New!
Get regular updates about newly solved problems
via algebra.com's RSS system.
Recent problems solved by 'mananth'
mananth answered: 12270 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299, >>Next
Geometry_Word_Problems/548969: a picture frame measures 24cm by 15 cm.There is 220 cm squared of picture showing.The frame is of uniform thickness.Find the thickness. 1 solutions
Answer 357362 by mananth(12270) on 2011-12-19 09:31:45 (Show Source):
You can put this solution on YOUR website!Area of picture frame =24*15 = 360 m^2
let the uniform width be x on length & width on each side
width of picture = 15-2x
length of picture = 24-2x
(15-2x)(24-2x)=220
360-30x-48x+4x^2=220
360-220-78x+4x^2=0
4x^2-78x+140=0
/2
2(2x^2-39x+70)=0
2(2x^2-35x-4x+70)=0
2(2x(x-17.5)-2(2x-35))=0
2((x-17.5)(x-2))=0
Neglect 17.5 since it is greater than width
so width = 2feet
m.ananth@hotmail.ca
|
test/548968: Sciencetific notation 1 solutions
Answer 357358 by mananth(12270) on 2011-12-19 09:20:59 (Show Source):
You can put this solution on YOUR website!scientific notation
it is way of writing very large numbers
example
Light travels at 300000 meters /s
that is written as 3*10^5 m/s
Distance between earth & Moon
assume 384000 km
3.84 * 10^5 km
The decimal point is put after one digit
m.ananth@hotmail.ca
|
Travel_Word_Problems/548800: Miguel walks 4 miles in 75 minutes. His rate for the first part of his walk is shown in the table below. The table below shows Time: 30 min Rate: 3 1/2 mph 1 solutions
Answer 357355 by mananth(12270) on 2011-12-19 09:13:56 (Show Source):
You can put this solution on YOUR website!time = 1/2 hour
rate = 3 1/2 = 7/2 mph
d=r*t
1/2 * 7/2 is the distance in the first part
=7/4 miles
4-7/4 is the balance walked in the second part
9/4 miles in the second half = 45 minutes = 3/4
rate = d/t
rate = (9/4) / (3/4)
=9/4 * 4/3
=3 mph in the second part
|
Graphs/548965: graph the equation y=-3x-2 1 solutions
Answer 357342 by mananth(12270) on 2011-12-19 08:42:55 (Show Source):
You can put this solution on YOUR website!y= -3 x + -2
Assume values of x and plug in the equation to get values of y.
Alos you can find the x & y intercepts and draw the graph
Plot the points
x 0 -2 -0.67 -1
y= -2 4 0 1
(x,y) ( 0 , -2 ),( -2 , 4
|
Radicals/548960: simplify by rationalizing the denominator
x/sqrtx-3
completely factorise the following
3x^2-3x-18
Simplify
2x-2/x^2-2x-8 / x^2-1/x^2+5x+4 1 solutions
Answer 357340 by mananth(12270) on 2011-12-19 08:36:29 (Show Source):
|
Rectangles/548892: In order for a chemical reaction to remain stable, its Celsius temperature must be no more than 99.6ēC. Find the Fahrenheit temperatures at which the reaction will remain stable. (F = 9/5C + 32) 1 solutions
Answer 357326 by mananth(12270) on 2011-12-19 05:07:16 (Show Source):
|
Travel_Word_Problems/548938: If Alec rode his bike from Atlanta, Georgia to New Orleans, Louisiana at 15 miles an hour the whole way there. How long did it take him to get to his destination? 1 solutions
Answer 357325 by mananth(12270) on 2011-12-19 05:02:29 (Show Source):
|
percentage/548878: Katie paid 1.35 sales tax on a blouse that was marked 18.00. At the same rate, how much sales tax would she pay for a pair of 34.00 pair of pants? 1 solutions
Answer 357324 by mananth(12270) on 2011-12-19 04:58:17 (Show Source):
|
Expressions-with-variables/548945: To buy both a new car and a new house, Tina sought two loans totalling $191,610. The simple interest rate on the first loan was 6.3%, while the simple interest rate on the second loan was 8.8%. At the end of the first year, Tina paid a combined interest payment of $16,681.66. What were the amounts of the two loans?
