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If they travel at 450 km/h and 620 km/h respectively, how many hours will pass before they are 2800 km apart??
1 solutions
Answer 337754 by mananth(12270)   on 2011-09-18 05:22:24 (Show Source):
You can put this solution on YOUR website!Car I -------- 450 km/h
Car II -------- 620 km/h
they are traveling away from each other
so add up speeds
620 + 450 = 1070 km/h
Distance = 2800 km
time = d/r
time= 2800 / 1070
Time = 2.62 h
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Finance/499121: Hi, can you please help me? Ive tried this problem 9 times...and I keep getting it wrong...
Thank you sooo much for your help! i hope you can help me... it would be soo appreciated! :)
Find all real solutions of the equation. or tell if there is NO REAL SOLUTION.
squareroot of: 9x + 64+8=x
1 solutions
Answer 337438 by mananth(12270) on 2011-09-17 06:21:40 (Show Source):
You can put this solution on YOUR website!
Take the square
9x+72=x^2
x^2-9x-72=0
Find the roots of the equation by quadratic formula
a= 1 ,b= -9 c -72
b^2-4ac= 81 - 288
b^2-4ac= 369
 = 19.21
x1=( 9 + 19.21 )/ 2
x1= 14.1
x2=( 9 -19.21 ) / 2
x2= -5.105
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Travel_Word_Problems/499128: The problem is: Car Travel. Two cars leave Denver traveling in
opposite directions. One car travels at a speed of
80 and the other at 96 . In how many
hours will they be 528 km apart?
I know that it is a problem that is going to take two equations to set it up and then use the substitution method to solve it, but I just am not figuring out how to set it up.
1 solutions
Answer 337437 by mananth(12270) on 2011-09-17 06:16:52 (Show Source):
You can put this solution on YOUR website!Car I -------- 80 km/h
Car II -------- 96 km/h
they are traveling away from each other
so add up speeds
96 + 80 = 176 km/h
Distance = 528 km
time = d/r
time= 528 / 176
Time = 3 h
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Equations/499131: How many gallons of 65% antifreeze solution and a 35% antifreeze solution must be mixed to obtain 15 gallons of 53% antifreeze solution?
1 solutions
Answer 337436 by mananth(12270) on 2011-09-17 06:11:17 (Show Source):
You can put this solution on YOUR website!percent percentage ---------------- quantity
antifreeze I 65 ---------------- x gal
antifreeze II 35 ---------------- 15 - x gal
Mixture 53.00% ---------------- 15
65 x + 35 ( 15 - x ) = 53 * 15
65 x + 525 - 35 x = 795
65 x - 35 x = 795 - 525
30 x = 270
/ 30
x= 9 gal 65.00% antifreeze I
6 gal 35.00% antifreeze II
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Equations/499133: One phone company charges $0.29 per minute for long-distance phone calls. A second company charges only $0.26 per minute for long-distance calls, but adds a monthly fee of $2.97. Find the number of minutes of long-distance calling for which the total bill from either company would be the same. Please round your answers to the nearest hundredth if necessary.
1 solutions
Answer 337435 by mananth(12270) on 2011-09-17 06:06:47 (Show Source):
You can put this solution on YOUR website!Let x be the number of calls
company B 2.97 + 0.26 x
company A 0 + 0.29 x
company B = company A
0 + 0.29 x = 2.97 + 0.26 x
0 + 0.29 x = 2.97 + 0.26 x
0 - 2.97 = 0.26 x -0.29 x
-2.97 < -0.03 x
99 = x
x should be 99 calls
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Numbers_Word_Problems/499163: at 12 noon, the teacher sent home 1/3 of the students plus 6. At 1pm, she sent home 1/4 of the remaining students.At 2pm, she sent home the last 21 students. How many students were originally in school that day?
