Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On

 Tutoring Home For Students Tools for Tutors Our Tutors Register Recently Solved
 By Tutor
| By Problem Number |

Tutor:

Recent problems solved by 'lwsshak3'

Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539, >>Next

 Quadratic-relations-and-conic-sections/636257: Write the equation of the circle in standard form.  Find the center, radius, intercepts, and graph the circle. x^2+y^2+8x+2y+8=0 I am having trouble with the steps involved.1 solutions Answer 400860 by lwsshak3(6522)   on 2012-08-10 03:13:09 (Show Source): You can put this solution on YOUR website!Write the equation of the circle in standard form. Find the center, radius, intercepts, and graph the circle. x^2+y^2+8x+2y+8=0 ** Standard form of equation for a circle: , (h,k)=(x,y) coordinates of center, r=radius. x^2+y^2+8x+2y+8=0 complete the square x^2+8x+y^2+2y+8=0 (x^2+8x+16)+(y^2+2y+1)=-8+16+1 Equation: .. r^2=9 radius=3 .. center:(-4,-1) .. x-intercepts: set y=0 (x+4)^2+1=9 (x+4)^2=8 x+4=±√8 x=-4±√8 x≈-6.83 or x≈-1.17 .. See graph below: y=±(9-(x+4)^2)^.5-1
 Quadratic-relations-and-conic-sections/636258: For the given equation, list the intercepts and test for symmetry. y=x^3-512 We are learning precalculus and I need to check my steps again, can anyon help out? Please.1 solutions Answer 400859 by lwsshak3(6522)   on 2012-08-10 02:37:35 (Show Source): You can put this solution on YOUR website!For the given equation, list the intercepts and test for symmetry. y=x^3-512 ** x-intercept set y=0 x^3-512=0 x^3=512=8^3 x=8 .. y-intercept set x=0 y=0-512=-512 .. symmetry: none see graph below:
 Quadratic-relations-and-conic-sections/636143: Write the equation of a parabola that as a vertical axis and passes through the origin, (3,-2), and (-2,2).1 solutions Answer 400787 by lwsshak3(6522)   on 2012-08-09 16:51:31 (Show Source): You can put this solution on YOUR website!Write the equation of a parabola that as a vertical axis and passes through the origin, (3,-2), and (-2,2). ** Standard form of parabola with vertical axis of symmetry: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of vertex. For given parabola: h=0 equation: y=Ax^2+k use given coordinates, (3,-2) and (-2,2), to solve for A and k .. -2=3^2A+k 2=(-2)^2A+k .. -2=9A+k 2=4A+k subtract 5A=-4 A=-4/5 k=2-4A =2-4*-4/5 =2+16/5 =10/5+16/5 =26/5 equation: y=-4x^2/5+26/5
 Travel_Word_Problems/636128: a car covers the first half of the distance between two places at a speed of 40km/hr and second half at 60 km/hr . calculate the average speed of the car1 solutions Answer 400762 by lwsshak3(6522)   on 2012-08-09 15:47:26 (Show Source): You can put this solution on YOUR website!a car covers the first half of the distance between two places at a speed of 40km/hr and second half at 60 km/hr . calculate the average speed of the car ** let x=total distance between the 2 places ave speed=distance/travel time .. travel time=distance/speed =(x/2)/40+(x/2)/60 =x/80+x/120 =(80x+120x)/(80*120) =200x/9600 .. ave speed=x/(200x/9600)=9600/200=48 average speed of the car=48 km/hr
 Quadratic-relations-and-conic-sections/636108: Write the equation of a circle that has the center on the x-axis, a radius of 1, and passes through the point (((square root of 2)/2),((square root of 2)/2)).1 solutions Answer 400752 by lwsshak3(6522)   on 2012-08-09 15:20:51 (Show Source): You can put this solution on YOUR website!Write the equation of a circle that has the center on the x-axis, a radius of 1, and passes through the point (((square root of 2)/2),((square root of 2)/2)). ** Equation of a circle: , (h,k)=(x,y) coordinates of center, r=radius For given circle: r^2=1 r=1 k==0 equation: (x-h)^2+y^2=1 solve for h using coordinates of given point (√2/2, √2/2) (√2/2-h)^2+(√2/2)^2=1 2/4-√2h+h^2+2/4=1 h^2-√2h+1=1 h^2-√2h=0 h(h-√2)=0 h=0 (reject, does not check) h=√2 Equation: (x-√2)^2+y^2=1
 Trigonometry-basics/635963: Please help me with this problem: log[2](4)+3x=61 solutions Answer 400662 by lwsshak3(6522)   on 2012-08-09 02:07:16 (Show Source): You can put this solution on YOUR website!log[2](4)+3x=6 log(4),base 2=2 2+3x=6 3x=4 x=4/3
