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mananth answered: 12270 problems
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11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299, >>NextMiscellaneous_Word_Problems/385246: A Piece of ribbon 180 centimeters is cut into two pieces. One piece is 4 times longer that the other . How long are the two pieces in centimeters? 1 solutions
Answer 272634 by mananth(12270) on 2010-12-13 03:36:09 (Show Source):
You can put this solution on YOUR website!one piece = x
other piece = 4x
..
added up you get total length
4x+x=180
5x=180
/5
x=36 cm. one piece.
other piece = 4x=4*36=144
..
check
144+36=180
...
m.ananth@hotmail.ca
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Miscellaneous_Word_Problems/385309: The length of a rectangle is 2in. less than 7 times its width. the area of the rectangle is 57 sq. in. What are the dimentions of the rectangle? 1 solutions
Answer 272631 by mananth(12270) on 2010-12-13 03:30:47 (Show Source):
You can put this solution on YOUR website!width = x
length = 7x-2
..
L*W= Area
...
x(7x-2)=57
7x^2-2x=57
7x^2-2x-57=0
7x^2-21x+19x-57=0
7x(x-3)+19(x-3)=0
(x-3)(7x+19)=0
x= 3 which is positive
Width = 3 in
length = 7x-2 = 21-2=19 in.
...
m.ananth@hotmail.ca
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Equations/385310: write an algebraic equation which could be used to solve the following problem. then find the solution: "A 40-inch rope is cut into three pieces so that the second piece is four times as long as the first and the third piece is three times as long as the first piece. Find the length of all three pieces."
im so confused 1 solutions
Answer 272629 by mananth(12270) on 2010-12-13 03:23:39 (Show Source):
You can put this solution on YOUR website!write an algebraic equation which could be used to solve the following problem. then find the solution: "A 40-inch rope is cut into three pieces so that the second piece is four times as long as the first and the third piece is three times as long as the first piece. Find the length of all three pieces."
...
first piece = x in
second piece = 4x
third = 3x
...
added they are 40 inches
x+4x+3x=40
8x=40
/8
x= 5 in first piece
second piece = 4x= 20 in
third piece = 3cx = 3*5 = 15 in
...
CHECK
15+20+5=40 in
...
m.ananth@hotmail.ca
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Human-and-algebraic-language/385311: Nadia can Completely mow the yard by herself in 30 minutes. Peter can completely mow the yard by himself in 45 minutes. How long would it take both of them to mow the yard if they worked together? 1 solutions
Answer 272627 by mananth(12270) on 2010-12-13 03:20:17 (Show Source):
You can put this solution on YOUR website!Nadia can Completely mow the yard by herself in 30 minutes. Peter can completely mow the yard by himself in 45 minutes. How long would it take both of them to mow the yard if they worked together?
...
Nadia 30 minutes
Peter = 45 minutes
..
Nadia = 1/30 of job in 1 minute
Peter = 1/45 of the job in1 minute.
Together = 1/30 +1/45
LCD = 90
=(3+2)/90
=5/90
=1/18 of the job in 1 minute.
together they will take 18 minutes to complete the job.
,,,.
m.ananth@hotmail.ca
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Miscellaneous_Word_Problems/385313: Girard wishes to mix red grapes worth $1.90 a pound with green grapes worth $1.10 a pound to get a 24 pound mixture worth $1.50 a pound. How many pounds of each does he need?
please help me 1 solutions
Answer 272626 by mananth(12270) on 2010-12-13 03:16:58 (Show Source):
You can put this solution on YOUR website!Girard wishes to mix red grapes worth $1.90 a pound with green grapes worth $1.10 a pound to get a 24 pound mixture worth $1.50 a pound. How many pounds of each does he need?
...
red grapes worth $1.90 a pound ................x pounds
green grapes worth $1.10 a pound ..............24-x
mixture 24 pound mixture worth $1.50 a pound.
..
1.90x+1.10(24-x)=24*1.50
1.90x+26.4-1.10x=36
0.8x+26.4=36
-26.4 -26.4
0.8x=9.6
/0.8
x=12 pounds of red grapes
12 pounds of green grapes
...
m.ananth@hotmail.ca
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Human-and-algebraic-language/385312: A book cost $15 if bought online and $22.50 if bought at the store. The bookstore sold 250 books and took in $4995. How many books were bought online and how many were bought in the store? 1 solutions
Answer 272625 by mananth(12270) on 2010-12-13 03:11:45 (Show Source):
You can put this solution on YOUR website!A book cost $15 if bought online and $22.50 if bought at the store. The bookstore sold 250 books and took in $4995. How many books were bought online and how many were bought in the store?
