# See tutors' answers!

Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On

 Tutoring Home For Students Tools for Tutors Our Tutors Register Recently Solved
 By Tutor
| By Problem Number |

Tutor:

# Recent problems solved by 'scott8148'

scott8148 answered: 6619 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629, >>Next

 Quadratic_Equations/81046: This problem is not from my book. I have tried to answer it but don't feel I am correct, and I need every point possible to pass this course. Problem What is the minimum product of two numbers whose difference is 4? What are the numbers? Here is what I have done. n(n+1)=-4 n^2 + n = -4 n^2 + n - 4 = 0 (n+1)(n-4) The numbers are 1, -4, the minimum product is -4 Thank you so much for your help. Like I said I don.t think my solution is correct. 1 solutions Answer 58131 by scott8148(6628)   on 2007-05-07 12:43:30 (Show Source): You can put this solution on YOUR website!if the difference is 4 (not 5), then the numbers are n and n+4 (not n+1) ... so y=n(n+4) setting y=0 gives n=0 and n=-4 ... the minimum value for y is midway between these values (on the axis of symmetry) at n=-2 so the numbers are -2 and 2, and the product (which you did find) is -4
 Square-cubic-other-roots/80961: I need to know if I have simplified this square root to its lowest terms. The problem is: sqrt(20m^3b) and I simplified it as 2m(sqrt(5mb)).1 solutions Answer 58084 by scott8148(6628)   on 2007-05-06 21:21:07 (Show Source): You can put this solution on YOUR website!GOOD WORK!!! your answer is correct
 Sequences-and-series/80947: From towns 363 miles apart, Pat and Mike set out to meet each other. If Pat travels 1 mile the first day, 3 miles the second, 5 miles the third, etc. and Mike travels 2 miles the first day, 6 miles the second and 10 miles the third, etc., when will they meet? - I got the answer from my teacher, I know it's 11 days, but I have no idea how to work it. PLEASE HELP!1 solutions Answer 58083 by scott8148(6628)   on 2007-05-06 21:16:21 (Show Source): You can put this solution on YOUR website!each day, Pat travels 2 miles more than the previous day ... on the first day he traveled 1 mile so the distance traveled on day x is 1+2(x-1) ... for Mike, 2+4(x-1) let d=days traveled ... distance equals (average per day)*(days) ... ((first day+last day)/2)*(days) so Pat's distance is (1+(1+2(d-1))/2)*d ... similarly, Mike's distance is (2+(2+4(d-1))/2)*d the combined distance is 363 ... so (1+(1+2(d-1))/2)*d+(2+(2+4(d-1))/2)*d=363 ... (d)*d+(2d)*d=363 ... ... d=11
 Miscellaneous_Word_Problems/80948: I need to know how old your three kids are. The product of their ages is 36. The sum of their ages is the same as my house number. The younger two are twins. How old are the kid's and what is my house number. I think that the kids are 2 and 9 and the house number is 13 but I cannot figure out an equation. This didn't come from a textbook. It is an extra credit paper.1 solutions Answer 58082 by scott8148(6628)   on 2007-05-06 19:57:32 (Show Source): You can put this solution on YOUR website!let a=youngest, b=next, c=oldest, and h=house a*b*c=36 ... a+b+c=h ... a=b ... a < c ... factors of 36 are 1 & 36, 2 & 18, 3 & 12, 4 & 9, 6 & 6 ... this leaves 1, 4, and 9 as possibilities for 1,1 & 36 is least likely ... 2,2 & 9 and 3,3 & 4 seem equally likely as possible age scenarios as you can see, more information is needed to arrive at a unique solution
 Linear-systems/80316: please help if you can, Solve this system of equations 4a+7b=27 8a-3c=-22 6b-3c=24 The solution is [],[],[] Thank you1 solutions Answer 57660 by scott8148(6628)   on 2007-05-01 22:38:55 (Show Source): You can put this solution on YOUR website!A) third equation minus second equation ... (6b-3c)-(8a-3c)=24-(-22) ... 6b-8a=46 B) two times second equation ... 2(4a+7b=27) ... 8a+14b=54 C) A+B ... (6b-8a)+(8a+14b)=46+54 ... 20b=100 ... b=5 from second equation ... 4a+(7*5)=27 ... 4a=-8 ... a=-2 from first equation ... (6*5)-3c=24 ... -3c=-6 ... c=2
 Graphs/80302: This question is from textbook beginners algebra Are the following pairs of lines parallel, perpendicular, or neither? L1 with equation x+2y=4 L2 with equation 2x+4y=51 solutions Answer 57654 by scott8148(6628)   on 2007-05-01 22:07:05 (Show Source): You can put this solution on YOUR website!if you put the equations into slope-intercept form (y=mx+b), you will see that the lines have the SAME slope ... this means that they are parallel x+2y=4 ... 2y=-x+4 ... 2x+4y=5 ... 4y=-2x+5 ...