 Polynomials-and-rational-expressions/635912: factor 25g^6 -10g^3 +11 solutions Answer 400661 by lwsshak3(6522)   on 2012-08-09 01:56:14 (Show Source): You can put this solution on YOUR website!factor 25g^6 -10g^3 +1 set equation=0 25g^6 -10g^3 +1=0 let u=g^3 u^2=g^6 .. 25u^2-10u+1=0 (5u-1)(5u-1)=0 u=1/5 (multiplicity 2) u=1/5=g^3 raise both sides to 1/3 power or take cube root of both sides g=5^(-1/3) g≈0.5848... two factors are: irrational number 0.5848...(multiplicity 2) The other four factors are 2 pairs of non-real or imaginary numbers)
 Polynomials-and-rational-expressions/635925: The area (in square inches) of a rectangle is given by the polynomial function A(p)= p^2 +11p+ 18. If the lenght of the rectangle is (p+2) inches. What is the width?1 solutions Answer 400651 by lwsshak3(6522)   on 2012-08-09 01:13:23 (Show Source): You can put this solution on YOUR website!The area (in square inches) of a rectangle is given by the polynomial function A(p)= p^2 +11p+ 18. If the lenght of the rectangle is (p+2) inches. What is the width ** Area=length*width Area/length=width (p^2 +11p+ 18)/(p+2) =(p+9)(p+2)/(p+2) width=(p+9)
 absolute-value/635935: This is a mixture of inequalities and absolute values. Solve the following absolute value in equalities: |x+1| is less than or equal to |x-3|1 solutions Answer 400647 by lwsshak3(6522)   on 2012-08-09 00:56:08 (Show Source): You can put this solution on YOUR website!This is a mixture of inequalities and absolute values. Solve the following absolute value in equalities: |x+1| is less than or equal to |x-3| ** |x+1|≤|x-3| solve for 2 conditions: x+1≤x-3 1≤-3 (reject, not true) .. x+1≤-x+3 2x≤2 x≤1 solution: (-∞,1]
 absolute-value/635756: √288 x^7 y^31 solutions Answer 400579 by lwsshak3(6522)   on 2012-08-08 16:51:23 (Show Source): You can put this solution on YOUR website!√(288 x^7 y^3) =√(144*2*x^6*x*y^2*y) =12x^3y√2xy
 Mixture_Word_Problems/635813: 60 ml of solution A is mixed with 120 ml of solution B to produce solution C which contains 8% of pure acid. If 80 ml of solution A is mixed with 40 ml of solution B, a solution D containing 10% of pure acid can be produced. Find the percentage of pure acid in solution A.1 solutions Answer 400577 by lwsshak3(6522)   on 2012-08-08 16:41:10 (Show Source): You can put this solution on YOUR website!60 ml of solution A is mixed with 120 ml of solution B to produce solution C which contains 8% of pure acid. If 80 ml of solution A is mixed with 40 ml of solution B, a solution D containing 10% of pure acid can be produced. Find the percentage of pure acid in solution A. ** let x=% acid in solution A let y=% acid in solution B 2 equations: 60x+120y=.08(60+120)=.08(180)=14.4 80x+40y=.10(80+40)=.10(120)=12 .. 60x+120y=14.4 80x+40y=12 .. 60x+120y=14.4 240x+120y=36 subtract -180x=-21.6 x=21.6/180=.12 40y=12-80x=12-.12*80=2.4 y=2.4/40=.06 percentage of pure acid in solution A=12%
 Graphs/635611: A tennis ball is thrown with an initial upward velocity of 64 feet per second. How long will it take for the ball to hit the ground? Use the formula in which the height above ground after t seconds is given by the quadratic function h = vt – 16t2, where h represents the height of the object in feet, and v represents the object's initial velocity in feet per second. The answer is supposed to be in seconds, but I am not at all sure how to get there.1 solutions Answer 400477 by lwsshak3(6522)   on 2012-08-08 02:37:34 (Show Source): You can put this solution on YOUR website!A tennis ball is thrown with an initial upward velocity of 64 feet per second. How long will it take for the ball to hit the ground? Use the formula in which the height above ground after t seconds is given by the quadratic function h = vt – 16t^2, where h represents the height of the object in feet, and v represents the object's initial velocity in feet per second. The answer is supposed to be in seconds, but I am not at all sure how to get there. ** When the ball hits the ground, h=0 vt–16t^2=0 64t-16t^2=0 .. t(64-16t)=0 t=0 (reject, not reasonable) or 64-16t=0 16t=64 t=64/16=4 How long will it take for the ball to hit the ground? 4 seconds
