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# Recent problems solved by 'mananth'

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 Rational-functions/604198: (7x)/(x-2)+(2x)/(x+2)=9 what are the steps to solve this1 solutions Answer 381004 by mananth(12270)   on 2012-04-26 23:22:51 (Show Source): You can put this solution on YOUR website! LCD = (x-2)(x+2)= x^2-4 Multiply equation by the LCD 10x=-36 x= -3.6
 Equations/604120: I need help with three math problems: #1.) 4x^2 + 10x +6 #2.) x^2 - 5x+6 = 0 #3.) (6x + 2) (3x - 12) = 0 Thanks!1 solutions Answer 381001 by mananth(12270)   on 2012-04-26 23:15:26 (Show Source): You can put this solution on YOUR website!#1.) 4x^2 + 10x +6 a=4, b=10 c= 6 ac= 24 4x^2+6x+4x+6 2x(2x+3)+2(2x+3) (2x+2)(2x+3) 2(x+2)(2x+3) #2.) x^2 - 5x+6 = 0 x^2-3x-2x+6 x(x-3)-2(x-3) (x-3)(x-2)=0 x=3 OR 2 #3.) (6x + 2) (3x - 12) = 0 If if you have to find the roots (6x+2)=0 6x=-2 x= -2/6 x=-1/3 OR 3x-12=0 3x=12 x=4
 Equations/604125: Mitchell paid \$94 for ten tickets to the concert. Adult tickets cost \$15 each. Students tickets cost \$8 each. How many of each kind of tickets did he buy?1 solutions Answer 380998 by mananth(12270)   on 2012-04-26 23:09:08 (Show Source): You can put this solution on YOUR website!x Number of adult tickets y Number of student tickets Total attended 7 x + 10 y = 10 .............1 15 x + 8 y = 94 .............2 Eliminate y multiply (1)by -4 Multiply (2) by 5 -26 x -40 y = -40 75 x + 40 y = 470 Add the two equations 49 x = 430 / 49 x = 9 plug value of x in (1) 7 x + 10 y = 10 57 + 10 y = 10 10 y = 10 -57 10 y = -47 y = -5 \$ 9 Number of adult tickets \$ -5 Number of student tickets m.ananth@hotmail.ca
 Surface-area/604188: How do i find the surface area and volume?1 solutions Answer 380992 by mananth(12270)   on 2012-04-26 23:00:29 (Show Source): You can put this solution on YOUR website!What is the shape? cuboid,Prism,?
 Polynomials-and-rational-expressions/604183: (r^5s^-3/r^-3s^10)^2 I tried this problem and got r^16 s^141 solutions Answer 380991 by mananth(12270)   on 2012-04-26 22:58:42 (Show Source): You can put this solution on YOUR website! Square the term
 Linear-equations/604088: How can you graph 6.5x+10y=-20 and -6x+3y=181 solutions Answer 380956 by mananth(12270)   on 2012-04-26 21:16:43 (Show Source): You can put this solution on YOUR website!6.5x+10y=-20 6.5 x + 10 y = -20 y= - 13/20 x -2 Assume values of x and plug in the equation to get values of y. Plot the points x 0 20 -20 y= -2 -15 11 (x,y) (0,-2),(20,-15),(-20,11 ) -6x+3y=18 -6 x + 3 y = 18 y= 2 x + 6 Assume values of x and plug in the equation to get values of y. Plot the points x 0 1 2 y= 6 8 10 (x,y) (0,6),(1,8),(2,10) The solution is (-3,0)
 test/604113: Factor the polynomial x˛-811 solutions Answer 380948 by mananth(12270)   on 2012-04-26 20:44:32 (Show Source): You can put this solution on YOUR website!Use the difference of two squares identity x^2-(9)^2 (x+9)(x-9)
 Radicals/604081: How would you solve radical 400 over 5 and both numbers are in the radical, not just the 4001 solutions Answer 380928 by mananth(12270)   on 2012-04-26 20:07:37 (Show Source):
 Miscellaneous_Word_Problems/603783: Four ball players have \$233 between them. Melvin has \$20 more than Harvey, \$53 more than Bruce and \$71 more than Rollo. How much money did each player have?1 solutions Answer 380831 by mananth(12270)   on 2012-04-26 09:08:20 (Show Source): You can put this solution on YOUR website!Melwin has x Harvey x-20 Bruce x-53 Rollo x-71 Add them up total is 233 4x-144=233 4x= 144+233 4x=377 /4 x= 94.25 Amount in Dollars Harvey = 94.25-20= 74.25 Bruce = 94.25-53= 41.25 Rollo= 94.25-71=23.25 Melwin = 94.25
