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Recent problems solved by 'stanbon'
stanbon answered: 57314 problems
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2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 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56970..56999 , 57000..57029 , 57030..57059 , 57060..57089 , 57090..57119 , 57120..57149 , 57150..57179 , 57180..57209 , 57210..57239 , 57240..57269 , 57270..57299 , 57300..57329, >>NextFinance/729463: Find the amount if $500 is invested at 15% compounded monthly for 17 months.
Amount = $ 1 solutions
Answer 445879 by stanbon(57387) on 2013-03-22 15:16:13 (Show Source):
You can put this solution on YOUR website!Find the amount if $500 is invested at 15% compounded monthly for 17 months.
---------
A(t) = P(1+(r/n))^(nt)
---
A(17/12) = 500(1+(0.15/12))^(12(17/12)
-----
A(17/12) = 500(1.0125)^(17)= $617.57
------------------------
Cheers,
Stan H.
=================
|
Age_Word_Problems/729473: brittany is 5 years older than three times the age of her brother. The sum of their ages is 21. if x represents the age of her brother, write an equation that represents this situation 1 solutions
Answer 445877 by stanbon(57387) on 2013-03-22 15:01:33 (Show Source):
You can put this solution on YOUR website!brittany is 5 years older than three times the age of her brother. The sum of their ages is 21. if x represents the age of her brother, write an equation that represents this situation
-----
Equations:
t = 3b + 5
t + b = 21
-------
Substitute for "t" and solve for "b":
3b+5+b = 21
4b = 16
Brother's age = 4 years
Brit's age = 3*4+5 = 17 years
==============================
Cheers,
Stan H
|
percentage/729471: Can you please help me with this? Thank you so much for your time!
Tyrone pays $5 for a lottery ticket. There is a .1% chance that he will win $200, a 1% chance that he will win $50, and a 5.2% chance that he will win $25 (Otherwise he wins nothing). Find his expected payoff. How much can he expect to win or lose on average? Don't forget to include the price of the ticket! 1 solutions
Answer 445871 by stanbon(57387) on 2013-03-22 14:51:32 (Show Source):
You can put this solution on YOUR website!Tyrone pays $5 for a lottery ticket. There is a .1% chance that he will win $200, a 1% chance that he will win $50, and a 5.2% chance that he will win $25 (Otherwise he wins nothing). Find his expected payoff. How much can he expect to win or lose on average? Don't forget to include the price of the ticket!
-----
Random Winning values: ......195......45.....20.........-5
Probabilities::::::::: .......1/100...1/100..5.2/100...92.8/100
--------------
Expected winnings = [195 + 45 + 104 -464]/100 = -120/100 = -$1.20
-------------------
Cheers,
Stan H.
===================
|
Probability-and-statistics/729303: Two dice are rolled in a game you pay $1.00 to play. If a total lower than 5 comes up, you win $5.00, if a total greater than 9 comes up you win $2.00, otherwise you lose your dollar for playing. Calculate the expected value of playing,and the price of the game making it fair.
Good luck, I'm not einstein. 1 solutions
Answer 445809 by stanbon(57387) on 2013-03-21 22:50:55 (Show Source):
You can put this solution on YOUR website!Two dice are rolled in a game you pay $1.00 to play.
--------------------------------------------------------
If a total lower than 5 comes up, you win $5.00,
ways to do that: 1/1,1/2,1/3,2/1,2/2,3/1 -----6 ways
--------------------------------------------------------
if a total greater than 9 comes up you win $2.00,
Ways to do that:
4/6----------------------1
5/5,5/6------------------2
6/4,6/5,6/6--------------3
Total-----------------------------------------6 ways
otherwise you lose your dollar for playing.
Total-----------------------------------------24 ways
===========================================================
Calculate the expected value of playing,
Random Value:.....$4......$1......-1
Probabilities.....1/6.....1/6.....4/6
----
Expected gain: (4 + 1 - 4)/6 = 1/6 or 16 2/3 cents
--------
and the price of the game making it fair.
