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Exponential-and-logarithmic-functions/375399: write an exponential equation y=ab^x whose graph passes through these points
(1,10), (2,25) 1 solutions
Answer 266965 by nerdybill(6958) on 2010-11-23 11:36:42 (Show Source):
You can put this solution on YOUR website!write an exponential equation y=ab^x whose graph passes through these points
(1,10), (2,25)
.
From:(1,10)
10 = ab^1
10 = ab (equation 1)
and from:(2,25)
25 = ab^2 (equation 2)
.
solve equation 1 for b:
10 = ab
10/a = b
.
substitute it into eq 2 and solve for a:
25 = ab^2
25 = a(10/a)^2
25 = a(100/a^2)
25 = (100/a)
a = 100/25
a = 4
.
substitute it into eq 1 and solve for b:
10 = ab
10 = 4b
10/4 = b
2.5 = b
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Angles/375294: find the measure of a supplement of a 70 degree angle....thank you 1 solutions
Answer 266963 by nerdybill(6958) on 2010-11-23 11:33:00 (Show Source):
You can put this solution on YOUR website!find the measure of a supplement of a 70 degree angle:
.
Two angles are "supplement" if the sum is 180 degrees.
.
Therefore,
the measure of the supplement of 70 is:
180-70 = 110 degrees
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Quadratic-relations-and-conic-sections/375307: Please help me solve this question.
A ball is thrown vertically upward. After t seconds, it's height h (in feet) is given by the function h(t)= 104t-16t^2. What is the maximum height that the ball will reach? Do not round your answer. Height: ___ ft 1 solutions
Answer 266962 by nerdybill(6958) on 2010-11-23 11:31:02 (Show Source):
You can put this solution on YOUR website!h(t)= 104t-16t^2
max height is at the vertex.
.
Vertex is when:
t = -b/(2a) = -104/(2*(-16)) = -104/(-32) = 3.25
.
h(3.25)= 104(3.25)-16(3.25)^2
h(3.25)= 338-169
h(3.25)= 169 feet
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logarithm/375373: let log2=a log3 =b and log 5= c, what is log 16 log 0.00003 log 8/3 in terms of a, b , c? please help 1 solutions
Answer 266941 by nerdybill(6958) on 2010-11-23 10:06:29 (Show Source):
You can put this solution on YOUR website!let log2=a log3 =b and log 5= c, what is log 16 log 0.00003 log 8/3 in terms of a, b , c?
.
log(16)
= log(2^4)
= 4*log(2)
= 4a
.
log(0.00003)
= log(3/10^5)
= log(3) - log(10^5)
= log(3) - 5log(10)
= log(3) - 5log(2*5)
= log(3) - 5[log(2)+log(5)]
= b-5[a+c]
.
log 8/3
= log(8)-log(3)
= log(2^3)-log(3)
= 3log(2)-log(3)
= 3a-b
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Graphs/375321: An investor of a new product believes that the cost of producing the product is given by the function:
C(x) = 1.75x + 7000
How much does it cost to produce 2000 units of her invention?
1 solutions
Answer 266940 by nerdybill(6958) on 2010-11-23 10:00:38 (Show Source):
You can put this solution on YOUR website!An investor of a new product believes that the cost of producing the product is given by the function:
C(x) = 1.75x + 7000
How much does it cost to produce 2000 units of her invention?
.
In this case, x is 2000
So, plug it in and solve:
C(x) = 1.75x + 7000
C(2000) = 1.75(2000) + 7000
C(2000) = 3500 + 7000
C(2000) = $10,500
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Quadratic_Equations/375243: how do solve: h(t) = -16t^2 + 90t + 15 1 solutions
Answer 266853 by nerdybill(6958) on 2010-11-22 23:11:15 (Show Source):
You can put this solution on YOUR website!how do solve: h(t) = -16t^2 + 90t + 15
.
this is an equation of motion for a projectile of some sort.
.
You really can't "solve" this -- you can however answer some questions such as:
-max height (vertex)
-time it hits the max height (vertex)
-time it hits the ground (set h(t) to zero solve for t)
.
What was the question?
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Expressions-with-variables/374996: Machine A can complete a task in 24 seconds. Together with machine B, the task can be completed in 18 s. How long would it take machine B working alone to complete the task?
