Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On

 Tutoring Home For Students Tools for Tutors Our Tutors Register Recently Solved
 By Tutor
| By Problem Number |

Tutor:

# Recent problems solved by 'solver91311'

Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829 , 13830..13859 , 13860..13889 , 13890..13919 , 13920..13949 , 13950..13979 , 13980..14009 , 14010..14039 , 14040..14069 , 14070..14099 , 14100..14129 , 14130..14159 , 14160..14189 , 14190..14219 , 14220..14249 , 14250..14279 , 14280..14309 , 14310..14339 , 14340..14369 , 14370..14399 , 14400..14429 , 14430..14459 , 14460..14489 , 14490..14519 , 14520..14549 , 14550..14579 , 14580..14609 , 14610..14639 , 14640..14669 , 14670..14699 , 14700..14729 , 14730..14759 , 14760..14789 , 14790..14819 , 14820..14849 , 14850..14879 , 14880..14909 , 14910..14939 , 14940..14969 , 14970..14999 , 15000..15029 , 15030..15059 , 15060..15089 , 15090..15119 , 15120..15149 , 15150..15179 , 15180..15209 , 15210..15239 , 15240..15269 , 15270..15299 , 15300..15329 , 15330..15359 , 15360..15389 , 15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629 , 15630..15659 , 15660..15689 , 15690..15719 , 15720..15749 , 15750..15779 , 15780..15809 , 15810..15839 , 15840..15869 , 15870..15899 , 15900..15929 , 15930..15959 , 15960..15989 , 15990..16019 , 16020..16049 , 16050..16079 , 16080..16109 , 16110..16139 , 16140..16169 , 16170..16199 , 16200..16229 , 16230..16259 , 16260..16289 , 16290..16319 , 16320..16349 , 16350..16379 , 16380..16409 , 16410..16439 , 16440..16469 , 16470..16499 , 16500..16529 , 16530..16559 , 16560..16589 , 16590..16619 , 16620..16649 , 16650..16679 , 16680..16709 , 16710..16739 , 16740..16769 , 16770..16799 , 16800..16829 , 16830..16859 , 16860..16889 , 16890..16919 , 16920..16949 , 16950..16979 , 16980..17009 , 17010..17039 , 17040..17069, >>Next

