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a) quadrilateral
b) rectangle
c) parallelogram
d) rhombus
1 solutions
Answer 319665 by solver91311(16897)   on 2011-07-01 11:18:52 (Show Source):
You can put this solution on YOUR website!
Since vertices A and D have equal y-coordinates we can conclude that segment AD lies in a horizontal line. Likewise, since vertices B and C have equal y-coordinates, segment BC lies in a horizontal line. Since the y-coordinate of A is different than the y-coordinate of B, segments AD and BC lie in different horizontal lines and are therefore parallel to each other.
Using the coordinates of points A and B, we can calculate the slope of the line containing segment AB. Similarly we can calculate the slope of the line containing segment CD. I leave it as an exercise for the student to show that the two described slopes are equal and therefore the two described segments are parallel.
The slope of a horizontal line is zero, therefore the slope of a vertical line is undefined. One pair of sides is horizontal and the other pair has been shown to have a defined slope. Therefore, we have disabused ourselves of the notion that the angles at each of the vertices might possibly be right angles, and thereby have excluded rectangle as an appropriate description for ABCD.
The measure of AD can clearly be seen to be 9 (square root of -9 squared plus 0 squared).
The measure of AB is ^2\ +\ (4)^2) . I'll leave it to you to verifiy that this is not equal to 9, thereby excluding rhombus as a possible description of ABCD.
That leaves quadrilateral or parallelogram. Since we have shown that there are two pairs of parallel sides, the answer should be obvious at this point.
John
My calculator said it, I believe it, that settles it
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Rectangles/466327: A rectangle has the length of 1.4 ft and a width of 1.2 ft . What is the effect on the perimeter if the length and width are doubled ?
1 solutions
Answer 319658 by solver91311(16897) on 2011-07-01 10:47:06 (Show Source):
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Money_Word_Problems/466266: This is a two part question; I have an idea on the second part which is graphing the equation but this first part I cannot solve.
Media services charges $40 for a phone and $20/month for its econonmy plan.
The equation c=20t + 40 describes the total cost, C of operating a Media Service phone for T months.
The total cost for 8 months of service is $?
My question is will I have to plug in the 8 were the t is like this:
c=20(8) + 40
1 solutions
Answer 319595 by solver91311(16897) on 2011-07-01 00:48:01 (Show Source):
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Average/466124: Rosa is on the school track team and ran the following distances during the past six days 5.6, 4.4, 3.6, 4.2, 5.3, 3.7 If she wantes to run at least a daily average of 4.7 miles over a 7-day period, what is the minimum number of miles she has to run on the seventh day?
My answer was 1.4 but the book has a different answer.
1 solutions
Answer 319470 by solver91311(16897) on 2011-06-30 15:42:37 (Show Source):
You can put this solution on YOUR website!
The challenge for me on this one is trying to figure out the process you used to get to an answer of 1.4, and I confess to being utterly stumped. Except to say that you might have just reached around behind yourself and pulled a number out of your backside -- which would be one possible explaination of why your answer smells bad.
Consider how you go about calculating the average. You add up all of your data elements and then divide by the number of data elements. In order to get an average of 4.7 over 7 days, the sum of the seven data elements must be 4.7 times 7 which is 32.9. So whatever the sum of your first six data points happens to be, subtracted from the required sum for 7 data points, namely 32.9, must be the required number of miles to be run on the last day to achieve the desired average.
AH HA! I went back and found out what you did. You took the sum of the first six data points, 26.8, and then multiplied the required average, 4.7, by 6 to get 28.2, and then took the difference, 1.4. Close but no cigar. What you calculated was the average daily shortfall from a 4.7 average over the first 6 days. In order to achieve a 7 day average of 4.7, on the 7th day you would need to do the 4.7 PLUS that average daily shortfall of 1.4 for a total of 6.1. One way to get there, but the way I described in the previous paragraph is much easier and much less prone to error.
John
My calculator said it, I believe it, that settles it
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Evaluation_Word_Problems/466052: Tracy's dog eats 8 ounces of dog food every day. How many pounds of dog food will her dog eat in 40 days?
So my math teacher said 320 pounds but i know that 16 ounces equal a pound and my teacher said that if the dog eats 8 ounces everday then in 40 days he will eat 40 times the amount the dog eats every day (this is true) but once my teacher did 8 times 40 he got 320 ounces and in the answer space wrote 320 pounds. I was wondering why he never converted the 320 ounces to pounds which would be 320/16 (i think)
please help... :)
1 solutions
Answer 319427 by solver91311(16897) on 2011-06-30 12:55:12 (Show Source):
You can put this solution on YOUR website!
Your math teacher probably got his tongue wrapped around his eye tooth and couldn't see what he was saying. The correct answer is 320 ounces which is 20 pounds.
Put it to him this way:
"So if you are feeding your dog 320 pounds of food every 40 days, then you are feeding your dog about 240 pounds every month since 30 is 3/4 of 40. Since even relatively inexpensive dog food runs nearly $1 per pound these days, that means you are spending $240 per month or nearly $3000 annually. I should eat so well.