 Linear_Equations_And_Systems_Word_Problems/80320: if you can help i would greatly appreciate it, One cup of vegetable A, six pieces of vegetable B, and one cup of vegetable C contain 12 grams of carbohydrates. One cup of vegetable A and six pieces of vegetable B have 1/2 the carbs of 1 cup of vegetable C. One cup each of vegetables A and C have 3 times the carbs of a serving of vegetable B. Find the number of grams of carbs in the given potion size of each vegetable. vegetable A has [] grams, B has [] grams, and C has [] grams1 solutions Answer 57653 by scott8148(6628)   on 2007-05-01 21:52:45 (Show Source): You can put this solution on YOUR website!three unknowns need three different equations ... the equations for this case are: A+B+C=12 ... A+B=C/2 ... A+C=3B subtract second equation from first equation to get C=12-(C/2) ... (3/2)C=12 ... C=8 subtract third equation from first equation to get B=12-3B ... 4B=12 ... B=3 using first equation A+3+8=12 ... A=1
 Radicals/80346: Oh boy! tough one for me : ( One fourth of a herd of camels was seen in the forest, twice the square root of that herd had gone to the mountain slopes and 3 times 5 camels remained on the riverbank. What is the numerical measure of the herd of camels? Ugg! Please help! Thank you1 solutions Answer 57651 by scott8148(6628)   on 2007-05-01 21:37:38 (Show Source): You can put this solution on YOUR website!let h equal number in herd, then multiply by 4 and subtract (h+60) to get square both sides to get .. subtract 64h to get using quadratic formula .. or since no fractional camels, h=36
 Quadratic_Equations/80324: HELP ASAP!!!! An object is propelled vertically upward from the top of a 112-foot building. The quadratic function s(t) = -16t^2 + 176t + 112 models the ball’s height above the ground, s(t) in feet, t seconds after it was thrown. How many seconds does it take until the object finally hits the ground? Round to the nearest tenth of a second if necessary.1 solutions Answer 57641 by scott8148(6628)   on 2007-05-01 21:04:03 (Show Source): You can put this solution on YOUR website!the object hits the ground when the height s equals zero ... so set s=0 and solve for t .. dividing by -16 gives .. no integer factors using quadratic equation so ... t=-.6 and t=11.6 , negative value is not realistic
 Graphs/80347: whay is the point of doing this if we will never use it in life unlss you are going to be a mathamatition1 solutions Answer 57638 by scott8148(6628)   on 2007-05-01 20:35:21 (Show Source): You can put this solution on YOUR website!it is good exercise for your mind ... developing problem solving techniques and logical thinking you go to gym class, but you probably won't become a professional athlete ... same situation
 Circles/79854: Here is my word problem, need to write an equation: A lanscape architect wants to position a tree 3 meters east and 9 meters north of a stong marker in a garden. When the tree is full grown, its branches will be roughly circular with a diameter of about 4 meters. Write an equation representing the outside of the grown tree's branches relative to the stone. I understand how to do equations with center points and endplate points, but I just don't see how to do this. Thanks1 solutions Answer 57408 by scott8148(6628)   on 2007-04-29 21:51:28 (Show Source): You can put this solution on YOUR website!think of the marker as the origin (0,0) ... you need an equation for a circle of radius 2, centered at (3,9)
 Linear-equations/79879: hi i have been trying to do these equations for such a long time and i just cant do it please help me Write an equation of the line that is parallel to the given line and passes though the given point. 10. y= -3x+2 (2,3) 11. y=1/2x - 5 (-3,-1)1 solutions Answer 57403 by scott8148(6628)   on 2007-04-29 21:35:46 (Show Source): You can put this solution on YOUR website!lines that are parallel have the same slope (the m in y=mx+b), but have different y-intercepts (the b term) when a line goes through a point, it means that the x and y values of the point satisfy (fit) the equation of the line y=-3x+b for x=2, y=3 ... 3=-3(2)+b ... 3=-6+b ... b=9 ... y=-3x+9 y=(1/2)x+b for x=-3, y=-1 ... -1=(1/2)(-3)+b ... -1=-(3/2)+b ... b=1/2 ... y=(1/2)x+(1/2)
