New!
Get regular updates about newly solved problems
via algebra.com's RSS system.
Recent problems solved by 'rapaljer'
rapaljer answered: 4664 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679, >>NextSystems-of-equations/22919: I did this text question but I want to make sure iots correct can you help here is my work
X/X squared+7x+12+ 2/x+3+ 4/x+4 I factored the X squared+7x+12 and gotx+4)(x+3)
LCD = (x+4) (X+3)
X+2(x+4)=4(x+3)
x+2x+8=4x+12
3x+8=4x+12
3x=4x+4
-1x=4
x=-4
1 solutions
Answer 11296 by rapaljer(4667) on 2005-12-18 18:42:58 (Show Source):
You can put this solution on YOUR website!This is correct, except for a couple of equal signs that should have been plus signs. I fixed those for you. Now, since this is a fractional equation, you have to check the answers to make sure you didn't accidentally divide by zero. There are certain values of x that are NOT acceptable. In this problem, x cannot equal -4, so you have to reject this answer, since it makes a denominator zero--NOT allowed! The answer is NO SOLUTION!
R^2 at SCC
|
Polynomials-and-rational-expressions/22624: a2+32a+60 1 solutions
Answer 11235 by rapaljer(4667) on 2005-12-17 01:17:57 (Show Source):
You can put this solution on YOUR website!Did you want to factor this? Find two numbers whose product is 60 that will add up to 32! If you can't think of it, start with 1, and say
"1 times 60"
"2 times 30"
"3 times 20"
"4 times 15"
"5 times 12"
"6 times 10"
7 doesn't go, nor does 8, or 9, but
"10 times 6" repeats the "6 times 10", so that means that you have all the combinations.
Obviously the 2 times 30 is the combination you needed. Now
 or
These answers are equally correct!
R^2 at SCC
|
Graphs/22622: Can someone help me solve for x?
(2x + 3y) + 3x = -3(y-4x) this is as far as I got
2x + 3y + 3x = -3y + 12x
5x + 3y = -3y + 12x
3y + 3y = 12x - 5x
6y = 7x
1 solutions
Answer 11234 by rapaljer(4667) on 2005-12-17 01:11:55 (Show Source):
|
Linear_Equations_And_Systems_Word_Problems/22673: A number differs from it's square by the average of the number and it's square
1 solutions
Answer 11233 by rapaljer(4667) on 2005-12-17 01:08:07 (Show Source):
You can put this solution on YOUR website!Let x = the number.
 = square of the number
 = difference between a number and its square
 = average of a number and it's square (add together and divide by 2)
The equation should look like this:
Multiply both sides of the equation by 2:
Set equal to zero, by subtracting x and  from each side:
Factor out the common factor of x:

x= 0 or x= 3
There are two solutions.
x=0: The square is 0. The difference of the number and its square is zero, and the average of 0 and its square is also 0.
x= 3: The square is 9. The difference of the number and its square is 6, and the average of the number and its square is  .
Both answers check.
R^2 at SCC
|
Coordinate-system/22851: Write an equation in slope-intercept form of a line with the following characteristics: Parallel to the graph of: -4x+3y=12
thank you very much :) 1 solutions
Answer 11232 by rapaljer(4667) on 2005-12-17 00:52:46 (Show Source):
You can put this solution on YOUR website!You must first find the slope of the given line by solving for y. Add 4x to each side:
-4x + 3y = 12
-4x + 4x + 3y = 4x + 12
3y = 4x + 12
Divide both sides by 3:
The slope of this line is  , so the slope of ANY line PARALLEL to this line will also be  . So the equation of any line is
y=mx+b
The equation of a line with slope  is  , where b is any number. It will also be the y-intercept of the line.
R^2 at SCC
|
Functions/22642: How do you solve: 3000=2000(1+.06)^t. 1 solutions
Answer 11231 by rapaljer(4667) on 2005-12-17 00:44:38 (Show Source):
You can put this solution on YOUR website!
Divide both sides by 2000:
In order to solve for t, where t is an exponent, you must take the ln of each side of the equation. It also works to take the log of each side--exactly the same answer!
