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Equations/604120: I need help with three math problems:
#1.) 4x^2 + 10x +6
#2.) x^2 - 5x+6 = 0
#3.) (6x + 2) (3x - 12) = 0
Thanks! 1 solutions
Answer 381001 by mananth(12270) on 2012-04-26 23:15:26 (Show Source):
You can put this solution on YOUR website!#1.) 4x^2 + 10x +6
a=4, b=10 c= 6
ac= 24
4x^2+6x+4x+6
2x(2x+3)+2(2x+3)
(2x+2)(2x+3)
2(x+2)(2x+3)
#2.) x^2 - 5x+6 = 0
x^2-3x-2x+6
x(x-3)-2(x-3)
(x-3)(x-2)=0
x=3 OR 2
#3.) (6x + 2) (3x - 12) = 0
If if you have to find the roots
(6x+2)=0
6x=-2
x= -2/6
x=-1/3
OR
3x-12=0
3x=12
x=4
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Equations/604125: Mitchell paid $94 for ten tickets to the concert. Adult tickets cost $15 each. Students tickets cost $8 each. How many of each kind of tickets did he buy? 1 solutions
Answer 380998 by mananth(12270) on 2012-04-26 23:09:08 (Show Source):
You can put this solution on YOUR website!x Number of adult tickets
y Number of student tickets
Total attended
7 x + 10 y = 10 .............1
15 x + 8 y = 94 .............2
Eliminate y
multiply (1)by -4
Multiply (2) by 5
-26 x -40 y = -40
75 x + 40 y = 470
Add the two equations
49 x = 430
/ 49
x = 9
plug value of x in (1)
7 x + 10 y = 10
57 + 10 y = 10
10 y = 10 -57
10 y = -47
y = -5
$ 9 Number of adult tickets
$ -5 Number of student tickets
m.ananth@hotmail.ca
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Linear-equations/604088: How can you graph 6.5x+10y=-20 and -6x+3y=18 1 solutions
Answer 380956 by mananth(12270) on 2012-04-26 21:16:43 (Show Source):
You can put this solution on YOUR website!6.5x+10y=-20
6.5 x + 10 y = -20
y= - 13/20 x -2
Assume values of x and plug in the equation to get values of y.
Plot the points
x 0 20 -20
y= -2 -15 11
(x,y) (0,-2),(20,-15),(-20,11 )
-6x+3y=18
-6 x + 3 y = 18
y= 2 x + 6
Assume values of x and plug in the equation to get values of y.
Plot the points
x 0 1 2
y= 6 8 10
(x,y) (0,6),(1,8),(2,10)
The solution is (-3,0)
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Equations/604073: Hi I need to ask a very important question, this is what my professor said about the answer
"Your answer is incorrect; you can multiply a number by itself 3 times and get a negative. Therefore, you do not get i"
I have done this over and over again, please help me out I have explained to her why I think I need to challenge her. Can anyone help???
Original question with answer below (I got answer from tutor on her and phone a program that I pay to use called www.Mathway.com)
Simplify -3√-1000
Tutor response:-3√-1000 then -3i√1000 which becomes -3(10)i√10 which is -30i√10
Mathway.com response”
-3√-1000
put all the perfect square roots out from under the radical, in this case remove 10i because it is a perfect square
(-3*10i*√10)
remove the parenthesis around the expression
-3*10i*√10
multiple the -30i by -30i
resulting in
-30i√10
1 solutions
Answer 380945 by mananth(12270) on 2012-04-26 20:42:28 (Show Source):
You can put this solution on YOUR website!Your professor' solution is perfect.
