graph the boundary line of the 2nd inequality: y =(-3/2)x +3 2nd: Sketch that as a dashed line. 3rd: Since you wan y < (-3/2)x+3, shade the half-plane BELOW the boundary. ------------------------------------------------------ A point IN the intersection: (0,0) A point Not IN the intersection: (0,6) ---------------------------------- Cheers, Stan H.

Rational-functions/444209: I Dont Understand How Do Do These Problems: It Says I have to identify any holes or vertical asymptotes? They Are All Over Each Other it starts with Y over the numbers . x+3 y= x+3 . x-2 y= (x+1(x-2) . 2x^2 y= x^2-4x . 1 y= x+2 (in middle) -3 . x^2+5 y= x-5 you think you can help me by today ? 1 solutions Answer 306289 by stanbon(57967)   on 2011-05-03 09:35:27 (Show Source): You can put this solution on YOUR website! I Dont Understand How Do Do These Problems: It Says I have to identify any holes or vertical asymptotes? They Are All Over Each Other It starts with Y over the numbers . x+3 ----- y = ?/(x+3) Vertical asymptote at x = -3 ------------------------------------- y= x+3 . x-2 --- y = (x+3)/(x-2) Vertical asymptote at x = 2 Horizontal asymptote at y = x/x = 1 ---------------------------------------- y= (x+1(x-2) . 2x^2 --- y = [(x+1)(x-2)]/(2x^2) = [x^2-3x+2)/(2x^2) VA at x = 0 HA at x = x^1/(2x^2) = 1/2 ------------ I can't make out the next few fractions. Cheers, Stan H. =================== y= x^2-4x . 1 y= x+2 (in middle) -3 . x^2+5 y= x-5

Polynomials-and-rational-expressions/444236: FIND THE ZEROS OF EACH FUNCTION BY FACTORING F(X)=Xto the second power - 3x-10 1 solutions Answer 306288 by stanbon(57967)   on 2011-05-03 09:24:44 (Show Source): You can put this solution on YOUR website! FIND THE ZEROS OF EACH FUNCTION BY FACTORING F(X)=Xto the second power - 3x-10 ------------------- F(x) = x^2-3x-10 ----- Use Inverse FOIL to factor: x^2-5x+2x-10 = 0 --- x(x-5)+2(x-5) = 0 --- (x-5)(x+2) = 0 --- x = 5 or x = -2 ====================== Cheers, Stan H. =====================

Rational-functions/444211: I dont know how to simplfy each complex fraction.. can you help ? 2/x ______ =? 1- 1/y 2. 3-3/x -------- 1/2 - 1/x These arew what i really need help most at.. thanks byy too if you can 1 solutions Answer 306287 by stanbon(57967)   on 2011-05-03 09:22:02 (Show Source): You can put this solution on YOUR website! simplfy each complex fraction.. can you help ? 2/x ______ =? 1- 1/y ------------------------------ (2/x)/[1-(1/y)] --- = (2/x)/[(y-1)/y] --- Invert the denominator and multiply to get: = (2/x)(y/(y-1) --- = (2y)/(xy-x) ============================================================ 2. 3-3/x -------- 1/2 - 1/x -------------------- (3-(3/x))/[(1/2)-(1/x)] ---- [(3x-3)/x] / [(x-2)/(2x)] ---- Invert and multiply: --- [(3x-3)/x] --- = [3(x-1)(x-2)]/[2x^2] ============================== Cheers, Stan H. ==========

Matrices-and-determiminant/444233: When does the system have a unique solution? Thanks :) 1 solutions Answer 306286 by stanbon(57967)   on 2011-05-03 09:15:16 (Show Source): You can put this solution on YOUR website! When does the system kx+3y=-6 x+(k+2)y=2 have a unique solution? ----------------------------- The slopes must be different. y = (-6-kx)/3 slope = -k/3 ---------------------- y = (-x+2)/(k+2) slope = -1/(k+2) -------------------- Solve: -k/3 = -1/(k+2) Cross-multiply: -k^2-2k = -3 k^2+2k-3 = 0 (k+3)(k-1) = 0 k = -3 or k = 1 ----------------------- The system has a unique solution as long as k does not = -3 or 1. =========================== Cheers, Stan H.

