Tutor:

New! Get regular updates about newly solved problems via algebra.com's RSS system.

---

Recent problems solved by 'solver91311'

solver91311 answered: 16882 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829 , 13830..13859 , 13860..13889 , 13890..13919 , 13920..13949 , 13950..13979 , 13980..14009 , 14010..14039 , 14040..14069 , 14070..14099 , 14100..14129 , 14130..14159 , 14160..14189 , 14190..14219 , 14220..14249 , 14250..14279 , 14280..14309 , 14310..14339 , 14340..14369 , 14370..14399 , 14400..14429 , 14430..14459 , 14460..14489 , 14490..14519 , 14520..14549 , 14550..14579 , 14580..14609 , 14610..14639 , 14640..14669 , 14670..14699 , 14700..14729 , 14730..14759 , 14760..14789 , 14790..14819 , 14820..14849 , 14850..14879 , 14880..14909 , 14910..14939 , 14940..14969 , 14970..14999 , 15000..15029 , 15030..15059 , 15060..15089 , 15090..15119 , 15120..15149 , 15150..15179 , 15180..15209 , 15210..15239 , 15240..15269 , 15270..15299 , 15300..15329 , 15330..15359 , 15360..15389 , 15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629 , 15630..15659 , 15660..15689 , 15690..15719 , 15720..15749 , 15750..15779 , 15780..15809 , 15810..15839 , 15840..15869 , 15870..15899 , 15900..15929 , 15930..15959 , 15960..15989 , 15990..16019 , 16020..16049 , 16050..16079 , 16080..16109 , 16110..16139 , 16140..16169 , 16170..16199 , 16200..16229 , 16230..16259 , 16260..16289 , 16290..16319 , 16320..16349 , 16350..16379 , 16380..16409 , 16410..16439 , 16440..16469 , 16470..16499 , 16500..16529 , 16530..16559 , 16560..16589 , 16590..16619 , 16620..16649 , 16650..16679 , 16680..16709 , 16710..16739 , 16740..16769 , 16770..16799 , 16800..16829 , 16830..16859 , 16860..16889, >>Next

Linear-systems/240749: How do you Graph 5x+2y=4 1 solutions Answer 176365 by solver91311(16897)   on 2009-11-19 13:35:22 (Show Source): You can put this solution on YOUR website! Step 1. Pick a value for x. It can be anything you like, but 0, 1, or some other small integer usually works well and makes the arithmetic easier. Step 2. Substitute that value in place of x in your equation. Do the arithmetic and determine the value of y that results. Step 3. Take the value of x that you selected for step 1 and the value of y that you calculated in step 2 and form an ordered pair (x,y). Step 4. Plot the ordered pair from Step 3 on your graph. Remember that the x value is the distance right or left along the horizontal axis and the y value is the distance up or down along the vertical axis. Step 5. Repeat steps 1 through 4 with a different value for x. Step 6. Draw a line across your graph that passes through the two points that you plotted. John

percentage/240751: How do I determine the answer to this question: 35% of 12,500 equals ___? 1 solutions Answer 176364 by solver91311(16897)   on 2009-11-19 13:32:13 (Show Source): You can put this solution on YOUR website! Change 35% to a decimal fraction, then multiply the decimal fraction representation times 12,500. John

test/240738: solve the system x+y=3 and x-y=-1 1 solutions Answer 176358 by solver91311(16897)   on 2009-11-19 11:59:43 (Show Source): You can put this solution on YOUR website! Just add the two equations term by term. The coefficient on in one equation is the additive inverse of the coefficient on in the other equation. When you add them, the variable will be eliminated leaving you with a single equation in the single variable that can be solved by ordinary means. Once you have the value of , substitute it back into either of the original equations, and then solve for Check your answer by substituting both values back into both original equations to ensure that you have a true statement in each case. John

absolute-value/240708: Two angles are complementary. The sum of the measure of the first angle and one-fourth the second angle is 76.5 degrees. Find the measures of the angles. What is the measure of the smaller angle? What is the measure of the other angle? 1 solutions Answer 176356 by solver91311(16897)   on 2009-11-19 11:56:07 (Show Source): You can put this solution on YOUR website! Let represent the measure of one of the angles Let represent the measure of the other angle Because they are complementary: degrees Because of the other given: degrees Solve the system for and to get the measures of the angles. John