 Exponential-and-logarithmic-functions/79490: This question is from textbook (1/4)^x-1=2^5-x solve1 solutions Answer 57269 by scott8148(6628)   on 2007-04-27 23:05:54 (Show Source): You can put this solution on YOUR website! ...so ...so ...so -2x+2=5-x ... so x=-3
 Circles/79578: Three circles with radii 6 are tangent to each other. Find the area of the region enclosed between them. Please provide a diagram.1 solutions Answer 57268 by scott8148(6628)   on 2007-04-27 22:43:05 (Show Source): You can put this solution on YOUR website!three lines connecting the centers of the three circles form an equilateral triangle with side 12 the three "slice of pie" shaped sections in the corners of the triangle are each 1/6 of a circle so the area of the "between" region is just the difference between the area of the triangle and 1/2 of a circle ... ...
 Equations/79531: If p = –2 and q = –1, evaluate 3p^2 + 3q. 3(-2)^2 + 3*(-1)= I cam up with 9. Is this right? 1 solutions Answer 57101 by scott8148(6628)   on 2007-04-25 16:00:22 (Show Source): You can put this solution on YOUR website!CORRECT!! ... GOOD JOB
 Average/79437: I know how to solve for college GPA but not for high school during your high schoolyears, your grades were as follows; English-4A's; Math-3B's Science-2B's and 1 A; PE- 4A's; American History-B; Economics-A; World History-B; Electives-3A's A=4.0, B=3.0, C=2.0 D=1.0 E=0.0 1 solutions Answer 57100 by scott8148(6628)   on 2007-04-25 15:58:10 (Show Source): You can put this solution on YOUR website!just like college except all courses are the same number of credits, which means you just average all the grades 13 A's and 7 B's ... gpa=(13*4.0+7*3.0)/20 ... gpa=3.65
 Numbers_Word_Problems/79332: Hi, I've been trying to set up an appropriate system of equations for quite some time, and I've had no luck. The question is as follows; The sum of the digits of a certain three digit number is nine. The sum of the hundreds and the tens digits is equal to the ones digit minus one. The number, divided by nine, equals three times the ones digit. What is the number? All I have so far is x+y+z=9. Could you show me how to set the problem up please?1 solutions Answer 56939 by scott8148(6628)   on 2007-04-23 21:53:50 (Show Source): You can put this solution on YOUR website!let h=hundreds digit, let t=tens digit, let u=ones digit ... h+t+u=9 ... h+t=u-1 ... (100h+10t+u)/9=3u IF YOU ONLY WANT THE SETUP ... DO NOT READ BEYOND THIS LINE from first two equations, u-1+u=9 ... 2u=10 ... u=5 ... t=4-h using third equation, 100h+10(4-h)+5=3*5*9 ... 100h+40-10h+5=135 ... 90h=90 ... h=1 ... t=3
 Linear-equations/79187: Choose the slope-intercept form of the equation of the line that passes through (-2,4) and is perpendicular to the graph of 2x+y=-20. So far, I have tried this: 2x+y=-20 y=-20-2x And I'm not sure where to go from there. Thanks, Susanna Rivera1 solutions Answer 56860 by scott8148(6628)   on 2007-04-22 23:04:29 (Show Source): You can put this solution on YOUR website!good so far ... being perpendicular means that the slopes are negative reciprocals ... y=mx+b ... m is slope, b is y-intercept the original slope is -2 (the x coefficient), so the slope of the new line is 1/2, making the new equation y=(1/2)x+b to find b, just plug in the point that the line goes thru ... 4=(1/2)*(-2)+b ... so b=5 ... new equation is y=(1/2)x+5
 Linear-equations/79214: Can anyone give me any insight into this? I'm stuck! Any help would be deepley appreciated. Thanks. When using the quadratic formula to solve a quadratic equation ax2 + bx + c = 0, the discriminant is b2 - 4ac. This discriminant can be positive, zero, or negative. (When the discriminant is negative, then we have the square root of a negative number. This is called an imaginary number, sqrt(-1) = i. ) Explain what the value of the discriminant means to the graph of y = ax2 + bx + c. Hint: Chose values of a, b and c to create a particular discriminant. Then, graph the corresponding equation1 solutions Answer 56858 by scott8148(6628)   on 2007-04-22 22:45:19 (Show Source): You can put this solution on YOUR website!The quadratic equation ax2+ bx + c = 0 has two real roots when bē-4ac > 0, and the curve will cross the x axis twice. one real root when bē-4ac = 0, and the curve is tangent to the x axis. no real roots when bē-4ac < 0, and the curve will not cross the x axis at all.