Probability-and-statistics/444138: If the observed value is 8, the expected value is is 5, an the standard error is 2, then the test value used for the z test is equal to what? If the observed value is 7, the expected value is 8, and the standard error is 2, then the test value used for the z test is equal to what? For the conjecture "The average rent of an apartment is more than $750 per month", what is the alternative hypothesis? Is the following a valid null hypothesis? Ho : = 6 1 solutions Answer 306283 by stanbon(57967)   on 2011-05-03 08:58:50 (Show Source): You can put this solution on YOUR website! If the observed value is 8, the expected value is is 5, and the standard error is 2, then the test value used for the z test is equal to what? ---- z(8) = (8-5)/2 = 3/2 ---------------------------- If the observed value is 7, the expected value is 8, and the standard error is 2, then the test value used for the z test is equal to what? z(7) = (7-8)/2 = -1/2 ---------------------------- For the conjecture "The average rent of an apartment is more than $750 per month", what is the alternative hypothesis? --- Ans: The average rent is <= 750 per month. ---------------------------------------------------- Is the following a valid null hypothesis? Ho : = 6 It should say u = 6 to be valid. Ho must be a statement about a population parameter (u or p) ====================================== Cheers, Stan H. ============

Probability-and-statistics/444169: There is a 0.9968 probability that a randomly selected 50-year-old female lives through the year (based on data from the U.S. Department of Health and Human Services). A Fidelity life insurance company charges $226 for insuring that the female will live through the year. If she does not survive the year, the policy pays out $50,000 as a death benefit. From the perspective of the 50-year-old female, what are the values corresponding to the two events of surviving the year and not surviving? If a 50-year-old female purchases the policy, what is her expected value? WORK TRIED: In the event she lives, the value is -$226. In the event she dies, the value is $49,774. 1 solutions Answer 306282 by stanbon(57967)   on 2011-05-03 08:52:20 (Show Source): You can put this solution on YOUR website! There is a 0.9968 probability that a randomly selected 50-year-old female lives through the year (based on data from the U.S. Department of Health and Human Services). ------------------- A Fidelity life insurance company charges $226 for insuring that the female will live through the year. If she does not survive the year, the policy pays out $50,000 as a death benefit. From the perspective of the 50-year-old female, what are the values corresponding to the two events of surviving the year and not surviving? ---- Ans: -226 ; 50,000-226 = 49774 ------------------------- If a 50-year-old female purchases the policy, what is her expected value? WORK TRIED: In the event she lives, the value is -$226. In the event she dies, the value is $49,774. ---- E(x) = 0.9968*(-226) + 0.0032(49774) = -$66 ================================================== Cheers, Stan H. ===========

Probability-and-statistics/444188: At a homeowners' association meeting, a board member can vote yes, vote no, or abstain on a motion. There are three motions on which a board member must vote. a) determine the number of points in the sample space b) construct a tree diagram and determine the sample space. Determine the probability that the board member votes c) no, yes, no in that order d) yes on exactly two of the motions e) yes on at least one motion 1 solutions Answer 306278 by stanbon(57967)   on 2011-05-03 08:43:37 (Show Source): You can put this solution on YOUR website! At a homeowners' association meeting, a board member can vote yes, vote no, or abstain on a motion. There are three motions on which a board member must vote. -------------------- Comment: I am assuming "must vote" includes the member may abstain. -------------------- a) determine the number of points in the sample space Ans: 3*3 = 9 -------------------- b) construct a tree diagram and determine the sample space. motion #1: 1y;1n;1? //motion #2: 2y:2n;2? //motion #3: 3y;3n;3? Determine the probability that the board member votes c) no, yes, no in that order::1/9 --------------------------- d) yes on exactly two of the motions::2/9 ----------------------------------------------- e) yes on at least one motion: 1 -P(all abstain or all "no") = 1-2/9 = 7/9 ================== Cheers, Stan H. ===========

Probability-and-statistics/444205: Find the P-value for the indicated hypothesis test. A manufacturer claims that fewer than 6% of its fax machines are defective. In a random sample of 97 such fax machines, 5% are defective. Find the P-value for a test of the manufacturer's claim. 1 solutions Answer 306276 by stanbon(57967)   on 2011-05-03 08:32:37 (Show Source): You can put this solution on YOUR website! Find the P-value for the indicated hypothesis test. A manufacturer claims that fewer than 6% of its fax machines are defective. This implies to have a left-tail test. -------------------------------------- In a random sample of 97 such fax machines, 5% are defective. Find the z-value of that sample proportion: z(0.05) = (0.05-0.06)/sqrt[0.05*0.95/97] = -0.4520 ------------------------ Find the P-value for a test of the manufacturer's claim. p-value = P(z < -0.4520) = tcdf(-100,-0.4520 when df = 96) = 0.3262 ============ I used a TI-84 to get the p-value ============ Cheers, Stan H.

