Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On

 Tutoring Home For Students Tools for Tutors Our Tutors Register Recently Solved
 By Tutor
| By Problem Number |

Tutor:

# Recent problems solved by 'mananth'

Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299, >>Next

 Travel_Word_Problems/499530: two planes, one going north and one going south, depart simultaneously from the same airport. If they travel at 450 km/h and 620 km/h respectively, how many hours will pass before they are 2800 km apart??1 solutions Answer 337754 by mananth(12270)   on 2011-09-18 05:22:24 (Show Source): You can put this solution on YOUR website!Car I -------- 450 km/h Car II -------- 620 km/h they are traveling away from each other so add up speeds 620 + 450 = 1070 km/h Distance = 2800 km time = d/r time= 2800 / 1070 Time = 2.62 h
 Finance/499121: Hi, can you please help me? Ive tried this problem 9 times...and I keep getting it wrong... Thank you sooo much for your help! i hope you can help me... it would be soo appreciated! :) Find all real solutions of the equation. or tell if there is NO REAL SOLUTION. squareroot of: 9x + 64+8=x 1 solutions Answer 337438 by mananth(12270)   on 2011-09-17 06:21:40 (Show Source): You can put this solution on YOUR website! Take the square 9x+72=x^2 x^2-9x-72=0 Find the roots of the equation by quadratic formula a= 1 ,b= -9 c -72 b^2-4ac= 81 - 288 b^2-4ac= 369 = 19.21 x1=( 9 + 19.21 )/ 2 x1= 14.1 x2=( 9 -19.21 ) / 2 x2= -5.105
 Travel_Word_Problems/499128: The problem is: Car Travel. Two cars leave Denver traveling in opposite directions. One car travels at a speed of 80 and the other at 96 . In how many hours will they be 528 km apart? I know that it is a problem that is going to take two equations to set it up and then use the substitution method to solve it, but I just am not figuring out how to set it up.1 solutions Answer 337437 by mananth(12270)   on 2011-09-17 06:16:52 (Show Source): You can put this solution on YOUR website!Car I -------- 80 km/h Car II -------- 96 km/h they are traveling away from each other so add up speeds 96 + 80 = 176 km/h Distance = 528 km time = d/r time= 528 / 176 Time = 3 h
 Equations/499131: How many gallons of 65% antifreeze solution and a 35% antifreeze solution must be mixed to obtain 15 gallons of 53% antifreeze solution? 1 solutions Answer 337436 by mananth(12270)   on 2011-09-17 06:11:17 (Show Source): You can put this solution on YOUR website!percent percentage ---------------- quantity antifreeze I 65 ---------------- x gal antifreeze II 35 ---------------- 15 - x gal Mixture 53.00% ---------------- 15 65 x + 35 ( 15 - x ) = 53 * 15 65 x + 525 - 35 x = 795 65 x - 35 x = 795 - 525 30 x = 270 / 30 x= 9 gal 65.00% antifreeze I 6 gal 35.00% antifreeze II
 Equations/499133: One phone company charges \$0.29 per minute for long-distance phone calls. A second company charges only \$0.26 per minute for long-distance calls, but adds a monthly fee of \$2.97. Find the number of minutes of long-distance calling for which the total bill from either company would be the same. Please round your answers to the nearest hundredth if necessary. 1 solutions Answer 337435 by mananth(12270)   on 2011-09-17 06:06:47 (Show Source): You can put this solution on YOUR website!Let x be the number of calls company B 2.97 + 0.26 x company A 0 + 0.29 x company B = company A 0 + 0.29 x = 2.97 + 0.26 x 0 + 0.29 x = 2.97 + 0.26 x 0 - 2.97 = 0.26 x -0.29 x -2.97 < -0.03 x 99 = x x should be 99 calls
 test/499141: want to learn to solve algebra problem1 solutions Answer 337434 by mananth(12270)   on 2011-09-17 06:00:37 (Show Source): You can put this solution on YOUR website!OK m.ananth@hotmail.ca