This should bring back the laws of logarithms, in which the exponent becomes the coefficient:
Finally divide both sides by ln(1.06), and calculate with a calculator:
 = 6.958515, which rounds off to about 6.96.
R^2 at SCC
|
Graphs/22623: Can someone help me solve for y:
5(4x + 3) <= -1/2y + 5
20x + 15 <= -1/2y + 5
20x + 15 - 5 <= -1/2y
20x + 10 <= -1/2y
I get lost after this. 1 solutions
Answer 11230 by rapaljer(4667) on 2005-12-17 00:35:39 (Show Source):
You can put this solution on YOUR website!What you have done so far looks right.
20x + 10 <= -1/2y
Now multiply both sides by -2, which of course reverses the inequality sign:
-2(20x + 10) >= -2(-1/2y)
-40x - 20 >= y
You probably don't want y on the right side so switch sides, but when you do this reverses the inequality again:
-40x - 20 >= y
y<=-40x-20
Is that what you wanted to do??
R^2 at SCC
|
Linear-systems/22650: What is the range of the function f(x) = -x - 3, when the domain is {-1, 0, 4, 7}? 1 solutions
Answer 11229 by rapaljer(4667) on 2005-12-17 00:29:24 (Show Source):
You can put this solution on YOUR website!Substitute the values of x to see what you get for f(x):
f(x) = -x - 3
f(-1) = -(-1) - 3 = -2
f(0) = -0 - 3= -3
f(4) = -4 - 3 =-7
f(7) = -7-3 = -10
Range is the set of all y-values, or in this case, all f(x) values, so
Range = { -2, -3, -7, -10}
R^2 at SCC
|
Inequalities/22850: How do you graph the coordinate plane of
y>2 ????? 1 solutions
Answer 11228 by rapaljer(4667) on 2005-12-17 00:22:56 (Show Source):
You can put this solution on YOUR website!Draw the line y = 2, which is up two units on the y axis, and draw a HORIZONTAL LINE. Because you are graphing y > 2, you do NOT want to include the line, so draw a DOTTED LINE (not a solid line!). Next, since you are graphing y > 2, you will be shading ABOVE the line. If it had been y < 2, then you would have to shade BELOW the line.
I don't know how to draw this for you in the medium of algebra.com, so you'll have to draw it yourself. That is a DOTTED, HORIZONTAL LINE, UP 2 units, and shade everything above the line.
R^2 at SCC
|
real-numbers/22807: Please help me solve this problem:
Find the GCF:
6x, 12xy, 18y.
Thanks 1 solutions
Answer 11226 by rapaljer(4667) on 2005-12-17 00:17:47 (Show Source):
You can put this solution on YOUR website!GCF means the Greatest Common Factor, which means the largest factor that divides into all three terms. It may contain numbers and variables. First look at the numbers. The largest number that divides into 6, 12,and 18 is 6. There are NO variables that divide into all three terms, so the GCF = 6.
R^2 at SCC
|
Probability-and-statistics/22696: A shipment of light bulbs undergoes an inspection where 200 bubls are testes and 6 turn out defective.
a.What is the probability that a light bulb in this shipment is defective?
b. If the shipment contains 10280 light bulbs, predict how many from the entire shipment will be defective.
1 solutions
Answer 11225 by rapaljer(4667) on 2005-12-17 00:14:52 (Show Source):
You can put this solution on YOUR website!Probability of a defective bulb =
The ratio of defective bulbs to the number of bulbs tested would be the fraction
 =  = 3%
Out of 10280 bulbs, you would expect that approximately
 or about 308 or 309 bulbs will be defective.