 logarithm/635637: Simplify the following expressions: log36 - log3 + log2 6 X log2 - 2 X log4 1 solutions Answer 400476 by lwsshak3(6522)   on 2012-08-08 02:17:57 (Show Source): You can put this solution on YOUR website!Simplify the following expressions: log36 - log3 + log2 log[36*2/3]=log[24] .. 6 X log2 - 2 X log4 log2^6-log4^2 =log[2^6/4^2] =log[64/16] =log[4]
 logarithm/635641: The atmospheric pressure (measured in millibars and given the symbol P) decreases with height (h, in miles) according to: P = 29.92xe^(-h/5) a) Find the pressure at a height of 4 miles. b) At what height (in miles) is the atmospheric pressure 10 millibars?1 solutions Answer 400474 by lwsshak3(6522)   on 2012-08-08 02:08:58 (Show Source): You can put this solution on YOUR website!The atmospheric pressure (measured in millibars and given the symbol P) decreases with height (h, in miles) according to: P = 29.92xe^(-h/5) .. a) Find the pressure at a height of 4 miles. P=29.92*e^(-4/5)≈13.44 millibars .. b) At what height (in miles) is the atmospheric pressure 10 millibars? 10=29.92*e^(-h/5) 10/29.92=e^(-h/5) take log of both sides ln(10/29.92)=-h/5 lne lne=1 -h=ln(10/29.92)*5≈-5.48 h=5.48 Height at which the atmospheric pressure is 10 millibars=5.48 miles
 Rational-functions/635607: I need help on the step by step process on how to analyze the graph of this following function ? R(x)= x^3 - 125 / x^2 - 49 ?1 solutions Answer 400468 by lwsshak3(6522)   on 2012-08-08 01:44:47 (Show Source): You can put this solution on YOUR website!I need help on the step by step process on how to analyze the graph of this following function ? Because the degree of the numerator is one degree higher than that of the denominator, function has a slant asymptote. .. To find the equation of the slant asymptote, divide denominator by numerator. By inspection, you can see you will get x+remainder. You can ignore the remainder. equation of the slant asymptote: y=x .. x-intercept: set R(x)=0 x-5=0 x-intercept=5 .. y-intercept: set x=0 -125/-49≈2.55 y-intercept≈2.55 .. vertical asymptotes: set denominator=0 x=7 and x=-7 .. number line: <..-...-7...+....5....-....7....+.....> The graph below shows the basic curve but I don't have the means to draw in the asymptotes. However, it should be good guide how to graph the entire curve with asymptotes and all.
 Rational-functions/635531: Use interval notation to express the solution set. Solve 8<2x<=101 solutions Answer 400410 by lwsshak3(6522)   on 2012-08-07 20:39:22 (Show Source): You can put this solution on YOUR website!Use interval notation to express the solution set. Solve 8<2x≤10 divide by 2 4 < x ≤ 5 number line <......(4<==>5]...........> solution: (4, 5]
 Linear_Equations_And_Systems_Word_Problems/635582: Trenton sells electronic supplies.Each week he earns 190 dollars plus commission equal to 4% of his sales. This week his goal is to earn no less than 500 dollars. Write and solve an inequality to find the amount of sales he must have to reach his goal.1 solutions Answer 400406 by lwsshak3(6522)   on 2012-08-07 20:32:11 (Show Source): You can put this solution on YOUR website!Trenton sells electronic supplies.Each week he earns 190 dollars plus commission equal to 4% of his sales. This week his goal is to earn no less than 500 dollars. Write and solve an inequality to find the amount of sales he must have to reach his goal. ** let x=amount of sales to reach his goal 4%x+190≥500 .04x≥500-190 .04x≥310 x≥310/.04 x≥7750 amount of sales to reach his goal≥7750
 Money_Word_Problems/635583: a bookstore currently sells 15 copies per week of a \$20 book. For each \$1 discount in price, the store can sell 3 more books.How many discounts will yield sales of \$468 per week on this book.1 solutions Answer 400404 by lwsshak3(6522)   on 2012-08-07 20:24:18 (Show Source): You can put this solution on YOUR website!a bookstore currently sells 15 copies per week of a \$20 book. For each \$1 discount in price, the store can sell 3 more books.How many discounts will yield sales of \$468 per week on this book. ** let x=no. of \$1 discounts price of each book=20-x no. of books sold=15+3x (20-x)(15+3x)=468 300+45x-3x^2=468 3x^2-45x-300+468=0 3x^2-45x-168=0 x^2-15x-56=0 (x-8)(x-7)=0 x=8 or x=7 No. of \$1 discounts that will yield sales of \$468 per week: 7 and 8
