Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On

 Tutoring Home For Students Tools for Tutors Our Tutors Register Recently Solved
 By Tutor
| By Problem Number |

Tutor:

# Recent problems solved by 'mananth'

Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299, >>Next

 Travel_Word_Problems/370236: The speed of the boat in still water is 28 mph. the boat traveled 70 miles per hour downstream in the same amount of time that it took to travel 42 miles upstream. What is the rate of current of the river?1 solutions Answer 263893 by mananth(12270)   on 2010-11-12 20:07:57 (Show Source): You can put this solution on YOUR website!The speed of the boat in still water is 28 mph. the boat traveled 70 miles per hour downstream in the same amount of time that it took to travel 42 miles upstream. What is the rate of current of the river? .. let rate of current be x mph rate of boat in still water = 28mph .. Upstream rate = 28-x mph downstream rate = 28+x .. upstream distance = 42 miles downstream distance = 70 miles ... t= d/r upstream time = downstream time ... 42/(28-x) = 70/x 42x=70(28-x) 42x=1960-70x 42x+70x=1960 112x=1960 /112 x= 1960/112 x= 17.5 mph. the rate of current ... m.ananth@hotmail.ca
 Inequalities/370230: Florencia has at most \$60 to spend on clothes. She wants to buy a pair of jeans for \$22 dollars and spend the rest on t-shirts. Each t-shirt costs \$8. Write an inequality for the number of t-shirts she can purchase and explain how you got that answer.1 solutions Answer 263891 by mananth(12270)   on 2010-11-12 19:58:52 (Show Source): You can put this solution on YOUR website!Florencia has at most \$60 to spend on clothes. She wants to buy a pair of jeans for \$22 dollars and spend the rest on t-shirts. Each t-shirt costs \$8. Write an inequality for the number of t-shirts she can purchase and explain how you got that answer. .. she has \$60 at most so that will be<=60 .. she wants to buy a pair of jeans for \$22. she will spend 22 for sure. .. let number of T shirts she buys be x so the cost of x T shirts will be 6x .. INEQUALITY .. ... m.ananth@hotmail.ca
 Human-and-algebraic-language/370233: If 8/3 of a cetain number is subtracted from eight times the number the result is 128. Find the number. One number is 20 more than a second number. Their sum is twenty six. What are the numbers? If tem times the smaller of two consectuve integers is added to six times the larger, the result is 118. Find the integers. Please help me write all three of them in equation form. 1 solutions Answer 263881 by mananth(12270)   on 2010-11-12 19:38:34 (Show Source): You can put this solution on YOUR website!If 8/3 of a cetain number is subtracted from eight times the number the result is 128. Find the number. 8x - (8/3)x]= 128 One number is 20 more than a second number. Their sum is twenty six. What are the numbers? lets second number be x first number = x+20 x+x+20=26 2x+20 =26 If tem times the smaller of two consectuve integers is added to six times the larger, the result is 118. Find the integers. .. x, x+1 be the integers 10 times smaller = 10x 6 times larger = =6(x+1) 10x+6(x+1)= 110 m.ananth@hotmail.ca
 Graphs/370074: for the data in the table tell whether y varies directly with x if it does write an equation for the direct variation x y 0 0 1 -2.5 2 -5 3 -7.51 solutions Answer 263725 by mananth(12270)   on 2010-11-12 09:50:51 (Show Source): You can put this solution on YOUR website!x y 0 0 1 -2.5 2 -5 3 -7.5 .. y = 2.5x is the equation