1 solutions
Answer 337433 by mananth(12270) on 2011-09-17 05:58:37 (Show Source):
You can put this solution on YOUR website!Total x
12 PM 1/ 3 x+ 6 were sent away
Remainder= x - 1/3x- 6
Balance in class 2/ 3x-6
1PM she sent away 1/ 2*( 2/3x-6)
Balance in class 2/3x-6 -(0.33x +3)
1/ 3 x-3
2.00PM She sent away 21
2 PM 1/3 x -3 -21 = 0
1/ 3 x- 24 = 0
1/ 3 x= 24
x= 72
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Linear-equations/499166: find the equation of the line containing (2,-3) and having the same slope as the line 3x + 4y = 10
1 solutions
Answer 337432 by mananth(12270) on 2011-09-17 05:16:01 (Show Source):
You can put this solution on YOUR website!3 x + 4 y = 10
Find the slope of this line
make y the subject
4 y = -3 x + 10
Divide by 4
y = -0.75 x + 2.5
Compare this equation with y=mx+b
slope m = - 3/4
The slope of a line parallel to the above line will be the same
The slope of the required line will be -0.75
m= - 3/4 ,point ( 2 , -3 )
Find b by plugging the values of m & the point in
y=mx+b
-3 = -1.50 + b
b= -1.5
m= -0.75
Plug value of the slope and b in y = mx +b
The required equation isy = - 3/4 x -1.5
y = - 3/ 4 x -3/ 2
m.ananth@hotmail.ca
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Length-and-distance/499134: Please help me with this question :
Two cars, a blue one and a red one, are driving towards each other from opposite ends of a 180km road. The blue car drives at 60km/h and the red car drives at 75km/h. How far from the blue car's starting point do they meet?
Thanks.
1 solutions
Answer 337431 by mananth(12270) on 2011-09-17 05:15:07 (Show Source):
You can put this solution on YOUR website!Blue Car 60 km/h
Red car 75 km/h
they are traveling towards each other
so add up speeds
75+60=135 km/h
distance = 180 km
time = d/r
time = 180/135
time = 1.33 h
Blue car speed = 60 km/h
time = 1.33 h
distance it travels to meet = 1.33*60
= 80 km.
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Travel_Word_Problems/498948: A plane traveled 864 miles to Shanghai and back. The trip there was with the wind. It took 9 hours. The trip back was into the wind. The trip back took 18 hours. What is the speed of the plane in still air? What is the speed of the wind?
1 solutions
Answer 337372 by mananth(12270) on 2011-09-16 20:50:32 (Show Source):
You can put this solution on YOUR website!Plane speed =x mph
Wind speed =y mph
against wind x-y 18.00 hours
with windx+y 9.00 hours
Distance = same= 864 miles
t=d/r
864 / ( x - y )= 18.00
18 ( x - y ) = 864.00
18 x -18 y = 864 ....................1
864 / ( x + y )= 9.00
9.00 ( x + y ) = 864
9.00 x + 9.00 y = 864 ...............2
Multiply (1) by 1.00
Multiply (2) by 2.00
we get
18 x + -18 y = 864
18 x + 18 y = 1728
36 x = 2592
/ 36
x = 72 mph
plug value of x in (1)
18 x -18 y = 864
1296 -18 y = 864
-18 y = 864 -1296
-18 y = -432
y = 24 mph
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Travel_Word_Problems/498946: A jet makes a trip to the maintenance facility and back. The trip there took 9 hours and the trip back took 6 hours. It averaged 330 km/h on the return trip. Find the average speed of the trip there.
1 solutions
Answer 337370 by mananth(12270) on 2011-09-16 20:47:45 (Show Source):
You can put this solution on YOUR website!Plane speed =x mph
Wind speed =y mph
against wind x-y 18.00 hours
with windx+y 9.00 hours
Distance = same= 864 miles
t=d/r
864/(x- y)=18.00
18(x-y)=864.00
18x-18y =864 ....................1
864/(x+y)= 9.00
9.00(x+y)= 864
9.00 x + 9.00 y = 864 ...............2
Multiply (1) by 1.00
Multiply (2) by 2.00
we get
18 x + -18 y = 864
18 x + 18 y = 1728
add the two
36 x = 2592
/ 36
x = 72 mph
plug value of x in (1)
18 x -18 y = 864
1296 -18 y = 864
-18 y = 864 -1296
-18 y = -432
y = 24 mph
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Angles/498867: If the arms of one angle are respectively parallel to the arms of another angle, then the two angles are ______________.
