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Of your 4 choices:

A. 1ft. equals 30.48 centimeters --TRUE, since 12*2.54 = 30.48 cm.

B. 1 centimeter equals 2.54 inches FALSE--1 inch = 2.54 cm.

C. 1 rod equals 3.28 meters -- I have no idea!! Do a Google search for "Unit of Measure Rod" and see what you get!

D. 1 meter equals 1.09 feet--FALSE, since a meter is slightly more than a yard (which is 3 feet!)

My answer is A.

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A plane leaves Denver, colorado, on June 1st at 1 p.m. Mountain Standard Time and arrives at New York City on June 2nd at 2 A.m. Eastern Daylight Saving Time. the actual time of this flight was...
A. 10 hours B. 11 hours C. 12 hours D. 13 hours

I don't do much traveling, but there are two hours of difference between Mountain Standard Time and Eastern Standard Time, right? However, Daylight Saving Time is one hour EARLIER than Eastern Standard Time, so the total difference in time is 3 hours. Therefore, when it is 2 A.M. in New York, it is really only 11 p.m. in Colorado, for a flight of 10 hours.

As a confirmation, here is another way to explain it:
2 a.m. EDT in NY = 1:00 a.m. EST in NY
1:00a.m. EST in NY = 11:00 p.m. MST in Colorado

Flight was from 1 p.m. to 11:00 p.m., which is 10 hours.

I'm not going to bet my life on this one, but I'm pretty sure the answer is A. 10 hours. See if my argument sounds right. Re-post the question, and see if anyone else agrees or disagrees with me.

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From the beginning notice that B and b represent different variables!

Start by clearing the fraction. Multiply both sides by 2.



Next, use the distributive property to remove the parentheses:


Next, you must isolate the b term. Subtract Bh from each side.



Finally, you need to get the "b" by itself, so you need to "undo" the "h" that is multiplied times the "b". Because the operation is multiplication, you will need to DIVIDE both sides by h.



I should have a lesson plan in algebra.com on Literal Equations. Also, check my own website by clicking on my tutor name anywhere in algebra.com. Go to MATH IN LIVING COLOR, and look in Intermediate Algebra, in Section 1.04 and also Section 2.07.

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x=4 and x=-2
(x-4) =0 and (x+2) = 0

(x-4)(x+2) = 0


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The first step is to factor the numerator and denominator.



Divide out the FACTORS of (x-2):


See also my lesson plans in algebra.com or go to my own website by clicking on my tutor name "rapaljer" anywhere in algebra.com. Look for MATH IN LIVING COLOR. In Basic Algebra, this topic of Reducing Fractions will be in Chapter 3. In Intermediate Algebra (for more advanced problems!), it will be in Chapter 2.

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First find the LCD, which is 15. Multiply both sides of the equation by the LCD of 15.


Divide out the denominators of 5 and 3 respectively, and it should look like this:







Check by substitution:




It checks!

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I have an entire lesson plan on finding Least Common Denominators. Look for it in algebra.com. Also, please check my own website by clicking on my tutor name "rapaljer" anywhere in algebra.com, then click on "Basic Algebra", "Samples from Basic Algebra: One Step at a Time". In "Chapter 3", look for "Section 3.03: Least Common Denominators."

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Maybe you should recheck the problem. I think you have a couple of typographical errors in this.

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You need to state the problem! We don't have your book!!

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Assuming that this is what you mean:

Factor the denominator of the first fraction and the numerator of the second fraction:


Divide out the factors of (t-2):


When you multiply, this leaves:


Reduce the fraction, by dividing out the 10 and t, which leaves factors of 3 and t^2 in the numerator, and a factor of 4 in the denominator.



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This one looks intimidating, when you apply the quadratic formula. Actually, it's not so bad, once you get past the !


a=66, b=67, c=10





or
or

Of course, this means that the problem could have been solved by factoring!!


Another really interesting problem!!

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You forgot to post the problem???

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It doesn't happen very often, but let's try it. Just remember to obey the rules, and don't make up new rules that aren't true for all real numbers. What we know is that you can multiply provided a and b are NOT both negative. Also, you know that rationalizing the denominator is always a good place to start:


Now, be really careful not to change the rules or make up "new" ones!






