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Money_Word_Problems/683587: A person invested $20,000, part at an interest rate of 6% annually and the remainder at 7% annually. The total interest at the end of 1 year was equivalent to an annual 6.75% rate on the entire $20,000. How much was invested at each rate?

1 solutions

Answer 423623 by mananth(12270) About Me  on 2012-11-21 06:52:41 (Show Source):
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6.75% on 20,000 = 1350 total interest earned.

Part I 6.00% per annum ------------- Amount invested =x
Part II 7.00% per annum ------------ Amount invested = y
20000
Interest----- 1350

Part I 6.00% per annum ---x
Part II 7.00% per annum ---y
Total investment
x + 1 y= 20000 -------------1
Interest on both investments
6.00% x + 7.00% y= 1350
Multiply by 100
6 x + 7 y= 135000.00 --------2
Multiply (1) by -6
we get
-6 x -6 y= -120000.00
Add this to (2)
0 x 1 y= 15000
divide by 1
y = 15000
Part I 6.00% $ 5000
Part II 7.00% $ 15000

CHECK
5000 --------- 6.00% ------- 300.00
15000 ------------- 7.00% ------- 1050.00
Total -------------------- 1350.00

m.ananth@hotmail.ca


Age_Word_Problems/683583: Two years ago, the sum of the ages of a boy and his sister is 20 years. Three years from now, their ages will differ by 10 years. Form a pair of linear equations and find their present age.
1 solutions

Answer 423622 by mananth(12270) About Me  on 2012-11-21 06:43:03 (Show Source):
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Let the boy's age bex
girls age be y
2 years ago their ages
x-2 boy's age
y-2 girls age
(x-2)+(y-2)=20
x+y-4=20
x+y=16...................(1)
3 years hence
their ages will be
x+3 & y+3
(x+3)-(y+3)=10
x-y=10.................(2)
Add (1) & (2)
2x= 26
x= 13 the boy's age
Girls age = 20-13=7
Their ages could be 13 & 7


Inequalities/683577: 1%2F3+%3C+%28x%2B4%29%2F2+%3C+2%2F3
1 solutions

Answer 423621 by mananth(12270) About Me  on 2012-11-21 06:33:32 (Show Source):
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1%2F3+%3C+%28x%2B4%29%2F2+%3C+2%2F3
Multiply by 2

%281%2A2%29%2F3+%3C+%28%28x%2B4%29%282%29%29%2F2+%3C+%282%2A2%29%2F3

2%2F3+%3C+%28x%2B4%29+%3C+4%2F3
add -4
%28%282%2F3%29-4%29%2F3+%3C+x%3C0

%28-10%2F3%29%3Cx%3C0


�t�e�s�t/683560: Dear tutors,
please help me answer:
solve for a: a/x + b/y = a/y
1 solutions

Answer 423617 by mananth(12270) About Me  on 2012-11-21 03:38:50 (Show Source):
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a%2Fx+-+a%2Fy=+b%2Fy
LCD = xy
(ay-ax)/xy = -b/y
(ay-ax)= (xy)(-b/y)
a(y-x) =(xy)(-b/y)
a= (xy)(-b/y)/(y-x)


Equations/683544: 2x+3y=200
5x+4y+290
1 solutions

Answer 423616 by mananth(12270) About Me  on 2012-11-21 03:35:02 (Show Source):
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2 x + 3 y = 200 .............1

5 x + 4 y = 290 .............2
Eliminate y
multiply (1)by -4
Multiply (2) by 3
-8 x -12 y = -800
15 x + 12 y = 870
Add the two equations
7 x = 70
/ 7
x = 10
plug value of x in (1)
2 x + 3 y = 200
20 + 3 y = 200
3 y = 200 -20
3 y = 180
y = 60
x= 10
y= 60
m.ananth@hotmail.ca


Sequences-and-series/683555: A ball takes 1 second to hit the ground when dropped.It then takes 90%of this time to rebound to its new height and this continues until the ball comes to rest.What is the geometric sequence?
1 solutions