I fail to understand why you multiply -30i by -30i
&
-30i *-30 i = -30*-30*i*i= 900i^2= 900
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Miscellaneous_Word_Problems/603783: Four ball players have $233 between them. Melvin has $20 more than Harvey, $53 more than Bruce and $71 more than Rollo. How much money did each player have? 1 solutions
Answer 380831 by mananth(12270) on 2012-04-26 09:08:20 (Show Source):
You can put this solution on YOUR website!Melwin has x
Harvey x-20
Bruce x-53
Rollo x-71
Add them up total is 233
4x-144=233
4x= 144+233
4x=377
/4
x= 94.25
Amount in Dollars
Harvey = 94.25-20= 74.25
Bruce = 94.25-53= 41.25
Rollo= 94.25-71=23.25
Melwin = 94.25
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Geometry_Word_Problems/603785: Find the dimensions of a photo that has an area of 48 sq. in and a perimeter of 28 in. 1 solutions
Answer 380829 by mananth(12270) on 2012-04-26 08:59:17 (Show Source):
You can put this solution on YOUR website!let length = x in
width = y in
Perimeter
2(x+y) = 28
x+y = 14
Area
xy = 48
x= 48/y
substitute x
x+y =14
48/y + y = 14
multiply equation by y
48+y^2=14y
y^2-14y+48=0
y^2-8y-6y+48=0
y(y-8)-6(y-8)=0
(y-8)(y-6)=0
y = 6 OR 8
the dimensions are 8 in by 6 in
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Travel_Word_Problems/603745: two cars, 645 kilometers apart, begin driving toward each other on long straight highway. one car travels 100 kilometers per hour and the other 10 kilometers per hour. At the same time, a canary, starting on one car, flies back and forth between the two cars as they approach each other. If the canary flies 120 kilometers per hour and spends no time to turn around at each car, how far has it flown when the cars collide? 1 solutions
Answer 380827 by mananth(12270) on 2012-04-26 08:55:26 (Show Source):
You can put this solution on YOUR website!We have to find out how much time the Canary flies, before they collide
Car I speed = 100 km/h
Car II speed = 10km/h
they are moving towards each other
so add up their speeds= 110 km/h
distance = 645 km
Time = d/r
t= 645/110
t= 5.86 hours
speed of Canary = 120 km/h
time = 5.86 hours
so distance it flies = 5.86 *120= 703 km approx
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Age_Word_Problems/603784: sonny is twice as old as david. Four years ago, he was four times as old as david. When will the sum of their ages be 66? 1 solutions
Answer 380825 by mananth(12270) on 2012-04-26 08:48:39 (Show Source):
You can put this solution on YOUR website!David be x years
Sonny = 2x
4 years ago their ages
David = x-4
Sonny = 2x-4
2x-4=4(x-4)
2x-4 = 4x-16
4x-2x=16-4
2x=12
/2
x= 6 --- David's age
Sonny's age = 12
Let their sum of ages be 66 after y years
6+y+12+y = 66
2y+18=66
2y=66-18
2y= 48
/2
y=24
their sum will be 66 after 24 years
CHECK
David =6 + 24= 30
Sonny = 12+24= 36
Total = 66
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Human-and-algebraic-language/603675: A motorist travels for 3okm at xkm/h and for 9okm at ykm/h and takes place 2.5hours for the journey. if the speed are interchanging, the journey take 2whole number 1/6 find x and y 1 solutions
Answer 380786 by mananth(12270) on 2012-04-25 23:09:02 (Show Source):
You can put this solution on YOUR website!Distance = speed * time
Time = distance/speed
t=d/r
First condition
Time Part I + time part II = 2.5 hour
30/x+90/y = 2.5
Let 1/x=a & 1/y = b
30a+90b=5/2.......................(1)
Second condition
90/x+30/y = 2 1/6 = 13/6
90a+30b= 13/6......................(2)
add (1) & (2)
120a+120b=5/2+13/6
120a+120b=14/3
divide by 120
a+b= 14/360.............(3)
(1)-(2)
-60a+60b=1/3
divide by -60
a-b=-1/180...................(4)