 Geometry_Word_Problems/603785: Find the dimensions of a photo that has an area of 48 sq. in and a perimeter of 28 in.1 solutions Answer 380829 by mananth(12270)   on 2012-04-26 08:59:17 (Show Source): You can put this solution on YOUR website!let length = x in width = y in Perimeter 2(x+y) = 28 x+y = 14 Area xy = 48 x= 48/y substitute x x+y =14 48/y + y = 14 multiply equation by y 48+y^2=14y y^2-14y+48=0 y^2-8y-6y+48=0 y(y-8)-6(y-8)=0 (y-8)(y-6)=0 y = 6 OR 8 the dimensions are 8 in by 6 in
 Travel_Word_Problems/603745: two cars, 645 kilometers apart, begin driving toward each other on long straight highway. one car travels 100 kilometers per hour and the other 10 kilometers per hour. At the same time, a canary, starting on one car, flies back and forth between the two cars as they approach each other. If the canary flies 120 kilometers per hour and spends no time to turn around at each car, how far has it flown when the cars collide?1 solutions Answer 380827 by mananth(12270)   on 2012-04-26 08:55:26 (Show Source): You can put this solution on YOUR website!We have to find out how much time the Canary flies, before they collide Car I speed = 100 km/h Car II speed = 10km/h they are moving towards each other so add up their speeds= 110 km/h distance = 645 km Time = d/r t= 645/110 t= 5.86 hours speed of Canary = 120 km/h time = 5.86 hours so distance it flies = 5.86 *120= 703 km approx
 Age_Word_Problems/603784: sonny is twice as old as david. Four years ago, he was four times as old as david. When will the sum of their ages be 66?1 solutions Answer 380825 by mananth(12270)   on 2012-04-26 08:48:39 (Show Source): You can put this solution on YOUR website!David be x years Sonny = 2x 4 years ago their ages David = x-4 Sonny = 2x-4 2x-4=4(x-4) 2x-4 = 4x-16 4x-2x=16-4 2x=12 /2 x= 6 --- David's age Sonny's age = 12 Let their sum of ages be 66 after y years 6+y+12+y = 66 2y+18=66 2y=66-18 2y= 48 /2 y=24 their sum will be 66 after 24 years CHECK David =6 + 24= 30 Sonny = 12+24= 36 Total = 66
 Linear-systems/603765: Can you please sovle me this equation 2y+3x=1050 Y+x=4501 solutions Answer 380824 by mananth(12270)   on 2012-04-26 08:44:00 (Show Source): You can put this solution on YOUR website!2y+3x=1050 y+x=450 multiply by -2 -2y-2x=-900 2y+3x=1050 Add this equation to the first one x= 150 x+y =450 Plug x y+150=450 y=450-150 y=300
 Human-and-algebraic-language/603675: A motorist travels for 3okm at xkm/h and for 9okm at ykm/h and takes place 2.5hours for the journey. if the speed are interchanging, the journey take 2whole number 1/6 find x and y1 solutions Answer 380786 by mananth(12270)   on 2012-04-25 23:09:02 (Show Source): You can put this solution on YOUR website!Distance = speed * time Time = distance/speed t=d/r First condition Time Part I + time part II = 2.5 hour 30/x+90/y = 2.5 Let 1/x=a & 1/y = b 30a+90b=5/2.......................(1) Second condition 90/x+30/y = 2 1/6 = 13/6 90a+30b= 13/6......................(2) add (1) & (2) 120a+120b=5/2+13/6 120a+120b=14/3 divide by 120 a+b= 14/360.............(3) (1)-(2) -60a+60b=1/3 divide by -60 a-b=-1/180...................(4) (3)+(4) 2a= 14/360-1/180 a=7/360 -1/360 a= 6/360 a=1/60 1/x= 1/60 x= 60 a+b = 14/360 b= 14/360 -1/60 b=8/360 b=1/y = 8/360 y= 360/8 y=45
 Quadratic_Equations/603689: Find all real solutions: x-5x^1/2+4=0 How would you solve this question?1 solutions Answer 380781 by mananth(12270)   on 2012-04-25 22:32:17 (Show Source): You can put this solution on YOUR website! square both sides x(x-16)-1(x-16)=0 (x-1)(x-16)=0 x= 1 OR 16
 Travel_Word_Problems/603637: A small motor boat travels 7mph in still water. It takes 6hrs. longer to travel 48 miles going up stream than it does going down stream. Find the rate of the current. (hint 7+x=rate going down stream and 7-x= rate going up stream. Round off your answer to the nearest tenth). 1 solutions Answer 380779 by mananth(12270)   on 2012-04-25 22:16:07 (Show Source): You can put this solution on YOUR website!Boat speed 7 miles current speed = x Speed with current 7 + x Speed against current 7 - x Distance = 48 miles t=d/r Time against current - Time with current = 6 hour 48 /( 7 - x)- 48 /( 7 +x) = 6 LCD= ( 7 - x)( 7 + x) Multiply equation by LCD We get 48(7+x)-48(7-x) =6*(7-x)(7+x) 336+48x-336+48 x= 6*(49-x^2) 96 x = 294 - -6 x^2 6 x^2 96 x + -294 = 0 Find the roots of the equation by quadratic formula a= 6 ,b= 96 c -294 b^2-4ac= 9216 - 7056 b^2-4ac= 16272 = 127.56 x1=( -96 + 127.56 )/ 12 x1= 2.63 x2=( -96 -127.56 ) / 12 x2= -18.63 Ignore negative value speed = 2.6 mph m.ananth@hotmail.ca