 Graphs/370075: the table models the height of a plant as it grows model the data with an equation based on your model predict the height of the plant at 12months time(months)plant height(cm) 3 15 5 25 7 35 9 451 solutions Answer 263723 by mananth(12270)   on 2010-11-12 09:48:34 (Show Source): You can put this solution on YOUR website!3 15 5 25 7 35 9 45 12 60 ... m.ananth@hotmail.ca
 Graphs/370077: giselle pays \$190 in advanced oh her account at the athletic club each toim she uses the club \$5 is deducted from the account the situation can be modled by the equation b=190-5x, where x is the number of visits and b is the total account balance. graph the equation find the account balance after 7 visits (\$155)1 solutions Answer 263721 by mananth(12270)   on 2010-11-12 09:46:05 (Show Source): You can put this solution on YOUR website!b=190-5x after seven visits b = 190-5*7 b=190-35 b= 155 ... .. m.ananth@hotmail.ca
 Graphs/370072: are the lines in the pair parallel? explain y=3/5x-13 6x-10y=-91 solutions Answer 263718 by mananth(12270)   on 2010-11-12 09:40:37 (Show Source): You can put this solution on YOUR website!y=3/5x-13 6x-10y=-9 10y=6x+9 /10 y= 6x/10 +9/10 y=3x/5 +9/10 .. both the slopes are same (3/5) so they are parallel .. .. m.ananth@hotmail.ca
 Equations/370047: Helen has a rectangular garden that measures 65 meters by 20 meters. How long is the diagonal length of the garden? (An example of diagonal length is from the top left corner to the bottom right corner of the garden.)1 solutions Answer 263697 by mananth(12270)   on 2010-11-12 08:34:59 (Show Source): You can put this solution on YOUR website!dimensions of the garden are 65 by 20 meters .. diagonal and thge sides form a right triangle. so we have to use Pythagoras theorem ... Diagonal ^2 = 65^2+20^2 =4225-400 =3825 = sqrt 3825 =61.8 meters .. m.ananth@hotmail.ca
 Graphs/370044: I am trying to find the slope for the line. 20x-5y=1.2 y=mx+b I have to get the y by itself, so am i setting up the problem like this -5y+20x+1.2. I have to subtract 20 by both sides. i am lost can you help me out.1 solutions Answer 263688 by mananth(12270)   on 2010-11-12 08:18:26 (Show Source): You can put this solution on YOUR website!20x-5y=1.2 to simplify , since there is one decimal multiply equation by 10 200x-50y =12 50y = 200x-12 y = 200x/50 -12/50 y = 4x - 6/25 .. slope = 4 .. m.ananth@hotmail.ca
 Travel_Word_Problems/370037: a tortoise makes a journey in two parts; it can either walk at 4cm/s or crawl at 3cm/s. if the tortoise walks the first part and crawls the second, it takes 110 seconds. If it crawls the first part and walks the second, it takes 100 seconds. find the lengths of the two parts of the journey.1 solutions Answer 263684 by mananth(12270)   on 2010-11-12 08:14:33 (Show Source): You can put this solution on YOUR website!let it walk x cm let it crawl y cm .. x/4 + y/3 = 110 3x+4y /12= 110 3x+4y = 1320.....................1 ... x/3 + y/4 = 100 4x+3y / 12 = 100 4x+3y= 1200......................2 ... multiply equation 1 by -4 & equation 2 by 3 -12x-16y= -5280 12x+9y = 3600 ... add the two equations ... -7 y = -5280+3600 -7y = -1680 y = -1680/-7 y = 240 cm crawl plug value of y in equation 1 3x+4y=12*110 3x+960=1320 3x=1320-960 3x=360 x = 120 cm walking m.ananth@hotmail.ca
 Travel_Word_Problems/370035: Andrea purchased two house plants for a total of \$65.oo. If the orchard cost \$19 more than the Fern, how much did the fern cost?1 solutions Answer 263678 by mananth(12270)   on 2010-11-12 07:38:54 (Show Source): You can put this solution on YOUR website!let the price of fern be \$x the orchard will cost x+19 .. she paid \$65 for both of them .. x+x+19 = 65 2x+19=65 add -19 2x+19-19 = 65-19 2x=46 /2 x= \$ 23 The price of fern. ... m.ananth@hotmail.ca