(3)+(4)
2a= 14/360-1/180
a=7/360 -1/360
a= 6/360
a=1/60
1/x= 1/60
x= 60
a+b = 14/360
b= 14/360 -1/60
b=8/360
b=1/y = 8/360
y= 360/8
y=45
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Travel_Word_Problems/603637: A small motor boat travels 7mph in still water. It takes 6hrs. longer to travel 48 miles going up stream than it does going down stream. Find the rate of the current. (hint 7+x=rate going down stream and 7-x= rate going up stream. Round off your answer to the nearest tenth). 1 solutions
Answer 380779 by mananth(12270) on 2012-04-25 22:16:07 (Show Source):
You can put this solution on YOUR website!Boat speed 7 miles
current speed = x
Speed with current 7 + x
Speed against current 7 - x
Distance = 48 miles
t=d/r
Time against current - Time with current = 6 hour
48 /( 7 - x)- 48 /( 7 +x) = 6
LCD= ( 7 - x)( 7 + x)
Multiply equation by LCD
We get
48(7+x)-48(7-x) =6*(7-x)(7+x)
336+48x-336+48 x= 6*(49-x^2)
96 x = 294 - -6 x^2
6 x^2 96 x + -294 = 0
Find the roots of the equation by quadratic formula
a= 6 ,b= 96 c -294
b^2-4ac= 9216 - 7056
b^2-4ac= 16272
 = 127.56
x1=( -96 + 127.56 )/ 12
x1= 2.63
x2=( -96 -127.56 ) / 12
x2= -18.63
Ignore negative value
speed = 2.6 mph
m.ananth@hotmail.ca
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Linear-equations/603656: John sold 5 rolls of plain wrapping paper and 8 rolls of shiny wrapping paper for a total of $199. Totsaka sold 5 rolls of plain wrapping paper and 6 rolls of shiny wrapping paper for a total of $163.
Determine the cost each of one roll of plain wrapping paper and one roll of shiny wrapping paper?
-Thanks to anyone who helps. 1 solutions
Answer 380769 by mananth(12270) on 2012-04-25 21:36:13 (Show Source):
You can put this solution on YOUR website!x cost of roll of plain wrapping paper
y cost of roll of shiny paper
Total attended
5 x + 8 y = 199 .............1
5 x + 6 y = 163 .............2
Eliminate y
multiply (1)by -3
Multiply (2) by 4
-15 x -24 y = -597
20 x + 24 y = 652
Add the two equations
5 x = 55
/ 5
x = 11
plug value of x in (1)
5 x + 8 y = 199
55 + 8 y = 199
8 y = 199 -55.00
8 y = 144
y = 18
$ 11 cost of roll of plain wrapping paper
$ 18 cost of roll of shiny paper
m.ananth@hotmail.ca
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Linear-equations/603652: - Thanks to whoever helps.
Heather sold 3 packages of tulip bulbs and 2 packages of crocus bulbs for a total of $85. Jimmy sold 10 packages of tulip bulbs and 2 packages of crocus bulbs for a total of $190. 1 solutions
Answer 380763 by mananth(12270) on 2012-04-25 21:24:48 (Show Source):
You can put this solution on YOUR website!You must also ask a question.
Anyway
x cost of package of tulips
y cost of package of crocus
Total attended
3 x + 2 y = 85 .............1
10 x + 2 y = 190 .............2
Eliminate y
multiply (1)by -1
Multiply (2) by 1
-3 x -2 y = -85
10 x + 2 y = 190
Add the two equations
7 x = 105
/ 7
x = 15
plug value of x in (1)
3 x + 2 y = 85
45 + 2 y = 85
2 y = 85 -45.00
2 y = 40
y = 20
$15 cost of package of tulips
$20 cost of package of crocus
m.ananth@hotmail.ca
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Mixture_Word_Problems/603643: A chemist has a solution that is 60% saline and another solution that is 35% saline. She wants to make 100 ounces of a mixture that will be 40% saline. How many ounces of the 60% saline solution will she use? 1 solutions
Answer 380760 by mananth(12270) on 2012-04-25 21:07:40 (Show Source):
You can put this solution on YOUR website! percent ---------------- quantity
Saline solution I 60.00% ---------------- x ounces
Saline solution II 35.00% ------ 100 - x ounces
Mixture 40.00% ---------------- 100
