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Polynomials-and-rational-expressions/560477: 3. To estimate animal populations, biologists count the total number of animals in a small section of a habitat. The total population of animals is directly proportional to the size of the habitat (in acres) polled.
a. Write an equation using only one variable that could be used to solve for the constant of variation k.
b. A biologist counted 12 white tail deer in a 100-acre parcel of land in a nature preserve. Find the constant of variation k.
c. If the entire nature preserve is 2,500 acres, then what is the total white tail deer population in the preserve? Describe how you arrived at your answer.
1 solutions
Answer 363902 by solver91311(16868) on 2012-01-21 19:58:02 (Show Source):
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Length-and-distance/559702: the coordinate of p are (-2,5) and the coordinates of q are (6,1).
a.what is the slope of pq?
b.what is the equation?
c.what are the coordinates of the mp of pq?
d. what is the eqquation of the perpendicular bisector of pq?
1 solutions
Answer 363500 by solver91311(16868) on 2012-01-19 18:05:22 (Show Source):
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Linear-equations/558554: Find (a)the equation of the line that is parallel to the given line and includes the given point, and (b) the equation of a line that is perpendicular to the given line through the given point. Wright both answers in slope-intercept form. (c) Graph both of these lines on the same axes. Please show all of your work.
y=-x+4,(-3,7) 1 solutions
Answer 363099 by solver91311(16868) on 2012-01-17 18:45:47 (Show Source):
You can put this solution on YOUR website!
Parallel lines have equal slopes. Perpendicular lines have slopes that are negative reciprocals.
For your part a) note that the given point is on the given line. Therefore the desired equation is identical to the given equation.
For your part b) calculate the negative reciprocal of the slope of the given line, then used the point slope form of an equation of a line to derive the desired equation.
where are the coordinates of the given point and is the given/calculated slope.
Rearrange to put the equation into slope-intercept form, that is: .
For your graphs, you already have one point on each of your lines, namely the given point, so plot that point. Select a small integer value for , substitute that value for into one of your equations, calculate the value of that results, create the point from the value you selected for and the value you calculated for , then plot the point. Draw a line through the two points. Repeat for the other equation.
John

My calculator said it, I believe it, that settles it
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