Answer 423612 by mananth(12270) About Me  on 2012-11-21 03:18:26 (Show Source):
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To fall down it takes 1second s.
To go up on rebound 0.9 s (90% of the time)
To fall down 0.9 s (When it falls down t=,no change in time)
To go up and rebound II 0.9*0.9 = 0.9^2
To fall down 0.9^2
To go up 0.9^3
To come down 0.9^3
Hence the time taken is 1 + 2(0.9) + 2(0.9) ^2 + 2(0.9) ^3 +...


Money_Word_Problems/683103: Melody has $45,000 to invest and wishes to
receive an annual income of $4290 from this
money. She has chosen investments that pay
5%, 8%, and 12% simple interest. Melody
wants to have the amount invested at 12% to
be double the amount invested at 8%. How
much should she invest at each rate?
1 solutions

Answer 423472 by mananth(12270) About Me  on 2012-11-20 01:03:24 (Show Source):
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Total money $45,000
annual income of $4290 from this money.

5%,(45000-3x)
8%,,----------------x
and 12% ------------2x (double of x)
equate the interest
(45000-3x)*5% +8%x+12%(2x)=4290
multiply by 100
(45000-3x)*5 +8x+12(2x)=4290*100
225000-15x+8x+24x=429000
17x= 429000-225000
17x=204000
/17
x=204000/17
x=12000 nvestment @ 8%
Now you can calculate the other amounts


Linear-equations/683119: a part of monthly expenses of a family on milk is fixed which is rs. 500 and the remaining varies with the quality of milk taken extra at the rate of rs.20 per kg. taking the quantity of milk required as x kg and the total expenditure on milk is y write a linear equation for this information and draw the graph
1 solutions

Answer 423471 by mananth(12270) About Me  on 2012-11-20 00:46:41 (Show Source):
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milk bought = x kg
total expediture = y
Fixed amount = Rs500
variable is x
y= 500+20x
generate values of x & y
when x= 10, y= 700
x=20, y=900
x=50,y=1500



Travel_Word_Problems/683004: A crew of four practices rowing up a river, then back down for the same distance. The current of the river is 3 km/hr. Currently the crew can can row at 15 km/hr in still water and makes the round trip in 25 minutes. How far upstream did they row?
1 solutions

Answer 423428 by mananth(12270) About Me  on 2012-11-19 20:04:44 (Show Source):
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Let distance be x
upstream speed = 15-3=12 mi/h
downstream speed = 15+3=18 mi/h
Time upstream + time downstream = 25 minutes= 25/60 = 5/12 hours
t=d/r
x/12 + x/18 = 5/12
LCD = 36
multiply equation by 36
3x+2x=15
5x=15
x=3 miles


Trigonometry-basics/682943: I need help slove this identity, please show the steps becasue I subed in 2 for B and both sides were the same so I know it is an identity but I do not how to prove it without subing in a number
(1+2inBcosB)/(sinB+cosB)=sinB+cosB
Thanks :)
1 solutions

Answer 423426 by mananth(12270) About Me  on 2012-11-19 19:57:08 (Show Source):


Polynomials-and-rational-expressions/682986: factor 36a^5b^5+9ab^3-72ab^5
1 solutions

Answer 423419 by mananth(12270) About Me  on 2012-11-19 19:46:19 (Show Source):


Surface-area/682987: If the ratio of two areas of circle A+B is 4, what is the ratio of teh radii of A+B
1 solutions

Answer 423418 by mananth(12270) About Me  on 2012-11-19 19:43:18 (Show Source):
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Area of circle A = pi*r1^2
Area of circle B = pi*r2^2

Area of circle A = pi*r1^2
---------------- -------
Area of circle B = pi*r2^2

4= r1^2/r2^2
r1/r2 = sqrt(4)
r1/r2= 2 (the positive value )


