Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On

 Tutoring Home For Students Tools for Tutors Our Tutors Register Recently Solved
 By Tutor
| By Problem Number |

Tutor:

Recent problems solved by 'mananth'

Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299, >>Next

 Linear-equations/730616: Find an equation for the line that passes through (0,-5) and is perpendicular to the graph of x+3y=4. Write in Slope-Intercept form: So far I have x+3y-3y-4=4-3y-4 x-4=-3y then divide each side by -3 -1x/3-(-4/3)=y or y=-1x/3+3/4 -5=-1(0)/3+3/4 it gets mixed up from here, am I even doing this correctly? Thanks 1 solutions Answer 446757 by mananth(12270)   on 2013-03-26 07:03:19 (Show Source): You can put this solution on YOUR website!good job slope = -1/3 the line perpendicular will have a slope of 3 ( negative reciprocal) point (0,-5) equation will be (y-(-5))=3(x-0) y+5=3x y=3x-5 is the equation
 Age_Word_Problems/730624: a man is ten times as old as his daughter, in 5 years time he will be 5 times as old as his daughter. how old are each of them now ? Please send breakdown of solution a father is 48 years old and his son 14 years old ,in how many years will the father be three times older than the son? Please send break down and solution1 solutions Answer 446756 by mananth(12270)   on 2013-03-26 06:58:28 (Show Source): You can put this solution on YOUR website!daughter 's age =x father's age = 10x 5 years later daughter's age = x+5 father's age = 10x+5 10x+5 = 5(x+5) 10x+5=5x+25 10x-5x=25-5 5x=20 x=4 daughter 4 years Father 40 years
 Travel_Word_Problems/730627: A motor boat went downstream for 120 km and immediately returned. It took the boat 15 hours to complete the round trip. If the speed of the river was twice as high, the trip downstream and back would have taken 24 hours. What is the speed of the boat in still water? 1 solutions Answer 446755 by mananth(12270)   on 2013-03-26 06:54:18 (Show Source): You can put this solution on YOUR website!speed of boat = x speed of current = y ...................(1) ....................(2) x/y =3, x=3y substitute x=3y 120+240=60y 360=60y y=6 kphthe speed of current x= 3y x= 18kph speed of boat
 Travel_Word_Problems/730555: A Train leaves Boston at 2:00pm. A second train leaves the same city in the same direction at 8:00pm. The second train travels 150mph faster than the first. If the second overtakes the first at 10pm, what is the speed of each of the two trains. 1 solutions Answer 446729 by mananth(12270)   on 2013-03-26 00:29:08 (Show Source): You can put this solution on YOUR website!Speed of first train ---------------x speed of train II-----------------x+150 Second train leaves after 6 hours the first train has traveled 6x miles before train II starts catch up speed = 150 catch up distance = 6x catch up time =8 hours 8=6x/150 x=200 mph speed of first train 200+150 = 350 mph is the speed of train II
 Geometry_Word_Problems/730512: A stained glass window is being designed in the shape of a rectangle surmounted by a semicircle. thw width of the window is to be 3 feet, but the height h. if 24 square feet of glass is to be used, find the hight h.1 solutions Answer 446711 by mananth(12270)   on 2013-03-25 20:52:53 (Show Source): You can put this solution on YOUR website!Total area = area of rectangle + area of semi circle 24=h*3 + pi*1.5^2 24=3h +1/2(3.14*2.25) 24= 3h+3.53 3h= 20.47 h=6.82 feet the height of the rectangular portion if you need total height then add the radius to it