How do I set up and answer 1 solutions
Answer 357321 by mananth(12270) on 2011-12-19 04:48:22 (Show Source):
You can put this solution on YOUR website!Fund A 6.30% per annum ---x
Fund B 8.80% per annum ---y
x+y=191610 ------------------------1
6.30%x+ 8.80%y= =$16,681.66
Multiply by100
6.3x+8.8y=$1,668,166.00 --------2
Multiply (1) by -6.3
we get
-6.3x-6.3y=-1207143.00
Add this to (2)
0x+2.5y=$461,023.00
divide by2.5
y = $184,409.20 investment at 8.80%
Balance $7,200.80 investment at 6.30%
CHECK
$7,200.80 --------- 6.30% ------- $453.65
$184,409.20 ------- 8.80% ------- $16,228.01
Total -------------- $16,681.66
m.ananth@hotmail.ca
|
Expressions-with-variables/548944: 5x -9y =7
7y 3x = -5
solve by substitution
1 solutions
Answer 357320 by mananth(12270) on 2011-12-19 04:38:19 (Show Source):
You can put this solution on YOUR website!5x-9y=7 .............1
7y=-5+3x ---------2
/7=
y=-0.71+0.43x
Substitute y in (1)
5x-9(-0.71+0.43 x)=7
5x+6.43-3.86x= 7
5x-3.86 x=7-6.43
1.14x=0.57
/1.14
x=0.5
Plug the value of x in (1)
5x-9y= 7
5*0.5-9y=7
2.5-9y= 7
-9y=4.5
/ -9
y= -0.5
m.ananth@hotmail.ca
|
Expressions-with-variables/548946: A dehydrated patient needs a 6.8% saline IV. Unfortunately, the hospital only has bags of 2% and 8% saline solutions. How many liters of each of these solutions should be mixed together to yield 2 liters of the desired concentration? 1 solutions
Answer 357319 by mananth(12270) on 2011-12-19 04:31:53 (Show Source):
You can put this solution on YOUR website!percent ---------------- quantity
Saline I 2 ----------------x L
Saline II 8 ------ 2-x L
Mixture 6.80% ---------------- 2
2x+8(2-x)=6.8*2
2x+16-8x=13.6
2x-8x= 13.6-16
-6x=-2.4
/ -6
x=0.4 L 2.00% Saline I
1.6 L 8.00% Saline II
m.ananth@hotmail.ca
|
Travel_Word_Problems/548855: Two cars left at an intersection at the same time, one heading north and the other heading west. Later they were exactly 95 miles apart. The car heading west had gone 38 miles less than twice as far as the car headed north. How far has each car traveleld? 1 solutions
Answer 357316 by mananth(12270) on 2011-12-19 03:33:12 (Show Source):
You can put this solution on YOUR website!This is a problem where pythagoras theorem has to be applied
at any given time the cars are travelling at right angles to each other
north bound has traveled x miles
west bound car traveled 2x-38miles
leg1^2+leg2^2=hypotenuse ^2
x^2+(2x-38)^2=95^2
x^2+4x^2-152x+1444=9025
5x^2-152x-7581=0
Find the roots of the equation by quadratic formula
a= 5 , b= -152 , c= -7581
b^2-4ac= 23104 + 151620
b^2-4ac= 174724
x1=( 152 + 418 )/ 10
x1= 57.00
x2=( 152 -418 ) / 10
x2= -26.60
Ignore negative value
57 miles north bound car
west bound car = 2*57-38=76 miles
m.ananth@hotmail.ca
|
Numbers_Word_Problems/548850: twice one number is 28 more than a second number. when 23 is added to the second number the result is 12 less than three times the first number, what are the numbers? 1 solutions
Answer 357315 by mananth(12270) on 2011-12-19 03:17:48 (Show Source):
You can put this solution on YOUR website!one number =x
other number =y
2x=y+28
y+23=3x-12
2x=y+28
2x-y=28................(1)
y+23=3x-12
y-3x=-35................(2)
2 x -1 y = 28 .............1
-3 x + 1 y = -35 .............2
Eliminate y
multiply (1)by 1
Multiply (2) by 1
2 x -1 y = 28
-3 x + 1 y = -35
Add the two equations
-1 x = -7.00
/ -1
x = 7
plug value of x in (1)
2 x + -1 y = 28
14 + -1 y = 28
-1 y = 28 -14
-1 y = 14
y = -14
7 & 14 are the numbers
|
Mixture_Word_Problems/548825: C and Y candy company mixes candy that costs $6.00 per kg with candy that costs $4.50 per kg. How many kilograms of each are needed to make ao 3kg box that costs $15.00? 1 solutions
Answer 357313 by mananth(12270) on 2011-12-19 03:11:23 (Show Source):
You can put this solution on YOUR website!$ 6 Candy x kgs
$4.5 candy y kgs
x+y=3....................(1)
6x+4.5y=15................(2)
multiply (1) by -6
-6x-6y=-18
add to (2)
-1.5y=-3
/-1.5
y=2
x=1
$ 6 Candy 1 kg
$4.5 candy 2 kgs
|
Graphs/548903: Snookers Lumber can convert logs into either lumber or plywood. In a given day, the mill turns out twice as many units of playwood as lumber. It makes a profit of $25 on a unit of lumber and $50 on a unit of plywood. How many of each unit must be produced and sold in order to make a profit of $13000?
