Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On

 Tutoring Home For Students Tools for Tutors Our Tutors Register Recently Solved
 By Tutor
| By Problem Number |

Tutor:

# Recent problems solved by 'solver91311'

Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829 , 13830..13859 , 13860..13889 , 13890..13919 , 13920..13949 , 13950..13979 , 13980..14009 , 14010..14039 , 14040..14069 , 14070..14099 , 14100..14129 , 14130..14159 , 14160..14189 , 14190..14219 , 14220..14249 , 14250..14279 , 14280..14309 , 14310..14339 , 14340..14369 , 14370..14399 , 14400..14429 , 14430..14459 , 14460..14489 , 14490..14519 , 14520..14549 , 14550..14579 , 14580..14609 , 14610..14639 , 14640..14669 , 14670..14699 , 14700..14729 , 14730..14759 , 14760..14789 , 14790..14819 , 14820..14849 , 14850..14879 , 14880..14909 , 14910..14939 , 14940..14969 , 14970..14999 , 15000..15029 , 15030..15059 , 15060..15089 , 15090..15119 , 15120..15149 , 15150..15179 , 15180..15209 , 15210..15239 , 15240..15269 , 15270..15299 , 15300..15329 , 15330..15359 , 15360..15389 , 15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629 , 15630..15659 , 15660..15689 , 15690..15719 , 15720..15749 , 15750..15779 , 15780..15809 , 15810..15839 , 15840..15869 , 15870..15899 , 15900..15929 , 15930..15959 , 15960..15989 , 15990..16019 , 16020..16049 , 16050..16079 , 16080..16109 , 16110..16139 , 16140..16169 , 16170..16199 , 16200..16229 , 16230..16259 , 16260..16289 , 16290..16319 , 16320..16349 , 16350..16379 , 16380..16409 , 16410..16439 , 16440..16469 , 16470..16499 , 16500..16529 , 16530..16559 , 16560..16589 , 16590..16619 , 16620..16649 , 16650..16679 , 16680..16709 , 16710..16739 , 16740..16769 , 16770..16799 , 16800..16829 , 16830..16859 , 16860..16889, >>Next