Probability-and-statistics/444206: Hi Any help you can give me on these problems will be greatly appreciated. 1) The new Twinkle bulb has a standard deviation 35 hours. A random sample of 50 light bulbs is selected from inventory. The sample mean was found to be 500 hours. (a. Find the margin of error E for a 95% confidence interval. Round your answer to the nearest hundredths. (b. Construct a 95% confidence interval for the mean life, mu of all Twinkle bulbs. 2) A standard placement test has a mean of 115 and a standard deviation of  = 10. Determine the minimum sample size if we want to be 95% certain that we are within 3 points of the true mean. 3)An experimental egg farm is raising chickens to produce low cholesterol eggs. A lab tested 16 randomly selected eggs and found that the mean cholesterol was 190 mg with a standard deviation of 18.0 mg. Assume that the population is normally distributed. a. What is the margin of error for a 95% confidence interval? Round your answer to the nearest tenths. b. What is the 95% confidence interval for the population mean cholesterol content for all experimental eggs? Assume that the population is normally distributed. 4. The new Twinkle bulb is being developed to last more than 1000 hours. A random sample of 100 of these new bulbs is selected from the production line. It was found that 64 lasted more than 1000 hours. a. What is the margin of error (E)? Round to the nearest three decimals. b. What is the 95% confidence interval for the population proportion (p) of all Twinkle bulbs? 1 solutions Answer 306274 by stanbon(57967)   on 2011-05-03 08:25:22 (Show Source): You can put this solution on YOUR website! Any help you can give me on these problems will be greatly appreciated. --------- All of your problems are essentially the same. You need a "sample mean"(x-bar) and you need a "margin of error"(ME). The sample mean is provided by the problem narrative. The ME = z*s/sqrt(n) where z depends on the level of confidence, s is the standeard deviation (usually given) and n is the sample size. The Confidence Interval is (x-bar - ME) < u < (x-bar + ME) --------------------------------------------------------------------------- 1) The new Twinkle bulb has a standard deviation 35 hours. A random sample of 50 light bulbs is selected from inventory. The sample mean was found to be 500 hours. (a. Find the margin of error E for a 95% confidence interval. Round your answer to the nearest hundredths. ME = z*s/sqrt(n) ME = 1.96*35/sqrt(50) = 9.7015 ===================================== (b. Construct a 95% confidence interval for the mean life, mu of all Twinkle bulbs. 500-9.7015 < u < 500+9.7015 =================================== Cheers, Stan H.

Probability-and-statistics/444217: Can you please show me how to figure this? Based on a survey at school, it was found that 75% of the boys and 65% of the girls like to watch hockey games. There are an equal number of boys and girls at the school. If someone does NOT like to watch hockey games, what is the approximate probability that the person is a boy? Thank you! 1 solutions Answer 306272 by stanbon(57967)   on 2011-05-03 08:15:55 (Show Source): You can put this solution on YOUR website! Based on a survey at school, it was found that 75% of the boys and 65% of the girls like to watch hockey games. There are an equal number of boys and girls at the school. If someone does NOT like to watch hockey games, what is the approximate probability that the person is a boy? ----------- P(boy | doesn't like) = P(boy AND doesn't like)/P(doesn't like) --- P(doesn't like) = (0.25+0.35)/2.00 = 0.30 = 0.25/0.30 --- = 5/6 ================== Cheers, Stan H.