 Numbers_Word_Problems/499163: at 12 noon, the teacher sent home 1/3 of the students plus 6. At 1pm, she sent home 1/4 of the remaining students.At 2pm, she sent home the last 21 students. How many students were originally in school that day?1 solutions Answer 337433 by mananth(12270)   on 2011-09-17 05:58:37 (Show Source): You can put this solution on YOUR website!Total x 12 PM 1/ 3 x+ 6 were sent away Remainder= x - 1/3x- 6 Balance in class 2/ 3x-6 1PM she sent away 1/ 2*( 2/3x-6) Balance in class 2/3x-6 -(0.33x +3) 1/ 3 x-3 2.00PM She sent away 21 2 PM 1/3 x -3 -21 = 0 1/ 3 x- 24 = 0 1/ 3 x= 24 x= 72
 Linear-equations/499166: find the equation of the line containing (2,-3) and having the same slope as the line 3x + 4y = 101 solutions Answer 337432 by mananth(12270)   on 2011-09-17 05:16:01 (Show Source): You can put this solution on YOUR website!3 x + 4 y = 10 Find the slope of this line make y the subject 4 y = -3 x + 10 Divide by 4 y = -0.75 x + 2.5 Compare this equation with y=mx+b slope m = - 3/4 The slope of a line parallel to the above line will be the same The slope of the required line will be -0.75 m= - 3/4 ,point ( 2 , -3 ) Find b by plugging the values of m & the point in y=mx+b -3 = -1.50 + b b= -1.5 m= -0.75 Plug value of the slope and b in y = mx +b The required equation isy = - 3/4 x -1.5 y = - 3/ 4 x -3/ 2 m.ananth@hotmail.ca
 Length-and-distance/499134: Please help me with this question : Two cars, a blue one and a red one, are driving towards each other from opposite ends of a 180km road. The blue car drives at 60km/h and the red car drives at 75km/h. How far from the blue car's starting point do they meet? Thanks.1 solutions Answer 337431 by mananth(12270)   on 2011-09-17 05:15:07 (Show Source): You can put this solution on YOUR website!Blue Car 60 km/h Red car 75 km/h they are traveling towards each other so add up speeds 75+60=135 km/h distance = 180 km time = d/r time = 180/135 time = 1.33 h Blue car speed = 60 km/h time = 1.33 h distance it travels to meet = 1.33*60 = 80 km.
 Travel_Word_Problems/498948: A plane traveled 864 miles to Shanghai and back. The trip there was with the wind. It took 9 hours. The trip back was into the wind. The trip back took 18 hours. What is the speed of the plane in still air? What is the speed of the wind?1 solutions Answer 337372 by mananth(12270)   on 2011-09-16 20:50:32 (Show Source): You can put this solution on YOUR website!Plane speed =x mph Wind speed =y mph against wind x-y 18.00 hours with windx+y 9.00 hours Distance = same= 864 miles t=d/r 864 / ( x - y )= 18.00 18 ( x - y ) = 864.00 18 x -18 y = 864 ....................1 864 / ( x + y )= 9.00 9.00 ( x + y ) = 864 9.00 x + 9.00 y = 864 ...............2 Multiply (1) by 1.00 Multiply (2) by 2.00 we get 18 x + -18 y = 864 18 x + 18 y = 1728 36 x = 2592 / 36 x = 72 mph plug value of x in (1) 18 x -18 y = 864 1296 -18 y = 864 -18 y = 864 -1296 -18 y = -432 y = 24 mph
 Travel_Word_Problems/498946: A jet makes a trip to the maintenance facility and back. The trip there took 9 hours and the trip back took 6 hours. It averaged 330 km/h on the return trip. Find the average speed of the trip there.1 solutions Answer 337370 by mananth(12270)   on 2011-09-16 20:47:45 (Show Source): You can put this solution on YOUR website!Plane speed =x mph Wind speed =y mph against wind x-y 18.00 hours with windx+y 9.00 hours Distance = same= 864 miles t=d/r 864/(x- y)=18.00 18(x-y)=864.00 18x-18y =864 ....................1 864/(x+y)= 9.00 9.00(x+y)= 864 9.00 x + 9.00 y = 864 ...............2 Multiply (1) by 1.00 Multiply (2) by 2.00 we get 18 x + -18 y = 864 18 x + 18 y = 1728 add the two 36 x = 2592 / 36 x = 72 mph plug value of x in (1) 18 x -18 y = 864 1296 -18 y = 864 -18 y = 864 -1296 -18 y = -432 y = 24 mph
 Linear-equations/499053: find the x- and y- intercepts for the equation. please show your work. then graph the equation -x+2y=41 solutions Answer 337355 by mananth(12270)   on 2011-09-16 20:25:14 (Show Source): You can put this solution on YOUR website!-x+2y=4 X INTERCEPT Plug y=0 -x=4 x=-4 .. Y INTERCEPT Plug x=0 2y=4 y=2 ...