 Travel_Word_Problems/370034: Ron and Doug leave the same spot at the same time going in opposite directions. Ron travels at 40mph while doug travels at 60mph. In how many hours will they be 350 miles apart?1 solutions Answer 263676 by mananth(12270)   on 2010-11-12 07:33:58 (Show Source): You can put this solution on YOUR website!Ron 40 mph Doug 60 mph .. they are moving away from each other their combined speed = 100 mph .. distance = 350 miles .. t = d/r .. t = 350/100 t=3.5 hours ... m.ananth@hotmail.ca
 Metalworking/369900: there are five people standing in a room. Antonio is 5 time the age of Patrick who is half the age of Merlyn. Ed is 30 years younger than double Merlyn and Patrick's combined ages. Precious is 79 years younger than Antonio. The sum of their ages is 271. How old is Precious?1 solutions Answer 263674 by mananth(12270)   on 2010-11-12 06:27:21 (Show Source): You can put this solution on YOUR website!there are five people standing in a room. Antonio is 5 time the age of Patrick who is half the age of Merlyn. Ed is 30 years younger than double Merlyn and Patrick's combined ages. Precious is 79 years younger than Antonio. The sum of their ages is 271. How old is Precious? .. let Antonio = x years Precious = x-79 Antonio = x= 5* age of patrick Patrick = x/5 .. Patrick = 1/2 age of Merlyn 2*patrick = Merlyn 2x/5= Merlyn .. Ed = 2*(2x/5 + x/5)-30 Ed = 2*(3x/5)-30 Ed= 6x/5-30 ... now you have all their ages in variables add them up x+x-79+x/5 +2x/5 +6x/5-30 =271 2x+x/5 +2x/5+6x/5 = 271+79+30 (10x+x+2x+6x)/5 =380 19x=5*380 x= 5*380/19 x = 100 Antonio's age Precious = Antonio's age -79 .. 100-79 = 21 Precious is 21 years .. m.ananth@hotmail.ca
 Linear-systems/369875: Carla has already written 10 pages of a novel. She plans to write 15 additional pages per month until she is finished. Write an equation to find the total number of pages P written after any number of months m.1 solutions Answer 263673 by mananth(12270)   on 2010-11-12 05:58:36 (Show Source): You can put this solution on YOUR website!Carla has written 10 pages she writes 15 pages /month let month be m .. P = 10 +15m ... m.ananth@hotmail.ca
 Linear-equations/370030: Thank you! Graph the equation and identify the y -intercept: Y = 1/5x 1 solutions Answer 263672 by mananth(12270)   on 2010-11-12 05:56:04 (Show Source): You can put this solution on YOUR website!y = (1/5)x .. As you see the graph passes through the origin so there is no intercept
 Geometry_Word_Problems/369880: A tree casts a shadow 180 feet long. Find the height of the tree if the angle of elevation of the sun is 30°.1 solutions Answer 263669 by mananth(12270)   on 2010-11-12 05:33:47 (Show Source): You can put this solution on YOUR website!Height of tree = x feet length of shadow = 180 feet angle of elevation = 30 deg. .. Tan = height/shadow Tan (30)* 180 = height of tree height of tree = 104 feet ( rounded off) .. m.ananth@hotmail.ca
 Quadratic_Equations/370023: solve equation x^2 + 24^2 = 26^21 solutions Answer 263665 by mananth(12270)   on 2010-11-12 05:26:27 (Show Source): You can put this solution on YOUR website!x^2 + 24^2 = 26^2 .. x^2= 26^2-24^2 x^2= (26+24)(26-24) x^2=50*2 x^2=100 take the square root x= 10 ... m.ananth@hotmail.ca
 Linear-equations/370025: Having trouble with this one. Thank you. Graph the equation and identify the y - intercept. y = 4/3x+2. (0,?) 1 solutions Answer 263664 by mananth(12270)   on 2010-11-12 05:24:26 (Show Source): You can put this solution on YOUR website!y = (4/3)x+2. FOR Y INTERCEPT plug x=0 y=2 (0,2) .. ... m.ananth@hotmail.ca