You should pay $1.67 to play
Then your expected winning would be zero and the game would be fair.
================================
Cheers,
Stan H
|
Probability-and-statistics/729292: 3. A box contains 40 computer disks, 5 of which are defective. Three disks are selected from the box (without replacement and regard to order). What is the probability that
(a) all three of the disks are defective?
(b) none of the three disks are defective?
(c) exactly one of the three disks is defective?
(d) at least one of the three disks works?
1 solutions
Answer 445808 by stanbon(57387) on 2013-03-21 22:31:52 (Show Source):
You can put this solution on YOUR website!A box contains 40 computer disks, 5 of which are defective. Three disks are selected from the box (without replacement and regard to order). What is the probability that
------------------------------------
(a) P(all three of the disks are defective) = 5C3/40C3
-----------------------------------------------------
(b) P(none of the three disks are defective) = 35C3/40C3
-----------------------------------------------------
(c) P(exactly one of the three disks is defective) = [5*35*34]/[40*39*38]
============
================
(d) P(at least one of the three disks works) = 1 - (answer to b)
=================
Cheers,
Stan H.
|
Linear-equations/729289: FIND ANY TWO LINEAR EQUATIONS PASSING THROUGH THE POINT (-1,-1/2). HOW MANY SUCH EQUATIONS ARE POSSIBLE
1 solutions
Answer 445800 by stanbon(57387) on 2013-03-21 22:09:13 (Show Source):
You can put this solution on YOUR website! FIND ANY TWO LINEAR EQUATIONS PASSING THROUGH THE POINT (-1,-1/2). HOW MANY SUCH EQUATIONS ARE POSSIBLE
-----
Form: y = mx + b
---
Let the slope be "m".
Solve for "b":
-1/2 = m(-1) + b
b = m-(1/2)
-----
Equation:
y = mx + m-1/2)
----
y = m(x+1)-(1/2
====================
Cheers,
stan H.
================
|
Exponential-and-logarithmic-functions/729290: How do I solve f(x)= (x-4)^2 where x is less than equal to 4?
I'm having trouble solving and finding the domain? 1 solutions
Answer 445799 by stanbon(57387) on 2013-03-21 22:05:47 (Show Source):
You can put this solution on YOUR website! How do I solve f(x)= (x-4)^2 where x is less than equal to 4?
I'm having trouble solving and finding the domain?
-------
You can graph it but you can't "solve" it.
----------------------------------
The graph looks like the left-half of a parabola with vertes at (4,0)
and opening upward.
----------------------------
If x is less than or equal to 4, that IS the domain.
----
Cheers,
Stan H.
================
|
Geometry_proofs/729283: Suppose tanθ=-3/4 and π/2<θ<π. Evaluate the five remaining trigonometric functions of θ. 1 solutions
Answer 445797 by stanbon(57387) on 2013-03-21 22:02:30 (Show Source):
You can put this solution on YOUR website!Suppose tanθ=-3/4 and π/2<θ<π. Evaluate the five remaining trigonometric functions of θ.
----
Theat is in QII where x is negative, y is positive, r is always positive.
----
Since tan(theta) = y/x = -3/4, y = 3 and x = -4
---
Then r = sqrt(3^2 + 4^2] = 5
----
sin = y/r = 3/5
cos = x/r = -4/5
tan = -3/4
csc = r/y = 5/3
sec = r/x = -5/4
cot = -4/3
============
Cheers,
Stan H.
|
logarithm/729266: Stars of magnitude m are visible through a telescope of minimum diameter d (in inches). the relationship is m=8.8 + 5.1 log d.
Round your answer to one decimal place.
1. a telescope with diamter 75 inches can detect a star of magnitude m = ____.