"Further, since you say you are feeding 8 ounces per day, you probably have a dog that weighs about 25 lbs. (c.f. Dog Breed Info Center), and that means, at 240 lbs/month of food, you are feeding your dog nearly 10 times his body weight each month. Hope they start "Biggest Loser for Dogs" soon.
"Bottom line, Mr. Math Teacher, math HAS to make sense."
John
My calculator said it, I believe it, that settles it
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Travel_Word_Problems/466029: Last month, Jacob traveled from Miami to New Orleans by train and made two stops along the way. The average speed for the three legs of his trip is defined as v1, v2, v3 respectively. The average speed for the entire trip is given by
3
____________
1---1---1
__ + ___ + __
v1----v2----v3
a. Simplify the complex fraction.
b. Find the average speed for the entire trip when v1 = 101mph, v2 = 71mph,
v3 = 106mph. Round to the nearest mph.
a. 3v1 v2 v3
-------------
v1v2+v1v3+v2v3; b. 91mph
b. 3v1 v2 v3
-------------
v1+V2+v3-----; b. 93mph
c. 3v1v2v3
------------
v1+v2+v3----; b. 90mph
d. 3v1v2v3
------------
v1v3+v2v3---; b. 93mph
e. 3v1v2v3
------------
v1v2+v1v3+v2v3 ; b. 90mph
1 solutions
Answer 319393 by solver91311(16897) on 2011-06-30 11:30:04 (Show Source):
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Triangles/466027: Triangle ABC is similar to triangle XYZ. Side AB measures 2, side BC measures x + 5, side CA measures x + 7, side XY measures 4 and side ZX measures 4x – 2. Find the value of x.
1 solutions
Answer 319389 by solver91311(16897) on 2011-06-30 11:12:56 (Show Source):
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Radicals/465887: I am supposed to solve this:
3+ root symbol (z-8) = root symbol(z+7)
I am not sure what to do here, any help would be appreciated! With explanation if possible!
1 solutions
Answer 319270 by solver91311(16897) on 2011-06-29 22:47:19 (Show Source):
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Probability-and-statistics/465824: 1. Find the mean of the distribution shown.
x 0 3 5
P(x) 0.36 0.40 0.24
2. The following distribution is not a probability distribution because
x -5 -4 -3 -2 -1
P(x) 0.11 0.16 0.42 0.16 0.30
3. The following distribution is not a probability distribution because
x -5 -4 -3 -2 -1
P(x) 0.20 0.20 –0.23 0.54 0.29
4. What probability value would be needed to complete the following probability distribution?
x -5 -1 0 1 4
P(x) 0.09 0.25 0.15 0.27
5. There are 50,000 people at a stadium watching a soccer match, and 40,000 of them are male. If 3 people are chosen at random, what is the probability that all 3 of them are male?
6. A researcher surveyed college students to study their opinion about the proposed change in smoking rules. The researcher asked a group of 20 students – 11 of them supported the change, 6 of them did not, and 3 had no opinion. This is not a binomial model because
7. Which of the following pairs of probability values could complete the following probability distribution?
8. A school is sending 11 children to a camp. If 20% of the children in the school are first graders, and the 11 children are selected at random, what is the mean and variance of the number of first graders chosen?
9. Find the mean of the distribution shown.
x 1 2
P(x) 0.46 0.54
10. On a Saturday evening, 34% of the people in Chicago go out to dinner, 18% see a movie, 13% have a party, and 35% stay home. Seventeen people are randomly selected. Can the probability that exactly 4 of them stay home be computed using a binomial model?
11. A coin is tossed five times. Find the probability of getting exactly three heads.
12. Find the mean of the distribution shown.
x -3 -2 -1 0
P(x) 0.19 0.24 0.40 0.17
13. Find the mean of the distribution shown.
x 2 3 4
P(x) 0.30 0.24 0.46
14. A computer store has 50 printers of which 35 are laser printers and 15 are ink jet printers. If a group of 10 printers is chosen at random from the store, find the mean and variance of the number of ink jet printers.
15. A researcher calculated the values and probabilities for a random variable X as shown below. Unfortunately, he erased the last value and needs to figure out what it was. If the mean of X was 2.2, then what was the last value?
16. What value would be needed to complete the following probability distribution?
17. The probability of failure for taking the bar exam in Philadelphia is 41%. If 375 people take the bar exam, what is the expected mean number of failures?
1 solutions
Answer 319217 by solver91311(16897) on 2011-06-29 20:08:26 (Show Source):
You can put this solution on YOUR website!
What do you think the probability is that someone is going to do an entire 17 question Stat assignment for you? Here are some situations with similar probabilities:
Snowball in hell.
When pigs fly.
Electing an honest politician.
Are you beginning to get the idea?
Go back and re-read (or read as the case may be) the instructions for posting questions on this site. Pay particular attention to the one that says "One question per post" When you have read that rule enough times that you have the concept clearly fixed in your mind, start reading the part about explaining where you are having difficulty and being specific about what help you need.