 Angles/498867: If the arms of one angle are respectively parallel to the arms of another angle, then the two angles are ______________.1 solutions Answer 337226 by mananth(12270)   on 2011-09-16 10:18:45 (Show Source): You can put this solution on YOUR website!equal
 Angles/498864: what is the measure of the angle if it is 3x+18 and 7x-22? if they are verticle angles?1 solutions Answer 337225 by mananth(12270)   on 2011-09-16 10:17:54 (Show Source): You can put this solution on YOUR website!3x+18 = 7x-22 because vertically opposite angles are equal. 3x-7x=-22-18 -4x=-40 x=-40/-4 x=10 3x+18 = 3*10+18 = 48 deg
 Equations/498873: I can't figure out how to set up this equation the find all three sides. The Perimeter of a triangle is 7ft. The longest side of a triangle measures 20 in more than the shortest side. The middle side is 2 times the measure of the shortest side. Find the lengths of the three sides in inches.1 solutions Answer 337222 by mananth(12270)   on 2011-09-16 09:51:59 (Show Source): You can put this solution on YOUR website!let shortest side be x in longest side = x+20in ==> x+20 middle side = 2x x+2x+x+20=84 4x+20=84 4x=64 x=16 2x=32 x+20=36 16,32,36 are the sides
 Linear-equations/498866: Find the x-intercept of y = 6x + 121 solutions Answer 337221 by mananth(12270)   on 2011-09-16 09:44:37 (Show Source): You can put this solution on YOUR website!y=6x+12 for X intercept plug y=0 0=6x+12 6x=-12 x=-2
 Quadratic_Equations/498870: how can i find a teacher who will really teach me?1 solutions Answer 337218 by mananth(12270)   on 2011-09-16 09:42:23 (Show Source): You can put this solution on YOUR website!m.ananth@hotmail.ca
 Travel_Word_Problems/498871: If a bus ride is 21minute how many miles is that1 solutions Answer 337216 by mananth(12270)   on 2011-09-16 09:41:40 (Show Source): You can put this solution on YOUR website!what is the average speed?