Age_Word_Problems/240707: How do I write the equations for this problem? Pam is 14 and her dad is 37. In how many years will Pam's dad be twice as old as she will be? 1 solutions Answer 176353 by solver91311(16897)   on 2009-11-19 11:35:23 (Show Source): You can put this solution on YOUR website! Every year into the future adds one to each of their ages. For example, 3 years from now, Pam will be 14 + 3 and Dad will be 37 + 3. When Pam is 14 plus "I don't know how many years" her Dad will be 37 plus "I don't know how many years" and 37 plus "I don't know how many years" will be two times 14 plus "I don't know how many years". That is rather cumbersome, so let's use a little shorthand. Let represent "I don't know how many years", then we can say: Just solve for John

Radicals/240720: solving an equation with a radical 6 outside the radical and x+3 inside to the fourth root = 15 1 solutions Answer 176343 by solver91311(16897)   on 2009-11-19 11:09:00 (Show Source): You can put this solution on YOUR website! I think you mean: In which case, first multiply by Raise to the 4th power: You can do the arithmetic from here. John

Travel_Word_Problems/240717: One car travels 20 km/hr faster than another. While one of them travels 240 km, the other travels 180 km. Find the speed of the fast car. 1 solutions Answer 176342 by solver91311(16897)   on 2009-11-19 11:03:19 (Show Source): You can put this solution on YOUR website! Cross-multiply and then solve for John

Square-cubic-other-roots/240630: Subtract. Simplify by collecting like radical terms if possible. 4*sqrt27 - 5*sqrt3 1 solutions Answer 176273 by solver91311(16897)   on 2009-11-18 23:25:53 (Show Source): You can put this solution on YOUR website! Hint: 27 = 3 times 9 John

Linear_Equations_And_Systems_Word_Problems/240624: Amy is making chocolate tea bread and a special oatmeal bread to sell at a bake sale. A batch of chocolate tea bread requires 2 eggs and 2 cups of flour. The oatmeal bread requies 3 cups of flour and 1 egg. Amy has 12 cups of flour and 8 eggs on hand. She makes a profit of $2 on both kinds of bread. Write a set of constraints that cold be used to graph the feasible region. 1 solutions Answer 176272 by solver91311(16897)   on 2009-11-18 23:24:42 (Show Source): You can put this solution on YOUR website! Let represent tea bread. Let represent oatmeal bread Integer restriction because she wouldn't be making a fractional part of a loaf of bread. John

logarithm/240625: how would you graph y=log(subscript 4)x? 1 solutions Answer 176271 by solver91311(16897)   on 2009-11-18 23:13:39 (Show Source): You can put this solution on YOUR website! I would pick several values for x, calculate the value of y using the base conversion formula, plot the points (x, y), and then draw a smooth curve through the points. John

Exponents/240620: If the sum of the digits is divisible by 9 that number is also divisible by 9,6,4,and 5 1 solutions Answer 176270 by solver91311(16897)   on 2009-11-18 23:07:29 (Show Source): You can put this solution on YOUR website! Fascinating statement. Not true, but fascinating nonetheless. Consider 81 John

Rectangles/240546: faye has 20 feet of fencing to make a regtangular pen for her dog.what is the largest area that she can fence in? 1 solutions Answer 176235 by solver91311(16897)   on 2009-11-18 20:25:47 (Show Source): You can put this solution on YOUR website! The perimeter of a rectangle is given by: Which can be rearranged to: The area, given by length times width, can then be represented as a function of the width for a given perimeter thus: This function is a quadratic that can be put into standard form thus: The graph of such a quadratic is a parabola that is concave down (the lead coefficient is less than zero), meaning that the vertex represents a maximum. The coordinate of the vertex of this parabola is given by: Therefore the width that gives the greatest area rectangle for any given perimeter is the perimeter divided by 4. The two widths are therefore half of the perimeter, hence the two lengths must also be half of the perimeter, and therefore the shape is a square. Divide your given perimeter by 4 and then square the result. John

Equations/240535: Please help me solve by the elimination method x+3y=16 -x+8y=17 1 solutions Answer 176230 by solver91311(16897)   on 2009-11-18 20:06:22 (Show Source): You can put this solution on YOUR website! The strategy for solving by elimination is to find a multiplier for one or both of the equations such that you make the coefficient on one of the variables in one of the equations be the additive inverse of the coefficient on that same variable in the other equation. In the case of given example, you don't have to find a multiplier for either equation because you already have a coefficient of 1 on x in the first equation and a coefficient of -1 on x in the second equation. Just add the two equations, term-by-term. Since you will be adding x to -x, you will end up with 0x, effectively eliminating (hence the name of the method) that variable. The end result will be a single equation in one variable, in this case, y. Solve for the remaining variable, and then use this value to substitute back into either of the original equations in order to solve for the variable that you eliminated. John