 Linear-equations/730492: Find the slope of the line containing the pair of points (-18,-9) and ((-19, -13)1 solutions Answer 446709 by mananth(12270)   on 2013-03-25 20:43:29 (Show Source): You can put this solution on YOUR website!x1 y1 x2 y2 -18 -9 -19 -13 The general equation of the line when co-ordinates of two points are given is y- 9 = 4 x -72 1 y= 4 x -63 / 1 y= 4 x-63
 Expressions-with-variables/730200: 2x - y =4 (1) 3x - 2y=7 (2)1 solutions Answer 446548 by mananth(12270)   on 2013-03-25 05:43:58 (Show Source): You can put this solution on YOUR website!2 x -1 y = 4 .............1 3 x -2 y = 7 .............2 Eliminate y multiply (1)by -2 Multiply (2) by 1 -4 x 2 y = -8 3 x -2 y = 7 Add the two equations -1 x = -1 / -1 x = 1 plug value of x in (1) 2 x -1 y = 4 2 -1 y = 4 -1 y = 4 -2 -1 y = 2 y = -2 x= 1 y= -2 m.ananth@hotmail.ca
 Geometry_Word_Problems/730168: Write an equation of the line passes through (5/6,-1/3) with slope m= - 1/21 solutions Answer 446547 by mananth(12270)   on 2013-03-25 05:41:07 (Show Source): You can put this solution on YOUR website!The general equation in point slope form y-y1=m(x-x1) Multiply equation by 12 12y+4 =6x+5 12y-6x= 1 y=(1/2)x+(1/12) You can write in any form you wish
 Travel_Word_Problems/730190: system of equations 2 cars start from points 92 miles apart and travel directly towards each other. one car starts at 11am and travels slower and the other starts at 11:15am and goes faster to make up for lost time. they meet at 12pm find the average speed of each car, if the slower car travels 6 mph slower than the faster one.1 solutions Answer 446546 by mananth(12270)   on 2013-03-25 05:26:48 (Show Source): You can put this solution on YOUR website!let the speed of slower car be x the speed of car II = x+6 They meet after 1 hour after car I starts distance by car I = x distance by car II = (x+6)*3/4........... ( speed * time) x+3/4(x+6)=92 multiply by 4 4x+3(x+6)=368 4x+3x+18=350 7x=350 x=50 50 & 56mph
 Sequences-and-series/730193: The fifth term of a geometric sequence is 15 and the eighth term is -15/8. Find the first term, common ratio and the third term.1 solutions Answer 446544 by mananth(12270)   on 2013-03-25 04:50:08 (Show Source): You can put this solution on YOUR website!t5 = a*r^4=15 t8 = ar^7= -15/8 r=-1/2 ar^4 = 15 a*(-1/2)^4=16 a*(1/16)=15 a= 240 T3 = 240*(1/4) T3= 60 CHECK t8= 240 * (-1/2)^7 = 240*(-1/128) =-15/8
 Money_Word_Problems/730175: interest received on one account at 8% and the second account at 9.5% first account is 3000 more than second what is total amount of interest earned1 solutions Answer 446519 by mananth(12270)   on 2013-03-25 00:19:02 (Show Source): You can put this solution on YOUR website!Account II--------------------x--------------------9.5% Account I------------------x+3000------------------8% Total interest earned = 9.5%x+8%(x+3000)
 test/729945: (6,-6); 9x+7y=8 write an equations of the line containing the given point and perpendicular to the line1 solutions Answer 446500 by mananth(12270)   on 2013-03-24 22:12:11 (Show Source): You can put this solution on YOUR website!9 x + 7 y = 8 Find the slope of this line 7 y = -9 x + 8 Divide by 7 y = -9/ 7 x + 8/7 Compare this equation with y=mx+b, m= slope & b= y intercept slope m = -9/7 The slope of a line perpendicular to the above line will be the negative reciprocal 7/9 Because m1*m2 =-1 The slope of the required line will be 7/9 m= 7/9 ,point ( 6 , -6 ) Find b by plugging the values of m & the point in y=mx+b -6 = 14/ 3 + b b= -32/3 m= 7/9 The required equation is y = 7/ 9 x -32/ 3 m.ananth@hotmail.ca