 Linear-equations/603656: John sold 5 rolls of plain wrapping paper and 8 rolls of shiny wrapping paper for a total of \$199. Totsaka sold 5 rolls of plain wrapping paper and 6 rolls of shiny wrapping paper for a total of \$163. Determine the cost each of one roll of plain wrapping paper and one roll of shiny wrapping paper? -Thanks to anyone who helps.1 solutions Answer 380769 by mananth(12270)   on 2012-04-25 21:36:13 (Show Source): You can put this solution on YOUR website!x cost of roll of plain wrapping paper y cost of roll of shiny paper Total attended 5 x + 8 y = 199 .............1 5 x + 6 y = 163 .............2 Eliminate y multiply (1)by -3 Multiply (2) by 4 -15 x -24 y = -597 20 x + 24 y = 652 Add the two equations 5 x = 55 / 5 x = 11 plug value of x in (1) 5 x + 8 y = 199 55 + 8 y = 199 8 y = 199 -55.00 8 y = 144 y = 18 \$ 11 cost of roll of plain wrapping paper \$ 18 cost of roll of shiny paper m.ananth@hotmail.ca
 Polynomials-and-rational-expressions/603661: How do u solve rational equation 3 over m squared = m-4 over 3m squared + 2 over 3m squared1 solutions Answer 380765 by mananth(12270)   on 2012-04-25 21:30:42 (Show Source): You can put this solution on YOUR website! 11m^2=m^3 m=11
 Linear-equations/603652: - Thanks to whoever helps. Heather sold 3 packages of tulip bulbs and 2 packages of crocus bulbs for a total of \$85. Jimmy sold 10 packages of tulip bulbs and 2 packages of crocus bulbs for a total of \$190.1 solutions Answer 380763 by mananth(12270)   on 2012-04-25 21:24:48 (Show Source): You can put this solution on YOUR website!You must also ask a question. Anyway x cost of package of tulips y cost of package of crocus Total attended 3 x + 2 y = 85 .............1 10 x + 2 y = 190 .............2 Eliminate y multiply (1)by -1 Multiply (2) by 1 -3 x -2 y = -85 10 x + 2 y = 190 Add the two equations 7 x = 105 / 7 x = 15 plug value of x in (1) 3 x + 2 y = 85 45 + 2 y = 85 2 y = 85 -45.00 2 y = 40 y = 20 \$15 cost of package of tulips \$20 cost of package of crocus m.ananth@hotmail.ca
 Rational-functions/603639: Simplify -5/(x-4) + (x-6)/10 then divide by (x+3)/(x-4). Assume all expressions are defined.1 solutions Answer 380761 by mananth(12270)   on 2012-04-25 21:19:41 (Show Source): You can put this solution on YOUR website!/ LCM is 10(x-4) / / / *
 Mixture_Word_Problems/603643: A chemist has a solution that is 60% saline and another solution that is 35% saline. She wants to make 100 ounces of a mixture that will be 40% saline. How many ounces of the 60% saline solution will she use?1 solutions Answer 380760 by mananth(12270)   on 2012-04-25 21:07:40 (Show Source): You can put this solution on YOUR website! percent ---------------- quantity Saline solution I 60.00% ---------------- x ounces Saline solution II 35.00% ------ 100 - x ounces Mixture 40.00% ---------------- 100 12 60.00%x +35.00% (100 -x)=40.00%*100 60x+35 (100-x) =4000 60x+3500-35x = 4000 60x- 35x = 4000 -3500 25 x = 500 / 25 x=20 ounces 60.00% Saline solution I 80 ounces 35.00% Saline solution II m.ananth@hotmail.ca
 Quadratic_Equations/603181: Determine the coordinates of the x-intercepts for the quadratic equation 6x2 - 7x + 2 = 0.1 solutions Answer 380622 by mananth(12270)   on 2012-04-24 21:40:10 (Show Source): You can put this solution on YOUR website! Factorize the equation to get the roots of the equation x= 2/3 & 1/2 The X intercepts are 2/3 & 1/2
 test/603188: This is a factoring question: x^3+10001 solutions Answer 380619 by mananth(12270)   on 2012-04-24 21:30:34 (Show Source): You can put this solution on YOUR website!x^3+1000 Use the identity