 Rational-functions/240218: determine which functions are polynomial functions and if they are state the degree f(x)=3x^5/2x+1 g(X)=3x^2+5^1/2-1 h(x)=3 f(x)=2x^3+3.14x+1/21 solutions Answer 176072 by solver91311(16897)   on 2009-11-18 01:25:49 (Show Source): You can put this solution on YOUR website! f(x) is not a polynomial function. f(x) is a rational function composed of the quotient of two polynomial functions. g(x) is a polynomial function because although it has a non-integer exponent, that exponent is not on a variable (unless you mis-typed it and it is supposed to be 5x^1/2) g(x) is degree 2. h(x) is a polynomial function of degree 0. Remember so you can re-write The other f(x) is a polynomial function of degree 3. Nothing says the coefficients have to be integers (or rational or even real, for that matter) John
 Polynomials-and-rational-expressions/240170: it says max went shopping and spent 3/7 of his money on a new pair of shoes.Then he spends 2/5 of his money on a new shirt. what fraction of his money did max spend?1 solutions Answer 176071 by solver91311(16897)   on 2009-11-18 01:10:55 (Show Source): You can put this solution on YOUR website! There is a problem with the way you stated your question. Did he spend 2/5 of the money he started with on the new shirt, or 2/5 of the money he had left after he bought the shoes? If it is the first way: If it is the second way: John
 Quadratic_Equations/240199: Evaluate each given value of the function f(x) if f(x) =6-2x Find f(0) Find f(-2)1 solutions Answer 176070 by solver91311(16897)   on 2009-11-18 00:53:33 (Show Source): You can put this solution on YOUR website! If Then John
 Permutations/240223: How many five-letter passwords can be made if no letters are repeated?1 solutions Answer 176069 by solver91311(16897)   on 2009-11-18 00:28:25 (Show Source): You can put this solution on YOUR website! 26 ways to pick the first letter. For each of those ways, there are 25 ways to pick the second letter (one less because letters cannot be repeated). So 26 times 25 ways to pick the first two letters. Then 24 ways for the third letter and so on. 26 X 25 X 24 X 23 X 22. You do the arithmetic. John
 Complex_Numbers/240201: hi again =] i have a similiar question to the previous one, using the property of exponents can you write the complex number in standard form? 2+i^2 and 5-i^4 thank you!1 solutions Answer 176062 by solver91311(16897)   on 2009-11-17 23:34:10 (Show Source): You can put this solution on YOUR website! Anything to the zero power is 1 by definition. Anything to the 1 power is itself. Definition of i The mod function returns the remainder from integer division. is the remainder when is divided by . John
 Linear-equations/240128: How do I graph y > -2x + 3?1 solutions Answer 176037 by solver91311(16897)   on 2009-11-17 20:30:35 (Show Source): You can put this solution on YOUR website! Step 1: Graph the equation except that since the original inequality has a symbol rather than a symbol, construct the graph using a dashed line. Step 2: Pick a test point that is NOT on the line. Since this line does not pass through the origin, the point (0,0) is an excellent choice. Step 3: Substitute the coordinates from the point you selected in the previous step for the variables in your original inequality. Perform any necessary arithmetic. Step 4: If the result of step 3 is a true statement, shade in the half-plane that contains the test point. If the result is a false statement, shade in the half-plane that does NOT contain the test point. Your solution set is the shaded area. Since the line is dashed, points on the line are NOT included in the solution set. John
 Geometry_proofs/240126: Given: L is the midpoint of line segment IE, line segment NE is congruent to NI. Prove that line segment NI bisects angle INE1 solutions Answer 176028 by solver91311(16897)   on 2009-11-17 20:07:44 (Show Source): You can put this solution on YOUR website! You can't prove that NI bisects angle INE. That's because NI doesn't bisect INE. Now, if you were just being careless and actually meant to say "prove that NL bisects angle INE", then proceed thus: (Note: This system won't render the congruence symbol, so I have substituted the identity symbol (≡) ≡ Given. ≡ Definition of midpoint ≡ Reflexive Property of Equality ≡ SSS ≡ CPCTC bisects Definition of Angle Bisector John
 Miscellaneous_Word_Problems/240105: A wire is used to anchor a 20 foot high pole. One end of the wire is attached to the top of the pole. The other end is fastened to a stake five feet away from the bottom of the pole. Find the length of the wirse, to the nearest tenth of a foot. Can someone help me? - not sure how to start the problem....thank you.1 solutions Answer 176027 by solver91311(16897)   on 2009-11-17 20:05:33 (Show Source): You can put this solution on YOUR website! The first thing that you have to do is presume that the pole is exactly perpendicular to the ground in the direction of the point where the wire is attached to the ground. That way you have a right triangle and that is the only way you can solve this problem with the information given. Now that you know you have a right triangle, one leg of the triangle is 20 feet because that is the length of the pole from the surface of the ground to the top , and the other leg is 5 feet because that is the distance from the base of the pole to the point where the wire is attached to the ground. Now just apply Pythagoras to calculate the measure of the hypotenuse of the triangle. Let be the length of the wire. Time to get out your calculator. Remember to round off according to the problem instructions. By the way, the round-off instructions in the problem are inappropriate. The results of a computation involving measurements should never be reported to a greater precision than the least precise of the given measurements. That means that, given the fact that the measurements here given to the nearest foot, you should actually report your answer to the nearest whole foot. On the other hand, had the given measurements been reported as 20.0 feet and 5.0 feet, then reporting the answer to the nearest tenth of a foot would be correct. All of that notwithstanding, follow the problem instructions. John