 Quadratic-relations-and-conic-sections/79148: Identify the conic section and write the standard form of the equation 1 solutions Answer 56853 by scott8148(6628)   on 2007-04-22 20:27:25 (Show Source): You can put this solution on YOUR website!see 79149
 Quadratic-relations-and-conic-sections/79149: Identify the conic section and write the standard form of the equation 1 solutions Answer 56852 by scott8148(6628)   on 2007-04-22 20:26:25 (Show Source): You can put this solution on YOUR website!x and y both squared with the same coefficient on the square terms means a circle the rest of the terms give the location of the center and the radius ... the general equation is complete the squares for x and y by taking 1/2 of the coefficient of the first order term, square it and add it ... so this is a circle centered at (-4,2) with a radius of 3
 Expressions-with-variables/79203: My son and I can't find the solution to this question. 148 people attend a 5 day camp. The chef needs 9 lbs of food for each child and 12 lbs for each adult.He needs a total of 1410 lbs of food. How many children and how many adults attend camp? We figured that there are 26 adults and 122 children but we can't set it up using two variables. Please help!1 solutions Answer 56848 by scott8148(6628)   on 2007-04-22 19:57:44 (Show Source): You can put this solution on YOUR website!always glad to help a parent let a=number of adults and c=number of children ... a+c=148 ... a=148-c and (foodwise) 12a+9c=1410 substituting ... 12*(148-c)+9c=1410 ... 1776-3c=1410 ... c=122 ... and a=26
 Expressions-with-variables/79150: I am having trouble solving this system using the substitution method. 2x + y = -1....then underneath x^2 = 4 + y. Thanks for your help! 1 solutions Answer 56843 by scott8148(6628)   on 2007-04-22 18:35:05 (Show Source): You can put this solution on YOUR website!solving the first equation for y gives y=-1-2x ... substituting into the second equation gives x^2=4-1-2x or x^2+2x-3=0 factoring gives (x+3)(x-1)=0 so x=-3 and x=1 ... from the first equation; when x=-3, y=5 and when x=1, y=-3 these numbers check with the second equation
 Linear-systems/79185: This question is from textbook College Algebra How do I solve this? I've tried by susbtitution and elimination without success. (1/3)x - (3/2)y = -5 (3/4)x + (1/3)y = 11 Thank you!1 solutions Answer 56841 by scott8148(6628)   on 2007-04-22 18:09:46 (Show Source): You can put this solution on YOUR website!sometimes, eliminating the fractions will make things easier ... multiplying the first equation by 6 gives 2x-9y=-30 multiplying the second equation by 12 gives 9x+4y=132 ... multiplying again by 9 gives 81x+36y=1188 multiplying the first equation again by 4 gives 8x-36y=-120 ... adding equations gives 89x=1068 , so x=12 and y=6
 logarithm/79109: logx+log141 solutions Answer 56802 by scott8148(6628)   on 2007-04-21 23:36:58 (Show Source): You can put this solution on YOUR website!logarithms are essentially exponents ... you add exponents (providing the bases are the same) when you are multiplying numbers so log(x)+log(14)=log(14x)
 Polynomials-and-rational-expressions/79090: What are the solutions of the following? pick a right chioce (x - 5)(x + 3) = 0 a. 5 and -3 b. 5 and 3 c.-5 and -3 d.-5 and 3 1 solutions Answer 56800 by scott8148(6628)   on 2007-04-21 23:22:43 (Show Source): You can put this solution on YOUR website!if the product of two quantities is zero, then one or both of them must be zero x-5=0 so x=5 ... x+3=0 so x=-3 looks like (a) is the winner
 Linear_Equations_And_Systems_Word_Problems/79076: This question is from textbook Algebra:Structure and Method Find the coordinates of the vertex and the equation of the axis of symmetry of the graph of the equation. y=x squared - 3x - 101 solutions Answer 56797 by scott8148(6628)   on 2007-04-21 23:14:03 (Show Source): You can put this solution on YOUR website!see 79012