R^2 at SCC
|
Coordinate-system/22849: I'm not real sure what catergory I should have put this question in, but I'm really having a difficult time understanding parallel and perpendicular lines.
here is the Question: Write an equation in slope-intercept form of a line with the following characteristics. Perpendicular to the graph of: y=3/2x-3.
my algebra book does not explain this well so if you could help me it would be greatly appreciated. Thanks. chris 1 solutions
Answer 11224 by rapaljer(4667) on 2005-12-17 00:03:49 (Show Source):
You can put this solution on YOUR website!If the given equation is y=3/2x -3, this means that the slope of the given line is  . The slope of any line parallel to this line is also going to have a slope of  , but that's another question. In this case, you need the slope of a line that is PERPENDICULAR to the given line. This slope would be the NEGATIVE RECIPROCAL of the slope  which would be  .
The equation of a line in slope intercept form is  . So the slope of a line perpendicular to the given line must have slope of  , so the equation would be  , where b could be any value, since no other restrictions were given. Usually the problem requires that the line pass through a given point, in which case you must also solve for b. But this too is another question!
Final answer,  , where b represents any number (which would also turn out to be the y intercept).
R^2 at SCC
|
Radicals/22803: We're rationalizing the demoninator. I'm having difficulty solving this:
4
-----
The Cube root of 3.
Help? 1 solutions
Answer 11223 by rapaljer(4667) on 2005-12-16 23:55:12 (Show Source):
You can put this solution on YOUR website!Before beginning ANY cube root problem, be sure that you know your perfect cubes. That is,
 ,  ,  ,
Now,
The idea is to somehow get the number in that radical in the denominator up to a perfect cube. When you think of the 3 inside the cube root sign, what perfect cube comes to mind associated with 3? The answer should be 27.
You need to get that denominator from 3 up to 27, by multiplying it by 9. In other words you must multiply the numerator and denominator by the cube root of 9.
Multiply numerator times numerator and denominator times denominator:
=  =  =
R^2 at SCC
|
Expressions-with-variables/22828: solve and write in simplest form
x^2-12x=0 1 solutions
Answer 11221 by rapaljer(4667) on 2005-12-16 23:35:18 (Show Source):
You can put this solution on YOUR website!Did you notice that this is a Quadratic Equation (see many of our lesson plans on solving quadratic equations!) Did you notice that this equation is already equal to zero? (This is VERY good!) Did you notice that there is a common factor of x? Then factor the common factor:
x(x-12)=0
Now, set each factor equal to zero.
x= 0 and x-12= 0
x=0 and x= 12
Wasn't that easy??
R^2 at SCC
|
Proportions/22839: ((x^2-4)/(x^2-4x-21))/((x^2-7x+10)/(X^2-2x-35))
This particular problem has been giving me lots of trouble. I figured that you would have to factor the bottom of the fractions to make them have four terms but I am stuck there. Id appreciate the help Thanks! 1 solutions
Answer 11220 by rapaljer(4667) on 2005-12-16 23:28:54 (Show Source):
You can put this solution on YOUR website!Is this a complex fraction that looks like this:
If so, then notice that you have a numerator which is a fraction and a denominator which is a fraction. Notice also that the middle fraction line separating the numerator and the denominator is the longest line. Now, just "unstack" the problem by writing this in the form of a
(NUMERATOR) divided by (DENOMINATOR).
Now, invert the second fraction and multiply. While you are at it, factor all the trinomials:
Divide out the (x-7) and the (x-2) factors, and you should be left with  for your final answer.
R^2 at SCC
|
Linear-equations/22841: I am not sure what my daughter teacher is wanting done on this problem, which is not from the text.
2X + 3Y = 6 y the y out to the right I assume means to solve for y.
Please help. 1 solutions
Answer 11219 by rapaljer(4667) on 2005-12-16 23:10:27 (Show Source):
You can put this solution on YOUR website!Get the y terms on one side (the left side) and all the other terms to the right side, but adding -2x to each side:
2x + 3y = 6
2x - 2x + 3y = -2x + 6
3y = -2x + 6
Next, divide both sides by 3 to undo the 3. It can be done in two ways. Here is the first way:
OR the second way:
R^2 at SCC
|
Linear-equations/17648:
The directions in my Algebra book is to "graph this equation". I'm not sure how to do these problems, but if I have an example to look at, I think I can figure the other problems out. PLEASE HELP! Thank-you. 1 solutions
Answer 8538 by rapaljer(4667) on 2005-10-30 00:57:41 (Show Source):
You can put this solution on YOUR website!Please see my recent Lesson Plan on Graphing and Slope of the Line for more details and examples. In this equation, the y intercept is 1, and the slope is -4 or -4/1, which means a rise of -4 and a run of 1.
