New!
Get regular updates about newly solved problems
via algebra.com's RSS system.
Recent problems solved by 'richard1234'
richard1234 answered: 5385 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399, >>Next
Travel_Word_Problems/397717: A driver leaves on a road trip at 8:00am. The function v(t) is the speed he is traveling t hours after the start of the trip. What value of t should be used so that v(t) will represent the driver's speed at 9:40 am? (three decimal places) 1 solutions
Answer 281802 by richard1234(5390) on 2011-01-20 23:25:34 (Show Source):
|
Expressions-with-variables/397724: Please help me solve this practice test question:
If ab=10, and a-squared + b-squared = 30, solve for y in the equation, y=(a+b)squared. Can you explain it also? Many thanks!
a. 40
b. 45
c. 50
d. 55 1 solutions
Answer 281801 by richard1234(5390) on 2011-01-20 23:23:41 (Show Source):
|
Polynomials-and-rational-expressions/397710: Here is a word problem I am having difficulty getting started on. I don't have an example in my book to help.
A population of deer in a state forest was rapidly decreasing due to over-hunting. To prevent further population decline, lawmakers enacted hunting restrictions. A biologist studying the deer found that, with the hunting restrictions in effect,t he growth of the deer population could be modeled by
N= 0.6x^4-20x^3+225x^2-950x+2300
where N represents the number of deer and x represents the number of years the restrictions are in effect. Using this model, estimate what the deer population would be if the hunting restrictions were kept in effect for 15 years. 1 solutions
Answer 281793 by richard1234(5390) on 2011-01-20 22:12:05 (Show Source):
You can put this solution on YOUR website!It's a little difficult to estimate with x = 15 because of those nasty coefficients in the other terms. It's much better just plugging x = 15 into a calculator, or on paper.
|
Complex_Numbers/397698: How do i solve the equation _ What is the square root of 4-7i? 1 solutions
Answer 281790 by richard1234(5390) on 2011-01-20 22:08:06 (Show Source):
You can put this solution on YOUR website!It is indeed possible to solve it using Euler's formula, by multiplying/dividing by  to obtain a unit vector and obtaining:
 where  and  .
However, the easiest way is probably to assume that the square root of  is  for real numbers a,b. Squaring both sides,
Equating the real and imaginary parts, we get the system of equations
 --> ab = -7/2.
Using the substitution b = -7/2a,
Use the quadratic formula to solve for  then take the square root. Note that  must be positive based on our assumption that a and b are real numbers. After that, the rest is just arithmetic.
|
Miscellaneous_Word_Problems/397536: What is the distance from Langhorne to Newtown if the car is traveling 35miles/hr up Rt.413 for 0.12seconds.... this is a sience problem. i am have terrible troble not because i can't find the answer more because i dont under stant why i could travel from one city to another in .12 sesonds PLESE HELP!!! 1 solutions
Answer 281764 by richard1234(5390) on 2011-01-20 21:33:06 (Show Source):
|
Radicals/397677: I'm stuck could you please help me here.
Find f(2a) if f(x) =2-x^3 + 2x-5.
I'm reviewing for a test tomorrow.
thanks, Pete 1 solutions
Answer 281758 by richard1234(5390) on 2011-01-20 21:28:01 (Show Source):
|
test/397646: 6 years ago bob was 4 times as old as Mary. In 4 years he will be twice as old as Mary. How old are they? 1 solutions
Answer 281756 by richard1234(5390) on 2011-01-20 21:26:14 (Show Source):
You can put this solution on YOUR website!Let b and m be Bob's and Mary's ages. Then,
b-6 = 4(m-6) --> b-6 = 4m - 24
b+4 = 2(m+4) --> b+4 = 2m + 8
This is essentially a system of equations that can be solved for b and m. Solving using any method (I used substitution), we get m = 11, b = 26, so Mary is 11 and Bob is 26.
|
Numbers_Word_Problems/397591: The sum of the digits of a two-digit number is 13. Twice the first digit is 1 less than the second digit. What is the two-digit number? 1 solutions
Answer 281734 by richard1234(5390) on 2011-01-20 20:29:08 (Show Source):
You can put this solution on YOUR website!Suppose the digits are d and 13-d. Then,
2d = (13-d)-1 = 12-d
Solving, d = 4, 13-d = 9. If 4 is the first digit (which satisfies the statement), then the number is 49.
|
Points-lines-and-rays/397519: I am doing something in math and I need the definition of "point." I looked in my math book, and there is no definition! I looked EVERYWHERE! Please can I have a good definition? 1 solutions
Answer 281729 by richard1234(5390) on 2011-01-20 20:21:39 (Show Source):
You can put this solution on YOUR website!I would do exactly what the other tutor did...just Google it. In fact, over 1.2 billion results showed up on my browser in .16 seconds.
|
Square-cubic-other-roots/397611: How do you simplify complex Radical numbers ?
ex: 3(squareroot of 3) - 1
-----------------------
3(squareroot of 2) - 1 1 solutions
Answer 281724 by richard1234(5390) on 2011-01-20 20:12:56 (Show Source):
You can put this solution on YOUR website!Btw, these do not involve complex numbers so I have changed the subject. However, some of these techniques can be used to simplify complex number expressions.