 Inequalities/498819: paul and frank are on the same path 39.15 miles apart. they are going to ride their bike towards each other until they meet. frank starts pedaling 1.5 hours before paul. paul rides 1.8 miles per hour faster than frank. if they meet 3 hours after paul starts riding, find the speed of each biker.1 solutions Answer 337203 by mananth(12270)   on 2011-09-16 07:55:49 (Show Source): You can put this solution on YOUR website!paul and frank are on the same path 39.15 miles apart. they are going to ride their bike towards each other until they meet. frank starts pedaling 1.5 hours before paul. paul rides 1.8 miles per hour faster than frank. if they meet 3 hours after paul starts riding, find the speed of each biker. Frank speed = x mph Paul speed = x+1.8 mph Frank leaves 1.5 hours early distance traveled by Frank in in 1.5 hours = 1.5x so when Paul starts Frank is (39.15-1.5x) miles away they are pedalling towards each other so add up the speeds 2x+1.8 t= d/r t= 3 hours d= (39.15-1.5x) r= 2x+1.8 3= (39.15-1.5x)/(2x+1.8) 6x+5.4 = 39.15-1.5x 7.5x=39.15-5.4 7.5x=33.75 x=4.5 Frank Speed = 4.5 mph Paul speed = 6.3 mph m.ananth@hotmail.ca
 Money_Word_Problems/498810: Evaldez enterprise invest 20,000 part at 12% and the rest 14%. How much should be invested in each rate so that the income from the 14% investment is half as much as the income from the 12% investment1 solutions Answer 337189 by mananth(12270)   on 2011-09-16 07:02:34 (Show Source): You can put this solution on YOUR website!12.00% per annum ------------- x 14.00% per annum ------------ (20,000-x) total investment 20000 interest from 14.00% = 0.5times interest from 12.00% 14.00% *x = 0.5* 12.00% ( 20000 - x) 14.00% x = 1200 - 0.06 x 0.14 x = 1200 - 0.06 x 0.2 x = 1200 x= 6000 14000 12.00% per annum ------------- \$6,000 14.00% per annum ------------ \$14,000
 Triangles/498813: Two angle measures in a triangle are 47° and 43°. What type of triangle is it ?1 solutions Answer 337186 by mananth(12270)   on 2011-09-16 06:44:39 (Show Source): You can put this solution on YOUR website!47+43= 90 deg Third angle has to be 90 deg (sum of all angles of triangle = 180 deg) Right triangle
 Age_Word_Problems/498815: Tomas's age is 33 and Tim is 6.In how many years will Tomas's age be 4 times more than Tim's1 solutions Answer 337185 by mananth(12270)   on 2011-09-16 06:41:43 (Show Source): You can put this solution on YOUR website!Tomas's age is 33 Tim is 6. After x years Tomas's age = 33+x Tim's age = 6+x 4(6+x)=33+x 24+4x=33+x 3x=9 x=3 after 3 years
 Miscellaneous_Word_Problems/498782: in the lab, robyn has two solutions that contain alcohol and is mixing them with each other. Soultion A is 6% alcohol and Solution Bis 20% alcohol. She uses 400 milliliters of Solution A. How many milliters of Solution B does she use, if the resulting mixture is a 12% alcohol solution?1 solutions Answer 337164 by mananth(12270)   on 2011-09-16 02:29:34 (Show Source): You can put this solution on YOUR website! percent ---------------- quantity Alcohol I 6 ---------------- 400 ml Alcohol II 20 ---------------- x ml Mixture 12 ---------------- 400 + x ml 6*400+20x=12( 400 + x ) 2400 + 20 x = 4800 + 12 x 20 x + -12 x = 4800 - -2400 8 x = 2400 / 8 x = 300 300 ml of 20 % Alcohol II
 Linear-equations/498706: I need help to solve this problem and graph it. y=(x-2)^2+61 solutions Answer 337163 by mananth(12270)   on 2011-09-16 02:26:23 (Show Source): You can put this solution on YOUR website!y=(x-2)^2+6 y= x^2-4x+4+6 y=x^2-4x+10 x=0, y=10 (0,10) x=2,y=6 (2,6) x=3,y=7 (3,7) x=-1, y=15 (-1,15) x=-2,y=22 (-2,22) Since this is a quadratic equation it is a parabola. since co-efficient of x^2 is positive Then the graph opens upwards