 Graphs/635575: Find the equation of the line containing the point (-3, -12) and having a slope of -4.1 solutions Answer 400403 by lwsshak3(6522)   on 2012-08-07 20:03:52 (Show Source): You can put this solution on YOUR website!Find the equation of the line containing the point (-3, -12) and having a slope of -4. ** Standard form of equation for a line: y=mx+b, m=slope, b=y-intercept y=-4x+b solve for b using coordinates of given point (-3,-12) -12=-4*-3+b b=-24 equation: y=-4x-24
 Equations/635578: 5x+17>-2x-41 solutions Answer 400402 by lwsshak3(6522)   on 2012-08-07 19:51:58 (Show Source): You can put this solution on YOUR website!5x+17>-2x-4 5x+17≥2x-4 3x≥-21 x≥-7 solution in interval notation: [-7,∞)
 Quadratic-relations-and-conic-sections/635551: Can you please help me out with this? Write an equation of an ellipse with center (2, 12), vertical major axis of length 18, and minor axis of length 41 solutions Answer 400401 by lwsshak3(6522)   on 2012-08-07 19:47:35 (Show Source): You can put this solution on YOUR website!Write an equation of an ellipse with center (2, 12), vertical major axis of length 18, and minor axis of length 4 ** Standard form of equation for an ellipse with vertical major axis: , a>b, (h,k),=(x,y) coordinates of center center: (2,12) length of vertical major axis=18=2a a=9 a^2=81 length of minor axis=4=2b b=2 b^4 Equation:
 Surface-area/635492: The questions is to Find the volume. Use 31.4 as the approximate value of pie. Round answers to the nearest tenth. Its a cylinder with top 7m and height 11m Which is the correct answer; A)423.1m B)120.9m C)241.8m D)1,692.5m1 solutions Answer 400371 by lwsshak3(6522)   on 2012-08-07 16:25:22 (Show Source): You can put this solution on YOUR website!The questions is to Find the volume. Use 31.4 as the approximate value of pie. Round answers to the nearest tenth. Its a cylinder with top 7m and height 11m Which is the correct answer; A)423.1m B)120.9m C)241.8m D)1,692.5m ** volume=area of top*height =3.14*(7^2/4)*11=423.1 correct ans: A)423.1m
 Polynomials-and-rational-expressions/635435: Rationalize the denominator. Assume that all expressions under radicals represent positive numbers. a√-√b over √a+√b1 solutions Answer 400369 by lwsshak3(6522)   on 2012-08-07 16:19:03 (Show Source): You can put this solution on YOUR website!Rationalize the denominator. Assume that all expressions under radicals represent positive numbers. a√-√b over √a+√b I assume you meant to write it this way: √a-√b over √a+√b =(√a-√b)/(√a+√b) multiply top and bottom by (√a-√b) (conjugate of (√a+√b)) =(√a-√b)^2/ (√a-√b)*(√a+√b) =(√a-√b)^2/ (a-b)
 Miscellaneous_Word_Problems/635484: you have a piece of wood that is 84 inches long. you cut the wood into 3 pieces. the 2nd piece is 8 inches longer than the first piece. the 3rd piece is 16 inches longer than the second piece. write an equation and then solve it to determine the lengths of the 3 pieces.1 solutions Answer 400365 by lwsshak3(6522)   on 2012-08-07 16:04:36 (Show Source): You can put this solution on YOUR website!you have a piece of wood that is 84 inches long. you cut the wood into 3 pieces. the 2nd piece is 8 inches longer than the first piece. the 3rd piece is 16 inches longer than the second piece. write an equation and then solve it to determine the lengths of the 3 pieces. ** le x=length of 1st piece x+8=length of 2nd piece x+8+16=x+24=length of 3rd piece .. x+(x+8)+(x+24)=84 3x+32=84 3x=84-32=52 x=52/3=17+1/3 x+8=25+1/3 x+24=41+1/3 .. length of 1st piece=17+1/3 in length of 2nd piece=25+1/3 in length of 3rd piece=41+1/3 in