 Geometry_Word_Problems/369984: The length of a room exceeds the width by 5 feet, and the height is 3 feet less than the width. The area of the four walls exceeds the sum fo the areas of ceiling and floor by 240 square feet. Find the dimensions of the room.1 solutions Answer 263663 by mananth(12270)   on 2010-11-12 05:20:34 (Show Source): You can put this solution on YOUR website!let width be x length = x+5 height = x-3 .. Area of 4 walls = 2*LH + 2*WH = 2*(x-3)(x+5)+2*x*(x-3) =2(x^2+2x-15)+2x^2-6x =2x^2+4x-30+2x^2-6x =4x^2-2x-30 ... Area of ceiling & floor Area = 2 * LW Area = 2*x*(x+5) Area = 2x^2+10x .. 4x^2-2x-30 =2x^2+10x+240 2x^2-12x-270=0 /2 x^2-6x-135=0 x^2-15x+9x-135=0 x(x-15)+9(x-15)=0 (x-15)(x+9)=0 x= 15 feet the width length = x+5 = 15 +5 = 20 feet height = x-3 = 15-3 = 12 feet ... m.ananth@hotmail.ca
 Travel_Word_Problems/370005: There is a race to a point 3miles away and back. Person A goes 20 mph, Person B goes 16mph. Where do they meet (in feet). I figured that it took person A .15 hours to the turning point and the Person B had traveled 2.4 miles in that time. I don't know how to go the rest of the answer....! Help!1 solutions Answer 263659 by mananth(12270)   on 2010-11-12 05:01:23 (Show Source): You can put this solution on YOUR website! race distance = 3 & back A = 20 mph B= 16 mph .. A takes 3/20 hour to reach other end .. By then B has reached 16*3/20 miles =12/5 miles .. at this point of time they are 3-(12/5) miles apart facing each other. =3/5 miles. .. Now they are running towards each other their speeds when added up is 36 mph .. distance = 3/5 miles speed = 36 mph .. time they meet = (3/5) /36 3/5 *1/36 =3/180 hours. .. in 3/180 hours B will run ( d= rt) 3/180 * 20 =1/3 mile ... 1/3 * 5280 = 1760 feet from the returning end. ... m.ananth@hotmail.ca
 Equations/370015: Hi, I don't understand how to do the below problem, can someone explain please? (1 1/3)(-1/3)(3/4) Thank you!!1 solutions Answer 263655 by mananth(12270)   on 2010-11-12 04:26:17 (Show Source): You can put this solution on YOUR website!1 1/3 = 4/3 .. 4/3 * -1/3 *3/4 .. since all are to be multiplied group them in the numerator & denominator (4*-1*3)/(3*3*4) -12/36 -1/4 ..
 Average/370018: If i score 99 on my first test and 85 on my second, what do I need to get on my third test in order to get an overall average of 90?1 solutions Answer 263653 by mananth(12270)   on 2010-11-12 04:22:27 (Show Source): You can put this solution on YOUR website!99 on first 85 on second total of two tests = 184 .. you need average 90 from 3 tests so total score will be 90*3 = 270 .. you have 184 you require 270 -184 = 86 in the third test ... m.ananth@hotmail.ca
 Expressions-with-variables/370002: (3x-2x)^21 solutions Answer 263648 by mananth(12270)   on 2010-11-12 01:09:26 (Show Source): You can put this solution on YOUR website!(3x-2x)^2 .. using the formula ( a-b)^2 = a^2-2ab +b^2 (3x)^2-2*3x*(-2x)+(2x)^2 9x^4-12x^2 +4x^2 .. m.ananth@hotmail.ca
 Expressions-with-variables/369972: A boy's age is three times the age of his sister. Their ages together total 16 years. What is the age of each?1 solutions Answer 263602 by mananth(12270)   on 2010-11-11 22:14:49 (Show Source): You can put this solution on YOUR website!let sister be x years brother will be 3x 3x+x =16 4x=16 divide both sides by 4 4x/4=16/4 x=4 sister's age brother's age = 3*x = 3*4 =12 years