 Linear-equations/498731: 36+7x-8y=0 -10y=-12-6x1 solutions Answer 337161 by mananth(12270)   on 2011-09-16 02:12:16 (Show Source): You can put this solution on YOUR website!7 x -8 y = -36 .............1 6 x -10 y = -12 .............2 Eliminate y multiply (1)by -5 Multiply (2) by 4 -35 x 40 y = 180 24 x -40 y = -48 Add the two equations -11 x = 132 / -11 x = -12 plug value of x in (1) 7 x + -8 y = -36 -84 + -8 y = -36 -8 y = -36 + 84 -8 y = 48 y = -6
 Radicals/498756: Between which two consecutive integers is each square root ? root 931 solutions Answer 337160 by mananth(12270)   on 2011-09-16 02:05:41 (Show Source): You can put this solution on YOUR website!sqrt 93 9 & 10 is between 9 & 10
 Linear-equations/498781: The sum of three numbers is 26. The second number is twice the first and the third number is 6 more than the second. Find the numbers1 solutions Answer 337159 by mananth(12270)   on 2011-09-16 01:59:51 (Show Source): You can put this solution on YOUR website!the numbers will be x,2x,2x+6 x+2x+2x+6=26 5x+6=26 -6 5x=20 /4 x=4 4,8,14
 Linear_Equations_And_Systems_Word_Problems/498715: In a chemistry class, 12 L of a 12% alcohol solution must be mixed with 20% solution to get a 14% solution. how many liters of the 20% solution are needed1 solutions Answer 337135 by mananth(12270)   on 2011-09-15 23:37:00 (Show Source): You can put this solution on YOUR website! percent ---------------- quantity Alcohol I 12 ---------------- 12 gallons Alcohol II 20 ---------------- x gallons Mixture 14 ---------------- 12 + x gallons 12*12+20x= 14 ( 12 + x ) 144 + 20 x = 168 + 14 x 20 x + -14 x = 168 - -144 6 x = 24 / 6 x = 4 4 gallons of 20 % Alcohol II
 Travel_Word_Problems/498729: Two buses leave Philadelphia at the same time and travel in opposite directions. One bus averages 55 mph, and the other 65 mph. When will they be 360 miles apart?1 solutions Answer 337131 by mananth(12270)   on 2011-09-15 23:30:45 (Show Source): You can put this solution on YOUR website!Bus I traveled east at 55 m/hr and bus II traveled west at 65 m/hr. they are moving away. So add up speeds . 120 = 120 m/h Distance = 360 m time = distance / time time= 360/120 time = 3 hours
 Travel_Word_Problems/498743: Mr. Franco and Mr. Jimenez each drove home from a business meeting. Mr. Franco traveled east at 100 km/hr and Mr. Jimenez traveled west at 80 km/hr. In how many hours were they 100 kilometers apart?1 solutions Answer 337129 by mananth(12270)   on 2011-09-15 23:26:52 (Show Source): You can put this solution on YOUR website!Mr. Franco traveled east at 100 km/hr and Mr. Jimenez traveled west at 80 km/hr. they are moving away. So add up speeds . 100+80 = 180 km/h Distance = 100 km time = distance / time time= 100/180 time = 5/9 hours
 Quadratic_Equations/498174: During the first part of a trip, a canoiest travels 35 mls. at a certain speed. The canoiest travels 9 mls. on the second part of the trip. at a speed of 5 mls. slower. The total time for this trip is 2 hrs. What was the speed on each part of the trip?1 solutions Answer 336928 by mananth(12270)   on 2011-09-15 02:39:57 (Show Source): You can put this solution on YOUR website!first part 35 miles second part 9 miles speed in first part x mph speed second part x -5 mph Total rowing time 2 hours Time first part 35 / x Time second part 9 / ( x -5 ) Time first part + time second part = 2 hours 35 / x + 9 /(x -5 ) = 2 LCD = ( x + 0 )* (x -5 ) multiply the equation by the LCD we get 35 * (x -5 )+ 9 x = 2 35 x -175 + 9 x = 2 X^2 + -10 x 54 x -175 = 2 X^2 2 X^2 -54 x 175 = 0 2 X^2+ -54 x+ 175 = / 2 1 X^2 -27 x 87.5 = Find the roots of the equation by quadratic formula a= 1 b= -27 c= 87.5 b^2-4ac= 729 - -350 b^2-4ac= 379 = 19.47 x1=( 27 + 19.47 )/ 2 x1= 23.23 mph x2=( 27 -19.47 ) / 2 x2= 3.77 mph First Part speed = 23.23 mph Second part speed = 18.23 mph m.ananth@hotmail.ca