 Linear-equations/635479: Write the slope-intercept form of the equation (5,2) and (-5,6)1 solutions Answer 400359 by lwsshak3(6522)   on 2012-08-07 15:51:52 (Show Source): You can put this solution on YOUR website!Write the slope-intercept form of the equation (5,2) and (-5,6) ** This is an equation of a straight line. Its standard form: y=mx+b, m=slope, b=y-intercept slope=∆y/∆x=(6-2)/(-5-5=4/-10=-4/10=-2/5 equation of line: y=-2x/5+b solve for b using one of given points(5,2) 2=-2*5/5+b 2=-2+b b=4 Equation: y=-2x/5+4
 Quadratic_Equations/635476: A ball is tossed from a window that is 10 feet off the ground. The height, h (in feet), of the ball at any time, t (in seconds), is given by the equation h = - 16 t^2 + 12x + 10. What is the maximum height (in feet) that the ball will reach?1 solutions Answer 400355 by lwsshak3(6522)   on 2012-08-07 15:35:02 (Show Source): You can put this solution on YOUR website!A ball is tossed from a window that is 10 feet off the ground. The height, h (in feet), of the ball at any time, t (in seconds), is given by the equation h = - 16 t^2 + 12x + 10. What is the maximum height (in feet) that the ball will reach? ** h = - 16 t^2 + 12x + 10 This is an equation of a parabola that opens downwards (function has a maximum) Its standard form: y=(x-h)^2+k, (h,k)=(x,y) coordinates of vertex, k=maximum value complete the square h=-16(t^2-(12/16)t)+10 =-16(t^2-(3/4)t)+10 =-16(t^2-(3/4)t+9/64)+9/4+10 =-16(t-(3/8)^2+9/4+40/4 h=-16(t-(3/8)^2+49/4 maximum height that the ball will reach=12.25 ft
 Quadratic_Equations/635457: Find the minimum value for the function: y = x^2 + 9x + 181 solutions Answer 400348 by lwsshak3(6522)   on 2012-08-07 15:05:22 (Show Source): You can put this solution on YOUR website!Find the minimum value for the function: y = x^2 + 9x + 18 This is an equation of a parabola that opens upwards (function has a minimum) Its standard form: y=(x-h)^2+k, (h,k)=(x,y) coordinates of vertex, k=minimum value complete the square y=(x^2+9x+20.25)+18-20.25 y=(x+9/2)^2-2.25 minimum value=-2.25
 Radicals/634745: 3sqrt(27(x+3))^31 solutions Answer 400275 by lwsshak3(6522)   on 2012-08-07 01:58:34 (Show Source): You can put this solution on YOUR website!3sqrt(27(x+3))^3 3√[27(x+3)]^3 =3*(27(x+3))^3/2
 Radicals/634843: Rationalize the denominator in the following expression sqrt(75a^3/(2b)1 solutions Answer 400272 by lwsshak3(6522)   on 2012-08-07 01:52:51 (Show Source): You can put this solution on YOUR website!Rationalize the denominator in the following expression sqrt(75a^3/(2b) =√(75a^3)/√2b =√2b/√2b*√(75a^3)/√2b =√2b*√(75a^3)/2b =[5a√(5a*2b)]/2b =[5a√(10ab)]/2b
 Exponential-and-logarithmic-functions/635350: Ten grams of Uranium will decay to 2.5 g in 496,000 years. What is its half-life? 1 solutions Answer 400265 by lwsshak3(6522)   on 2012-08-07 01:28:29 (Show Source): You can put this solution on YOUR website!Ten grams of Uranium will decay to 2.5 g in 496,000 years. What is its half-life? ** Formula for radioactive decay: A/Ao=2^-t/h, A=radioactive material present at time t, Ao=amt present initially, h=material half life. 2.5/10=2^-4.96*10^5/h .25=2^-4.96*10^5/h take log of both sides log.25=-4.96*10^5/h)log2 h(log.25)=-(4.96*10^5)log2 h=-(4.96*10^5)log2/log.25=-2.48*10^5 .. half-life of material=2.48*10^5 yrs
 test/635356: A total of 925 tickets were sold for a game for a total of \$2,495. if adult tickets sold for \$5.00 and childrens sold for \$2.00, how many of each kind of ticket were sold? I saw this question like this and the farthest I got was 5a+2c=2495 What do I do from that point?1 solutions Answer 400261 by lwsshak3(6522)   on 2012-08-07 01:03:47 (Show Source): You can put this solution on YOUR website!A total of 925 tickets were sold for a game for a total of \$2,495. if adult tickets sold for \$5.00 and childrens sold for \$2.00, how many of each kind of ticket were sold? ** let x=no. of adult tickets sold 925-x=no. of children tickets sold .. 5x+2(925-x)=2495 5x+1850-2x=2495 3x=2495-1850=645 3x=645 x=215 925-x=710 .. no. of adult tickets sold=215 no. of children tickets sold=710 .. you could have continued with your solution by noting that: a+c=925 c=925-a