...
books online = x numbers
books from store= y
x+y=250..........1
15x+22.50y = 4995...........2
...
multiply (1) by -15
-15x-15y=-3750
add this to (2)
15x-15x+22.50y-15y= -3750+4995
7.5y=1245
/7.5
y=1245/7.5
y = 166 books from store.
Balance online. 84 books
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m.ananth@hotmail.ca
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Human-and-algebraic-language/385314: Grace starts biking at 12 mph. One hour later, Dan starts biking at 15 mph, following the same route. How long will it take him to catch up with Grace? 1 solutions
Answer 272623 by mananth(12270) on 2010-12-13 03:04:59 (Show Source):
You can put this solution on YOUR website!Grace starts biking at 12 mph. One hour later, Dan starts biking at 15 mph, following the same route. How long will it take him to catch up with Grace?
...
Grace = 12 mph
Dan = 15 mph
..
hrace has traveled 12 miles when Dan starts
distance to make up =12miles
catch up speed = 15-12 = 3mph
t=d/r
t=12/3
t= 4 hours
...
m.ananth@hotmail.ca
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Human-and-algebraic-language/385315: Peter is outside looking at pigs and chickens in the yard. He comes inside, tells Nadia that he counted 13 heads and 36 feet, and asks her how many pigs and chickens were in the yard. what should Nadia tell him? 1 solutions
Answer 272621 by mananth(12270) on 2010-12-13 03:02:07 (Show Source):
You can put this solution on YOUR website!Peter is outside looking at pigs and chickens in the yard. He comes inside, tells Nadia that he counted 13 heads and 36 feet, and asks her how many pigs and chickens were in the yard. what should Nadia tell him?
...
pig =x
chickens=y
x+y=13 heads..............1
4x+2y=36...................2
...
multiply 1 by -2
-2x-2y=-26
add to 2
4x-2x+2y-2y=36-26
2x=10
/2
x= 5 number of pigs
chickens qill be 8
...
m.ananth@hotmail.ca
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Travel_Word_Problems/385317: a boat travels 2 km/hr in still water. the boat travels 4 km in the same amount of time it takes to travel 1 km upstream. what is the speed of the river? 1 solutions
Answer 272615 by mananth(12270) on 2010-12-13 02:51:29 (Show Source):
You can put this solution on YOUR website!a boat travels 2 km/hr in still water. the boat travels 4 km in the same amount of time it takes to travel 1 km upstream. what is the speed of the river?
..
speed of boat in still water = 2km/h
..
let speed of current = c km/h
..
upstream seed 2-c
downstream speed = 2+c
..
upstream d=1
downstream d=4
..
t=d/r
t upstream = t downstream
1/(2-c)=4/(2+c)
cross multiply
(2+c)=4(2-c)
2+c=8-4c
5c=6
c=6/5 km/h
...
m.ananth@hotmail.ca
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Travel_Word_Problems/385236: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 110 miles per hour. Train A passes a station at 4:20 A.M. If train B passes the same station at 4:50 A.M., at what time will train B catch up to train A? 1 solutions
Answer 272610 by mananth(12270) on 2010-12-13 01:17:34 (Show Source):
You can put this solution on YOUR website!Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 110 miles per hour. Train A passes a station at 4:20 A.M. If train B passes the same station at 4:50 A.M., at what time will train B catch up to train A?
...
Train A 4.20 A.M speed = 100 mph
Train B 4.50 A.M speed = 110 mph
..
difference in time they reach station = 30 minutes = 1/2 hour.
...
catch up speed of train B will be 110-100 = 10 mph.
..
Train A has traveled 50 miles in 1/2 hour.
...
catch up time = 50/10 = 5 hours.
Train B will catch up at 9;50 A.M
...
m.ananth@hotmail.ca
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Linear_Equations_And_Systems_Word_Problems/385266: one pan pizza and two cheesburgers provide 2860 claories. two pan pizzas and one cheeseburger provide 2990 calories. find the caloric content of each item 1 solutions
Answer 272606 by mananth(12270) on 2010-12-13 00:47:09 (Show Source):
You can put this solution on YOUR website!one pan pizza and two cheesburgers provide 2860 claories. two pan pizzas and one cheeseburger provide 2990 calories. find the caloric content of each item
...
pan pizza --- x calories
cheeseburgers - y calories
..
x+2y=2860.....................1
2x+y=2990......................2
...
multiply equation 1 by -2
-2x-4y=-5720
add it to equation2
..