Linear-systems/444218: I am having trouble simplifying this. {12+[6(9x+2y)]}-[8(4x+19y)] 1 solutions Answer 306268 by stanbon(57967)   on 2011-05-03 08:03:47 (Show Source): You can put this solution on YOUR website! duplicate

Linear-systems/444219: I am having trouble simplifying this {12+[6(9x+2y)]}-[8(4x+19y)] 1 solutions Answer 306267 by stanbon(57967)   on 2011-05-03 08:02:39 (Show Source): You can put this solution on YOUR website! {12+[6(9x+2y)]}-[8(4x+19y)]} ----- = {12+[54x+12y]}-[32x+152y]} = {12+54x+12y-32x-152y} --- = 22x -140y + 12 ==================== Cheers, Stan H. ==========

Probability-and-statistics/444133: Are the following statements a valid pair of null and alternative hypothesis? Ho: U> 5 and Ha: u<17? Is the following a valid null statement? Ho : 13=11? 3.) Assume that a 95% confidence interval for the mean is (13.0, 15.0). What is the result of a hypothesis test of Ho u =1.0 at a (alpha) = 0.05? 1 solutions Answer 306232 by stanbon(57967)   on 2011-05-02 22:56:51 (Show Source): You can put this solution on YOUR website! Are the following statements a valid pair of null and alternative hypothesis? Ho: U> 5 and Ha: u<17? ---- No; Equality must ALWAYS be stated in Ho. ---------------------------------------------------- Is the following a valid null statement? Ho : 13=11? No; it is a contradiction : it does not make a statement about a population parameter. ---------------------------------------------------- 3.) Assume that a 95% confidence interval for the mean is (13.0, 15.0). What is the result of a hypothesis test of Ho u = 1.0 at a (alpha) = 0.05? --- Reject Ho. ============== Cheers, Stan H.

Probability-and-statistics/444075: What are the numbers used in making a box-and-whisker plot? (a) Low value, Q1, mean, Q3, high value (b) Low value, Q1, median, Q3, high value (c) s, mean, s2, interquartile range (d) Q1, Q2, Q3 (e) Low value, interquartile range, high value 1 solutions Answer 306208 by stanbon(57967)   on 2011-05-02 20:59:02 (Show Source): You can put this solution on YOUR website! Ans: b Cheers, Stan H.

Probability-and-statistics/444065: A baseball player has a batting average of 0.16. What is the probability that he has exactly 6 hits in his next 7 at bats? What is the probability ? 1 solutions Answer 306207 by stanbon(57967)   on 2011-05-02 20:56:08 (Show Source): You can put this solution on YOUR website! A baseball player has a batting average of 0.16. What is the probability that he has exactly 6 hits in his next 7 at bats? ----- Binomial Problems with n = 7 and p = 0.16 ----- P(x = 6) = 7C6(0.16)^6*(0.84) = binompdf(7,0.16,6) = 0.00009865.. --------------------- Cheers, Stan H.

Probability-and-statistics/444069: Thirty percent of the population in a southwestern community are Spanish-speaking Americans. A Spanish-speaking person is accused of killing a non-Spanish-speaking American and goes to trial. Of the first 12 potential jurors, only 2 are Spanish-speaking Americans, and 10 are not. The defendant's lawyer challenges the jury selection, claiming bias against her client. The government lawyer disagrees, saying that the probability of this particular jury composition is common. Compute the probability and discuss the assumptions. 1 solutions Answer 306196 by stanbon(57967)   on 2011-05-02 20:27:17 (Show Source): You can put this solution on YOUR website! Thirty percent of the population in a southwestern community are Spanish-speaking Americans. A Spanish-speaking person is accused of killing a non-Spanish-speaking American and goes to trial. ----------------------------------------------------- Of the first 12 potential jurors, only 2 are Spanish-speaking Americans, and 10 are not. The defendant's lawyer challenges the jury selection, claiming bias against her client. The government lawyer disagrees, saying that the probability of this particular jury composition is common. Compute the probability and discuss the assumptions. ------- Binomial Problem with n = 12 and p = 0.30 ----------------- P(x = 2) = 12C2(0.3)^2*(0.7)^10 = binompdf(12,0.3,2) = 0.1678 = 16.78% ------------------------------ So the probabiity of that happenin is close to 17%. I'll leave the discussion to you. ----- Cheers, Stan H.

Numeric_Fractions/444047: Pond depth. On July 1, Garrett’s Pond was 25 ft deep. Since that date, the water level has dropped ft per week. For what dates will the water level not exceed 21 ft? 1 solutions Answer 306185 by stanbon(57967)   on 2011-05-02 19:56:02 (Show Source): You can put this solution on YOUR website! Pond depth. On July 1, Garrett’s Pond was 25 ft deep. Since that date, the water level has dropped ?? ft per week. For what dates will the water level not exceed 21 ft? ----------------------- A number is missing from your post. See ??. Cheers, Stan H.