Multiply both sides by the conjugate of the denominator, i.e.  to produce
A consequence of the difference of two squares theorem, this ensures the denominator will be an integer.
|
Complex_Numbers/396778: How do I use a graph to demonstrate the operation of these complex numbers?
1. (7-6i)+(-5-2i)
2. (5-9i)-(-3-12i)
Thank you for your help! 1 solutions
Answer 281530 by richard1234(5390) on 2011-01-19 22:41:58 (Show Source):
You can put this solution on YOUR website!Complex numbers add exactly like vectors do. For example, on the first question, you have the complex number  , which is equivalent to a vector with an x-component of 7 and a y-component of -6. You're adding  which is another vector. To add them graphically, you could use the parallelogram rule or the head-to-tail method.
The second one is similar, but you have to subtract the vectors instead. (Hint: vectors follow the commutative properties and other arithmetic properties as real numbers do!)
|
Functions/396562: f(x)=3x^2-2x
f(0)=3(0)^2-2(0)=0
likewise for f-(-1), let x=-1 f(-1)=5 i don't undestand how they came up with 5
finally (2)=2(2)^2-2(2)=8 1 solutions
Answer 281523 by richard1234(5390) on 2011-01-19 22:33:19 (Show Source):
|
Probability-and-statistics/397124: Hello,
I have this math brain teaser that is killing me. Can you help please?
In a dark room, a boxed is filled with different colored balls there are 14 blue, 13 red, 22 black and 18 green. What is the smallest number of balls you need to select to get at least 4 of the same color.
Kindest regards,
Candy 1 solutions
Answer 281520 by richard1234(5390) on 2011-01-19 22:24:40 (Show Source):
You can put this solution on YOUR website!Note that the Pigeonhole Principle says that if there if we have kn + 1 pigeons distributed into n holes, then there is at least one hole with k+1 pigeons. In this case, n = 4 (there are four colors, or "holes"), and we want to guarantee that one of these "holes" has four "pigeons." Therefore, letting k = 3, we see that if we draw 3(4) + 1 or 13 balls, we are guaranteed to have four of the same color.
If there are 12 balls, then it is possible to draw three of each color.
|
Evaluation_Word_Problems/397119: Please help me solve this question!
"Determine the equation of the tangent to the circle (x-2)^2+(y+3)^2=13 at the point (5,-5)" 1 solutions
Answer 281516 by richard1234(5390) on 2011-01-19 22:19:52 (Show Source):
You can put this solution on YOUR website!Right away, we can tell that the center of the circle is at (2, -3).
It suffices to find the slope of the line between (2, -3) and (5, -5). This is because the radius of a circle is perpendicular to the line tangent to the circle at that point (5, -5).
The slope of the line is  . Therefore the slope of the line tangent to the circle is 3/2 (since these two lines are perpendicular). Since it runs through the point (5, -5) we can find the y-intercept:
-5 = 5(3/2) + b, where b is the y-intercept. Solving, we get b = -25/2, so the equation is  .
|
Length-and-distance/397114: I'm so stuck on this question! I don't even know where to start! please help!
"Use Coordinate geometry to verify that the triangle formed by the points (3,5) , (7,3) and (-5,4) is isosceles " 1 solutions
Answer 281510 by richard1234(5390) on 2011-01-19 22:09:24 (Show Source):
You can put this solution on YOUR website!The triangle can't be isosceles...this is because the distance between each pair of points is different:
(3,5), (7,3)
(3,5), (-5,4)
(7,3), (-5,4)
|
Complex_Numbers/396764: Hello, how do I figure out this complex numbers problem? Any help is greatly appreciated!
The point (-4+bi)has been plotted on the complex plane and r=8. If 0°≤θ≤180° find the value of b. Leave answer as a radical.
Thank you.
1 solutions
Answer 281507 by richard1234(5390) on 2011-01-19 22:04:32 (Show Source):
|
|