 Quadratic_Equations/609582: Since all quadratic expressions form parabolas, are all parabolas quadratic expressions?1 solutions Answer 383798 by solver91311(17077)   on 2012-05-10 14:56:37 (Show Source): You can put this solution on YOUR website! Any function that has a parabola for a graph is a quadratic function. However the converse is NOT true. It is NOT true that ALL quadratic expressions form parabolas. is a circle, not a parabola. John My calculator said it, I believe it, that settles it
 Numbers_Word_Problems/609585: fourteen less a number is six less than the same number 1 solutions Answer 383796 by solver91311(17077)   on 2012-05-10 14:51:31 (Show Source): You can put this solution on YOUR website! Fascinating little fact. Was there a question in there somewhere? John My calculator said it, I believe it, that settles it
 Miscellaneous_Word_Problems/609586: Joe measured several greeting cards. The ratio of length to width of each card was 4 to 5. Which of the following ratios could NOT be the dimensions of one of cards Joe measured? A. 16 cm long by 20 cm wide B. 8 in long by 10 in. wide C. 6 in. long by 8 in. wide D. 12 cm long by 15 cm wide1 solutions Answer 383795 by solver91311(17077)   on 2012-05-10 14:50:31 (Show Source): You can put this solution on YOUR website! For each of the given pairs of dimensions, divide the smaller by 4 and the larger by 5. If you get the same answer, the set of dimension is in the same proportion, otherwise not. John My calculator said it, I believe it, that settles it
 Graphs/609572: Solve the inequalities by graphing. Select the correct graph. 5x + 6y >1 y - x < 0 1 solutions Answer 383791 by solver91311(17077)   on 2012-05-10 13:48:53 (Show Source): You can put this solution on YOUR website! Step 1: Choose either inequality. Change the relationship symbol to "=". Graph the resulting line. If the original relationship symbol was or , do it with a dashed or broken line. If your symbol was or , graph the equation with a solid line. Step 2: Pick any point on the coordinate plane that does not lie on the line you just graphed. If the line does not pass through the origin, then the origin is an excellent choice for this step. If the line does pass through the origin, select a point other than the origin -- I recommend a point that has small integer coordinates. Step 3: Substitute the values of the coordinates of the point chosen in Step 2 for the corresponding variables in the inequality you started with in Step 1. Step 4: Do the appropriate arithmetic to determine whether the substitution created a true statement or not. If you created a true statement, shade in the side of the line containing the point selected in Step 2. If you created a false statement, shade in the side of the line that does not contain the selected point. Step 5: Repeat steps 1 through 4 for the other inequality. The solution set will be the region where the two shaded areas overlap. If the two shaded areas do not overlap at all, the solution set is the empty set. Note that points on any dashed boundary lines, in the case where you do not have a or relationship, are not included in the solution set. Points on solid boundary lines are included in the solution set. John My calculator said it, I believe it, that settles it
 Volume/609570: find the volume of a 5cm by 9cm solid cylinder using 3.14 for pie, round to the nearest tenth v=3.14 r2h1 solutions Answer 383790 by solver91311(17077)   on 2012-05-10 13:46:59 (Show Source): You can put this solution on YOUR website! You don't say whether it is a 5 cm radius base and a 9 cm height or a 5 cm height and a 9 cm radius base. Which ever it is, just plug in the numbers, i.e., calculate or And just an "oh by the way" Pie is a food item, generally with a more or less flaky crust (depending on the skill of the preparer) and, when used as a dessert item usually contains a fruit or other sweet filling, or when used as a entrée or side dish generally contains some sort of savory filling. pi is the thirteenth letter of the lower case Greek alphabet representing the mathmatical constant that is the ratio between the circumference and the diameter of a circle. John My calculator said it, I believe it, that settles it
Linear-equations/609549: Hello. My assignment is to come up with four essential vitamins/minerals and their recommended daily values. Also, four foods that contain each of those vitamins/minerals. Then I have to construct a linear system of equations that determines how much of each item a person would need to consume to achieve the recommended daily value of each nutrient.
For the minerals, I have: Magnesium- 400mg, Potassium-3500mg, Sodium-2400mg, and Zinc-15mg
The foods that I have chosen and calculated are:
1.)4 oz.Chicken: calcium-17.01mg, iron-1.18mg, magnesium-32.89mg, sodium-83.91mg,potassium-290.30mg, & zinc-1.13mg)
2.) 4oz Salmon: calcium-7.94mg, iron-.62mg, mag-35.15mg,sodium-74.84mg, potassium-425.24mg, zinc-.58mg
3.)Whole wheat: calcium-18.20mg, iron-1.75mg, mag-58.24mg,sodium-9.10mg, potassium-123.76mg, zinc-1.04mg
4.)1 cup 2% Milk: calcium-292.80mg, iron-.05mg, mag-26.84mg,sodium-114.68mg, potassium-341.60mg, zinc-1.17mg
Honestly, I have no idea how to begin to create a linear equation for all of these. Hopefully someone can simplify the process for me, or give me an example of a linear equation that I can use to create one for each food
1 solutions

Answer 383788 by solver91311(17077)   on 2012-05-10 13:36:26 (Show Source):
You can put this solution on YOUR website!

I think the trick to this one is to count 4oz chicken, 4oz salmon, some unspecified amount of whole wheat, and 1 cup milk, as "servings." Then let represent the number of required servings of chicken, represent the number of required servings of salmon, etc.

Now, make yourself a table:

 Servings Magnesium Potassium Sodium Zinc Chicken 32.89 290.30 83.91 1.13 Salmon 35.15 425.24 74.84 0.58 Whole Wheat 58.24 123.76 9.1 1.04 2% Milk 26.84 341.60 114.68 1.17 Requirement 400 3500 2400 15

Next note that the amount of magnesium that you would get from servings of chicken would be mg. So the total amount of magnesium you would get from this chicken/salmon/wheat/milk diet would be:

And you want this to add up to 400mg of magnesium, so:

.

The others are set up the exact same way, just read down each of the columns in the table to get the numbers you need.