1 solutions
Answer 337226 by mananth(12270) on 2011-09-16 10:18:45 (Show Source):
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Equations/498873: I can't figure out how to set up this equation the find all three sides. The Perimeter of a triangle is 7ft. The longest side of a triangle measures 20 in more than the shortest side. The middle side is 2 times the measure of the shortest side. Find the lengths of the three sides in inches.
1 solutions
Answer 337222 by mananth(12270) on 2011-09-16 09:51:59 (Show Source):
You can put this solution on YOUR website!let shortest side be x in
longest side = x+20in ==> x+20
middle side = 2x
x+2x+x+20=84
4x+20=84
4x=64
x=16
2x=32
x+20=36
16,32,36
are the sides
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Inequalities/498819: paul and frank are on the same path 39.15 miles apart. they are going to ride their bike towards each other until they meet. frank starts pedaling 1.5 hours before paul. paul rides 1.8 miles per hour faster than frank. if they meet 3 hours after paul starts riding, find the speed of each biker.
1 solutions
Answer 337203 by mananth(12270) on 2011-09-16 07:55:49 (Show Source):
You can put this solution on YOUR website!paul and frank are on the same path 39.15 miles apart. they are going to ride their bike towards each other until they meet. frank starts pedaling 1.5 hours before paul. paul rides 1.8 miles per hour faster than frank. if they meet 3 hours after paul starts riding, find the speed of each biker.
Frank speed = x mph
Paul speed = x+1.8 mph
Frank leaves 1.5 hours early
distance traveled by Frank in in 1.5 hours = 1.5x
so when Paul starts Frank is (39.15-1.5x) miles away
they are pedalling towards each other
so add up the speeds
2x+1.8
t= d/r
t= 3 hours
d= (39.15-1.5x)
r= 2x+1.8
3= (39.15-1.5x)/(2x+1.8)
6x+5.4 = 39.15-1.5x
7.5x=39.15-5.4
7.5x=33.75
x=4.5
Frank Speed = 4.5 mph
Paul speed = 6.3 mph
m.ananth@hotmail.ca
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Money_Word_Problems/498810: Evaldez enterprise invest 20,000 part at 12% and the rest 14%. How much should be invested in each rate so that the income from the 14% investment is half as much as the income from the 12% investment
1 solutions
Answer 337189 by mananth(12270) on 2011-09-16 07:02:34 (Show Source):
You can put this solution on YOUR website!12.00% per annum ------------- x
14.00% per annum ------------ (20,000-x)
total investment 20000
interest from 14.00% = 0.5times interest from 12.00%
14.00% *x = 0.5* 12.00% ( 20000 - x)
14.00% x = 1200 - 0.06 x
0.14 x = 1200 - 0.06 x
0.2 x = 1200
x= 6000 14000
12.00% per annum ------------- $6,000
14.00% per annum ------------ $14,000
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Miscellaneous_Word_Problems/498782: in the lab, robyn has two solutions that contain alcohol and is mixing them with each other. Soultion A is 6% alcohol and Solution Bis 20% alcohol. She uses 400 milliliters of Solution A. How many milliters of Solution B does she use, if the resulting mixture is a 12% alcohol solution?
1 solutions
Answer 337164 by mananth(12270) on 2011-09-16 02:29:34 (Show Source):
You can put this solution on YOUR website! percent ---------------- quantity
Alcohol I 6 ---------------- 400 ml
Alcohol II 20 ---------------- x ml
Mixture 12 ---------------- 400 + x ml
6*400+20x=12( 400 + x )
2400 + 20 x = 4800 + 12 x
20 x + -12 x = 4800 - -2400
8 x = 2400
/ 8
x = 300
300 ml of 20 % Alcohol II
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Linear-equations/498706: I need help to solve this problem and graph it. y=(x-2)^2+6
1 solutions
Answer 337163 by mananth(12270) on 2011-09-16 02:26:23 (Show Source):
You can put this solution on YOUR website!y=(x-2)^2+6
y= x^2-4x+4+6
y=x^2-4x+10
x=0, y=10 (0,10)
x=2,y=6 (2,6)
x=3,y=7 (3,7)
x=-1, y=15 (-1,15)
x=-2,y=22 (-2,22)
Since this is a quadratic equation it is a parabola.