Signed-numbers/240530: -8(x-3) +12x= 15-(2x +3) answer: -2 (anyone can show me why the answer is -2 and can give a full break down thank you). 1 solutions Answer 176225 by solver91311(16897)   on 2009-11-18 19:55:21 (Show Source): You can put this solution on YOUR website! Distribute to remove parentheses. Remember has a coefficient of -1. Collect like terms: Add to both sides and add to both sides: Collect like terms: Multiply both sides by the reciprocal of the coefficient on the variable, namely John

Surface-area/240522: need a rectangle. width must be 1ft less than length area=12 square feet what are widths? 1 solutions Answer 176222 by solver91311(16897)   on 2009-11-18 19:45:07 (Show Source): You can put this solution on YOUR website! Let represent the width. Then represents the length. Since the area of a rectangle is the length times the width: Put the quadratic in standard form: Now all you need to do is solve the quadratic and take the positive root as the width and add 1 to get the length. Hint: It factors. -3 times 4 = -12 John

Linear-equations/240526: what is the y-intercept of the line that contain the data point? 1 solutions Answer 176220 by solver91311(16897)   on 2009-11-18 19:42:25 (Show Source): You can put this solution on YOUR website! What data point? What line? What is the slope? You have to give us something to work with.

Coordinate-system/240489: I am asked to find the slope of two lines, each in the same quadrant, quadrant 1. There are no coordinates. Is there a formula I should be using? 1 solutions Answer 176188 by solver91311(16897)   on 2009-11-18 18:18:10 (Show Source): You can put this solution on YOUR website! You must have some other information. You must also be referring to line segments rather than lines. It is impossible for a line to be wholly contained in a single quadrant. John

Quadratic_Equations/240473: A rectangular garden is 20 ft longer than it is wide. Its area is 2925 . What are its dimensions? 1 solutions Answer 176185 by solver91311(16897)   on 2009-11-18 18:15:23 (Show Source): You can put this solution on YOUR website! I already answered this one -- just a few minutes ago, in fact. Sorry, but the answer hasn't changed. Let represent the width. Then represents the length. Since the area of a rectangle is the length times the width: Put the quadratic in standard form: Now all you need to do is solve the quadratic and take the positive root as the width and add 20 to get the length. Hint: It factors. -45 times 65 = -2925 John

Geometry_Word_Problems/240478: the expressions 5x+13 and 10x-7 represent the lengths (in inches) of two sides of an equilateral octagon. find the length of a side of the octagon 1 solutions Answer 176181 by solver91311(16897)   on 2009-11-18 18:12:09 (Show Source): You can put this solution on YOUR website! If the octagon is equilateral, a word literally meaning "equal sided," then any two sides of the octagon are equal to each other. Specifically, the side labeled and the side labeled are equal to each other. That means that Just solve for and then plug that value back into either of the expressions used to label the sides. Do the arithmetic. That's your answer. Plug the value of into the other expression and do the arithmetic to check your work. John

Functions/240477: what are the values of this expression: f(3)+h(4) 1 solutions Answer 176170 by solver91311(16897)   on 2009-11-18 18:03:00 (Show Source): You can put this solution on YOUR website! No idea since you didn't bother to supply the definitions of f and h. However, if you look at the answer to question number 240199, you might get an idea of how to solve your problem. http://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.240199.html John

Quadratic_Equations/240471: A rectangular garden is 20 ft longer than it is wide. Its area is 2925 . What are its dimensions? 1 solutions Answer 176167 by solver91311(16897)   on 2009-11-18 17:59:08 (Show Source): You can put this solution on YOUR website! Let represent the width. Then represents the length. Since the area of a rectangle is the length times the width: Put the quadratic in standard form: Now all you need to do is solve the quadratic and take the positive root as the width and add 20 to get the length. Hint: It factors. -45 times 65 = -2925 John

Inequalities/240460: how would you graph 5x + 3y is greater than or = to -9 usimg system of inequalities? 1 solutions Answer 176162 by solver91311(16897)   on 2009-11-18 17:53:38 (Show Source): You can put this solution on YOUR website! Step 1: Graph the equation . Since the original inequality has a symbol and therefore the solution set will contain points on the line, construct the graph using a solid line. Step 2: Pick a test point that is NOT on the line. Since this line does not pass through the origin, the point (0,0) is an excellent choice. Step 3: Substitute the coordinates from the point you selected in the previous step for the variables in your original inequality. Perform any necessary arithmetic. Step 4: If the result of step 3 is a true statement, shade in the half-plane that contains the test point. If the result is a false statement, shade in the half-plane that does NOT contain the test point. Your solution set is the shaded area. Since the line is solid, points on the line are included in the solution set. John