John

My calculator said it, I believe it, that settles it

 Quadratic-relations-and-conic-sections/609537: the points (-1,4) and (3,-2) are the endpoints of a diameter of a circle. Find the center of the circle, and the radius, and write the equation of the circle.1 solutions Answer 383783 by solver91311(17077)   on 2012-05-10 12:28:52 (Show Source): You can put this solution on YOUR website! Use the midpoint formulas to calculate the midpoint of the diameter, which is to say the center of the circle. and where and are the coordinates of the given diameter endpoints. Use the distance formula to calculate the measure of the radius of the circle where and are the coordinates of either diameter endpoint and the calculated diameter midpoint. Write the equation of the circle centered at with radius : John My calculator said it, I believe it, that settles it
 Linear-systems/609547: How do you slove the non linear system algebraically. y=x^2+3x-5 y=2x+11 solutions Answer 383781 by solver91311(17077)   on 2012-05-10 12:21:15 (Show Source): You can put this solution on YOUR website! You have two expressions in each of which is equal to . They can't both be equal to without being equal to each other, can they? Set the two expressions in equal to each other, collect like terms all in the LHS leaving the resulting quadratic trinomial in equal to zero. Solve the quadratic for its two roots, if they exist. Hint: The resulting quadratic is factorable over the integers. John My calculator said it, I believe it, that settles it
 Quadratic-relations-and-conic-sections/609543: When given the characteristics of the parabola, center at origin, and directrix at x=7. How do you find standard form? 1 solutions Answer 383780 by solver91311(17077)   on 2012-05-10 12:17:07 (Show Source): You can put this solution on YOUR website! When you say "center" at origin, I presume you mean the vertex is at the origin. A parabola doesn't have a "center" per se, which is a departure from the descriptions of the other three types of conics. Since the directrix is a vertical line, the axis of the parabola is horizontal. Since the directrix must be outside of the parabola, i.e. the parabola opens away from the directrix, this paricular parabola opens to the left. The problem with answering this question for you is that you don't define what you mean by "standard" form. There are two common forms for a parabola: and Some authors call the first one the "vertex" form and the second one the "standard" form. Other authors call the first one the "standard" form and the second one the "general form." So the question is, what does your teacher/instructor/professor and/or textbook author(s) mean by "standard" form? John My calculator said it, I believe it, that settles it
 Money_Word_Problems/609183: how long will it take money to triple if it is invested at 5% compounded daily? 6% compounded continuously1 solutions Answer 383608 by solver91311(17077)   on 2012-05-09 15:49:33 (Show Source): You can put this solution on YOUR website! And you want , hence where and take the log (base doesn't matter) of both sides: Use the laws of logs Just plug in your given values and do the arithmetic on your calculator. John My calculator said it, I believe it, that settles it
 expressions/609182: Where would the parentheses go in 6+6/6+6*6=6 to make the statement true?1 solutions Answer 383603 by solver91311(17077)   on 2012-05-09 15:39:02 (Show Source): You can put this solution on YOUR website! Place the parentheses so that the numerator of the fraction equals the denominator of the fraction. That way, the value of the fraction is 1 and 1 times 6 is 6. John My calculator said it, I believe it, that settles it
 Quadratic_Equations/609180: The solution of a quadratic equation can be found by graphing each side separately and locating the points of intersection Solve: 3x^2 + 2x + 5 = 6x^2 How would I do this on the calculator?1 solutions Answer 383602 by solver91311(17077)   on 2012-05-09 15:36:48 (Show Source): You can put this solution on YOUR website! The calculator? What calculator? Though there is no such thing as a stupid question, I ask about the calculator to point out just how very close you came. Don't write back and tell me some calculator model, because I don't have one no matter what model it is. You can repost if you want, and perhaps someone else can help you. But I would be sure to specifiy the make and model when you do so. John My calculator said it, I believe it, that settles it
 Functions/609163: The function H described by H(x)=2.75x+71.48 can be used to predict the height, in centimeters of a woman whos humerus (the bone from the elbow to the shoulder) is x cm long. Predict the height of a woman whos humerus is 36cm long is ___cm.1 solutions Answer 383599 by solver91311(17077)   on 2012-05-09 15:26:24 (Show Source): You can put this solution on YOUR website! Replace x with 36 and do the arithmetic. John My calculator said it, I believe it, that settles it