Polynomials-and-rational-expressions/443904: Biologist want to set up a station to test alligators in the lake for West Nile virus. Suppose that the costs for such a station are $2,500 for setup costs and $3.00 to administer each test. a.) write an expression that gives the total cost to test x animals. b.) you can find the average cost per animal by dividing total costs by number of animals. write the expression that gives the average cost per animal. c.) find the average cost per animal for 10 animals, 100 animals, and 1,000 animals. d.) as the number of animals tested increases, what happens to the average cost to test the animals? would the average cost ever fall below $3.00? if so, identify a value that supports your anser. if not, explain how you know. e.) how many animals should be tested for the average cost to be $5.00 per animal? 1 solutions Answer 306118 by stanbon(57967)   on 2011-05-02 16:38:02 (Show Source): You can put this solution on YOUR website! Biologist want to set up a station to test alligators in the lake for West Nile virus. Suppose that the costs for such a station are $2,500 for setup costs and $3.00 to administer each test. a.) write an expression that gives the total cost to test x animals. --- C(x) = 2500 + 3x ----------------------------------- b.) you can find the average cost per animal by dividing total costs by number of animals. write the expression that gives the average cost per animal. --- A(x) = (2500+3x)/x ----------------------------------- c.) find the average cost per animal for 10 animals, 100 animals, and 1,000 animals. --- Find A(10), A(100) and A(1000) ----------------------------------- d.) As the number of animals tested increases, what happens to the average cost to test the animals? :::it decreases. ----- would the average cost ever fall below $3.00? :: No ------------------------------------------------------ If so, identify a value that supports your answer. A(5000) = (2000+3*5000)/5000 = 17/5 = $3.40 ------------- if not, explain how you know. e.) how many animals should be tested for the average cost to be $5.00 per animal? --- Solve: 5.00 = (2000+3x)/x 5x = 2000+3x 2x = 2000 x = 1000 ---------------- Cheers, Stan H.

Evaluation_Word_Problems/443903: One gear turns times in a minute. Another gear turns 45 times in a minute. Initially, a mark on each gear is pointing due north. After how many seconds will the two gears next have both their marks pointing due north? 1 solutions Answer 306112 by stanbon(57967)   on 2011-05-02 16:24:25 (Show Source): You can put this solution on YOUR website! One gear turns ?? times in a minute. Another gear turns 45 times in a minute. Initially, a mark on each gear is pointing due north. After how many seconds will the two gears next have both their marks pointing due north? ------------------------ Your post is missing a needed number in the 1st sentence. Cheers, Stan H.

Probability-and-statistics/443770: Please help Records of individuals from France who died recently are selected at random. The individuals lived an average of years with a standard deviation of years. Records of individuals from Germany who died recently are selected at random and independently. The individuals lived an average of years with a standard deviation of years. Assume that the population standard deviations of the life expectancies can be estimated by the sample standard deviations, since the samples that are used to compute them are quite large. At the level of significance, is there enough evidence to support the claim that the life expectancy, , in France is greater than the life expectancy, , in Germany? Perform a one-tailed test. 1) The null hypothesis 2) The alternative hypothesis 3) The type of test statistic (ex. Z, t, Chi-Square, etc.) 4) The value of the test statistic 5) The p value 6) YES or NO 1 solutions Answer 306026 by stanbon(57967)   on 2011-05-02 12:26:41 (Show Source): You can put this solution on YOUR website! I don't know why this happens so often on this site but your post is missing the "mean" number and the "standard deviation" number. Both are essential to working your problem. Cheers, Stan H.

Triangles/443778: If the lengths of two sides of a triangle are 4 and 13, what is the range of possible lengths for the third side? 1 solutions Answer 306025 by stanbon(57967)   on 2011-05-02 12:22:56 (Show Source): You can put this solution on YOUR website! If the lengths of two sides of a triangle are 4 and 13, what is the range of possible lengths for the third side? ---- Let the 3rd side be "s". --- The 13-4 < s < 13+4 9 < s < 17 ==================== Cheers, Stan H.