Functions/682979: Find the equation in slope-intercept form of the line satisfying the conditions through (4,5); m=-5/9
1 solutions

Answer 423417 by mananth(12270) About Me  on 2012-11-19 19:40:12 (Show Source):
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point (4,5)
m=-5/9
The equation of line in point slope form is
%28y-y1%29=+m%28x-x1%29
where (x1,y1) is (4,5) and m= -5/9
y-5= (-5/9) (x-4)
multiply equation by 9 to eliminate the denominator
9(y-5)=(-5)(x-4)
9y-45=-5x+20
9y=-5x+20+45
9y=-5x+45
/9
y=(-5/9)x+5


Numeric_Fractions/682970: how do you solve (in detail- understanding) this 6 grade math problem...
4 1/5
-1 1/2

1 solutions

Answer 423414 by mananth(12270) About Me  on 2012-11-19 19:33:54 (Show Source):
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%284+%281%2F5%29%29+-%281+%281%2F2%29%29
convert the mixed fraction into a simple fraction
%28%285%2A4%2B1%29%2F5%29+-%28%282%2A1%2B1%29%2F2%29


%2821%2F5%29+-%283%2F2%29
We have to equalize the denominator to enable us to add or subtract the numerators of the two fractions.
the denominators of the fractions are 5 &2
multiply both of them we get 10
This will be the common denominator
5 times 2 is 10
so multiply the numerator and denominator of first fraction by 2
2 times 5 is 10
& multiply and divide the second fraction by 5 to get 10 denominator
%2821%2F5%29%2A%282%2F2%29-%283%2F2%29%285%2F5%29
%2842%2F10%29-%2815%2F10%29
Since the denominators are same we can subtract the numerators.
%2842-15%29%2F10
%2827%2F10%29
There you are!


Trigonometry-basics/682967: what is the x and y intercept of 2x plus 8y=-24
1 solutions

Answer 423408 by mananth(12270) About Me  on 2012-11-19 19:19:07 (Show Source):
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2x+8y=-24
For X intercept plug y=0
2x+0=-24
2x=-24
/2
x=-12
For Y intercept plug x =0
0+8y=-24
8y=-24
/-8
y=-3


Money_Word_Problems/682570: An investor invested a total of $900 in two mutual funds. One fund earned a 8% profit while the other earned a 2% profit. If the investor's total profit was $48, how much was invested in each mutual fund?
1 solutions

Answer 423250 by mananth(12270) About Me  on 2012-11-19 01:10:23 (Show Source):
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Part I 8.00% per annum ------------- Amount invested =x
Part II 2.00% per annum ------------ Amount invested = y =
900
Interest----- 48

Part I 8.00% per annum ---x
Part II 2.00% per annum ---y
Total investment
x + 1 y= 900 -------------1
Interest on both investments
8.00% x + 2.00% y= 48
Multiply by 100
8 x + 2 y= 4800.00 --------2
Multiply (1) by -8
we get
-8 x -8 y= -7200.00
Add this to (2)
0 x -6 y= -2400
divide by -6
y = 400
Part I 8.00% $ 500
Part II 2.00% $ 400

CHECK
500 --------- 8.00% ------- 40.00
400 ------------- 2.00% ------- 8.00
Total -------------------- 48.00

m.ananth@hotmail.ca


Miscellaneous_Word_Problems/682569: Arasoo is 4 years older than Peter.Ali is 2 years younger than Peter.If the sum of their ages is 47,what are their respective ages?
1 solutions

Answer 423249 by mananth(12270) About Me  on 2012-11-19 01:07:25 (Show Source):
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Let Peter's age be x years
Arasoo's age = x+4
ali's age x-2 years
Their sum = 47 years
x+x+4+x-2=47
3x=45
x=15
Peter's age = 15
Arasoo's age = x+4 , =19 years
Ali's age = x-2 . = 13 years