To graph this start by graphing the y-intercept by going 1 unit up on the y-axis, and put the first point here. Next, with your pencil on this point on the y-axis, move DOWN 4, then go over 1 unit to the right, and put the next point. Then draw a line connecting the two points. It should look like this:
R^2 at SCC
|
Mixture_Word_Problems/17662: A car radiator holds 24 L of a 20% antifreeze solution. How much of the 20% solution should be drained and be replaced with pure antifreeze to give a 40% antifreeze solution? 1 solutions
Answer 8536 by rapaljer(4667) on 2005-10-30 00:39:06 (Show Source):
You can put this solution on YOUR website!Begin with 24 L of .20 antifreeze
Drain x L of .20 antifreeze
Add x L of 1.00 antifreeze
Equals 24 L. of .40 antifreeze
Equation:
.20(24) - .20x + 1.00x = .40(24)
4.80 + .80x = 9.60
4.80-4.80 +.80x = 9.60 - 4.80
.80x = 4.80
 liters
R^2 at SCC
|
Proportions/17671: Deborah has a recipe that makes 4 dozen chocolate chip cookies. It requires 2 cups of chocolate chips for every 5 cups of flour. If she needs 36 cookies, how many cups of chocolate chips will she need? 1 solutions
Answer 8535 by rapaljer(4667) on 2005-10-30 00:29:45 (Show Source):
You can put this solution on YOUR website!Would you like an equation, or shall we do it the easy way?
The easy way is to notice that 4 dozen cookies require 2 cups, so 36 cookies would be 3 dozen. That's 3/4 as many cookies, which will require 3/4 as many chocolate chips.
So, just take 3/4 of 2 cups, which would be  or a cup and a half of chocolate chips.
R^2 at SCC
|
Proportions/17672: A recipe for 2 1/2 dozen whole sheat muffins requires 600g of flour. How many muffins can be made with 900g of flour? 1 solutions
Answer 8534 by rapaljer(4667) on 2005-10-30 00:07:13 (Show Source):
You can put this solution on YOUR website!2 1/2 dozen muffins would be 24 + 6 or 30 muffins with 600 g of flour.
Let x = number of muffins made with 900 g of flour.
Set up a ratio with muffins divided by flour:
Remember that  means that
In the same way, cross-multiply
 to obtain:
Divide by 600:
 muffins.
HOWEVER, the EASY way to do this, in this particular case, is to notice that you are comparing 600 g of flour with 900 g of flour. This is half again as much as 600 g., so you can make half again as many muffins. Half of 30 is 15, so add 30+15= 45 muffins. Much easier, right???
R^2 at SCC
|
Graphs/17674: One plane left New York headed to Tokyo flying at an average speed of 375 mi/h. Another plane left New York 1 h. later following the same route and flying at an average speed of 500 mi/h. If both planes followed the same course, how many hours after it left New York would the second plane catch up to the first plane?
Write an equation you could solve to answer the question. 1 solutions
Answer 8533 by rapaljer(4667) on 2005-10-29 23:56:12 (Show Source):
You can put this solution on YOUR website!Let x = time of the second plane flying at 500 mph.
x+1 = time of the first plane flying at 375 mph.
Distance of first plane = Distance of second plane
R*T = R*T
500x = 375(x+ 1)
500x = 375x + 375
500x - 375x = 375x - 375x + 375
125x = 375
 hours = time for second plane to catch the first plane.
Check:
Distance of first plane = 4 *375= 1500 miles
Distance of second plane = 3*500 = 1500 miles
R%2 at SCC
|
real-numbers/17645: it's really about fctors but I can't find it so my question is how to solve this problem: 7*13+8*13+5*13 can you please solve it or instructions thanks 1 solutions
Answer 8529 by rapaljer(4667) on 2005-10-29 23:42:20 (Show Source):
You can put this solution on YOUR website!I have a feeling that whoever made up or assigned this problem had in mind to use the distibutive property to factor out the common factor of 13.