 expressions/730139: 3³ + 4(-1 - 2) - 25 I am having trouble finding the answer. I came up with 3.1 solutions Answer 446498 by mananth(12270)   on 2013-03-24 22:05:33 (Show Source): You can put this solution on YOUR website!3³ + 4(-1 - 2) - 25 27+4(-3)-25 27-12-25 27-37 =-10
 Linear_Equations_And_Systems_Word_Problems/730123: An investor invested a total of \$2,500.00 in two mutual funds. one fund earned 9% of the profit while the other earned a 6% profit. If the investors total profit was \$165.00 how much was invested in each mutual fund?1 solutions Answer 446495 by mananth(12270)   on 2013-03-24 22:01:31 (Show Source): You can put this solution on YOUR website!Part I 9.00% per annum ------------- Amount invested =x Part II 6.00% per annum ------------ Amount invested = y 2500 Interest----- 165.00 Part I 9.00% per annum ---x * Part II 6.00% per annum ---y Total investment x + 1 y= 2500 -------------1 Interest on both investments 9.00% x + 6.00% y= 165 Multiply by 100 9 x + 6 y= 16500.00 --------2 Multiply (1) by -9 we get -9 x -9 y= -22500.00 Add this to (2) 0 x -3 y= -6000 divide by -3 y = 2000 - x) Part I 9.00% \$ 500 Part II 6.00% \$ 2000 CHECK 500 --------- 9.00% ------- 45.00 2000 ------------- 6.00% ------- 120.00 Total -------------------- 165.00 11.6 m.ananth@hotmail.ca 1520
 Linear-systems/730132: use the method of substitution to solve the system of linear equation a. 2x-y=2 b. 7x-3y=101 solutions Answer 446493 by mananth(12270)   on 2013-03-24 21:59:06 (Show Source): You can put this solution on YOUR website!2 x + - y = 2 .............1 - y = 2 + -2 x / -1 = y = -2 + 2 x 7 x + -3 y = 10 .....................2 Substitute y in (2) 7 x -3 ( -2 + 2 x ) = 10 7 x + 6 + -6 x = 10 7 x -6 x = 4 1 x = 4 / 1 x= 4 Plug the value of x in (1) 2 x - y = 2 2 * 4 - y = 2 8 + - y = 2 -1 y = -6 / -1 y= 6 m.ananth@hotmail.ca
 Travel_Word_Problems/730127: A woman rows a boat upstream form one point on a river to another point 12km away in 1 and half hours. The return trip with the current takes only 40 minutes. How fast would she be rowing if she were rowing in still water (as if there is no current), and what speed is the current flowing ?1 solutions Answer 446491 by mananth(12270)   on 2013-03-24 21:54:08 (Show Source): You can put this solution on YOUR website!Boat speed speed =x mph current speed =y mph against current 1.5 hours with current 2/ 3 hours Distance with current 12 miles distance against current 12 t=d/r against current (x-y) 12.00 / ( x - y )= 1.50 1.50 x - -1.50 y = 12.00 ....................1 with current (x+y) 12.00 / ( x + y )= 2/3 2/3 ( x + y ) = 12.00 2/3 x + 2/3 y = 12.00 2x+2y=36 x+y=18........................(2) multiply equation (1) by 2 we get3x-3y=24 multiply equation (2) by 3 3x+3y=54 add up the equations 6x=78 x=13 km/h the speed of boat in stll water plug x in the equation x+y=18 y=5km/h the current speed
 Linear_Equations_And_Systems_Word_Problems/730125: a+6b=5 a+2b=-3 solve using the elimination method, the answer is an ordered pair1 solutions Answer 446486 by mananth(12270)   on 2013-03-24 21:43:21 (Show Source): You can put this solution on YOUR website!1 a + 6 b = 5 .............1 1 a + 2 b = -3 .............2 Eliminate y multiply (1)by 1 Multiply (2) by -3 1 a 6 b = 5 -3 a -6 b = 9 Add the two equations -2 a = 14 / -2 a = -7 plug value of a in (1) 1 a + 6 b = 5 -7 + 6 b = 5 6 b = 5 + 7 6 b = 12 b = 2 a= -7 b= 2 (-7,2) is the solution m.ananth@hotmail.ca
 Linear-equations/729952: Determine the equation of the line passing through the point (1;2) and parallel to the line y=-3x1 solutions Answer 446483 by mananth(12270)   on 2013-03-24 21:38:59 (Show Source): You can put this solution on YOUR website!y=-3x slope = -3 A parallel line will have the same slope , -3 point (1,2) The equation will be y-2=-3(x-1) y-2=-3x+3 y=-3x+5 is the equation