If you think I am being too harsh with you, please understand that not only have I had a long, hard day, I also really, really, really dislike lazy people who have no desire to learn anything but are trying to get someone else to do their work for them with the least amount of effort possible.
John
My calculator said it, I believe it, that settles it
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Unit_Conversion_Word_Problems/465835: 2.Sam had to pay Tony $238. He worked 2/3 of a day and makes $99 in a day at the Company. He had a yard sale and made $150, but he also had to pay Tina $78. He started out with $200 cash, so what was he left with after paying Tony and Tina? If he doesn’t have enough tell how much he will owe Tony because he pays Tina first?
1 solutions
Answer 319214 by solver91311(16897) on 2011-06-29 19:56:48 (Show Source):
You can put this solution on YOUR website!
Money in is plus, money out is minus.
He had $200, so + 200
He made 2/3 of $99, so +66
He made $150, so + 150
He paid $78, so -78
He paid $238, so -238
Add all of the numbers. If the answer is positive, that's the amount left. If the answer is negative but greater than or equal to -238, then that's what he still owes Tony. If the answer is negative but less than -238, he owes Tony the entire 238 and the amount less than -238 is what he still owes Tina.
John
My calculator said it, I believe it, that settles it
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Finite-and-infinite-sets/465832: Let U = {x│x is an American}
C = {x│x is a smoker}
D = {x│x has a health problem}
E = {x│x is a male}
Describe in words a member of each of the following:
(a) ¯C¯
(b) ¯C¯ ∩ ¯D¯
(c) C ∩ D
(d) D - C
(e) D U C
NOTE: U denotes “union” , ∩ denotes “intersection” and ¯ ¯ denotes “negation”,
for example, ¯ C¯ = is not a smoker
Stumped unable to start.
1 solutions
Answer 319212 by solver91311(16897) on 2011-06-29 19:49:58 (Show Source):
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Probability-and-statistics/465798: My homework is due tonight and I can't figure out these two problems:
5. A fair coin is flipped 20 times and the sequence of heads and tails is observed. Find the probability that the sequence consists of AT LEAST two heads. Answer in fraction reduced to the lowest terms.
The previous answer provided was wrong:
P(2<= x <=20) = 1 - P(0<= x <=1) = 1 - [1/2^20 + 20C2(1/2^20)]
= 1 - [(1+190)/2^20]
= 1 - (191/2^20)
---
== 1048385/1048576
8. Refer to the given graph. Assume one can move only down or to the right. If a route starts at A and ends at C, what is the probability that the route passes through B? Answer in fraction reduced to the lowest terms.
a
[][][]b[][]
[][][][][]
[][][][][]
[][][][][]
[][][][][]c
i said c(4,1) x c(6,2) = 60
But it was wrong
1 solutions
Answer 319194 by solver91311(16897) on 2011-06-29 18:23:10 (Show Source):
You can put this solution on YOUR website!
You are approaching the problem correctly, but I'm not sure you have the formula appropriately used.
The probability of  successes in  trials where  is the probability of success on any given trial is given by:
\ =\ \left(n\cr k\right\)\left(p\right)^k\left(1\,-\,p\right)^{n\,-\,k})
Where ) is the number of combinations of things taken at a time and is calculated by !})
but you want ) which would require calculating:
\ =\ \sum_{i=2}^{20}\ \left(20\cr\ i\right\)\left(0.5\right)^i\left(1\,-\,0.5\right)^{20\,-\,i})
A daunting task indeed. However ) which can be rendered:
\ =\ 1\ -\ \left\[\left(20\cr\ 0\right\)\left(0.5\right)^0\left(0.5\right)^{20}\ +\ \left(20\cr\ 1\right\)\left(0.5\right)^1\left(0.5\right)^{19}\right\]\ =\ 1\ -\ 21\,\cdot\,\left(0.5\right)^{20}\ >\ 0.999)
Is much easier to calculate. In fact, looking a little deeper, you managed to come up with the correct denominator, but your numerator is off by a touch -- should have been 1048576 minus 21 = 1048555.
You only get one problem per posting. But I'll give you a hint for the second one. Since you can only move down and right, if any of your first three moves are down, you will miss point B. Therefore your first three moves must be to the right. From there you have a limited number of ways to go, so it should be relatively easy to count the number of successful paths.
By the way, I know just by looking at your answer of 60 that it is incorrect without looking at any other part of the problem. Why do you think that is? Hint: You are trying to find a probability.
John
My calculator said it, I believe it, that settles it
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Travel_Word_Problems/465789: 4. During a 4th of July weekend, 32 vehicles became trapped on the Sunshine Skyway Bridge while it was being repaved. A recent city ordinance decreed that only cars with 4 wheels and trucks with six wheels could be on the bridge at any given time. If there were 148 tires that needed to be replaced to due to damage, how many cars and trucks were involved in the incident? (2 points)
1 solutions
Answer 319190 by solver91311(16897) on 2011-06-29 17:50:16 (Show Source):
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