7*13+8*13+5*13 = 13*(7+8+5), which is 13*20 or 260, and you can almost do it in your head.
R^2 at SCC
|
Matrices-and-determiminant/17601: how would you solve this equation with elimination
5r+2s=0
-3t=12
6s+5t=10 1 solutions
Answer 8492 by rapaljer(4667) on 2005-10-28 21:22:29 (Show Source):
You can put this solution on YOUR website!This one is easier than it looks. First look at the second equation. You can see by looking at this equation that  .
Knowing that t=-4, solve for s in the third equation:
6s+5t= 10
6s+5(-4) = 10
6s-20=10
6s=30
s=5
Knowing that s=5, solve for r in the first equation:
5r + 2s=0
5r+2(5)=0
5r +10=0
5r= -10
r=-2
(r,s,t) = (-2, 5. -4)
R^2 at SCC
|
Radicals/17587: square x-2=3 solve by using graphing utility to verify the solution 1 solutions
Answer 8491 by rapaljer(4667) on 2005-10-28 21:01:02 (Show Source):
You can put this solution on YOUR website!Assuming that you mean  , the first step is to set the equation equal to zero to write  , and graph  . The solution will be the value(s) of x where this graph crosses the x axis. You can assume because of the square root that  . The value of x where the graph crosses the x axis is the solution for this equation:
The normal graph for x from -10 to 10 may NOT work here. You may need to use a value of x larger than 10. Let's try graphing up to x= 20 and see if the graph crosses the x axis. It turns out that x= 11 is the value that works, so this is the solution. X=11, and it checks also!
R^2 at SCC
|
Polynomials-and-rational-expressions/17594: Add these expressions.
a+6/a+2 + 16/a^2-4
1 solutions
Answer 8490 by rapaljer(4667) on 2005-10-28 20:53:29 (Show Source):
You can put this solution on YOUR website!Do you mean  ?? If so, then the first step in adding fractions is to factor the denominators so as to find the LCD.
 and the LCD = (a-2)(a+2).
In order to get the LCD in the first fraction, you already have the (a+2) factor, but you will need to multiply numerator and denominator of this first fraction by (a-2). The second fraction already has the LCD, so leave it alone.
Now you have an LCD of (a-2)(a+2), and this becomes THE denominator of the fraction:
Now, just add numerators together as follows:
Simplify:
The numerator DOES factor, so you must factor the numerator in order to reduce the fraction.
Divide out the (a+2) factor in the denominator with one of the numerator factors:
 FINAL ANSWER!!
R^2 at SCC
|
Radicals/17582: can some one please show me how to rationalize the denominator in this problem?
1 / 2 + radical x
thanks 1 solutions
Answer 8489 by rapaljer(4667) on 2005-10-28 20:27:22 (Show Source):
You can put this solution on YOUR website!I'm assuming that your problem is  .
Since this is a binomial denominator (two terms!), you must multiply numerator and denominator by the conjugate of the denominator--that is, the same as the denominator, but with the oppposite sign in the middle.
It looks like this:
 *
When you expand the denominator, the middle terms subtract out (as they ALWAYS do!), and the denominator is just  . This has no radicals, so it is said to be rationalized.
Final answer:
R^2 at SCC
|
Quadratic_Equations/17600: what is the difference between factoring and expanding? 1 solutions
Answer 8486 by rapaljer(4667) on 2005-10-28 20:11:40 (Show Source):
You can put this solution on YOUR website!Factoring and expanding are exactly the opposite operation. To factor means to express as a product. To expand means to multiply something out.
For examples, to factor 15 means to write it as a product 3*5.
To factor 5x+ 20 means to write 5(x+4), which is written as a product.
To factor  means to write it as a product  .
To expand 5(x+4) means to remove the parentheses and multiply it out: 5x + 20.
To expand  means to multiply it out:  .
R^2 at SCC
|
|