since co-efficient of x^2 is positive Then the graph opens upwards
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Linear-equations/498731: 36+7x-8y=0
-10y=-12-6x
1 solutions
Answer 337161 by mananth(12270) on 2011-09-16 02:12:16 (Show Source):
You can put this solution on YOUR website!7 x -8 y = -36 .............1
6 x -10 y = -12 .............2
Eliminate y
multiply (1)by -5
Multiply (2) by 4
-35 x 40 y = 180
24 x -40 y = -48
Add the two equations
-11 x = 132
/ -11
x = -12
plug value of x in (1)
7 x + -8 y = -36
-84 + -8 y = -36
-8 y = -36 + 84
-8 y = 48
y = -6
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Linear_Equations_And_Systems_Word_Problems/498715: In a chemistry class, 12 L of a 12% alcohol solution must be mixed with 20% solution to get a 14% solution. how many liters of the 20% solution are needed
1 solutions
Answer 337135 by mananth(12270) on 2011-09-15 23:37:00 (Show Source):
You can put this solution on YOUR website! percent ---------------- quantity
Alcohol I 12 ---------------- 12 gallons
Alcohol II 20 ---------------- x gallons
Mixture 14 ---------------- 12 + x gallons
12*12+20x= 14 ( 12 + x )
144 + 20 x = 168 + 14 x
20 x + -14 x = 168 - -144
6 x = 24
/ 6
x = 4
4 gallons of 20 % Alcohol II
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Travel_Word_Problems/498729: Two buses leave Philadelphia at the same time and travel in opposite directions. One bus averages 55 mph, and the other 65 mph. When will they be 360 miles apart?
1 solutions
Answer 337131 by mananth(12270) on 2011-09-15 23:30:45 (Show Source):
You can put this solution on YOUR website!Bus I traveled east at 55 m/hr
and bus II traveled west at 65 m/hr.
they are moving away. So add up speeds . 120 = 120 m/h
Distance = 360 m
time = distance / time
time= 360/120
time = 3 hours
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Travel_Word_Problems/498743: Mr. Franco and Mr. Jimenez each drove home from a business meeting. Mr. Franco traveled east at 100 km/hr and Mr. Jimenez traveled west at 80 km/hr. In how many hours were they 100 kilometers apart?
1 solutions
Answer 337129 by mananth(12270) on 2011-09-15 23:26:52 (Show Source):
You can put this solution on YOUR website!Mr. Franco traveled east at 100 km/hr
and Mr. Jimenez traveled west at 80 km/hr.
they are moving away. So add up speeds . 100+80 = 180 km/h
Distance = 100 km
time = distance / time
time= 100/180
time = 5/9 hours
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Quadratic_Equations/498174: During the first part of a trip, a canoiest travels 35 mls. at a certain speed. The canoiest travels 9 mls. on the second part of the trip. at a speed of 5 mls. slower. The total time for this trip is 2 hrs. What was the speed on each part of the trip?
1 solutions
Answer 336928 by mananth(12270) on 2011-09-15 02:39:57 (Show Source):
You can put this solution on YOUR website!first part 35 miles
second part 9 miles
speed in first part x mph
speed second part x -5 mph
Total rowing time 2 hours
Time first part 35 / x
Time second part 9 / ( x -5 )
Time first part + time second part = 2 hours
35 / x + 9 /(x -5 ) = 2
LCD = ( x + 0 )* (x -5 )
multiply the equation by the LCD
we get
35 * (x -5 )+ 9 x = 2
35 x -175 + 9 x = 2 X^2 + -10 x
54 x -175 = 2 X^2
2 X^2 -54 x 175 = 0
2 X^2+ -54 x+ 175 =
/ 2
1 X^2 -27 x 87.5 =
Find the roots of the equation by quadratic formula
a= 1 b= -27 c= 87.5
b^2-4ac= 729 - -350
b^2-4ac= 379  = 19.47
x1=( 27 + 19.47 )/ 2
x1= 23.23 mph
x2=( 27 -19.47 ) / 2
x2= 3.77 mph
First Part speed = 23.23 mph
Second part speed = 18.23 mph
m.ananth@hotmail.ca
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