 Mixture_Word_Problems/603183: how much pure acid must be mixed into 100ml of 20% acid to create a solution of 60% acid?1 solutions Answer 380618 by mananth(12270)   on 2012-04-24 21:24:25 (Show Source): You can put this solution on YOUR website!-------------- percent ---------------- Amount Acid solution 20 ---------------- 100 ml Pure acid 100 ---------------- x ml Mixture 60 ---------------- 100 + x ml 20*100 +100x =60(100 +x) 2000+ 100x=6000+60x 100x-60x=-2000+ 6000 40 x = 4000 / 40 x = 100 ml Pure acid m.ananth@hotmail.ca
 Linear_Equations_And_Systems_Word_Problems/603101: There are thirty-three students in the Chess Club. There are five more boys than girls in the club. Write and solve a system of equations to find the number of boys and girls in the Chess Club.1 solutions Answer 380615 by mananth(12270)   on 2012-04-24 21:19:51 (Show Source): You can put this solution on YOUR website!x number of boys y number of girls Total attended x+y = 33 .............1 x-y=5 .............2 Eliminate y Add the two equations 2 x = 38 / 2 x = 19 plug value of x in (1) 1 x + 1 y = 33 19 + 1 y = 33 1 y = 33-19 1 y = 14 y = 14 19 number of boys 14 number of girls m.ananth@hotmail.ca
 Complex_Numbers/603157: i need to simplify complex numbers. the problem is (6+3sq.rt.-1)(6-sq.rt.-1) we have the answers but we need to show our work and i have no idea how to get there. the answer is 39+12sq.rt.-11 solutions Answer 380613 by mananth(12270)   on 2012-04-24 20:59:49 (Show Source):
 Age_Word_Problems/603173: you can buy 3 hotdogs and 1 coke for \$4.55. you can buy 2 hotdogs and 1 coke for \$3.30 how much does 1 hotdog cost1 solutions Answer 380610 by mananth(12270)   on 2012-04-24 20:50:56 (Show Source): You can put this solution on YOUR website!x cost of each hot dog y cost of each coke Total attended 3 x + 1 y = 4.55 .............1 2.00 x + 1.00 y = 3.30 .............2 Eliminate y multiply (1)by -1.00 Multiply (2) by 1.00 -3.00 x -1.00 y = -4.55 2.00 x + 1.00 y = 3.30 Add the two equations -1.00 x = -1.25 / -1.00 x = 1.25 plug value of x in (1) 3.00 x + 1.00 y = 4.55 3.75 + 1.00 y = 4.55 1.00 y = 4.55 -3.75 1.00 y = 0.80 y = 0.80 \$1.25 cost of each hot dog \$0.80 cost of each coke m.ananth@hotmail.ca
 Surface-area/603171: what is the length width and heighth of a 48 inch surface area cube1 solutions Answer 380607 by mananth(12270)   on 2012-04-24 20:46:42 (Show Source): You can put this solution on YOUR website!Surface area of cube = 6 * l^2 where l is the length of the edge of the cube 6l^2=48 /6 l^2=8
 Triangles/602769: Hello, would any tutors please help me with these problems? I don't really understand how to do them. If also you can explain how you did them, I would be really thankful. Thank you for your time!!! http://i90.photobucket.com/albums/k250/robinahood11/photo22.jpg1 solutions Answer 380402 by mananth(12270)   on 2012-04-23 23:57:44 (Show Source): You can put this solution on YOUR website!13.A A(2,8) B(0,8) C(2,2) Let O be the center of the circle circumscribing the triangle Then d(OA)=d(OB)=d(OC) all are radii. Let the coordinates of be (x,y) The distance between two points (x1,y1) & (x2,y2) is given by d= O(x,y) & A(2,8) d(OA)= = = B(0,8)O(x,y) d(OB)= = Since OA & OB are radii They are equal = square both sides -4x=-68+64 =-4x=-4 x=1 C(2,2) O(x,y) D(OC)= = = d(OC)=d(OA) = square both sides = 12y=60 /12 y=5 The center (1,5) 17 bisector 18 median 19 altitude m.ananth@hotmail.ca
 Linear-equations/602750: Find an equation of the line having the given slope and containing the given point: m=3; (3,5)1 solutions Answer 380401 by mananth(12270)   on 2012-04-23 23:18:57 (Show Source): You can put this solution on YOUR website!m= 3 Plug value of the slope and point(3,) in y=mx+b 5.00 = 3 * 3 +b b= 5 -9 b= -4 So the equation will be Y = 3 x + -4 m.ananth@hotmail.ca