Travel_Word_Problems/682567: A boeing 747 flies the 3000 mile distance from Los Angeles to NEw York, with the tailwind, in 5 hours. The return trip, against the wind, takes 6 hours. Find the speed of the plane and the speed of the wind.
1 solutions

Answer 423248 by mananth(12270) About Me  on 2012-11-19 01:03:17 (Show Source):
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Find boat speed & current speed Both times given

Plane speed =x mph
wind speed =y mph
against wind 6 hours
with wind 5 hours

Distance against 3000 miles distance with wind 3000 miles
t=d/r against wind -
3000 / ( x - y )= 6
6(x-y)=3000
6x-6y= 3000 ....................1

3000/(x-y)= 5
5(x+y) =3000
5x+5y =3000 ...............2
Multiply (1) by 5
Multiply (2) by 6
we get y
30 x + -30 y = 15000
30 x + 30 = 18000
60 x = 33000
/ 60
x = 550 mph

plug value of x in (1) y
6 x -6 y = 3000
3300 -6 -3300 = 3000
-6 y = 3000
-6 y = -300 mph
y = 50
Plane speed 550 mph
wind speed 50 mph

m.ananth@hotmail.ca


Proportions/682565: A metallurgist needs to produce 10kg of an alloy which is 65% copper and 35% tin. He has an alloy which is 50% copper and 50% tin. How Much of this 50-50 alloy must he melt together with pure copper to make the desired alloy? How much copper must he use? If necessary, round each answer to the nearest tenth of a a kilogram.
1 solutions

Answer 423247 by mananth(12270) About Me  on 2012-11-19 00:58:44 (Show Source):
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Copper
percent ---------------- quantity
Metal alloy I 50 ---------------- x Kg
Pure copper 100 ------ 10 - x Kg
Mixture 65 ---------------- 10
600
50x+100 (10-x) =65*10
5000x+10000(10 -x)=65000
5000x+ 100000 -10000x = 65000
5000x - 10000 x = 65000 - -100000
-5000 x = -35000
/ -5000
x = 7 Kg 50.00% Metal alloy I
3 Kg 100.00% Pure copper

m.ananth@hotmail.ca


Exponential-and-logarithmic-functions/682451: Please help. I need to solve this equation for t and I have no clue on how to do it. If you could please show the steps I would appreciate it very much.
(a)/(1+be^-kt)= (a/2)
This equation is asking for the time t at which the population size will be equal to half of its maximum (a/2). I need to solve for t.
1 solutions

Answer 423186 by mananth(12270) About Me  on 2012-11-18 20:32:29 (Show Source):


Complex_Numbers/682454: How would I solve 5√3 over 3√5?
1 solutions

Answer 423184 by mananth(12270) About Me  on 2012-11-18 20:17:49 (Show Source):
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5sqrt%283%29%2F3sqrt%285%29
multiply by the conjugate
%285sqrt%283%29%2Asqrt%285%29%29%2F%283sqrt%285%29%2Asqrt%285%29%29

5sqrt%2815%29%2F%283%2A5%29

5sqrt%2815%29%2F15

sqrt%2815%29%2F3


Quadratic_Equations/682430: Bill can row 3 mph in still water. It takes him 3 hr 36 min to go 3 mi upstream and then return. Find the speed of the current.
1 solutions

Answer 423183 by mananth(12270) About Me  on 2012-11-18 20:13:31 (Show Source):
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Rowing speed = 3 mph
current speed = x mph

against current = 3 - x
with current = 3 + x

Total distance =3 miles Total Time= 3.60 hours
Time upstream + time downstream =

3/(3-x)+3/(3+x )=3.6
3(3+x)+ 3(3-x)= 3.60(9- 1X^2)
9+3x+ 9-3x=32.4-3.6 X^2
18 - -32.4 = -3.6 X^2
-14.4 =-3.6 x^2
-3.6 x^2= -14.4
x^2 = 4
X = +/- 2
Ignore negative value
current speed = 2mph