Snooker Lumber must produce and sell Units of lumber and Units of plywood to make a profit of $13000. 1 solutions
Answer 357311 by mananth(12270) on 2011-12-19 02:57:37 (Show Source):
You can put this solution on YOUR website!lumber l units
plywood p units p=2l
25l+50p=13000
but p=2l
25l + 50*2l=13000
125l=13000
/125
l=13000/125
Lumber units 104
plywood units 104 *2=208 units
|
Rectangles/548940: the length of a rectangle is 3 feet less than five times its width, if the perimeter is 90 feet, find the dimensions (lenth and Width). What is the area of the rectangle? 1 solutions
Answer 357307 by mananth(12270) on 2011-12-19 02:42:09 (Show Source):
You can put this solution on YOUR website!width =w
length = 5w-3
Perimeter = 2(L+W)
2(w+5w-3)=90
2(6w-3)=90
/2
6w-3=45
6w=48
/6
w=8
width = 8 feet
length = 5*8-3=37 feet
Area = L*w
Area = 8*37=296 sq.ft
|
Travel_Word_Problems/548934: Please help me with this problem. "While training for a biathlon race, Kevin covered a total distance fo 9km by swimming for 45 minutes and running for 20 minutes. The next day he swam for 30 minutes and ran for 40 minutes. Find his rates (in km/h) for swimming and running (assume these rate are contant). Thanks! 1 solutions
Answer 357302 by mananth(12270) on 2011-12-19 01:35:02 (Show Source):
You can put this solution on YOUR website!swimming rate = s
running rate =r
d=r*t
convert minutes to hours
First day
(3/4)s+(1/3)r = 9
LCD = 12
multiply equation by 12
9s+4r=108...............(1)
Day II
(1/2)s+(2/3)r= 9
LCD = 6
multiply equation by 6
3s+4r=54....................(2)
9 s + 4 r = 108 .............1
3 s + 4 r = 54 .............2
Eliminate r
multiply (1)by -1
Multiply (2) by 1
-9 s -4 r = -108
3 s + 4 r = 54
Add the two equations
-6 s = -54.00
/ -6
s = 9
plug value of s in (1)
9 s + 4 r = 108
81 + 4 r = 108
4 r = 108 -81
4 r = 27
r = 6 3/ 4
swimming rate 9 km/h
running rate 6 3/4 km/h
m.ananth@hotmail.ca
|
test/548936: Walter is a waiter at the Towne Diner. He earns a daily wage of $50, plus tips that are equal to 15% of the total cost of the dinners he serves. What was the total cost of the dinneres he served if he earned $170 on Tuesday? 1 solutions
Answer 357300 by mananth(12270) on 2011-12-19 01:23:59 (Show Source):
You can put this solution on YOUR website!D(w) = 50 + 0.15 x
where x is the cost of dinner he serves
he earned $170
170=50+0.15x
170-50 = 0.15x
120=0.15x
120/0.15=x
800=x
$800 dinner was served by the waiter.
m.ananth@hotmail.ca
|
|