2. a star of magnitude 10.6 can be detected using a telescope with lens diameter d = ______ inches
for the firs problem I substituted 75 in for d. m= 8.8 + 5.1 log 75. I then solved for log 75 which is 1.875. m = 8.8 + 5.1(1.875). I then solved for m to be 18.4.
the second problem I substituted 10.6 in for m. 10.6 = 8.8 + 5.1 log d.
I didn't know what to do or if the first part is correct. Please help. 1 solutions
Answer 445795 by stanbon(57387) on 2013-03-21 21:45:45 (Show Source):
You can put this solution on YOUR website!Stars of magnitude m are visible through a telescope of minimum diameter d (in inches). the relationship is m(d) = 8.8 + 5.1 log d.
Round your answer to one decimal place.
1. a telescope with diamter 75 inches can detect a star of magnitude
m(75) = 8.8 + 5.1*log(75) = 18.37
-----------------------------------------
2. a star of magnitude 10.6 can be detected using a telescope with lens
Solve: 10.6 = 8.8+5.1*log(d)
5.1*log(d) = 1.8
log(d) = 0.3529
d = 10^0.3529 = 2.2539 inches
-----------------------------------
Cheers,
Stan H.
|
Probability-and-statistics/729132: A binomial distribution has 100 trials (n = 100) with a probability of success of 0.25 (π=0.25). We would like to find the probability of 75 or more successes using the normal distribution to approximate the binomial. Applying the continuity correction factor, what value would be used to calculate a z-score?
74.5
75
75.5
25
1 solutions
Answer 445792 by stanbon(57387) on 2013-03-21 21:20:25 (Show Source):
You can put this solution on YOUR website!A binomial distribution has 100 trials (n = 100) with a probability of success of 0.25 (π=0.25). We would like to find the probability of 75 or more successes using the normal distribution to approximate the binomial. Applying the continuity correction factor, what value would be used to calculate a z-score?
---------------
74.5 ; 75 ; 75.5 ; 25
-------
Ans: 74.5
----------------
Cheers,
Stan H.
|
Probability-and-statistics/729221: Approximately 40% of the Wisconsin population have type O blood. If 4 persons are selected at random to be donors, find P[at least one type O]. Round your answer to four decimal places.
1 solutions
Answer 445782 by stanbon(57387) on 2013-03-21 20:57:10 (Show Source):
You can put this solution on YOUR website!Approximately 40% of the Wisconsin population have type O blood. If 4 persons are selected at random to be donors, find P[at least one type O]. Round your answer to four decimal places.
P(at least 1) = 1 - P(none)
-----
= 1 - 0.6^4
-----
= 1 - 0.1296
-------
= 0.8704
====================
Cheers,
Stan H.
====================
|
Probability-and-statistics/729071: A probability experiment consist of two possible outcomes: Event A and Event B. Event A is 3 times more likely that Event B. Calculate the probability of Event A (rounded to two decimals). 1 solutions
Answer 445780 by stanbon(57387) on 2013-03-21 20:48:04 (Show Source):
You can put this solution on YOUR website!A probability experiment consist of two possible outcomes: Event A and Event B. Event A is 3 times more likely that Event B. Calculate the probability of Event A (rounded to two decimals).
------
Let P(A) = 3x
Let P(B) = x
-----
Equation:
x + 3x = 1
4x = 1
x = 1/4 (Probability of B)
3x = 3/4 (Probability of A)
---------------------------
Cheers,
Stan H.
===================
|
Mixture_Word_Problems/729079: How many pounds of salted nuts selling at $1.60 per pound should be mixed with 2 pounds of salted nuts selling for $2.20 per pound to obtain a mixture selling for $1.72 per pound? 1 solutions
Answer 445689 by stanbon(57387) on 2013-03-21 16:01:23 (Show Source):
You can put this solution on YOUR website! How many pounds of salted nuts selling at $1.60 per pound should be mixed with 2 pounds of salted nuts selling for $2.20 per pound to obtain a mixture selling for $1.72 per pound?