12
60.00%x +35.00% (100 -x)=40.00%*100
60x+35 (100-x) =4000
60x+3500-35x = 4000
60x- 35x = 4000 -3500
25 x = 500
/ 25
x=20 ounces 60.00% Saline solution I
80 ounces 35.00% Saline solution II
m.ananth@hotmail.ca
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Mixture_Word_Problems/603183: how much pure acid must be mixed into 100ml of 20% acid to create a solution of 60% acid? 1 solutions
Answer 380618 by mananth(12270) on 2012-04-24 21:24:25 (Show Source):
You can put this solution on YOUR website!-------------- percent ---------------- Amount
Acid solution 20 ---------------- 100 ml
Pure acid 100 ---------------- x ml
Mixture 60 ---------------- 100 + x ml
20*100 +100x =60(100 +x)
2000+ 100x=6000+60x
100x-60x=-2000+ 6000
40 x = 4000
/ 40
x = 100 ml Pure acid
m.ananth@hotmail.ca
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Linear_Equations_And_Systems_Word_Problems/603101: There are thirty-three students in the Chess Club. There are five more boys than girls in the club. Write and solve a system of equations to find the number of boys and girls in the Chess Club. 1 solutions
Answer 380615 by mananth(12270) on 2012-04-24 21:19:51 (Show Source):
You can put this solution on YOUR website!x number of boys
y number of girls
Total attended
x+y = 33 .............1
x-y=5 .............2
Eliminate y
Add the two equations
2 x = 38
/ 2
x = 19
plug value of x in (1)
1 x + 1 y = 33
19 + 1 y = 33
1 y = 33-19
1 y = 14
y = 14
19 number of boys
14 number of girls
m.ananth@hotmail.ca
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Complex_Numbers/603157: i need to simplify complex numbers. the problem is (6+3sq.rt.-1)(6-sq.rt.-1) we have the answers but we need to show our work and i have no idea how to get there. the answer is 39+12sq.rt.-1 1 solutions
Answer 380613 by mananth(12270) on 2012-04-24 20:59:49 (Show Source):
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Age_Word_Problems/603173: you can buy 3 hotdogs and 1 coke for $4.55. you can buy 2 hotdogs and 1 coke for $3.30 how much does 1 hotdog cost 1 solutions
Answer 380610 by mananth(12270) on 2012-04-24 20:50:56 (Show Source):
You can put this solution on YOUR website!x cost of each hot dog
y cost of each coke
Total attended
3 x + 1 y = 4.55 .............1
2.00 x + 1.00 y = 3.30 .............2
Eliminate y
multiply (1)by -1.00
Multiply (2) by 1.00
-3.00 x -1.00 y = -4.55
2.00 x + 1.00 y = 3.30
Add the two equations
-1.00 x = -1.25
/ -1.00
x = 1.25
plug value of x in (1)
3.00 x + 1.00 y = 4.55
3.75 + 1.00 y = 4.55
1.00 y = 4.55 -3.75
1.00 y = 0.80
y = 0.80
$1.25 cost of each hot dog
$0.80 cost of each coke
m.ananth@hotmail.ca
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Triangles/602769: Hello, would any tutors please help me with these problems? I don't really understand how to do them. If also you can explain how you did them, I would be really thankful. Thank you for your time!!!
http://i90.photobucket.com/albums/k250/robinahood11/photo22.jpg 1 solutions
Answer 380402 by mananth(12270) on 2012-04-23 23:57:44 (Show Source):
You can put this solution on YOUR website!13.A
A(2,8)
B(0,8)
C(2,2)
Let O be the center of the circle circumscribing the triangle
Then d(OA)=d(OB)=d(OC) all are radii.
Let the coordinates of be (x,y)
The distance between two points (x1,y1) & (x2,y2) is given by
d= 
O(x,y) & A(2,8)
d(OA)= 
= 
=
B(0,8)O(x,y)
d(OB)=  =
Since OA & OB are radii
They are equal
 = 
square both sides

-4x=-68+64
=-4x=-4
x=1
C(2,2) O(x,y)
D(OC)= 
= 
=
d(OC)=d(OA)
 = 
square both sides
 = 
12y=60
/12
y=5
The center (1,5)
17 bisector
18 median
19 altitude
m.ananth@hotmail.ca
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