 Functions/609176: Find the indicated outputs for f(x)=3x^2-5x. f(0)=?1 solutions Answer 383597 by solver91311(17077)   on 2012-05-09 15:24:25 (Show Source): You can put this solution on YOUR website! Take whatever is inside the parentheses and put it in place of , then do the arithmetic. So See? John My calculator said it, I believe it, that settles it
 Expressions-with-variables/609166: Solve the following equation for x and y. 12x + 8i = 8/15 + 14yi1 solutions Answer 383595 by solver91311(17077)   on 2012-05-09 15:20:47 (Show Source): You can put this solution on YOUR website! Hint: John My calculator said it, I believe it, that settles it
 Functions/609174: Given the function f described by f(x)=12x, find each of the following. (a) f(-6) (b) f(6) (c) f(21) f(-6)=___?1 solutions Answer 383593 by solver91311(17077)   on 2012-05-09 15:17:09 (Show Source): You can put this solution on YOUR website! Take whatever is inside the parentheses and put it in place of , then do the arithmetic. So See? John My calculator said it, I believe it, that settles it
 Equations/609172: solution to -5f+40=5f+30 in simplest form1 solutions Answer 383591 by solver91311(17077)   on 2012-05-09 15:13:11 (Show Source): You can put this solution on YOUR website! Add -5f to both sides. Add -40 to both sides. Divide by the coefficient on the single term containing the variable. John My calculator said it, I believe it, that settles it
 Equations/609171: whats the solution to 6k-k=27-4k in simplest form1 solutions Answer 383589 by solver91311(17077)   on 2012-05-09 15:11:49 (Show Source): You can put this solution on YOUR website! Collect terms on in the LHS. Add 4k to both sides. Once you have a single term that contains the variable, divide by the coefficient. John My calculator said it, I believe it, that settles it
 Average/609169: The average fuel economy of a car that went 200 highway miles on 6 gal of gas and 100 city miles on 4 gal of gas.( find average)1 solutions Answer 383586 by solver91311(17077)   on 2012-05-09 15:10:26 (Show Source): You can put this solution on YOUR website! Hint: The car went (200 + 100) miles on (6 + 4) gallons of gas. John My calculator said it, I believe it, that settles it
 Travel_Word_Problems/609146: Mr. P and his sister leave their home at the same time traveling in opposite directions. Mr. P. travels at 57 mph and his sister travels at 65 mph. In how many hours will they be 366 miles apart?1 solutions Answer 383584 by solver91311(17077)   on 2012-05-09 15:08:51 (Show Source): You can put this solution on YOUR website! Answer the question if one of them stayed put and the other travelled at 122 mph. Same answer. John My calculator said it, I believe it, that settles it
 Polynomials-and-rational-expressions/608880: I have been working on this problem for two days with no solution. please help! Factor the equation: 3x to the third power minus 9x minus 301 solutions Answer 383414 by solver91311(17077)   on 2012-05-08 22:32:48 (Show Source): You can put this solution on YOUR website! The best you can do is: John My calculator said it, I believe it, that settles it
 Linear-equations/608872: A (5,2) is in the standard (x,y) coordinate place. what must be the coordinates of the point of B so that the line x=4 is the perpendicular bisector is AB? and why?1 solutions Answer 383413 by solver91311(17077)   on 2012-05-08 22:28:39 (Show Source): You can put this solution on YOUR website! In order for AB to be perpendicular to , a vertical line, the segment AB must be contained in a horizontal line. Horizontal lines have the characteristic that the coordinate of all points in the line are equal. Hence, if point A has a coordinate of 2, then point B must have a coordinate of 2 also. In order for to be the perpendicular bisector of AB, the point where intersects the line containing the segment AB must be the midpoint of AB. We know the coordinate of that midpoint because we know that , and we also know the coordinate of that midpoint because all points on the segement AB (indeed, all points on the line containing the segment AB) have a coordinate of 2. The distance from the point to the point can be calculated using the distance formula, or you can simply note that there is zero difference in the coordinates so the distance is the difference between the coordinates, i.e. 1. That means that point B has to be 1 unit on the other side of the midpoint, that is to say at John My calculator said it, I believe it, that settles it
Probability-and-statistics/608878: An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
Compute the probability of each of the following events:
Event A: The sum is greater than 9 .
Event B: The sum is not divisible by 3 and not divisible by 4.
1 solutions