Volume/443513: The lenght of the side of a square is increase by 50%. By what % is the area of the square increase. 1 solutions Answer 305901 by stanbon(57967)   on 2011-05-01 21:55:21 (Show Source): You can put this solution on YOUR website! The length of the side of a square is increase by 50%. By what % is the area of the square increase. ------------------------------ If side = "s", area = s^2. --- If s is increased by 50% you get (1.5s) Area will be (1.5s)^2 = 2.25s^2 --- Increase = 2.25s^2-s^2 = 1.25s^2 --- % increase = (1.25s^2)/s^2 = 1.25 = 125% increase =============================== Cheers, Stan H.

Miscellaneous_Word_Problems/443507: "Please help!!! I cannot figure out the answer to this question. I've tried different formulas and still can't get the right answer. If I can find the right formula this will help out tremendously. Here is the question: A farm brings 15 tons of watermelon to market. Find a 90% confidence interval for the population mean cash value of this crop. What is the margin of error? Hint: 1 ton is 2000 pounds. (Round your answers to two decimal places.) 1 solutions Answer 305886 by stanbon(57967)   on 2011-05-01 20:59:48 (Show Source): You can put this solution on YOUR website! A farm brings 15 tons of watermelon to market. Find a 90% confidence interval for the population mean cash value of this crop. What is the margin of error? Hint: 1 ton is 2000 pounds. (Round your answers to two decimal places.) ------ It appears that the sample mean is 15 tons. No unit price sees to be available. No standard deviation value is stated. ----- The margin of error is zs/sqrt(n) -- For a 90% CI z = 1.645 ---- The CI will be 15-1.645s/sqrt(n) < u < 15+1.645s/sqrt(n) -------------------------------------------------------------- Cheers, Stan H.

Mixture_Word_Problems/443407: a recipe for sauce makes 12 1/2 oz., and the recipe calls for 7 oz puree. you want to make thirty 1 1/2 oz servings. how many oz of puree should you use? 1 solutions Answer 305850 by stanbon(57967)   on 2011-05-01 18:26:38 (Show Source): You can put this solution on YOUR website! A recipe for sauce makes 12 1/2 oz., and the recipe calls for 7 oz puree. you want to make thirty 1 1/2 oz servings. how many oz of puree should you use? -------------------- puree/(30*(3/2)) = 7 oz/(25/2)oz --- puree/45 = 7/12.5 ---- puree = (315/12.5) = 25.2 oz. ====================================== Cheers, Stan H.

Polygons/443410: Which polygon has 2 times as many angles as a pentagon? 1 solutions Answer 305842 by stanbon(57967)   on 2011-05-01 18:12:33 (Show Source): You can put this solution on YOUR website! Which polygon has 2 times as many angles as a pentagon? ---------------------- Ans: decagon

Probability-and-statistics/443406: A study conducted at a certain college shows that 65% of the school's graduates find a job in their chosen field within a year after graduation. Find the probablity that among 5 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduation. My teacher gave me the answer of 0.995, I was wondering what steps/how to begin this problem. I have tried nCr = n! / r!(n - r)! = nPr / r! to slove this, using p = .65, n = 5, and r = 1. And have not been able to get the correct answer. Thank you!!! 1 solutions Answer 305838 by stanbon(57967)   on 2011-05-01 18:09:51 (Show Source): You can put this solution on YOUR website! A study conducted at a certain college shows that 65% of the school's graduates find a job in their chosen field within a year after graduation. Find the probablity that among 5 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduation. My teacher gave me the answer of 0.995, I was wondering what steps/how to begin this problem. ------------------- P(a single student finds a job) = 0.65 P(a student does not find a job) = 0.35 ------------------ Binomial Problem with n = 5 ; p(finds a job) = 0.65 --- Problem: Find P(at least one of 5 finds a job) = 1 - P(none of 5 find a job) --- = 1 - (0.35)^5 --- = 1 - 0.005252 ------------- = 0.9947 ========================== Cheers, Stan H.

Equations/443386: Show the work to solve |2x+5| -1 < 6 Describe the graph of the solution in a complete sentence 1 solutions Answer 305832 by stanbon(57967)   on 2011-05-01 18:00:10 (Show Source): You can put this solution on YOUR website! Show the work to solve |2x+5| -1 < 6 Describe the graph of the solution in a complete sentence ---------------------- |2x+5| -1 < 6 --- |2x+5| < 7 --- 2x+5< -7 or 2x+5> 7 ----- 2x < -12 or 2x > 2 ---- x < -6 or x > 1 ====================== Cheers, Stan H.