----
Equation:
value + value = value
1.6x + 2.2*2 = 1.72(x+2)
-----
160x + 220*2 = 172x + 172*2
-------------------
12x = 48*2
x = 8 lbs. (amt. of $1.60 per pound nuts needed)
===============
Cheers,
Stan H.
===============
|
Quadratic_Equations/728609: Stuck and needs help with these math problems please help
1. Solve: x/3 = 3/x-8
2. Solve: 3x + 2/x + 2 - 1 = 2x
3. Solve: (x-2)(x-4)(x+1)<0
4. Solve: 3x/x-5 <5 1 solutions
Answer 445561 by stanbon(57387) on 2013-03-20 18:46:42 (Show Source):
You can put this solution on YOUR website!1. Solve: x/3 = 3/x-8
x(x-8) = 9
x^2-8x-9 = 0
(x-9)(x+1) = 0
x = 9 or x = -1
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2. Solve: 3x + 2/x + 2 - 1 = 2x
(3x+2)/(x+2) - 1 = 2x
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3x+2 - (x+2) = 2x(x+2)
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3x+2 -x-2 = 2x^2+4x
2x^2 +2x + 2 = 0
x^2 + x + 1 = 0
Use the Quadratic formula.
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3. Solve: (x-2)(x-4)(x+1)<0
Draw a Number Line.
Plot: x = -1, x = 2, x = 4
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Test a value in each interval.
Test x = -10: -*-*- < 0 true
Test x = 0 : -*-*+ < 0 false
Test x = 3 : +*-*+ < 0 true
Test x = 10 : +*+*+ < 0 false
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Solution:(-oo,-1)U(2,4)
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Cheers,
Stan H.
===============
4. Solve: 3x/x-5 <5
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Circles/728616: Please help!!! The circumference of a circular plate is 94.2 centimeters. Find the radius of the plate. Use 3.14 as an approximation 1 solutions
Answer 445524 by stanbon(57387) on 2013-03-20 16:03:51 (Show Source):
You can put this solution on YOUR website!The circumference of a circular plate is 94.2 centimeters. Find the radius of the plate. Use 3.14 as an approximation
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C = 2*pi*r
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94.2 = 2*(3.14)*r
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r = 94.2/(6.28)
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radius = 15 cm
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Cheers,
Stan H.
=====================
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Probability-and-statistics/728322: A certain game has two stacks of 30 tiles with pictures on them. In the first stack of tiles, there are 10 dogs, 4 cats, 5 balls, and 11 horses. In the second stack of tiles, there are 3 flowers, 8 fish, 12 balls, 2 cats, and 5 horses. The top tile in each stack is chosen. Find each probabillity.
1. P(neither is a horse)
2. P(exactly one is a fish)
1 solutions
Answer 445517 by stanbon(57387) on 2013-03-20 15:54:25 (Show Source):
You can put this solution on YOUR website! A certain game has two stacks of 30 tiles with pictures on them.
In the first stack of tiles, there are 10 dogs, 4 cats, 5 balls, and 11 horses.
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In the second stack of tiles, there are 3 flowers, 8 fish, 12 balls, 2 cats, and 5 horses.
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The top tile in each stack is chosen. Find each probabillity.
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The events (selecting) are independent.
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1. P(neither is a horse) = (19/30)(25/30) = 0.5278
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2. P(exactly one is a fish) = (1)(8/30) = 8/30
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Cheers,
Stan H.
