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Use substitution to determine weather the point is in the line.
Y=5x+3;A(1;8) 1 solutions
Answer 404407 by solver91311(17077) on 2012-08-29 20:03:47 (Show Source):
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Rational-functions/643090: Could you please help me with this problem? I am given the function f(x)= x^2 + 2x + 6 with a domain where x = all real numbers, and x is ≤ k. F is a one to one function, and I am to determine the greatest possible value of k. When k has that value, I am then to determine the range of f, and then the inverse function f^-1 and state its domain and range. After that I am to graph f(x) and f^-1(x). I believe I know how to find the value of k; it's just asking for the upper limit of the domain of the function given. I think to determine the range you can complete the square and put the equation into standard parabola form and so determine the vertex from that, using the y point of the vertex and the fact that it is either an up/down parabola (I believe this one is up) to find the range. I'm just having trouble finding the inverse function. When I switch the x's and y's from the original equation and try to solve for y I seem to get stuck. I know how to find the domain and range from there and I am fairly certain I can graph the equation. I just need help finding the inverse function. Please help? :) 1 solutions
Answer 404366 by solver91311(17077) on 2012-08-29 18:24:40 (Show Source):
You can put this solution on YOUR website!
In order to get the range of you first have to establish the maximum value of . The key to this is the fact that has been declared a 1 to 1 function. Parabolas, in their full glory, are never 1 to 1 functions because for any value of the independent variable there is a second value of the independent variable on the other side of and equidistant from the vertex that gives the same function value. In other words a full parabola never passes the horizontal line test. Enter this mysterious value . If you think about it a second, you can choose a value for at or less than the -coordinate of the vertex and you will guarantee yourself a 1 to 1 function. Obviously, if you choose , then will be at its maximum value.
So where is the vertex? For any quadratic function in standard form, i.e., , the -coordinate of the vertex is located at , and the -coordinate is just the value of the function at that value.
Let's find your vertex:
Hence, your vertex is at
Now we know that the maximum possible value of is -1, and, since we know the parabola opens upward because of the positive lead coefficient on , the value of the function at the vertex is a minimum, we can say that
On to the inverse. Let's discover the inverse relation that would derive from the original function. As is normal, replace with
Now let's go about solving for in terms of . Put all the terms in the LHS, and every thing else in the RHS.
Complete the square on the LHS:
Factor the LHS perfect square:
Take the root:
Finish up
And finally, swap the variables:
Almost there but we aren't quite ready to call this an inverse function yet -- because it is not a function. We have both sides of the "on its side" parabola and we only want one of the sides to match our original function. Since our original function was the left side of the parabola, the inverse has to be the bottom side of the resulting sideways parabola (because of the required symmetry of a function and its inverse about the line ), hence:
Swapping the coordinates of the vertex on the original function will give you the vertex on the inverse. Your domain and range of the inverse should be easy to see from there.
John

My calculator said it, I believe it, that settles it
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Geometry_proofs/643016: I need help solving this proof,
PQ 5 RS. Prove PR 5 QS ____________________
P Q R S
Professor gave us this much
1.PQ=RS given
2.QR=QR Reflexive property
3.
4.
5.PR=QS
We are to do 3,4,5 and give reason, I have no clue how to do this. Help! 1 solutions
Answer 404305 by solver91311(17077) on 2012-08-29 15:44:19 (Show Source):
You can put this solution on YOUR website!
Not sure what you mean by "PQ 5 RS", so I'm just going to assume that you mean to say: "The measure of line segment PQ is equal to the measure of the line segment RS", which is what your first step, PQ = RS means.
3. PQ + QR = QR + RS, Additive property of Equality.
4. PQ + QR = PR and QR + RS = QS, Definition of the sum of line segments
5. Therefore PR = QS by Transitive Equality. Q.E.D.
John

My calculator said it, I believe it, that settles it
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Functions/643017: i don't really know how to explain the question so i will write it out.
Consider the function below, f(x).
how do i evaluate f(0) using the graph 1 solutions
Answer 404301 by solver91311(17077) on 2012-08-29 15:27:32 (Show Source):
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Travel_Word_Problems/643015: two cars traveling toward each other are 270 miles apart. car a is traveling 25 miles per hour faster than car B. the cars pass after 2 hours. how fast is each car traveling?
1 solutions
Answer 404299 by solver91311(17077) on 2012-08-29 15:23:36 (Show Source):
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Volume/642533: I have a pool that has a 45,000 L volume. What is the weight of the pool (just the water) on the surrounding land? 1 solutions
Answer 404135 by solver91311(17077) on 2012-08-28 19:06:20 (Show Source):
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Polynomials-and-rational-expressions/642364: I have no clue on what to do in order to solve this problem. I have tried numerous times and it doesnt seem like it is right. can someone help please?
Maximum profit. A chain store manager has been told by the main office that daily profit, P, is related to the number of clerks working that day, x, according to the function P = -25x^2 +300x. What number of clerks will maximize the profit, and what is the maximum possible profit? 1 solutions
Answer 404077 by solver91311(17077) on 2012-08-28 15:49:55 (Show Source):
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Trigonometry-basics/642348: Use a trigonometric ratio to find the value of x. Round the answer to the tenths’ place.
Here's a link to a picture of the problems:
#1 http://diagnostics.aceministries.com/images/math/math_8_5_1_7.png
Again, thank you so much for your help! I need a refresher! 1 solutions
Answer 404068 by solver91311(17077) on 2012-08-28 15:12:46 (Show Source):
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