Linear-equations/240459: Find an equation of the line passing through each pair of points (-6, 0) and (9, -8).Write the equation in the form Ax=By=C. 1 solutions Answer 176149 by solver91311(16897)   on 2009-11-18 17:25:59 (Show Source): You can put this solution on YOUR website! Use the two-point form of the equation of a line: where and are the coordinates of the given points. Once you have plugged in the values you were given, do the arithmetic and rearrange the equation to put it into Standard Form, namely: Some texts require that A, B, and C be integers to be in proper Standard Form. John

Linear-equations/240419: if you have the corridents ( 1, 6) ( 4, r) and m=5 how do you find r 1 solutions Answer 176147 by solver91311(16897)   on 2009-11-18 17:21:59 (Show Source): You can put this solution on YOUR website! Since "corridents" is not a word that has meaning in the English language, I will allow myself to infer from the rest of your question (if indeed it is a question, since there is no question mark anywhere to be seen) that you meant to say "coordinates." Use the formula for the slope: Plug in the values you were given: Now all you need to do is solve for John

Equations/240294: A= 1/2h (b1+b2 for b1 Please help, solve the problem for the indicated letter 1 solutions Answer 176108 by solver91311(16897)   on 2009-11-18 11:09:33 (Show Source): You can put this solution on YOUR website! Multiply by 2: Multiply by Add to both sides: John

Equations/240293: Solve the formula for the indicated letter. thanks P = s1 + s2 + s3 for s3 (Points :2) 1 solutions Answer 176106 by solver91311(16897)   on 2009-11-18 11:05:14 (Show Source): You can put this solution on YOUR website! Add and to both sides: John

logarithm/240290: given that log xy=2, logy/x+log 4 = 2, find the values of x and y. 1 solutions Answer 176105 by solver91311(16897)   on 2009-11-18 11:02:13 (Show Source): You can put this solution on YOUR website! So: and So: So: If , then . If , then . John

Equations/240288: Solve using the addition and multiplication principles. thanks -6r + 3 ≤ -3(4r - 9) 1 solutions Answer 176104 by solver91311(16897)   on 2009-11-18 10:51:49 (Show Source): You can put this solution on YOUR website! John

Polygons/240282: The measure of each interior angle of a regular polygon is t times the measure of each exterior angle of the polygon. Show that the polygon has 2(t+1) sides. 1 solutions Answer 176103 by solver91311(16897)   on 2009-11-18 10:43:25 (Show Source): You can put this solution on YOUR website! The measure of an interior angle of a regular -gon is given by: The measure of an exterior angle of a regular -gon is given by: So: John

Circles/240236: Three circles each of radius 3.5 cm are drawn in such a way that each of them touches the other two. Find the area enclosed between these circles. 1 solutions Answer 176074 by solver91311(16897)   on 2009-11-18 01:41:53 (Show Source): You can put this solution on YOUR website! If the circles just touch each other, then you can draw a line connecting the centers of each pair of adjacent circles creating an equilateral triangle of side length 7 (2 times 3.5). The area of an equilateral triangle is given by: There are four areas inside of this equilateral triangle, three circle sectors and the area we seek. The area of a circle sector is given by: where is the central angle of the sector. So, the area we want is the area of the equilateral triangle minus three times the sector area. You just need to simplify but I would leave the answer in terms of the radical and John

Rational-functions/240218: determine which functions are polynomial functions and if they are state the degree f(x)=3x^5/2x+1 g(X)=3x^2+5^1/2-1 h(x)=3 f(x)=2x^3+3.14x+1/2 1 solutions Answer 176072 by solver91311(16897)   on 2009-11-18 01:25:49 (Show Source): You can put this solution on YOUR website! f(x) is not a polynomial function. f(x) is a rational function composed of the quotient of two polynomial functions. g(x) is a polynomial function because although it has a non-integer exponent, that exponent is not on a variable (unless you mis-typed it and it is supposed to be 5x^1/2) g(x) is degree 2. h(x) is a polynomial function of degree 0. Remember so you can re-write The other f(x) is a polynomial function of degree 3. Nothing says the coefficients have to be integers (or rational or even real, for that matter) John