2x-2x+y-4y=2990-5720
-3y=-2730
/-3
y=-2730/-3
y=910 CALORIES PER CHEESEBURGER
plug value of y in1
x+1820=2860
-1820
x=1040 calories in pan pizza
m.annath@hotmail.ca
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Proportions/385272: The cost of a pizza varies directly with the square of its radius. If the cost of the pizza is $8.00 when the radius is 8 inches, find the cost when the radius increases to 10 inches. 1 solutions
Answer 272605 by mananth(12270) on 2010-12-13 00:36:19 (Show Source):
You can put this solution on YOUR website!The cost of a pizza varies directly with the square of its radius. If the cost of the pizza is $8.00 when the radius is 8 inches, find the cost when the radius increases to 10 inches.
...
Cost c proportional to r^2

...
 where k is the constant of proportionality
r=8 c =8
plug these values

divide both sides by 8^2
...
k=8/8^2
k=1/8
...
k=1/8 r=10
c=kr^2
c=1/8*10^2
c=100/8
c=$ 12.50
...
m.ananth@hotmail.ca
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Geometry_Word_Problems/385281: the area of a rectangle is 102 square inches. the length of the rectangle is 5 inches greater than twice the width. find the dimensions of the rectangle 1 solutions
Answer 272601 by mananth(12270) on 2010-12-13 00:29:15 (Show Source):
You can put this solution on YOUR website!the area of a rectangle is 102 square inches. the length of the rectangle is 5 inches greater than twice the width. find the dimensions of the rectangle
...
width = w in
length = 2w+5 in
..
L*W=Area
w(2w+5)=102
2w^2+5w=102
-102 -102
2w^2+5w-102=0
2w^2+17w-12w-102=0
w(2w+17)-6(2w+17)=0
(w-6)(2w+17)=0
w= 6 inches the width
Length=2x+5=12+5=17 inches
....
m.ananth@hotmail.ca
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Linear_Equations_And_Systems_Word_Problems/385284: A candy store has two types of jelly beans, one selling for $2 per pound and the other selling for $4 per pound. The beans are to be mixed to provide 100 lb of a mixture selling for $2.50 per pound. How much of each type of jelly bean should be used to form 100 lb of the mixture? 1 solutions
Answer 272598 by mananth(12270) on 2010-12-13 00:20:40 (Show Source):
You can put this solution on YOUR website!A candy store has two types of jelly beans, one selling for $2 per pound and the other selling for $4 per pound. The beans are to be mixed to provide 100 lb of a mixture selling for $2.50 per pound. How much of each type of jelly bean should be used to form 100 lb of the mixture?
...
$2 per pound ------------x pounds
$4 per pound. -----------100-x
mixture 100 lb $2.50 per pound.
...
2x+4(100-x)=100*2.50
2x+400-4x=250
-2x+400=250
-400 -400
-2x=250-400
-2x=-150
/-2
x=75 pounds of $2 beans
25 pounds of $4 beans
...
m.ananth@hotmail.ca
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Geometry_Word_Problems/385280: a 3 ft wide sidewalk surrounds a rectangular swimming pool. the perimeter of the pool is 84 ft. the length of the larger rectangle is twice the width of the swimming pool. find the dimensions of the swimming pool 1 solutions
Answer 272594 by mananth(12270) on 2010-12-13 00:08:15 (Show Source):
You can put this solution on YOUR website!a 3 ft wide sidewalk surrounds a rectangular swimming pool. the perimeter of the pool is 84 ft. the length of the larger rectangle is twice the width of the swimming pool. find the dimensions of the swimming pool
...
perimeter of pool = 84 ft.
width of swimming pool = x
..
length of larger rectangle = 2x
length of the pool = 2x-6 (reduce 3ft from both sides)
...
Perimeter = 2*(l+w)
2*(x+2x-6)=84
2*(3x-6)=84
/2
3x-6=42
+6 +6
3x=48
/3
x= 16 ft. the width of the pool.
length = 2x-6 = 32-6 = 26 feet
POOL width 16 ft length = 26 feet
..