 Mixture_Word_Problems/730110: ellen wants to mix candy worth 1.09\$ per pound with candy worth \$3.32 per pound to form 25 pounds of a mixture worth \$2.43 per pound. how many pounds of the expensive candy should she use?1 solutions Answer 446476 by mananth(12270)   on 2013-03-24 21:18:16 (Show Source): You can put this solution on YOUR website! price ---------------- quantity Candy type I 3.32 ---------------- x pounds Candy type II 1.09 ------ 25 - x pounds Mixture 2.43 ---------------- 25 25 3.32 x + 1.09 ( 25 - x ) = 60.75 3.32 x + 27.25 - 1.09 x = 60.75 3.32 x - 1.09 x = 60.75 - -27.25 2.23 x = 33.5 / 2.23 x = 15.02 pounds 3.32 Candy type I 9.98 pounds 2.43 Candy type II m.ananth@hotmail.ca
 Equations/730084: Mrs. Crews bought 4 pencils and 3 pens for \$5.60... Mrs Henderson bought 2 pencils and 3 pens for \$4.60 of the same kind... What is the price for each pen and pencil? 1 solutions Answer 446473 by mananth(12270)   on 2013-03-24 21:12:45 (Show Source): You can put this solution on YOUR website!x= price of pencil y= price of pen 4.00 x + 3.00 y = 5.60 .............1 2.00 x + 3.00 y = 4.60 .............2 Eliminate y multiply (1)by -1.00 Multiply (2) by 1.00 -4.00 x -3.00 y = -5.60 2.00 x + 3.00 y = 4.60 Add the two equations -2.00 x = -1.00 / -2.00 x = .50 plug value of x in (1) 4.00 x + 3.00 y = 5.60 2.00 + 3.00 y = 5.60 3.00 y = 5.60 -2.00 3.00 y = 3.60 y = 1.20 x= 0.50 price of pencil y= 1.20 price of pen m.ananth@hotmail.ca
 Travel_Word_Problems/729798: An aeroplane takes off from the ground at an angle of 27 degrees and its average speed in the first 10 seconds is 200 km h-1 . What is the altitude of the plane at the end of this time?1 solutions Answer 446256 by mananth(12270)   on 2013-03-24 06:19:40 (Show Source): You can put this solution on YOUR website!from the given condition sin theta = opposite side / hypotenuse Sin 27 = altitude/ the distance traveled in 10 seconds 200 km/h 200*1000/3600 m /s =55.56 sin 27 = altitude / 55.56 0.45= altitude/55.56 altitude = 25 meters
 Linear-systems/729818: Three numbers are in the ratio of 4 : 5 : 6. If the sum of the largest and the smallest equals the sum of the third and 55, find the numbers.1 solutions Answer 446255 by mananth(12270)   on 2013-03-24 06:08:07 (Show Source): You can put this solution on YOUR website!let the common multiple be x the numbers will be 4x,5x, 6x 4x+6x=5x+55 10x=5x+55 5x=55 x=11 44,55,66 are the numbers
 test/729826: THE DIAMETER OF THE WHEEL OF A CAR IS 5OCM.THE CAR TRAVELLS 72KM/HR,THEN WHAT IS THE DISTANCE COVERED BY CAR IN 1SEC,AND HOW MANY TIMES THE WHEEL RPTATES WITHIN 1 SECOND??1 solutions Answer 446254 by mananth(12270)   on 2013-03-24 06:02:02 (Show Source): You can put this solution on YOUR website!72 km/h = (72000/3600) m/s = 20 m/s it travels 20 m in 1 sec =2000 cm circumference of wheel = pi *d =3.14*50 =157 cm Number of rotations = 2000/157 = 12.74 rev
 Equations/729830: a rectangle has a perimeter of 36cm. the square of the length of its diagonal is 164 square metres. find the dimensions of the rectangle.1 solutions Answer 446253 by mananth(12270)   on 2013-03-24 05:53:45 (Show Source): You can put this solution on YOUR website!Perimeter 2(l+w)=36 l+w=18 l^2+w^2= 164 (l+w)^2-2lw=164 18^2-2lw=164 324-21w=164 21w=160 lw=80 l=80/w substitute l in l+w=18 80/w + w = 18 multiply by w 80+w^2=18w w^2-18w+80=0 (w-10)(w-8)=0 w=8 OR 10 so dimensions are 10cm & 8 cm