Linear-systems/682433: Use the elimination method to solve the system of equations.
a+9b=23
a+2b=2

1 solutions

Answer 423176 by mananth(12270) About Me  on 2012-11-18 19:43:40 (Show Source):
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1 a + 9 b = 23 .............1

1 a + 2 b = 2 .............2
Eliminate y
multiply (1)by -2
Multiply (2) by 9
-2 a -18 b = -46
9 a + 18 b = 18
Add the two equations
7 a = -28
/ 7
a = -4
plug value of a in (1)
1 a + 9 b = 23
-4 + 9 b = 23
9 b = 23 + 4
9 b = 27
b = 3
x= -4
y= 3
m.ananth@hotmail.ca


Linear_Equations_And_Systems_Word_Problems/682064: Need help putting this world problem into a linear equation:
There are three types of phones in a shipment: Android, Blackberry, and
iphone. The shipment has the following specifications:
- The total number of phones is 195.
- The total value is $88225.
- The number of iphones equals twice the number of Android phones and
twice the number of Blackberry phones combined.
- The value of each phone is $195 for an Android, $150 for a Blackberry,
and $595 for an iphone
1 solutions

Answer 423032 by mananth(12270) About Me  on 2012-11-18 00:06:19 (Show Source):
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Android,...........x
Blackberry,........y
and iphone.--------z


The total number of phones is 195.
x+y+z=195..................(1)
- The total value is $88225. The value of each phone is $195 for an Android, $150 for a Blackberry,
and $595 for an iphone
195x+150y+595z=88225.............(2)
- The number of iphones equals twice the number of Android phones and
twice the number of Blackberry phones combined.
z=2x+2y
2x+2y-z=0.....................(3)
solve for x y & z
You will get 25, 40,130 phones respectively.
m.ananth@hotmail.com


Complex_Numbers/681954: {(125y3 + 216)/(64y3 - 1)}/{(25y2-36)/(16y2+4y+1)}
1 solutions

Answer 423002 by mananth(12270) About Me  on 2012-11-17 21:23:33 (Show Source):
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%28%28125y3+%2B+216%29%2F%2864y3+-1%29%29%2F%28%2825y2-36%29%2F%2816y2%2B4y%2B1%29%29

%28%285y%29%5E3%2B%286%29%5E3%29%2F%28%284y%29%5E3-%281%29%5E3%29%29%29/%28%28%285y%29%5E2-%286%29%5E2%29%29%2F%2816y%5E2%2B4y%2B1%29%29

%28%285y%2B6%29%2825y%5E2-30y%2B36%29%29%2F%28%284y-1%29%2816y%5E2%2B4y%2B1%29%29/%28%285y%2B6%29%285y-6%29%29%2F%2816y%5E2%2B4y%2B1%29%29


Cancel of the common factors

%2825y%5E2-30y%2B36%29%2F%28%284y-1%29%285y-6%29%29


Travel_Word_Problems/682040: a rowing team rowing with the current, traveled 40km in 2 hrs. rowing against the current the team can only travel 16 km in 2 hrs find the team rowing rate in calm water and the rate of the current
1 solutions

Answer 422997 by mananth(12270) About Me  on 2012-11-17 20:48:07 (Show Source):
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Rowing speed =x mph
current speed =y mph
against current 2 hours
with current 2 hours

Distance with current 40 miles distance against current 16
t=d/r against current (x-y)
16.00 / ( x - y )= 2.00

2.00 x - -2.00 y = 16.00 ....................1
with current (x+y)
40.00 / ( x + y )= 2.00
2.00 ( x + y ) = 40.00
2.00 x + 2.00 y = 40.00 ...............2
Multiply (1) by 1.00
Multiply (2) by 1.00
we get y
2.00 x + -2.00 y = 16.00
2.00 x + 2.00 = 40.00
4.00 x = 56.00
/ 4.00
x = 14 mph

plug value of x in (1) y
2 x -2 y = 16
28 -2 -28 = 16
-2 y = 16
-2 y = -12 mph
y = 6
Rowing 14 mph
current 6 mph