CHECK
16+16+26+26=84
...
m.ananth@hotmail.ca
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Linear-systems/385208: Can I please get some help with this problem.
Solve the following system of two linear equations.
5x-6y= 40
3x+2y=8
Thank you 1 solutions
Answer 272560 by mananth(12270) on 2010-12-12 22:37:53 (Show Source):
You can put this solution on YOUR website!5x-6y= 40................1
3x+2y=8...................2
...
multiply equation (2) by 3
9x+6y=24
...
add it to (1)
9x+5x+6y-6y=24+40
14x=64
/14
x=64/14
x=32/7
...
plug value of x in (1)
5*(32/7)-6y=40
6y=5(32/7)-40
y=-20/7
..
m.ananth@hotmail.ca
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Rectangles/385225: 85 square feet of area height is three feet less than twice the base find base and height 1 solutions
Answer 272555 by mananth(12270) on 2010-12-12 22:18:38 (Show Source):
You can put this solution on YOUR website!85 square feet of area height is three feet less than twice the base find base and height
..
base =b
height h = 2b-3
..
1/2 * base * height = Area of triangle
1/2 *b*(2b-3)=85
multiply by 2
b(2b-3)=170
2b^2-3b=170
2b^2-3b-170=0
2b^2-20b+17b-170=0
2b(b-10)+17(b-10)=0
(b-10)(b+17)=0
 feet- the base
...
height = 2b-3= 2*10-3
 feet
...
m.ananth@hotmail.ca
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Quadratic_Equations/385217: i'm learning polynomials and such in class and a question came up in one of my group tests. i asked someone else for help and they showed me how to do it but i don't get how to get from the equation to the answer.
i do not understand how 2w^2+11w=84 gets to whatever the weird answer was. i do not understand how it is a quadratic equation and how to simplify it...please help and thanks so much.
PS. the problem i had on my group test was this:
The length of a picture is one inch less than twice its width. the frame around the picture has a uniform width of two inches and an area of 96 square inches. what are the dimensions of the picture?
i did the equation like this:
(2w+3)(w+4)=96
which simplified to:
2w^2+11w=84 1 solutions
Answer 272554 by mananth(12270) on 2010-12-12 22:10:25 (Show Source):
You can put this solution on YOUR website!The length of a picture is one inch less than twice its width. the frame around the picture has a uniform width of two inches and an area of 96 square inches. what are the dimensions of the picture?
...
width of picture = w
length = 2w-1
...
Area of picture = w(2w-1)
...
uniform width of 2 in.surrounding the picture
so width will be w+4
length = (2w-1)+4=2w+3
..
Area of picture + area frame =(w+4)(2w+3)
...
(Area of picture + area frame)-area of picture= area of frame
..
(w+3)(2w+3)-w(2w-1)=96
2w^2+9w+9-2w^2+w=96
10w+9=96
-9 -9
10w=87
/10
 cm the width
Length = 2w-1= 2*8.7-1
Length =17.4-1
Length  cm
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Geometry_Word_Problems/385216: the perimeter of a rectangle is 180m the length is 5m more than double the width use an equation 1 solutions
Answer 272547 by mananth(12270) on 2010-12-12 21:49:11 (Show Source):
You can put this solution on YOUR website!the perimeter of a rectangle is 180m the length is 5m more than double the width use an equation
width=x
length=2x+5
2*(l+w)=perimeter
2*(x+2x+5)=180
/2
3x+5=90
-5 -5
3x=85
/3
x=28.33m the width
length = 2x+5 =61.66
...
m.ananth@hotmail.ca
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Miscellaneous_Word_Problems/385141: A door is 6 ft 6 in. tall and 36 in wide. Can a piece of plywood that is 7 ft by 8ft be carried through the door? 1 solutions
Answer 272530 by mananth(12270) on 2010-12-12 20:15:43 (Show Source):
You can put this solution on YOUR website!A door is 6 ft 6 in. tall and 36 in wide. Can a piece of plywood that is 7 ft by 8ft be carried through the door?
First find the diagonal of the door
..
Diagonal D ^2 = (13/2)^2+3^2
D^2=(169/4)+9
D^2=(169+36)/4
D^2=205/4

Diagonal D = 7.15 feet
..
Yes it is possible .
The sheet width = 7ft.
...
m.ananth@hotmail.ca
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