 Linear_Equations_And_Systems_Word_Problems/79012: This question is from textbook Algebra:Structure and Method Find the coordinates of the vertex and the equation of the axis of symmetry of the graph of each equation. y=x squared-3x-101 solutions Answer 56795 by scott8148(6628)   on 2007-04-21 23:13:02 (Show Source): You can put this solution on YOUR website!this is the equation of a parabola with the axis of symmetry parallel to the y-axis and opening upward the axis of symmetry is midway between the points where the parabola crosses the x-axis (y=0) ... factoring gives (x-5)(x+2)=0 ... so the crossing points are (5,0) and (-2,0) the axis of symmetry goes thru (1.5,0) and the equation is x=1.5 ... this is also the x value for the vertex plugging into the original equation, y=2.25-4.5-10 ... so the vertex is (1.5,-12.25)
 Polynomials-and-rational-expressions/79104: I need to find the solution set of the equation x/(x-2) + 5/x(x-2) = 9/2(x-2). I think the LCD is 2x(x-2), and multiplying the numerators by the missing factors of the LCD, I get 2x^2 + 10/LCD = 9x/LCD, but that's as far as I got.1 solutions Answer 56793 by scott8148(6628)   on 2007-04-21 22:29:12 (Show Source): You can put this solution on YOUR website!good job on the LCD ... since this is an equation, you need to treat both sides the same to keep things equal just multiply the whole equation by the LCD ... 2x^2+10=9x ...or 2x^2-9x+10=0 ... factoring gives (2x-5)(x-2)=0 so x=5/2 and x=2
 Functions/79114: Please help me answer this question. This is a worksheet. I have consulted my textbook and the resource books my mom bought. I'm very confused. A rancher who raises ostriches has 60 yards of fencing to enclose 4, equally sized, rectangular pens for his flock of ostriches. He is considering two options: A. Arrange the smaller pens in a line with adjacent pens sharing one common fence. (The diagram shows a rectagle divided vertically into 4 sections.) B. Arrange the four smaller pens so that they share exactly two common fences as shown in the diagram. (The diagram shows a rectangle that is divided in half horizontally and then vertically.) The problems is: Define the functions for the total area of each of the two options. I've tried dividing out 60 and plugging it into each diagram hoping that would help me come up with a function. I also tried working with a linear equation, but I think it suppose to be a quadratic function. I appreciate any help you can give me. Thank you.1 solutions Answer 56792 by scott8148(6628)   on 2007-04-21 22:16:58 (Show Source): You can put this solution on YOUR website!you need to define the dimensions of the rectangles in terms of length (l) and width (w) and 60 yards of fence A. in this case, 2 lines of fence correspond to the length and 5 lines to the width ... so 2l+5w=60 ... or l=(60-5w)/2 since area equals l times w, substituting for l gives ... a=((60-5w)/2)*w ... area = B. similar to A, 3 lines are equal to the length and 3 lines are equal to the width ... so 3l+3w=60 ... or l=20-w again, substituting gives ... a=(20-w)*w ... area = you could also solve for w in terms of l and substitute to get the areas in terms of l
 Triangles/78260: Gi ven the numbers as measurments of the sides of a triangle, Can the triangle exist and explain, A. 8,10,20 B. 16,18,25 C.7,7,71 solutions Answer 56124 by scott8148(6628)   on 2007-04-15 17:05:27 (Show Source): You can put this solution on YOUR website!a triangle can exist as long as the sum of the two shorter sides is greater than the longest side ... otherwise, the triangle can't close using this fact, A is not possible while B and C are