Now, I know this is correct because I checked it with my calculator. However, there may be something else that can be done to eliminate the square root of the square root. I remember doing something like this about 20 years ago in trigonometry, but I haven't worked with it in a very long time. Therefore, if you want a second opinion, go ahead and post the question again, and see if someone else has some ideas about it.

This is a very interesting problem!!

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The perimeter of a triangle is the sum of its sides: 6+8+10 = 24 inches.

The radius of a circle is half the diameter: 8/2 = 4 inches.

The volume of a cube is : cubic inches.

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There are two ways to interpret this equation. Do you mean
or do you mean ?? What you have written technically means the first way I wrote it, but usually what is meant is the second way to write it.

If the problem is , then solve it this way. Multiply both sides by n:


Add +s to each side and subtract nD from each side:



You probably meant this:
Multiply both sides by n:



Add +s and subtract nD from each side:



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You need to state the problem!!

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The big deal in math is that you are NOT allowed to divide by zero!! Therefore, any number that makes a denominator zero is NOT allowed!! In this case, the denominator factors:


Therefore the values of x that must be excluded are x=7 and x=2.

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First graph the line y=2x-1, which is a straight line with y intercept -1 and slope is 2/1.


Graph this with a dotted line, and shade everything below the line.

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(-4,0) and (-5,-3)

Distance =

Difference between x values is 1 unit.
Difference between y values is 3 units.

Distance =
Distance =

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Let e= a+bi, and e(complememt) = a-bi

What you have is
e + 6ē = 7
a+bi + 6(a-bi) = 7 +0i
a+bi +6a -6bi = 7 + 0i
7a -5bi = 6 + 0i

Therefore, 7a= 6, so a=6/7
and -5b= 0, so b=0

Therefore, e=6/7 +0i

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Remove parentheses


Combine like terms:


Factor out the common factor of h:


Divide out the h factor:


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Remove parentheses


Combine like terms:


Factor out the common factor of h:


Divide out the h factor:


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Since there are no variables in the denominator, you can find the LCD for the entire problem, which is 12, and multiply both sides by the LCD:






Remember, when you divide both sides of an inequality by a negative number, you must reverse the inequality!!


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You need to state the problem.

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What was the question? Were you supposed to determine which two expressions have the same value???

is not a real value (or if you consider complex numbers, the value is 9i.



I suppose if you want two that are equivalent, it would be and .

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This can also be written with a common denominator of 5:


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A double root occurs when the power of the factor that gives you the root is 2.

a) 8y^2 +1 = 6y


No double roots, since the powers of the factors are not 2.

b) x^4-25x^2 =0


x=0 is of multiplicity 2, since the power of the x factor is 2.

c)(X-3)^3-(x-3)^2= 0


x=3 is of multiplicity 2, since the power of the (x-3) factor is 2.

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A double root occurs when the power of the factor that gives you the root is 2.

a) 8y^2 +1 = 6y


No double roots, since the powers of the factors are not 2.

b) x^4-25x^2 =0


x=0 is of multiplicity 2, since the power of the x factor is 2.

c)(X-3)^3-(x-3)^2= 0


x=3 is of multiplicity 2, since the power of the (x-3) factor is 2.

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Find a perfect square, the largest one you can find, that divides evenly into 500. This would be 100. Make that, 100*5




For additional help on square roots, see my Lesson Plans on algebra.com or go to my own website by clicking on my tutor name "rapaljer" anywhere in algebra.com, then look for MATH IN LIVING COLOR and go to Basic Algebra, Section 5.01.

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A(t)= -16t^2 + 32t + 6 , when t=2:
A(2) = -16*2^2+32*2+6
A(2) =-16*4+ 64 + 6
A(2) =-64+64+6
A(2)=6 feet

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I used a calculator to find . Are you allowed to use calculators? If not, then try this. Break down the number 3375 by trying to find a perfect cube that divides evenly into 3375. The perfect cubes are

2^3 = 8
3^3= 27
4^3= 64
5^3= 125

To begin with , since 3375 ends in a 5, it is divisible by 5, so try dividing 2275 by 125. It goes 27 times. So you can break it down like this:






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