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Probability-and-statistics/728559: An apartment complex has two activating devices in each fire detector. One is smoke-activated and has a probability of .98 of sounding an alarm when it should. The second has a heat sensitive activator and has a probability of .95 of operating when it should. Each activator operates independently on the other. Presume a fire starts near a detector. What is the probability that both will work properly? 1 solutions
Answer 445515 by stanbon(57387) on 2013-03-20 15:47:58 (Show Source):
You can put this solution on YOUR website!An apartment complex has two activating devices in each fire detector. One is smoke-activated and has a probability of .98 of sounding an alarm when it should. The second has a heat sensitive activator and has a probability of .95 of operating when it should. Each activator operates independently on the other. Presume a fire starts near a detector. What is the probability that both will work properly?
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Their operation is an independent event.
Ans: 0.98*0.95 = 0.931
========================
Cheers,
Stan H.
========================
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Equations/728520: I need to use the discriminant to determine the number and type of solutions for this equation: x^2+2x=-11
Thanks! 1 solutions
Answer 445475 by stanbon(57387) on 2013-03-20 12:48:18 (Show Source):
You can put this solution on YOUR website! I need to use the discriminant to determine the number and type of solutions for this equation: x^2+2x=-11
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a = 1
b = 2
c = 11
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b^2-4ac = 2^2-4*1*11 = 4-44 < 0
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Since the discriminant is negative there are 2 complex number solutions.
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Cheers,
Stan H.
==============
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Exponents/728512: Find the power of i
(-i)42
Possible answers:
A) (-i)2
B) 1
C) i
D) -i
E) -1 1 solutions
Answer 445474 by stanbon(57387) on 2013-03-20 12:44:55 (Show Source):
You can put this solution on YOUR website!(-i)^42 = (i^3)^(42) = i^(126) = (i^4)^31*i^2 = 1*(-1) = -1
========================
Cheers,
Stan H.
========================
Possible answers:
A) (-i)2
B) 1
C) i
D) -i
E) -1
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Quadratic_Equations/728509: Write a quadratic equation having the given numbers as solutions.
8/5, 5/3
Possible answers:
A) 3x2 -40x + 25=0
B) 3x2 + 25x + 40=0
C) 3x2 + 49/5x + 8=0
D) 3x2 -49/5x + 8=0
E) 3x2 + 40x + 25=0 1 solutions
Answer 445472 by stanbon(57387) on 2013-03-20 12:34:55 (Show Source):
You can put this solution on YOUR website!Write a quadratic equation having the given numbers as solutions.
8/5, 5/3
Possible answers:
f(x) = k(5x-8)(3x-5)
f(x) = k(5x^2-49x+40)
Let k = (3/5)
Then
f(x) = 3x^2 - (3/5)49x + (3/5)40
f(x) = 3x^2 - 29.4x + 24
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Comment: The optional answers do not match the posted problem.
------
Cheers,
Stan H.
=====================
A) 3x2 -40x + 25=0
B) 3x2 + 25x + 40=0
C) 3x2 + 49/5x + 8=0
D) 3x2 -49/5x + 8=0
E) 3x2 + 40x + 25=0
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Probability-and-statistics/728372: A hundred squash balls are tested by dropping from a height of 100 inches and measuring the height of the bounce. A ball is “fast” if it rises above 32 inches. The average height of bounce was 30 inches and the standard deviation was ¾ inches. What is the chance of getting a “fast” standard ball?
PLEASE PROVIDE A STEP BY STEP SOLUTION FOR BETTER UNDERSTANDING 1 solutions
Answer 445471 by stanbon(57387) on 2013-03-20 12:24:35 (Show Source):
You can put this solution on YOUR website!A hundred squash balls are tested by dropping from a height of 100 inches and measuring the height of the bounce.
A ball is “fast” if it rises above 32 inches.
The average height of bounce was 30 inches and the standard deviation was ¾ inches.
-------------------
What is the chance of getting a “fast” standard ball?
z(32) = (32-30)/(3/4) = 8/3
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P(x > 32) = P(z > 8/3) = normalcdf(8/3,100) = 0.0038
=====================
cheers,
Stan H.
============
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Probability-and-statistics/728393: An Adweek Media/Harris Poll revealed that 44% of US adults in the 18-34 years category think that "Made in America" ads boost sales.