 Human-and-algebraic-language/240097: How do you set up this word problem (& others like it)? A mother is eighteen years older than her son. She was three times as old as he was one year ago. How old are they now?1 solutions Answer 176022 by solver91311(16897)   on 2009-11-17 19:47:54 (Show Source): You can put this solution on YOUR website! Let represent the mother's age. Let represent the son's age. Then the first thing we know is: One year ago, mother was , and the son was , and the second thing we know is: Now you have two 2-variable linear equations. Solve the system. The ordered pair will give you your answers. John
 Travel_Word_Problems/240099: Two cars depart form the same place. One heads north at a certain speed, and the other car heads east at a speed 7mph faster than the first car. After one hour the cars are 17 miles apart. How fast is each car traveling?1 solutions Answer 176019 by solver91311(16897)   on 2009-11-17 19:42:42 (Show Source): You can put this solution on YOUR website! I already answered this problem today, but here it is again in case you missed it. If you are going miles per hour for 1 hour, you must have traveled miles. Since east is 90 degrees from north, apply Pythagoras: Just solve for John
 Divisibility_and_Prime_Numbers/240094: What is the smallest positive number divisible by four primes?1 solutions Answer 176018 by solver91311(16897)   on 2009-11-17 19:39:39 (Show Source): You can put this solution on YOUR website! I presume you mean "what is the smallest positive number divisible by four different primes?" If that is the case, you are looking for the product of the four smallest primes. The smallest prime is 2. 1 is not prime, by definition. On the other hand, if your "four primes" can all be the same prime, then the answer is John
 Linear-systems/240096: a system of linear equations that has the point (4,-7) as it's solution???1 solutions Answer 176017 by solver91311(16897)   on 2009-11-17 19:35:55 (Show Source): You can put this solution on YOUR website! Sorry, but there is no verb in your question. I can't understand what it is that you want to do. John
 Triangles/240083: can a right triangle have more than 1 right angle?1 solutions Answer 176016 by solver91311(16897)   on 2009-11-17 19:34:27 (Show Source): You can put this solution on YOUR website! The following answer applies to a right triangle in a Euclidian plane. The sum of the measures of the interior angles of ANY triangle is 180° A right angle measures 90° If a triangle had two right angles, then the sum of the measures of those two angles would be 90° + 90° = 180°. That would leave 0° for the third angle. So, in a word, the answer to your question is: No. A triangle on the surface of a sphere, torus, or any sort of Reimann Surface has different properties. John
 Quadratic_Equations/239988: Doing a quadratic equation problem, i cam across a problem. the equation i got was x^2-6c-3=0. When plugging this problem into the equation, x=-b+/-(sqrt(b^2+4ac))/2a, I did not know if you could plug the b value (-3) into the place of -b or if you had to make it a positive b.1 solutions Answer 176013 by solver91311(16897)   on 2009-11-17 19:04:45 (Show Source): You can put this solution on YOUR website! If is truly your equation, then if you compare it to the general form of a quadratic: that , , and . However, if that is the case, then there is no need for the quadratic formula because: Although, if you insist on using the quadratic formula, you will find that: reduces to the same answer. If you actually meant , that is another story, and then I'm curious where you got the idea that . John
 Polygons/239990: how many side does a regular polygon have if the sum of its interior angles measures 27001 solutions Answer 175966 by solver91311(16897)   on 2009-11-17 16:36:44 (Show Source): You can put this solution on YOUR website! The sum of the interior angles of a convex -gon is given by: degrees. So, since you know the sum of the angles (2700) you can say: Now all you need to do is solve for to get the number of angles which is the same as the number of sides. This works whether the polygon is regular or not. John
 Linear-equations/239978: So I need help with a word problem. I am pretty sure that i have to write it in y=mx+b form but I'm having a lot of trouble. I've only gotten as far as solving for slope but thats about it. Here it is. After being in business for a year, you discover that you are selling more boxes then you expected. you find that this is due to a larger base of customers. You find for the last several months you have consistently sold 325 boxes of markers at $23.50 per box. You continue to assume that if you charge$30 per box that you will sell 0 boxes. Use (23.5, 325) and (30,0) to find the new linear demand function.1 solutions Answer 175963 by solver91311(16897)   on 2009-11-17 16:31:02 (Show Source): You can put this solution on YOUR website! Since you have two ordered pairs, you need to use the two point form of the equation of a line: Where and are your two given points, namely and Make the indicated substitutions and then do the arithmetic. In order to express this as a function, you need to put your result into slope-intercept form, namely by solving for John