 Angles/369970: two angles are supplementary if their sum is 180degrees. the larger angle measures eight degrees more than three times the smaller angle. if x represents the measure of the smaller angle and these two angles are supplementary, find the measure of each angle. 1 solutions Answer 263601 by mananth(12270)   on 2010-11-11 22:10:17 (Show Source): You can put this solution on YOUR website!smaller angle x larger angle = 3x+8 .. their sum =180 x+3x+8=180 4x+8=180 -8 4x= 172 /4 x=43 degrees the other angle will be 180 -43=137 degrees ... m.ananth@hotmail.ca
 Expressions-with-variables/369965: How do you solve 9 + 3k = 2k - 12?1 solutions Answer 263600 by mananth(12270)   on 2010-11-11 22:07:56 (Show Source): You can put this solution on YOUR website!9 + 3k = 2k - 12 add -2k on both sides 9+3k-2k=2k-2k-12 9+k=-12 add -9 to both sides 9-9+k=-12-9 k=-21 ... m.ananth@hotmail.ca
 Surface-area/369955: Please help me solve this word problem: There is a 30-60-90 triangle with an area of 24 radical 3. What is the perimeter of this triangle, and what are the side lengths? (All in terms of X) Thanks so much for the help.1 solutions Answer 263591 by mananth(12270)   on 2010-11-11 21:51:45 (Show Source): You can put this solution on YOUR website!in a 30-60-90 triangle the legs are x & xsqrt3 the hypotenuse = 2x .. Area = !/2 * base * height multiply by 2 divide by sqrt3 x^2= 48 x = 6.92 hypotenuse = 2*6.92= 13.84 second leg = x sqrt*(3) =6.92*sqrt*(3) = 11.98 .. perimeter = 11.98+6.92+13.84= 32.74 m.ananth@hotmail.ca
 Travel_Word_Problems/369902: A mosquito can fly at 0.6 mi/h. How many inches per second is this? 1 solutions Answer 263567 by mananth(12270)   on 2010-11-11 20:40:56 (Show Source): You can put this solution on YOUR website!0.6 mi/h 0.6 * 5280 = 3168 feet 1 foot = 12 inches 3168 feet = 3168 * 12= 38106 inches .. 1 hour = 3600 seconds .. 38106/3600=10.56 inches/second ... m.ananth@hotmail.ca
 Travel_Word_Problems/369904: an artic tern flew 11,000 miles in 115 days. How many feet per minute did the bird average? A sneeze can travel up to 100 mi/h. how many feet per second is this?1 solutions Answer 263566 by mananth(12270)   on 2010-11-11 20:36:30 (Show Source): You can put this solution on YOUR website!11,000 miles in 115 days. .. 1 mile = 5280 feet 11000 miles = 11000* 5280 feet =58080000 feet ... 115 days 115 * 24 = 2760 hours 2760 * 60 = 165,600 minutes .. feet /min = 58,080,000/165,600 = 350.72 feet/minute .. sneeze speed = 110 mph 110 miles = 110 * 5280 =580,800 feet 1hour = 3600 seconds .. feet/second = 580,800/3600 = 161.33 feet/second .. m.ananth@hotmail.ca
 Numeric_Fractions/369882: Find the least common denominator (LCD) for fractions with the given denominators. 1. 14 and 21 2. 3, 4, and 5 1 solutions Answer 263562 by mananth(12270)   on 2010-11-11 20:27:32 (Show Source): You can put this solution on YOUR website!1. 14 and 21 14= 2*7 21=3*7 common factor = 7 LCD = common factor * non common factors LCD = 7 * 3*2 LCD= 42 ... 2. 3, 4, and 5 60 ... m.ananth@hotmail.ca
 Linear_Equations_And_Systems_Word_Problems/369883: Giselle pays \$190 in advance on her account at the athletic club.Each time she uses the club,\$5 is deducted from the account.The situation can be moldeled by the equation b=190-5x,where x is the number of visits and b is the total account balance graph the equation and find the account balance after 7 visits1 solutions Answer 263559 by mananth(12270)   on 2010-11-11 20:23:25 (Show Source): You can put this solution on YOUR website!b= 190-5x x= 7 b= 190-5*7 b=155 will be the balance ... m.ananth@hotmail.ca