1 solutions
Answer 266683 by nerdybill(6958) on 2010-11-22 15:31:38 (Show Source):
You can put this solution on YOUR website!Machine A can complete a task in 24 seconds. Together with machine B, the task can be completed in 18 s. How long would it take machine B working alone to complete the task?
.
Let x = seconds it takes machine B (working alone)
then
18(1/24 + 1/x) = 1
multiplying both sides by 24x:
18(x + 24) = 24x
18x + 432 = 24x
432 = 6x
72 secs = x
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Miscellaneous_Word_Problems/374292: When a projectile is fired, the vertical component of its initial velocity is such that its height h metres t seconds after firing is given by .
Determine if the projectile will reach each height.
a)2.75km
b)4.0km 1 solutions
Answer 266370 by nerdybill(6958) on 2010-11-21 09:04:15 (Show Source):
You can put this solution on YOUR website!
Is a quadratic (parabola) that opens downwards. We can tell because the coefficient associated with the t^2 term is negative. If so, then the vertex defines the hight point.
.
Highest point is reached when the time is:
t = -b/(2a) = -250/(2*(-4.9)) = -250/(-10.8) = 25.51
Highest point projectile will reach:
 meters
 kilometers
.
So, now we can answer the question:
a)2.75km (yes)
b)4.0km (no)
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Linear-equations/373983: Please can someone help!!
Find the slope-intercept equation of the line that has the given characteristics
Slope 4 and y-intercept (0,7)
The slope - intercept equation is ___? 1 solutions
Answer 266169 by nerdybill(6958) on 2010-11-20 10:58:10 (Show Source):
You can put this solution on YOUR website!Plug the given information:
Slope 4 and y-intercept (0,7)
into the "point-slope" form of:
y - y1 = m(x - x1)
y - 7 = 4(x - 0)
y - 7 = 4x
y = 4x + 7 (this is what they're looking for)
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Quadratic_Equations/373974: Write a quadratic equation for -7,5 1 solutions
Answer 266155 by nerdybill(6958) on 2010-11-20 10:04:00 (Show Source):
You can put this solution on YOUR website!I'm assuming you want a quadratic that crosses at a point (x,y)
where
(x,y) = (-7,5)
.
If so, consider:
y = x^2 + x + C
Plug in your values, solve for C:
5 = (-7)^2 + (-7) + C
5 = 49 - 7 + C
5 = 42 + C
-37 = C
So, your equation would be:
y = x^2 + x - 37
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Linear-equations/373807: My niece is in 8th grade and is having trouble with Slope intercept form, Point intercept form and Standard form. I told her I would help her but in order to do that I must learn what these are. Can you help Me? 1 solutions
Answer 266027 by nerdybill(6958) on 2010-11-19 19:41:56 (Show Source):
You can put this solution on YOUR website!www.purplemath.com is a good place to start.
All three are used to describe a straight line.
.
Slope-intercept form:
http://www.purplemath.com/modules/strtlneq.htm
y = mx + b
where
m is the slope
b is the y-intercept (point at which it crosses the y-axis)
.
Point-slope form:
http://www.purplemath.com/modules/strtlneq2.htm
y - y1 = m(x - x1)
is basically used when you are given one point (x1, y1) and a slope and you want to determine the equation of the line.
.
Standard form is in the form: (not used too often)
Ax + By = C
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Miscellaneous_Word_Problems/373121: I am not sure how to go about this word problem so can you please help me solve this problem. I am getting overwhelmed!
John wants to fence a 150 square meters rectangular field. He wants the length and width to be natural numbers {1,2,3,...}. What field dimensions will require the least amount of fencing? Show work.
Thank you so much!
Jessica 1 solutions
Answer 265651 by nerdybill(6958) on 2010-11-18 10:32:10 (Show Source):
You can put this solution on YOUR website!John wants to fence a 150 square meters rectangular field. He wants the length and width to be natural numbers {1,2,3,...}. What field dimensions will require the least amount of fencing?
.
You could create a "table":
width length area perimeter
1 150 150 302
2 75 150 154
3 50 150 106
5 30 150 70
6 25 150 62
10 15 150 50
15 10 150 50
25 6 150 62
30 5 150 70
.
From the above, we see that the answer is a field that is:
10 feet by 15 feet
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Equations/373108: Hi tutors.. :) Im having a problem with Algebra Number Problems. For example an equation like this : There are two numbers whose sum is 72. One number is twice the other. What are the numbers?