A different Harris Interactive poll showed that 78% of US adults in the 18-34 years category use social media online.
Suppose that 85% of US adults in the 18-34 years category think that "Made in America" ads boost sales or use social media online.
If a US adult in the 18-34 years category is randomly selected a.
What is the probability that the person thinks "Made in America" ads boost sales AND uses social media on-line &
b. What is the probability that the person thinks that "Made in America ads boost sales given that the person does not use social media on-line?
-------------------- 1 solutions
Answer 445470 by stanbon(57387) on 2013-03-20 12:18:18 (Show Source):
You can put this solution on YOUR website!A) 44% of US adults in the 18-34 years category think that "Made in America" ads boost sales.
----------------------
B) 78% of US adults in the 18-34 years category use social media online.
----------------------
Suppose that 85% of US adults in the 18-34 years category think that "Made in America" ads boost sales OR use social media online.
====================================================================
If a US adult in the 18-34 years category is randomly selected
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a. What is the probability that the person thinks "Made in America" ads boost sales AND uses social media on-line &
Ans: P(A AND B) = P(A)+P(B)-P(A or B) = 0.44+0.78-0.85 = 0.37
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b. What is the probability that the person thinks that "Made in America ads boost sales given that the person does not use social media on-line?
P(A | B) = P(A and B)/P(B) = 0.37/0.78 = 0.4744
=====================================================
Cheers,
Stan H.
=================
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Probability-and-statistics/728498: what is the probability of a baseball player getting 3 hits if his average is .359
b not hitting a in game
c. getting a least one hit 1 solutions
Answer 445467 by stanbon(57387) on 2013-03-20 12:06:22 (Show Source):
You can put this solution on YOUR website!a. what is the probability of a baseball player getting 3 hits if his average is .359
Ans: 0.359^3
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b P(not hitting a hit in game) = (1-0.359)^3 = 0.2634
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c. P(getting a least one hit) = 1 - P(no hits) = 0.7366
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Cheers,
Stan H.
=================
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Probability-and-statistics/728379: The weight of the eggs produced by a certain breed of hen is Normally distributed with a mean of 65 grams and a standard deviation of 5 grams.
Calculate the probability that a randomly selected egg weighs between 62.5g and 68.75g. Show your work.
My work:
Dont you need a population of how many eggs are produced by a hen before you start the equation? If not, how do I do this? 1 solutions
Answer 445466 by stanbon(57387) on 2013-03-20 12:00:48 (Show Source):
You can put this solution on YOUR website! The weight of the eggs produced by a certain breed of hen is Normally distributed with a mean of 65 grams and a standard deviation of 5 grams.
Calculate the probability that a randomly selected egg weighs between 62.5g and 68.75g. Show your work.
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z(62.5) = (62.5-65)/5 = -0.50
z(68.75) = (68.75-65)/5 = 0.75
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P(0.62.5<= x <=68.75) = P(-0.5<= z <=0.75) = 0.4649
====================================
Cheers,
Stan H.
======================
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Probability-and-statistics/728408: 7% of the items produced on a machine in the past have been defective. If 15 of the items produced during a day are selected at random, calculate the probability that:
eatleast two of the items is deffective
This is my attempt: 2/15 (7%) + 3/15 (7%) = 0.093 + 0.014 = 0.107 1 solutions
Answer 445465 by stanbon(57387) on 2013-03-20 11:54:21 (Show Source):
You can put this solution on YOUR website! 7% of the items produced on a machine in the past have been defective. If 15 of the items produced during a day are selected at random, calculate the probability that: at least two of the items are defective
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P(2<= x <=15) = 1 - P(0<= x <=1) = 1 - [(0.93)^15 + (15(0.07)(0.93)^14]
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= 1 - [0.7168]
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= 0.2832
-----------------
Cheers,
Stan H.
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