Answer 383412 by solver91311(17077)   on 2012-05-08 22:14:33 (Show Source):
You can put this solution on YOUR website!

Sum Ways # of Ways
21,11
31,2; 2,12
41,3; 2,2; 3,13
51,4; 2,3; 3,2; 4,14
61,5; 2,4; 3,3; 4,2; 5,15
71,6; 2,5; 3,4; 4,3; 5,2; 6,16
82,6; 3,5; 4,4; 5,3; 6,25
93,6; 4,5; 5,4; 6,34
104,6; 5,5; 6,43
115,6; 6,52
126,61

The probability of anything is the number of ways that it can happen that you would consider a success divided by the number of ways it can happen total -- successes and failures.

If you add up the number of total ways that you can roll a pair of dice you get 36.

John

My calculator said it, I believe it, that settles it

 Square-cubic-other-roots/608865: I am in bad need of help, can someone help me with this problem? Thank you! Simplify by taking roots of the numerator and the denominator. ∛(1000/343) (Simplify your answer. Type an exact answer, using radicals as needed.)1 solutions Answer 383411 by solver91311(17077)   on 2012-05-08 22:12:18 (Show Source): You can put this solution on YOUR website! So use your calculator to take the cube root of 1000 and the cube root of 343. Divide. John My calculator said it, I believe it, that settles it
 Equations/608867: Solve and state solution set. 6/(x+1)=2/(x-1)1 solutions Answer 383410 by solver91311(17077)   on 2012-05-08 21:48:46 (Show Source): You can put this solution on YOUR website! Cross-multiply Distribute, collect like terms, and solve. John My calculator said it, I believe it, that settles it
 Polynomials-and-rational-expressions/608869: Hi, Is this correct? Instructions: Divide and simplify (type exponential notation with positive exponents) t^6 ____ t^19 The answer I got is 1 ___ t^13 or do I have to write t^13. Thanks1 solutions Answer 383408 by solver91311(17077)   on 2012-05-08 21:45:33 (Show Source): You can put this solution on YOUR website! Yep, John My calculator said it, I believe it, that settles it
 Surface-area/608862: A sphere has a radius of 6. Which of the following are true? -the volume of a hemisphere with the same radius is 216pi -the volume is 288pi -the volume is 48pi -the surface area of a hemisphere with the same radius is 72pi -the surface area is 144pi -the surface area is 864pi -the the surface area of a hemisphere with the same radius is 108pi -the volume of a hemisphere with the same radius is 144pi1 solutions Answer 383407 by solver91311(17077)   on 2012-05-08 21:42:52 (Show Source): You can put this solution on YOUR website! Formula for the volume of a sphere: Formula for the surface area of a sphere: the volume of a hemisphere is one-half the volume of a sphere with the same radius. The surface area of a hemisphere a matter of interpretation. Either it is half the surface area of a sphere with the same radius, or it is that same half sphere surface area PLUS the area of the circular base of the hemisphere, namely . John My calculator said it, I believe it, that settles it
 Equations/608660: I need the entire MAT116 course solutions. Just everything for the class from the DQs to the quizzes. Just everything. g.b13691@gmail.com1 solutions Answer 383334 by solver91311(17077)   on 2012-05-08 15:47:50 (Show Source): You can put this solution on YOUR website! I e-mailed this Bozo. Can you believe he wants all of the MAT 116 solutions for free? Stupid is as stupid does, I guess. John My calculator said it, I believe it, that settles it
 Finance/608658: To estimate the population in a rookery, 4965 fur seal pups were captured and tagged in early August. In late August, 900 fur seal pups were captured. Of these, 218 had been tagged. Based on these figures, estimate the population of fur seal pups in the rookery to the nearest hundred.1 solutions Answer 383331 by solver91311(17077)   on 2012-05-08 15:35:21 (Show Source): You can put this solution on YOUR website! Round to the nearest 100. John My calculator said it, I believe it, that settles it
 Rational-functions/608634: Can you show me how to graph 3x+y=5?1 solutions Answer 383330 by solver91311(17077)   on 2012-05-08 15:32:34 (Show Source): You can put this solution on YOUR website! Step 1. Pick a value for x. It can be anything you like, but 0, 1, or some other small integer usually works well and makes the arithmetic easier. Step 2. Substitute that value in place of x in your equation. Do the arithmetic and determine the value of y that results. Step 3. Take the value of x that you selected for step 1 and the value of y that you calculated in step 2 and form an ordered pair (x,y). Step 4. Plot the ordered pair from Step 3 on your graph. Remember that the x value is the distance right or left along the horizontal axis and the y value is the distance up or down along the vertical axis. Step 5. Repeat steps 1 through 4 with a different value for x. Step 6. Draw a line across your graph that passes through the two points that you plotted. John My calculator said it, I believe it, that settles it