Also. There are three consecutive integers. the sum of the smallest and largest is 36.
I just dont get it:( Help please 1 solutions
Answer 265647 by nerdybill(6958) on 2010-11-18 10:11:15 (Show Source):
You can put this solution on YOUR website!There are two numbers whose sum is 72. One number is twice the other. What are the numbers?
.
Let x = first number
then from "One number is twice the other." we have
2x = second number
.
From: "There are two numbers whose sum is 72" we derive our equation:
x + 2x = 72
3x = 72
x = 24 (first number)
Second number:
2x = 2(24) = 48
.
.
.
Also. There are three consecutive integers. the sum of the smallest and largest is 36.
.
Let x = first consecutive integer
then
x+1 = second consecutive integer
x+2 = third
.
From:"the sum of the smallest and largest is 36" we get:
x + x+2 = 36
2x+2 = 36
2x = 34
x = 17 (first)
.
Second:
x+1 = 17+1 = 18
.
Third:
x+2 = 17+2 = 19
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Quadratic_Equations/372797: Jack wanted to throw an apple to Lauren, who was on a balcony 40 feet above him, so he tossed it upward with an initial speed of 56 ft/s. Lauren missed it on the way up, but then caught it on the way down. How long was the apple in the air?
Would I use the equation h(t) = -16t^2 + 56t +40? (where h = height and t = time) I'm not very good at solving quadratic word problems :( 1 solutions
Answer 265524 by nerdybill(6958) on 2010-11-17 18:32:32 (Show Source):
You can put this solution on YOUR website!Well, you're close
The general equation is
h(t) = -(1/2)gt^2 + Vot + h(0)
where
g is gravity 32 ft/sec^2
Vo is initial velocity
h(0) is initial height of Jack (not Lauren)
.
So, plugging in what we know
h(t) = -(1/2)(32)t^2 + 56t + 0
which reduces to
h(t) = -16t^2 + 56t
.
So, since Lauren is 40 feet up -- set h(t) to 40 and solve for t:
h(t) = -16t^2 + 56t
40 = -16t^2 + 56t
0 = -16t^2 + 56t - 40
multiply both sides by -1:
0 = 16t^2 - 56t + 40
divide both sides by 8:
0 = 2t^2 - 7t + 5
0 = (2t-5)(t-1)
So,
t = {1, 5/2}
1 sec represents the time the apple reaches 40 ft (going up)
So
5/2 secs or
2 and 1/2 secs (is your solution)
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Linear-systems/372684: If an object is projected vertically upward from an altitude of s(o) feet with an intial velocity of v(o) ft/sec, then its distance above the ground after t seconds is: s(t)=-16t^2+ v(o)t+ s(o).
If s(1)= 64 and s(2)=66, what are s(o) and v(o)?
I honestly do not know how to set the problem up! Please help, it would be greatly appreciated!Thanks :)
1 solutions
Answer 265418 by nerdybill(6958) on 2010-11-17 14:26:23 (Show Source):
You can put this solution on YOUR website!Given:
s(t)=-16t^2+ v(o)t+ s(o).
If s(1)= 64 and s(2)=66, what are s(o) and v(o)?
.
So,
when x=1 then s(1)=64
and
when x=2 then s(2)=66
.
From here, you now have two unknowns and two equations:
when x=1 then s(1)=64
s(t)=-16t^2+ v(o)t+ s(o)
s(1)=-16(1)^2+ v(o)(1)+ s(o)
64=-16+ v(o)+ s(o)
89=v(o)+ s(o) equation 1
.
when x=2 then s(2)=66
s(t)=-16t^2+ v(o)t+ s(o)
s(2)=-16(2)^2+ v(o)(2)+ s(o)
66=-16(4)+ 2v(o)+ s(o)
130=2v(o)+ s(o) equation 2
.
Considering the "system of equations" then:
130=2v(o)+ s(o)
89=v(o)+ s(o)
.
Multiply both sides of the bottom equation by -1 and add:
130=2v(o)+ s(o)
-89=-v(o)- s(o)
---------------------
41 ft/sec = v(0)
.
Substitute the above into:
89=v(o)+ s(o)
89=41+ s(o)
48 feet = s(o)
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