Travel_Word_Problems/681980: I live 260 miles from a popular mountain retreat. On my way there to do some mountain biking, my car had a break down forcing me to bike the rest of the way. If I drove 2 hours longer than I biked and average 60 mph driving and 10 mph biking, how many hours did I spend biking to the resort?
1 solutions

Answer 422991 by mananth(12270) About Me  on 2012-11-17 20:41:58 (Show Source):
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let biking distance be x
biking speed = 10 mph
driving distance = 260-x
driving speed = 60 mph
x/10 +2=(260-x)/60
x/10 -(260-x)/60 = -2
LCD = 60
multiply equation by 60
6x-260+x=-2*60
7x= -120+260
7x=140
/7
x= 20 miles
time biking = distance biking/speed biking
=20/10 = 2 hours



Travel_Word_Problems/682028: carlos and sheri drove a total of 258 miles in 5 hours. carlos drove the first part of the trip and averaged 53 miles per hour. sheri drove the remander of the trip and averaged 51 miles per hour. for approximately how many hours did sheri drive?
1 solutions

Answer 422988 by mananth(12270) About Me  on 2012-11-17 20:29:02 (Show Source):
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let carlos drive x miles
speed carlos = 53mi/h
sheri drives 258-x miles
speed sheri 51 mi/h
Time carlos drove + time cheri drove = 5 hours
t=d/r
x/53 + (258-x)/51 = 5
LCD = (53)*(51)
%2851x%2B53%28258-x%29%29%2F%28%2853%29%2A%2851%29%29=5
51x+13674-53x=5*51*53
-2x=-13674+13515
-2x=-159
/-2
x=79.5 miles
Sheri drove for 258-79.5
=178.5
t=d/r
sheri drove for 178.5/51
= 3.5 hours






�t�e�s�t/681833: find the leangth of the line segment joining the following pairs of points:
(a,0)and(0,b)
1 solutions

Answer 422820 by mananth(12270) About Me  on 2012-11-17 00:36:10 (Show Source):
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Distance between two points
x1 y1 x2 y2

a 0 0 b
d= sqrt%28%28y2-y1%29%5E2%2B%28x2-x1%29%5E2%29
d= sqrt%28%28b%5E2-0%29%5E2%2B%280-a%5E2%29%5E2%29
d=sqrt%28b%5E2-a%5E2%29



Mixture_Word_Problems/681777: If an object is projected vertically upward from an altitude of a feet with an initial velocity of v ft/sec, then its distance s(t) above the ground after t seconds is
s(t) = −16t2 + vt + a.
If s(1) = 99 and s(4) = 129, what are v and a?
1 solutions

Answer 422783 by mananth(12270) About Me  on 2012-11-16 20:18:07 (Show Source):
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s(t) = −16t2 + vt + a.
If s(1) = 99 and s(4) = 129, what are v and a?
99= -16(1)^2+v(1)+a
99=v+a-16
v+a=99+16
v+a=115..........(1)
129= -16(4^2)+4v+a
129=-256+4v+a
4v+a=129+256
4v+a=386...........(2)
Solve (1) & (2)
subtract (2) from (1)
-3v=-276
v=92
Plug v in equation above to get a


Problems-with-consecutive-odd-even-integers/681778: The product of two consecutive even integers is 12 less than 6 times their sum.
1 solutions

Answer 422779 by mananth(12270) About Me  on 2012-11-16 20:07:08 (Show Source):
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let the integerrs be x & x+2
Product = x(x+2)
12 less than 6 times the sum
6(x+x+2)-12
6(2x+2)-12

x(x+2)=6(2x+2)-12
x^2+2x=12x+12-12
x^2+2x-12x=0
x^2-10x=0
x(x-10)=0
x=0 OR 10
10,12